A wire of length L is used in an electric heater. When the potential
difference across the wire is 200 V, the power dissipated in the wire is
1000 W. The same potential difference is applied across a second similar wire of
length 2L. What is the power dissipated in the second wire?

The difference in momentum between the runner and truck with different masses and velocities is 2850kgm/s.

Momentum in physics is the tendency of a body to maintain its inertial motion. It is the product of its mass and velocity, or the vector sum of the products of its masses and velocities.

Momentum, denoted by p, can be calculated as follows:

p = mv

According to this question, a 50.0-kg runner moving at a speed of 3.00 m/s and a 3.00×10³-kg truck moving at a speed of only 1.00 m/s.

change in momentum (∆p) = 3000 - 150 = 2850kgm/s

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The magnitude of the action–reaction pair between the two boxes (A and B) will be "18.2 N".

According to the question,

Mass of box A,

Mass of box B,

Horizontal force,

From the Newton's law,

→ \(F_{app} = (\frac{F_{app}}{m_A+m_B} )a\)

or,

→      \(a = \frac{F_{app}}{(m_A+m_B)}\)

Bu substituting the values, we get

→         \(= \frac{100}{9+2}\)

→         \(= \frac{100}{11}\)

→         \(9.10 \ m/s^2\)

We can see that between the two boxes, the action-reaction pair exist.

then,

→ \(F_{action-reaction} = m_b \ a\)

→                          \(=2\times 9.10\)

→                          \(= 18.2 \ N\) (magnitude)

Thus the above solution is appropriate.

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The expression "velocity as a function of time" refers to the change in an object's velocity over time, which can be observed by graphing the velocity against time on a graph.

Speed and time are related in the first equation of motion. V = u + at represents the first motion equation. Here, u denotes the starting velocity, a the acceleration, and t the duration, whereas v denotes the end velocity. The derivative of x with respect to time, or v(t)=ddtx, represents the instantaneous velocity of an object. It is the limit of average velocity as the time approaches zero (t). V (t) equals d d t x (t). Instantaneous velocity has a dimension of length per time, just like average velocity does.

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Answer:

Total distance traveled by the sound wave = 2d . Thus we can conclude that the cliff should be at a distance of 877.15 metres from the source of sound to meet the required conditions

Explanation:

this is what i found on the web

F= 300 N

d = 0.6m

m = 30g = 0.03 kg

• a.

Apply Hooke's law formula:

F = k x

k= F/ x

Where:

k= spring constant

F= force = 300N

x = distance = 0.6 m

k = 300N/0.6m = 500N/m

• b.

PE = 1/2 k (x)^2

PE = 1/2 (500 N/m) (0.6)^2 = 90 J

• c.

KE = 1/2 m v^2

KE = kinetic energy = PE = potential energy

v = √KE/ (1/2*m) = √2KE/m = √ (2* 90 / 0.03 ) = 77.46 m/s

Answers:

a = 500 N/m

b= 90 J

C = 77.46 m/s

Explanation:

initial velocity (u) = 22 m/s

Final velocity = ?

acceleration = 7.3 m/s^2

time = 6.8 sec

Now,

acceleration = final velocity- intial velocity/time taken

7.3 = v-u/t

7.3= v-22/6.8

7.3×6.8= v-22

49.64=v-22

49.64+22 =v

v= 71.64 m/s

The correct statement is " Sunlight absorbed at the surface results in greenhouse gases warming the atmosphere." The correct option is B.

The greenhouse effect is a natural phenomenon that keeps the Earth's temperature within a range that is suitable for humans and other forms of life. The greenhouse effect is maintained by certain gases in the atmosphere, known as greenhouse gases, which trap the sun's energy and warm the Earth's surface.

Option A, which states that human activities absorb sunlight to create stable warm temperatures on Earth, is not correct. Human activities do not directly absorb sunlight. However, they do release greenhouse gases, which contribute to the greenhouse effect and increase the temperature of the Earth's surface.

Option C, which states that greenhouse gases produced from human activities heat the surface temperatures of Earth, is partially correct. Human activities, such as burning fossil fuels, do release greenhouse gases that contribute to the greenhouse effect. However, this option suggests that the greenhouse gases themselves heat the surface of the Earth, which is not accurate. The greenhouse gases trap heat in the atmosphere, which warms the Earth's surface.

Option D, which states that sunlight is reflected by the surface of the Earth, and heat is trapped in the atmosphere by greenhouse gases, is not entirely accurate. The Earth's surface absorbs the sun's energy, and some of this energy is reflected back into space. The rest is absorbed by the Earth's surface and then re-emitted as heat. The greenhouse gases in the atmosphere trap this heat and prevent it from escaping into space, which causes the Earth's temperature to rise.

Therefore, The correct answer is option B.

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Answer:

3ft/s²

Explanation:

\(a = \frac{60 - 45}{5} = 3ft \div {s}^{2} \)

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Answer:

protons+neutrons= mass number, so if the mass number is 13 and protons are 6 its 13-6=7 neutrons

Explanation:

mass number: the sum of the number of protons and

neutrons in an atom

this is key as it explains that protons+neutrons= mass number, so if the mass number is 13 and protons are 6 its 13-6=7 neutrons

Answer:

♡ goodmorning ♡

the answer is a.

hope this could help! ☆

- madeline/madi

✧･ﾟ: *✧･ﾟ:･ﾟ✧*:･ﾟ✧･ﾟ

Explanation:

Answer:

potential lines that are perpendicular to the electric field, they must be parallel to the plates

Explanation:

A and C) for this drawing, as the electric field lines go from the positive plate to the negative plate and are horizontal to the potential lines that are perpendicular to the field, they must be parallel to the plates, see attached part a

B) in this case the ground has an energy of zero and the lines are parallel to the ground, see attached part b

The power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.

The parallel force on the patient is calculated as follows;

F = mg sinθ

F = (75 x 9.8) x sin(12)

F = 152.82 N

P = FV

where;

F = 152.82 x 0.861

F = 131.58 W

Thus, the power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.

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Answer: ITS 1 TRUST ME MAN BYE K

Explanation: OK BYE TRUST YEAH

Answer:

\(T=326.928K\)

Explanation:

From the question we are told that:

Emissivity \(e=0.44\)

Absorptivity \(\alpha =0.3\)

Rate of solar Radiation \(R=0.3\)

Generally the equation for Surface absorbed energy is mathematically given by

 \(E=\alpha R\)

 \(E=0.3*950\)

 \(E=285W/m^2\)

Generally the equation for Emitted Radiation is mathematically given by

 \(\mu=e(\sigmaT^4)\)

Where

T=Temperature

 \(\sigma=5.67*10^8Wm^{-2}K_{-4}\)

Therefore

 \(\alpha*E=e \sigma T^4\)

 \(0.3*(950)=0.44(5.67*10^-8)T^4\)

 \(T=326.928K\)

Answer:

- They need oxygen to burn fuel

- Aerodynamics

- Extreme temperatures

- Radiation

- Pressure issues

Explanation:

A airplane is a heavier-than-air aircraft kept aloft by the upward thrust exerted by the passing air on its fixed wings and driven by propellers, jet propulsion, etc.

Aeroplanes cannot travel in space for several reasons:

They need oxygen to burn fuel - Aeroplane engines rely on the oxygen in the atmosphere to burn fuel and generate thrust. In space, there is no atmosphere so there is no oxygen for the engines to work.

Aerodynamics - Aeroplane wings generate lift by interacting with the air. In space, there is no air so wings would be unable to generate any lift. Aeroplanes rely on aerodynamics to fly which does not work in space.

Extreme temperatures - In space, temperatures can range from -150 degrees Celsius to 150 degrees Celsius. Aeroplanes are designed to operate within a much narrower temperature range. The extreme cold and heat of space could damage aeroplane components.

Radiation - In space, there are high levels of radiation from the Sun and cosmic rays. Aeroplane bodies are not designed to shield against this type of radiation and it could damage electronics and affect aeroplane systems.

Pressure issues - Aeroplanes are designed to withstand air pressures at altitudes up to around 12 kilometers. In low-Earth orbit and beyond, the air pressure is essentially zero. This extreme change in pressure could cause structural damage to the aeroplane.

In summary, while aeroplanes are designed to fly through the Earth's atmosphere, they lack the key features needed to operate in the extreme environment of outer space like spaceships. Aeroplanes require things like oxygen, aerodynamics and being able to withstand changes in pressure - all of which do not exist or work the same way in space.

Explanation:

The wing is pushed up by the air under it. Large planes can only fly as high as about 7.5 miles. The air is too thin above that height. It would not hold the plane up.

Answer:

   k = -3.1450 10⁻⁴  s⁻¹

Explanation:

In this exercise we are given the equation that describes the cooling process

        dT / dt = k (T -)

Let's solve is this equation,

        dT / (T-T_ {e}) = k dt

change of variable for integration

       T -T_{e} = T ’

       dT = dT '

       ∫ dT ’/ T’ = k  ∫ dt

we integrate

        ln T ’= k t

we change to the initial variables

        ln (T - T_{e}) = k t

Let's evaluate from the lower limit T = T for t = 0 to the upper limit T = T₀ for time t

       ln (T₀ -T_{e}) - ln (T -T_{e}) = k (t-0)

we simplify

       ln (T₀ -T_{e} / T -T_{e}) = k t

       k = ln (T₀ -T_{e})  / (T-Te) / t

In the exercise they indicate that the temperature T = 205 F, the ambient temperature is T_{e} = 70F, the temperature to which T₀ = 200 F falls in a time t = 2 min = 120 s

Let's calculate

           k = ln [(200- 70) / (205 -70)] / 120

           k = -0.0377403 / 120

           k = -3.1450 10⁻⁴  s⁻¹

1) The starting temperature of the gas is 288 K

b) When the pressure is doubled, the temperature is 576 K

We know that we have to use the ideal gas equation so as to be able to obtain the temperature of the starting of the gas and we know that;

Pressure = 200 kPa or 1.97 atm

Volume =  3000 cm3  or 3 L

Temperature = ?

Number of moles = mass/molar mass = 7 g/28 g/mol = 0.25 moles

Then we have;

PV = nRT

T = PV/nR

T =  1.97 * 3/0.25 * 0.082

T = 5.91/0.0205

T = 288 K

If the pressure doubles and we have;

P1/T1 = P2/T2

P1T2 = P2T1

T2 = 2(1.97) * 288/1.97

T2 = 576 K

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Answer:

25 m/s

Explanation:

⠀⠀⠀⇒ Speed = 90 km/h

⠀⠀⠀⇒ Speed = 90 km/60 min [As 1 hr = 60 min]

⠀⠀⠀⇒ Speed = (90 × 1000) m/(60 × 60)sec

⠀⠀⠀⇒ Speed = 90000 m/3600 sec

⠀⠀⠀⇒ Speed = 900 m/36 sec

⠀⠀⠀⇒ Speed = 300 m/12 sec

⠀⠀⠀⇒ Speed = 100 m/4 sec

⠀⠀⠀⇒ Speed = 25 m/s

Answer:

 v = 126 m / s

Explanation:

Let's analyze this exercise a little, they give us the thrust that is the applied force and the time that it lasts, and they ask us for the final speed, so we can use the Impulse ratio and the variation of the amount of movement

       I = F t = Dp

       F t = pf -p₀

      Now let's use Newton's second law to find the net thrust

        F = E - fr

the friction force has the formula

       fr = μ N

let's write Newton's second law on the y-axis

       N-W = 0

       N = W

we substitute

      fr = μ mg

we look for the net out

       F = 200 - μ mg

With the skater starting from rest, the initial speed is zero (vo = 0)

we substitute

      (200 - very m g) t = m v

       v = (200 µm - very g) t

let's calculate

     v = (200/75 - 0.10 9.8) 75

      v = 126 m / s

Answer:

Ants position at point A = -7 cm

Ants position at point B = 38 cm

Ants position at point C = 26 cm

Ants position at point D = -7 cm

Explanation:

In this question, we are dealing with displacement which is the change in position of an object.

Now, we are told the journey began from A to B and then from C to D.

Now, AB = 31 cm and AO = 7cm

But along AB, we have the origin O.

Since A is on the left hand side of the origin, it means it is negative. Thus, position A = -7cm

Then position B = 31 - (-7) = 31 + 7 = 38 cm

Since BC = 12cm, then position C = 38 - 12 = 26 cm

Position D is same as position A = -7cm

The term velocity is the combination of speed and direction.

The total displacement covered by any object per unit of time is known as velocity. The generally considered unit for velocity is a meter per second. It depends on the magnitude as well as the direction of the moving body. The unit of velocity is meter/second. It can also be represented by the infinitesimal rate of change of displacement with respect to time.

If an object is moving eastwards, then its velocity is expressed as being eastwards. If an object is moving southwards, then its velocity is described as being southwards. So an airplane moving towards the north with a speed of 450 km/hr has a velocity of 450 km/hr northward.

Speed has no effect on direction as the speed of any object or body is a scalar quantity and the velocity at any given time is expressed with the magnitude of velocity as well as with the direction of motion of an object.

The term velocity is the combination of speed and direction. therefore the correct option is option C.

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Answer:

The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.

Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:

Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet

To find the total resistance when the conductors are in parallel, we use the formula:

1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3

Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)

Substituting the values, we get:

Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))

Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.

Answer:

The loss in rotational kinetic energy due to the collision is 36.585 J.

Explanation:

Given;

mass of the disk, m₁ = 1.64 kg

radius of the disk, r = 0. 61 m

angular velocity of the disk, ω₁ = 17.6 rad/s

mass of the rod, m₂ = 1.51 kg

length of the rod, L = 1.79 m

angular velocity of the rod, ω₂ =  5.12 rad/s (clock-wise)

let the counter-clockwise be the positive direction

let the clock-wise be the negative direction

The common final velocity of the two systems after the collision is calculated by applying principle of conservation of angular momentum ;

m₁ω₁  + m₂ω₂ = ωf(m₁ + m₂)

where;

ωf is the common final angular velocity

1.64 x 17.6    + 1.51(-5.12) = ωf(1.64 + 1.51)

21.1328 = ωf(3.15)

ωf = 21.1328 / 3.15

ωf = 6.709 rad/s

The moment of inertia of the disk is calculated as follows;

\(I_{disk} = \frac{1}{2} mr^2\\\\I_{disk} = \frac{1}{2} (1.64)(0.61)^2\\\\I_{disk} = 0.305 \ kgm^2\)

The moment of inertia of the rod about its center is calculated as follows;

\(I_{rod} = \frac{1}{12} mL^2\\\\I_{rod} = \frac{1}{12} \times 1.51 \times 1.79^2\\\\I _{rod }= 0.4032\ kgm^2\)

The initial rotational kinetic energy of the disk and rod;

\(K.E_i = \frac{1}{2} I_{disk}\omega _1 ^2 \ \ + \ \ \frac{1}{2} I_{rod}\omega _2 ^2 \\\\K.E_i= \frac{1}{2} (0.305)(17.6) ^2 \ \ + \ \ \frac{1}{2} (0.4032)(-5.12) ^2\\\\K.E_i = 52.523 \ J\)

The final rotational kinetic energy of the disk-rod system is calculated as follows;

\(K.E_f = \frac{1}{2} I_{disk}\omega _f ^2 \ \ + \ \ \frac{1}{2} I_{rod}\omega _f ^2\\\\K.E_f = \frac{1}{2} \omega _f ^2(I_{disk} + I_{rod})\\\\K.E_f = \frac{1}{2} (6.709) ^2(0.305+ 0.4032)\\\\K.E_f = 15.938 \ J\)

The loss in rotational kinetic energy due to the collision is calculated as follows;

\(\Delta K.E = K.E_f \ - \ K.E_i\\\\\Delta K.E = 15.938 J \ - \ 52.523 J\\\\\Delta K.E = - 36.585 \ J\)

Therefore, the loss in rotational kinetic energy due to the collision is 36.585 J.

Given that,

Charge = 16 nC

Mass = 33 g

Distance = 27 cm

We need to calculate the acceleration

Using formula of electrostatic force

\(F=\dfrac{kqQ}{r^2}\)

\(ma=\dfrac{kq^2}{r^2}\)

Put the value into the formula

\(33\times10^{-3}\times a=\dfrac{9\times10^{9}\times(16\times10^{-9})^2}{(27\times10^{-2})^2}\)

\(a=\dfrac{9\times10^{9}\times(16\times10^{-9})^2}{(27\times10^{-2})^2\times33\times10^{-3}}\)

\(a=0.0009577\ m/s^2\)

\(a=9.577\times10^{-4}\ m/s^2\)

We need to calculate the speed of charge

Using equation of motion

\(v^2=u^2+2as\)

Where, v= speed

u = initial speed

a = acceleration

s = distance

\(v^2=0+2\times9.577\times10^{-4}\times16\times10^{-2}\)

\(v=\sqrt{0+2\times9.577\times10^{-4}\times16\times10^{-2}}\)

\(v=0.0175\ m/s\)

Hence, The speed of the charge is 0.0175 m

Answer:

It might be like 45-50 mph

Explanation: