Answers
Answer:
The notation of configuration of Co is \([Ar] 3d^7 4s^2\)
(A) is correct option.
Explanation:
Given that,
The following notations is the correct noble gas configuration for Co.
(A). [Ar] 3d⁷ 4s²
(B). [Ar] 4s² 4p⁶ 3d
(C). [Kr] 4s² 4p⁶ 4d
(D). [Co] 3d⁷ 4s²
We know that,
Cobalt :
Co is the symbol of cobalt which is a chemical element.
Atomic number of Co is 27.
We need to find the notation of the configuration of noble gas Co
Using configuration
\(Co_{27}=2, 8, 15, 2\)
\(Co_{27}=1s^2, 2s^2,2p^6, 3s^2 3p^6 3d^7, 4s^2\)
So, we can write as the notation of noble gas configuration
\(Co_{27}=[Ar] 3d^7 4s^2\)
Hence, The notation of configuration of Co is \([Ar] 3d^7 4s^2\)
(A) is correct option.
Related Questions
Calculate the N/Z ratio for elements with atomic numbers 104 through 109. Are they in the belt of stability? Are they stable? How do you know?
Answers
The ratio of neutrons to protons, or the N/Z ratio, plays a crucial role in determining a nucleus' stability. The range of N/Z ratios in which nuclei are stable is generally referred to as the belt of stability.
How can you tell whether a substance is stable or unstable?If the forces between the constituents of the nucleus are equal, an atom is stable. If these forces are out of balance or if the nucleus has an excessive amount of internal energy, an atom is unstable (radioactive).
Z = 104 for Rutherfordium, element 104. The isotopes 261Rf and 262Rf, having masses of 261 and 262, respectively, have the longest half-lives. Accordingly, N/Z ratios are:
261Rf: N/Z = (261-104)/157 = 1.08
262Rf: N/Z = (262-104)/158 = 1.09
These N/Z ratios are a little bit higher than the average belt of stability values, which are about 1.0 for heavy nuclei. These isotopes are thought to be reasonably stable because they are close enough.
Z = 109 for Meitnerium, element 109. The isotopes 278Mt and 282Mt, with masses of 278 and 282, respectively, have the longest half-lives. Accordingly, N/Z ratios are:
278Mt: N/Z
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Enthalpy Lab + Questions NEED HELP ASAP FOR THE ANALYSIS QUESTIONS (be sure to show your work) + CONCLUSION
PURPOSE OF EXPERIMENT: To find Heat of Solution of sodium hydroxide and to find the heat of neutralization between sodium hydroxide and hydrochloric acid.
Experiment 1 Procedure:
1. Measure 50.0 mL of water (tap) into a 100 mL graduated cylinder and pour it into a large coffee cup.
2. Determine the temperature of this water
3. Measure out 2.00 g of sodium hydroxide into a piece of paper towel *tare scale!
4. Add the sodium hydroxide to the water in the coffee cup and put a small cup over it, with the thermometer through the hole. Stir GENTLY with the thermometer and record the temperature every 30 seconds for 3 minutes or until it peaks. Record this in a properly labelled table.
5. Let this stand for 45 minutes before proceeding to Exp. 2.
WHAT WE FOUND IN EXP 1:
T (temp.) initial = 20 degrees C
T (temp) FINAL = 28.5 degrees C
moles of sodium hydroxide = 0.0518mol
the molar mass of sodium hydroxide = 39.969g/mol
C (specific heat of water) = 4.184J/g degrees C
THE NUMBER OF TRIALS FOR TEMP IN EXP 1
1st trial = 21 C
2nd trial = 24.5 C
3rd trial = 26 C
4th trial = 26 C
5th trial = 28 C
6th trial = 28.5 C
7th trial = 28.5 C (final temp)
ANALYSIS FOR EXPERIMENT ONE:
1. Determine the moles of sodium hydroxide (NaOH) from the experiment.
2. Determine Qsurroundings and Qrxn
3. Determine the enthalpy for the dissociation of sodium hydroxide (delta H sol)
4. Write the thermochemical equation for the dissociation of sodium hydroxide TWO ways and write an enthalpy diagram
5. What assumptions did you make to calculate #2? (some example assumptions to make: assume that the solution is water and that heat and density COULD be the same as water, etc)
6. Research the actual value and determine the percent error
7. In terms of bonds breaking and forming, what is RESPONSIBLE FOR ENTHALPY CHANGE?
EXPERIMENT 2 PROCEDURE:
1. Measure out 50.0 mL of 0.75 concentration M HCl into a graduated cylinder
2. Measure and record the temperature of the sodium hydroxide solution from exp. 1.
3. Add the hydrochloric acid solution to the sodium hydroxide solution, put the small cup on, and record the temperature change every 15 seconds for 1 minute. Stir GENTLY. Record this in a properly labelled table (will be given below)
4. Solutions can be discarded down the sink.
WHAT WE FOUND IN EXP. 2:
T (temp) initial = 23.5 C
T (temp) FINAL = 27 C
THE NUMBER OF TRIALS FOR TEMP IN EXP 2
1st trial = 27 C
2nd trial = 27 C
3rd trial = 27 C
4th trial = 27 C (FINAL TEMP)
ANALYSIS FOR EXPERIMENT 2:
1. Determine the moles of HCl added to this mixture
2. Write the chemical equation for this reaction
3. Determine the limiting reagent
4. Determine the Qsurr and Qrxn *CONVERT TO kJ*
5. Determine the enthalpy for the neutralization reaction.
6. Write the thermochemical equation for the dissociation of sodium hydroxide TWO WAYS and write an enthalpy diagram
7. Research the actual value and determine the percent error.
8 Explain sources of experimental error for both experiments and BE SPECIFIC! (NOT CALCULATION ERRORS, SPILLING, OR LOSING REACTANTS - DO NOT COUNT AS ERRORS! They can be EXPERIMENTAL due to heat loss/gain, room temp *specific heat capacity is for 25 C*, and atmospheric pressure is constant. And they can be MEASUREMENTS - consider the precision and the potential range of error for each measurement)
9. In terms of bonds breaking and forming, what's responsible for the enthalpy change?
CONCLUSION: write a brief statement that refers to the purpose.
Answers
The difference between the energy needed to break the bonds in the reactants and the energy released when new bonds are created in the products is what essentially determines the enthalpy change.
What impact does bond breaking have on enthalpy?In general, a bond must be broken by a positive change in enthalpy, whereas a bond must be formed by a negative change in enthalpy. In other words, the process of breaking a bond is endothermic, whereas the process of forming a bond is exothermic.
What is the bond-breaking and bond-forming reaction's enthalpy change?The energy needed to break the links between the reactants less the energy released during the formation of new bonds in the products is the enthalpy of reaction.
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In terms of bonds breaking and forming, what's responsible for the enthalpy change?
how many atoms are in 5.7 g of helium?
Answers
Answer:
3.5*1024
Explanation:
3584
find heat capacity when 47.0 J of heat is added to 13.0 g of a liquid, its temperature rises by 1.71 ∘C
Answers
Heat capacity when 47.0 J of heat is added to 13.0 g of a liquid, its temperature rises by 1.71 ∘C is 22.23 J/ ∘C g .
from the above statement we have got
Q = 47.0 J
MASS = 13.0 g
temperature (T) = 1.71 ∘C
heat capacity ( c ) = ?
NOW, from the formulae , Q = mcΔt
put all the values given in equation
47.0 J = 13.0 g \(\times\) c \(\times\)1.71 ∘C
c = 47.0 ÷ 13.0\(\times\)1.71
c = 47/22
c = 22.23 J/ ∘C g
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What type of compound is a salt
Answers
Answer: Salt is an ionic compound.
Explanation:
A compound formed by transfer of electrons from one atom to another is called an ionic compound.
For example, chemical formula of salt is NaCl (also called table salt).
Salt is formed when sodium (atomic no. 11) donates its one valence electron to chlorine (atomic no. 17). As a result, sodium ion and chlorine ion chemically combine together and form the compound NaCl.
Thus, we can conclude that salt is an ionic compound.
What type of chemical reaction requires oxygen gas as reactant and releases heat?
Answers
Answer:
A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat.
use the interactive to observe the reactions between various metals and metal cation solutions. determine whether a reaction occurs for each metal-metal nitrate solution pair.
Answers
Aluminum and Sodium Nitrate: No Reaction
What is sodium?Sodium is a chemical element found in nature as a silver-white metal. It is the sixth most abundant element in the Earth's crust, making up around 2.8 percent of the total mass of the crust. It is also one of the most important elements in human diet. Sodium is essential for many biological processes, such as maintaining water balance, transporting nutrients, and regulating nerve impulses. It can be found in many foods, such as table salt, dairy products, seafood, and processed foods. It is also an important component of many medications, such as antacids, diuretics, and blood pressure medications. Without adequate sodium in the diet, people may experience headaches, fatigue, muscle cramps, and other symptoms. Too much sodium in the diet, however, can increase the risk of high blood pressure, stroke, and heart disease.
Aluminum is more reactive than sodium, so a reaction will not occur when they are combined. Aluminum will not react with the sodium nitrate because sodium is not reactive enough to cause a reaction.
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Which process produces the energy that is used by solar panels?
O A. Nuclear fusion
O B. Combustion
O C. Chemical decay
D. Nuclear decay
Answers
Answer:
B
Explanation:
Answer:
A
Explanation: got it right
7) How many molecules of CO2 are in 2.5 L at STP?
Answers
By using the ideal gas law and Avogadro's number, we find that there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.
To determine the number of molecules of CO2 in 2.5 L at STP (Standard Temperature and Pressure), we can use the ideal gas law and Avogadro's number.
Avogadro's number (N_A) is a fundamental constant representing the number of particles (atoms, molecules, ions) in one mole of substance. Its value is approximately 6.022 × 10^23 particles/mol.
STP conditions are defined as a temperature of 273.15 K (0 °C) and a pressure of 1 atmosphere (1 atm).
First, we need to convert the volume from liters to moles of CO2. To do this, we use the ideal gas law equation:
PV = nRT,
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Since we have STP conditions, we can substitute the values:
(1 atm) × (2.5 L) = n × (0.0821 L·atm/(mol·K)) × (273.15 K).
Simplifying the equation:
2.5 = n × 22.4149.
Solving for n (the number of moles):
n = 2.5 / 22.4149 ≈ 0.1116 moles.
Next, we can calculate the number of molecules using Avogadro's number:
Number of molecules = n × N_A.
Number of molecules = 0.1116 moles × (6.022 × 10^23 particles/mol).
Number of molecules ≈ 6.72 × 10^22 molecules.
Therefore, there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.
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You have 750 grams of Cr(S03). How many particles are present?
Answers
Explanation:
Before we find the number of particles we have to convert from grams to moles. To do that we can use the molar mass of our compound.
molar mass of Cr = 52.00 g/mol
molar mass of S = 32.07 g/mol
molar mass of O = 16.00 g/mol
molar mass of CrSO₃ = 1 * 52.00 g/mol + 1 * 32.07 g/mol + 3 * 16.00 g/mol
molar mass of to c = 132.07 g/mol
mass of onver = 750 g
moles of tles = 750 g/(132.07 g/mol)
moles of we ha = 5.68 molesvles we haCrSO₃CrSO₃CrSO₃CrSO₃
According to Avogadro's Number we have 6.022 * 10^23 particles in 1 mol of molCr. Let's use that relationship to find the answer to our problem.
1 mol of SO₃Cr = SO₃6.022 * 10^23 partic
n° of particles = 5.68 moles * 6.022 * 10^23 particles/(1 mol)
n° of particles = 3.42 * 10^24 particles
Answer: there are 3.42 * 10^24 particles.
EXAMPLE 8 (Mixed) How many liters of hydrogen gas are produced if 15.9 g of hydrochloric acid reacts with excess zine metal ? Assume STP Zn + 2HCl -> ZnCh + H_{2} ( 109 L)
Answers
The total amount of hydrogen gas generated is 9.76 L, under the condition that 15.9 g of hydrochloric acid reacts with excess zine metal.
Furthermore the balanced chemical equation for the reaction between hydrochloric acid and zinc metal is:
2HCl + Zn → ZnCl₂ + H₂
The molar mass of HCl is 36.46 g/mol.
Then, 15.9 g of HCl is equivalent to 15.9 g / 36.46 g/mol = 0.436 mol of HCl.
As per the balanced chemical equation, 1 mole of HCl reacts with 1 mole of Zn to produce 1 mole of H₂ gas.
Hence, 0.436 mol of HCl will produce 0.436 mol of H₂ gas.
In Stp (Standard Temperature and Pressure), one mole of any gas occupies 22.4 L.
So, 0.436 mol of H₂ gas will occupy:
0.436 mol × 22.4 L/mol = 9.76 L (approx)
Then, approximately 9.76 L of hydrogen gas will be produced when 15.9 g of hydrochloric acid reacts with excess zinc metal at STP.
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Plz help mee
Sandy soil
A) holds water well
B) contains clay and humus
C) has loose grains and few nutrients
Answers
A
think of this way: in Florida and many other costal places, people have sand in their backyards to limit flooding and things due to being so close to the ocean.
Exercise 1. Calculate the volume of a sample of ammonia (NH3) at 0°C and 1.00 atm if the sample occupies a volume of 0.25 L at 27°C and 0.850 atm.
Answers
The volume of a sample of ammonia at 0°C and 1.00 atm is approximately 0.232 L.
How to find the volume of a sample of ammonia (NH3)?
The relationship between the volume and temperature of a gas is described by Charles's law, which states that the volume of a gas is proportional to its temperature, provided that the pressure and number of moles of the gas remain constant.
Mathematically, this can be expressed as:
V1 / T1 = V2 / T2
Where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.
Given:
Initial volume = 0.25 L
Initial temperature = 27°C = 27 + 273.15 = 300 K
Initial pressure = 0.850 atm
Final temperature = 0°C = 273.15 K
Final pressure = 1.00 atm
To convert from one pressure to another, we can use the ideal gas law:
P1V1 = P2V2
Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Rearranging, we can find the final volume:
V2 = P1V1 / P2
V2 = (0.850 atm) * (0.25 L) / (1.00 atm)
V2 = 0.213 L
Finally, using Charles's law, we can find the volume of the sample at 0°C and 1.00 atm:
V2 / T2 = V1 / T1
V2 / 273.15 = V1 / 300
V1 = (V2 * 300) / 273.15
V1 = (0.213 L) * (300 K) / (273.15 K)
V1 = 0.232 L
So, the volume of a sample of ammonia at 0°C and 1.00 atm is approximately 0.232 L.
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Which of the following are general properties of acids?
I. has no reaction with metal
II. tastes sour
III. conducts electricity
Answers
Answer:
II. tastes sour III. conduct electricity
Explanation:
Let us go through all three statements.
Statement I says that acid doesn't react with a metal.
This is false because acids react with metals to form salt and hydrogen.
Statement II says that acids taste sour.
This statement is true. If you taste a lemon you realize that it's sour. This is due to the presence of citric acid in the lemon.
Statement III says that acids conduct electricity.
This statement is also true. If you mix an acid in the water, it dissociates many Hydrogen ions which act as charge carriers and help conduct electricity.
At high temperatures, the proton transfer rate is dominated by the barrier-crossing process. The barrier is 2.40 kJ/mol at 298 K, and the Arrhenius prefactor A=6.00 x1011 s1. At low temperatures, the rate is dominated by proton tunneling. In this case, the proton tunneling rate constant is ktunnel = 1.41 x1010 s-1. a. Calculate the classical rate of proton transfer, kclassical from the barrier at 298 K. b. At which temperature, Teritical, is ktunnel = kclassical? c. Do you expect Teritical to increase or decrease if deuterium (H) is substituted for hydrogen? Explain. d. If the spacing between the minima is doubled but the barrier height remains the same, do you expect Teritical to change? Explain.
Answers
Pre-exponential factor can be obtained from the Arrhenius pre-factor and using this we can calculate the classical rate of proton transfer.
Pre-exponential factor (A) is an important component of the Arrhenius equation, which was formulated by the Swedish chemist Svante Arrhenius in 1889. The pre-exponential factor is also known as the frequency factor. It represents the frequency of collisions between reactant molecules at a standard concentration. it is actually dependent on temperature because it is related to molecular collision, which is a function of temperature. because the pre-exponential factor depends on frequency of collisions, it is related to collision theory and transition state theory. The collision theory deals with gases and neglects to account for structural complexities in atoms and molecules.
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What would this mechanism look like?
Answers
Answer:
Not sure sorry :(
Explanation:
Which of the following would have the strongest ion-dipole interaction with water? Explain.
T13+
Cd²+
Na+
Answers
The strongest ion-dipole interaction with water is T13+ than Cd²+ than Na+.
What is ion dipole interaction?An ion-dipole interaction is defined as the intermolecular force of attraction present between the charged ion (anion or cation) and the molecule. It is mainly found in the solution where the ionic compounds dissolved in the polar solvents.
The strength of ion-dipole interactions is mainly dependent on the distance and the charge. Ionic charge goes on increasing moving across a period on the periodic table.
Since, charge on Ti is 3 and greater than Cd which is greater than Na.
Thus, we concluded that the strongest ion-dipole interaction with water is T13+ than Cd²+ than Na+.
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A container with a volume 2.0L is filled with a gas at a pressure of 1.5 atm. By decreasing the volume of the container to 1.0 L, what is the resulting pressure? Type in your answer using the correct number of significant figures . Remember to use formula for Boyles law; P1V1=P2V2
Need help with this question!!!
Answers
Answer:
P2 = 3
Explanation:
u know that:
V1 = 2.0L
P1 = 1.5 atm
V2 = 1.0L
P2 = ? (p1v1=p2v2)
1.5x2 = P2x1.0
3=P2x1.0 =>> 3.0 =P2
divided both side by 1.0 the remove 1.0 (left P2)
The pressure by decreasing the volume to 1 L will be \(P_2=3 \ atm\)
what will be a new pressure?The given data is that
Volume \(V_1=2 \ Litres\)
Pressure \(P_1=1.5\ atm\)
When volume is reduced to
\(V_2=1\ liters\)
By using Boyles Law
\(P_1V_1=P_2V_2\)
\(P_2=\dfrac{P_1V_1}{V_2}\)
\(P_2=\dfrac{2\times 1.5}{1} =3 \ atm\)
Thus the pressure by decreasing the volume to 1 L will be \(P_2=3 \ atm\)
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determine the oxidation state for each of the elements below. the oxidation state of ... iodine ... in ... diiodine pentoxide i2o5 ... is ... . the oxidation state of xenon in xenon trioxide xeo3 is . the oxidation state of manganese in manganese(?) oxide mn2o3 is .
Answers
The oxidation state of iodine in diiodine pentoxide (I₂O₅) is +5, the oxidation state of xenon in xenon trioxide (XeO₃) is +6, and the oxidation state of manganese in manganese(III) oxide (Mn₂O₃) is +3.
The oxidation state (or oxidation number) of an element is the number of electrons it has gained or lost to form a chemical bond.
The oxidation state of iodine in diiodine pentoxide (I₂O₅) is calculated as follows:
The compound is neutral, so the sum of the oxidation states of all the elements must be zero.
Let x be the oxidation state of iodine.
The total oxidation state due to the two iodine atoms in the molecule is 2x.
The total oxidation state due to the five oxygen atoms in the molecule is (-2) x 5 = -10.
The sum of the oxidation states is 2x - 10 = 0.
Solving for x, we get:
2x - 10 = 0
2x = 10
x = +5
The oxidation state of xenon in xenon trioxide (XeO₃) is calculated as follows:
The compound is neutral, so the sum of the oxidation states of all the elements must be zero.
Let x be the oxidation state of xenon.
The total oxidation state due to the xenon atom in the molecule is x.
The total oxidation state due to the three oxygen atoms in the molecule is (-2) x 3 = -6.
The sum of the oxidation states is x - 6 = 0.
Solving for x, we get:
x - 6 = 0
x = +6
The oxidation state of manganese in manganese(III) oxide (Mn₂O₃) is calculated as follows:
The compound is neutral, so the sum of the oxidation states of all the elements must be zero.
Let x be the oxidation state of the manganese.
The total oxidation state due to the two manganese atoms in the molecule is 2x.
The total oxidation state due to the three oxygen atoms in the molecule is (-2) x 3 = -6.
The sum of the oxidation states is 2x - 6 = 0.
Solving for x, we get:
2x - 6 = 0
2x = 6
x = +3
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A process that leads to the transformation of one set of chemical substances to another
A. Reactants
B. Chemical reaction
C. Law of conservation of mass
D. Products
Answers
Answer:
B . chemical. reaction
Explanation:
B chemical reaction
What is the molecular formula for a compound with a molar mass of 42.08g/mol and an empirical formula of ch2
Answers
Answer:
\(C_3H_6\)
Explanation:
Hello!
In this case, since the empirical formula is the smallest representation of the molecular formula, it is known that the times in which the empirical formula is into the molecular formula is a whole number and is computed by dividing the molar mass of the molecular formula by that of the empirical formula as shown below:
\(\frac{42.08g/mol}{12.01+1.01x2}= \frac{42.08g/mol}{14.03g/mol}=3\)
Thus, the molecular formula times the empirical formula by 3 to obtain:
\(C_3H_6\)
Regards!
What limitations occurs for chalk in vinegar chemistry pd lab experiment?
Also the precautions to take
Need this asap!!
Answers
Answer:
When conducting a chemistry lab experiment using chalk (calcium carbonate) in vinegar (acetic acid), there are several limitations and precautions to be aware of:
Limitations of chalk in vinegar chemistry experiment:
Reaction rate: The reaction between chalk and vinegar is relatively slow, which may require a longer observation period or higher concentration of vinegar to observe significant changes within a reasonable time frame.
Solubility: Chalk may not dissolve completely in vinegar, resulting in incomplete reaction or difficulty in obtaining accurate results.
Product formation: The reaction between chalk and vinegar produces carbon dioxide gas, water, and calcium acetate. The carbon dioxide gas may escape into the atmosphere, leading to loss of product and inaccurate measurements.
pH: Chalk is a basic substance, and the reaction with vinegar, which is acidic, may result in neutralization, leading to a decrease in the overall acidity of the reaction mixture.
Precautions to take in chalk in vinegar chemistry experiment:
Ventilation: The reaction between chalk and vinegar produces carbon dioxide gas, which can displace air and potentially cause asphyxiation in a closed or poorly ventilated area. Conduct the experiment in a well-ventilated area or under a fume hood to ensure adequate air circulation.
Eye and skin protection: Vinegar is an acid and can cause skin and eye irritation. Wear appropriate personal protective equipment (PPE), such as gloves and goggles, to protect yourself from contact with vinegar or any other chemicals used in the experiment.
Chemical handling: Handle the chemicals, including chalk and vinegar, with care, following proper lab safety protocols. Avoid ingestion, inhalation, or direct contact with the chemicals, and dispose of them properly according to local regulations.
Accuracy in measurements: Use calibrated and accurate measuring tools, such as graduated cylinders or burettes, to measure the amount of chalk, vinegar, and other reagents accurately. This will ensure the reliability and accuracy of the experimental results.
Observations: Make careful and detailed observations during the experiment, noting any changes in appearance, gas evolution, or other relevant observations. Take measurements at appropriate intervals and record the data accurately for analysis and interpretation.
It is important to follow good laboratory practices, including proper chemical handling, accurate measurements, and cautious observations, to ensure safe and reliable results in a chalk in vinegar chemistry lab experiment. Consult with a qualified instructor or supervisor for specific guidelines and precautions related to your experiment.
Identify reactions types and balancing equations
Answers
Balance the following chemical equations:
1. N2 + 3 H2 → 2 NH3
Ex: Synthesis reaction
2. 2 KClO3 → 2 KCl + 3 O2
Single Replacement reaction
3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl
Decomposition reaction
4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2
Double Replacement reaction
5. 2 H2 + O2 → 2 H2O
Combustion reaction
6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2
Synthesis reaction
7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2
Decomposition reaction
8. C3H8 + 5 O2 → 3 CO2 + 4 H2O
Combustion reaction
9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O
Double Replacement reaction
10. 4 P + 5 O2 → 2 P2O5
Synthesis reaction
11. 2 Na + 2 H2O → 2 NaOH + H2
Single Replacement reaction
12. 2 Ag2O → 4 Ag + O2
Decomposition reaction
13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O
Combustion reaction
14. 2 KBr + MgCl2 → 2 KCl + MgBr2
Double Replacement reaction
15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O
Double Replacement reaction
16. C5H12 + 8 O2 → 5 CO2 + 6 H2O
Combustion reaction
17. 4 Al + 3 O2 → 2 Al2O3
Synthesis reaction
18. Fe2O3 + 2 Al → 2 Fe + Al2O3
Single Replacement reaction
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Iron and Chlorine gas react according to the following balanced equation: 2 Fe(S) + 3 Cl2 (g) 2 FeCl3(s) a) Calculate the molar mass in grams of “one mole” of each of the following: Fe ________ Cl2 __________________ FeCl3 ______________
Answers
The molar mass in grams of "one mole" of each substance is:
Fe: 55.845 g/mol
\(Cl_2\): 70.906 g/mol
\(FeCl_3\): 162.204 g/mol
To calculate the molar mass in grams of "one mole" of each substance, we need to determine the atomic masses of the elements involved in the equation.
The atomic mass of iron (Fe) is 55.845 g/mol.
For chlorine (\(Cl_2\)), we need to consider that the molar mass of \(Cl_2\) is twice the atomic mass of chlorine because the formula shows that two chlorine atoms combine to form one molecule of \(Cl_2\). The atomic mass of chlorine is 35.453 g/mol, so the molar mass of \(Cl_2\) is 2 * 35.453 g/mol = 70.906 g/mol.
The formula for iron(III) chloride (\(FeCl_3\)) indicates that one mole of \(FeCl_3\)contains one mole of iron and three moles of chlorine. Therefore, we can calculate the molar mass of \(FeCl_3\)by summing the atomic masses of iron and chlorine:
Molar mass of \(FeCl_3\)= (1 * atomic mass of Fe) + (3 * atomic mass of Cl)
Substituting the values, we have:
Molar mass of \(FeCl_3\) = (1 * 55.845 g/mol) + (3 * 35.453 g/mol)
= 55.845 g/mol + 106.359 g/mol
= 162.204 g/mol
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select all that apply which of the following options correctly describe the structure shown? select all that apply.
Answers
which element forms the skeleton of this polymer?
a.carbon
b.copper
c.hydrogen
d.oxygen
Answers
Answer: A - Carbon
Explanation: Hope this helps!
A). Carbon
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The correct value of m, n, x and y to obtain a balanced equation is?
m B2O3(s) + n HF(l) → x BF3(g) + y H2O(l)
a.
m=1, n=1, x=1 and y=1
b.
m=1, n=6, x=2 and y=3
c.
m=1, n=1.5, x=1 and y=1
d.
m=2, n=12, x=4 and y=6
Answers
Answer:
d
Explanation:
answer d makes the equation balance
Saccharin is a weak organic base with a Kb of 4.80 × 10-3. A 0.900-g sample of saccharin dissolved in 45.0mL of water has a pH of 12.310. What is the molar mass of saccharin?
Answers
The molar mass of saccharin is 0.900 g / [Sac].
Saccharin is a weak organic base with a Kb of 4.80 × 10-3 and we are given that a 0.900-g sample of saccharin dissolved in 45.0mL of water has a pH of 12.310.
We are supposed to calculate the molar mass of saccharin.
The formula for finding the molar mass of a substance is:Molar mass = (mass of substance) / (number of moles).
We are given that the Kb of saccharin is 4.80 × 10-3.
Since it is a base, it reacts with water to form the conjugate acid of saccharin (HSac) and hydroxide ions (OH-).
The balanced chemical equation for this reaction is: C7H4NO3S + H2O → HSac + OH-.
We can use the Kb value to find the concentration of the hydroxide ions produced:Kb = [HSac][OH-] / [Sac].
Initial concentration of saccharin, [Sac] = (0.900 g) / (Molar mass) = 0.900 / M Molar mass = 0.900 / [Sac].
Now we can use the given pH value to find the concentration of the hydroxide ions using the expression:pH = 14 - pOHpOH = 14 - pH[OH-] = 10^-pOH.
Substitute these values in the expression for Kb and solve for [HSac]:Kb = [HSac][OH-] / [Sac][HSac] = (Kb x [Sac]) / [OH-]
Now we can substitute the values we have into the expression for the molar mass:Molar mass = (mass of substance) / (number of moles)Number of moles = [Sac]Molar mass = 0.900 / [Sac].
Therefore, the molar mass of saccharin can be calculated by first finding the concentration of hydroxide ions produced using the pH value, then using the Kb value to find the concentration of the conjugate acid of saccharin, and finally using these values to find the molar mass of saccharin using the formula Molar mass = (mass of substance) / (number of moles).
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What are some other molecules in the plasma membrane explain their function.
43 points! ILL MARK BRAINLIEST
Answers
Function of a lipid is storing energy signaling and acting as cell membranes.
Function of a protein is that it helps build and repair yours body’s tissues
Function of cholesterol is that it serves as a precursor for the synthesis of substances like hormones, bile acids, and vitamin D
Function of carbohydrates is that it provides you with energy and it’s a fuel source for your brain.
Explanation: Have a good rest of your day!
The plasma membrane is primarily made up of phospholipid bilayers. Other molecules, such as the steroid cholesterol, are also present.
What is plasma membrane?The plasma membrane, also referred to as the cell membrane, is the membrane found in all cells that separates the cell's interior from its surroundings.
A cell wall is basically attached to the plasma membrane on the outside of bacterial and plant cells.
Membrane biogenesis is the process by which plasma membranes form. Proteins and lipids are created first in the rough endoplasmic reticulum and then in the smooth endoplasmic reticulum.
These are then taken to the Golgi complex to be modified.
The plasma membrane is primarily made up of phospholipid bilayers.
Other compounds discovered in the membrane have included the steroid cholesterol, that also works to help the membrane maintain its shape, and transport proteins, which allow substances to pass through the membrane.
Thus, these are some other materials present in cell membrane.
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F and G react together. When the concentration of F is tripled and the concentration of G remains constant, there is a nine-fold increase in the rate of the reaction. What is the order of the reaction with respect to F?
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There is a nine-fold rise in the pace of the reaction when the concentration of F is tripled but the concentration of G stays the same. The response is in the second order relative to F.
What happens to rate of reaction if concentration is tripled?If you increase one reactant's concentration in a third order reaction involving two reactants by three times, the rate rises by a factor of three. If a reactant is first order, its concentration will cause a doubling in the reaction's rate; a tripling in the reaction's rate, etc. If a reactant is third order, its rate of reaction will increase by a factor of 8 when its concentration is doubled (23 = 8), etc.
The concentration of a reactant does not impact the rate. The rate remains unchanged even if the concentration is doubled. The given rate law needs to be written first. The concentrations of A and B will be increased by three times each after that.
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