which of the following concerning molecular geometry and dipole moments is correct? all molecules with polar bonds have a permanent dipole moment. all square planar molecules are nonpolar. all linear molecules are nonpolar. only molecules with polar bonds may have a permanent dipole moment. a molecule with nonpolar bonds could have a permanent dipole moment, depending on the molecular geometry.

Answer:

B

Explanation:

to find the new rate when the concentration of reactants changes

Once alcohol is in the bloodstream it will reach the brain in a few seconds to minutes, depending on various factors such as the amount and concentration of alcohol consumed, body weight, metabolism, and other individual factors.

Alcohol can swiftly cross the blood-brain barrier after it is ingested, having an impact on the brain and neurological system. Depending on the quantity and frequency of drinking, alcohol's effects on the brain can range from minor disturbances in judgment and coordination to more serious consequences including loss of consciousness and, in the worst circumstances, death.

Long-term changes in brain structure and function, such as cognitive impairment and a higher chance of developing specific neurological and mental illnesses, can also result from chronic alcohol consumption.

Once alcohol is in the bloodstream it will reach the brain in a few seconds to minutes, depending on various factors such as the amount and concentration of alcohol consumed, body weight, metabolism, and other individual factors.

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Based on the mole ratio, the maximum number of grams of NO that can be produced is 19.4 g.

The maximum number of grams of NO that can be produced is calculated from the equation of the reaction as follows:

Equation of the reaction: 4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O(l)

Mole ratio of NH₃ and O₂₂is 4 : 5

moles of NH₃ = 15.9 / 17.03

moles of NH₃ = 0.9336 moles

moles of O₂ = 25.9 / 32

moles of NH₃ = 0.809 moles

the limiting reactant is O₂

Mass of NO produced = 0.809 * 4/5 * 30

Mass of NO produced = 19.4 g

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Answer:

In thin-layer chromatography, the retention factor (Rf) is used to compare and help identify compounds. The Rf value of a compound is equal to the distance traveled by the compound divided by the distance traveled by the solvent front (both measured from the origin).

The molecular weight of unknown gas : 23.46 g/mol

Given

A vessel contains 10% of oxygen and 90% of an unknown gas.

diffuses rate of mixed gas = 86 s

diffuses rate of O₂ = 75 s

Required

the molecular weight of unknown gas (M)

Solution

The molecular weight of mixed gas :(M O₂=32 g/mol)

\(\tt 0.1\times 32+0.9\times M=3.2+0.9M\)

Graham's Law :

\(\tt \dfrac{r_{O_2}}{r_{mixed~gas}}=\sqrt{\dfrac{M_{mixed}}{M_{O_2}} }\\\\\dfrac{75}{86}=\sqrt{\dfrac{3.2+0.9M}{32} }\\\\0.76=\dfrac{3.2+0.9M}{32}\\\\24.32=3.2+0.9M\\\\21.12=0.9M\rightarrow M=23.46~g/mol\)

Answer:

by keep gping

Explanation:

Answer:

need to do the opposite

Explanation:

We have to do a dimensional analysis. We have to convert from 25.9 grams of Cr2O3 to moles using the molar mass of Cr2O3 which is 152 g/mol (You can find the molar mass using the periodic table). Then, we have that in 1 mol of Cr2O3, there are 2 moles of chromium (Cr) and finally, the value that we obtain is converted to grams of Cr using the molar mass of Cr which is 52 g/mol.

This dimensional analysis would look like this:

The answer is that the mass of chromium is 17.7 grams.

Methane is the unidentified gas since its molar mass is 16 g/mol.

When describing atomic masses and molecular masses, the Dalton (Da) or unified atomic mass unit (u) are two alternative units of mass that are frequently employed. It is known to be 1/12 the mass of a carbon-12 atom and is also referred to as "amu" in older.

We must be aware that a gas's molar mass directly relates to how long it takes to diffuse.

t1/t2 = √M1/M2

Let t1 equal the 1.50 minutes it takes for the combustible gas to disseminate. Let t2 equal the 4.73 minutes it takes for the bromine vapor to disperse.

M1 = the flammable gas's molar mass equals

160 g/mol is the molar mass of the bromine vapor, or M2.

replacing values.

1.50/4.73 = √M1/160

(1.50/4.73) ^2 = M1/160

0.1006 = M1/160

M1 = 0.1006 × 160

M1 = 16 g/mol

Methane is the gas in question.

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The molecular mass of the gas, given that 2.63 g of the gas occupied 0.98 L at standard conditions of temperature and pressure is 60 g/mol

First, we shall obtain the mole of the gas. Details below:

PV = nRT

1 × 0.98 = n × 0.0821 × 273

0.98 = n × 22.4133

Divide both sides by 22.4133

n = 0.98 / 22.4133

n = 0.0437 mole

Finally, we shall obtain the molecular mass of the gas. This is shown below:

Molar mass = mass / mole

Molar mass of gas = 2.63 / 0.0437  

Molar mass of gas = 60 g/mol

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Answer:

bonded

Explanation:

Compounds are two elements bonded together.

A mixture is multiple substances blended together.  The substances aren't bonded together and can easily be extracted  from each other.

Answer:

They would all exhibit the same pressure.

Explanation:

Since the same number of mole of each gas is placed in different containers, it means the gas will occupy the same volume.

Now, the gases were observed at the same temperature. This means they will all have the same pressure as their volume is the same.

Now we can further understand this by doing a simple calculation as follow:

Assumptions:

For H2:

Number of mole (n) = 1 mole

Volume (V) = 22.4L

Temperature (T) = 298K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure =..?

PV = nRT

Divide both side V

P = nRT /V

P = 1 x 0.0821 x 298 / 22.4

P = 1 atm

Therefore, H2 has a pressure of 1 atm.

For N2:

Number of mole (n) = 1 mole

Volume (V) = 22.4L

Temperature (T) = 298K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure =..?

PV = nRT

Divide both side V

P = nRT /V

P = 1 x 0.0821 x 298 / 22.4

P = 1 atm

Therefore, N2 has a pressure of 1 atm

For O2:

Number of mole (n) = 1 mole

Volume (V) = 22.4L

Temperature (T) = 298K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure =..?

PV = nRT

Divide both side V

P = nRT /V

P = 1 x 0.0821 x 298 / 22.4

P = 1 atm

Therefore, O2 has a pressure of 1 atm

For He:

Number of mole (n) = 1 mole

Volume (V) = 22.4L

Temperature (T) = 298K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure =..?

PV = nRT

Divide both side V

P = nRT /V

P = 1 x 0.0821 x 298 / 22.4

P = 1 atm

Therefore, He has a pressure of 1 atm.

From the above illustrations we can see that the gases have the same pressure since they have the same number of mole, volume and were observed at the same temperature.

To convert grams (g) of a substance to moles (mol), you need to divide the mass by the molar mass of the substance.

The molar mass of Be(NO2)2 can be calculated by adding the molar masses of its constituent atoms, which are:

The molar mass of Be: 9.01 g/mol

The molar mass of N: 14.01 g/mol

The molar mass of O: 16.00 g/mol (there are two oxygen atoms in the nitrite ion, NO2-)

So the molar mass of Be(NO2)2 is:

9.01 g/mol (Be) + 2(14.01 g/mol (N) + 2(16.00 g/mol (O)) = 9.01 g/mol + 28.02 g/mol + 32.00 g/mol = 69.03 g/mol

Now we can use this molar mass to convert 11.9 g of Be(NO2)2 to moles:

moles = mass/molar mass

moles = 11.9 g / 69.03 g/mol

moles ≈ 0.1727 mol

Therefore, 11.9 g of Be(NO2)2 is equivalent to approximately 0.1727 moles.

Answer:

I think it's the second option

Explanation:

I'm just taking a stab in the dark here, so to speak

Answer:

See the answer below.

Explanation:

If an aqueous solution of two salts contains both Na2CO3 and Na2SO4, the following steps will prove the occurrence of both carbonate and sulphate ions:

1. Add a dilute acid (such as HCl) to the solution. The presence of carbonate ion will result in the release of carbon dioxide gas which will be shown by formation of effervescent bubbles. The gas can be proven to be carbon dioxide by channeling it into a lime water which usually turns milky with the presence of the gas.

\(CO^{2-}_3(aq) + 2H^+(aq) ==> H_2O(l) + CO_2(g)\)

2. Add barium chloride to an acidified portion of the aqueous solution. The presence of sulphate ion will be indicated by the formation of white barium sulphate precipitate. Initial acidification is done to disperse off any carbonate ion that might be present in the solution and give a false-positive white precipitate result.

\(Ba^{2+}(aq) + SO^{2-}_4(aq) --> BaSO_4(s)\)

Which of the statements about liquids and gases are true?

The particles in liquids and gases can move past one another freely.

Which of the statements about liquids and gases are true?

Both liquids and gases have a definite volume.

The particles in liquids and gases can move past one another freely

Both liquids and gases have a definite shape.

Neither liquids nor gases have a definite shape.

The particles in liquids and gases can move past one another freely.

Some types of solids that are insoluble in water are:

Many solids are insoluble in water, meaning they do not dissolve in water to a significant extent. Here are some examples of common solids that are generally insoluble in water:

Metals: Most metals, such as gold, silver, platinum, and copper, are insoluble in water.

Non-Metallic Elements: Many non-metallic elements, such as carbon (in the form of graphite or diamond), sulfur, phosphorus, and iodine, are insoluble in water.

Metal Oxides: Some metal oxides, particularly those of less reactive metals, are insoluble in water. Examples include aluminum oxide (Al2O3), iron(III) oxide (Fe2O3), and lead(II) oxide (PbO).

Metal Carbonates: Most metal carbonates are insoluble in water. Examples include calcium carbonate (CaCO3), lead(II) carbonate (PbCO3), and copper(II) carbonate (CuCO3).

Metal Sulfides: Many metal sulfides are insoluble in water. Examples include lead(II) sulfide (PbS), silver sulfide (Ag2S), and mercury(II) sulfide (HgS).

Insoluble Salts: Certain salts have limited solubility in water. Examples include silver chloride (AgCl), lead(II) iodide (PbI2), and calcium sulfate (CaSO4).

It's important to note that while these solids are generally insoluble in water, they may exhibit some solubility to a small extent. The solubility of a solid in water can vary depending on factors such as temperature, pressure, and the presence of other solutes.

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The pair of compounds forms a homogeneous solution when combined are : A. homogeneous solution, B. non homogeneous solution, C. homogeneous solution, D. non homogeneous solution.

Part A) :- (a) CH₃CH₂CH₂CH₂CH₃ and CH₃CH₂CH₂CH₂CH₂CH₃ form a homogeneous solution because they are both nonpolar molecules and therefore have similar intermolecular forces.

(b) CBr₄ and H₂O do not form a homogeneous solution because CBr₄ is a nonpolar molecule and H₂O is a polar molecule, so they have different intermolecular forces and are not miscible.

(c) LiNO₃ and H₂O form a homogeneous solution because LiNO₃ is an ionic compound that dissolves in water to form a solution.

(d) CH₃OH and CH₃CH₂CH₂CH₂CH₃ do not form a homogeneous solution because CH3OH is a polar molecule and CH₃CH₂CH₂CH₂CH₃ is a nonpolar molecule, so they have different intermolecular forces and are not miscible.

Part B)

For the homogeneous solutions, the type of forces involved are:

(a) CH₃CH₂CH₂CH₂CH₃ and CH₃CH₂CH₂CH₂CH₂CH₃: London dispersion forces (induced dipole-induced dipole)

(c) LiNO₃ and H₂O: Ion-dipole forces.

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Answer:

The answer is C

Explanation:

Duh its the name HALF LIFE!!

just a way to remember

The statement which is true about the half-life of a source is (D) It is half the time it takes the activity of the source to decrease to zero. Hence the correct option is (D)

Half-life is the length of time it takes for a radioactive element to decay to half of its initial value.

This suggests that a source's activity has a half-life when it takes time for it to decrease to half its initial value.

It is the amount of time needed for half of the atomic nuclei in a radioactive sample to spontaneously decay, which releases energy and particles into other nuclear species. Alternatively, it is the amount of time needed for the radioactive sample to disintegrate at a rate of one per second.

Therefore, The statement which is true about the half-life of a source is (D) It is half the time it takes the activity of the source to decrease to zero. Hence the correct option is (D)

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In most experiments, the decay of a large number of radioactive isotopes over time is measured in order to calculate the half-life of a radioactive isotope. They compute the quantity of radioactive atoms still present at various time points and graph the data. Time is represented on the x-axis, while the quantity of radioactive atoms left is shown on the y-axis.

In an exponential decay curve, the remaining number of atoms declines quickly at initially before gradually levelling out on the graph. The amount of time it takes for half of the radioactive atoms in a sample to decay is known as the half-life. Scientists seek for the point on the graph where the number of atoms left is half of what it was to establish the half-life. They pick out this location on the graph and calculate the associated time. The radioactive isotope's half-life is represented by this period of time.

Similar to your example with the dimes, you could display this data on a graph if you were to run an experiment in which you threw a lot of dimes and counted how many were still there after each toss. The x-axis would show the number of tosses, and the y-axis would show how many dime are left.

If the surviving dimes follow a pattern similar to radioactive decay, you would notice a steady decline in their quantity over time. Even if the graph isn't a perfect exponential decay curve, you can still locate a point where the number of dimes left is half of what they were initially. The "half-life" of the dimes in your experiment would be represented by the corresponding number of throws at this stage.

You can comprehend the general idea of finding the time or number of events necessary for a quantity to reduce to half of its initial value by drawing a comparison between figuring out the half-life of radioactive isotopes and the fictitious scenario of figuring out the "half-life" of dimes.

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Answer:

i would have to say oxygen .

Explanation:

Answer:

2 moles

In words, 1 mole of Mg reacts with 2 moles of HCl to form 1 mole of MgCl₂ and 1 mole of H₂. The molar ratio of HCl to MgCl₂ is 2:1.

Answer

B) in chemical changes and physical changes.

Explanation

Matter can change form through physical and chemical changes, but through any of these changes, matter is conserved. The same amount of matter exists before and after the change —none is created or destroyed. This concept is called the Law of Conservation of Mass.

Also, the law of conservation of energy states that in any physical or chemical process, energy is neither created nor destroyed. In other words, the entire energy in the universe is conserved.

Therefore, mass and energy are conserved in chemical changes and physical changes.

The correct answer is option B) in chemical changes and physical changes.

Answer:

okay....

Explanation:

technically, fish do not have wings. they are called fins and they are used for the purpose of transportation, just as legs are for humans.

~Ren

Answer:

Concentration of unknown solution is 0.0416 M

Explanation:

As we know  

Absorbance is equal to the product of molar absorptivity of KMnO4 m, path length and concentration

From the given set of graphical data, it is clear that the absorbance vs concentration is a straight line.  

From the graph, we can obtain-  

Y = 5.73 X – 0.0065

Absorbance = 0.232

0.232 = 5.73 X – 0.0065

X = 0.0416  

Concentration of unknown solution is 0.0416 M

Hydrogen is formed at the negative electrode (cathode) and oxygen at the positive electrode (anode) and the concentration of sulfuric acid increases.

Direct electric current is used in the electrolysis process to accelerate chemical reactions that would not naturally occur.

It can be seen that as the electrolysis proceeds the dilute sulfuric acid gets slightly more concentrated as only water is removed from the electrolyte as hydrogen and oxygen.

The ions present in the dilute acid are H+(aq), OH–(aq) and SO4 2–(aq).

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suggest an explanation of why the concentration of the sulfuric acid increases during electrolyis

The answer responses to  the structures shown in the diagram are:

A. chromosomes

C. They would be the same.

B. They are in pairs because each one comes from a different parent.

The chromosomes are in pairs because humans have a diploid number of chromosomes, meaning they have two sets of chromosomes, one inherited from each parent.

The nucleus is important in eukaryotic cells and has many important parts that help the cell work properly. There are some parts inside cells called the nuclear membrane, nucleoplasm, nucleolus, and chromatin. Chromatin is made up of DNA and other proteins.

Every part of a person's body has the same genes, but the way they are organized can be different in different types of cells. The chromosomes in our skin cells might not be the same as the chromosomes in our muscle cells, even if they come from the same person.

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Identify the structures shown.

A. chromosomes

B. mitochondria

C. nuclei

D. vacuoles

C

Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.

A. There would be longer.

B. They would be shorter.

C. They would be the same.

D. They would be different.

Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.

A. There would be longer.

B. They would be shorter.

C. They would be the same.

D. They would be different.

Explain why the structures are in pairs.

A. They aren't in pairs.

B. They are in pairs because each one comes from a different parent.

C. This cell is making a copy of itself.

D. The cell always has 2 copies in case 1 is damaged.

Answer:

Partial lunar eclipse.

Explanation:

A lunar eclipse is a cosmological event by which, in the presence of the Earth between the Sun and the Moon, the latter does not receive the light of the Sun in the totality of its visible face, with which a part (or the totality ) of her is in the dark.

Thus, if the lunar eclipse implies an absence of sunlight in the entire lunar surface, the eclipse will be total, while if the eclipse implies an absence of light only in part, the eclipse will be partial (which is the most common event).