The given code demonstrates the implementation of a remote method invocation (RMI) in Java. It sets up a server-side application that registers a remote object for remote method invocation.
The code uses the java.rmi.Naming class and includes a CalculatorServer class with a constructor and a main method. The constructor instantiates a CalculatorImpl object, which represents the actual implementation of the remote methods.
The Naming.rebind method is used to bind the remote object to a specific name in the RMI registry. The code is executed on the server-side to set up the RMI server.
import java.rmi.Naming;: This line imports the Naming class from the java.rmi package, which provides methods for binding and looking up remote objects in the RMI registry. This line is used on the server-side.
public class CalculatorServer: This line declares a public class named CalculatorServer, which represents the server-side application for RMI.
public CalculatorServer(): This is the constructor of the CalculatorServer class, which is responsible for setting up the RMI server.
Calculator c = new CalculatorImpl();: This line creates an instance of the CalculatorImpl class, which implements the remote methods defined in the Calculator interface. This line is used on the server-side.
Naming.rebind("rmi://localhost:1099/CalculatorService", c);: This line binds the remote object (c) to the specified name (CalculatorService) in the RMI registry using the rebind method of the Naming class. The URL "rmi://localhost:1099/CalculatorService" represents the location and name of the remote object. This line is used on the server-side.
System.out.println("Trouble: " + e);: This line prints an error message if an exception occurs during the execution of the code. It is used to handle any potential exceptions that may arise. This line is used on the server-side.
public static void main(String args[]) { new CalculatorServer(); }: This is the main method of the CalculatorServer class. It creates an instance of the CalculatorServer class, which triggers the setup of the RMI server. This line is used on the server-side to initiate the execution of the server application.
To learn more about constructor visit:
brainly.com/question/13097549
#SPJ11
If OSHA determines that an employer's response to a non-formal complaint is adequate, what options does the employee filing the non-formal complaint have?
Which of the following classes of biomaterials would be most appropriate for fabricating an artificial tendon, a tissue that must sustain substantial deformation at low forces and quickly regain its original dimensions after stress release? Why ?
(a) Metals
(b) Ceramics
(c) Polymers
This list gives the lengths of different leaves in centimeters. 7. 5, 9. 5, 9. 0, 8. 0, 7. 5, 8. 5, 7. 5, 8. 5, 9. 5, 8. 5, 9. 0, 9. 5, 8. 0, 9. 5, 8. 0, 9. 0, 9. 0, 9. 0 Create a line plot to display the data. To create a line plot, hover over each number on the number line. Then click and drag up to plot the data
The line plot would have a number line ranging from 7 to 9.5 with increments of 0.5. There would be data points plotted at 7.5, 9.5, 9.0, 8.0, 8.5, and 9.0, with multiple points at certain values.
The line plot would visually represent the distribution of leaf lengths.
Here is a textual representation of the line plot based on the given data:
7.5 | X
7.75 |
8.0 | X
8.25 |
8.5 | X X
8.75 |
9.0 | X X X X
9.25 |
9.5 | X X X
9.75 |
In the line plot, each X represents a data point from the given list. The vertical axis represents the count or frequency of each length, while the horizontal axis represents the range of lengths.
To know more about data click the link below:
brainly.com/question/29610516
#SPJ11
Suppose that in a machining operation of multidirectional FRPs you are getting high principal (cutting) forces. Which action would you take to reduce the principal forces
To reduce high principal (cutting) forces in machining multidirectional FRPs, adjusting the cutting parameters would be an effective action.
What cutting parameters can be adjusted to reduce principal forces in machining multidirectional FRPs?By optimizing the cutting parameters, it is possible to minimize the principal forces experienced during the machining of multidirectional FRPs. One key parameter to consider is the cutting speed. Decreasing the cutting speed can help reduce the forces generated, as it allows for better heat dissipation and prevents excessive stress on the material. Additionally, adjusting the feed rate, which refers to the speed at which the cutting tool advances, can also have an impact. Lowering the feed rate can help reduce the forces acting on the material during machining.
Furthermore, selecting the appropriate tool geometry and material can contribute to reducing principal forces. Using a tool with a sharper cutting edge or one specifically designed for machining FRPs can result in improved cutting performance and reduced forces. Moreover, considering the use of cutting fluids or coolants can aid in dissipating heat and lubricating the cutting process, thereby minimizing forces.
Learn more about: high principal
brainly.com/question/32216997
#SPJ11
What value is returned by the following function? Express your answer as a function of n. Give the worst-case running time using the Big-Oh notation. function mystery(n) r = 0 for i = 1 to n - 1 do for j = i + 1 to n do for k = 1 toj do r=r+1 return(r)
This code contains three loops. The first loop's I values range from 1, 2, 3,..., n-1, and also the n-value is O(\(n^{3}\)).
What exactly is coding?We connect with computers through coding, often known as computer programming. Coding is similar to writing a sequence of commands since it instructs a machine what to do. You can instruct machines or tell them how and where to behave much more quickly by mastering the art of code.
Is coding difficult?If you select an introductory programming language, learning to code is simple. It might be challenging to begin programming if you try and start with a more advanced coding language. Spend some time learning simpler languages. Python should be used before more advanced languages.
First loop running for n-1 times Values of j during second loop are from i+1,i+2,i+3,..,n So, Second loop running for n-i-1 times.
So, in worst case second loop running for n times Values of k during the loop are 1,2,3,....,j So, Third loop running for j times
So, in worst case third loop running for n times
Time complexity = O(Product of number of times three loop runs) = O(n*n*n) = O(\(n^{3}\)) So, answer is O(\(n^{3}\))
Therefore the value of n is O(\(n^{3}\)).
To know more about code visit:
https://brainly.com/question/16039305
#SPJ4
Consider a mild steel specimen with yield strength of 43.5 ksi and Young's modulus of 29,000 ksi. It is stretched up to a point where the strain in the specimen is 0.2% (or 0.002). If the specimen is unloaded (i.e. load reduces to zero), the residual strain (or permanent set) is: 0.05% 0.1% 0% 0.2%
Answer:
0.05%
Explanation:
From the question, we have;
The yield strength of the mild steel, \(\sigma _c\) = 43.5 ksi
Young's modulus of elasticity, ∈ = 29,000 ksi
The total strain, \(\epsilon _c\) = 0.2% = 0.002
The inelatic strain \(\epsilon_c^{in}\) is given as follows;
\(\epsilon_c^{in}\) = \(\epsilon _c\) - \(\sigma _c\)/∈
Therefore, we have;
\(\epsilon_c^{in}\) = 0.002 - 43.5/(29,000) = 0.0005
Therefore, the inelastic strain, \(\epsilon_c^{in}\) = 0.0005 = 0.05%
Taking the inelastic strain as the residual strain, we have;
The residual strain = 0.05%
Find the Laplace transform F(s) = L {f(t)} of the function f(t) = 3 + sin(6t), defined on the interval t greaterthanorequalto 0. F(s) = L {3 + sin (6t)} = For what values of s does the Laplace transform exist?
The Laplace transform exists for all s such that the integral defining F(s) converges, i.e., for all s in the complex plane such that Re(s) > 0.
The Laplace transform is a mathematical tool used to transform a function of time (usually denoted by f(t)) into a function of a complex variable (usually denoted by F(s)), where s is a complex frequency parameter.
Using the linearity property of the Laplace transform, we have:
L{3} = 3/s (by the formula L{1} = 1/s)
\(L{sin(6t)} = 6/(s^2 + 6^2)\) (by the formula L{sin(at)} = \(a/(s^2 + a^2))\)
So, applying the formula L{f(t)} = L{3 + sin(6t)} = L{3} + L{sin(6t)} we get:
F(s) = L{f(t)} = 3/s + 6/\((s^2 + 6^2)\)
Thus, for all s such that the integral defining F(s) converges, i.e. for all s in the complex plane such that Re(s) > 0, the Laplace transform exists.
For more details regarding Laplace transform, visit:
https://brainly.com/question/31481915
#SPJ4
A turbine of a fossil fuel burning installation delivers 1,500 hp of mechanical energy to a generator. The generator then converts 80.0% of the mechanical energy into electrical energy. If the terminal potential difference of the generator is 1790 V, what current does it deliver (in A)
Answer:
The generator delivers current of 500.11 A
Explanation:
Given the data in the question;
mechanical energy delivered to the generator = 1500 hp
efficiency η = 80.0 %
terminal potential difference of the generator = 1790 V
we know that;
1 hp = 746 W
so
the mechanical energy delivered to the generator will be
Generator Input = ( 1500 × 746 )W = 1119000 W
So the generator output will be;
Generator Output = Generator Input × η
we substitute
Generator Output = 1119000 W × 80.0 %
Generator Output = 1119000 W × 0.8
Generator Output = 895200 W
So the Current will be;
\(I\) = Generator Output / terminal potential difference of the generator
we substitute
\(I\) = 895200 W / 1790 V
\(I\) = 500.11 A
Therefore, The generator delivers current of 500.11 A
what is the force that counteracts the weight force for flight?
Lift force that balances an object's weight so that it remains in the air. Lift grows as the airplane travels faster until its force is equivalent to the weight.
What does flying thrust force mean?The force that propels a plane forward through the air is called thrust. A jet engine or a propeller both provide thrust. Lift, gravity, thrust, and drag are the four factors that affect an aircraft when it is flying straight and level. Lift equals gravity, and thrust equals drag, so the opposing forces are balanced against one another.
What are the four lifting forces in flight?Four forces interact with an airplane during flight: lift, a force that acts upward; gravity, a force that acts downward; thrust, a force that acts forward; and friction drag, the force acting backward (also called wind resistance). Thrust counters drag, while lift counters gravity.
To know more about Lift force visit:-
https://brainly.com/question/16380983
#SPJ4
Consider a Diesel cycle that starts (at point a in Fig. 20.7) with air at temperature Ta. The air may be treated as an ideal gas. (a) If the temperature at point c is Tc, derive an expression for the efficiency of the cycle in terms of the compression ratio r. (b) What is the efficiency if Ta
Answer:
b
Explanation:
what is anythin efficiency if ta
8. Find the volume of the figure shown below: * V=L x W x H 7 cm 2 cm 2 cm
water (10 oc) flows with a speed of 2 m/s through a horizontal run of pvc pipe. the length of the pipe is 50 m, and the pipe is schedule 40 with a nominal diameter of 2.5 inch. calculate: a) the pressure drop in kpa b) the head loss in meters c) the power in watts needed to overcome the head loss
The pipe is schedule 40 and has a nominal diameter of 2.5 inches. It is 50 meters long. Then pressure drop is 29.1kpa,Head loss is 2.967m and power is 176.986 watt.
a)Pressure drop = 32μVL/D²
=32*1.307*10⁻³*2*50/0.0119882
=29102.6 pascal
=29.1 Kpa
b)Head loss=p1-p2/pg=29.1*10³/999.7*9.81
=2.967 m
c)power=(p1-P2)q
=29.1*10³*6.082*10⁻³
Power =176.986 watt //watt is the unit of power
The difference in total pressure between two points on a network used to transport fluids is known as a pressure drop. When frictional forces acting on a fluid as it flows through the tube, brought on by the resistance to flow, occur, a pressure drop happens.
Learn more about pressure drop here:
https://brainly.com/question/15851784
#SPJ4
this is it dont anwser this is for my other account
Answer:
thanks for the poiunts
Explanation:
Type your answer in the box. which implies that every In engineering, all equations must be dimensionally term must have the same unit. Read about this Do you know the answer? I know it Think so Unsure No idea
In engineering, it is important that all equations be dimensionally consistent, which means that every term must have the same unit.
This ensures that the equation is physically meaningful and that the results are accurate. Dimensional consistency is a key concept in engineering and is used to check the validity of equations and to derive new equations. It is also important for converting units and for making sure that all terms in an equation are in the correct units.
Without dimensional consistency, equations can lead to incorrect results and can cause problems in engineering design and analysis.
Learn more about engineering:
https://brainly.com/question/28321052
#SPJ11
the primary difference between integrated/concurrent engineering development and functional/sequential development is:
Integrated development invests more money upfront to make savings later on. Sequential development covers the stages of development more thoroughly.
An integrated development environment (IDE) is a piece of software that offers computer programmers a full range of tools for creating software. A build automation tools and a source code editor are typically included in an IDE. SharpDevelop is an example of IDEs that lacks the requisite compiler, interpreter, or both. Other IDEs, such as NetBeans and Eclipse, do.
A version control system or numerous tools to make the creation of a graphical user interface (GUI) simpler may be included, blurring the line between an IDE and other components of the larger development environment. For usage in object-oriented software development, a class browser, an object browser, and a class hierarchy diagram are also common features of contemporary IDEs.
Learn more about integrated development here:
https://brainly.com/question/9671083
#SPJ4
Sawzall® is another term commonly applied to?
O reciprocating saws
Otable saws
O jigsaws
O circular saws
Answer:
reciprocating saw
Explanation:
Which of the following materials are considered resilient flooring? a. Ceramic tile, b. brick, c. stone, d. terrazzo, e. concrete.
The correct answer is option d. Resilient flooring materials include d. terrazzo.
Resilient flooring refers to flooring materials that have some degree of flexibility and bounce back when compressed. In the provided options, only terrazzo is considered a resilient flooring material. Terrazzo is a composite material typically made from a combination of marble, granite, glass, or other aggregates mixed with a cementitious or epoxy binder. It is poured and then polished to create a smooth and durable surface. Terrazzo offers some level of flexibility and resilience due to its composition, allowing it to absorb impact and provide a certain degree of comfort underfoot.
On the other hand, ceramic tile, brick, stone, and concrete are not considered resilient flooring materials. These materials are generally rigid and do not possess the same flexibility or cushioning properties as terrazzo. They are commonly used for their durability, aesthetics, and suitability in various applications but do not fall under the category of resilient flooring.
Learn more about terrazzo here;
https://brainly.com/question/28261247
#SPJ11
What failure(s) would you suspect if the output of a 3-input NAND gate stays HIGH no matter what the inputs are
Answer:A 4-input NAND gate is normally high. It can only go low when all four of the inputs have a logical high on them. Assuming the circuit should see a condition where all four inputs go high, then a constant high output indicates a fault does exist.The first step in troubleshooting this failure is to verify the circuit, under normal operation should be seeing a condition where all four inputs do go high. It is completely possible that the circuit is working properly and the condition you were expecting simply does not occur. Verifying what your inputs should be allow you to confirm whether a failure exists in reality.Second, you should verify that the logic probe, multi-meter, oscilloscope, logic analyzer, or monitoring circuit you are using to test circuit outputs is working properly. This is easiest done by touching the probe of the monitoring device to another output you should see changing states. In one system I once had to trouble-shoot, the device had a built-in monitoring circuit and the failure was actually in the monitoring circuit rather than in the main circuit. Once you have confirmed that your test equipment is working properly, you can begin testing the actual circuit to troubleshoot the failure.Given that the circuit should be seeing periods where the gate should go low and that your test equipment is working properly, then a constant high output on this gate means either the output of the gate is open (assuming their is a tie-up resistor somewhere on the output line) or at least one of the inputs is being held low. A constant low input could be a failed gate driving one of the inputs, a short to ground on the circuit board trace connected to the constant low input, or a tie-up resistor on the input that has opened (Technically, this last cause creates a floating input which could intermittently be seen as either a high or low, but in my experience is invariably seen as a low.) The only way to determine which fault exists is to measure the voltages on each input pin to determine which input is failing and then trace the constant low back to its source.729 viewsView 1 upvote1Add a comment...Sponsored by Purdue University OnlinePurdue's 100% Online Master's Now Accepting Applications.Earn an online MS in Electrical and Computer Engineering degree in 12-24 months. View curriculum guide.Learn MoreLoring Chien, Electrical Engineer for 45 years & IEEE Sr. Life memberAnswered Jul 2, 2020
Explanation:
When you trace errors in a workbook, what types of cells does Excel identify? Select all the options that apply. a. independent cells on the current worksheet b. dependent cells on the current worksheet c. precedent cells on the current worksheet d. precedent cells on other worksheets
The cells referred to by a selected formula that contains an error message are displayed when you use Excel's Trace Error function.
How can cell mistakes be tracked down? When you use Excel's Trace Problem feature, it identifies the cells that a chosen formula references and displays any error messages.If it turns out that the formula won't work because of the cell referencing, you may then correct the cell references inside the formula cell to solve the mistake.Choose the worksheet that needs to be checked for mistakes.Press F9 to recalculate the worksheet if it is being calculated by hand.Click on the Formulas tab > Formula Auditing > Error Checking to reveal the Error Checking window if it is not already visible.Follow up on the cells that a formula uses for its data (precedents). Decide which cell holds the formula for which you're looking for prior data.On the Formulas tab, select Trace Precedents from the Formula Auditing group to show a tracer arrow to each cell that directly supplies data to the active cell.To learn more about Excel's Trace Error refer
https://brainly.com/question/28488328
#SPJ4
Legal metrology would protect consumers from businesses that do not take measurements according to defined measuring regulations.
From what my research concluded, true
Za answa iz:
True
Twust meh
Why is the reversed Carnot cycle executed within the saturation dome not a realistic model for refrigeration cycles?
Explanation:
The paths of warmth and job interactions are inverted by repeating the Carnot process. A Carnot fridge or a Carnot heating system is considered a fridge or heat engine that acts on the reverse Carnot cycle.
The Carnot process comprises liquid phase mixture compression and expanding, which limits mechanical components.
Which of these functions in excel is best suited for extracing a substring from within a long text message? a) LOWER Ob) TRIM c) MID d) LEN e) CONCAT
MID function in excel is best suited for extracting a substring from within a long text message.
MID can return a specific number of characters from a long text string, starting at the position you specify, based on the number of characters you specify. The MID function is under Excel TEXT functions.
Formula:
=MID(text,start_num,num_chars)
The MID function uses the arguments given below:
Text (required argument) – The original text or string.
Start_num (required argument) – This argument is an integer. It specifies the position of the first character that you want out of the long text.
Num_chars (required argument) – This is an integer that specifies the number of characters, starting with start_num, to be returned from the start.
Learn more about Excel at:
brainly.com/question/24749457
#SPJ4
Calculate the maximum value of shear flow, , in the web at a section 1m from the free end of the beam.
Answer:
See explanation
Explanation:
Since no figure was given, I'll explain how to do this problem theoretically. The formula for shear flow is \(q=\frac{VQ}{I}\) where V is the shear force, Q is the moment of area (more on this later), and I is the moment of inertia.
The first step to solve this problem is to find the resultant internal forces of the beam. This can be done in several ways, but the easiest is to solve the beam statically and draw a shear diagram to determine the maximum shear force V.
The second step to solving this problem is to determine the location of the neutral axis of the cross section if it is not given. The formula for the neutral axis is \(NA = \frac{\sum y*A}{\sum A}\). The y in this equation represents the middle of the small shapes that the web is divided into. An I-beam can be thought of as 3 rectangles, while a T-beam can be thought of as 2. The A in this formula represents the area of each of the rectangles (an I-beam will have 3 of these and a T-beam will have 2).
The third step for this problem is to find the moment of inertia. There are several formulas for moment of inertia depending on the shape of the cross section. I-beam's and T-beams both can be thought of as multiple rectangles, so they have the same base formula of \(I=\frac{1}{12}bh^3\) where b is the base of the rectangles and h is the height. For I-beams, the easiest way to calculate moment of inertia is to think of the entire cross section as a big rectangle that had two smaller rectangles cut out of it. The formula for this moment of inertia becomes \(I=\frac{1}{12} b_{big}h^{3} _{big}-\frac{1}{6}b_{small}h^{3}_{small}\). Note that this form of moment of inertia already takes into account subtracting 2 small rectangles. For T-beams, this approach will not work, so the parallel axis theorem must be used. The moment of inertia for the T-beam becomes \(I=\frac{1}{12}b_{1} h^{3}_{1} +b_{1}h_{1}dy_{1}^{2} +\frac{1}{12}b_{2} h^{3}_{2} +b_{2}h_{2}dy_{2}^{2}\) where the terms with the subscript 1 represent the first rectangle and the terms with the subscript 2 represent the second rectangle. The dy terms represent the distance from the center of that specific rectangle to the neutral axis.
The fourth step for this problem is to find Q. The formula to find Q is \(Q=\sum y'A'\) where y' represents the distance from the neutral axis to the center of the "wanted" point and A' is the area of the rectangle that has the wanted point at its center. (This would be the area above or below the thickness (t) if you were solving for maximum shear \(\tau=\frac{VQ}{It}\)).
The last step for this problem is to substitute the found values into the formula for shear flow \(q=\frac{VQ}{I}\). V came from step 1, Q came from step 4, and I came from step 3.
which one of these reduce fraction?
if citrus overlord is 200 (I'm offering for a lucid leaf) and shiny eternal contrast is 250, 450 so far and I'm also last thing offering for lucid (which is 100 secret value and I'm offering in shiny value and Lucid's shiny value is 500 but gets op's because it's a secret pet) is a shiny dark omen which is 100, I'm offering 550 for 500 but gets op's, w or l, I think w.
Answer: I'm pretty sure your taking a W.
your getting a W, lucid isn't that bad to trade, you can probably flip lucid for more shiny's and getting a better offer because omen has bad demand and you can tell someone to switch it for something better you can flip lucid and get better pets ok so accept and trade lucid unless you wanna keep it.
Explanation:
Answer:
gg's if you did it cause w
Explanation:
Explain what the ancient Romans did to solve the problem in the following scenario.
Situation: In ancient Italy, farmers were experiencing a drought. Rather than move to where the water was, Roman inventors decided to bring the water to the farmers.
Answer:
They moved fresh water around their vast empire with aqueducts and canals.
Explanation:
A. A solidified lava flow containing zircon mineral crystals is present in a sequence of rock layers that are exposed in a hillside.A mass spectrometer analysis was used to count the atoms of uranium-235 and lead-207 isotopes in zircon samples from thelava flow. The analysis revealed that 71% of the atoms were uranium-235, and 29% of the atoms were lead-207. Refer toFIGURE 8.11 to help you answer the following questions.1. About how many half-lives of the uranium-235to lead-207 decay pair have elapsed in the zircon crystals? ______________2. What is the absolute age of the lava flow based onits zircon crystals? Show your calculations.3. What is the age of the rocklayers above the lava flow? _______________4. What is the age of the rocklayers beneath the lava flow? _______________B. Astronomers think that Earth probably formed at the same time as
Answer:
1. 0.494
2. = 352.299 million years
3. It is between 0 years to 352.299 million years
4. greater than the 352.299 million years.
Explanation:
Given
Uranium 235 ———— lead 207( zircon sample)
t= 0 100%. 0%
t= t. 71%. 29%
1)- half lives elapsed = n
(1/2)n = 0.71
By taking log and solving n = 0.494
No of half lives = 0.494
2) Calculating the age of the larva
- age of lava flow = half life of uranium 235 x n
= 713 x 0.494
= 352.299 million years
3)- The rock layers was created above this lava flow is of later occurrence so the age will be lower than that of the age of the lava flow so the age of rock over the lava flow will lower than the 352.299 million years it will be in between 0 years to 352.299 million years.
4)- The rock layers created underneath this lava flow is of earlier occurrence so its age is more than that of the age of the lava flow so the age of rock will more than the lava flow is greater than the 352.299 million years.
B. The astronomers think the earth was created as all of the other rock materials in our solar system, including the oldest meteorites. The oldest meteorites ever found on Earth contain nearly equal amounts of both Uranium-238 and Lead-206.
The number of half-lives of the uranium-235to lead-207 decay pair have elapsed in the zircon crystals is; 0.494
What is the number of half lives?We are given;
The atoms of Uranium-235 and lead-207 which made up the zircon sample.
At t = 0; Uranium-235 is 100% while lead-207 is 0%
At t = t; Uranium-235 is 71% while lead-207 is 29%
1) Let the half lives that elapsed be n. Thus;
(¹/₂)ⁿ = 0.71
n*log0.5 = log 0.71
n = (log 0.71)/(log 0.5)
n = 0.494
Thus;
Number of half lives = 0.494
2) Formula to get the absolute age of the larva is;
Absolute age age of lava flow = half life of uranium-235 * n
The half life of uranium-235 is 713 million years. Thus;
Absolute age age of lava flow = 713 * 0.494
Absolute age of lava flow = 352.22 million years
3) The rock layers above the lava flow were created after the lava flow and so the age will be lower than that of the age of the lava flow. Thus, it's age will be between 0 years and 352.299 million years.
4) A: The rock layers beneath the lava flow were in existence earlier than the lava flow and as such, the age of rock layers beneath the lava flow will be greater than 352.22 million years.
B; The astronomers think the earth was created as all of the other rock materials in our solar system.
Read more about Half life at; https://brainly.com/question/26148784
Briefly explain the four (4) main classification of rural latrine in Ghana and give example each.
Answer:
Temporally pit latrine ,improved latrine,ordinary latrine
Explanation:
l think the temporally latrine are used for camp ,vacation. improved latrine are at home for those who can afford. an ordinary latrine is used by people who can not afford money for removing fieces in the improved or temporally latrine
As part of a heat treatment process, cylindrical, 304 stainless steel rods of 100-mm diameter are cooled from an initial temperature of 500 C by suspending them in an oil bath at 30 C. If a convection coefficient of 500 W/m2 K is maintained by circulation of the oil, how long does it take for the centerline of a rod to reach a temperature of 50 C, at which point it is withdrawn from the bath
Answer:
Explanation:
Given that:
diameter = 100 mm
initial temperature = 500 ° C
Conventional coefficient = 500 W/m^2 K
length = 1 m
We obtain the following data from the tables A-1;
For the stainless steel of the rod \(\overline T = 548 \ K\)
\(\rho = 7900 \ kg/m^3\)
\(K = 19.0 \ W/mk \\ \\ C_p = 545 \ J/kg.K\)
\(\alpha = 4.40 \times 10^{-6} \ m^2/s \\ \\ B_i = \dfrac{h(\rho/4)}{K} \\ \\ =0.657\)
Here, we can't apply the lumped capacitance method, since Bi > 0.1
\(\theta_o = \dfrac{T_o-T_{\infty}}{T_i -T_\infty}} \\ \\ \theta_o = \dfrac{50-30}{500 -30}} \\ \\ \theta_o = 0.0426\\\)
\(0.0426 = c_1 \ exp (- E^2_1 F_o_)\\ \\ \\ 0.0426 = 1.1382 \ exp (-10.9287)^2 \ f_o \\ \\ = f_o = \dfrac{In(0.0374)}{0.863} \\ \\ f_o = 3.81\)
\(t_f = \dfrac{f_o r^2}{\alpha} \\ \\ t_f = \dfrac{3.81 \times (0.05)^2}{4.40 \times 10^{-6}} \\ \\ t_f= 2162.5 \\ \\ t_f = 36 mins\)
However, on a single rod, the energy extracted is:
\(\theta = pcv (T_i - T_{\infty} )(1 - \dfrac{2 \theta}{c} J_1 (\zeta) ) \\ \\ = 7900 \\times 546 \times 0.007854 \times (500 -300) (1 - \dfrac{2 \times 0.0426}{1.3643}) \\ \\ \theta = 1.54 \times 10^7 \ J\)
Hence, for centerline temperature at 50 °C;
The surface temperature is:
\(T(r_o,t) = T_{\infty} +(T_1 -T_{\infty}) \theta_o \ J_o(\zeta_1) \\ \\ = 30 + (500-30) \times 0.0426 \times 0.5386 \\ \\ \mathbf{T(r_o,t) = 41.69 ^0 \ C}\)
"Convert the OrderedPairs class, which is provided below, into a templated class. Note that it will only work with types that have the operators + and < and << overloaded. But you should be able to try your templated class out with types string, myString, double, feetInches, and fraction.
Also add an if statement to each of the two mutators to throw an exception named ""DuplicateMemberError"" if the precondition has not been met. The precondition is given as a comment in the header file. Notice that you can test your exception handling by entering the same number twice when prompted for two numbers.
Finally, to show that your class will work with different types, and also to show that you know how to use a templated class as a client, modify the given client file so that it uses your class using int as the type parameter, and then, in the same main(), repeat the code again with a few changes necessary to make it use ordered pairs of strings instead of ordered pairs of ints. One of the things you'll have to change is the generation of the random values for the ordered pairs. Here's what I used:
string empty = """";
myList2[i].setFirst(empty + char('a' + rand() % 13));
myList2[i].setSecond(empty + char('n' + rand() % 13));
------------------------------------------------------------------------------------------------------------------------------------------------------
Here is the header file, orderedpairs.h. The syntax for declaring a constant in a class may look mysterious. To use constants in a class, we have to declare it inside the class, then assign it a value outside the class, as you'll see below. (That's actually not true for int constants -- they can be assigned inside the class -- but we want our code to be flexible enough to handle different types.)
#include
/* precondition for setFirst and setSecond: the values of first and second cannot be equal,
except when they are both equal to DEFAULT_VALUE.
*/
namespace cs_pairs {
class orderedPair {
public:
static const int DEFAULT_VALUE;
orderedPair(int newFirst = DEFAULT_VALUE, int newSecond = DEFAULT_VALUE);
void setFirst(int newFirst);
void setSecond(int newSecond);
int getFirst();
int getSecond();
orderedPair operator+(const orderedPair& right);
bool operator<(const orderedPair& right);
void print();
private:
int first;
int second;
};
// You will need a template prefix here above this declaration
const int orderedPair::DEFAULT_VALUE = int();
}
-----------------------------------------------------------------------------------------------------------------------------------------------------------
Here is the implementation file, orderedpairs.cpp
#include ""orderedpair.h""
#include
using namespace std;
namespace cs_pairs {
orderedPair::orderedPair(int newFirst, int newSecond) {
setFirst(newFirst);
setSecond(newSecond);
}
void orderedPair::setFirst(int newFirst) {
// if statement to throw an exception if precondition not met goes here.
first = newFirst;
}
void orderedPair::setSecond(int newSecond) {
// if statement to throw an exception if precondition not met goes here.
second = newSecond;
}
int orderedPair::getFirst() {
return first;
}
int orderedPair::getSecond() {
return second;
}
orderedPair orderedPair::operator+(const orderedPair& right) {
return orderedPair(first + right.first, second + right.second);
}
bool orderedPair::operator<(const orderedPair& right) {
return first + second < right.first + right.second;
}
void orderedPair::print() {
cout << ""("" << first << "", "" << second << "")"";
}
}
----------------------------------------------------------------------------------------------------------------------------
Here is the client file.
#include
#include ""orderedpair.h""
using namespace std;
using namespace cs_pairs;
int main() {
int num1, num2;
orderedPair myList[10];
cout << ""default value: "";
myList[0].print();
cout << endl;
for (int i = 0; i < 10; i++) {
myList[i].setFirst(rand() % 50);
myList[i].setSecond(rand() % 50 + 50);
}
myList[2] = myList[0] + myList[1];
if (myList[0] < myList[1]) {
myList[0].print();
cout << "" is less than "";
myList[1].print();
cout << endl;
}
for (int i = 0; i < 10; i++) {
myList[i].print();
cout << endl;
}
cout << ""Enter two numbers to use in an orderedPair. Make sure they are different numbers: "";
cin >> num1 >> num2;
orderedPair x;
try {
x.setFirst(num1);
x.setSecond(num2);
} catch (orderedPair::DuplicateMemberError e) {
x.setFirst(0);
x.setSecond(0);
}
cout << ""The resulting orderedPair: "";
x.print();
cout << endl;
}"
To convert the `orderedPair` class into a templated class and add exception handling for duplicate members, you need to make the following modifications:
1. Update the header file `orderedpairs.h`:
```cpp
#pragma once
#include <iostream>
#include <string>
namespace cs_pairs {
template <typename T>
class orderedPair {
public:
static const T DEFAULT_VALUE;
orderedPair(T newFirst = DEFAULT_VALUE, T newSecond = DEFAULT_VALUE);
void setFirst(T newFirst);
void setSecond(T newSecond);
T getFirst();
T getSecond();
orderedPair<T> operator+(const orderedPair<T>& right);
bool operator<(const orderedPair<T>& right);
void print();
private:
T first;
T second;
};
// You will need a template prefix here above this declaration
template <typename T>
const T orderedPair<T>::DEFAULT_VALUE = T();
}
```
2. Update the implementation file `orderedpairs.cpp`:
```cpp
#include "orderedpair.h"
namespace cs_pairs {
template <typename T>
orderedPair<T>::orderedPair(T newFirst, T newSecond) {
setFirst(newFirst);
setSecond(newSecond);
}
template <typename T>
void orderedPair<T>::setFirst(T newFirst) {
if (newFirst == second && newFirst != DEFAULT_VALUE && second != DEFAULT_VALUE)
throw DuplicateMemberError();
first = newFirst;
}
template <typename T>
void orderedPair<T>::setSecond(T newSecond) {
if (newSecond == first && newSecond != DEFAULT_VALUE && first != DEFAULT_VALUE)
throw DuplicateMemberError();
second = newSecond;
}
template <typename T>
T orderedPair<T>::getFirst() {
return first;
}
template <typename T>
T orderedPair<T>::getSecond() {
return second;
}
template <typename T>
orderedPair<T> orderedPair<T>::operator+(const orderedPair<T>& right) {
return orderedPair(first + right.first, second + right.second);
}
template <typename T>
bool orderedPair<T>::operator<(const orderedPair<T>& right) {
return first + second < right.first + right.second;
}
template <typename T>
void orderedPair<T>::print() {
std::cout << "(" << first << ", " << second << ")";
}
}
```
3. Update the client file:
```cpp
#include <iostream>
#include <cstdlib>
#include <ctime>
#include "orderedpair.h"
using namespace std;
using namespace cs_pairs;
struct myString {
string data;
myString(string newData = "") {
data = newData;
}
bool operator<(const myString& right) {
return data < right.data;
}
friend ostream& operator<<(ostream& os, const myString& obj) {
os << obj.data;
return os;
}
};
struct feetInches {
int feet;
int inches;
feetInches(int newFeet = 0, int newInches = 0) {
feet = newFeet;
inches = newInches;
}
bool operator<(const feetInches& right) {
return feet < right.feet || (feet == right.feet && inches < right.inches);
}
friend ostream& operator<<(ostream& os, const feetInches& obj) {
os << obj.feet << " ft, " << obj.inches << " in";
return os;
}
};
struct fraction {
int numerator;
int denominator;
fraction(int newNumerator = 0, int newDenominator = 1) {
To know more about Client, click here:
https://brainly.com/question/30436876
#SPJ11