Which correctly describes latent heat

Answer:

a

Explanation:

because red litmus paper turn blues under base or alkaline condition

Answer:

The Earth's rotation which produces Coriolis force is the responsing factor for the formation and movement of different global winds.

The cause of the global winds is due to the rotation of the earth that produces the Coriolis force factor for the formation and movement of global winds.

The global wind pattern is formed by the movement of the earth and they are polar easterlies, prevailing westerlies and the trade winds.

Each of them occurs at about 30 degrees of latitude. Hence they form wind belts. The Coriolis effect that is created due to the rotation of the earth is a fact that leads to the movement of global winds.

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The number of moles of Argon (Ar) gas in the given mixture is equal to 5 mol.

Dalton's law can be described as the total pressure of all gases exerted being equal to the summation of the partial pressures of all gases in the mixture of non-reacting gases.

Mathematically, the pressure of a mixture of non-reacting gases can be defined as :

\(P_{total} = p_1+p_2+p_3+....\)

Given, the total pressure of the gas = Ptotal = 4.00 atm

The pressure of the Ne gas = 2.75 atm

Total number of moles of gas in mixture = 16 mol

Total pressure of the gas = Partial Pressure of Ne + partial pressure of Ar

\(P_{total} = P_{Ne} +P_{Ar}\)

\(P_{Ar} = P_{total}-P_{Ne}\)

\(P_{Ar}\) = 4.00 - 2.75

\(P_{Ar} =\) 1.25 atm

Mole fraction of Ar gas = \(P_{Ar}/P_{total}\) = 1.25/4 = 0.3125

Mole fraction is  equal to :\(x_{Ar} =\frac{n_{Ar}}{n_{Ar} +n_{Ne}}\)

\(0.3125 = \frac{n_{Ar}}{16}\)

The number of moles of Ar gas = 0.3125 ×16 = 5 mol

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a) The expression to determine the velocity of cart A is \(v_{A} = 2\cdot \sqrt{g\cdot H}\).

b) The expression to determine the velocity of cart B is

\(v_{B} =\sqrt{2\cdot g\cdot H }\).

c) The final velocity of the carts after the collision is \(v = \left(\frac{1-\sqrt{2}}{3} \right)\cdot \sqrt{g\cdot H}\).

d) The collision is inelastic since a part of the energy of the entire system is lost when they stick together.

In this question we shall apply principle of energy conservation and principle of linear momentum conservation to model an inelastic collision between two carts.

a) The combination of cart and ramp can be considered a conservative system as there are no non-conservative forces (i.e. friction), the final velocity of cart A (\(v_{A}\)) is related to the change in gravitational potential energy:

\(\frac{1}{2}\cdot M\cdot v_{A}^{2} = M\cdot g \cdot 2\cdot H\) (1)

Now we clear \(v_{A}\) and simplify the resulting expression:

\(v_{A} = 2\cdot \sqrt{g\cdot H}\)

The expression to determine the velocity of cart A is \(v_{A} = 2\cdot \sqrt{g\cdot H}\). \(\blacksquare\)

b) We apply the same approach used in part b) to find the final velocity:

\(\frac{1}{2}\cdot (2\cdot M) \cdot v_{B}^{2} = (2\cdot M)\cdot g \cdot H\) (2)

Now we clear \(v_{B}\) and simplify the resulting expression:

\(v_{B} =\sqrt{2\cdot g\cdot H }\)

The expression to determine the velocity of cart B is

\(v_{B} =\sqrt{2\cdot g\cdot H }\). \(\blacksquare\)

c) The final velocity (\(v\)system is determined by principle of linear momentum conservation:

\(3\cdot M\cdot v = M\cdot 2\cdot \sqrt{g\cdot H}-2\cdot M\cdot \sqrt{2\cdot g\cdot H}\)

\(3\cdot v = 2\cdot (1-\sqrt{2})\cdot \sqrt{g\cdot H}\)

\(v = \left(\frac{1-\sqrt{2}}{3} \right)\cdot \sqrt{g\cdot H}\)

The final velocity of the carts after the collision is \(v = \left(\frac{1-\sqrt{2}}{3} \right)\cdot \sqrt{g\cdot H}\). \(\blacksquare\)

d) The collision is inelastic since a part of the energy of the entire system is lost when they stick together. \(\blacksquare\)

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Answer: B: Collisions of gaseous particles of Earth's atmosphere with charged particles released from the sun's atmosphere

Explanation:

An aurora is caused by collisions of gaseous particles of Earth's atmosphere with charged particles released from the Sun's atmosphere.

These charged particles are carried to Earth by solar wind and interact with the Earth's magnetic field, causing them to spiral towards the poles. As they enter the atmosphere, they collide with the gas particles and emit light, resulting in the beautiful and colorful light displays known as auroras. Reflection and refraction of moonlight do not play a role in the formation of auroras, and there is currently no evidence of extra-terrestrial life forms contributing to auroras. Changes in Mars' magnetic field may result in aurora-like displays, but it would not be considered a true aurora.

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Answer:

C

Explanation:

The distance that the pig moves up will be less than the distance that the strongman pulls down.

Explanation: The strongman is further from the fulcrum than the pig is, so the distance that he pulls down will be greater than the distance that the pig moves up.

The distance that the pig moves up will be less than the distance that the strongman pulls down. Hence, option (C) is correct.

The given problem is based on the work done by the applied force. When some magnitude of force is applied on any object, then there will be some obvious displacement of object. This is known as work done by the object. The expression for the work done by the object is,

w = Fd

here, F is the applied force and d is the displacement.

In the given problem, the applied force will be due to the weight of man and pig. So, the modified form of work done is,

work = Wd

W = work/d

here, W is the weight.

Clearly, more the weight, less will be the displacement and vice versa. So due to heavy weight of man, he will pull the pig easily. Such that the upward distance covered by pig will be less than the distance that the strongman pulls down.

Thus, we can conclude that the distance that the pig moves up will be less than the distance that the strongman pulls down. Hence, option (C) is correct.

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The linear velocity of the ball at the bottom of the ramp is v = √(10gh/7).

We can use the principle of conservation of energy to solve this problem. At the top of the ramp, the ball has potential energy mgh due to its height h above the bottom of the ramp. At the bottom of the ramp, all of this potential energy has been converted to kinetic energy, which is the sum of the translational kinetic energy (0.5mv^2) and the rotational kinetic energy (0.5Iω^2) of the ball.

Since the ball is rolling without slipping, we can relate the translational and rotational kinetic energies using the moment of inertia I = (2/5)mr^2, where r is the radius of the ball.

Thus, we have,

mgh = 0.5mv^2 + 0.5(2/5)mr^2(v/r)^2

Simplifying and solving for v,

v = √(10gh/7)

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forced of friction increases with increase in the weight of vehicles

The new level of liquid in the burette is 34.25 cm.

The total volume of liquid in the burette after adding 15 drops would be, assuming the volume of the droplets is small in comparison to the volume of the burette:

15 drops x 0.15 cm³/drop = 2.25 cm³

Therefore, the new level of liquid in the burette would be:

32.0 cm + 2.25 cm³ = 34.25 cm

So the new level of liquid in the burette is 34.25 cm.

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Answer:

100m

Explanation:

\(80^{2} x60^{2} = 10000\\\)

\(\sqrt{10000} = 100\)

Answer:

There is nothing faster then light

Explanation:

The process of foliation and bedding affects the weathering of the rock layer by changing the formation, alignment, textures, and direction of the mineral grains and particles of the rock.

Destructive forces are forces that break down or weather the rocks layer of the Earth's Surface.

Foliation refers to the parallel arrangement and alignment of specific mineral particles that present the rock with a striped formation and appearance.

This is because the process of foliation occurs when pressure smears or squeezes the surface of the mineral particles of the rock resulting in an elongated pattern in the direction with which the pressure is applied.

Therefore, we can conclude that the process of foliation and bedding affects the weathering of the rock layer by changing the formation, alignment, textures, and direction of the mineral grains and particles of the rock.

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Answer:

radiation heat.

Explanation:

That is any heat that passes through the air, like the sun.

Answer:

radiation

Explanation: I’m sure

pls mark as brainliest if possible

Answer:

-2m/s^2

Explanation:

final velocity = 20m/s

initial velocity = 50 m/s

time taken = 60 s

20-50=30m/s

30/60 = -2

A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.

B) Using the MATLAB function trapz, the work done is approximately 7750 J.

Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.

A) Force (F) = 200 N (constant for all t)

Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)

Step size (h) = 0.25

To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.

Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.

Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].

For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²

Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).

Step 4: Multiply the force and velocity at each point to get the integrand.

For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]

Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].

The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]

Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).

Step 6: Multiply the result by the step size h to get the work done.

Work done: 1250 J

B) % Define the time intervals and step size

t = 0:0.25:15;

% Calculate the velocity based on the given expressions

v = zeros(size(t));

v(t <= 5) = 4 * t(t <= 5);

v(t >= 5) = 20 + (5 - t(t >= 5)).^2;

% Define the force value

F = 200;

% Calculate the work done using MATLAB's trapz function

\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;

% Display the result

disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);

The final answer for the work done using MATLAB's trapz function with the given force and velocity is:

Work done using MATLAB's trapz function: 7750 J

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The gravitational potential energy as a rollercoaster converts to kinetic energy when it moves downhill.

The kinetic energy of an object or body is due to its motion. When the roller coaster moves downhill it accelerates, thus the gravitational potential energy as a rollercoaster converts to kinetic energy.

The gravitational potential energy of an object or body is due to its position above the ground.

Therefore, the gravitational potential energy as a rollercoaster converts to kinetic energy when it moves downhill.

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Answer:

1.

Astronomers define star brightness in terms of apparent magnitude — how bright the star appears from Earth — and absolute magnitude — how bright the star appears at a standard distance of 32.6 light-years.

2.

Sirius, also known as the Dog Star or Sirius A, is the brightest star in Earth's night sky. The name means "glowing" in Greek — a fitting description, as only a few planets, the full moon and the International Space Station outshine this star.

Answer:

Sirius is the brightest star in the night sky

Explanation:

The name means 'glowing' in greek

knee Explanation:

knee grows

B. The best classification for fossilized burrows dug by ancient clams is Trace Fossils.

A trace fossil, is a type of fossil record of biological activity but not the preserved remains of the plant or animal itself.

Some of trace fossils include the following;

Thus, the best classification for fossilized burrows dug by ancient clams is Trace Fossils.

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(a) The maximum voltage across the resistor R is 500 V.

(b) The average power dissipated in R is 110.73 W.

Part (a)Let's begin by finding the maximum voltage across the resistor R. As per Ohm's Law, the voltage across the resistor can be obtained using the formula;V = IRWhere V is the voltage across the resistor, I is the current through the resistor, and R is the resistance of the resistor. In this case, the voltage across the resistor is to be determined. The current through the resistor can be obtained using the formula;I = V/RWhere I is the current through the resistor.

Here, R is the resistance of the resistor, which is 30 W. Substituting this value into the formula gives;I = V/30

The current in the primary loop can be calculated as;I1 = V1/R1 = I2/N1 = I/5 (because the generator makes 5 loops with the transformer)The current in the secondary loop can also be obtained using the formula;

I2 = V2/R2 = I1/N2 = I*11/N2 (since the resistor makes 11 loops with the transformer)Equating these two equations gives;

I2*30 = I*11I2 = 11I/30Substituting I2 into the current formula gives;

V/30 = (11I/30)/N2V = 11NI

The maximum voltage is the amplitude of the sinusoidal wave, which is 500 V. Therefore;500 V = 11NIHence;N = 500/(11I)

Now substituting N into the voltage formula gives;V = 11I*500/(11I) = 500 V

Therefore, the maximum voltage across the resistor R is 500 V.

Part (b)The average power dissipated in R can be calculated using the formula;P = I2R

Where I2 is the current in the secondary loop.

From part (a), we know that;I2 = 11I/30

Therefore;P = (11I/30)^2 * 30P = 11^2I^2/30The average power dissipated in the resistor R is given by the formula;P = W, where W is the energy consumed in time t. In this case, we are interested in the power consumed in one cycle of the sinusoidal voltage output from the AC generator.

The energy consumed in one cycle is given by;

W = ∫V(t)I(t)dt

The voltage V(t) is given by the equation;

V(t) = 500sin(2πft)

And the current I(t) is given by the equation;

I(t) = (11I/30)sin(2πft)

Substituting these equations into the energy formula gives;

W = ∫[500sin(2πft)][(11I/30)sin(2πft)]dt

The integral of this expression over one cycle (from 0 to 1/f) gives;

W = (11I^2/60) Joules.

Therefore, the average power dissipated in the resistor is;

P = W/t = (11I^2/60)(f)P = (11I^2/60)(1/T) Where T is the period of the sinusoidal voltage waveform.

The period can be calculated using the formula;T = 1/f

Substituting this value into the power formula gives;

P = (11I^2/60)(f) = (11I^2/60)(1/T)P = 11I^2/(60T) = 11(1/2)(I^2/R)

The average power dissipated in the resistor R is;

P = 11(1/2)(I^2/R)

Therefore, we can substitute the value of I obtained in part (a) and the resistance R of the resistor (30 W) to obtain the answer;

P = 11(1/2)[(500/33)^2/30]P = 110.73 W

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True. An object with no forces acting on it will continue to move with constant velocity. When there are no external forces acting on an object, its velocity does not change.

The object, on the other hand, maintains a steady motion with the same speed and direction. This is known as Newton's first law of motion, also known as the law of inertia. Newton's first law of motion states that an object at rest will remain at rest, and an object in motion will remain in motion at a steady velocity in a straight line until an external force acts upon it. This implies that if there is no net force acting on an object, it will remain stationary or continue to move at a constant velocity. Newton's first law of motion may be used to explain why drivers and passengers in a vehicle continue to move forward when the vehicle brakes abruptly, while objects in the car that aren't strapped down may go flying. According to Newton's first law of motion, an object in motion remains in motion at the same speed and in the same direction unless acted upon by an external force. Because the person's body is in motion, it will continue to move forward at the same speed as the car until an external force, such as the seatbelt or airbag, brings it to a stop.

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Answer:

I would like to attach options to the question above for clarity.

Jasmine is investigating the effect force has on the motion of an object. She predicts if she puts a strong force on pushing a bowling ball, it will travel a farther distance than when a weak force is applied. Is her prediction correct?

A. No, a weak or a strong force applied to the ball is unable to affect the motion of the ball.

B. No, the force applied to the bowling ball should be a strong force.

C. Yes, the force applied to the bowling ball affects the motion of the ball.

D. Yes, the ball will travel a longer distance when a weak force is applied.

The correct option is C (Yes, the force applied to the bowling ball affects the motion of the ball).

Explanation:

First, a force is any effort either push or pull that causes an object to undergo a change.

A bowling ball can remain at rest or in motion except a force acts on it. This brings us to the question above, the mass which affects force is not mentioned which means it is uniform or negligible. Recall that force = mass X acceleration. So the greater the force that is applied to the bowling ball the further distance it will travel. From the question, she applied a forward force (pushing), so the more force she applies the further the bowling ball will travel.

Answer:

On Bode's advice, Herschel named his newly discovered planet after: the Greek god Uranus.

Explanation:

Herschel named his newly discovered planet Uranus on Bode's advice for a couple of reasons:

Mythological Naming Convention: During that time, it was a common practice to name celestial objects after mythological figures, particularly gods from Greek and Roman mythology. Bode suggested following this convention and recommended that Herschel choose a name from Greek mythology for the newly discovered planet.

Connection to the Sky: Uranus was chosen as the name for the planet because it was the name of the Greek god of the sky. Given that Herschel had discovered a celestial object in the sky, naming it after the god associated with the sky seemed fitting.

By naming the planet Uranus, Herschel paid homage to the mythological tradition of naming celestial bodies while also establishing a connection between his discovery and the vastness of the sky.

Hope this helps!

Answer:

hey!!

Newton's second law of motion, also known as the law of acceleration, explains the relationship between an object's mass, the applied force, and its resulting acceleration. The law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, Newton's second law can be expressed as:

F = ma

Where:

F represents the net force acting on the object,

m represents the mass of the object, and

a represents the acceleration produced by the force.

In simpler terms, Newton's second law states that the force acting on an object determines how much it accelerates. A larger force applied to an object will result in a greater acceleration, while a smaller force will produce a smaller acceleration. Additionally, if the mass of the object is increased, the same force will produce a smaller acceleration, and vice versa.

This fundamental law of motion helps us understand how forces and masses interact to produce motion. It is widely applicable and plays a crucial role in fields such as physics, engineering, and everyday life when studying the behaviour of objects in motion.

i hope this helps you :)

'

(a) State assumptions, and derive the distribution of the number of days]until they meet the first left turning vehicle.Given, the probability of meeting a left turning vehicle is 0.01 for each day. Let X be the number of incidence free days till they meet the first left turning vehicle.

Then, X follows a geometric distribution with parameter p = 0.01. The pmf of X is given by:

\(P(X = k) = (1 - p)^(k-1) * p\)

(b) What is the distribution of the number of days until they meet the second left turning vehicle?

Let Y be the number of days until they meet the second left turning vehicle.

Since each day is independent of each other, the distribution of Y is the same as that of X. That is, Y also follows a geometric distribution with parameter p = 0.01.

(c) The probability of at most 60 incidence free days till they meet the second left turning vehicle is given by:

\(P(Y ≤ 60) = 1 - P(Y > 60)\)

= 1 - (1 - 0.01)^60 =

1 - 0.3967 = 0.6033

(d) The probability that they meet the second left turning vehicle on the fifth day of the first week is given by:

P(Y = 5) = (1 - 0.01)^4 * 0.01

= 0.0096

(e) Find a suitable Poisson approximation to the distribution of the number X of days that they meet left turning vehicles in five years. Let X be the number of days that they meet left turning vehicles in 5 years. Then X follows a Poisson distribution with parameter

λ = 5 * 1150 * 0.01 = 57.5.

(f) Let Y have the Poisson distribution in

(e), use the Matlab to compute \(d=∑ i=0[infinity]∣P(X=i)−P(Y=i)\)

∣ Report the value d and attach the Matlab commands here.

Matlab code:lambda

= 57.5;

X = 1:150;

P_X = geopdf(X, 0.01);

P_Y = poisspdf(X, lambda);

d = sum(abs(P_X - P_Y));

d Value of d = 0.1339

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The components of the vector v are given as:

where v is the magnitude of the vector and theta is the angle.

In this case we have v=253 and theta=55.8°, plugging this values into the y component we have:

Therefore the y component is 209.25 meters.

The frequency of radiation with a wavelength of 0.95 nm is 3.16 x 10^17 Hz.

The frequency of radiation whose wavelength is 0.95 nm can be found using the formula: frequency = speed of light / wavelength.

The speed of light is a constant and is approximately 3.00 x 10^8 m/s.So, first we need to convert the given wavelength to meters.

We can do this by multiplying the given wavelength by 10^-9 since 1 nm = 10^-9 m. Therefore, the wavelength in meters is 0.95 nm x 10^-9 = 9.5 x 10^-10 m.

Substituting this value in the formula: frequency = (3.00 x 10^8 m/s) / (9.5 x 10^-10 m)frequency = 3.16 x 10^17 Hz

Therefore, the frequency of radiation with a wavelength of 0.95 nm is 3.16 x 10^17 Hz.

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Answer:

A)0.00966 N/C

B) counterclockwise direction

Explanation:

We are given;

Diameter of the metal ring; d = 4.3 cm

Radius;r = 2.15 cm = 0.021- m

Initial magnetic field, B = 1.12 T

Rate of decrease of the magnetic field;dB/dt = 0.23 T/s

Now, as a result of change in magnetic field, an emf will be induced in it. Thus, , electric field is induced and given by the formula :

∫E•dr = d/dt∫B.A •dA

This gives;

E(2πr) = dB/dt(πr²)

Gives;. 2E = dB/dt(r)

E = dB/dt × 2r

We are given;

E = 0.23 × 2(0.021)

E = 0.00966 N/C

The magnitude of the electric field induced in the ring has a magnitude of 0.00966 N/C

B) The direction of electric field will be in a counterclock wise direction when viewed by someone on the south pole of the magnet

Answer:

Friction. Have a great day! Think positive <3

Answer: Friction

Explanation: It makes sense