Which of the following is a trinomial?x-1O A.8O B. 2x+4O c. V11x-7D. 5x2 + 3x + 6

Answer:

$288

Step-by-step explanation:

20% of 360 is 72 d 360 minus 72 is 288

Answer:

The table is now 288

Y = 360(1 - 0.2)

Y = 360(0.8)

Y = 288

To clarify, 20% of 360 is 72, so 72 was taken off with the discount.

Answer:

The rate is 5 dollars per student.

Step-by-step explanation:

The rate per student can be found with \(\frac{dollars}{student}\):

\(\frac{150dollars}{30student}=5\frac{dollars}{student}\\\\\frac{350dollars}{70student}=5\frac{dollars}{student}\)

The rate is 5 dollars per student.

9514 1404 393

Answer:

  150°

Step-by-step explanation:

The size of one interior angle of a regular n-gon is ...

  interior angle = 180° - 360°/n

For n=12, this measure is ...

  = 180° -360°/12 = 180° -30°

  interior angle = 150°

Answer:

150

Step-by-step explanation:

Answer:

5) 6 units up and 8 units right

Step-by-step explanation:

Answer:

\(\Huge\boxed{-8}\)

Step-by-step explanation:

Hello there!

When given two ordered pairs we can use the slope formula to solve for the slope

\(m=\frac{y_2-y_1}{x_2-x_1}\)

where m = slope

All we have to do is plug in the y and x values into the formula and calculate the slope

\(m=\frac{1-9}{7-6} \\1-9=-8\\7-6=1\\\frac{-8}{1} =-8\\m=-8\)

So we can conclude that the slope of the line that passes through the points (6,9) and (7,1) is -8

The vertex form of the quadratic equations in standard form are, respectively:

Case 9: y = 2 · (x + 2)² - 12

Case 10: y = - (1 / 2) · (x + 3 / 4)² + 33 / 32

Case 11: y = 3 · (x - 4 / 3)² - 16 / 3

Case 12: y = - 3 · (x - 3)²

Case 13: y = (x - 4)² + 3

Case 14: y = (x - 1)² - 7

Case 15: y = (x + 3 / 2)² - 9 / 4

Case 16: 2 · (x + 1 / 4)² - 1 / 8

Case 17: y = 2 · (x - 3)² - 7

Case 18: y = - 2 · (x + 1)² + 10

In this problem we find ten cases of quadratic equation in standard form, whose vertex form can be found by a combination of algebra properties known as completing the square. Completing the square consists in simplifying a part of the quadratic equation into a power of a binomial.

The two forms are introduced below:

Standard form

y = a · x² + b · x + c

Where a, b, c are real coefficients.

Vertex form

y - k = C · (x - h)²

Where:

Now we proceed to determine the vertex form of each quadratic equation:

Case 9

y = 2 · x² + 4 · x - 4

y = 2 · (x² + 2 · x - 2)

y = 2 · (x² + 2 · x + 4) - 12

y = 2 · (x + 2)² - 12

Case 10

y = - (1 / 2) · x² - 3 · x + 3

y = - (1 / 2) · [x² + (3 / 2) · x - 3 / 2]

y = - (1 / 2) · [x² + (3 / 2) · x + 9 / 16] + (1 / 2) · (33 / 16)

y = - (1 / 2) · (x + 3 / 4)² + 33 / 32

Case 11

y = 3 · x² - 8 · x

y = 3 · [x² - (8 / 3) · x]

y = 3 · [x² - (8 / 3) · x + 16 / 9] - 3 · (16 / 9)

y = 3 · (x - 4 / 3)² - 16 / 3

Case 12

y = - 3 · x² + 18 · x - 27

y = - 3 · (x² - 6 · x + 9)

y = - 3 · (x - 3)²

Case 13

y = x² - 8 · x + 19

y = (x² - 8 · x + 16) + 3

y = (x - 4)² + 3

Case 14

y = x² - 2 · x - 6

y = (x² - 2 · x + 1) - 7

y = (x - 1)² - 7

Case 15

y = x² + 3 · x

y = (x² + 3 · x + 9 / 4) - 9 / 4

y = (x + 3 / 2)² - 9 / 4

Case 16

y = 2 · x² + x

y = 2 · [x² + (1 / 2) · x]

y = 2 · [x² + (1 / 2) · x + 1 / 16] - 2 · (1 / 16)

y = 2 · (x + 1 / 4)² - 1 / 8

Case 17

y = 2 · x² - 12 · x + 11

y = 2 · (x² - 6 · x + 9) - 2 · (7 / 2)

y = 2 · (x - 3)² - 7

Case 18

y = - 2 · x² - 4 · x + 8

y = - 2 · (x² + 2 · x - 4)

y = - 2 · (x² + 2 · x + 1) + 2 · 5

y = - 2 · (x + 1)² + 10

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The general solution of the partial differential equation is:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

The partial differential equation (PDE) is given as:

Uxx = (1/2)Ut with the boundary and initial conditions as 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)

Assume that the solution can be written as a product of two functions:

U(x, t) = X(x)T(t)

Substituting this into the PDE, we have:

X''(x)T(t) = (1/2)X(x)T'(t)

Dividing both sides by X(x)T(t), we get:

(X''(x))/X(x) = (1/2)(T'(t))/T(t)

Since the left side only depends on x and the right side only depends on t, both sides must be equal to a constant, denoted as -λ²:

(X''(x))/X(x) = -λ²

(1/2)(T'(t))/T(t) = -λ²

Simplifying the second equation, we have:

T'(t)/T(t) = -2λ²

Solving the second equation, we find:

T(t) = Ce^(-2λ²t)

Applying the boundary condition U(0, t) = 0, we have:

U(0, t) = X(0)T(t) = 0

Since T(t) ≠ 0, we must have X(0) = 0.

Applying the boundary condition U(3, t) = 0, we have:

U(3, t) = X(3)T(t) = 0

Again, since T(t) ≠ 0, we must have X(3) = 0.

Therefore, we can conclude that X(x) must satisfy the following boundary value problem:

X''(x)/X(x) = -λ²

X(0) = 0

X(3) = 0

The general solution to this ordinary differential equation is given by:

X(x) = Asin(λx) + Bcos(λx)

Applying the initial condition U(x, 0) = 5*sin(4πx), we have:

U(x, 0) = X(x)T(0) = X(x)C

Comparing this with the given initial condition, we can conclude that T(0) = C = 5.

Therefore, the complete solution for U(x, t) is given by:

U(x, t) = Σ [Aₙsin(λₙx) + Bₙcos(λₙx)]*e^(-2(λₙ)²t)

where:

Σ represents the summation over all values of n

λₙ are the eigenvalues obtained from solving the boundary value problem for X(x).

To find the eigenvalues λₙ, we substitute the boundary conditions into the general solution for X(x):

X(0) = 0: Aₙsin(0) + Bₙcos(0) = 0

X(3) = 0: Aₙsin(3λₙ) + Bₙcos(3λₙ) = 0

From the first equation, we have Bₙ = 0.

From the second equation, we have Aₙ*sin(3λₙ) = 0. Since Aₙ ≠ 0, we must have sin(3λₙ) = 0.

This implies that 3λₙ = nπ, where n is an integer.

Therefore, λₙ = (nπ)/3.

Substituting the eigenvalues into the general solution, we have:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

where Aₙ are the coefficients that can be determined from the initial condition.

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The following are binomial random variable,

A)A Roll a fair die 5 times and X = the number of rolls that land showing a "4", is a binomial random variable.

B) Roll 5 fair dice at once and let Z = the number of dice that land showing an even value (2, 4, or 6), is a binomial random variable.

C) Roll 5 fair dice at once and let Y = the number of dice that land showing a "4" , is a binomial random variable.

A random binomial variable should satisfy the following conditions:

1. The number of trials are defined or fixed.

2. Each trial is independent of others.

3. The probability of success is same in all trials.

4. There should be only two outcomes in each trial.

Lets we evaluate the options based on the above conditions:

(A) Rolling fair dice 5 times have 5 trials, each rolling is independent, probability of 4 is 1/6 in all cases and the dice will either land 4 or will not land 4. So, X will have values from 0 to 5, 0 when dice doesn't land 4 even once in 5 rolls and 5 when dice land 4 in all rolls. This variable satisfies the condition to be a random binomial variable. So, X is a random binomial variable.

(B)For rolling 5 dices at once, the number of trials is 1 and fixed and the outcomes are 0 dice with even number to all 5 dices with even number. If the dices are rolled multiple times each trial will be independent of each other and the probability of success will be same for each trial. So the variable Z is a random binomial variable as it satisfies all the conditions.

(C)For rolling 5 dices at once, the number of trials is 1 and fixed and the outcomes are 0 dice land with 4 to all 5 dices land with 4. If the dices are rolled multiple times each trial will be independent of each other and the probability of success will be same for each trial. So the variable Y is a random binomial variable as it satisfies all the conditions.

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Answer: The function would have a minimum value because the least you will ever have is 0$. It cannot go below 0, so that is the minimum. However, depending on how much time has passed, the maximum amount of money you have can change. It can always go up more, so there is no set maximum.

Step-by-step explanation:

The two positive numbers are 55, and 55.

Given that,

Two positive numbers whose product is a maximum and whose sum is 110.

To Find :  Two positive real numbers with a maximum product whose sum is 110.

x + y = 110

x = 110-y

Area = xy = (110-y)y

A = 110y-y^2

Maximum A occurs when y = -b/(2a) = -110/(2*-1) = 55

x + y = 110

x + 55 = 110

x = 55

and y is also 55.

Therefore, the two positive numbers are 55, and 55.

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Answer:

The answer is No solution

Step-by-step explanation:

Solve 3x+ -1/3y = 20 for x:

3x+ −1/3y+1/3y=20+1/3y(Add 1/3y to both sides)

3x=1/3y+20

\(3=\frac{1}{3}\frac{}{} y\frac{+20}{3}\)   Divide both sides by 3

x\(=\frac{1}{9} y +\frac{20}{3}\)

Substitute 1/9y+20/3  for x in−18x+2y=−30

−18x+2y=−30

-18\((\frac{1}{9}y +\frac{20}{3} +2y=-30\))

−120=−30 (Simplify both sides of the equation)

−120+120=−30+120 (Add 120 to both sides)

0=90

Answer:

b

Step-by-step explanation:

i took the test myself

Answer:

B

Step-by-step explanation:

Edge 2022

A balanced and proportionate likeness observed in two sides of an item is characterized as symmetry. The shape can be completed as shown below.

A balanced and proportionate likeness observed in two sides of an item is characterized as symmetry. It signifies that one side is a mirror image of the other. The line of symmetry is the imaginary line or axis along which you can fold a figure to produce the symmetrical halves.

The shape can be completed as shown below, so that the complete shape is symmetrical about the given axis.

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Answer:

240 ounces is your answer

The transformation illustrated in the figure is translation.

Translation is a Transformation process in which the size or shape of a figure is not changed rather it only changes the coordinates of the vertices that make up that shape by moving them from one point to another.

Analysis:

Both shapes are congruent, since all the vertices remain in their respective positions even though they were moved and no change in the shape or size, then the transformation process is Translation.

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Answer:

5, -9

Step-by-step explanation:

(x - 5)(x + 9) = 0    These are factors, to get the roots, just set each one equal to zero

x - 5 = 0

x = 5

x + 9 = 0

x = -9

Answer:

Postive 5 and negative 9.

Step-by-step explanation:

So remember, all we have to do is set each of the parethese to zero and solve. It should look like this:

x-5=0 and x+9=0

For the first equation we have made, jsut add 5 to both sides so x is alone. This will get you:

x=5

So the first answer for x is 5.

Now lets solve our second equation and find the second answer for x.

So all we have to do for this one is subtract 9 from both sides. This should get you:

x=-9

So now we know that our two answers for x is 5 and -9.

These two answers seem to be on your list as #2 answer and #3 answer.

Answer:

10

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

OMG I finally know one on here!

The number of people that nare expected to vote in the election is 260,000. people.

Simply put, a fraction is a portion of a whole. Mathematically, the number is represented as a quotient with split numerator and denominator. The numerator and denominator of a simple fraction are both integers. On the other hand, a complex fraction has a fraction in either the numerator or the denominator.

In this situation, the pre-election survey showed that two out of every three eligible voters would cast ballots in the county election and there are 390,000 eligible voters in the county.

The number of people expected to vote will be:

= Fraction of expected voters × Total number of people

= 2/3 × 390000

= 2 × 130000

= 260000

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The value of x for each item is given as follows:

28. x = 5.

29. x = 3.44.

For item 28, we apply the crossing chord theorem, which states that the products of the parts of the chords are equal, hence the value of x is obtained as follows:

16x = 10 x 8

16x = 80

x = 5.

For item 29, we apply the two secant theorem, hence the value of x is obtained as follows:

10(x + 10) = 12(12 + 25)

10x + 100 = 444

10x = 344

x = 3.44.

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Answer:

i think the answer is 1/10

Answer:

y = -6

Step-by-step explanation:

y=acos(bx+c)+d

d = -6  .. vertical shift

midline: y = -6

Answer:

40%

Step-by-step explanation:

Every week you he buys 4 number of 2 Litres bottle of lemonade.

Thus, let's say cost of each bottle is X.

This means he total cost is 4X

Now, total litres = 4 × 2 = 8 litres

Thus, cost per litre = 4X/8 = ½X

Now, we are told that Last week the bottles on the shelf were limited edition “2.5 litres for the price of 2 litres” bottles ".

This means that now, it is cheaper.

However, the supermarket also had a “buy 3 bottles, get another one free” offer.

Now since he buys 8 litres weekly, now since it's 2.5 L bottle, he will buy 3 since he will be given 1 free for every 3 he buys.

Thus, total litres he is paying for = 2.5 × 3 = 7.5 litres

Thus, cost per bottle is; 3X

Since he is getting 1 bottle free, then total bottle he gets is; 7.5 L + 2.5 L = 10L

Thus;

cost per litre is now; 3X/10

Difference in costs per litre is;

½X - 3X/10 = X/5

percentage of the cost of four bottles of lemonade lower than usual last week = (X/5)/(½X) × 100% = 2/5 × 100% = 40%

The algebraic expression that represents the number of beads per necklace is given as follows:

250/8.

The algebraic expression representing the number of beads per necklace is obtained applying the proportion in the context of the problem.

The proportion is given by the division of the total number of beads by the total number of necklaces, as follows:

Beads per necklace = Number of beads / Number of necklaces.

The parameters for this problem are given as follows:

Hence the algebraic expression that represents the number of beads per necklace is given as follows:

250/8.

(dividing the number of beads by the number of necklaces given in this problem).

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The calculated mean price is a sample mean and it is denoted by x.

Given that

Mean price of paintings = $3550

Number of paintings = 20

Population is defined as the overall collection from which a sample or observations are taken.

The sample is small or less number of observations that we take from a large population to perform data analysis.

In the given data, all the paintings at the art fair are population while the number of paintings that the art collector bought is a sample.

Hence,

The calculated mean price is a sample mean and it is denoted by x.

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Answer:

x = 0 , y = 0 , z = -3

Step-by-step explanation:

Solve the following system:

{x - 6 y + 4 z = -12 | (equation 1)

x + y - 4 z = 12 | (equation 2)

2 x + 2 y + 5 z = -15 | (equation 3)

Swap equation 1 with equation 3:

{2 x + 2 y + 5 z = -15 | (equation 1)

x + y - 4 z = 12 | (equation 2)

x - 6 y + 4 z = -12 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - (13 z)/2 = 39/2 | (equation 2)

x - 6 y + 4 z = -12 | (equation 3)

Multiply equation 2 by 2/13:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - z = 3 | (equation 2)

x - 6 y + 4 z = -12 | (equation 3)

Subtract 1/2 × (equation 1) from equation 3:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - z = 3 | (equation 2)

0 x - 7 y + (3 z)/2 = -9/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+0 y - z = 3 | (equation 2)

0 x - 14 y + 3 z = -9 | (equation 3)

Swap equation 2 with equation 3:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x - 14 y + 3 z = -9 | (equation 2)

0 x+0 y - z = 3 | (equation 3)

Multiply equation 3 by -1:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x - 14 y + 3 z = -9 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 3 × (equation 3) from equation 2:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x - 14 y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 2 by -14:

{2 x + 2 y + 5 z = -15 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{2 x + 0 y+5 z = -15 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Subtract 5 × (equation 3) from equation 1:

{2 x+0 y+0 z = 0 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 0 | (equation 1)

0 x+y+0 z = 0 | (equation 2)

0 x+0 y+z = -3 | (equation 3)

Collect results:

Answer: {x = 0 , y = 0 , z = -3

Step-by-step explanation:

The equation that shows the point-slope form of the line passing through (3, 2) with a slope of (1/2) is:

y - 2 = (1/2)(x - 3)

In the point-slope form of a linear equation, the formula is y - y1 = m(x - x1), where (x1, y1) represents a point on the line, and m represents the slope of the line. By substituting the given values into the formula, we can determine the correct equation.

In this case, the given point is (3, 2) and the slope is (1/2). Plugging these values into the formula, we get:

y - 2 = (1/2)(x - 3)

This equation represents the line passing through the point (3, 2) with a slope of (1/2). It is in the point-slope form, which allows us to easily determine the equation of a line based on a given point and slope.

Therefore, the correct equation is y - 2 = (1/2)(x - 3).

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Answer: B

Step-by-step explanation: