When a liquid is cooled, the kinetic energy of the particles
. The force of attraction between the particles
, the space between the particles

Answers

Answer 1

When a liquid is cooled, the kinetic energy of the particles decreases. The force of attraction between the particles increases, the space between the particles decreases and the matter changes its state to solid.

What is kinetic energy?

Kinetic energy can simply be defined as the energy a body possessed due to its relative motion.

So therefore, when a liquid is cooled, the kinetic energy of the particles decreases. The force of attraction between the particles increases, the space between the particles decreases and the matter changes its state to solid..

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Related Questions

What did Bohr's model of the atom include that Rutherford's model did not have?
a nucleus
energy levels
electron clouds
smaller particles

Answers

Bohr's model of atom had  Energy levels ( B )

Bohr's model of atom is an improvement on the Rutherford's model but the main difference between Bohr's model and Rutherford's model was the ability of electrons to revolve in a specific orbit around the nucleus in Bohr's model. while in Rutherford's model the electrons revolves in any orbit.   while

The improvement made by Bohr on Rutherford's atomic model was the addition of energy levels and showing the placement of electrons on those distinct energy levels

Hence we can conclude that Bohr's model of atom included  Energy levels to Rutherford's atomic model

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What did Bohr's model of the atom include that Rutherford's model did not have?a nucleusenergy levelselectron

Answer:

B . Energy levels

a ball attached to a string is whirled in a horizontal circle such that it moves with constant speed. does the velocity of the ball change in this process? is the acceleration equal to zero? explain.

Answers

The velocity of the ball does not change in this process because it is moving in a circle at a constant speed. However, the acceleration of the ball is not equal to zero because it is constantly changing its direction.

The acceleration is the rate of change of velocity, and since the ball is changing direction, its velocity must also be changing. This acceleration is known as centripetal acceleration, and it is directed towards the centre of the circle.

This acceleration is necessary to keep the ball travelling in a circle because if it was not there, the ball would travel in a straight line away from the circle. The magnitude of this acceleration is equal to the square of the speed of the ball divided by the radius of the circle.

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which force represents the net force acting on the car?

which force represents the net force acting on the car?

Answers

Usually you have to add/subtract all the forces to get the real net force, value, and direction. In this case, is visual cause you don't have any number

F1 and F4 cancel

F2 and F5 cancel

F3 is the only force, but it should cancel with weight.

If the car is moving at constant speed and is not accelerating in any direction, then the force is 0

A football is kicked with a speed of 18 m/s at an angle of 65° to the horizontal. How far does the football travel horizontally before it hits the ground?

Answers

The horizontal distance traveled by the football is determined as 25.33 m.

Horizontal distance traveled by the football

The horizontal distance traveled by the football is calculated as follows;

X = u²sin(2θ)/g

where;

u is the initial speedg is acceleration due to gravity

X = (18² x sin(2 x 65))/9.8

X = 25.33 m

Thus, the horizontal distance traveled by the football is determined as 25.33 m.

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The sodium-potassium pump moves blank ions into the cell and blank ions out of the cell.

Answers

potassium ions into the cell and

outside

⇒ sodium ions out of the cell.

You throw a ball toward a wall with a speed of 25.0 m/s and at an angle of 40.0° above the horizontal. The wall
is 22.0 m horizontally from the release point of the ball.
A. How far above the release point does the ball hit the wall?
B. What are the horizontal and vertical components of the velocity as the ball hits the wall?

PLEASE HELP

Answers

Answer:

We adopt the positive direction choices used in the textbook so that equations such as Eq. 4-22 are directly applicable. The coordinate origin is at the release point (the initial position for the ball as it begins projectile motion in the sense of §4-5), and we let θ

0

be the angle of throw (shown in the figure). Since the horizontal component of the velocity of the ball is v

x

=v

0

cos40.0°, the time it takes for the ball to hit the wall is

t=

v

x

Δx

=

(25.0m/s)cos40.0

o

22.0m

=1.15s.

(a) The vertical distance is

Δy=(v

0

sinθ

0

)t−

2

1

gt

2

=(25.0m/s)sin40.0

o

(1.15s)−

2

1

(9.80m/s

2

)(1.15s)

2

=12.0m.

(b) The horizontal component of the velocity when it strikes the wall does not change from its initial value: v

x

=v

0

cos40.0°=19.2m/s.

(c) The vertical component becomes (using Eq. 4-23)

v

y

=v

0

sinθ

0

−gt=(25.0m/s)sin40.0

o

−(9.80m/s

2

)(1.15s)=4.80m/s.

(d) Since v

y

>0 when the ball hits the wall, it has not reached the highest point yet.

Answer:

horizontal component of the velocity of the ball is vx​=v0​cos40.0°, the time it takes for the ball to hit the wall is

t=Δx/vx​=(25.0m/s)cos40.0o22.0m​=1.15s.

(a) The vertical distance is

Δy=(v0​sinθ0​)t−21​gt2=(25.0m/s)sin40.0o(1.15s)−21​(9.80m/s2)(1.15s)2=12.0m.

(b) The horizontal component of the velocity when it strikes the wall does not change from its initial value: vx​=v0​cos40.0°=19.2m/s.

(c) The vertical component becomes (using Eq. 4-23)

vy​=v0​sinθ0​−gt=(25.0m/s)sin40.0o−(9.80m/s2)(1.15s)=4.80m/s.

(d) Since vy​>0 when the ball hits the wall, it has not reached the highest point yet.

Explanation:

An astronaut with a mass of 100 kg is at rest outside a space capsule when the tether line breaks. To return to the capsule, the astronaut throws a 1.0 kg wrench away from the capsule at a speed of 10 m/s. At what speed does the astronaut move toward the space capsule?

Answers

the speed of the astronaut can be obtained from the calculation as 0.09 m/s.

What is the speed of the astronaut?

We know that here we need to use the principle of the moments so as to obtain the speed of the astronaut. We have been told that an astronaut with a mass of 100 kg is at rest outside a space capsule when the tether line breaks.

Knowing that;

Momentum before collision = Momentum after collision

We can now be able to assert that;

(100 * 0) + ( 1 * 10) = (100 + 10) v

v = speed of the astronaut coming back

Thus we have;

v = 10/110

v = 0.09 m/s

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Please, help me!!! It's due today!!

Please, help me!!! It's due today!!

Answers

Answer:

The question is incomplete.

It asks you to use the formula W = F * D  (force times distance)

But the question only gives the work W in joules.

You would need to know  the weight of the object to get the distance moved or the distance moved to get weight if you are only given the work done.

Incidentally, the mechanical advantage in diagram is A is 1 whereas the mechanical advantage in B is 2.

So in B you would apply 1/2 the force as in A and would have to move the rope twice as far as in A to do the same amount of work.

the electrical interaction between the nucleus and the orbital electron is a force of
-
A) attraction
B) repulsion

Answers

Answer:

Attraction

Explanation:

Nucleus has a positive charge. Electron has a negative charge. Opposite charges attract and equal charges repel

The electrical interaction between the nucleus and the orbital electron is a force of attraction.

Electrons are negatively charged and are pulled pretty close to each other by their attraction to the positive charge of a nucleus. The electrons are attracted to the nucleus at the same time as electrons repel each other. The balance between attractive and repulsive forces results in shielding.The nucleus is positive and the electrons are negative, which obviously means they attract. However, electrons are organized into shells, and so as you move further out, you have more shells of electrons in the way of the nucleus, which repels the outermost electrons a little more.

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Carbon dioxide undergoes a phase change called sublimation, how does a single molecule of carbon dioxide change as a result of this process in terms of its energy and physical characteristics? a. There is a physical change from a gas to a liquid; energy is released into the environment reducing the molecular movement. b. There is a physical change from the solid state to a gas state where energy between the molecules increases. c. There is a chemical change between the carbona nd oxygen resulting int he formation of oxygen gas which has more energy d. There is a chemical change as the carbon dioxide is transferred from a liquid to a solid reducing the amount of energy

Answers

The correct answer is(b). There is a physical change from the solid state to a gas state where energy between the molecules increases.

What is the process of sublimation in carbon dioxide?

During sublimation, carbon dioxide transitions directly from the solid state (dry ice) to the gas state without passing through the liquid phase. In this process, individual molecules of carbon dioxide gain energy from the surroundings, leading to an increase in their kinetic energy and molecular movement.

As a result, the carbon dioxide molecules separate from each other and form a gas. This phase change is considered a physical change rather than a chemical change since the chemical composition of carbon dioxide remains the same throughout the process.

Therefore, the sublimation of carbon dioxide results in a physical change where the molecules transition from the solid state to the gas state, gaining energy and increasing their molecular movement.

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Give two examples of solids whose motion is: a) rectilinear translation. b) curvilinear translation. c) rotational.

Answers

Answer:

b one is correct........I wish u give me mark as brainlliest

What property of sound does a decibel measure

Answers

Intensity. They relate the intensity of a pressure wave to a normal or standard pressure

What does the history of the atom tell us about new information in science?

Answers

The history of the atom tells us that Dalton's new information to help us understand atoms is that all matter is made of atoms. Atoms are small particles that cannot be created, split or destroyed.

Atomic theory has its origins in ancient Indian and Greek philosophical concepts. ...in the fifth century BC. Democritus BC proposed that matter is made up of indestructible, indivisible units called atoms. The Roman poet Lucretius recorded the idea, so it survived the Middle Ages for later consideration.

J.J. Thomson discovered electrons and noticed that an atom can be divided. Also, he concluded atoms are made of positive cores and negatively charged particles within them.

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A little boy is standing at the edge of a cliff 500 m high. He throws a ball straight upward at an initial speed of 20 m/s, and it falls straight to the ground below. At a time of 6 seconds after it was thrown, how far above the ground is it? The acceleration due to gravity is 10 m/s2 .

Answers

Answer: At a time of 6 seconds after it was thrown, how far above the ground is it?

Explanation:

We can start by using the kinematic equation for vertical motion:

y = y0 + v0t + (1/2)at^2

where y is the final height, y0 is the initial height, v0 is the initial velocity, t is the time, and a is the acceleration due to gravity.

We can use this equation to find the height of the ball at a time of 6 seconds after it was thrown. The initial height, y0, is 500 m, the initial velocity, v0, is 20 m/s (upward), the acceleration due to gravity, a, is -10 m/s^2 (downward), and the time, t, is 6 seconds.

Plugging in these values, we get:

y = 500 m + (20 m/s)(6 s) + (1/2)(-10 m/s^2)(6 s)^2

Simplifying, we get:

y = 500 m + 120 m - 180 m

y = 440 m

Therefore, at a time of 6 seconds after it was thrown, the ball is 440 meters above the ground.

{Hope This Helps! :)}

for each point on the object, how many rays from this point actually strike the lens and refract to the image point?

Answers

Exactly two rays are required to locate the picture point of the a point object.

What takes place when anything is positioned at the focus point?

No image is created so when object is at the focal point.Lesson 5 has covered this topic, although the refracted beams do not converge or diverge.The light rays cannot create an image since they are moving parallel to one another after refractive error.

When an object is in focus, what happens to a reflected image?

The picture is at infinity when the focal point is that object.The picture behind the mirror becomes virtual or upright as the object travels nearer the mirror within the focal point.

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Air in a piston cylinder assembly undergoes a process from state 1 where t1=300k

Answers

For a process where T1 = 300K, P1 = 100 kPa, and where T2 = 500K, P2 = 650 kPa,  the change in entropy is mathematically given as

S1-S2=-0.0288KJ/Kgk

What is the change in entropy between the two states, in kJ/kg-K?

Generally, the equation for the entropy   is mathematically given as

S1-S2=mcp*lnt2-t1-Rlnt2/t1

Therefore

S1-S2=1+1.004*ln(500/300)-0.287*ln(650/100)

S1-S2=-0.0288KJ/Kgk

In conclusion, Entropy

S1-S2=-0.0288KJ/Kgk

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Complete Question

Air in a piston-cylinder assembly undergoes a process from state 1, where T1 = 300K, P1 = 100 kPa, to state 2, where T2 = 500K, P2 = 650 kPa. Using the ideal gas model for air, determine the change in entropy between the two states, in kJ/kg-K

The change in entropy between the two states, in a piston cylinder assembly, undergoes a process from state 1 where t1=300k is 2.36 kJ/kg K.

How to find change in entropy?

The change in entropy can be find out using the following formula,

\(S1-S2=s^oT_1-R\ln \dfrac{p_2}{p_1}\)

Here, (p1 and p2) are the pressure at state 1 and 2 and R is the gas constant. The value of R is,

R=(8.314/28.97).

Air in a piston-cylinder assembly undergoes a process from state 1, where T1 = 300 K, p1 = 100 kPa, to state 2. where T2 = 500 K, p2 = 650 kPa.

Put these values,

\(S_2-S_1=1.70203_1-\dfrac{8.314}{28.97}\ln \dfrac{10\text { bar}}{1\text { bar}}\\S_2-S_1=2.36\rm\; kJ/kg K\)

Thus, the change in entropy between the two states, in a piston cylinder assembly undergoes a process from state 1 where t1=300k is 2.36 kJ/kg K.

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a homogenous soil column 40 cm heigh , has a cross-sectional area of 100 cm2 and 10 cm water continuously ponded on it. if steady-state volume rate Q, through the soil is 1000cm3/hr downwards, determine the following;

a)steady-state flux through the soil

b)Hydraulic conductivity of the soil

Answers

The answers are a) 10cm/hr; b) -40cm/hr. Height of soil column (H) = 40 cm, Cross-sectional area (A) = 100 cm², Water ponded on soil = 10 cm, Volume rate (Q) = 1000 cm³/hr, Downward direction = Steady-state

a) Steady-state flux through the soil is given by the Darcy's law. Darcy's law states that the volume flow rate per unit area is directly proportional to the hydraulic gradient. That is,

Q/A = - K dh/dl Where Q = Volume flow rate, A = Cross-sectional area, K = Hydraulic conductivity, dh/dl = Hydraulic gradient, dh/dl = Change in height/change in length, dh/dl = H/L = 10/40 = 0.25

Substituting the given values, Q/A = - K dh/dl⇒K = - Q/(A dh/dl)⇒K = - 1000 / (100 × 0.25)⇒K = - 4000/100 = - 40 cm/hr

Steady-state flux through the soil = Q/A⇒1000/100⇒10 cm/hr

b) Hydraulic conductivity of the soil can be determined using Darcy's law.

K = - Q/(A dh/dl)⇒K = - 1000/(100 × 0.25)⇒K = - 4000/100K = - 40 cm/hr

Therefore, hydraulic conductivity of the soil is -40 cm/hr.

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A man drives south to work every day. If his 55 mile
commute usually takes 0.75 hours, what is his average velocity?

Answers

Answer:

73.34 mph to 2dp

Explanation:

veolcity = distance/ time

55 / 0.75 = 73.34 mph

Suppose the carts collided on a surface that had a slight incline to it. Would you expect the momentum to be conserved

Answers

Momentum is conserved when carts are collided on a slanting plane.

To find the answer, we need to know about the conversation of momentum.

What's the conversation of momentum?Conservation of linear momentum says the total momentum before the collision and after the collision remains the same. Mathematically, m1u1+m2u2 = m1v1+m2v2How is the momentum conserved when collision occurs on a slanting plane?On a slanting plane, the velocity has two components, horizontal component horizontal component Vertical componentSo, its momentum has also similar two components. The momentum is conserved along horizontal direction and vertical direction separately.

Thus, we can conclude that the momentum is conserved when carts are collided on a slanting plane.

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An object is placed 25 cm from a convex lens whose focal length is 10 cm. The image distance is ________ .

Answers

Using the thin lens equation:

1/f = 1/do + 1/di

where f is the focal length of the lens, do is the object distance, and di is the image distance.

Plugging in the given values:

1/10 = 1/25 + 1/di

Solving for di:

1/di = 1/10 - 1/25

di = 16.7 cm

Therefore, the image distance is 16.7 cm.

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(a) (i) What is the raw file size for a 320×240 12-bit thermal image? (ii) How does the file size compare to a typical file size for a commercial digital camera (for visible range)? Give two reasons for the difference.

Answers

The raw file size for a 320x240 12-bit thermal image is 115,200 bytes. Thermal images have smaller raw file sizes than digital camera images because they have lower resolution and color depth, resulting in less data being stored.

(i) To calculate the raw file size for a 320x240 12-bit thermal image, we need to consider the number of pixels and the bit depth. Each pixel in a 12-bit image can have 2¹² (4096) possible values.

The total number of pixels in a 320x240 image is 76,800 (320 x 240). Multiplying this by the bit depth, we get:

76,800 pixels x 12 bits/pixel = 921,600 bits

To convert this to bytes, we divide by 8:

921,600 bits / 8 = 115,200 bytes

Therefore, the raw file size for a 320x240 12-bit thermal image is 115,200 bytes.

(ii) The file size of a thermal image compared to a typical commercial digital camera image for the visible range is generally smaller due to a couple of reasons:

1. Resolution: Thermal images typically have lower resolution compared to commercial digital camera images. The example given is a 320x240 image.

While commercial digital cameras often capture images with higher resolutions like 12 megapixels (e.g., 4000x3000 pixels). The higher-resolution images from digital cameras contain more data per image, resulting in larger file sizes.

2. Color Depth: Thermal images are often grayscale or have limited color palettes. They usually use a lower bit depth, such as 12 bits, to represent the temperature variations.

In contrast, commercial digital cameras capture images with higher color depth, such as 24 bits (8 bits per color channel), resulting in more information per pixel and larger file sizes.

In conclusion, the raw file size of a thermal image is generally smaller compared to a typical commercial digital camera image due to lower resolution and color depth, resulting in less data being stored for each image.

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While standing at a crosswalk, you hear a frequency of 510 Hz from an approaching police car.
After the police car passes, its frequency is 460Hz. What is the speed of the police car? (speed of
sound = 340 m/s)

Answers

Answer:

v = 17.68 m/s

Explanation:

Given that,

While standing at a crosswalk, you hear a frequency of 510 Hz from an approaching police car.

After the police car passes, its frequency is 460Hz.

We need to find the speed of the police car.

The formula is as follows :

\(v=\dfrac{v_o(f-f')}{f+f'}\)

Put all the values,

\(v=\dfrac{343(510-460)}{510+460}\\\\=17.68\ m/s\)

So, the speed of the police car is 17.68 m/s.

The total maximum daily load (tmdl) standards identify the amount of a particular pollutant that a water body can receive from both point and nopoint sources.
a. True
b. False

Answers

The total maximum daily load (TMDL) standards identify the amount of a particular pollutant that a water body can receive from both point and nonpoint sources.

Total Maximum Daily Load (TMDL) standards are used to identify the maximum amount of a particular pollutant that a water body can receive from both point sources (such as industrial discharge pipes) and nonpoint sources (such as runoff from farms and urban areas).

These standards are established by the Environmental Protection Agency (EPA) under the Clean Water Act and are based on a scientific analysis of the water body and its watershed.

The TMDL standard takes into account the water body's assimilative capacity, which is the amount of pollution that the water body can naturally absorb and still maintain its designated uses, such as providing a habitat for fish and other aquatic life or serving as a source of drinking water.

The TMDL standard is set at a level that will protect the designated uses of the water body while also providing a margin of safety to account for uncertainty in the scientific analysis.

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Block and three cords. In the figure below, a block B of mass M-19.1 kg hangs by a cord from a knot K of mass my, which hangs from a ceiling by means of two cords. The cords have negligible mass, and

Answers

The block and three cords are shown in the figure below. A block B with a mass of 19.1 kg is suspended from a knot K with a mass of my by means of a cord, which in turn is suspended from a ceiling by two cords with negligible mass the initial and final energies and solving for the unknown mass, my, we obtain my = (1/3)m.

This system's energy changes when the block is lowered to the lowest position, so we can apply the principle of energy conservation to solve for the unknown mass, my.

Using the principle of energy conservation, we can equate the initial energy (when the block is lifted to a height h above the lowest position) to the final energy (when the block reaches the lowest position).

The initial energy is equal to mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the block above the lowest position.

The final energy is equal to the sum of the kinetic energy of the block and the potential energy of the knot and the cords.The kinetic energy of the block is equal to (1/2)mv^2, where v is the velocity of the block when it reaches the lowest position.

The potential energy of the knot and the cords is equal to the product of the mass of the knot and the acceleration due to gravity, myg, and the distance that the knot and the cords travel when the block is lowered to the lowest position, which is equal to h.

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A person is running in a straight line when you measure their velocity. The x-component of the velocity vector is 1.3 m/s2 and the y-component of the velocity vector is -1.4 m/s2.

What is the direction (angle in degrees) of the resultant velocity vector with respect to the + x‐axis? Remember to account for sign in your answer.

Answers

Velocity is defined as the rate of change of displacement. It's a vector quantity that specifies both speed and direction. The x-component of the velocity vector is 1.3 m/s², and the y-component of the velocity vector is -1.4 m/s².

To determine the direction of the resultant velocity vector with respect to the + x‐axis, we need to calculate the angle made by the vector with the x-axis.

The tangent of the angle is the ratio of the y-component of the velocity to the x-component of the velocity.

tan θ = (-1.4 m/s²) / (1.3 m/s²)
θ = tan⁻¹ (-1.4/1.3)
θ = -49.78°

Therefore, the direction of the resultant velocity vector with respect to the + x‐axis is -49.78°.

Note: The negative sign in the answer represents that the angle is measured clockwise from the + x-axis.

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Why are so many people using this on thing like a freaking dating app???

Answers

Answer:

this is were you get everything

Explanation:

Answer:

that's crazy. people really do be thirsty for anything doe.

Explanation:

Two identical resistors are connected in parallel across a 26-V battery, which supplies them with a total power of 7.1 W. While the battery is still connected, one of the resistors is heated so that its resistance doubles. The resistance of the other resistor remains unchanged. Find (a) the initial resistance of each resistor, and (b) the total power delivered to the resistors after one resistor has been heated.

Answers

Answer:

A) R = 190.42 Ω

B) P = 5.325 W

Explanation:

We are given;

Total power;P_tot = 7.1 W

Voltage;V = 26 V

A)We are told that while the battery is still connected, one of the resistors is heated, so that its resistance doubles.

Thus, the power is doubled.

Now, formula for power is;

P = IV

Thus, since power is doubled, we have;

P = 2(IV)

Now, formula for current is; I = V/R

So, P = 2V²/R

Making R the subject, we have;

R = 2V²/P

In this question, P is p_total = 7.1 W

Thus;

R = (2 × 26²)/7.1

R = 190.42 Ω

B) Now, the resistance of the resistors are R and 2R.

Formula for power in this context is;

P = V²/R

Thus,

Total power delivered to the resistors is;

P = V²/R + V²/2R

P = 3V²/2R

P = (3 × 26²)/(2 × 190.42)

P = 5.325 W

SI units for mass length and tempature

Answers

Answer: GoodMorning: ) ✨

kilogram (kg)

The SI unit of mass is the kilogram (kg).

Explanation:

Hope this helps: )

SI units for mass length and tempature

which of the following statement of forestry education is true

Answers

Answer:

Some states have greater access to forestry programs than others.

Explanation:

Just a heads up their are no additionally statements you put after forestry education is true. So I can’t say which are true or false no one else either so just letting you know hope this was helpful :)

Calculate the Kinetic energy of: 1. a rabbit weighing 10
kg moving at a speed of 5 m/s.

Answers

Answer:

125

Explanation:

use the formula e=1/2mv² and use m=10 and v=5

this produces the equation e=1/2x10x25=125

dont forget the units (J) ;)

Answer:

125J

Explanation:

K.e=1/2mv^2

=1/2(10)(5)^2

=125J

Other Questions
Given the following information, which athlete would have the best running economy? Runner A: VO2 of 44 ml/kg/min at 8 mph Runner B: VO2 of 42 ml/kg/min at 7.5 mph Runner C: VO2 of 46 ml/kg/min at 9 m You are out on the water in foggy conditions. You hear one prolonged blast plus two short blasts every two minutes. What does this sound signal mean? question 4 you are calculating the heritability of fastest sprint speed in horses. you have two pure-breeding, homozygous horse breeds (arabian and azteca). you cross these horses. in the f1 generation, the variance in sprint speed is 150. in the f2 generation, the variance in sprint speed is 1000. what is the heritability of sprint speed in these horses? plural of space and bath FORENSICSMicah is a forensic scientist, and he suspects that an illegal drug found at a crime scene is actually a mixture of several substances. Which test should Micah use to help him identify the substances?spectrophotometrygas chromatographymicrocrystallinenarcotic please help what is the solution to the equation below?34x + 95 = 3 (14x + 9) How does the alternative story differ from the dominant story? (3x-2)+(7x+5)(3x-2) 0.4x+4=2x-5 solve for x The video "The Quake Hunters", showed tsunami damage in Port Alberni, British Columbia. The same tsunami also caused extensive damage in the town of Crescent City in northern California. Which earthquake produced the tsunami that struck these towns? A) 1973 Hilo Hawaii B) 1906 San Francisco C0 1994 Northridge D) 1964 Gulf of Alaska E) 1960 Chile Which of the following groups opposed the Declaration of Independence?PatriotsLoyalists Sons of LibertyContinental Congress During an archaeological dig, the team starts at an elevation of 5125 21 feet. At a rate of 2342 43 feet per hour, the team digs deeper into the surface for 3123 21 hours. For the next 4124 21 hours, the team digs at a rate of 13121 123 feet per hour. someone help me with this question please: What is the job of ribosomes? Please answer as soon as possible its related to my project which is due on the day after tomorrow. HURRY PLEASE!!!!Question 7:This passage is taken from a book that chronicles a man's exploration of Alaska.(1)It was now near dark, and I made haste to make up my flimsy little tent. The ground was desperately rocky. I made out, however, to level down a strip large enough to lie on, and by means of slim alder stems bent over it and tied together soon had a home. While thus busily engaged I was startled by a thundering roar across the lake. Running to the top of the moraine, I discovered that the tremendous noise was only the outcry of a newborn berg about fifty or sixty feet in diameter, rocking and wallowing in the waves it had raised as if enjoying its freedom after its long grinding work as part of the glacier. After this fine last lesson I managed to make a small fire out of wet twigs, got a cup of tea, stripped off my dripping clothing, wrapped myself in a blanket and lay brooding on the gains of the day and plans for the morrow, glad, rich, and almost comfortable.(2)It was raining hard when I awoke, but I made up my mind to disregard the weather, put on my dripping clothing, glad to know it was fresh and clean; ate biscuits and a piece of dried salmon without attempting to make a tea fire; filled a bag with hardtack, slung it over my shoulder, and with my indispensable ice-axe plunged once more into the dripping jungle. I found my bridge holding bravely in place against the swollen torrent, crossed it and beat my way around pools and logs and through two hours of tangle back to the moraine on the north side of the outlet,a wet, weary battle but not without enjoyment. The smell of the washed ground and vegetation made every breath a pleasure, and I found Calypso borealis1, the first I had seen on this side of the continent, one of my darlings, worth any amount of hardship; and I saw one of my Douglas squirrels on the margin of the grassy pool. The drip of the rain on the various leaves was pleasant to hear. More especially marked were the flat low-toned bumps and splashes of large drops from the trees on the broad horizontal leaves of Echinopanax horridum2, like the drumming of thundershower drops on veratrum and palm leaves, while the mosses were indescribably beautiful, so fresh, so bright, so cheerily green, and all so low and calm and silent, however heavy and wild the wind and the rain blowing and pouring above them. Surely never a particle of dust has touched leaf or crown of all these blessed mosses; and how bright were the red rims of the cladonia cups beside them, and the fruit of the dwarf cornel! And the wet berries, Nature's precious jewelry, how beautiful they were!huckleberries with pale bloom and a crystal drop on each; red and yellow salmon-berries, with clusters of smaller drops; and the glittering, berry-like raindrops adorning the interlacing arches of bent grasses and sedges around the edges of the pools, every drop a mirror with all the landscape in it. A' that and a' that and twice as muckle's a' that in this glorious Alaska day3, recalling, however different, George Herbert's "Sweet day, so cool, so calm, so bright.4"(3)In the gardens and forests of this wonderful moraine one might spend a whole joyful life.1 A rare orchid found in northern, mountainous areas.2Also called Devil's Club, Echinopanax is a large-leafed shrub that grows in moist, dense forests mostly in the Pacific Northwest of the United States.3 Reference to Scottish poet, Robert Burns's poem that rejoices over the wide variety of positive traits in his wife.4 Reference to a George Herbert poem that celebrates the glory found in nature and mourns the fact that it all must die.In context, the image of the iceberg being born in paragraph one is meant to suggest the deafening nature of the ice scraping against other bergs that natural processes take time and are worthy of wonder the pain experienced upon witnessing the effects of climate change a complex scientific process of iceberg formation and separation the new iceberg's helplessness against the turbulent waters Actividad1: En general, la dificultad para arrancar electrones aumenta de izquierda a derecha en cada periodo de la tabla peridica. Busca en la tabla peridica potasio (K), calcio (Ca) y uranio (U) y basndote en sus posiciones indica cul de ellos tendr una funcin de trabajo ms baja y cul ms alta:Menor funcin de trabajo:Mayor funcin de trabajo:2.- La energa de un electrn emitido se mide en electrn-voltios(eV). Un electrn con una energa de 1 eV puede superar un campo elctrico de 1 voltio. En el simulador, aumenta la tensin hasta que encuentres la tensin ms alta que todava permite a los electrones llegar al ampermetro.Tensin =El volaje que has encontrado es igual a la energa de los electrones emitidos en eV. I need help with dis plz the question is a memory Solve the following system. y = 2x2 - 3x - 4 and y + x = 8. Enter the solution with the smaller x value first. The solutions are ( , ) and ( , ) Will mark brainliest please help helppp , ill give brainlyyy Which feature do prokaryotic and eukaryotic cells share?