Answers
When choosing an appropriate art material, avoid organic solvents or solvent-containing products.
What are organic solvents?Organic solvents are substances with a carbon structure that can dissolve or disperse one or more other substances.
Avoid using aerosol spray cans, airbrushes, products that can stain skin or clothing or cannot be removed from clothing, organic solvents, products containing solvents, and irritants or corrosive chemicals like acids, alkalis, and bleach.
Call a manufacturer to inquire about the suppliers of their materials, speak with their research and development department, or go in person if you're interested.
Therefore, avoid using organic solvents or products that contain solvents when selecting the right art medium.
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Related Questions
What is the value of the magnitude of the difference of vectors A and B, |A - B|?
Answers
Answer:
Let, θ be the angle between vector a and vector b.
So, the angle between vector a and vector (-b) must be (180° - θ).
Magnitude of the difference of vectors a and b
= |a - b|
= Magnitude of the resultant of the vector sum of the vectors a and (-b)
= |{√|a|^2 + |b|^2 + 2 * |a| * |b| * cos (180° - θ)}|
= |{√|a|^2 + |b|^2 - 2 * |a| * |b| * (cos θ)}|.
Explanation:
A stone of mass 6.74kg is dropped from rest at a height of 6.02m. What impulse does gravity impart to this stone from the instant is dropped until it hits the ground, assuming negligible air resistance?
Answers
The impulse the gravity imparts on the stone from the instant it was dropped until it hits the ground is 72.66 Ns
What is impulse?
This is defined as the change in momentum of an object.
Impulse = change in momentum
Impulse = final moment – Initial momentum
Impulse = force × time
How to determine the timeInitial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 6.02 mTime (t) =?h = ½gt²
6.02 = ½ × 9.8 × t²
6.02 = 4.9 × t²
Divide both side by 4.9
t² = 6.02 / 4.9
Take the square root of both side
t = √(6.02 / 4.9)
t = 1.1 s
How to determine the impulseTime (t) = 1.1 sMass (m) = 6.74 kgAcceleration due to gravity (g) = 9.8 m/s²Force (F) = mg = 6.74 × 9.8 = 66.052 NImpulse =?Impulse = Force × time
Impulse = 66.052 × 1.1
Impulse = 72.66 Ns
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When the south pole of a magnet approaches this iron nail from the left, what
happens to its domains?
A. All the arrows align to point down.
OB. All the arrows align to point right.
C. All the arrows align to point up.
OD. All the arrows align to point left.
t
Answers
In order to answer the question of where the arrows of the magnetic domains point, one must consider the properties of the magnets' poles: A) The arrows line up and point upward.
What comprises a magnet?Iron or cobalt is a common component of permanent magnets. An alloy composed of aluminum is called alnico. Involves a systematic process minerals are capable of making powerful electromagnets. They are widely utilized in industrial and consumer electronics applications.
Why was magnet named?The word "lithos magnes" from classical Greek is where the name first appeared. According to Pliny's explanation in his "Naturalis Historia," the term is derived from the myth of the Greek shepherd Magnes on Mount Ida, whose iron staff and the nails in his shoes were drawn to the magnetite stones.
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Answer:
POINTS LEFT
Explanation:
just did it
Briefly explain why the moon doesn't have an atmosphere or plate tectonic activity.
Answers
Answer:
The moon does not have an atmosphere because it does not have enough gravity to hold onto the gases that make up an atmosphere. The moon also does not have plate tectonic activity because it does not have enough internal heat to drive the movement of the plates.
Explanation:
A body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest. Calculate their common velocity of the two bodies coalesce after collision
Answers
When a body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest, their common velocity after the collision is 1.68 m/s.
When two objects of different masses collide, they can exchange momentum. An object's mass and velocity together make up its momentum. When two objects collide, their momentum is conserved, meaning that the total momentum of the two objects before the collision equals the total momentum of the two objects after the collision. This principle can be used to calculate the velocity of the two objects after a collision.A body of mass 12 kg is travelling at a velocity of 4.2 m/s and collides with a second body of mass 18 kg at rest. The total mass of the system is 12 kg + 18 kg = 30 kg. To determine the velocity of the two objects after the collision, we need to use the conservation of momentum principle. Before the impact, the system's entire momentum is:momentum before = \((mass_1 x velocity_1) + (mass_2 x velocity_2)\)where mass1 is the mass of the first object, velocity1 is the velocity of the first object, \(mass_2\) is the mass of the second object, and \(velocity_2\) is the velocity of the second object. In this case,\(mass_1 = 12 kg, velocity_1 = 4.2 m/s, mass_2 = 18 kg\), and \(velocity_2 = 0\) (because the second object is at rest). Substituting these values into the equation above, we get: momentum before = (12 kg x 4.2 m/s) + (18 kg x 0)momentum before = 50.4 kg m/sFollowing the collision, the system's overall momentum is:momentum after =\((mass_1 + mass_2) * velocity\)where mass1 + mass2 is the total mass of the system, and velocity is the velocity of the two objects after the collision. Let's call this velocity "v". Substituting the values we know into the equation above, we get: momentum after = (12 kg + 18 kg) x vmomentum after = 30 kg x vUsing the conservation of momentum principle, we know that momentum before = momentum after. Therefore, we can set these two equations equal to each other and solve for v.50.4 kg m/s = 30 kg x vv = 50.4 kg m/s ÷ 30 kgv = 1.68 m/sFollowing the impact, the two bodies' common velocity is 1.68 m/s. Hence, the answer to this problem is that when a body of mass 12kg travelling at 4.2m/s² collides with a second body of mass 18kg at rest, their common velocity after the collision is 1.68 m/s.For more questions on collision
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5. A hammer is dropped from the top of atower that is 400 m high. If we neglect airresistance so that the only force on thehammer is gravity, with what velocity doesthe hammer strike the ground?
Answers
We wil have the following:
First, we will determine the travel time:
\(400m=(0m)+(0m/s)t+\frac{1}{2}(9.8m/s^2)t^2\Rightarrow t^2=\frac{2(400m)}{(9.8m/s^2)}\)\(\Rightarrow t^2=\frac{4000}{49}s^2\Rightarrow t=\frac{20\sqrt[]{10}}{7}s\)\(\Rightarrow t\approx9.0s\)Now, we find the velocity after that time:
\(v=(0m/s)+(9.8m/s^2)(20\sqrt[]{10}/7s)\Rightarrow v=28\sqrt[]{10}m/s\)\(\Rightarrow v\approx88.5m/s\)So, it will have approximately 88.5 m/s.
Examine The
graph and determine which girl
swam the farthest during the workout
Answers
Answer:
Mary
Explanation:
because if you look at her line, her distance is exceedin the others faster and higher. She has swam 2,200 m in 30 minutes while the other girls only swam 1,800 m and 1,200 m.
hence, Mary swam the most distance after 30 min.
have a nice night! :)
15 POINTSSS PLS ANSWER
Why can't you determine the EXACT age of a layer of rock by simply observing fossils in a rock layer? What constraints you in making this determination?
Answers
To determine the exact age of a layer of rock, geologists typically use radiometric dating techniques such as measuring the decay of radioactive isotopes in rocks.
Why can't you determine the EXACT age of a layer of rock by simply observing fossils in a rock layer?While fossils found within a layer of rock can provide important clues about the age of the rock, they cannot determine the exact age of the layer with precision.
This is because the fossil record is incomplete and fossils found in a layer of rock are unlikely to represent all species that existed during a particular time period.
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As a galaxy evolves and becomes more massive, what is most likely to happen?
Answers
Answer:
Explanation:
The most likely thing that would happen is that the galaxies continue becoming more and more massive, eventually becoming part of a galaxy cluster. These are massive but cluttered parts of the universe that hold many galaxies extremely close to one another. This also leads to galaxies colliding with one another, although when this happens they usually seem to pass right through each other as if they were ghosts. This is simply due to their sheer size and distance between their bodies of mass.
Answer:
It will merge with other galaxies
Explanation:
Pearson Connexus 2023
A force is applied to a block sliding along a surface (Figure 2). The magnitude of the force is 15 N, and the horizontal component of the force is 4.5 N. At what angle (in degrees) above the horizontal is the force directed?
Answers
Answer:
Fy = 14.3 [N]
Explanation:
To be able to solve this problem we must know that the force is a vector and has magnitude and direction, therefore it can be decomposed into the force in the X & y components:
When we have the components on the horizontal and vertical axes we must use the Pythagorean theorem.
\(F = \sqrt{F_{x}^{2} +F_{y}^{2} }\)
where:
F = 15 [N]
Fx = horizontal component = 4.5 [N]
Fy = vertical component [N]
\(15=\sqrt{4.5^{2}+F_{y}^{2}}\\ 15^{2}= (\sqrt{4.5^{2}+F_{y}^{2}})^{2} \\225 = 4.5^{2}+F_{y} ^{2}\\ F_{y}^{2} =225 -4.5^{2}\\ F_{y}^{2}=204.75\\F_{y}=\sqrt{204.75}\\ F_{y}=14.3 [N]\)
Unbalanced forces have no change in motion and ______ equal zero
just need the answer that fills the blank space plsss
Answers
Answer
due to balanced forces, an object in motion cannot change its direction or speed, and also the net forces act a zero in balanced forces.
Explanation:
Unbalanced forces have a change in motion and they have a resultant force in a direction. Whereas, a balanced force does not change in direction and the resultant force is zero.
What is force?Force is an external agent acting on a body to make it changed in its state of motion or rest or to deform it. There are various kinds of forces such as magnetic force, nuclear force, gravitational force, frictional force etc.
If there are two or more forces acting on a body from the same direction, then the net force will be the sum of all the forces. If the two forces are equal in magnitude and if act from the opposite directions they will cancel each other and will not make a displacement. Such forces are called balanced forces.
The imbalance in force on a body is made by the change in direction or in magnitude of the forces. Then there will be a net force and will make the body a change in its motion.
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help pls!!
Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.
A) What is the amplitude of the wave ? Include correct units.
B) Use the graph to determine the time of one wave. Use it to find the frequency.
C) If the speed of the wave is 25 cm/s, what is the wavelength of the wave ? Show data listing, equation , substitution leading to the answer for full credit.
Answers
(a) The amplitude of the wave is determined as 8 cm.
(b) The period of the wave motion is 20 s and the frequency of the wave is 0.05 Hz
(c) The wavelength of the wave is 500 cm.
What is the amplitude of the wave ?(a) The amplitude of the wave is the maximum displacement of the wave.
from the graph, amplitude of the wave = 8 cm
(b) The period of the wave motion is calculated as;
T = 20 s
The frequency of the wave = 1/T = 1/20 s = 0.05 Hz
(c) The wavelength of the wave is calculated by applying the following wave formula.
λ = v / f
λ = 25 cm/s / 0.05 Hz
λ = 500 cm
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cart a having a mass of 150 kg initially moving to the right at a speed of 8 m/s collides with cart b with a mass of 150 kg, initially moving to the right at 6 m/s after a collision cart a continues to move to the right but with a speed of 5 m/s
a. what is the speed of cart b after collision
b. what is the total momentum of the system before and after collision
Answers
The speed of cart b is 6m/s while the total momentum of the systmen is 4200 kg m/s
Conservation of Linear MomentumGiven Data
Mass of cart one M1 = 150kgInitial Velocity U1 = 8m/sFinal VelocityV1 = 5 m/sMass of cart two M2 = 150kg
Velocity U2 = 6m/s
Applying the principle of conservation of linear momentum we have
M1U1+M2U2 = M1V1+ M2V2
a. what is the speed of cart b after collision
substituting our given data we have
150*8+ 150*6 = 150*5+150*V2
1200 + 900 = 1200+ 150V2
2100 - 1200 = 150V2
900 = 150V2
Divide both sides by 150
V2 = 900/150
V2 = 6m/s
b. what is the total momentum of the system before and after collision
Total Momentum in the system is
Total momentum = Momentum before Impact+ Momentum after Impact
Total momentum = M1U1+M2U2 + M1V1+ M2V2
Total momentum = 1200 + 900 + 1200+ 900
Total momentum = 4200 kg m/s
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the distance between an object and its real image is 40 cm, if the magnification is 3, calculate the object and image distance if the focal length of the lens is 15 cm
Answers
The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.
What is the image and object distance?The object and image distance formed by the lens is calculated by applying the following lens formula.
v + u = 40 ------- (1)
v/u = 3 ------------ (2)
v = 3u
Substitute v into equation (1);
3u + u = 40
4u = 40
u = 40/4
u = 10 cm
The image distance = 3u
= 3 x 10 cm
= 30 cm
Thus, the object distance is 10 cm and the image distance is 30 cm.
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Calculate the average speed
1) between 0 min and 3 min.
2) between 3 min and 5 min.
3) between 5 min and 10 min
4) between 0 min and 10 min
Answers
Answer:
000000000000000000000000000
A 1.1-kg object is suspended from a vertical spring whose spring constant is 120 N/m. (a) Find the amount by which the spring is stretched from its unstrained length. (b) The object is pulled straight down by an additional distance of 0.20 m and released from rest. Find the speed with which the object passes through its original position on the way up.
Answers
Answer:
e = 0.0898m
v = 2.07m/s
Explanation:
a) According to Hooke's law
F = ke
e is the extension
k is the spring constant
Since F = mg
mg = ke
e = mg/k
Substitute the given value
e = 1.1(9.8)/120
e = 10.78/120
e = 0.0898m
Hence it is stretched by 0.0898m from its unstrained length
2) Total Energy = PE+KE+Elastic potential
Total Energy = mgh +1/2mv²+1/2ke²
Substitute the given value
5.0= 1.1(9.8)(0.2)+1/2(1.1)v²+1/2(120)(0.0898)²
Solve for v
5.0 = 2.156+0.55v²+0.48338
5.0-2.156-0.48338= 0.55v²
2.36 =0.55v²
v² = 2.36/0.55
v² = 4.29
v ,= √4.29
v = 2.07m/s
Hence the required velocity is 9.28m/s
A 60 kg runner has 480 J of kinetic energy. How fast is the runner moving?
Answers
Given that the mass of the runner, m = 60 kg
The kinetic energy of the runner, K.E. = 480 J
To find the speed of the runner, v
Kinetic energy is given by the formula
\(K\mathrm{}E\mathrm{}=\text{ }\frac{1}{2}mv^2\)Substituting the known values, speed will be
\(\begin{gathered} v=\sqrt[]{\frac{2\times K.E.}{m}} \\ =\sqrt[]{\frac{2\times480}{60}} \\ =4\text{ m/s} \end{gathered}\)Thus the speed of the runner is 4 m/s.
I NEED HELP!!! PLS HELP ME MARK U BRAINLIEST!!
Answers
Answer:
The answer is X
Explanation:
Cause the highest points will most likely have the most potential energy
A 0.20kg ball is released from rest at a height of 30cm above an ideal vertical spring. The spring has a spring constant of 25Nm, and all motion is restricted to the vertical direction. The maximum compression of the spring is most nearly:
A) 0 m
B) 0.08 m
C) 0.15 m
D) 0.22 m
E) 0.31 m
Answers
The maximum distance of the spring is nearly 0.31 m. Option (E) is correct.
Given:
Mass of the ball, m = 0.20 kg
Acceleration due to gravity, a= 9.81 m/s²
Initial height, h = 30 cm = 0.30 m
Spring constant, k = 25 Nm
The potential energy is given by:
P = mg(h+x)
P = 0.20 kg × 9.81 × (0.30 + x)
The potential energy of the spring is:
P₁= 0.5 × k × x²
P₁ = 0.5 × 25 × x²
The potential energies of the spring and ball are equal. Equating the energies:
0.20 kg × 9.81 × (0.30 + x) = 0.5 × 25 × x²
12.5x² - 1.962x - 0.5886 = 0
x = 0.31 and -0.1522
The value of x cannot be negative.
Hence, the maximum compression of the spring is nearly 0.31 m. Option (E) is correct.
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0.200-kg particle has a speed of 1.50 m/s at point circled A and kinetic energy of 7.20 J at point circled B.
(a) What is its kinetic energy at circled A? _______J
(b) What is its speed at circled B? ________m/s
(c) What is the net work done on the particle by external forces as it moves from circled A to circled B? _________J
Answers
A. The kinetic energy at point A is 0.225 J
B. The speed at point B is 8.49 m/s
C. Net work done on the particle by external forces as it moves from circled A to circled B is 6.975 J.
To answer this question, we need to use the formula for kinetic energy:
KE = (1/2)mv2
Where KE is the kinetic energy, m is the mass, and v is the velocity.
(a) To find the kinetic energy at point A, we can plug in the given values:
KE = (1/2)(0.200 kg)(1.50 m/s)2
KE = 0.225 J
So the kinetic energy at point A is 0.225 J.
(b) To find the speed at point B, we can rearrange the formula for kinetic energy and plug in the given values:
v2 = (2KE)/m
v2 = (2(7.20 J))/(0.200 kg)
v2 = 72
v = sqrt(72)
v = 8.49 m/s
So the speed at point B is 8.49 m/s.
(c) To find the net work done on the particle, we can use the formula:
W = KEfinal - KEinitial
W = (7.20 J) - (0.225 J)
W = 6.975 J
So the net work done on the particle is 6.975 J.
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A 7.30 kg sign hangs from two wires. Thefirst wire is attached to the left end, andpulls 28.0 N directly left. What is theX-component of the force of the secondwire?F2F1wEnterX-component (N)I
Answers
As, the mass is in rest, the x-component of the force must be zero.
\(\begin{gathered} F_2(x)-F_1=0 \\ F_2(x)=F_1 \\ F_2(x)=28.0\text{ N} \end{gathered}\)Therefore, x component of the second force is 28.0 N.
Balancing y component of the force,
\(\begin{gathered} F_y=W \\ =mg \\ =7.3\times9.8 \\ =71.54\text{ N} \end{gathered}\)Therefore, y component of the force is 71.54 N.
is a computer translucent?
Answers
Answer:
no it's opaque
hope this helps
have a good day :)
Explanation:
Why are rocks made of limestone usually an indication that an area was previously covered by ocean water
Answers
Answer:
what's the question? I don't understand
Answer:
Limestone can from form shell fragments of sea creatures
Explanation:
What must the center-to-center distance between two point charges of 60.0 nC be to have a force of 4 N between them?
Answers
Given:
• Each Charge = 60.0 nC
,• Force between the charges = 4 N
Let's find the center-to-center distance between thw two point charges.
To find the center-to-center distance, apply the formula:
\(F=\frac{kQ_1Q_2_{}}{r^2}\)Where:
Q1 = Q2 = 60.0 nC
k is the Coulomb's constant = 9 x 10⁹ N⋅m^2⋅C^-2
r is the distance
F is the force = 4 N
Rewrite the formula for r, input the values and solve for r.
We have:
\(\begin{gathered} r=\sqrt[]{\frac{kQ_1Q_2}{F}} \\ \\ r=\sqrt{\frac{9\times10^9\times(60\times10^{-9})\times(60\times10^{-9})}{4}} \\ \\ r=\sqrt[]{8.1\times10^{-6}} \\ \\ r=2.8\times10^{-3}\text{ m }\approx2.8mm \end{gathered}\)Therefore, the center-to-center distance is 2.8 mm
ANSWER:
2.8 mm
Rest energy is the energy a body has due to its position at rest.
True
False
Answers
The energy of a body's mass at rest is calculated as the product of the mass at rest and the square of the speed of light, thus the Rest energy is the energy a body has due to its position at rest, so this statement is true.
What is energy?Energy is the ability to perform work in physics. It could exist in several different forms, such as potential, kinetic, thermal, electrical, chemical, radioactive, etc. Additionally, there is heat and work, which is energy being transferred from one body to another. Energy is always assigned based on its nature once it has been transmitted. Thus, heat transmitted may manifest as thermal energy while work performed may result in mechanical energy.
The energy of a body's mass, at rest, is calculated as the product of the mass at rest and the square of the speed of light.
Therefore, rest energy is the energy a body has due to its position at rest.
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3) Little bunny FooFoo was hopping through the forest with a velocity of 1.5 m/s. The good
fairy came down for the 3rd time so FooFoo accelerated at 8.0 m/s2 for 0.5 seconds. What
was FooFoo's new velocity?
A) 5.5 m/s
B) 2.7 m/s
C) 2.5 m/s
D) 17.5 m/s
4) A car initially moving at 32 m/s slows to a stop in 15 seconds. What is the car's average
Answers
(3) FooFoo's new velocity is determined as 5.5 m/s.
option A is the correct answer.
(4) The average acceleration of the car is 2.13 m/s².
What is the final velocity of FooFoo?
The final velocity of the FooFoo is calculated by applying the following kinematic equation as shown below.
v = u + at
where;
v is the final velocity of the FooFoou is the initial velocity of the FooFooa is the acceleration of the FooFoot is the time of motion of the FooFooThe given parameters include the following;
the initial velocity of FooFoo, u = 1.5 m/sthe acceleration of FooFoo, a = 8 m/s²the time of motion of FooFoo, t = 0.5 sThe final velocity of FooFoo is calculated as follows;
v = 1.5 + ( 8 ) ( 0.5 )
v = 5.5 m/s
The average acceleration of the car is calculated as follows;
v = u - at
where;
v is the final velocity of the car when it stops = 0u is the initial velocity of the car, u = 32 m/st is the time of motion of the car, t = 15 s0 = 32 - 15a
15a = 32
a = 32 / 15
a = 2.13 m/s²
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The missing question is below:
4) A car initially moving at 32 m/s slows to a stop in 15 seconds. What is the car's average acceleration of the car?
Describe 2 ways in which a giant boulder by the ocean may change over time.
Answers
Answer:
I'm not sure if they're right but...
1. It would erode because of the water
2. It would probably become a home for the ocean creatures
The two (2) ways in which a giant boulder by the ocean may change over time are:
1. The ocean water would change the boulder's appearance and texture.
2. The giant boulder would be transformed into sediments due to erosion and weathering through dissolution.
A boulder can be defined as a large (giant) rounded mass of rock fragment that is formed through its detachment from a parent consolidated rock, especially due to erosion and weathering.
Basically, the size of a boulder is greater than 256 millimeters (25.6 centimeters or 10.1 inches) in diameter.
The reason why giant (large) boulders are present in steep mountain streams or oceans is mainly because they are usually too heavy for them to be moved by the body of water.
This ultimately implies that, water cannot move a giant (large) boulder that is present in an ocean because of its size and weight.
However, a giant (large) boulder that is present in an ocean would be affected in these two (2) ways:
Ocean water would change the boulder's appearance and texture. The giant boulder would be transformed into sediments due to the actions of erosion and weathering through dissolution.
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does a radio wave have a high or low frequency
Answers
Answer:
Low
Explanation:
Radio waves have photons with the lowest energies.
A girl runs up the down escalator in the mall. If the escalator is moving with a velocity of 27 m/min and the girl is running with a velocity of 28 m/min, how far up the escalator can she go in 2 minutes?
Answers
The girl can go up the escalator by 2 meters in 2 minutes if a girl runs up the down escalator in the mall and escalator is moving with a velocity of 27 m/min and the girl is running with a velocity of 28 m/min,
When the girl runs up the down escalator, her effective velocity is the difference between her velocity and the velocity of the escalator. In this case, the escalator is moving down with a velocity of 27 m/min, while the girl is running up with a velocity of 28 m/min. So, her effective velocity is:
Effective velocity = Girl's velocity - Escalator's velocity
= 28 - 27
= 1 m/min
Therefore, the girl is moving up the escalator at a speed of 1 m/min.
To calculate how far up the escalator she can go in 2 minutes, we need to use the formula:
Distance = Speed x Time
In this case, the speed is the effective velocity of the girl, which is 1 m/min, and the time is 2 minutes. So, the distance she can go up the escalator is:
Distance = Speed x Time
= 1 x 2
= 2 meters
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Find the size of the image formed in the situation shown in figure.
A) 0.5 cm
B) 0.6 cm
C) 1.2 cm
D) 1 cm
Answers
Given
distance of the object u = -40 cm.
radius of curvature of the refracting surface R = -20 cm.
The height of the object h = 1 cm.
To Find
The size of the image
Solution
We will now write the following data using the sign convention:
The object's distance is u = -40 cm.
The refracting surface has a radius of curvature of R = -20 cm.
The object's height is h = 1 cm.
We know that the lens maker formula is: n2vn1u=n2n1R.
v denotes the image formation distance.
The refractive index of the second medium is n2=1.33, and the refractive index of the first medium is n1=1.
In the preceding equation, we will now substitute the known values.
1.33v−1−40cm=1.33−1−20cmv=32.05cm
We know that the magnification ratio can be expressed as vu=Hh.
H denotes the height of the created image.
We'll now swap the given and obtained values.
⇒32.05cm divide by 40cm=H divide by 1cm
⇒H=0.6cm
As a result, the best choice is (B).
Further information: The rules of reflection apply to reflection from a concave mirror. The normal to the point of incidence is drawn along the radius of the mirror, that is, by connecting the point of incidence to the centre of curvature.
The development of an image in a concave mirror is mostly determined by the distance between the object and the mirror. The concave mirror produces both real and virtual images. A virtual and magnified picture is generated when the object is placed very close to the mirror.
The complete question is -
Find the size of the image formed in the situation shown in figure.
photo
A) 0.5 cm
B) 0.6 cm
C) 1.2 cm
D) 1 cm
Learn more about scales at
brainly.com/question/25324744
