Which of the following equations defines the law of conservation of energy?

total energy = kinetic energy - potential energy
total energy = kinetic energy - potential energy

total energy = potential energy - kinetic energy
total energy = potential energy - kinetic energy

total energy = kinetic energy + potential energy
total energy = kinetic energy + potential energy

total energy = kinetic energy x potential energy

Given,

Mass of the water, m=50.0 kg

Height to which water was lifted, Δh=10.0 m

Time taken to pump the water, t=75.0 s

The work done to lift the water is given by the change in the potential energy of the water

i.e.

Where g is the acceleration due to gravity.

On substituting known values in the above equation,

Power is given by

Substituting the known values,

Therefore the power consumption of the pump is 65.4 W

Answer:

A high EQ (emotional intelligence)

In today's transitioning workplace, having a high EQ is the most important trait of a good boss. Bosses must be able to discern between their own personal beliefs and the thoughts and beliefs of others, and other generations (boomers, Gen X, xennials, millennials and now Gen Z).

Explanation:

hope it helps you

Hikers frequently take photos in the area, and bear behavior is generally observed during the evening and morning hours, so precautions should be taken to avoid a bear attack and promote safe hiking.

People frequently visit the forest, mountains, and other areas where humans and wildlife interact, such as the forest, where bears, elephants, and other wildlife roam freely, and hikers should be aware of this fact and take precautions, such as standing still when a bear approaches.

Hence, hikers frequently take photos in the area, and bear behavior is generally observed during the evening and morning hours, so precautions should be taken to avoid a bear attack and promote safe hiking.

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With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.

When you increase the number of wire windings in the generator from 5 to 20, the effect on the light bulb will be a brighter illumination. The brightness of the light bulb is directly proportional to the number of windings in the generator.

By increasing the number of windings, you are increasing the amount of wire wrapped around the magnet. This results in a higher number of turns per unit length, leading to an increased magnetic flux passing through the wire coils.

According to Faraday's law of electromagnetic induction, a change in magnetic flux induces an electromotive force (EMF) in a conductor, which in this case is the copper wire. The induced EMF causes electric current to flow through the wire, creating a flow of electrons.

The 30-W light bulb requires a certain amount of electrical power to produce its specified brightness. With 20 windings, the generator will produce a higher EMF and, consequently, a larger current. This increased current will provide more power to the light bulb, resulting in a brighter illumination compared to the dim illumination observed with only 5 windings.

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Answer:

It will turn back into a solid but it will take some time.

Explanation:

The rocket landed 92.45m below when it hit the ground.

When a  body is dropped from a height, its initial velocity is 0. A body executing free fall moves with constant acceleration i.e., acceleration due to gravity

Given data -

By using 2nd equation of motion:

\(s = ut + \frac{1}{2} at^2\)

Equation of motion under gravity:

\(s = ut + \frac{1}{2} gt^2\)

  \(= 0 \times 4.3 \sec + \frac{1}{2} \times 10 \times (4.3)^{2}\) ( assuming g = 10 m/s²)

  \(= \frac{1}{2} \times 10 \times 18.49\)

  = 5 × 18.49

  =  92.45 m

Thus we can conclude that the rocket landed 92.45m below when it hit the ground.

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Answer:

12 cm/s

Explanation:

Quite simply, you are looking for  cm/s

  so   60 cm / 5s   = 12 cm/s

Answer:

12 cm/second

Explanation:

To calculate the speed of an object, simply obtain the distance traveled by the ball and divide it by the total time it took to travel 60 centimeters.

⇒ Distance/Time = Speed

In this case, the ball traveled 60 centimeters in 5 seconds.

Therefore, the speed of the ball is;

60 centimeters (Distance)/5 seconds (Time) = 12 cm/second

Answer:

d = 7200 m

Explanation:

Given that,

Average speed of a runner, v = 2 m/s

Time taken by the runner, t = 60 min = 3600 s

We need to find the distance covered by the runner.

Speed = distance divided by time taken.

v = d/t

Putting all the values,

\(d=v\times t\\\\d=2\times 3600\\\\d=7200\ m\)

So, the distance covered by the runner is 7200 m.

B) Both employ the triple point of water and absolute zero.

Absolute zero and the triple point of water serve as the foundation for both the Celsius and Kelvin scales. Absolute zero, or 0 K on the Kelvin scale and -273.15 °C on the Celsius scale, is the temperature at which all matter has no thermal energy.

The triple point of water is determined to be 273.16 K on the Kelvin scale and 0.01 °C on the Celsius scale. It is the temperature and pressure at which water can coexist in all three phases (solid, liquid, and gas) in equilibrium.

Absolute zero and the triple point of water serve as identical fiduciary points for both the Celsius and Kelvin temperature systems. The temperature ranges for each scale are determined by the fiduciary points, which are essential to temperature scales.

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When a car is traveling north, its acceleration vector can point south when it is slowing down.

A vector quantity has both magnitude and direction. The direction of a vector is always shown by the direction to which the arrow points.

If the car is travelling north, the direction of the acceleration vector will continue to point northwards.

However, when the car slows down, the direction of the accelerating vector will now point southwards.

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Answer:

The force is  \(F = 784 \ N\)

Explanation:

From the question we are told that

      The mass of the man is  \(m = 70 \ kg\)

      The mass of the beam is \(m_b = 10 \ kg\)

Now from the question we can deduce that when this beam start to tip that both the force exerted by the weight of the man and that of the beam is been supported by the  right support so

 The force exerted on the right support is mathematically evaluated as

           \(F = (m + m_b) * g\)

substituting values

         \(F = (70 + 10 ) * 9.8\)

         \(F = 784 \ N\)

The force exerted on the beam by the right support is 784 Newton.

Given the data in the question;

Force exerted on the beam by the right support; \(F = W = \ ?\)

When the beam just starts to tip, the right support holds up the combined mass of the man and the beam.

Hence;

\(M_{net} = m_m + m_b\\\\M_{net} = 70kg + 10kg\\\\M_{net} = 80kg\)

Now, To determine the force exerted on the beam by the right support, we use the general formula for weight or equation of force of gravity which is expressed as:

\(F = W = m * g\)

Where m is mass and g represents the acceleration due to gravity( \(9.8m/s^2\) )

We substitute our values into the equation

\(F = 80kg * 9.8m/s^2\\\\F = 784kg.m/s^2\\\\F = 784N\)

Therefore, the force exerted on the beam by the right support is 784 Newton.

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Answer:

(a) The acceleration lasts 9.642 seconds.

(b) The acceleration of the fireworks shell is 5.808 meters per square second.

Explanation:

Statement is incomplete. Complete description is presented below:

A fireworks shell is accelerated from rest to a velocity of 56 meters per second over a distance of 0.270 meters. (a) How long (in seconds) did the acceleration last? (b) Calculate the acceleration.

(b) Let suppose that the fireworks shell is accelerated uniformly. Given that initial (\(v_{o}\)) and final speed (\(v_{f}\)), measured in meters per second, and distance (\(s\)), measured in meters, are known, we calculate the acceleration (\(a\)), measured in meters per square second, by this kinematic expression:

\(a = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot s}\) (1)

If we know that \(v_{o} = 0\,\frac{m}{s}\), \(v_{f} = 56\,\frac{m}{s}\) and \(s = 0.270\,m\), then the acceleration is:

\(a = \frac{\left(56\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot (270\,m)}\)

\(a = 5.808\,\frac{m}{s^{2}}\)

The acceleration of the fireworks shell is 5.808 meters per square second.

(a) Now we calculate the time associated with acceleration (\(t\)), measured in seconds, by means of this kinematic equation:

\(t = \frac{v_{f}-v_{o}}{a}\)

If we know that \(v_{o} = 0\,\frac{m}{s}\), \(v_{f} = 56\,\frac{m}{s}\) and \(a = 5.808\,\frac{m}{s^{2}}\), then time associated with acceleration is:

\(t = \frac{56\,\frac{m}{s}-0\,\frac{m}{s}}{5.808\,\frac{m}{s^{2}} }\)

\(t = 9.642\,s\)

The acceleration lasts 9.642 seconds.

Answer: i use this in ss class

Explanation:

The lead ball will float with about 17% of its volume above the surface of the mercury.

We know that density is defined as mass per unit volume of a substance. The density of a substance is an intrinsic property which can be used to identify a substance.

Given that Lead is less dense that mercury, we know that lead will float on mercury. Since the density of mercury is 13.6 g/cm3 and that of lead is 11.3 g/cm3, lead ball will float with about 17% of its volume above the surface of the mercury.

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Missing parts;

A spherical ball of lead (density 11.3 g/cm3) is placed in a tub of mercury (density 13.6 g/cm3). Which answer best describes the result?

A.The lead ball will float with about 83% of its volume above the surface of the mercury.

B.The lead ball will float with about 17% of its volume above the surface of the mercury.

C.The lead ball will float with its top exactly even with the surface of the mercury.

D.The lead will sink to the bottom of the mercury.

E.none of the above

Answer: No. Wifi, Cellphone or Microwave radiations does not affect human health.

Explanation:

There is no scientific studies that prove that non iodizing radiation have an adverse effect on human health. Any forms of cellular or satellite communications use non iodizing radiations. So even we use them for extended period of time they seems to be quite safe. As for microwave as well as radio waves and visible light , they all are non iodizing radiation. The one that may cause any ill effect on human body will be the UV radiations which is not in any of these. So all these are quite safe to use and amazing technology to make human lives better.

Answer:

Plasma is a phase of matter that makes up stars.

Answer:so that's C

Explanation:

Wave speed equals frequency*wavelength. So doubling the frequency must halve the wavelength in order for wave speed to remain the same

The speed of the block m1 on the frictionless table is 1.34 m/s.

The given parameters;

The net torque on both blocks is calculated as;

\(\tau _{net} = I \alpha\)

\(T_2R- T_1 R_1 = I \alpha \\\\\)

where;

\(T_1 = m_1 g + m_1 a\\\\T_2 = m_2 g - m_2 a\)

The acceleration of both blocks is calculated as follows;

\(R(T_ 2- T_1) = MR^2 \times (\frac{a}{R} )\\\\R(T_2 -T_1) = MRa\\\\T_2 - T_1 = Ma\\\\(m_2g - m_2 a) - (m_1 g + m_1 a) = Ma\\\\m_2 g - m_1 g - m_2 a - m_1 a = Ma\\\\g(m_2 - m_1) = Ma + m_2a+ m_1a\\\\g(m_2 - m_1) = a(M+ m_2 + m_1)\\\\where;\\\\M \ is \ mass \ of \ string = 0 \\\\g(m_2 - m_1) = a (0+ m_2 + m_1)\\\\g(m_2 - m_1) = a(m_1 + m_2)\\\\a = \frac{g(m_2 - m_1)}{m_1 + m_2} \\\\a = 1.88 \ m/s^2\)

The speed of the block m1 is calculated as follows;

\(a = \frac{v^2}{r} \\\\v^2 = ar\\\\v = \sqrt{a r} \\\\v = \sqrt{1.88 \times 0.95} \\\\v = 1.34 \ m/s\)

Thus, the speed of the block m1 on the frictionless table is 1.34 m/s.

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Given data

The angular acceleration of the car is

The given time is t = 25 s

The expression for the angular displacement is given by the rotational equation of motion as

Substitute the values in the above expression as

3.86×10^11 molecules of gas remain in the tube

P = nkT

n = P/kT

= hdg/kT

Number of molecules in the electron tube is = n×V = hdgV/kT

⟹n = hdg/kT

=

1.2×10^−10 ×13600 × 9.8 × 100 × 10^−6/1.38×10^−23 × 300

= 3.86×10^11

Answer:

The fifth harmonic frequency is 2.9 KHz.

Explanation:

For a closed tube, the fifth harmonic frequency is also the second overtone. So that;

fifth harmonic frequency = \(\frac{5V}{4L}\)

where V is the velocity of the sound in air, and L is the length of the tube.

But L = 0.15 m and V = 343 m/s, then:

fifth harmonic frequency = \(\frac{5*343}{4*0.15}\)

                                     = \(\frac{1715}{0.6}\)

                                     = 2858.33 Hertz

fifth harmonic frequency = 2.9 KHz

The fifth harmonic frequency of the soda bottle is approximately 2.9 KHz.

Answer:

2828.33

Explanation:

answer for acellus

If the power output of the engines is increased by 100% to 2P0, the airplane will be able to fly at a new speed of 1.26\(v_{0}\).

As, P = F v

So, P = kv³

Then, v/v0 = \(\sqrt[3]{P/P0}\).

Therefore, after substituting the values, the speed will be 1.26\(v_{0}\).

What is power?

In physics, power is the amount of energy transferred or converted per unit of time. In the International System of Units, the unit of power is the watt, which is equivalent to 1 joule per second. In older works, force is sometimes called activity. Power is a scalar quantity.

Power is related to other quantities. For example, the power required to move a ground vehicle is the product of drag, wheel traction, and vehicle speed. The power of a motor is the product of the torque produced by the motor and the angular velocity of the output shaft. Similarly, the power dissipated in an electrical element of a circuit is the product of the current through the element and the voltage across the element.

If the power output of the engines is increased by 100% to 2P0, the airplane will be able to fly at a new speed of 1.26\(v_{0}\).

As, P = F v

So, P = kv³

Then, v/v0 = \(\sqrt[3]{P/P0}\).

Therefore, after substituting the values, the speed will be 1.26\(v_{0}\).

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Answer:

-15 as it inverse to gravity

the direction of big force

The total electric field produced by the charges at the midpoint is

8 x 10³ N/C.

Amount of charge on the first particle, q₁ = 40 x 10⁻⁹C

Amount of charge on the second particle, q₂ = 60 x 10⁻⁹C

Distance between the charges, r = 30 cm = 0.3 m

The expression for the electric field due to the charges is given by,

E = 1/4πε₀ x q/r²

At the midpoint between the two charges, d = 0.15 m

So, the electric field produced by the charge q₁ at the midpoint is,

E₁ = 1/4πε₀ x q₁/d²

E₁ = 9 x 10⁹ x 40 x 10⁻⁹/(0.15)²

E₁ = 1.6 x 10⁴ N/C

So, the electric field produced by the charge q₂ at the midpoint is,

E₂ = 1/4πε₀ x q₂/d²

E₂ = 9 x 10⁹ x 60 x 10⁻⁹C/(0.15)²

E₂ = 2.4 x 10⁴ N/C

Therefore, the total electric field produced by the charges at the midpoint is,

E = E₂ - E₁

E = 2.4 x 10⁴- 1.6 x 10⁴

E = 8 x 10³ N/C

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Answer:

The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.

Explanation:

According to Rotational Physics, the total acceleration of the train rounding the horizontal turn is a combination of tangential (\(a_{t}\)) and radial accelerations (\(a_{r}\)), measured in meters per square second. The former one represents the change in the magnitude of the velocity, whereas the latter one represents the change in its direction. By definition of magnitude and Pythagorean Theorem we get that magnitude of total acceleration (\(a\)), measured in meters per square second, is:

\(a = \sqrt{a_{r}^{2}+a_{t}^{2}}\) (Eq. 1)

Magnitudes of tangential and radial accelerations are determined by using the following formulas:

\(a_{t} = \frac{v_{f}-v_{o}}{t}\) (Eq. 1)

\(a_{r} = \frac{v_{f}^{2}}{R}\) (Eq. 2)

Where:

\(v_{o}\), \(v_{f}\) - Initial and final speeds, measured in meters per second.

\(t\) - Time, measured in seconds.

\(R\) - Radius, measured in meters.

If we know that \(v_{o} = 24.444\,\frac{m}{s}\), \(v_{f} = 14.444\,\frac{m}{s}\), \(t = 18\,s\) and \(R = 120\,m\), then the magnitude of the total acceleration when the train speed reaches 52 kilometers per hour is:

\(a_{t} = \frac{14.444\,\frac{m}{s}-24.444\,\frac{m}{s} }{18\,s}\)

\(a_{t} = -0.556\,\frac{m}{s^{2}}\)

\(a_{r} = \frac{\left(14.444\,\frac{m}{s} \right)^{2}}{120\,m}\)

\(a_{r} = 1.739\,\frac{m}{s^{2}}\)

\(a = \sqrt{\left(-0.556\,\frac{m}{s^{2}} \right)^{2}+\left(1.739\,\frac{m}{s^{2}} \right)^{2}}\)

\(a \approx 1.826\,\frac{m}{s^{2}}\)

The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.

The ball is briefly at rest and has zero acceleration at the lowest point of its arc. When the ball is at its lowest position, there is 8330 N of tension in the cable.

There won't be any tension and weight will act downward and centrifugal force upward at the highest position. (as stated). As a result, the tension is 6 mg at the lower point and zero at the higher point.

Is the tension in the string higher, lower, or equal to the weight of the ball at its lowest point? The weight of the ball is outweighed by the strain in the string.

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a) The capacitance of the ceramic capacitor is approximately 354.16 pF.

b) The potential difference between the plates of the capacitor will be approximately 3.39 x 10^6 volts.

To calculate the capacitance of the ceramic capacitor, we can use the formula:

C = (ε₀ * εᵣ * A) / d

where:

C is the capacitance,

ε₀ is the vacuum permittivity (approximately 8.854 x 10^(-12) F/m),

εᵣ is the relative permittivity of the ceramic (given as 100),

A is the effective plate area (given as 4 cm², which is equal to 4 x 10^(-4) m²),

d is the separation between the plates (given as 0.1 mm, which is equal to 0.1 x 10^(-3) m).

Let's calculate the capacitance in picofarads (pF):

a) Calculation of capacitance (C):

C = (ε₀ * εᵣ * A) / d

= (8.854 x 10^(-12) F/m * 100 * 4 x 10^(-4) m²) / (0.1 x 10^(-3) m)

= (8.854 x 100 x 4) / 0.1

= 354.16 pF

Therefore, the capacitance of the ceramic capacitor is approximately 354.16 pF.

b) To find the potential difference (PD) between the plates when the capacitor is given a charge of 1.2 μC (microcoulombs), we can use the formula:

PD = Q / C

where:

PD is the potential difference,

Q is the charge (given as 1.2 μC, which is equal to 1.2 x 10^(-6) C),

C is the capacitance (calculated in part a) as 354.16 pF, which is equal to 354.16 x 10^(-12) F).

Let's calculate the potential difference (PD):

b) Calculation of potential difference (PD):

PD = Q / C

= (1.2 x 10^(-6) C) / (354.16 x 10^(-12) F)

= 3.39 x 10^6 V

Therefore, the potential difference between the plates of the capacitor will be approximately 3.39 x 10^6 volts.

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