An old fashioned computer monitor accelerates electrons and directs them to the screen in order to create an image.
If the accelerating plates are 0.958 cmcm apart, and have a potential difference of 2.60×104 VV , what is the magnitude of the uniform electric field between them?

Answer:

The value is  \(a = 20.4 \%\)  

Explanation:

From the question we are told that

    The  acceleration due to gravity of the planet is  \(a = 5.40 \ m/s^ 2\)

     The  percentage  volume of the apparatus submerged in the ocean on earth is \(k = 25.0 \%\)

  Generally the buoyant force acting on the apparatus  is equal to the weight of the apparatus

i.e

     \(\rho_s * V_s * g = m * g\)

Hence the mass of the apparatus  is mathematically represented as

           \(m_s = \rho_s * V_s\)

Here  \(\rho_s\) is the  density of the sea water with a value of  \(\rho_s = 1030 \ kg/m^3\)

        \(V_s\) is the volume of the apparatus submerged

So  

          \(m_s = 1030 * 0.25 V\)  

Here V  is the total  volume of the apparatus

=>        \(m_s = 257.5 V \ kg\)  

  Generally at the new planet the mass of the apparatus is mathematically represented as

      \(m_c = \rho_c * V_c\)

Here  \(\rho_c\) is the  density of the glycerin with a value of  \(\rho_c = 1260 \ kg/m^3\)

Gnerally  \(m_s = m_c\)  

So

         \(257.5 V = 1260 * V_c\)

=>      \(V_c = \frac{257.5V }{ 1260 }\)  

=>      \(V_c = 0.204 \ V\)

Hence the percentage volume of the apparatus which is submerged in glycerin at the new planet is  

           \(a = 0.204 * 100 = 20.4 \%\)  

Answer:

33.33%

Explanation:

take efficiency =power output/power input multiply by 100%

The magnitude of the linear acceleration of the falling bucket is 9.8 m/s^2. The magnitude of the linear acceleration of the falling bucket is equal to the acceleration due to gravity, which is 9.8 m/s^2.

A bucket with a mass of a kg is attached to a cylindrical, massive pulley with a radius of b m. The bucket starts from rest and falls for c s into a well. The tension in the rope is d N. To find the magnitude of the linear acceleration of the falling bucket, we can use the following equation:

F_net = ma

Where F_net is the net force acting on the bucket, m is the mass of the bucket, and a is the acceleration of the bucket.

We can find the net force acting on the bucket using the tension in the rope: F_net = T - mg, where T is the tension in the rope, and mg is the weight of the bucket. Since the bucket is falling, we know that a = -g (where g is the acceleration due to gravity, which is a constant -9.8 m/s^2). So we can set up the following equation: T - mg = maT - mg = m(-g)T = mg - mgT = m(-g)T = -mg

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The negative sign of the force implies that it is in the opposite direction of other force to be in equilibrium.

The force of attraction or repulsion occurring between two charged particles is known as electrostatic force. It is also known as Coulomb's force.

Here,

The three point charges are placed rectilinearly at equal distances of 20m apart. Thus they can be shown as an equilateral triangle of side 20 mm and the three point charges are placed at its corners.

So, when the electrostatic forces between the point charges are calculated, the force exerted by A on B is -135 N.

The negative sign of the force implies that it is opposite to the direction of the rest of force. That means the force exerted by A on B  and the remaining resultant forces must be equal and opposite in direction. This is to attain equilibrium of forces.

Hence,

The negative sign of the force implies that it is in the opposite direction of other force to be in equilibrium.

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According to the given weber question , the answer is 1 weber equals: 1 T/m2.

Weber is a sociological term that refers to the concept proposed by Max Weber, a German sociologist. The notion is concerned with the organisation of social action and how that structure impacts our perception of the world. Weber believed that social activity should be viewed as a form of communication between individuals, rather than simply as an act of compliance or obedience. Weber's concept of social action has thus had an impact on the development of different sociological theories, such as those involving the nature of power and authority, the construction of social hierarchies, and the impact of social standards on individual behaviour.

The SI unit for magnetic flux is the weber (Wb). It corresponds to one tesla-meter squared (Tm2). That is, one weber equals one tesla per metre squared (T/m2).

So, the correct answer is E.

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Electric potential at 4m away would be 50 V.

Electric potential is nothing but a collections of charges, which effects travels in the form of electric rays.

we have formula for electric potential as below:

V = \(\frac{Kq}{r}\)

where, V is the electric potential.

q is the charge and r is the distance and K is the constant.

putting th evalues for the firat case,

100 = kq/2

kq = 200

again calculating for the 4 m distance

V = kq/r = 200/4 = 50 V

Hence the electric potential at the 4m away would be 50 V.

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Answer: 42.41 cm

Explanation:

Answer:  

Exothermic Reaction  

Explanation:  

ENDOTHERMIC REACTION: A chemical reaction is considered endothermic if the energy is absorbed during the reaction. In other words, if the energy is required by the reactants to proceed with the reaction, then the reaction is endothermic.

The value of enthalpy change ΔH is positive in such reactions showing intake of energy.

EXOTHERMIC REACTION: A chemical reaction is considered exothermic if the energy is released during the reaction. In other words, if the energy is produced as a product of the reaction, then the reaction is exothermic.

The value of enthalpy change ΔH is negative in such reactions showing the release of energy.

Since, the value of ΔH = -125 KJ, is negative for the given reaction.

Therefore, it would be considered as Exothermic Reaction.

Answer:

Explanation:

If dropped from a position of rest, the object will be traveling 9.8 m/s (approximately 10 m/s) at the end of the first second, 19.6 m/s (approximately 20 m/s) at the end of the second second, 29.4 m/s (approximately 30 m/s) at the end of the third second

Answer:2n

Explanation:10/5=2

The weight of the object on the moon is 16.33 N.

Given,

The weight of the object on earth is 98 N.

The gravitational acceleration on the moon is 1/6 of that on Earth.

Let the weight of the object on the moon be w.

The weight of the object can be found using the formula;

w = mg

where,

m = mass of the object

g = acceleration due to gravity

Now, Acceleration due to gravity on the Earth,

g_Earth = 9.8 m/s²

Acceleration due to gravity on the Moon,

g_Moon = 1/6

g_Earth = 9.8 / 6 m/s²

             = 1.633 m/s²

The mass of the object can be found using the formula;

w_Earth = mg_Earth

             => 98

             = m x 9.8

             => m

             = 98 / 9.8

            = 10 kg

The weight of the object on the moon,

w = m x g_Moon

   = 10 x 1.633

   = 16.33 N

Therefore, the weight of the object on the moon is 16.33 N.

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The answer is 6.

Add 4 then divide 2. You should have 18 after you do that, subtract 10 then multiply 20. You then have 6.

Answer:

maneeee , i just need a couple points so ..

Explanation:

hehee , played yall

The supplied assertion states that a proton experience would be forced in the same field at -2.24 i^ pN

The main distinction is that whereas as proton is a charged particles particle found inside the atom's nucleus, a particle is a highly reactive particle that orbiting the nucleus. Two up neutrons and one drop quark are found in protons. One up atom and five down quarks make up neutrons. The "strong nuclear force," one of the four basic forces, holds the nucleus together (gravity and electromagnetism are two others).

Charge q = -1*10⁻⁶C

Electrostatic force F = 14 i^ N

The electric field is

       E = F/q

          = (14 i^ N) / (-1*10⁻⁶ C)

          = -14*10⁶ i^ N/C

The force on a proton is:

   F = qpE

      = (1.6*10⁻¹⁹ C)(-14*10⁶ i^ N/C)

      = -22.4*10⁻¹³ i^ N

      = -2.24*10⁻¹² i^ N

      = -2.24 i^ pN

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The complete question is-

1.0 µC charge experiences a 14 i N electric force in a certain electric field. What force would a proton experience in the same field?

Answer:

yeah

Explanation:

the answer is right.

Answer:

The magnitude of the student's displacement is less than the distance she walked.

Walking:  11 Blocks

Displacement:  8.54 Blocks

Explanation:

See the attached diagram.  The unit of length is blocks.  We can add the actual blocks walked as shown.  She walked a total of 11 blocks.

Her displacement is the distance measured directly from where she started (line A).  Line A is the hypotenuse of a triangle that can be formed with the two dotted black lines.  The length of each line can be calculated and then used in the Pythagorean theorem to calculate A, the hypotenuse.

That result is 8.54 Blocks, a shorter distance, once she earns her wings.

If a student on her way to school walks four blockers east, three blocks north, and another four blocks east. Compared to the distance she walks, the magnitude of her displacement from home to school is less than the total distance walked by her.

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.

As given in the problem if a  student on her way to school walks four blockers east, three blocks north, and another four blocks east,

The total distance walked by the student = 11 blocks

Displacement of the student from home = √(8² + 3²)

                                                                   = 8.5 blocks

The total displacement by the student would be less than the

Thus, the magnitude of her displacement from home is less than the distance.

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Answer:

3

Explanation:

dogs

Steve's negligence in leaving the truck's motor running in neutral and forgetting to set the parking brake resulted in a series of events that caused the truck to crash into a gas station pump.

Steve, a driver for QRI, made a careless mistake while making a delivery. He left the truck's motor running in neutral and forgot to set the parking brake. As a result, the truck rolled and crashed into a nearby gas station pump. This caused a fire to ignite, which spread quickly to a construction site a block away.

There are several factors at play here that contributed to the chain of events. First, leaving the truck's motor running in neutral allowed it to move freely without any control. Second, forgetting to set the parking brake meant there was no additional mechanism to keep the truck stationary.

The collision with the pump caused a rupture, resulting in a fuel leak. The ignition source, possibly a spark or heat from the impact, ignited the fuel and started a fire.

The fire then spread to the nearby construction site. Construction sites often contain materials that are combustible, such as wood, paint, or fuel. The proximity of these materials to the gas station allowed the fire to easily extend to the construction site.

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Explanation:

the object should be placed at 2F

Answer:

at 2F

Explanation:

hope it will help you

The dura mater forms the tough and fibrous outer sac of the meninges. The meninges are the protective layers that surround the brain and spinal cord. The three layers of the meninges are the dura mater, arachnoid mater, and pia mater.

The dura mater is the thickest and outermost layer of the meninges. It is a fibrous membrane that is attached to the skull and the vertebrae of the spine. The dura mater forms a tough, outer sac that surrounds and protects the brain and spinal cord.

The dura mater is composed of two parts: the outer dura mater and the inner dura mater. The outer dura mater is made up of dense connective tissue that is rich in collagen fibers. It is attached to the skull and the vertebrae of the spine, forming a tough, protective barrier around the brain and spinal cord. The inner dura mater is a thinner layer of connective tissue that is rich in blood vessels and lymphatic vessels. It is also known as the arachnoid mater. The inner dura mater is attached to the outer dura mater, forming a space called the subarachnoid space, which contains cerebrospinal fluid (CSF).

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The object is 51 / 2 = 25.5 meters away from the bat.

Cool 20 °C temperature is close to room temperature. The speed of sound in air at room temperature is approximately 340 m/s.

Given that the bat receives an echo after 0.150 s, we can use the equation as follows to calculate the distance:

  s = v * t

  s = 340 / 0.150

  s = 51 m

So the sound travels a total of 51 m. That is the length it needs to hit the object and to travel back (as an echo) to the bat. That means that the object is 51 / 2 = 25.5 meters away.

Your question seems incomplete. The completed version is most likely as follows:

Bats rely on sound localization to be able to fly during the night. On a cool 20 °C summer night, a bat produces an ultrasonic sound with a frequency of 39 kHz. While remaining stationary, the bat emits a sound pulse and receives an echo after 0.150 sec. How far away, in meters, is the reflecting object from the bat?

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Answer:

1. 180 m

2. 1.5 miles/hour

3. 0 m/s

Explanation:

The complete question is

A dog runs 300 m North and sees the dog catcher and runs 120 m south Whats the dogs displacement.

A jogger runs north for 3.0 miles. If this took 2.0 hours, what is the jogger’s average velocity in miles per hour?

The same jogger runs 3.0 miles on the track, starting and finishing his run after completing exactly 12 laps around the track. What is his average velocity?

1. Displacement is how far the dog moves from the original starting point.

If the dog runs 300 m north, and then 120 m south, then the displacement from the starting point will be

displacement = 300 - 120 = 180 m

2. Displacement of the jogger = 3 miles

Time taken by the jogger = 2 hours

velocity of the jogger = ?

Velocity is = displacement/time

velocity = 3/2 = 1.5 miles/hour

3. velocity = displacement/time

if the jogger completes exactly 12 laps around the track, then the jogger will return to the starting point. This means that the jogger's displacement from the starting point is 0 miles

Jogger's velocity will therefore be = 0 m/s

Answer: No

Explanation:

A chemical for formula is combined of atomic that is has a chemical compounds

(a) The acceleration of the crate  is  1.5 m/s^2

(b) The crate’s final velocity is 9 m/s.

To move the crate with a constant velocity, the force you apply must equal the force of friction. So, to move the crate, you must push with a force of 275 N.

If you push with a force of 380 N, the net force on the crate will be;

F (net)  380 N - 275 N = 105 N.

The acceleration of the crate will be given by Newton's second law of motion:

a = F / m

where;

So, substituting in the known values, we get:

a = 105 N / 70 kg = 1.5 m/s^2

Finally, if the crate started from rest, its final velocity after 6 seconds can be found using the equation:

v = at

v = 1.5 m/s^2  x  6s = 9 m/s

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6.5 The lowest observed microwave absorption frequency.

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Option A: Chromatic aberration is a problem with reflecting telescopes. Large glass lenses with flawless interiors are challenging to produce. There are various surfaces to shape and polish on refractive telescopes.

Compared to huge mirrors, large glass lenses are more challenging to support. Telescopes are instruments used to observe and study celestial objects such as stars, planets, galaxies, and nebulae. They work by collecting and focusing electromagnetic radiation from these objects, allowing astronomers to study their properties and characteristics. Telescopes come in a variety of designs, such as refracting, reflecting, and catadioptric telescopes. Refracting telescopes use lenses to bend and focus light while reflecting telescopes use mirrors to do the same. Catadioptric telescopes use both lenses and mirrors to focus light. Modern telescopes can also operate in a variety of wavelengths, including visible light, radio waves, and X-rays. In recent years, the development of space telescopes has enabled astronomers to observe the universe beyond the limitations of the Earth's atmosphere. Telescopes have played a crucial role in advancing our understanding of the universe and continue to be an essential tool in modern astronomy.

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Answer:

The minimum mass of m2 before m1 starts sliding across the table is 57 grams

Explanation:

The given mass on the table, m1 = 250 g

The coefficient of friction between the table and the mass, m1, μ = 0.228

Therefore, the friction force, F\(_F\) between the mass m1 and the table is given as follows;

F\(_F\) = W₁ × μ

Where;

W₁ = The weight of m1  = Mass of m1 × Acceleration due to gravity

W₁ = 250 g × 9.81 m/s² = 0.25 kg × 9.81 m/s² = 2.4525 N

W₁ = 2.4525 N

Which gives;

F\(_F\) = 2.4525 N × 0.228 = 0.55917 N

F\(_F\) = 0.55917 N

By equilibrium of forces, the weight, W₂, of the mass m2 at which the mass m1 starts sliding is equal to the frictional force F\(_F\) of m1 or 0.55917 N

Therefore, for slipping to occur, we have;

W₂ = 0.55917 N

However, W₂ = Mass of m2 × Acceleration due to gravity

∴ W₂ = 0.55917 N = m2 × 9.81 m/s²

0.55917 N = m2 × 9.81 m/s²

m2 = 0.55917 N/(9.81 m/s²) = 0.057 kg = 57 grams

The minimum mass of m2 before m1 starts sliding across the table is 57 grams.

The bike rider's average velocity is 1.5m/s in the northwest direction. This means that on average, the rider covers a distance of 1.5 meters every second in the northwest direction.

The magnitude of the average velocity can be determined by finding the total displacement and dividing it by the total time taken. In this case, the bike rider travels 75m toward the west and 75m toward the north, resulting in a total displacement of 75m in the northwest direction.

To find the average velocity, we need to calculate the total time taken. Since the distance traveled in each direction is the same and the speed is constant at 1.5m/s, we can divide the total distance by the speed to find the total time. In this case, 75m / 1.5m/s = 50s.

Next, we divide the total displacement (75m) by the total time (50s) to find the average velocity. 75m / 50s = 1.5m/s.

Therefore, the magnitude of the average velocity is 1.5m/s.

In summary, the bike rider's average velocity is 1.5m/s in the northwest direction. This means that on average, the rider covers a distance of 1.5 meters every second in the northwest direction.

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Answer:

I think it's C - sorry if I'm wrong

Answer:

B and C

Explanation: