Which of the following is a heterogeneous mixture?
Opotting soil
Tap Water
Ochlorine gas (CI)
Otable salt NaCl

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

843.75

Explanation:

ok so the moon radius is 1,350,000meters right so meters to miles

1 mile=1600meters

1,350,000/1600=843.75

843.75 miles

Hope that helps!

Merry Christmas!

Moles of NO formed : 0.833

Given

2.5 moles of NO2

Required

moles of NO formed

Solution

Reaction

3 NO₂(g) + H₂O(l) = 2 HNO₃(aq) + NO(g)

The reaction coefficient in a chemical equation shows the mole ratio of the compounds in the reactants and products

From the equation, mol ratio of NO₂ and NO = 3 : 1, so moles of NO :

\(\tt moles~NO=\dfrac{1}{3}\times 2.5\\\\moles~NO=0.833\)

Answer:

A

Explanation:

The sun is larger than the planets in our solar system and has far more mass and gravity than the planets.

The calculate the age of the rock sample values, the age of the rock sample can be determined.

we can use the concept of radioactive decay and the ratio of 87Sr to 87Rb. Since 87Sr is a stable product of the beta decay of 87Rb, the increase in the ratio of 87Sr to 87Rb over time reflects the decay of 87Rb.

The ratio of 87Sr to 87Rb in ancient samples is given as 0.0205. This means that for every 0.0205 moles of 87Rb, there is one mole of 87Sr.

Since the half-life of 87Rb is 4.75×10^10 years, after each half-life, half of the 87Rb would have decayed into 87Sr. Therefore, the ratio of 87Sr to 87Rb increases by a factor of 2.

To determine the age of the rock sample, we can calculate the number of half-lives that have occurred based on the change in the ratio. The ratio of 0.0205 corresponds to 1 half-life, 0.041 corresponds to 2 half-lives, 0.082 corresponds to 3 half-lives, and so on.

By taking the logarithm of the ratio change and dividing it by the logarithm of 2 (since the ratio doubles with each half-life), we can find the number of half-lives.

Using this information, the age of the rock sample can be calculated as follows:

Age (in years) = number of half-lives × half-life of 87Rb

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Answer: conducting impulses

Explanation:

just did it on edge

Answer:

c. conducting impulses.

Explanation:

got it right on edg, hope this helps!

Answer:25,06 kJ of energy must be added to a 75 g block of ice.

ΔHfusion(H₂O) = 6,01 kJ/mol.

T(H₂O) = 0°C.

m(H₂O) = 75 g.

n(H₂O) = m(H₂O) ÷ M(H₂O).

n(H₂O) = 75 g ÷ 18 g/mol.

n(H₂O) = 4,17 mol.

Q = ΔHfusion(H₂O) · n(H₂O)

Q = 6,01 kJ/mol · 4,17 mol

Q = 25,06 kJ.

Explanation:

how many there are of each element for example H20 is 2 hydrogen atoms plus 1 oxygen atom

A 52gram sample of water that has an initial temperature of 10C absorbs 4130 joules. If the specific heat of water is 4.184 j.  25°C is the final temperature of the water.

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using several temperature scales, which traditionally drew on different reference locations.

The most popular scales include the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the scale of Fahrenheit (°F), or the Kelvin scale (K), with the latter being mostly used for scientific purposes.

q = m×c×ΔT

4130 = 52×4.184×(T2- 10C)

T2= 25°C  

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Answer:

0.87mole

Explanation:

The reaction equation is given as;

    4Fe + 3O₂  →  2Fe₂O₃

Number of moles of Fe₂O₃ in 138.5g

To solve this problem;

 Number of moles = \(\frac{mass}{molar mass}\)

Molar mass of Fe₂O₃ = 2(56) + 3(16) = 160g/mol

 Now;

          Number of moles  = \(\frac{138.5}{160}\)   = 0.87mole

Answer: 2.5 lit

Explanation:

Answer:

D) AlCl₃(aq) + 3 KOH(aq) → Al(OH)₃(s) + 3 KCl(aq)​

Explanation:

Which equation represents a double replacement reaction?

A) 2 Al(s) + 6 HCl(aq) → 2 AlCl₃(aq) + 3 H₂(g)

No, this is a single replacement reaction, in which Al replaces H in its acid.

B) 2 Al(s) + 3 Cl₂(g) → 2 AlCl₃(s)

No, this is a synthesis reaction, in which two simple substances combine to form a compound.

C) 2 AlCl₃(s) → 2 Al(s) + 3 Cl₂(g)

No, this is a decomposition reaction, in which a compound decomposes into simple substances.

D) AlCl₃(aq) + 3 KOH(aq) → Al(OH)₃(s) + 3 KCl(aq)​

Yes, this is a double replacement reaction, in which both reactants exchange their cations and anions.

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From Practical perform shown below, It conclude that  If you increase the temperature of a reaction, then the reaction rate will increase because particles experience more collisions at higher temperatures.

The effects of temperature and a reactant’s particle size on reaction rate.

Step 1: Gather Materials250 mL graduated cylinder

   Thermometer

   Water

   Timer

   Four 250 mL beakers

   Seven 1,000 mg effervescent tablets

Step 2: Measure the Reaction Rate at ≈ 20°C (Room Temperature)

a) Using a graduated cylinder, fill a 250 mL beaker with 200 mL of water.

b) Measure the temperature of the water and record it in the correct row of Table A.

c) Reset the timer. Start the timer as you place a full tablet into the beaker.

d) Record the reaction time on the Data Sheet in the correct row of Table A.

e) Compute the reaction rate to the nearest mg/L/sec. Record it in the last column of Table A.

Step 3: Measure the Reaction Rate at ≈ 40°C Repeat Step 2, heating the water to approximately 40°C using a hot plate during sub-step a.

Step 4: Measure the Reaction Rate at ≈ 65°CRepeat Step 2, heating the water to approximately 65°C using a hot plate during sub-step a.

Step 5: Measure the Reaction Rate at ≈ 5°CRepeat Step 2, chilling the water to approximately 5°C inside an ice bath during sub-step a. (To create an ice bath, place 100 mL of ice and 100 mL of water in a 600 mL beaker of ice water and wait until the temperature reaches approximately 5°C. To save time, you may wish to set up the ice bath, using an additional 250 mL beaker, while working on Step 4.)Variation of Particle Size

Step 6: Measure the Reaction Rate for a Full Tablet

a) Using a graduated cylinder, fill a 250 mL beaker with 200 mL of water.

b) Reset the timer. Start the timer as you place the tablet in the beaker.

c) Record the reaction time on the Data Sheet in the appropriate row of Table B.

d) Compute the reaction rate to the nearest mg/L/sec. Record it in the last column of Table B.

Step 7: Measure the Reaction Rate for a Partially Broken Tablet Repeat Step 6, but this time break the tablet into eight small pieces on a piece of filter paper. Make sure to place all of the pieces into the beaker at the same time.

Step 8: Measure the Reaction Rate for a Crushed Tablet Repeat Step 6, but this time crush the tablet into tiny pieces on a piece of filter paper. Make sure to place all of the pieces into the beaker at the same time.

Explanation:

According to chemical equilibrium,if you increase the temperature of a reaction, then the reaction rate will increase because particles experience more collisions at higher temperatures.

Chemical equilibrium is defined as the condition which arises during the course of a reversible chemical reaction with no net change in amount of reactants and products.A reversible chemical reaction is the one wherein the products as soon as they are formed react together to produce back the reactants.

At equilibrium, the two opposing reactions which take place take place at equal rates and there is no net change in amount of the substances which are involved in the chemical reaction.At equilibrium, the reaction is considered to be complete . Conditions which are required for equilibrium are given by quantitative formulation.

Factors which affect chemical equilibrium are change in concentration , change in pressure and temperature and presence of catalyst.

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Answer:

B. po

Explanation:

sana po makatulong

Answer: D - 126.4g

Explanation:  

% Yield = Actual Yield/Theoretical Yield

38% = Actual Yield/332.5

38/100 = Actual Yield/332.5

(.38)(332.5) = 126.35 g = 126.4 g Actual Yield

Answer:

is D. the correct answer

Explanation:

I'm not sure if it is. Please let me know if I'm mistaking.

Answer:

melting

Explanation:

Answer:

A.

Explanation:

I just know.

Answer:

a.

Explanation:

The rate expression is k [BF₃]²[NH₃], overall order is 3, rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.

The rate expression for this reaction can be written as:

Rate = k [BF₃]^m[NH₃]^n

The method of initial rates can be used to calculate the values of m and n. When we compare experiments 1 and 2, notice that halving the concentration of [NH3] reduces the initial rate of reaction. This suggests that the reaction is first order in terms of [NH3], implying that n = 1.

When comparing experiments 1 and 3, notice that increasing the concentration of [BF3] by a factor of 2.5 increases the initial rate of reaction by a factor of 9.39 (i.e., 2.13/0.227). This shows that the reaction is about second order in relation to [BF3], i.e., m 2.

Therefore, the rate expression for the reaction is:

Rate = k [BF₃]²[NH₃]

The overall order of the reaction is m + n = 3.

Using the data from experiment 4, substitute the values and solve for k:

Rate = k [BF₃]²[NH₃]

1.02 × 10-¹ = k (3.00 × 10⁻¹)² (1.00 x 10⁻¹)

k = 1.02 × 10-¹ / (3.00 × 10⁻¹)² (1.00 x 10⁻¹)

k = 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹

Therefore, the rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.

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Chlorofluorocarbons (CFCs) are man-made chemicals containing chlorine and fluorine that cause ozone molecules to break down. Thus, option B is the answer.

Chlorofluorocarbons are non-toxic, synthetic compounds that contain atoms of Chlorine, Fluorine and Carbon. They are commonly used in the manufacture of aerosol sprays and are also used as solvents and refrigerants. CFCs were first introduced in 1928 by General Motors Company for its refrigerators.

While CFCs are very safe to use in most applications and are stable in the lower atmosphere, these chemicals when released to the upper atmosphere can cause significant reactions. CFCs when released into the upper atmosphere can lead to the destruction of the ozone molecules followed by the release of the UV radiation into the atmosphere.

Thus, CFCs are man-made chemicals which cause ozone molecules to break down.

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Answer: D. None of these will increase the half life.

Explanation:

Half life is the amount of time taken to decay to half of its original value.  The half life is related to rate constant by the following relation for a first order reaction:

\(t_{\frac{1}{2}}=\frac{0.693}{k}\)

As half life is independent of concentration , temperature and pressure, none of these factors would affect the half life.

Thus in the reaction,  \(SO_2Cl_2 \rightarrow SO_2(g)+Cl_2(g)\) following first order kinetics, none of the factors will increase the half life.

Answer:

The mass of 2 moles of carbon tetrachloride is

307.646 grams

Explanation:

The chemical formula for Carbon tetrachloride is \(\ce{CCl_4}\).  It contains 1 carbon atom and 4 chlorine atoms.

Carbon tetrachloride is formed due to the covalent bond between one carbon atom with four chlorine atoms.

In order to find the mass of 2 moles of \(\ce{CCl_4}\) we need to determine the molar mass.

The molar mass of carbon is 12.011 g/mol.

The molar mass of chlorine is 35.453 g/mol.

As stated before we have 1 carbon atom and 4 chlorine atoms. So the molar mass can be evaluated by

\(\left(1*12.011\right)+\left(35.453*4\right)=153.823\)

The molar mass of \(\ce{CCl_4}\) is 153.823 g/mol.

You can multiply that by 2 to get the mass in grams of 2 moles of carbon tetrachloride.

\(2*153.823 =307.646\)

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29 is not the best answer depends on the context and the rules for significant figures.

What is best answer?

The best answer depends on the context and the rules for significant figures. If we assume that we need to round to three significant figures:

Therefore, 29 is not the best answer.

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(a) The balanced chemical equation of magnesium and dilute sulfuric acid is Mg + H₂SO₄ → MgSO₄ + H₂.

(b) The solution was filtered to remove the solid magnesium sulphate (MgSO₄) produced.

The balanced chemical equation of magnesium and dilute sulfuric acid is given as;

Mg + H₂SO₄ → MgSO₄ + H₂.

During the reaction the fizzing that was observed was due to the production of hydrogen gas.

At the end of the reaction, magnesium sulphate (MgSO₄) will be formed, as well as hydrogen gas.

The magnesium sulphate (MgSO₄) formed is a solid, and filtration can be used to remove the solid  magnesium sulphate (MgSO₄) formed.

Filtration is a separation technique used to separate a mixture of liquid and solid, so it will be the best separation technique to recover the produced  magnesium sulphate (MgSO₄).

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Answer:

Wind energy

An ideal source of energy needs to be reliable, cost effective, safe and must lead to almost zero adverse environmental impact.

Wind energy is energy obtained from air moving at high velocity. This energy is harvested using windmills which convert mechanical energy to electrical energy.

Wind is inexpensive because it occurs naturally. However, a large expanse of land is required in order to mount sufficient number of windmills that will generate enough electrical energy for practical purposes.

This method of electricity generation is safe and does not lead to any environmental hazard unlike the burning of fossil fuels, use of nuclear energy or loss of habitat due to hydroelectric power generation.

Explanation:

Answer:

Specific volume at state c = 0.75833 m^3/kg

Total internal energy at state E = 12801.15 KJ

Explanation:

Given data:

compressed liquid water = 5 kg

pressure = 500 kpa

at c , x = 0.2

attached below are the schematic TV and PV diagrams and other parts of the solution. hello

To calculate the volume of the solution, we need to know the concentration of BaCl2 in the solution. Therefore, the volume of the solution is approximately 0.387 L.

Molarity. Molarity, the most typical unit of concentration, is also the most helpful when calculating the stoichiometry of reactions in solution. The number of moles of solute contained in precisely 1 L of solution is known as the molarity (M).

We can use the ionic strength to calculate the concentration of Ba2+ ions in the solution:

Ionic strength = ½ ΣmiZi²

where ΣmiZi² is the sum of the concentration (mi) of each ion species multiplied by the square of its charge (Zi).

Since BaCl2 dissociates into Ba2+ and 2Cl- ions, the ionic strength of the solution can be expressed as:

0.003 = ½ [Ba2+] + [Cl-]

Since [Cl-] = 2[Ba2+], we can substitute to get:

0.003 = ½ [Ba2+] + 2[Ba2+]

0.003 = 2.5[Ba2+]

[Ba2+] = 0.0012 M

The concentration of Ba2+ ions in the solution is 0.0012 M. We can use this concentration and the mass of BaCl2 to calculate the volume of the solution:

0.104 g BaCl2 * (1 mol BaCl2 / 208.23 g) * (1 mol Ba2+ / 1 mol BaCl2) * (1 L / 0.0012 mol Ba2+) = 0.387 L

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Answer:

Acids and bases can help neutralize each other.

Acids turn litmus paper red, bases turn it blue.

Strong bases can be slippery and slimy feeling.

Acids taste sour, bases taste bitter.

Proteins are made up of amino acids.

Vitamin C is also an acid called ascorbic acid.

Ammonia is a base chemical.

Explanation:

school

I just did this for my class.

Here are 10 facts about acids and bases to help you learn about acids, bases, and pH along with a chart for comparison.

1. Any aqueous (water-based) liquid can be classified as an acid, base, or neutral. Oils and other non-aqueous liquids are not acids or bases.

2. There are different definitions of acids and bases, but acids can accept an electron pair or donate a hydrogen ion or a proton in a chemical reaction, while bases can donate an electron pair or accept hydrogen or a proton.

3. Acids and bases are characterized as strong or weak. A strong acid or strong base completely dissociates into its ions in water. If the compound does not completely dissociate, it's a weak acid or base. How corrosive acid or a base does not relate to its strength.

4. The pH scale is a measure of the acidity or alkalinity (basicity) or a solution. The scale runs from 0 to 14, with acids having a pH less than 7, 7 being neutral, and bases having a pH higher than 7.

5. Acids and bases react with each other in what is called a neutralization reaction. The reaction produces salt and water and leaves the solution closer to a neutral pH than before.

6. One common test of whether an unknown is an acid or a base is to wet litmus paper with it. Litmus paper is a paper treated with an extract from a certain lichen that changes color according to pH. Acids turn litmus paper red, while bases turn litmus paper blue. A neutral chemical won't change the paper's color.

7. Because they separate into ions in water, both acids and bases conduct electricity.

8. While you can't tell whether a solution is an acid or a base by looking at it, taste and touch may be used to tell them apart. However, since both acids and bases can be corrosive, you shouldn't test chemicals by tasting or touching them! You can get a chemical burn from both acids and bases. Acids tend to taste sour and feel drying or astringent, while bases taste bitter and feel slippery or soapy. Examples of household acids and bases you can test are vinegar (weak acetic acid) and baking soda solution (diluted sodium bicarbonate -- a base).

9. Acids and bases are important in the human body. For example, the stomach secretes hydrochloric acid, HCl, to digest food. The pancreas secretes a fluid rich in the base bicarbonate to neutralize stomach acid before it reaches the small intestine.

10. Acids and bases react with metals. Acids release hydrogen gas when reacted with metals. Sometimes hydrogen gas is released when a base reacts with a metal, such as reacting sodium hydroxide (NaOH) and zinc. Another typical reaction between a base and a metal is a double displacement reaction, which may produce a precipitate metal hydroxide.

Explanation:

Alkali metal refers to group1 elements.

Alkali earth metal refers to group 2 elements.

Non metals refers to elements in grouos 4 to group 7.

Halogen refers to group 17 elements

Transition Metal refers to group 3 to group 12 elements

Noble gases refer to elements in group 18.

To obtain the group number from the electronic configuration, we calculate the total number of electrons in the principal quantum number (coefficient of the letters).

a. [Ne]3s1

Principal quantum number = 3

Number of electrons present = 1

This element belongs to group 1. It is an Alkali Metal.

b. [Ne]3s23p3

Principal quantum number = 3

Number of electrons present = 2 + 3 = 5

This element belongs to group 15 (5A). It is a Non metal

c. [Ar]4s23d104p5

Principal quantum number = 4

Number of electrons present = 2 + 5 = 7

This element belongs to group 17 (7A). It is an Halogen.

d. [Kr]5s24d1

This configuration belongs to the element yttrium and has an incomplete d shell. Hence it is a transition metal.

e. [Kr]5s24d105p6

Principal quantum number = 5

Number of electrons present = 2 + 6 = 8

This element belongs to group 18 (8A). It is a Noble gas.

Answer:

(a) Rate of formation of NO2 is also 0.066M/s

(b) Rate of reaction of O2 gas is 0.033M/s

Explanation:

(a) in one second, according to the equation,

2 moles of NO combines with 2moles of NO2.

Therefore 0.066M NO will still consume 0.066mole NO2.

(b) According to the equation,

2 moles NO consumes 1 mole O2, 0.0666M will consume 0.0333 mole O2