Marcle is registering for her college classes Which cost 105 per unit. If each classes, can she take to have a maximum cost of 1,365?
Answers
If each unit costs 105 dollars and Marcle wants to spend a maximum of 1,365 dollars on classes, then she can take up to 13 classes.
To calculate the maximum number of classes Marcle can take, we need to divide the maximum cost she is willing to spend by the cost of each unit. So, we have:
Maximum cost Marcle is willing to spend = $1,365
Cost of each unit = $105
Number of classes Marcle can take = Maximum cost Marcle is willing to spend / Cost of each unit
Number of classes Marcle can take = $1,365 / $105
Number of classes Marcle can take ≈ 12.98
Since Marcle cannot take a fraction of a class, we round down to the nearest whole number to get the maximum number of classes she can take without exceeding her budget. Therefore, Marcle can take up to 13 classes.
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Related Questions
helpppp pleeaseee ))))): ?
Answers
Answer:
The reflections of triangle's across the x - axis are A and D
please answer question 3 & 4
By default, Tableau considers categorical data to be dimensions and quantitative data to be measures. True False Question 4 1 pts In Tableau, green pills represent measures and blue pills represent di
Answers
Question 3: By default, Tableau considers categorical data to be dimensions and quantitative data to be measures. True or False?
Answer: True
Tableau is a powerful data visualization software that allows users to explore, analyze and visualize data from various sources. In Tableau, data is classified into two categories: dimensions and measures. Dimensions are categorical variables that describe the data, such as names, dates, regions, and product categories. Measures are quantitative variables that represent the data's numerical values, such as revenue, profit, and quantity. By default, Tableau considers categorical data to be dimensions and quantitative data to be measures, but you can also change this setting in Tableau according to your needs.
Question 4: In Tableau, green pills represent measures and blue pills represent dimensions. True or False?Answer: FalseExplanation:In Tableau, green pills represent dimensions, and blue pills represent measures. Dimensions are discrete fields used to categorize, group, or filter data, while measures are continuous fields that are used to perform mathematical operations, such as sum, average, minimum, maximum, and count. You can drag a dimension or measure field from the Data pane to the Rows or Columns shelf in Tableau to create a view. Green pills can be used to add dimensions to the view, while blue pills can be used to add measures to the view.
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Someone please helppp
Answers
i dont know what the answer is but all i can say is to read it closely and try asking your teacher and\or parents to help you understand
Determine if the following statements are true or false.
If the null hypothesis that the means of four groups are all the same is rejected using ANOVA at a significance level a = 0.05, then...
a. The standardized variability between the groups is higher than the standardized variability within the groups.
b. The appropriate a* to be used in pairwise comparisons of group means is 0.05/4 = 0.0125 because there are four groups.
c. We can then conclude that all of the group means are different from one another.
Answers
a. The statement is true.
b. The statement is false.
c. The statement is false.
a. When the null hypothesis of equal means for four groups is rejected using ANOVA at a significance level of 0.05, it implies that there is sufficient evidence to suggest differences between the group means. ANOVA compares the variability between groups to the variability within groups. If the null hypothesis is rejected, it means that the standardized variability between the groups is higher than the standardized variability within the groups.
b. The appropriate significance level for pairwise comparisons of group means, also known as post hoc tests, is not simply divided by the number of groups. Dividing the significance level by the number of groups, as stated in option b, is not a valid approach. To appropriately account for multiple comparisons, adjustments like the Bonferroni correction, Tukey's HSD, or the Sidak correction are commonly used. These methods ensure that the overall Type I error rate is controlled.
c. Rejecting the null hypothesis using ANOVA only indicates that there are differences between at least two group means. It does not provide information about which specific group means differ from each other. To identify which group means are significantly different, additional post hoc tests or pairwise comparisons are required. These tests allow for a more detailed analysis of specific group differences and provide insights into which pairs of group means are statistically significant.
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Susan buys a new computer 1200 dollars.Sales tax is 11%. How much does Susan actually have to pay?
Answers
In short, Susan has to pay *$1,332*
The amount that Susan actually have to pay should be considered as the $1,332.
Calculation of the amount:
Since the purchase price of the computer is $1,200
And, the sales tax rate is 11%
So here the total amount be like
= $1,200 + 11% of $1,200
= $1,200 + $132
= $1,332
hence, The amount that Susan actually have to pay should be considered as the $1,332.
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When given a line such as y + 2 = 1/2 (x + 20), how do I find the slope intercept form?
Answers
Given the equation of the line:
\(y+2=\frac{1}{2}(x+20)\)The slope-intercept form is: y = m * x + b
Where (m) is the slope
So, we will solve the given equation for (y)
\(\begin{gathered} y+2=\frac{1}{2}\cdot x+\frac{1}{2}\cdot20 \\ y+2=\frac{1}{2}x+10 \\ y=\frac{1}{2}x+10-2 \\ \\ y=\frac{1}{2}x+8 \end{gathered}\)so, the answer will be the slope-intercept form:
\(y=\frac{1}{2}x+8\)Can y’all help me in the question I just asked please!
Answers
Answer: A
Step-by-step explanation: A shows a turkey sandwich with all the types of bread and a ham sandwich with all the types of bread.
The position of a particle moving along the x-axis varies with time according to x(t)=7.4t
2
−4.8t
3
m.
v(t)=14.8t−14.4t
2
a(t)=
(b) Find the velocity (in m/s ) and acceleration (in m/s
2
) at t=2.0 s. (Indicate the direction with the sign of your answer.)
v(2.0 s)=m/s
a(2.0 s)=
(c) Find the time t>0 (in s) at which the position is a maximum. I s (d) Find the time t>0 (in s) at which the velocity is zero. \& s (e) For time t>0, find the maximum position (in m ). (Indicate the direction with the sign of your answer.
Answers
Given,x(t) = 7.4t² − 4.8t³m
We need to find the following.(b) Velocity (in m/s) and acceleration (in m/s²) at t = 2 s and indicate the direction with the sign of your answer.
(c) Find the time t > 0 (in s) when the position is at a maximum.
(d) Find the time t > 0 (in s) when the velocity is zero.
(e) Find the maximum position (in m) for time t > 0 and indicate the direction with the sign of your answer.
To calculate velocity, we need to differentiate position with respect to time.
That is,
v(t) = x′(t)
= 14.8t - 14.4t²m/s
We can calculate acceleration by differentiating velocity with respect to time.
That is,
a(t) = v′(t) = 14.8 - 28.8t m/s²
Now, we can substitute t = 2 s to find velocity and acceleration.
v(2.0 s) = 14.8(2.0) - 14.4(2.0)² = 4.4 m/s (The direction is positive because velocity is positive at t = 2 s) a(2.0 s) = 14.8 - 28.8(2.0) = -42.8 m/s²
(The direction is negative because acceleration is negative at t = 2 s)
Now, we can find the time when the position is at a maximum.
To find the maximum, we need to differentiate position with respect to time and equate it to zero.
dx/dt = 14.8t - 14.4t²
= 0.
Simplifying, we get 14.8t(1 - t) = 0.
Hence,t = 0, 1 s.To determine the time when velocity is zero, we set the expression for velocity to zero and solve for t.
v(t) = 0 = 14.8t - 14.4t² => 14.8t = 14.4t² => t(14.4t - 14.8) = 0.
Hence,t = 0, 1.028 s (rounded to three decimal places).
To find the maximum position, we substitute t = 1 s into the expression for position.
x(1.0 s) = 7.4(1.0)² − 4.8(1.0)³
= 2.6 m.
(The direction is positive because the particle is moving in the positive direction).
Therefore, the answers are,v(2.0 s) = 4.4 m/s (positive direction)a(2.0 s) = -42.8 m/s² (negative direction)t = 1 st = 0, 1.028 sx = 2.6 m (positive direction).
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The student performed a different single transformation on PQR to create JKL. The coordinates of vertex K are (4,1). What could be the single transformation the student performed?
Answers
The single transformation which this student performed include the following: a reflection over the y-axis.
What is a reflection over the y-axis?In Geometry, a reflection over or across the y-axis or line x = 0 is represented and modeled by this transformation rule (x, y) → (-x, y).
By applying a reflection over the y-axis to the coordinate of the given triangle PQR, we have the following coordinates:
(x, y) → (-x, y).
Coordinate P = (-1, 1) → Coordinate J' = (-(-1), 1) = (1, 1).
Coordinate Q = (-4, 1) → Coordinate K' = (-(-4), 1) = (4, 1).
Coordinate R = (-4, 4) → Coordinate L' = (-(-4), 4) = (4, 4).
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Someone please help me thank you
Answers
Answer:
x = 8 and y = 10
Step-by-step explanation:
The given equations are :
2x -y = 6 ....(1)
-9x + 3y = -42 ....(2)
Multiply eqation (1) by 3.
6x - 3y = 18 .....(3)
Adding equation (2) and (3).
-9x + 3y + 6x - 3y = -42 +18
-3x = -24
x = 8
Put the value of x in equation (1).
2(8) -y = 6
16 - 6 = y
y = 10
Hence, the values of x and y are 8 and 10 respectively.
find the value of 3x=1/9
Answers
Find the period and the amplitude of the periodic function. I'm awful with graphs :(
Answers
A period is the difference in x over which a sine function returns to its equivalent state and the amplitude is A/5.
Amplitude:
The amplitude of a periodic variable is a measure of its change over a period of time, such as a temporal or spatial period. The amplitude of an aperiodic signal is its magnitude compared to a reference value. There are various definitions (see below) of amplitude, which is any function of the magnitude of the difference between the extreme values of a variable. In the previous text, the phase of a periodic function is called the amplitude.
X = A sin (ω[ t - K]) + b
A is the amplitude (or peak amplitude),
x is the oscillating variable,
ω is angular frequency,
t is time,
K and b are arbitrary constants representing time and displacement respectively.
According to the Question:
An equation does not have an amplitude. This "equation" represents the formula of a vibration, and was better written as:
X= A/5* sin(1000.t + 120)
These oscillations have a certain amplitude. X values can vary from minimum to maximum. Normally, the stop position of the oscillation is X=0. In this case, we can see that the maximum occurs when the sine is +1 and the minimum occurs when the sine is -1.
For theses cases X= A/5 respectively -A/5.
Therefore,
The amplitude is A/5.
For formulas of this type, the term in front of the sinus (or cosine) is equal to the amplitude.
Complete question:
Can I find the amplitude of this equation? A/5 *
need help, I will be gaveing out points for helpers
Answers
Answer:
The 3rd answer
Step-by-step explanation:the
180-30\2
....
=75
30+2*75=
...
180
Answer:
30 + 2x = 180
Step-by-step explanation:
This is becuase we know this triangle is an isosceles triangle. (The two markings on the sides prove that.) An isosceles triangle is when two sides (so naturally also two angles) are the same. This means the other angle is x. We know that if we add all of the angles, we'll get 180. So, 30 + x + x = 180 or "30 + 2x = 180".
Also, x = 75.
Here:
30 + 2x = 180
30 - 30 + 2x = 180 - 30
2x = 150
2x / 2 = 150 / 2
x = 75
HOPE THIS HELPED!! HAVE AN AWESOME DAY!
Is (-10,10) a solution for the inequality y≤x+7
Answers
Answer: no
Step-by-step explanation: if we'd substitute the numbers, it'd look like this 10≤-10+7 which isn't true as "≤" this symbol means more than or equals to but -10 plus 7 is equal to 3 so it doesn't fit the inequality
The ratio of a quarterback's completed passes to attempted passes is 7 to 8. If he attempted 24 passes, how many did he complete
Answers
7 : 8
24/8 = 3
7*3 = 21 completed :)
Assume that grass has 1500 calories of energy. How many calories are transferred to the
flea beetle? How many calories are transferred to the sparrow?
Answers
Answer:
Calories are transferred to flea beetle = 150 Calories
Calories are transferred to the sparrow = 15 Calories
Step-by-step explanation:
Given:
Calories in grass = 1,500 Calories
Find:
Calories are transferred to flea beetle
Calories are transferred to the sparrow
Computation:
According to food chain level only 10 % of Calorie transferred to the next level.
So,
Calories are transferred to flea beetle = 10% (Calories in grass)
Calories are transferred to flea beetle = 10% (1,500)
Calories are transferred to flea beetle = 150 Calories
Calories are transferred to the sparrow = 10% (Calories are transferred to flea beetle)
Calories are transferred to the sparrow = 10% (150)
Calories are transferred to the sparrow = 15 Calories
The following data shows the daily production of cell phones. 7, 10, 12, 15, 18, 19, 20. Calculate the Mean, Variance and Standard Deviation of production of cell phones. Show your work in the space provided for: a) Mean b) Variance per Day c) Standard Deviation 16 SB
Answers
The following data shows the daily production of cell phones. 7, 10, 12, 15, 18, 19, 20. Mean The formula for finding the mean is: mean = (sum of observations) / (number of observations).
Therefore, the mean for the daily production of cell phones is: Mean = (7+10+12+15+18+19+20) / 7
= 101 / 7
Mean = 14.43
Variance The formula for finding the variance is: Variance = (sum of the squares of the deviations) / (number of observations - 1) Where the deviation of each observation from the mean is: deviation = observation - mean First, calculate the deviation for each observation:7 - 14.43
= -7.4310 - 14.43
= -4.4312 - 14.43
= -2.4315 - 14.43
= 0.5718 - 14.43
= 3.5719 - 14.43
= 4.5720 - 14.43
= 5.57
Now, square each of these deviations: 56.25, 19.62, 5.91, 0.33, 12.75, 20.9, 30.96 The sum of these squares of deviations is: 56.25 + 19.62 + 5.91 + 0.33 + 12.75 + 20.9 + 30.96
= 147.72
Therefore, the variance for the daily production of cell phones is: Variance = 147.72 / (7-1) = 24.62 Standard deviation ) Mean = 14.43b) Variance per Day = 24.62c) Standard Deviation = 4.96
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the drying times for a certain type of cement are normally distributed with a standard deviation of 68 minutes. a researcher wishes to estimate the mean drying time for this type of cement. find the sample size needed to assure with 99% confidence that the sample mean will not differ from the population mean by more than a margin of error of 7 minutes
Answers
By increasing the sample size to 248, the researcher can be more confident in their estimate of the mean drying time for the type of cement being studied.
To determine the sample size required to estimate the mean drying time for a certain type of cement, the following formula can be used:
\(n = ((Zα/2 \times σ) / E)^2\) where: Zα/2 is the critical value of the standard normal distribution for the desired confidence level (99% in this case), which is 2.576 σ is the standard deviation of the population (68 minutes)E is the maximum margin of error that can be tolerated (7 minutes).
Substituting these values into the formula, we get:
\(n = ((2.576 \times 68) / 7)^2\) = 247.36. Rounding up to the nearest whole number, the sample size required is 248.
This means that if the researcher takes a random sample of 248 drying times and calculates the mean drying time, with 99% confidence we can say that the true population mean drying time is within plus or minus 7 minutes of the sample mean.
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In an arithmetic sequence, the first term, a1, is equal to 10, and the fourth term, a4,
is equal to 19. Which number represents the common difference of the arithmetic
sequence?
d=3
d=5
d=4
d=6
Answers
The common difference of the arithmetic sequence is d = 3.
What is an Arithmetic sequence?
An arithmetic progression, also referred to as an arithmetic sequence, is a set of numbers where each term following the first is derived by adding a fixed constant number to the term before it.
To solve this problem, we can use the formula for the nth term of an arithmetic sequence. The formula is as follows:
an = a1 + (n - 1)d
Where an is the sequence's nth term, a1 is the first term, d is a common difference, and n is the number of terms we want to discover:
We know that a1 = 10 and a4 = 19. By entering these numbers into the formula, we obtain:
a4 = a1 + (4 - 1)d
19 = 10 + 3d
In order to find d, we can divide by 3 after subtracting 10 from both sides:
9 = 3d
d = 3
Therefore, the common difference of the arithmetic sequence is d = 3.
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the ratio of wins to games played fir certain siftball team.is 2 to 3 I the team played 33 games how many game did the team win PLS HELP
Answers
Answer:22
Step-by-step explanation:
tell me if you want the explanation in the comments
Answer:
22
Step-by-step explanation:
If the total is 33 games ,33 divided in 3 parts,each part is 11
Of the 3 parts the team won 2 parts
so 2x11 = 22
PLZ ANSWER ONLY IF YOU KNOW!!! BRAILIEST 5 STARS AND A THANKS!!!
When Samantha uses her calling card overseas, the cost of a phone call is $0.75 for the first three minutes and $0.12 for each additional minute, thereafter. Samantha plans to spend at most $3.60 to make a call. Find the greatest possible length of talk time. Round your answer to the nearest whole number.
Answers
x = 26.75 min
26 minutes, would = 3.51. if you add .12 to that it is 3.63.
so the most that she could talk would be 26 minutes.
Find the percent of each number a. 50% of 46 b. 70% of 110
Answers
Select the correct answer.
Triangle XYZ has an altitude of h. Jayden proves the area of AXYZ using trigonometry. His work is shown.
Z
h
b
a
х
у
The area of AXYZ is žyh
by the definition of the area of a triangle. Using the sine ratio, sin(x) = . Also, asin(x) = h is true by the
multiplication property of equality. So, by the substitution property of equality, the area of AXYZ is 2xysin(x).
Where did Jayden make his first error in the proof?
Answers
The first error Jayden made in teh proof is: D. the sine ratio, sin(X) = h/x is incorrect, its should be sin(Z) = h/x.
What is the Sine Ratio?Whn solving a right triangle, the sine ratio can be used which is expressed as, sin ∅ = opposite side/hypotenuse, given that ∅ is the refrence angle.
In the proof of Jayden, the area of the triangle is correct, which is 1/2(base × height).
However, the sine ratio is wrong.
Therefore, the first error Jayden made in teh proof is: D. the sine ratio, sin(X) = h/x is incorrect, its should be sin(Z) = h/x.
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Answer:
Step-by-step explanation:
The first error Jayden made in teh proof is: D. the sine ratio, sin(X) = h/x is incorrect, its should be sin(Z) = h/x.
What is the Sine Ratio?
Whn solving a right triangle, the sine ratio can be used which is expressed as, sin ∅ = opposite side/hypotenuse, given that ∅ is the refrence angle.
In the proof of Jayden, the area of the triangle is correct, which is 1/2(base × height).
However, the sine ratio is wrong.
Therefore, the first error Jayden made in teh proof is: D. the sine ratio, sin(X) = h/x is incorrect, its should be sin(Z) = h/x.
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Thirteen years ago, you deposited $2400 into a superannuation
fund. Eight years ago, you added an additional $1000 to this
account. You earned 8%, compounded annually, for the first five
years, and 5.
Answers
The total amount money after thirteen years of savings will be $5030.63
To calculate the amount of money in the account today, we need to calculate the future value of each contribution separately and then add them together.
Let's start by calculating the future value of the initial deposit of $2400 over the first five years at an interest rate of 8% compounded annually.
Using the formula for compound interest:
Future Value = \(Principal\) * \((1 + Interest Rate)^{Time}\)
Future Value = $2400 * (1 + 0.08)⁽⁵⁾
Future Value = $2400 * (1.08)⁵
Future Value = $2400 * 1.46933
Future Value = $3526.40
So, after five years, the initial deposit will grow to $3526.40.
Now, let's calculate the future value of the additional deposit of $1000 over the last eight years at an interest rate of 5.5% compounded annually.
Future Value = $1000 * (1 + 0.055)⁸
Future Value = $1000 * (1.055)⁸
Future Value = $1000 * 1.50423
Future Value = $1504.23
So, after eight years, the additional deposit will grow to $1504.23.
Now, let's add the two amounts together to find the total amount in the account today:
Total Amount = $3526.40 + $1504.23
Total Amount = $5030.63
So, the total amount money after thirteen years of saving will be $5030.63
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Complete question:
Thirteen years ago, you deposited $2400 into a superannuation fund. Eight years ago, you added an additional $1000 to this account. You earned 8%, compounded annually, for the first five years, and 5.5%, compounded annually, for the last eight years. How much money do you have in your account today?
1. Consider a damped spring-mass system with m = 1kg, = 2
kg/s^2 and c = 3 kg/s. Find the general solution. And solve the
initial value problem if y(0) = 1 and y′(0) = 0.
Answers
The general solution of the damped spring-mass system with the given parameters is y(t) = e^(-t/2) [c1cos((√7/2)t) + c2sin((√7/2)t)]. By applying the initial conditions y(0) = 1 and y'(0) = 0, the specific solution can be obtained as y(t) = (2/7)e^(-t/2)cos((√7/2)t) + (3/7)e^(-t/2)sin((√7/2)t).
The equation for the damped spring-mass system can be expressed as my'' + cy' + ky = 0, where m is the mass, c is the damping coefficient, and k is the spring constant. In this case, m = 1 kg, c = 3 kg/s, and k = 2 kg/\(s^2\).
To find the general solution, we assume a solution of the form y(t) = e^(rt). By substituting this into the equation and solving for r, we get \(r^2\) + 3r + 2 = 0. Solving this quadratic equation gives us the roots r1 = -2 and r2 = -1.
The general solution is then given by y(t) = c1e^(-2t) + c2e^(-t). However, since we have a damped system, the general solution can be rewritten as y(t) = e^(-t/2) [c1cos((√7/2)t) + c2sin((√7/2)t)], where √7/2 = √(3/4).
By applying the initial conditions y(0) = 1 and y'(0) = 0, we can solve for the coefficients c1 and c2. The specific solution is obtained as y(t) = (2/7)e^(-t/2)cos((√7/2)t) + (3/7)e^(-t/2)sin((√7/2)t). This satisfies the given initial value problem.
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A gardener has two different strengths of weedkiller: a 6% solution and a 15% solution, some of each solution needs to be mixed together to make 30 litres of a 10% solution. How much of each kind of solution is required?
Answers
Answer:
Approximately 16.67 liters concentration of the 6% solution and approximately 13.33 liters of the 15% solution are required to make 30 liters of a 10% solution.
Step-by-step explanation:
Let's denote the amount of the 6% solution as x liters and the amount of the 15% solution as y liters. We need to find the values of x and y that satisfy the conditions.
Since we want to make 30 liters of a 10% solution, we can set up the following equations:
Equation 1: x + y = 30 (total volume equation)
Equation 2: (0.06x + 0.15y) / 30 = 0.10 (concentration equation)
From Equation 1, we have x = 30 - y. Substituting this into Equation 2, we get:
(0.06(30 - y) + 0.15y) / 30 = 0.10
Simplifying the equation gives:
(1.8 - 0.06y + 0.15y) / 30 = 0.10
1.8 + 0.09y = 3
0.09y = 1.2
y ≈ 13.33
Substituting y back into Equation 1, we find:
x + 13.33 = 30
x ≈ 16.67
Therefore, approximately 16.67 liters of the 6% solution and approximately 13.33 liters of the 15% solution are required to make 30 liters of a 10% solution.
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Evaluate each expression if x=6. the expressions are: 4(x-5). and 2x divided by 6.
PLEASE HELP ME THIS IS DUE TONIGHT
Answers
Answer:
4(x-5)=4(6-5)=4
2x/6=(2×6)/6=2
Andrea was traveling down a road at 45 mph when she was forced to immediately apply her brakes in order to come to a complete stop. Her car left two skid marks that averaged 60 feet in length with a difference of 6 feet between them. Her brakes were operating at 90% efficiency at the time of the incident. What was the possible drag factor of this road surface? What were the lengths of each skid mark?
Answers
The drag factor of the road surface was 0.68.
The lengths of the skid marks were approximately 52.1 feet and 49.1 feet, respectively.
What was the possible drag factor of this road surface?To solve this problem, we can use the following formula:
d = (v^2 / 2g) * f
Where:
d = distance (in feet) traveled during skidv = initial velocity (in feet per second)g = acceleration due to gravity (32.2 ft/s^2)f = drag factor of the road surfaceFirst, we need to convert Andrea's speed from mph to feet per second:
45 mph = 66 feet per second
Next, we can use the average length of the skid marks to find the distance traveled during skid:
d = (60 feet + 54 feet) / 2
d = 57 feet
We also know that the efficiency of Andrea's brakes was 90%, which means that only 90% of the force applied to the brakes was actually used to slow down the car.
Therefore, we can adjust the initial velocity to take into account this reduction in braking power:
adjusted velocity = 66 feet per second * 0.9 = 59.4 feet per second
Substituting the values into the formula and solving for the drag factor:
57 feet = (59.4^2 / (2 * 32.2)) * f
f = 0.68
To find the lengths of each skid mark, we can use the formula:
d = (v^2 / 2g) * f
For the first skid mark:
60 feet = (v^2 / (2 * 32.2)) * 0.68
v = 52.1 feet per second
And for the second skid mark:
54 feet = (v^2 / (2 * 32.2)) * 0.68
v = 49.1 feet per second
Now we can use these velocities to find the lengths of each skid mark:
Length of first skid mark = 52.1 feet per second * 1 second
Length of first skid mark = 52.1 feet
Length of second skid mark = 49.1 feet per second * 1 second
Length of second skid mark = 49.1 feet
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Answer: UR QUESTION HERE
Step-by-step explanation:
How would you graph this correctly onto a graph?
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Answer:
Here is how you graph your equations correctly :D
Step-by-step explanation:
Graph y > x − 2.
Use the slope-intercept form to find the slope and y-intercept.
Slope: 1
y-intercept: (0, -2)
Graph a dashed line, then shade the area above the boundary line since y is greater than x − 2 .
y > x - 2
Graphy < −4x + 2.
Use the slope-intercept form to find the slope and y-intercept.
Slope: -4
y-intercept: (0, 2)
Graph a dashed line, then shade the area below the boundary line since y is less than − 4 x + 2 .
y < -4x + 2
Plot each graph on the same coordinate system.
y > x - 2
Y < -4x + 2
I hope this helps.