what significant event occurred about 400,000 years after the big bang? a. the universe became transparent to radiation. b. the temperature of the radiation decreased to -600 k. c. all of the present galaxies in the universe were instantly formed.

Answer:

Explanation:

The density of gold is 19.3 g/cm³. Thus, you can determine the density of the unknown cube by doing the following. Get a measuring cylinder (marked in cm³) that contains a certain volume of water (preferably above average but not close to been filled up). Get a weighing balance (that can read in grams) also.

Measure the mass of the unknown stone (using the weighing balance) and record. Take the initial volume of the water in the measuring cylinder and record (in cm³) and then drop the unknown stone inside the measuring cylinder gently (avoid splashes). Record the final volume of the cylinder after the unknown stone was dropped.

Then calculate the density of the stone by using the formula; mass ÷ change in volume

The change in volume can be determined by; Final volume - initial volume

If the answer obtained from the calculation (of the density of the stone) is not around 19.3 g/cm³ (say 19.3 ± 0.2), then the stone is not gold but if it is around 19.3 g/cm³, then the stone is gold.

The Lewis structure for the sulfite ion (SO32-) can be completed as follows:

            O

          ╱  ╲

    O = S = O

          ╲  ╱

            O^-

the central sulfur atom (S) is surrounded by three oxygen atoms (O). The sulfur atom has six valence electrons, and each oxygen atom contributes six valence electrons. Adding up the total valence electrons gives us 6 (sulfur) + 3 * 6 (oxygen) + 2 (negative charge) = 26 valence electrons. Starting with the skeleton structure, we distribute the remaining electrons to fulfill the octet rule for each atom. We can place two lone pairs of electrons on each oxygen atom and two lone pairs on the sulfur atom. After distributing all the electrons, we check if each atom has a complete octet.

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Taking into account the definition of Scientific notation, the correct representation of 5,970,000,000,000,000,000,000,000 kg in scientific notation is 5.97×10²⁴ kg.

Scientific notation is a quick way to represent a number using powers of base 10. This notation is used to be able to express very large or very small numbers very easily.

The numbers are written as a product:

where:

In this case, to write the number 5,970,000,000,000,000,000,000,000 kg in scientific notation, the following steps are performed:

So, the correct representation of 5,970,000,000,000,000,000,000,000 kg in scientific notation is 5.97×10²⁴ kg.

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The answer for Eating food from a uranium glass plate is safer is Choice C which is food is irradiated / not contaminated.

It is safer to eat food from a uranium glass plate because the uranium added to the glass will always be in the oxidized form used to color it. The uranium added to the glass will also be not soluble thus it will not be radioactive.

Thus, the reason for eating food safely from the uranium glass plate is it will not be contaminated

The other two options(alpha cannot penetrate skin or body and contains a low percentage of uranium) will be wrong because the plate will be completely non-radioactive.

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Beta radiations consist of positrons or electrons. These radiations have higher energy than alpha particles but lower energy than gamma particles. A piece of paper will not be enough to stop a beta particle. It can be stopped by a few inches of glass or thin aluminum sheets.

Thus the beta radiation requires glass to be stopped.

Answer:

(9.4 times / 8.5 minutes) x (1 minute / 60 seconds)

= (9.4) / (8.5 x 60) times/second

= 0.013 Hz .

Answer:

the ansewer is C

Explanation:

Answer:

Centripetal force = 13140 Newton.

Explanation:

Given the following data;

Mass = 1.46 E3 kg = 1.46*10³ = 1460 kg

Velocity = 15m/s

Radius, r = 25m

To find the centripetal force, we would use the following formula:

Centripetal force = mv²/r

Substituting into the equation, we have;

Centripetal force = (1460*15²)/25

Centripetal force = (1460 * 225)/25

Centripetal force = 328500/25

Centripetal force = 13140 Newton.

Given,

The mass of the object, m=2.1 kg

The speed of the object, v=25 m/s

Kinetic energy is the energy that an object possesses due to its motion. And potential energy is the energy that an object possesses due to its position.

The gravitational potential energy depends on the height of the object. As the change in the height of the object is not mentioned in the question, let us assume that there is no change in the potential energy.

The velocity of the object, however, changes. Thus the energy possessed by the object is the kinetic energy.

And the kinetic is given by

On substituting the known values,

Thus the kinetic energy of the ball is 656.25 J

1488 N/m. The force necessary to stretch or compress a spring by a specific quantity is described by the force constant of the spring, which serves as a gauge of its stiffness. When a fish is weighed using a spring scale,

the force of the fish is transmitted to the spring, causing it to extend. The mass of the fish may be calculated by measuring the amount of stretch. We may utilize Hooke's law, which stipulates that the force a spring exerts is directly proportional to the degree of stretch or compression of the spring, to get the force constant of the spring in the scale. We may construct the equation F = -kx in this situation, where F the force applied by the fish, where x is the stretch (7.50 cm), and k is the spring's force constant. This equation may be changed to solve for k: k = -F/x. We calculate k as \(k = -(11.7 kg x 9.8 m/s2) / (0.075 m) = -1488 N/m\)by plugging in the supplied variables. As a result, the spring's force constant on the scale is 1488 N/m.

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Answer: the poles

Explanation:

Answer:

Total momentum of both is 16250 kgm/s

Answer:

The answer is 46.0089 N of weight

Explanation:

The answer is in the question

F=mg

reverse the question, mg=F

Plug in the values of mass (4.69) and gravity (9.81)

4.69(9.81)=F

F = 46.0089 (or D)

1. R

2. P and Q

3. P and Q

4. Q

5. 2 seconds

Wait have a diagram to explain better. It's attached above.

Explanation:

I think it is the third image as marked in the diagram I kept above because as we know first class levers have the fulcrum between the force and the load

Moving from the element with atomic number 10 to atomic number 11 on the periodic table changes observed are :

Reactivity increases,

Sodium has more shell,

Valence electrons in sodium are farther from the nucleus,

Atomic number 11 does not have a full electron shell

In increasing order of atomic number, the elements are listed. The amount of protons in an atom's nucleus is indicated by its atomic number. An element's identity is determined by its proton count. The number of protons determines an element's identity.

The indirect relativistic effect amplifies the decreases in the binding energies of the valence d and f electrons as they move down the periodic table. As a result, the d electrons in the heavier coinage metals become more chemically active, leading to higher oxidation states in these elements.

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The answer to your question is that the image will be located 4 mm to the left of the lens. To find the location of the image formed by a diverging lens, we can use the thin lens equation

where f is the focal length of the lens, do is the distance of the object from the lens, and di is the distance of the image from the lens.

Substituting the given values, we get:

1/3 = 1/12 - 1/dₙ

Solving for di, we get:

dₙ = -4 mm

The negative sign indicates that the image is virtual and upright, meaning it appears on the same side of the lens as the object. Therefore, the image is located 4 mm to the left of the lens.
Hi, I'd be happy to help you with your question. The main answer is that the image is located at a distance of 4 mm on the left side of the diverging lens. Here's the explanation:

Step 1: Identify the focal length and object distance. In this case, the focal length (f) is -3 mm (since it's a diverging lens) and the object distance (d_o) is -12 mm (since it's on the left side of the lens).

Step 2: Use the lens formula to find the image distance (d_i). The lens formula is given by 1/f = 1/dₙ + 1/dₙ.

Step 3: Substitute the given values into the lens formula: 1/(-3) = 1/(-12) + 1/dₙ.

Step 4: Solve the equation for d_i. In this case, d_i = -4 mm.

So, the image is located at a distance of 4 mm on the left side of the diverging lens.

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Answer:

A generator is a device that converts mechanical energy into electrical energy by rotating a coil of wire in a magnetic field.

Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

The voltage provided by the power supply = 20 V

The Voltage across resistors in series in a circuit is equal to the sum of the voltage drops across each resistor.

Therefore for two resistors in series the total voltage provided by the power supply is equivalent to the summation of the voltage drops acroos each resistor ( i.e 10 V + 10 V = 20 V )

Hence we can conclude that the voltage provided by the power supply is 20 V

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The frequency of the waves is 0.48Hz and  their speed is 4.2m/s.

Define frequency.

The number of waves passing a fixed place in a unit of time is known as frequency.

Given ,

Time ,t is 2.1s

Frequency, F =1/t

                   F =1/2.1

                  F =0.48Hz

A periodic wave's wavelength, or the distance over which the wave's shape repeats, is its spatial period. It is the separation between neighboring wave points that correspond to the same phase, such as two adjacent crests, troughs, or zero crossings. It is a property of both traveling waves and standing waves as well as other spatial wave patterns. The spatial frequency is the wavelength's reciprocal. The Greek letter lambda ( λ) is frequently used to denote wavelength.

Speed ,v = λ / T.

            v = 8.8/2.1

            v  =4.2m/s

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The ball reaches a maximum height of approximately 42.83 ft.  the ball lands at a horizontal distance of approximately 81.36 ft. he average value of f(x)= x³8 +9x on the interval is 10.5.

To determine the maximum height and horizontal distance traveled by the ball shot at an angle of 45 degrees with an initial velocity of 41 ft/sec and neglecting air resistance, we can use basic kinematic equations.

Maximum Height:

The maximum height reached by the ball can be calculated using the equation for vertical displacement:

y_max = (v₀² * sin²θ) / (2g),

where v₀ is the initial velocity, θ is the launch angle (45 degrees), and g is the acceleration due to gravity (32 ft/s²).

Plugging in the values, we get:

y_max = (41² * sin²45°) / (2 * 32) = 42.83 ft.

Therefore, the ball reaches a maximum height of approximately 42.83 ft.

Horizontal Distance:

The horizontal distance traveled by the ball can be calculated using the equation for horizontal displacement:

x = v₀ * cosθ * t,

where x is the horizontal distance and t is the time of flight.

Since the ball goes up and then comes back down, the total time of flight can be calculated as:

t_total = 2 * (v₀ * sinθ) / g.

Plugging in the values, we get:

t_total = 2 * (41 * sin45°) / 32 ≈ 2.88 s.

Using this total time, we can find the horizontal distance:

x = 41 * cos45° * 2.88 ≈ 81.36 ft.

Therefore, the ball lands at a horizontal distance of approximately 81.36 ft.

Moving on to the second question:

To find the position of a particle at time t = 14, given its acceleration, initial position, and initial velocity, we can use the equations of motion.

The position function s(t) can be obtained by integrating the acceleration function twice with respect to time. Since the given acceleration is a linear function, we have:

s(t) = (1/6)at³ + (1/2)v₀t² + s₀,

where a is the acceleration, v₀ is the initial velocity, and s₀ is the initial position.

Plugging in the given values, we get:

s(14) = (1/6)(24)(14)³ + (1/2)(15)(14)² + 12 ≈ 546.67.

Therefore, the position of the particle at time t = 14 is approximately 546.67.

Lastly, for the average value of f(x) = x³ + 9x on the interval [1, 2], we can use the formula for the average value of a function on an interval:

Average value = (1 / (b - a)) * ∫[a, b] f(x) dx,

where [a, b] represents the interval.

Plugging in the values, we have:

Average value = (1 / (2 - 1)) * ∫[1, 2] (x³ + 9x) dx.

Evaluating the integral, we get:

Average value = (1 / 1) * [(1/4)x⁴ + (9/2)x²] evaluated from 1 to 2,

Average value = (1/4)(2⁴ + 9(2²)) - (1/4)(1⁴ + 9(1²)),

Average value = (1/4)(16 + 36) - (1/4)(1 + 9),

Average value = (1/4)(52) - (1/4)(10),

Average value = 13 - 2.5,

Average value ≈ 10.5

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The radio wave with a frequency of 1000 kHz has a wavelength of 300 meters and can penetrate the ocean to a greater depth compared to the radio wave with a frequency of 80 MHz and a wavelength of 3.75 meters. In non-coherent AM detection, both too low and too high RC time constants can lead to distortions and inaccuracies in the demodulated message.

To find the wavelength of a radio wave, we can use the formula: wavelength (λ) = speed of light (c) / frequency (f). The speed of light is approximately 3 x 10^8 meters per second.

For the first radio wave with a frequency of 1000 kHz (1000 kilohertz), we convert the frequency to Hz by multiplying by 10^3: 1000 kHz = 1000 x 10^3 Hz. Using the formula, we can calculate its wavelength:

λ = (3 x 10^8 m/s) / (1000 x 10^3 Hz) = 300 meters

For the second radio wave with a frequency of 80 MHz (80 megahertz), we convert the frequency to Hz by multiplying by 10^6: 80 MHz = 80 x 10^6 Hz. Calculating the wavelength:

λ = (3 x 10^8 m/s) / (80 x 10^6 Hz) = 3.75 meters

Now, let's discuss the effect of wavelength on how deep each radio wave can penetrate the ocean. Generally, radio waves with longer wavelengths can penetrate deeper into the ocean than those with shorter wavelengths. This is because water molecules absorb and scatter electromagnetic waves, causing attenuation or loss of signal strength.

The first radio wave with a wavelength of 300 meters can penetrate the ocean to a greater depth compared to the second radio wave with a wavelength of 3.75 meters. The longer wavelength allows it to travel further through the water before being significantly attenuated.

In Non-Coherent AM detection, the RC time constant plays a crucial role in the demodulation process. When the RC time is too low (short time constant), the received message will have distorted and noisy edges, resulting in poor signal quality. This distortion occurs because the low RC time constant causes rapid changes in the voltage across the capacitor, leading to inaccurate detection of the message.

On the other hand, when the RC time is too high (long time constant), the received message will exhibit a slow rise and fall of amplitude, resulting in a sluggish response. The high RC time constant causes a slower discharge of the capacitor, leading to a delayed detection of the message.

Therefore, an optimal RC time constant should be chosen to ensure accurate demodulation and faithful reproduction of the original message signal.

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Answer:

rolling friction is the weakest

Explanation:

rolling friction, which is weakest in solid surface

Answer:

0.81 m/s^2

Explanation:

A child rides a bicycle from rest

The child reaches a velocity of 3.8m/s

The time is 4.7 secs

Therefore the acceleration can be calculated as follows

v= u + at

3.8= 0 + a(4.7)

3.8= 0 + 4.7a

3.8-0= 4.7a

3.8= 4.7a

a= 3.8/4.7

= 0.81 m/s^2

Hence the acceleration is 0.81 m/s^2

When an object is projected at angle, it will have some horizontal and vertical velocities. there no horizontal motion, projectile's horizontal component stays the same.

To determine the drag on the car when it is driven through still air at 55 mph, we need to use the formula: drag = (1/2) × density of air × velocity² × drag coefficient × cross-sectional area of the car. Assuming standard conditions, the density of air is 1.225 kg/m³ or 0.0023769 lb/ft³. Converting the velocity to ft/s, we get 80.67 ft/s. Plugging in the given values, we get:
drag = (1/2) × 0.0023769 × 80.67² × 0.21 × 30
drag = 215.3 lb
Therefore, the drag on the car when driven through still air at 55 mph is 215.3 lb. To determine the drag on the car when driven into a 25 mph wind, we need to add the velocity of the wind to the velocity of the car. Therefore, the total velocity is 80.67 + 25 = 105.67 ft/s. Using the same formula and plugging in the new velocity, we get:
drag = (1/2) × 0.0023769 × 105.67² × 0.21 × 30
drag = 337.2 lb
Therefore, the drag on the car when driven into a 25 mph wind is 337.2 lb.

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The drag on a car is the resistance that it experiences as it moves through the air. The drag force is proportional to the air density, the velocity of the car, the drag coefficient, and the cross-sectional area of the car. The formula to calculate drag force is:

Drag force = 0.5 x air density x velocity^2 x drag coefficient x area
In this case, the drag coefficient is predicted to be 0.21, and the cross-sectional area of the car is 30 ft2. We are given the velocity of the car, which is 55 mph.
First, we need to convert the velocity from miles per hour (mph) to feet per second (fps). We know that 1 mph is equal to 1.47 fps. Therefore:
55 mph x 1.47 fps/mph = 80.85 fps
The air density at sea level is approximately 0.00237 slugs/ft3. Therefore, we can calculate the drag on the car as follows:
Drag force = 0.5 x 0.00237 slug/ft3 x (80.85 fps)^2 x 0.21 x 30 ft2
Drag force = 131.28 pounds of force (lbf)
This means that when the car is driven through still air at 55 mph, it experiences a drag force of 131.28 lbf.
Now, let's consider the case where the car is driven into a 25 mph headwind. In this case, the velocity of the car relative to the ground is:
55 mph - 25 mph = 30 mph
We need to convert this velocity to fps:
30 mph x 1.47 fps/mph = 44.1 fps
Using the same formula as before, we can calculate the drag on the car:
Drag force = 0.5 x 0.00237 slug/ft3 x (44.1 fps)^2 x 0.21 x 30 ft2
Drag force = 48.77 lbf
This means that when the car is driven into a 25 mph headwind, it experiences a drag force of 48.77 lbf.

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Answer:

what?

Explanation:

Answer:

600m/s²

Explanation:

Given parameters:

Mass of car  = 600kg

Impulse  = 18000kgm/s

Time  = 0.05s

Unknown:

Acceleration  = ?

Solution:

To solve this problem, let us find the force that cause the impact first;

          Impulse  = Force x time

          Force  = \(\frac{impulse}{time}\)    = \(\frac{18000}{0.05}\)    = 360000N

So;

        Force   = mass x acceleration

         Acceleration  = \(\frac{Force }{mass}\)    = \(\frac{360000}{600}\)    

         Acceleration  = 600m/s²

The ball is worth two points when it is shot from inside the 3-point arc.

The 3-point arc is a circular arc painted on the basketball court in which a player can take a shot and score three points if the ball goes through the hoop without touching the rim. The 3-point arc is 23 feet 9 inches away from the basket, and it encloses an area known as the 3-point line. Any shot that is taken from beyond the 3-point line and goes through the hoop without touching the rim scores three points.

Conversely, if a shot is taken from inside the 3-point line and goes through the hoop without touching the rim, it scores two points. Therefore, the answer to the question is that a ball is worth two points when it is shot from inside the 3-point arc.

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The order of events when a neuron fires an action potential is as follows:

1. Depolarization: The neuron's membrane potential is changed from its resting potential to a more positive voltage.

2. Threshold: The membrane potential reaches a critical level, known as the threshold potential, which triggers the action potential.

3. Action potential: An all-or-none electrical impulse is generated and propagates along the axon.

4. Repolarization: The membrane potential returns to its resting potential.

Answer:

i can

Explanation:

i know what's the answer