Which has a higher electronegativity phosphorus or sodium

To help the crystals form, these three options are correct- 1. Scrape the inside of the Erlenmeyer flask with a glass rod below the surface of the solvent. 2. Add a scrap of paper to nucleate the crystals. 3. Add some crystals of the compound you are trying to crystallize.

Crystallization is the process of a solid material forming a structured arrangement of its particles, typically resulting in a highly ordered and often repeating pattern. This can be seen in the formation of solid crystals such as salt, sugar, and diamonds. Crystallization occurs when molecules of the solid tend to organize themselves into a more ordered pattern.

Adding a scrap of paper to nucleate the crystals is a process known as seeding. Seeding involves introducing a small crystal into a container of supersaturated solution, which then provides a nucleus for additional crystals to form around. This process accelerates the growth of the crystals and can be used to create larger, more consistent crystals. It can also be used to create crystals with specific shapes and sizes. The addition of a scrap of paper encourages the solution to form around it, helping to encourage the formation of crystals.

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A lot of energy is required to overcome these forces and melt or vaporize the alkane

The melting point and boiling point of alkanes (a type of hydrocarbon with only single bonds between the carbon atoms) generally increase as the number of carbon atoms in the molecule increases. This is because the larger the molecule, the more Van der Waals forces (also known as London dispersion forces) that are present. These forces are a type of weak attractive force that can exist between any two molecules and are caused by the fluctuating dipoles (temporary separations of positive and negative charge) that occur within a molecule. The more carbon atoms a molecule has, the more fluctuating dipoles it has, and the stronger the Van der Waals forces are. As a result, more energy is required to overcome these forces and melt or vaporize the substance.

In addition to the size of the molecule, the type of bond present in the molecule can also affect the melting point and boiling point. Single bonds, like those found in alkanes, are weaker than double bonds or triple bonds. As a result, molecules with double or triple bonds have higher melting points and boiling points than molecules with the same number of carbon atoms but only single bonds.

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Washing up liquid is used in enzyme experiments as a tool to help control the reaction conditions and to demonstrate the power and versatility of enzymes.

Washing up liquid is used in enzyme experiments for several reasons:

To break down grease and oils: Enzymes are commonly used in laundry detergents and dishwashing liquids to help break down grease and oils on clothing and dishes. In enzyme experiments, washing up liquid can be used to simulate this effect and demonstrate the power of enzymes.

To increase the surface area for reaction: By adding washing up liquid to an enzyme experiment, the surface area for reaction is increased, allowing the enzymes to react with a larger amount of substrate and produce more product.

To act as a surfactant: Washing up liquid contains surfactants, which are compounds that lower the surface tension of liquids and allow the enzymes to diffuse into the substrate more easily. This helps to increase the reaction rate of the enzymes.

To control the viscosity of the reaction mixture: Washing up liquid can also help to control the viscosity of the reaction mixture, allowing the enzymes to move freely and react with the substrate.

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Answer: When the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The overall chemical reaction follows:

\(CaO(s)+CO_2\rightarrow CaCO_3(s)\)     \(\Delta H^o_{rxn}=?\)

The intermediate balanced chemical reaction are:

(1) \(Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\rightarrow CaCO_3(s)\)    \(\Delta H_1=-812.8kJ\)  

(2) \(2Ca(s)+O_2(g)\rightarrow 2CaO(s)\)     \(\Delta H_2=-1269kJ\)

The expression for enthalpy of the reaction follows:

\(\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[\frac{1}{2}\times (-\Delta H_2)]\)

Hence, when the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

Answer:

A. is halved and has its sign changed.

Explanation:

just took the test on edge

Answer:

ecosystem

Explanation:

An ecosystem includes all of the living things (plants, animals and organisms) in a given area, interacting with each other, and also with their non-living environments (weather, earth, sun, soil, climate, atmosphere). The living and nonliving components of the ecosystem are linked together through nutrient cycles and energy flows. Ecosystems are of any size, but usually they are in particular places.

In an ecosystem, plants depend on the soil for nutrients. These nutrients are cycled in nature by the various biogeochemical cycles within the ecosystem. The ecosystem is a self sustaining unit in terms of materials and energy flow.

Answer:

D. ecosystem

Explanation:

An ecosystem is a large community of living organisms (plants, animals and microbes) in a particular area. The living and physical components are linked together through nutrient cycles and energy flows.

In an ecosystem there is symbiotic relationship which entails each living organism contributes to the well being of the other and the entire population.

The concentration of H+ at equilibrium is 1.06 x 10^-4 M.

To determine the concentration of H+ in the weak acid solution at equilibrium, we need to use the percent ionization and the initial concentration of the weak acid.

Let's assume that the weak acid is denoted by HA. Then, we can write the equilibrium equation for the dissociation of HA as:

HA ⇌ H+ + A-

The equilibrium constant expression for this dissociation reaction is:

Ka = [H+][A-]/[HA]

Since the acid is weak, we can assume that the concentration of A- at equilibrium is approximately equal to the initial concentration of HA, since only a small fraction of HA is dissociated. Therefore, we can simplify the equilibrium constant expression to:

Ka = [H+]^2/[HA]

Rearranging this equation, we get:

[H+]^2 = Ka[HA]

Taking the square root of both sides, we get:

[H+] = sqrt(Ka[HA])

Now, we can plug in the values given in the problem:

Ka = unknown

[HA] = 0.00550 M

percent ionization = 8.20%

To find Ka, we can use the percent ionization:

percent ionization = [H+]/[HA] x 100%

8.20% = [H+]/0.00550 M x 100%

[H+] = 0.000451 M

Now, we can use the equation we derived earlier to find [H+] at equilibrium:

[H+] = sqrt(Ka[HA])

0.000451 M = sqrt(Ka x 0.00550 M)

Squaring both sides, we get:

Ka x 0.00550 M = (0.000451 M)^2

Solving for Ka, we get:

Ka = (0.000451 M)^2 / 0.00550 M

Ka = 3.70 x 10^-6 M

Finally, we can use the equation [H+] = sqrt(Ka[HA]) to find the concentration of H+ at equilibrium:

[H+] = sqrt(3.70 x 10^-6 M x 0.00550 M)

[H+] = 1.06 x 10^-4 M

Therefore, the concentration of H+ at equilibrium is 1.06 x 10^-4 M.

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Answer:

Structural formulas are helpful because they explain the properties and structure of the compound which empirical and molecular formulas cannot always represent.

Explanation:

HOPE ITS HELPFUL FOR U

Answer:

1mpm(1 meters per minute) Explanation: Speed:Distance/time 25/25=1 plz mark as brainliest

Answer:

1mpm(1 meters per minute)

Answer:

they require more testing in real-word conditions

Explanation:

One of the biggest reasons for this very slow uptake of hydrogen vehicles is the existing infrastructure. ... The sceptics' first argument against hydrogen vehicles is that they're less efficient than EVs are. Because hydrogen doesn't occur naturally, it has to be extracted, then compressed in fuel tanks.

To convert from nanocoulombs to coulombs, divide the number of nanocoulombs by 10^9.

The conversion between nanocoulombs (nC) and coulombs (C) is based on the fact that 1 coulomb is equal to 10^9 (1 billion) nanocoulombs.

Conversely, to convert from coulombs to nanocoulombs, multiply the number of coulombs by 10^9. For example, if you have 0.5 coulombs, this is equal to 0.5 x 10^9 = 500,000,000 nanocoulombs.

The coulomb is the standard unit of electric charge in the International System of Units (SI), and is used to measure the amount of electric charge in a system. The nanocoulomb is a subunit of the coulomb, and is used to measure small amounts of electric charge.

Conversion between nanocoulombs and coulombs is important in many areas of physics and engineering, including electricity, electronics, and electrical engineering. Understanding the relationship between these units and being able to accurately convert between them is critical for accurate and precise measurement and calculation.

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Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\ \)

From the question

mass of gold = 200 g

density = 20.5 g/mL

It's volume is

\(volume = \frac{200}{20.5} \\ = 9.7560975609...\)

We have the final answer as

Hope this helps you

The value for the molar volume of an ideal gas at STP is very important with regard to stoichiometric calculations. The volume occupied by 176 g of C₃H₈ is 89.4 L.

The volume occupied by one mole of a substance at a given temperature and pressure is called its molar volume at that temperature and pressure. The molar volume at STP is 22.414 L.

At 0°C and 1 atm, 1 mole of any gas behaving ideally occupies a volume of 22.414 L.

The molar mass of C₃H₈ = 44.097 g/mol

The number of moles (n) is given as:

n = Given mass / Molar mass

n = 176 / 44.097 = 3.99 moles

The volume occupied = 3.99 × 22.414 = 89.43 L

Thus the volume occupied by 113 g of C₃H₈ is 89.4 L.

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Your question is incomplete, but most probably your full question was

What volume in liters at STP is occupied by 176 grams of propane, C3H₈?

Round answers to one decimal.

Answer:

CH3CH2CH2CH2CH2CH2OH-HEXAN-1-OL

Explanation:

hope this helps! plz mark as brainliest! :)

Answer:

Molecular Formula is a representation of a compound that what atoms of elements are present in the molecule of a compound. The actual numbers of atoms of each element that occur in the smallest free unit or molecule of the compound is expressed by the molecular formula of the compound. Molecular formulas contain no information about the arrangement of atoms. Because of this, one molecular formula can describe a number of different chemical structures only.

According to the given statement When Sr-80 undergoes decay, the nuclide produces ⁸⁰Rb₃₇.

An element is stable if the forces exerted by its component parts are equal. An molecule is volatile if these components are out of harmony or if the core contains an excessive volume of internal energy (radioactive). The an atom's nucleus might become unstable if there are too many neutrons or protons present.

For Sr - 80, the neutron to proton ratio is 42/38, or 1.1.

Lower than the stable nucleus size ratio of around 1.2.

43/37 = 1.16 is the proton ratio for ⁸⁰ Rb₃₇

As a result, ⁸⁰Rb₃₇ is produced when Sr-80 undergoes decay.

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Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

volume = final volume of water - initial volume of water

volume = 75 - 50 = 25 mL

From the question we have

\(density = \frac{5}{25} = \frac{1}{5} = 0.2 \\ \)

We have the final answer as

Hope this helps you

The given statement is false.

In physics, a quantum (plural quanta) is the minimum amount of any bodily entity (physical property) concerned in an interaction. The vital thinking that a bodily property can be "quantized" is referred to as "the speculation of quantization".[1] This capability that the magnitude of the bodily property can take on only discrete values consisting of integer multiples of one quantum.

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The predicted formula is C₆H₅Br and the molecular weight of that compound is 159.02g/mol and the two peaks at 156 and 158 m/z are above 60 according to the given graph.

Isotopic Abundance in Mass Spectrometry is given below as follows:

The abundance of 12C is 98.91%, M+1 is 13 C 1.1%

The abundance of ¹H is 99.99%  

The abundance of ¹⁶O is 99.76%  

Given the Value of Chlorine is 75.77% for ³⁵Cl and 24.23% for ³⁷Cl

Nominal Mass 35 and 37, the exact mass is 34.9689 and 36.9659.

For Bromine: 50.50% ⁷⁹Br and 49.50% ⁸¹Br  

Nominal Mass 79 and 81, exact mass 78.9183 and 80.9163  The Mass spectrum of C₆H₅Br is as follows

The two peaks at 156m/z and 158 m/z mean that the  Relative Intensity of 156 and 158 m/z are above 60 according to the given graph. The predicted molecular formula C₆H₅Br and molecular weight of C₆H₅Br is 159.02 g/mol.

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The following reactions of alkenes is not stereospecific is C. acid-catalyzed hydration reaction (H₂O/H₂SO₄)

Stereospecific reactions occur when the stereochemistry of the reactant is retained in the product. These types of reactions are distinguished by the use of double-headed arrows in reaction mechanisms to demonstrate the conservation of stereochemistry. The following reactions of alkenes stereospecific are hydrogenation (H₂/P₁), bromination (Br₂ in CH₂Cl₂), bromohydrin formation (Br₂/H₂O).

The acid-catalyzed hydration reaction (H₂O/H₂SO₄) of alkenes is not stereospecific because the H and OH atoms can be added to either face of the alkene's double bond. When the reaction occurs, an intermediate carbocation is formed, which is planar. This carbocation can either be attacked by the nucleophile from above or below, resulting in the formation of an equal amount of stereoisomers. Therefore, the correct answer is C. acid-catalyzed hydration reaction (H₂O/H₂SO₄) is not stereospecific.

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11.4 g/cm³ is equivalent to 1.14 Pg/dal.  In order to convert 11.4 g/cm³ to Pg/dal, we need to use the following conversion factors:

1 g = 10¹² Pg (pico-grams)

1 cm³ = 10⁻¹ dal (deca-liters)

First, we can convert the density from grams per cubic centimeter to grams per liter, since both of these are common units for density. To do this, we simply multiply by 1000 (since there are 1000 cubic centimeters in a liter):

11.4 g/cm³ x 1000 cm³/L = 11400 g/L

Next, we can convert from grams to pico-grams and from liters to deca-liters:

11400 g/L x 10⁻¹² Pg/g x 10⁻¹ dal/L = 1.14 Pg/dal

Therefore, 11.4 g/cm³ is equivalent to 1.14 Pg/dal. This conversion shows that the density is much higher when expressed in pico-grams per deca-liter, as compared to grams per cubic centimeter.

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To determine the total change in enthalpy of a reaction, we need to examine the enthalpy values of the reactants and products and consider their stoichiometric coefficients. Without specific information about the reaction, it is not possible to provide an exact answer from the given options (A, B, C, or D). The total change in enthalpy depends on the specific reaction and the enthalpy values associated with it.

The total change in enthalpy of a reaction, denoted as ΔH, is influenced by the enthalpy values of the reactants and products. It is calculated by subtracting the sum of the enthalpy values of the reactants from the sum of the enthalpy values of the products, considering their stoichiometric coefficients.

However, without specific information about the reaction or enthalpy values associated with it, it is not possible to determine the total change in enthalpy from the given options (A, B, C, or D). The values provided (25 kJ, 30 kJ, 35 kJ, and 55 kJ) are arbitrary and do not correspond to a specific reaction.

To accurately determine the total change in enthalpy, the specific reaction and corresponding enthalpy values need to be provided.

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Answer:

75%

Explanation:

So, the reaction will consume 1 mole of hydrogen gas and produce

1mole H2⋅2 moles NH33moles H2=0.667 moles NH3

at 100% yield. This represents the reaction's theoretical yield.

Now, you know that the reaction produced 0.50 moles of ammonia. This represents the reaction's actual yield.

In order to find the percent yield, you need to figure out how many moles of ammonia are actually produced for every 100 moles of ammonia that could theoretically be produced.

You know that 0.667 moles will produce 0.50 moles, so you can say that

100moles NH3.in theory⋅0.50 moles NH3.actual0.667moles NH3.in theory=75 moles NH3.actual

Therefore, you can say that the reaction has a percent yield equal to

% yield = 75%

polar molecules have an unequal distribution of charges whilst non polar molecules are equally shared between atoms or elements producing no charged end.

The central transition metal ion in the compound \(K[Pt(NH_{3} )Cl_{5}\) is Pt(IV), with a charge of +4 and a coordination number of 5. The coordination number refers to the number of ligands (\(NH_{3}\) and Cl) that are bonded to the Pt ion.

In the compound \(K[Pt(NH_{3} )Cl_{5}\), the central ion is a platinum (Pt) ion with a charge of +4. This is determined by the oxidation state of the Pt ion, which is +4 in this compound. The oxidation state of an element in a compound is a measure of the number of electrons that an atom of that element has gained or lost relative to its elemental state.

The coordination number of the Pt ion in this compound is 5. The coordination number refers to the number of ligands, which are atoms or molecules that are bonded to the central ion. The Pt ion is bonded to five ligands in this compound: five chlorides (Cl) ions and one ammonia (\(NH_{3}\)) molecule. The coordination number of the central ion in a compound is a measure of the number of bonds that the ion forms with surrounding ligands, and it is an important factor in determining the overall structure and properties of the compound.

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Answer:

There are 5.43 grams of NaOCl

Explanation:

The given percent by mass of the solute tells us that out of the 150 g of the solution, 3.62% are due solely to the solute.

In other words, the mass of the solute in the solution is:

Thus, in 150 grams of the given bleach solution, there are 5.43 grams of sodium hypochlorite.