Whats is the resistance of a bulb with a current of 60a in a circuit with a 12v battery

The radioactive decay equation is \(Th^{232} - > Ra^{228} + He^{4}\). The activity of 10 g of thorium, calculate the initial activity using the decay constant and the number of nuclei.  the activity after 10 years, use the radioactive decay law with the appropriate values.

a) The radioactive decay equation for thorium-232 (\(Th^{232}\)) can be represented as follows:

\(Th^{232} - > Ra^{228} + He^{4}\)

In this equation, thorium-232 decays into radium-228 and emits an alpha particle (helium-4 nucleus). This decay process occurs spontaneously over time.

b) To find the radioactive radiation activity of 10 g of thorium, we need to use the concept of activity, which represents the rate of decay of radioactive material. The activity (A) is given by the equation:

A = λ * N

Where λ is the decay constant and N is the number of radioactive nuclei present. The decay constant is related to the half-life (T1/2) of the isotope by the equation:

λ = ln(2) / T1/2

For thorium-232, with a half-life of 1.4 * \(10^{10}\) years, the decay constant is approximately λ = ln(2) / (1.4 * \(10^{10}\) years).

To find the number of radioactive nuclei (N) in 10 g of thorium, we can use Avogadro's number and the molar mass of thorium-232. The molar mass of thorium-232 is 232 g/mol, so we have:

N = (10 g) / (232 g/mol) * (6.022 * \(10^{23}\)nuclei/mol)

Now, we can calculate the activity (A) by substituting the values into the equation A = λ * N.

c) To find the activity after 10 years, we need to consider the radioactive decay law, which states that the activity of a radioactive substance decreases exponentially over time. The equation for the remaining activity (A_t) after time t is given by:

A_t = A_0 * e^(-λ * t)

Where A_0 is the initial activity at t = 0.

By substituting the appropriate values into the equation, including the initial activity calculated in part b, we can determine the activity after 10 years.

In summary, to find the radioactive radiation activity of thorium-232, we use the decay equation, the concept of activity, and the radioactive decay law. By applying these principles, we can calculate the initial activity of 10 g of thorium and determine the activity after a specified time, such as 10 years.

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Answer:

Medium - 3. a substance or material in which something exists or occurs

Transverse Waves - 5. waves in which the movement in the medium is perpendicular to the direction the wave is traveling

Surface Waves - 7. a wave that travels on the surface of the water in both transverse and longitudinal motions

Crest - 9. Highest part of the wave

Trough - 10. Lowest part of the wave

Interference - 1. the overlapping of 2 waves having equal amplitude and wavelength

Wave - 2. a disturbance that travels through a medium transporting energy from one location to another location

Amplitude - 8. Height of a wave

Longitudinal Waves - 6. waves in which the movement in the medium is parallel to the direction the wave is traveling

Mechanical Waves - 4. waves that require a medium in which to travel, involves a transfer of kinetic energy from one place to another in the material

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To prepare a Greek salad, different types of cut must be used to cut these ingredients depending on the ingredient.

In culinary there are different types of cuts depending on the cooking or the presentation that you want to give the dish. For example, in the case of Greek salad, all the ingredients are required to be cut in such a way that the bites are suitable for the size of the mouth.

Therefore, the cutting technique for each ingredient is:

the Greek salad looks like the image below:

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The question is incomplete. The complete question is :

The Rocket Club is planning to launch a pair of model rockets. To build the rocket, the club needs a rocket body paired with an engine. The table lists the mass of three possible rocket bodies and the force generated by three possible engines.

A 4-column table with 3 rows. The first column labeled Body has entries 1, 2, 3. The second column labeled Mass (grams) has entries 500, 1500, 750. The third column labeled Engine has entries 1, 2, 3. The fourth column labeled Force (Newtons) has entries 25, 20, 30.

Based on Newton’s laws of motion, which combination of rocket bodies and engines will result in the acceleration of 40 m/s2 at the start of the launch?

Body 3 + Engine 1

Body 2 + Engine 2

Body 1 + Engine 2

Body 1 + Engine 1

Solution :

Given :

Body       Mass (gram)     Engine      Force (newtons)

1                   500                 1                     25

2                  1500                2                    20

3                  750                  3                    30

The body 1 has a mass of 500 gram which is equal to 0.5 kg

And engine 2 has a force of 20 newtons.

We know that according to Newton's laws of motion,

Force = mass x acceleration

 20    = 0.5 x acceleration

Acceleration \($=\frac{20}{0.5}$\)

                      \($=\frac{200}{5}$\)

                      \($= 40 \ m/s^2$\)

Therefore, based on laws of motion of Newton, the Body 1 + Engine 2 combination of the rocket bodies and engines will result in an acceleration of \($ 40 \ m/s^2$\) at the start of the launch.

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Answer:

A

Explanation:

The element that unicornium-210 (210Ui) could not decay into based on atomic mass alone is 90Sr.

A radioactive isotope is a type of atom that has an unstable nucleus that spontaneously decays or disintegrates, emitting radiation in the form of particles or electromagnetic waves. This process is known as radioactive decay.

The unstable nature of the nucleus arises from having too many or too few neutrons compared to the number of protons in the atom, which affects the stability of the atomic nucleus. The decay of radioactive isotopes can have practical applications in fields such as nuclear medicine, energy production, and environmental monitoring, but can also pose health and safety risks if not handled properly.

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So free point OK ty see ya!

Answer:

Scientific Definition of Mass. Mass is the quantity of inertia (resistance to acceleration) possessed by an object or the proportion between force and acceleration referred to in Newton's Second Law of Motion (force equals mass times acceleration). In other words, the more mass an object has, the more force it takes to get it moving.

Explanation:

The ICD-10-CM code is reported in Box 21 of the CMS 1500 form. On the CMS 1500 form, which is used for submitting healthcare claims, the ICD-10-CM code is reported in Box 21. Box 21 is specifically designated for the diagnosis or nature of illness or injury.

The ICD-10-CM (International Classification of Diseases, 10th Revision, Clinical Modification) is a coding system used to classify and report medical diagnoses and procedures. It contains alphanumeric codes that represent various diseases, injuries, and conditions. These codes provide a standardized way of communicating diagnoses across healthcare providers and insurance companies. When completing the CMS 1500 form, healthcare providers are required to enter the appropriate ICD-10-CM code in Box 21 to indicate the reason for the medical service being claimed. This ensures accurate and efficient processing of healthcare claims and reimbursement.

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The ICD-10-CM code is reported in Box 21 of the CMS 1500 form. On the CMS 1500 form, which is used for submitting healthcare claims, the ICD-10-CM code is reported in Box 21. Box 21 is specifically designated for the diagnosis or nature of illness or injury.

The ICD-10-CM (International Classification of Diseases, 10th Revision, Clinical Modification) is a coding system used to classify and report medical diagnoses and procedures. It contains alphanumeric codes that represent various diseases, injuries, and conditions. These codes provide a standardized way of communicating diagnoses across healthcare providers and insurance companies. When completing the CMS 1500 form, healthcare providers are required to enter the appropriate ICD-10-CM code in Box 21 to indicate the reason for the medical service being claimed. This ensures accurate and efficient processing of healthcare claims and reimbursement.

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Answer:

the answer to this question is A globular cluster

Objects have the same velocity only if they are moving at the same speed and in the same direction.

Objects moving at different speeds, in different directions, or both have different velocities.

When two bodies are moving in opposite directions, relative velocity between them is equal to sum of the velocity of bodies.

But if the bodies are moving in same direction their relative velocity is equal to difference in velocity of the bodies.

Relative velocity is defined as the velocity of an object B in the rest frame of another object A. 2) A motorcycle travelling on the highway at a velocity of 120 km/h passes a car travelling at a velocity of 90 km/h.

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Answer:

The distance from sphere A to sphere C on the right such that the original small sphere remains at rest is a/2

Explanation:

The force of a charge at a point is given as follows;

From an online source, we have;

E₁ + E₂ = 0

The electric field due to the sphere B of charge +8q = E₁

\(E_1 = \dfrac{k \cdot (8 \cdot Q)}{a^2}\)

The position of the sphere B = A distance 'a' to the left of 'A'

The electric field due to the sphere C of charge +2q = E₂

The position of the sphere C = A distance to the right of 'A'

Therefore, for the electric field strength of sphere 'B' at 'A', we have;

\(E_1 = \dfrac{k \cdot (8 \cdot Q)}{a^2} = 4 \times \dfrac{k \cdot (2 \cdot Q)}{a^2}\)

Let 'x' be the distance of the +2q charge to the right of 'A', we have;

\(E_2 = \dfrac{k \cdot (2 \cdot Q)}{x^2}\)

Therefore, for the force of the +2q charge to balance the +8q charge at C, we have;

\(\dfrac{k \cdot (2 \cdot Q)}{x^2} = \dfrac{k \cdot (8 \cdot Q)}{a^2} = 4 \times \dfrac{k \cdot (2 \cdot Q)}{a^2}\)

\(\therefore \ \dfrac{1}{x^2} = \dfrac{4}{a^2}\)

\(\therefore \ \sqrt{ \dfrac{1}{x^2} }= \sqrt{\dfrac{4}{a^2}}\)

\(\dfrac{1}{x} = \dfrac{2}{a}\)

\(x= \dfrac{a}{2}\)

Therefore, the distance, 'x', from sphere A to sphere C on the right such that the original small sphere remains at rest is x = a/2.

Answer:

\(9.8\; {\rm J}\), assuming that the gravitational field strength is \(g = 9.8\; {\rm N \cdot kg^{-1}}\).

Explanation:

Notice that both the speed and the direction of motion of this block are constant. In other words, the velocity of this block is constant.

By Newton's Second Law, the net force on this block would be \(0\). External forces on this block should be balanced. Thus, the magnitude of the (downward) weight of this block should be equal to the magnitude of the (upward) force that the boy applies on this block.

Let \(m\) denote the mass of this block. It is given that \(m = 1\; {\rm kg}\). The weight of this block would be:

\(\begin{aligned}\text{weight} &= m\, g \\ &= 1\; {\rm kg} \times 9.8\; {\rm N \cdot kg^{-1}} \\ &= 9.8\; {\rm N}\end{aligned}\).

Hence, the force that the boy applies on this block would be upward with a magnitude of \(F = 9.8\; {\rm N}\).

The mechanical work that a force did is equal to the product of:

The displacement of this block (upward by \(s = 1\; {\rm m}\)) is in the same direction as the (upward) force that this boy had applied. Thus, the work that this boy had done would be the product of:

\(\begin{aligned}\text{work} &= F\, s \\ &= 9.8\; {\rm N} \times 1\; {\rm m} \\ &= 9.8\; {\rm J}\end{aligned}\).

Explanation:

Acc=change in velocity/time

a=30-0 / 6

a =30/6

a = 5m/s^2

The statement that is true is: "The higher the velocity of a projectile, the larger the cavity it produces."low-velocity injuries produce extensive temporary wound channels. there are four levels of velocity.

A projectile is an object that is thrown, launched, or shot through the air and travels in a parabolic path under the influence of gravity. It can be a solid, liquid, or gas and can be propelled by various means such as a gun, bow, and arrow, or even by throwing with one's own body. The trajectory of a projectile is determined by its initial velocity, angle of projection, and the force of gravity acting upon it. Understanding the principles of projectile motion is important in a variety of fields, such as engineering, physics, and sports. Projectile motion is also affected by air resistance and other external factors, making it a complex area of study.

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The following information is provided in the problem: A sled with a weight of 19.7 kg is pulled with a force of 42.0 N at an angle of 43.0° across ground where μ₁ = 0.130. We need to find out the normal force that is exerted on the sled.

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Let's assume it took 10 seconds to walk from A to B. Using the formula, the distance covered would be 5.10 m/s × 10 s = 51 meters. The distance covered would be 3.20 m/s × 15 s = 48 meters. Adding the distances, the total distance traveled is 51 meters + 48 meters = 99 meters.

A person walks at a constant speed of 5.10 m/s from point A to point B along a straight line.

Then, they walk back from point B to point A at a constant speed of 3.20 m/s.
To find the total distance traveled, we need to calculate the distance covered from A to B and then add it to the distance covered from B to A.
To find the distance from A to B, we can use the formula distance = speed × time.

Since we know the speed is 5.10 m/s, we need to find the time it took to cover the distance.

Unfortunately, the time is not provided in the question, so we cannot calculate the exact distance.

However, if we assume the time taken to walk from A to B is 10 seconds, the distance covered would be 5.10 m/s × 10 s = 51 meters.
Similarly, to find the distance from B to A, we can use the same formula. Assuming it took 15 seconds to walk back, the distance covered would be 3.20 m/s × 15 s = 48 meters.
Therefore, the total distance traveled is 51 meters + 48 meters = 99 meters.
A person walks at a constant speed of 5.10 m/s along a straight line from point A to point B and then back along the line from point B to point A at a constant speed of 3.20 m/s.

To find the total distance traveled, we need to calculate the distance covered from A to B and then add it to the distance covered from B to A.

The formula to find the distance is distance = speed × time.

However, the question does not provide the time taken for each segment of the walk, so we cannot calculate the exact distances.

We can, however, make assumptions about the time taken.

Let's assume it took 10 seconds to walk from A to B.

Using the formula, the distance covered would be 5.10 m/s × 10 s = 51 meters.

Now, let's assume it took 15 seconds to walk back from B to A.

The distance covered would be 3.20 m/s × 15 s = 48 meters.

Adding the distances, the total distance traveled is 51 meters + 48 meters = 99 meters.

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Answer:

So Nessa went so fast it made her pass the tile in a second. Lets take a look at this problem, It says "the" tile so we should assume that it means 1 tile. Then draw a diagram representing that tile then you should have your problem finished. Hope that helped and I'm willing to help if you have anymore questions!

Explanation:

Answer:

Calcium chloride is very effective, working at temperatures below most products, and is significantly more effective than sodium chloride because of its ability to extract moisture from its surroundings and to cause exothermic or heat generating reactions.

Explanation:

Hope this helps

For the given LC circuit (inductor-capacitor) , the sum of the energy stored in the capacitor and that in the inductor remains constant.

Energy transferred between the inductor and capacitor. So the total energy oscillating between the two components at a resonant frequency.

The energy stored in the capacitor and inductor individually varies over time as the energy oscillates between them.

When voltage changes the energy stored in the capacitor also changes. This is caused by the change in current flowing.

So we can say both the energy stored in the capacitor and the energy stored in the inductor remains constant in a given LC circuit.

The energy dissipated in the circuit can vary over time. Like that the energy stored in the current flowing in the circuit and the energy stored in the capacitor can also vary over time in an LC circuit.

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To calculate the horizontal distance the projectile will fall, we need to determine the time of flight first. The equation for vertical motion (ignoring air resistance) can be written as: y = v₀y * t + (1/2) * g * t²

Where: y = vertical displacement (which is -49.0 m since the projectile is falling) v₀y = initial vertical velocity (which is 0 m/s since the projectile is launched horizontally) g = acceleration due to gravity (approximately -9.8 m/s²) t = time of flight. Substituting the known values into the equation:

-49.0 m = 0 * t + (1/2) * (-9.8 m/s²) * t²

-49.0 m = -4.9 m/s² * t²

Simplifying the equation:

t² = 49.0 m / (4.9 m/s²)

t² = 10 s²

t = √(10) s

t ≈ 3.16 s. Now, we can use the horizontal velocity to calculate the horizontal distance: v = d / t. Rearranging the equation: d = v * t. Given that the horizontal velocity (v) is 20.0 m/s and the time of flight (t) is approximately 3.16 s, we can substitute these values into the equation: d = 20.0 m/s * 3.16 s. d ≈ 63.2 m. Therefore, the projectile will fall approximately 63.2 meters horizontally.

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The cannonball will be in the air a time of: 3.6421 s

The horizontal launch formula we will use and the procedure is:

t = √((2 * h) / g)

Where:

Information about the problem:

Applying the time formula we have:

t = √((2 * h) / g)

t = √((2 * 65 m) / 9.8 m/s²)

t = √(130 m / 9.8 m/s²)

t = √(13.2653 s²)

t = 3.6421 s

Is the motion described by an object that has been thrown horizontally with no angle of inclination at a certain height and considers the effect that the force of the earth's gravity has on the thrown object.

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Answer:

v = 24 cm and inverted image

Explanation:

Given that,

The focal length of the object, f = +8 cm

Object distance, u = -12 cm

We need to find the position &nature of the image​. Let v be the image distance. Using lens formula to find it :

\(\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\)

Put all the values,

\(\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{8}+\dfrac{1}{(-12)}\\\\v=24\ cm\)

So, the image distance from the lens is 24 cm.

Magnification,

\(m=\dfrac{v}{u}\\\\m=\dfrac{24}{-12}\\\\m=-2\)

The negative sign of magnification shows that the formed image is inverted.

Convex lens of focal length 30cm combined with concave lens of focal length 15 cm. The combined focal length is 20 cm. The power of a lens is defined as the reciprocal of the focal length of a lens in meters which is, P = 5 D (diopters). The combination of convex and concave lenses will act like a convex lens.

To find the combined focal length, power, and nature of the combination of a convex lens of focal length 30 cm combined with a concave lens of focal length 15 cm, follow the steps below:

Combined focal length:

Use the lens formula for the convex and concave lenses and the given values.

Focal length (f) = 30 cm for the convex lens

Focal length (f) = -15 cm for the concave lens

Using the lens formula:

1/f = 1/v - 1/u

1/f = (v - u) / uv

v = focal length of the combination of lenses

u = object distance

For the combination of lenses:

u = object distance

v1 = distance from object to the concave lens

v2 = distance from the concave lens to the convex lens

v = distance from the convex lens to the image

Given:

f1 = focal length of convex lens = 30 cm

f2 = focal length of concave lens = -15 cm

v1 = -f2 = -(-15) = 15 cm

By combining the convex and concave lenses, the final image will be formed on the same side as the object. Thus, the sign convention for u and v will be positive. Therefore, using the lens formula, the value of v will be given by:

1/f = 1/v - 1/u

1/f = (v - u) / uv

v = 1/f1u + 1/f2

v = 1/30(0.5) + 1/(-15)(0.5) + 0.5

v = -6 cm

The combined focal length is the distance between the optical center and the focal point of the lens system. It is calculated as follows:

1/F = 1/f1 + 1/f2 - (d / (f1f2))

F = 20 cm (approximately)

Therefore, the combined focal length is 20 cm.

Power of the combination:

The power of a lens is defined as the reciprocal of the focal length of a lens in meters.

P = 1/f = 1/0.2

P = 5 D (diopters)

Nature of the combination:

Since the focal length of the combined lenses is positive, the combination is a convex lens. Therefore, the combination of convex and concave lenses will act like a convex lens.

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Answer:

below

Explanation:

Work = force x distance = PE gain = mgh =  4 kg * 9.81 m/s^2 * 6 = 235.44  j

Power  = work / time      ( time is in seconds)

          = 235.44 / (2*60) = 1.962 watts  

   SPECIFIC power = 1.962 w / 4 kg = .49 w/kg

Answer:

It blocks some light, but not all.

Explanation:

The point of polarization is to get the light to travel in a single plane. The light waves occur in a single plane. The direction of the vibration of the waves is the same. With two polarized filters, it is possible to block out nearly all the light.

Answer:

C

Explanation:

You will hear a lower pitch of sound than your teacher who is directly below the bell.

The pitch of a sound refers to how high or low the sound is. If a sound is high we say that it has a high pitch and vice versa.

We must note that the closer you are the bell the higher the pitch of the bell sound you hear. Hence, you will hear a lower pitch of sound than your teacher who is directly below the bell.

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