A machine part consists of three heavy disks linked by struts of negligible weights as shown in the figure. Calculate the moment of inertia of the body about an axis through the centre of disk A and the kinetic energy, if the body rotates about an axis through A perpendicular to the plane of the diagram, with angular speed ω = 6.0 rads-1..
if the values of mass (m) and radius (R) are provided, the moment of inertia of the body about an axis through the center of disk A can be calculated as (3/2) * m * R^2, and the kinetic energy of the rotating body would be 162 * m * R^2 Joules.
To calculate the moment of inertia of the body about an axis through the center of disk A, we need to consider the moment of inertia contributions from each individual disk and add them up.
Let's denote the moment of inertia of each disk as I_A, I_B, and I_C, respectively. The moment of inertia of a disk rotating about its center can be calculated using the formula:
I = (1/2) * m * r^2
Where m is the mass of the disk and r is its radius.
Since the struts have negligible weight, we can assume that each disk has the same mass.
Let's assume the mass of each disk is m and the radius of each disk is R.
The moment of inertia of disk A (I_A) is given by:
I_A = (1/2) * m * R^2
The moment of inertia of disk B (I_B) and disk C (I_C) will be the same since they have the same mass and radius:
I_B = I_C = (1/2) * m * R^2
The total moment of inertia of the body about the axis through the center of disk A (I_total) is the sum of the individual moment of inertias:
I_total = I_A + I_B + I_C
= (1/2) * m * R^2 + (1/2) * m * R^2 + (1/2) * m * R^2
= (3/2) * m * R^2
To calculate the kinetic energy of the rotating body, we can use the formula:
Kinetic Energy = (1/2) * I_total * ω^2
Substituting the given values:
Kinetic Energy = (1/2) * ((3/2) * m * R^2) * (6.0 rad/s)^2
Simplifying further, if the values of m and R are given, we can calculate the moment of inertia and kinetic energy.
Assuming that the values of mass (m) and radius (R) are given, we can calculate the moment of inertia (I_total) and kinetic energy.
For the given values of ω = 6.0 rad/s and the previously calculated I_total:
I_total = (3/2) * m * R^2
Kinetic Energy = (1/2) * I_total * ω^2
= (1/2) * [(3/2) * m * R^2] * (6.0 rad/s)^2
= (9/2) * m * R^2 * (36.0 rad^2/s^2)
= 162 * m * R^2 Joules
Therefore, if the values of mass (m) and radius (R) are provided, the moment of inertia of the body about an axis through the center of disk A can be calculated as (3/2) * m * R^2, and the kinetic energy of the rotating body would be 162 * m * R^2 Joules.
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Determine the absolute maximum bending stress in the beam, assuming that the support at B exerts a uniformly distributed reaction on the beam. The cross section is rectangular with a base of 3 in. and height of 6 in.
The maximum bending stress in the beam can be calculated using the equation: σmax = Mc/I
What is equation?A statement claiming the equivalence of two expressions is known as an equation. It is typically expressed using mathematical symbols, and can be used to solve for unknown values. An equation can also be used to describe any physical or logical relationship between two or more items. Equations often involve variables, which are symbols that represent unknown values, and can help to express the behavior of a system.
Where M is the moment at the point where the stress is to be calculated, c is the distance from the neutral axis to the point where the stress is to be calculated, and I is the second area moment of inertia of the beam.
For a rectangular beam with a base of 3 inches and a height of 6 inches, the second area moment of inertia is I = (3*6^3)/12 = 27 in^4
Assuming the support at B exerts a uniformly distributed reaction on the beam, the maximum bending moment M = (Reaction * Length^2)/8 = (500 * 6^2)/8 = 1,875 in-lb.
Therefore, the maximum bending stress in the beam is σmax = (1,875 * 6)/27 = 350 psi.
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how many taste buds do humans have 100,000, 100, 10,000 1,000
The approximate number of taste buds that humans have is 10,000 (option C).
What are taste buds?Tastebuds are any of the small organs on the tongue used for tasting.
Taste buds are cells on the tongue that allow one to perceive tastes, including sweet, salty, sour, bitter and umami.
Taste buds regenerate approximately every 10 days, which means injured taste buds usually repair on their own. The average adult human has between 2000 and 8000 tastebuds.
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How is a credit card reader related to magnetism?
There are 5.5 L of a gas present at -38.0 C. What is the temperature if the volume of the gas has changed to 1.30 L?
Answer:
We are given:
V1 = 5.5L T1 = -38 C or 235 k
V2 = 1.3L T2 = T
From the gas equation:
PV = nRT
Since the pressure (P) , number of moles (n) and the universal gas constant (R) are constants, we can write the same equation as:
V / T = k (where k is a constant)
so a bit more insight, since the values noted above are constant, when multiplied by each other, they will provide us with a constant number irrespective of the value of the variables
Changing the variables for the first case:
V1 / T1 = k (where k is the same constant) ----------------(1)
Similarly,
V2 / T2 = k (again, k has the same value)----------------(2)
From (1) and (2):
k is the common value
V1 / T1 = V2 / T2
Replacing the variables
5.5 / 235 = 1.3 / T
T = 1.3 * 235 / 5.5
T = 55.54 k
Therefore, at 55.54 K the gas will have a volume of 1.3L
You weigh 780 N.
What would you weigh if the Earth were
seven times as massive as it is and its radius
were five times its present value?
Answer in units of N.
If the Earth were seven times as massive as it is and its radius were five times its present value, your new weight will 218.4 N.
What is your weight?
Your weight is the measure of force of gravity on you. So weight depends on the value of acceleration due to gravity.
W = mg
where;
m is massg is acceleration due to gravityThe formula for acceleration due to gravity is given as;
g = ( GM ) / ( R² )
where;
G is universal gravitation constantM is the mass of the EarthR is the radius of the EarthIf the Earth were seven times as massive as it is and its radius were five times its present value, the new acceleration due to gravity will be calculated as;
g' = ( G x 7M ) / (5R)²
g' = ( 7 / 25 ) ( GM / R² )
g' = 7/25 (g)
So the new acceleration due to gravity will reduce by a factor 7/25, and same will happen to your initial weight.
new weight = 7/25 x 780 N = 218.4 N
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Along with force, which other variable is used to calculate impulse?(1 point)
A The mass of an object.
B The amount of time the object is in motion.
C The amount of time the force is applied.
D The speed of the object.
Answer: The amount of time the force is applied.
Explanation:
The other variable along with the force which is used to calculate the impulse is the amount of time the object is in motion. Hence, option B is correct.
What is impulse?A force's overall impact as it operates across time is quantified by the term "impulse." It is often written in Newton seconds and given the symbol, J end text, and value.
This is similar to a shift in momentum, as we previously saw (p). The impulse-momentum theorem refers to this correspondence. We can directly connect the way a force applies to an object over time and the way that force affects the motion of an object according to the impulse-momentum theorem.
Because forces are frequently not constant in reality, impulse is necessary and beneficial. People- and engine-related forces start out at zero and gradually increase over time, however they can vary depending on a variety of circumstances.
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The gravitational attraction between two objects increases if
Answer:
they are closer!!
Explanation:
Hope this helped!! :D
what is the most effortless walking speed for a person with 90cm long legs if the length of each step is 90cm
Answer:
75 cm/second.
Explanation:
Formula:
Walking speed = stride length / time per step
Walking speed = 90cm/time per step
= 90cm/1.2 seconds (a common estimate time per step)
= 75cm/second.
Why does a rocket with more mass need more thrust to launch it?
The reason why this is needed is because a rocket with more mass is going to speed up slower. This happens due to the rocket being up in the air, and the force of gravity is now acting in the opposite direction of thrust, so now the amount of thrust that is pushing the rocket upwards is decreased. As well as that, you now have to increase the amount of upwards thrust to counteract this. For Example, the Saturn V rocket engine.
Two boxes of masses 3M and 5M are attached by a massless rope. They are being pulled to the right with a constant force of P = 800 N, which allows them to just overcome static friction, with a μs= 0.70 between the floor and the boxes.
a. Find M.
b. Find the Tension in the rope between the two boxes.
Answer:
a) about 14.577 kg
b) 300 N
Explanation:
b) In order for the acceleration to be the same for each mass, the 800 N force must be divided between the boxes in proportion to their mass. That is, the net force on the 5M mass must be 5/8 of the total force, or 500 N. Then the tension in the rope is 800 N -500 N = 300 N, which is 3/8 of 800 N.
Tension: 300 N
__
a) The total mass is 8M, and the total normal force on the floor is ...
F = ma = (8M)(9.8 m/s^2)
The friction force is 0.7 times this, and is equal to the 800 N force pulling on the boxes.
800 N = (8M)(9.8 m/s^2)(0.7)
M = 800/(8·9.8·0.7) kg ≈ 14.577 kg
The principle of cross-cutting relationships states that certain features, such as faults, are than the rock layers they cut through. These features are breaks in Earth’s surface where rock has moved sideways, upward, or downward. formations are made of molten rock that has cooled. Those on Earth’s surface are called . Those beneath Earth’s surface are called .
PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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50 points!
Light waves of frequency 6 x 10^14 Hz have a wavelength of 3.75 x 10^-7 m in water. What is their speed in water?
\(\\ \bull\sf Frequency=f=6\times 10^{14}Hz\)
\(\\ \bull\sf Wavelength=\lambda=3.75\times 10^{-7}m\)
Now
. Velocity=v\(\\ \sf\longmapsto v=f\lambda\)
\(\\ \sf\longmapsto v=6\times 10^{14}s^{-1}\times 3.75\times 10^{-7}m\)
\(\\ \sf\longmapsto v=22.5\times 10^7ms^{-1}\)
Answer:
velocity=v = 22.5 * 10⁷ m s ^ - 1
Explanation:
\(\sf\longmapsto \: Frequency = 6 * 10 ^ {14 } H z\)
\(\sf\longmapsto \: Wavelength = 3.75 \times 10 {}^{-7} m\)
Now let's solve out!!
\(\sf\longmapsto \: velocity = frequency \lambda\)
\(\sf\longmapsto \: velocity=6 \times 10 {}^{14} s {}^{ - 1} \times \ 3.75 \times 10 {}^{ - 7} m\)
\(\sf\longmapsto \: velocity= 22.5 \times 10 ^ 7 m s ^ { - 1}\)
Note:
\(\lambda\) is the Greek letter known as lambda.
A 5 kg mass experiences a force of 100N while traveling in a circle ofradius 6.0m. What is its velocity?
Given that the mass of the object is m = 5kg.
The force on the object is F = 100 N.
The radius of the circle is r = 6 m
We have to find velocity.
Velocity can be calculated by the formula
\(\begin{gathered} F=\frac{mv^2}{r} \\ v=\sqrt{\frac{Fr}{m}} \end{gathered}\)Substituting the values, the velocity will be
\(\begin{gathered} v=\sqrt[]{\frac{100\times6}{5}} \\ =10.95\text{ m/s} \end{gathered}\)Thus, the velocity is 10.95 m/s
On an aircraft carrier, a catapult provides an accelerating force on the aircraft. The catapult provides a constant force for a distance of 150 m along the deck. Calculate the resultant force on the aircraft as it accelerates. Assume that all of the kinetic energy at take-off is from the work done on the aircraft by the catapult.
To calculate the resultant force on the aircraft as it accelerates from the catapult, we can use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.
Since all of the kinetic energy at take-off is from the work done on the aircraft by the catapult, we can equate the work done by the catapult to the kinetic energy of the aircraft at take-off, that is:
Work done by catapult = kinetic energy of aircraft at take-off
The work done by the catapult is given by the force provided by the catapult multiplied by the distance over which it acts, that is:
Work done by catapult = force × distance
The distance over which the force provided by the catapult acts is given as 150 m, so we have:
Work done by catapult = force × 150
The kinetic energy of the aircraft at take-off is given by:
(1/2) × mass × velocity^2
Since the aircraft is initially at rest, its initial velocity is zero, so we have:
kinetic energy of aircraft at take-off = 0.5 × mass × (final velocity)^2
Using the work-energy principle, we can equate the two expressions for work done and kinetic energy, that is:
force × 150 = 0.5 × mass × (final velocity)^2
Solving for force, we get:
force = 0.5 × mass × (final velocity)^2 / 150
Therefore, the resultant force on the aircraft as it accelerates is given by:
force = 0.5 × mass × (final velocity)^2 / 150
Note that we need to know the mass and final velocity of the aircraft in order to calculate the resultant force.
Three boxes, A, B, and C, are placed on a frictionless surface as shown in the diagram below. If you push on box A with a force of 8.25 N, find the contact force (in N) between each pair of boxes. Here mA = 6.25 kg, mB = 3.25 kg, and mC = 1.50 kg. contact force between A and B N contact force between B and C N
The contact force (in N) between each pair of boxes is mathematically given as
F_{ab} = 3.56 N
F_{bc} = 1.2 N
What is the contact force (in N) between each pair of boxes.?Generally, Any force that is generated as a consequence of two objects coming into touch with one another is referred to as a contact force. Contact forces are present everywhere and are the cause of the vast majority of macroscopic groupings of matter's obvious interactions with one another.
In conclusion, The equation for is Acceleration of the system is mathematically given as
a = 8.25 / (5.85 + 2.95 + 1.50)
a= 0.8 m/s^2
Therefore
F_{ab} = (Mb + Mc)*a
F_{ab} = (2.95 + 1.50) * 0.8
F_{ab} = 3.56 N
F_{bc} = Mc * a
F_{bc}= 1.5 * 0.8
F_{bc} = 1.2 N
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For an atom's electrons, how many energy sub levels are present in the principal energy level n=4?
A. 4
B. 9
C. 10
D. 16
E. 32
Answer:
the principal energy level is d because electrons are 2 times more
DON'T ADD LINKS!
Imagine that a single cell below goes through four cell divisions.
How many cells are produced? To find out, draw the parent cell
and cells present after each division. Then write the number of
cells in the space below each drawing. (Hint: the number of cells
doubles with each division.)
Two, four, eight and sixteen cells are produced from first, second, third and fourth cell division respectively.
How many cells are produced?When the body cell passes through cell division process, it divides into two daughter cells. In the second cell division, two cells divides into four cells. In the third cell division, the four cells divides into eight cells. In the fourth cell division, the eight cells divides and sixteen cells are produced.
So we can conclude that two, four, eight and sixteen cells are produced from first, second, third and fourth cell division respectively.
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A particle of mass 2unit moves along space curve defined by ~r(t) = (4t 2 − t 3 )ˆi − 5tˆj + (t 4 − 2)ˆk. Find the force acting on it at any time to work out
The force acting on the particle at t = 1 s is 24.4 N.
Mass of the particle, m = 2 units
Distance of the curve, r(t) = (4t²- t³)i - 5tj + (t⁴- 2)k
The velocity of the particle,
v = d[r(t)]/dt = (8t - 3t²)i - 5j + 4t³k
The acceleration of the particle,
a = d²[r(t)]/dt² = (8 - 6t)i + 12t²k
Let the time for which the force is acting be 1 second.
Therefore, acceleration at t = 1 is,
a₁ = 2i + 12k
Hence, the magnitude of acceleration,
|a₁| = √(2²+ 12²)
|a₁| = √148
|a₁| = 12.2 unit/s²
Therefore, the force acting on the particle at t = 1 s is,
F₁ = m x |a₁|
F₁ = 2 x 12.2
F₁ = 24.4 N
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Barney walks at a velocity of 1.7 meters/second on an inclined plane which has an angle of 18.5 with the ground what is the horizontal component of Barney’s velocity
Answer:
Explanation:
The horizontal velocity is 1.61.
Hello!
If light on the wavelength spectrum has an energy of 1.8 eV and microwaves have an energy of 1.2 x 10^-4 , does that mean ligth is 15.000 more dangerous than the radiation of a microwave ?
It is true that the light is 15.000 more dangerous than the radiation of a microwave.
What is the wavelength?The wavelength shows the extent or how far the wave travels. Now we know that the energy of the wave can be use to find out how much dangerous the wave is.
Now;
1.6 * 10^-19 J = 1eV
x J = 1.8 eV
x = 1.8 eV * 1.6 * 10^-19 J /1eV
x = 2.88 * 10^-19 J
Now if the energy of the microwaves is 1.2 x 10^-4 J, then it follows that;
2.88 * 10^-19 J/ 1.2 x 10^-4 J,
= 2.4 * 10^15
Hence, it is true that the light is 15.000 more dangerous than the radiation of a microwave.
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(I) A car slows down from 28 m????s to rest in a distance of 88 m. What was its acceleration, assumed constant?
Answer:
The value is \(a = - 4.45 m/s^2\)
Explanation:
From the question we are told that
The initial speed is \(u = 28 \ m/s\) at a distance of \(s_1 = 0 \ m\)
The final speed is \(v = 0 \ m/s\) at a distance of \(s_2 = 88 \ m\)
Generally from the kinematic equation we have that
\(v^2 = u^2 +2as\)
=> \(a = \frac{v^2 - u^2 }{ 2(s_2 - s_1 )}\)
=> \(a = \frac{0 - 28^2 }{ 2(88 - 0 )}\)
=> \(a = - 4.45 m/s^2\)
The negative sign shows that it is decelerating
For a particle with curvilinear motion, which of the following is always tangential to the motion path? Position vector Velocity vector Acceleration vector None of the above
The velocity vector is always tangential to the motion path for a particle with curvilinear motion. The velocity of a particle describes the rate of change of its position over time and its direction is always tangent to the path of the particle's motion.
What does the acceleration vector describe?The acceleration vector describes the rate of change of the velocity and its direction can be either tangential or normal to the motion path, depending on whether the particle is changing speed or direction.
Are vector and scalar different from each other?Yes, vectors and scalars are different. A scalar is a physical quantity that has only magnitude and no direction. A vector, on the other hand, is a physical quantity that has both magnitude and direction, such as velocity, force, or displacement.
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true or false: the height from which cliff divers jump affects the velocity at which they will fall. velocity is speed in a certain direction.
Answer:
False
Explanation:
Because that is not true
Jason walks 20 m East, turns around and 20 m West, Finally, he walks 10 rn North. This takes 20 s. what is Jason's velocity
Answer:
0.5 m/s north
Explanation:
Take east to be +x, west to be -x, north to be +y, and south to be -y.
His displacement in the x direction is:
x = 20 m − 20 m = 0 m
His displacement in the y direction is:
y = 10 m
His total displacement is therefore 10 m north.
His velocity is equal to displacement divided by time.
v = 10 m north / 20 s
v = 0.5 m/s north
A proton traveling due west in a region that contains only a magnetic field experiences a vertically upward force (away from the surface of the earth). What is the direction of the magnetic field?
South
Explanation:
The magnetic force F on a point charge moving with a velocity v in the presence of a magnetic field B is given by
\(\vec{\textbf{F}} = q\vec{\textbf{v}}\textbf{×}\vec{\textbf{B}}\)
and according to the right-hand rule, an upward magnetic force on a proton moving westward is only possible if the magnetic field is directed southward.
When the pivot point of a balance is not at the center of mass of the balance, how is the net torque on the balance calculated? When a force is applied directly to the pivot point of a balance, what is the torque due to that force?
Answer:
Explanation:
Net torque is calculated by multiplying the force with distance from the point of application of force to the point of pivot .
If more than 2 forces are present, then we either subtract the product of forces with their respective distances from pivot point or we add them . It depends on whether they both are present on opposite sides of pivot or on same side of pivot .
When a force is applied directly to the pivot point of balance, then the torque on due that force = 0 (zero) .
It is so because the torque is defined as the product of force and perpendicular distance from the pivot point but here the distance is 0 , therefore torque is zero.
the variable resistor r in the circuit of fig. 11.50 is adjusted until it absorbs the maximum average power. find r and the maximum average power absorbed.
The load impedance ZL must be equal to the complex conjugate of the Thevenin impedance ZTh for maximum average power transfer. This indicates that the load impedance (or resistance) must be equal to the magnitude of the Thevenin impedance for the highest average power transfer to a fully resistive load.
How is the average amount of energy absorbed determined?
As a result, the total power used by a circuit over the course of one full cycle is the sum of the power saved and the power returned.
How do you calculate average power?
The formula for average power in mathematics is: Average power = Total energy consumed Average amount of time spent P = W t.
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A force of 400-N pushes on a 25-kg box horizontally. The box accelerates at 9 m/s? Find the coefficient of kinetic friction between the box and floor.
Answer:
0.69Explanation:
Using the Newtons law of motion;
\(\sum Fx = ma_x\\Fm - Ff = ma_x\)
Fm is the moving force = 400N
Ff is the frictional force = μR
μ is the coefficient of kinetic friction
R is the reaction = mg
m is the mass
a is the acceleration
The equation becomes;
\(Fm - \mu R = ma_x\\Fm - \mu mg = ma_x\\400- \mu (25)(9.8) = 25(9)\\400 - 254.8 \mu = 225\\- 254.8 \mu = 225 - 400\\- 254.8 \mu = -175\\ \mu = \frac{-175}{- 254.8} \\\mu = 0.69\)
Hence the coefficient of kinetic friction between the box and floor is 0.69
The coefficient of kinetic friction between the box and the floor is 0.714.
Friction: This can be defined as the force that tends to oppose two surfaces in motion.
The question above can be solved using the formula
F-ma = mgμ................. Equation 1
Where F = Force applied to push the box, m = mass of the box, a = acceleration of the box, μ = coefficient of kinetic friction, g = acceleration due to gravity.
make μ the subject of the equation
μ = (F-ma)/mg................ Equation 2
From the question,
Given: F = 400 N, m = 25 kg, a = 9 m/s²,
Constant: g = 9.8 m/s²
Substitute these values into equation 2
μ = [400-(25×9)]/(25×9.8)
μ = (400-225)/245
μ = 175/245
μ = 0.714
Hence, the coefficient of kinetic friction between the box and the floor is 0.714.
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