Answer:
Newtons
Explanation:
Its units are newtons because force has both magnitude and direction.
the distance between two successive peaks of a wave is called a ___________.
The distance between two successive peaks of a wave is called a wavelength.
In physics, wavelength refers to the distance between successive crests, troughs, or any other repeating pattern in a wave. It is denoted by the Greek letter lambda (λ). Wavelength is a fundamental property of waves and is commonly used to describe various types of waves, including electromagnetic waves (such as light and radio waves) and sound waves.
In the case of electromagnetic waves, wavelength represents the spatial extent of the wave and is typically measured in meters or multiples thereof, such as nanometers (10^-9 meters) or micrometers (10^-6 meters). Different types of electromagnetic waves have different wavelengths. For example, visible light consists of a range of wavelengths, with red light having longer wavelengths and blue light having shorter wavelengths.
In the context of sound waves, wavelength refers to the distance between successive compressions or rarefactions in the wave. It is commonly measured in meters or fractions of a meter, such as centimeters or millimeters.
The relationship between wavelength (λ), frequency (f), and the speed of the wave (v) is given by the equation: v = λf. This equation states that the speed of a wave is equal to the product of its wavelength and frequency.
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The study of the human mind and how it behaves in certain situations is called
A.history
B.psychology
C. anger
D. therapy
Answer:
Psychology
Explanation:
The study of the human mind and how it behaves in certain situations is called Psychology.
Which kind of studies are used to
investigate the nature versus
nurture theories of human
personality development?
Investigating the nature versus nurture theories of human personality development requires the use of a combination of different types of studies. By using a multidisciplinary approach, researchers can gain a better understanding of how both genetics and environmental factors contribute to personality development.
One type of study is behavioral genetics research, which examines the extent to which genetics contribute to individual differences in behavior and personality traits. This type of study typically involves comparing the similarity of traits between individuals who share different amounts of genetic material, such as twins and siblings.
Another type of study used to investigate nature versus nurture is twin studies. These studies compare the behavioral and personality traits of identical twins, who share 100% of their genetic material, with those of fraternal twins, who share only 50% of their genetic material. By comparing the similarities and differences in traits between these two groups of twins, researchers can determine the degree to which genetics contribute to personality development.
Additionally, adoption studies are used to investigate the role of environmental factors in shaping personality. These studies typically compare the traits of adopted children with those of their biological parents, who they share genetics with but not environment, and their adoptive parents, who they share environment with but not genetics.
Overall, investigating the nature versus nurture theories of human personality development requires the use of a combination of different types of studies. By using a multidisciplinary approach, researchers can gain a better understanding of how both genetics and environmental factors contribute to personality development.
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Which one of the following statements about supernovae is FALSE?
a) At optical wavelengths, a supernova can appear as bright as the entire galaxy of stars in which it's located
b) A supernova produces an expanding shell of gas that is rich in heavy elements
c) Nobody has seen a bright supernova in our own Milky Way Galaxy during the past century
d) A neutron star is produced when a white dwarf exceeds a certain mass limit and becomes a supernova experiencing a runaway chain of nuclear fusion reactions
e) One kind of supernova occurs when the iron core of a massive star collapses
The false statement about supernovae is (c) - nobody has seen a bright supernova in our own Milky Way Galaxy during the past century.
This statement is incorrect because there have been several bright supernovae observed in the Milky Way Galaxy in the past century. For example, the most recent one was SN 1987A, which occurred in the Large Magellanic Cloud, a satellite galaxy of the Milky Way, but was visible from Earth.
Supernovae are incredibly powerful and dramatic events that occur when a star runs out of fuel and can no longer support its own weight. There are two main types of supernovae - Type I and Type II. Type I supernovae occur in binary star systems where one star is a white dwarf and the other star is either a giant or a main sequence star. Type II supernovae occur when a massive star runs out of fuel and its core collapses, triggering a runaway fusion reaction that causes the star to explode.
When a supernova occurs, it produces an expanding shell of gas that is rich in heavy elements such as iron. These elements are created during the explosion and are scattered throughout space, eventually forming new stars and planets. Supernovae are also important sources of energy that can trigger the formation of new stars and even help to regulate the overall structure and evolution of galaxies.
In conclusion, while there are many fascinating and incredible facts about supernovae, it is important to understand that they are also incredibly powerful and can have a profound impact on the universe around them. Understanding these events is a critical part of our ongoing efforts to explore and learn about the vast expanse of space that surrounds us. Therefore, the false statement is (c).
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Which statement describes the transmission of mechanical waves?(1 point)
They cannot travel through matter nor in a vacuum.
They can travel through matter, but not in a vacuum.
They cannot travel through matter, but they can in a vacuum.
They can travel through matter and in a vacuum.
Answer:
They can travel through matter, but not in a vacuum.
Explanation:
The best statement that describes the transmission of mechanical waves is that they can travel through matter but not in a vacuum.
Mechanical waves require a material medium for their propagation. In the absence of such medium they are not transmitted. Examples are seismic waves, sound waves, water waves e.t.c
A type of wave than can be transmitted through a vacuum and through matter are the electromagnetic waves.
Answer:
it is option B. they are correct
What do MRI and ultrasound have in common as diagnostic imaging techniques? Check all that apply.
anyone can you help me
Answer:
SORRY I CAN'T DO FOR YOU BECAUSE I DON'T KNOW WHERE IS THE QUESTION
Explanation:
one function of a cell wall
Answer:
The cell wall surrounds the plasma membrane of plant cells and provides tensile strength and protection against mechanical and osmotic stress. It also allows cells to develop turgor pressure, which is the pressure of the cell contents against the cell wall.
What’s the author main purpose in writing this article? In do Juvenill Killer Desert
Modest evidence suggests that young people who commit crimes deserve to service their entire lives in prison. Modicum demonstrates that despite the fact that children commit crimes, they do not merit the harsh punishment Dutton received while incarcerated.
The court stated that because of their youth, they are more impulsive, more susceptible to social pressure, and less able to see the repercussions of their actions. Their brains are also reportedly less developed. There are 79 of these juvenile killers alive today; they will all perish in jail.
Context is crucial when discussing juvenile punishment instances. The juvenile death sentence was abolished by the Supreme Court in 2005 on the grounds that children are not the same as adults. Younger people, according to the court, have brains that are actually less developed, are more impulsive, are more susceptible to social pressure, and are less able to see the effects of their actions.
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to investigate the issue of juvenile offenders in the United States receiving life sentences without the possibility of release.
The article's primary goal is to draw attention to the problem of juvenile offenders in the United States receiving life sentences without the possibility of release. In this article, the impact of this sentencing strategy on juvenile offenders is examined, and the fairness of such sentences is questioned. The author's claim that these punishments are ineffectual and unjust is supported by data and evidence. The paper also urges a shift in strategy and offers substitutes that give young offenders priority in rehabilitation and restorative justice.
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A worker lifts a 10 kilogram block a vertical height of 2 meters. The work he does on the block is:
Answer:
Work = 196 Joules (1 kg*m^2/sec^2 is 1 Joule)
Explanation:
Work, W, is defined as force. F, times displacement, d.
W = Force*displacement
In the worker's case, the force he/she is struggling against is Earth's gravity's acceleration, g, (9.8 m/sec^2) times the mass, m.
Force = mg
Force = (10kg)*(9.8 m/sec^2) = 98 kg*m/sec^2
Use this force in the work calculation.
W = Force*displacement
The displacement is 2 meters.
Work = (98 kg*m/sec^2)*(2 meters) = 196 kg*m^2/sec^2
1 kg*m^2/sec^2 is 1 Joule
Work = 196 Joules
Which sport requires the least amount of agility? HELLLLPPP
1.volley ball
2.golf
3.football
4.basketball
Answer:
golf
Explanation:
it's less physical strength in more of you hitting the ball with whatever the stick is called
If too much energy is given to an electron that is above the threshold
frequency what happens to the extra energy?
Answer:
The electron gives up It's extra energy in a form called "photon light" and falls back down to its normal energy level
Explanation:
Please help WHATS the answer
Focal length = 1/2 radius
Focal length = 1/2 (62)
Focal length = 31cm
Answer is B.
1. A car starts from the rest on a circular track with a radius of 300 m. It accelerates with a constant tangential acceleration of a = 0.75 m/s?. Determine the distance traveled and the time elapsed"
Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.
To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.
The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).
Using the equation:
v = v₀ + at
where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:
v = 0 + (0.75 m/s²) * t
v = 0.75t m/s
The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:
v = ωr
Substituting the values:
0.75t = ω * 300
Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:
ω = ω₀ + αt
ω = 0 + (0.75 m/s²) * t
ω = 0.75t rad/s
We can now substitute the value of ω into the equation:
0.75t = (0.75t) * 300
Simplifying the equation gives:
0.75t = 225t
t = 0.75 seconds
The time elapsed is 0.75 seconds.
To calculate the distance traveled (s), we can use the equation:
s = v₀t + (1/2)at²
Since the initial velocity (v₀) is zero, the equation becomes:
s = (1/2)at²
s = (1/2)(0.75 m/s²)(0.75 s)²
s = (1/2)(0.75 m/s²)(0.5625 s²)
s = 0.2119 meters or approximately 21.19 centimeters
Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.
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You are raising up a big bucket of water from a 29.3 m deep well. The combined mass of the water and the bucket is 12.1 kg. The bucket is attached to a heavy duty steel chain. The mass of the chain is 18.9 kg. How much work do you perform during the lifting process
The amount of work exerted during the lifting process is approximately 8,344.51 Joules, representing the gravitational potential energy gained as the bucket and water system is raised from the 29.3 m deep well.
To determine the amount of work performed during the lifting process, we need to calculate the gravitational potential energy gained by the bucket and water system as it is raised from the well.
The work done is equal to the change in gravitational potential energy, which can be calculated using the formula:
Work = mgh
where:
m = mass (combined mass of the water and bucket)
g = acceleration due to gravity (approximately 9.8 m/s²)
h = height (depth of the well)
Given information:
Mass of water and bucket (m) = 12.1 kg
Height of the well (h) = 29.3 m
First, let's calculate the gravitational potential energy gained by the water and bucket system:
Potential energy = mgh
Potential energy = (12.1 kg + 18.9 kg) × 9.8 m/s² × 29.3 m
Potential energy = 31 kg × 9.8 m/s² × 29.3 m
Potential energy ≈ 8,344.51 Joules
Therefore, the work performed during the lifting process is approximately 8,344.51 Joules.
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An object with a mass of 10kg accelerates 16 m/s2 when an unknown force is
applied to it. What is the amount of force?
160 N
9.8 m/s2
165.8 kg
1.6 N
Answer:
The answer is 160 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 10 × 16
We have the final answer as
160 NHope this helps you
The slope of a distance-time graph will give
The gravitational potential energy of a cucumber-harth system changes when which factor changes?
A) the cucumber's speed
B) the cucumber's mass
c) the cucumber's temperature
D) the length
The rotating blade of a blender turns with constant angular acceleration of 1.51 rad/s^2. How much time does it take to reach an angular velocity of 36.8 rad/s, starting from rest?
time to reach an angular velocity of 36.8 is 24.370 s.
What is angular acceleration?The temporal rate at which angular velocity changes is referred to as angular acceleration. Naturally, there are two forms of angular acceleration, referred to as spin angular acceleration and orbital angular acceleration, just as there are two types of angular velocity, namely spin angular velocity and orbital angular velocity. As opposed to orbital angular acceleration, which is the angular acceleration of a point particle around a fixed origin, spin angular acceleration describes the angular acceleration of a rigid body about its centre of rotation.
w(t) = w(0) + α*t
also w(0) =0
=> time = 36.8/1.51= 24.370 s
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how much time will it take for a bug to travel 55 M across the floor if it's traveling by 1.1 m / s
Answer:
The bug will take 50 seconds to travel 55 m across the floor if it's traveling by 1.1 m / s.
Explanation:
Given
Distance covered by bug = d = 55 m
The speed = s = 1.1 m/s
To determine
Time the bug will take to cover the distance = t = ?
Using the formula to determine the time the bug will take to travel 55 m across the floor if it's traveling by 1.1 m/s.
Distance = Speed x Time
d = s x t
t = d/s
t = 55/1.1
t = 50 s
Therefore, the bug will take 50 seconds to travel 55 m across the floor if it's traveling by 1.1 m / s.
12) Driving home from school one day, you spot a ball rolling out into the street (FIGURE 5-27). You brake for 1.20 s, slowing your 950-kg car from 16.0 m>s to 9.50 m>s. What was the average forceexerted on your car during braking and How far did you travel while braking?
We are given the following information
Mass of car = 950 kg
Initial speed of car = 16.0 m/s
Final speed of car = 9.50 m/s
Time = 1.20 s
The average force exerted on the car during braking can be found using Newton's 2nd law of motion
\(F=m\cdot a\)Where m is the mass of the car and a is the acceleration of the car.
The acceleration of the car is given by
\(\begin{gathered} a=\frac{v_f-v_i}{t} \\ a=\frac{9.50-16.0}{1.20} \\ a=-5.4167\; \; \frac{m}{s^2} \end{gathered}\)The negative sign indicates deacceleration since the car is stopping.
So, the force is
\(\begin{gathered} F=m\cdot a \\ F=950\cdot5.4167 \\ F=5145.865\; \; N \end{gathered}\)Therefore, an average force of 5145.865 N was exerted on your car during braking.
The distance traveled by the car while braking can be found as
\(s=v_i\cdot t+\frac{1}{2}\cdot a\cdot t^2\)Let us substitute the given values
\(\begin{gathered} s=16.0\cdot1.20+\frac{1}{2}\cdot(-5.4167)\cdot(1.20)^2 \\ s=19.20-3.90 \\ s=15.3\; m \end{gathered}\)Therefore, the car traveled a distance of 15.3 m while braking.
the class of laser which causes the greatest potential hazard is? quizlet who of the following is fully responsible for the laser in his or her lab? the proper immediate response to a laser accident involving an eye injury is?
The class of laser that causes the greatest potential hazard is Class 4.
The individual who is fully responsible for the laser in his or her lab is the Laser Safety Officer (LSO) or the Principal Investigator (PI) of the lab. They are responsible for implementing and enforcing laser safety protocols, conducting risk assessments, providing training to personnel, and ensuring compliance with applicable regulations.
The proper immediate response to a laser accident involving an eye injury is as follows:
Ensure the safety of the affected person and others in the area by turning off the laser immediately.
If possible, assist the injured person to a safe area away from the laser beam.
Encourage the injured person to keep their eyes closed to minimize further damage.
Seek immediate medical attention for the injured person. Call emergency services or go to the nearest emergency room.
Provide any necessary information to medical professionals regarding the type of laser involved, laser parameters, and any known hazards associated with the laser.
Report the incident to the appropriate authorities within the organization, such as the Laser Safety Officer or supervisor.
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A thin beam of light of wavelength 50 μm (in the infrared portion of the em spectrum) goes through
a thin slit and falls on a screen 3.00 m past the slit. You observe that the first completely dark fringes
occur on the screen at distances of ±8.24 mm from the central bright fringe, and that the central bright
fringe has an intensity of I0 at its center. (a) How wide is the slit? (b) What is the highest order fringe
this scenario is capable of producing? (c) What is the intensity of light at a point on the screen that is
one-quarter of the way from the central bright fringe to the first dark fringe?
Solution :
Given :
Wavelength of the thin beam of light, λ = 50 μm
Distance of the screen from the slit, D = 3.00 m
Width of the fringe, Δy = ±8.24 mm
Therefore, width of the slit is given by :
\($d=\frac{n \lambda D}{\Delta y}$\)
\($=\frac{2 \times 50 \times 10^{-9} \times 3}{2 \times 8.24 \times 10^{-3}}$\)
= 0.000018203 m
= 0.0182 mm
= 0.018 mm
The intensity of light is given by :
\($I=I_0\left(\frac{\sin \beta /2}{\beta/ 2}\right)^2$\) , where \($\beta=\frac{2 \pi D \sin \theta}{\lambda}$\)
\($I=I_0\left(\frac{\sin \frac{\pi d \sin \theta}{\lambda}}{\frac{\pi d \sin \theta}{\lambda}}\right)^2$\)
\($I=I_0\left(\frac{\sin \frac{\pi d y}{D\lambda}}{\frac{\pi d y}{D\lambda}}\right)^2$\)
Now, \($\frac{dy}{D \lambda} = \frac{8.24 \times 10^{-3}\times 0.018 \times 10^{-3}}{4 \times 50\times 10^{-9}\times 4}$\)
= 0.1854
≈ 0.18
\($I=I_0\left(\frac{\sin 0.56}{0.56}\right)^2$\)
\($=I_0 \times 0.81$\)
= 2 x0.81
\($= 1.62 \ W/m^2$\)
The speed of light traveling through an unknown material is 1.98×108 m/s. Given that the speed of light in a vacuum is 3.00×108 m/s, what is the dielectric constant of the unknown material?
The dielectric constant of the unknown material is 2.3.
What is dielectric constant?Dielectric constant is referred as a relative permittivity or amount of charge required to produce one unit of electric flux in a given medium.
Given the speed of light in vacuum c =3 x 10⁸ m/s and the speed of light through an unknown material v = 1.98 x 10⁸ m/s.
The dielectric constant is related to the velocity by the following relation,
v = c/√K
Rearranging for dielectric constant, we get
K = (c/v)²
Substitute the value into the expression ,we get
K =(3 x 10⁸ / 1.98 x 10⁸)²
K = 2.3
Thus, the dielectric constant of the unknown material is 2.3.
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the tanker jet is flying at a constant speed of 360 km/hr and initially 10 km ahead of the receiver jet. the receiver jet is initially flying at a speed of 360 km/hr and needs to catch up with the tanker jet. the receiver jet can accelerate and decelerate at a maximum magnitude of 1.05g, where g is the gravitational acceleration and equals 9.8 m/sec/sec. determine the minimum amount of time, in seconds, taken by the receiver jet to catch up with the tanker jet. write your answer rounded to the closest second.
The minimum amount of time taken by the receiver jet to catch up with the tanker jet is 100 seconds, rounded to the nearest second.
Let's assume that the receiver jet accelerates at the maximum rate (1.05g) until it reaches the same speed as the tanker jet, and then coasts for the rest of the journey.
The time taken for the receiver jet to reach the same speed as the tanker jet can be calculated using the following formula:
t = v / a
where
v = final speed - initial speed
a = acceleration (1.05g)
The initial speed of the receiver jet is 360 km/hr = 100 m/s. The final speed is the same as the tanker jet, which is 360 km/hr = 100 m/s.
So, v = 100 m/s - 100 m/s = 0
a = 1.05 * 9.8 m/s^2 = 10.29 m/s^2
t = v / a = 0 / 10.29 m/s^2 = 0 s
Since the receiver jet reached the same speed as the tanker jet in zero seconds, it will continue to fly at a constant speed of 100 m/s for the rest of the journey. The distance that the receiver jet needs to cover can be calculated as follows:
d = v * t
where
v = 100 m/s (speed of the receiver jet)
t = time taken to cover the distance (to be calculated)
Since the tanker jet was initially 10 km ahead of the receiver jet, the distance that the receiver jet needs to cover is 10 km = 10,000 m.
t = d / v = 10,000 m / 100 m/s = 100 s
So, the minimum amount of time taken by the receiver jet to catch up with the tanker jet is 100 seconds, rounded to the nearest second.
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Msx1 is a regulator of bone formation during development and postnatal growth: in vivo investigations in a transgenic mouse model
The in vivo investigations using a transgenic mouse model have provided important evidence that supports the role of Msx1 as a regulator of bone formation. These findings contribute to our understanding of how bones develop and grow, which has implications for both developmental biology and potential therapeutic interventions for bone-related conditions.
Msx1 is a regulator of bone formation during development and postnatal growth. This means that it plays a role in controlling the process of bone formation, both during the early stages of development and in the growth that occurs after birth.
In vivo investigations, which involve studying the effects of a particular factor in a living organism, have been conducted using a transgenic mouse model. Transgenic mice are mice that have been genetically modified to have specific genes or traits.
These investigations have provided valuable insights into the function of Msx1 in bone formation. They have shown that when Msx1 is present, it acts as a regulator, controlling the process of bone formation. This means that it helps to ensure that bones develop and grow properly.
One example of how Msx1 functions as a regulator is during the early stages of bone development. It helps to determine the shape and structure of the bones, ensuring that they form correctly.
Another example is in postnatal growth, where Msx1 helps to regulate the growth of bones as the organism continues to develop. It ensures that bones grow at the right rate and in the right direction.
Overall, the in vivo investigations using a transgenic mouse model have provided important evidence that supports the role of Msx1 as a regulator of bone formation. These findings contribute to our understanding of how bones develop and grow, which has implications for both developmental biology and potential therapeutic interventions for bone-related conditions.
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Fighter jets on aircraft carriers are accelerated down a 270 foot "runway" in two seconds when they are taking off. A fully loaded, combat ready F-15 has a maximum take-off weight of 62,000 pounds. To ensure the pilot can reach sufficient velocity within 2 seconds a pneumatic cannon propels the plane down the runway. If this same cannon was used to launch your Toyota Corolla (mass is 2646lbs), how fast in miles per hour would you be going after reaching the end of the runway?
The speed of the Toyota Corolla would have been 143.9 mph.
What is the acceleration of the F-15?
The acceleration of the F-15 can be calculated as follows:
Acceleration = Velocity Change / Time = (Take-off Speed) / Time
where;
Take-off Speed = √(2dg /t²)
Take-off Speed = √(2 x (270 ft) x 32.2 ft/s² / (2 s)²)
T = √(17496) = 131.6 ft/s
Acceleration = Velocity Change / Time
= (131.6 ft/s) / (2 s) = 65.8 ft/s²
We can use the same acceleration to launch the Toyota Corolla, and calculate its final velocity:
Final Velocity = Initial Velocity + Acceleration x Time
where;
Initial Velocity = 0 (because the car is not moving initially), Time = 2 sFinal Velocity = 0 + (65.8 ft/s²) * (2 s) = 131.6 ft/s
Finally, we can convert the velocity from feet per second to miles per hour:
Velocity (mph) = Velocity (ft/s) x (1 hour/3600 s) x (5280 ft/mile)
= 131.6 ft/s x (1 hour/3600 s) x (5280 ft/mile)
= 143.9 mph
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A global magnetic field generated from inside the planet is found around which terrestrial planet or planets?MercuryEarthVenusMoonJupiter
A global magnetic field generated from inside the planet is found around Mercury, Earth, and Jupiter. Venus and the Moon do not have a global magnetic field.
Mercury's magnetic field is about 1% as strong as Earth's magnetic field and is believed to be generated from a dynamo effect caused by the planet's partially molten core. Earth's magnetic field is generated from the motion of molten iron in its outer core. Jupiter's magnetic field is the largest of any planet in the Solar System and is believed to be generated by a dynamo effect caused by the planet's metallic hydrogen core. The lack of a global magnetic field on Venus and the Moon is due to their cores being too small and cooling too quickly to generate a magnetic field.
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a circuit has three resistors connected in series. resistor r2 has a resistance of 200 ohms and a voltage drop of 30 volts. what is the current in resistor r3?
The current through resistor R3 is 0.33 A. A circuit with three resistors connected in series is shown below: Circuit diagram of three resistors connected in series As per the given information, R2 has a resistance of 200 ohms and a voltage drop of 30 volts.
Therefore, the voltage drop across R1 is V1 = V - V2 - V3V = voltage supplied to the circuit = voltage drop across R1 + voltage drop across R2 + voltage drop across R3R1 = Resistance of resistor R1.R2 = Resistance of resistor R2 = 200 Ω.V3 = Voltage drop across resistor R3.I3 = Current through resistor R3.To calculate the current in resistor R3, let's follow the steps given below.Step 1: Find the voltage drop across R1.Using Ohm's Law, the voltage drop across R2 is V2 = IR2Substitute the values of V2 and R2 to get the value of current I.I = V2/R2I = 30/200I = 0.15 A
Using Kirchhoff's voltage law, the voltage drop across R1 isV1 = V - V2 - V3V = V1 + V2 + V3Substitute the values of V, V2, and V3 to get the value of V1.V1 = V - V2 - V3V1 = 100 - 30 - V1V1 = 70 VStep 2: Find the current through R3.Using Ohm's Law, the voltage drop across R3 is V3 = I3R3.Substitute the values of V3 and R3 to get the value of current I3.I3 = V3/R3I3 = (V - V1 - V2)/R3I3 = (100 - 70 - 30)/R3I3 = 0.33 A
Therefore, the current through resistor R3 is 0.33 A.
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a ball on the end of a string is whirled around in a horizontal circle of radius 0.300 m. the plane of the circle is 1.00 m above the ground. the string breaks and the ball lands 1.90 m (horizontally) away from the point on the ground directly beneath the ball's location when the string breaks. find the radial acceleration of the ball during its circular motion.
The radial acceleration of the ball during its circular motion is approximately 59.4 m/s^2.
Centripetal acceleration, a = v^2 / r, where v is the speed of the ball and r is the radius of the circle.
The time it takes for the ball to reach the ground,
y = 1/2 g t^2
where y is the initial height of the ball (1.00 m), g is the acceleration due to gravity (9.81 m/s^2), and t is the time it takes for the ball to reach the ground.
t = sqrt(2y/g)
= sqrt(2 x 1.00 / 9.81)
≈ 0.45 s
Velocity, v = x/t
= 1.90 / 0.45
≈ 4.22 m/s
The radial acceleration of the ball during its circular motion can now be found using the equation,
a = v^2 / r
a = v^2 / r = (4.22)^2 / 0.300 ≈ 59.4 m/s^2
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