The answer is 3/a, have a nice day
HELP PLEASE!! 15 POINTS
the number of minutes needed to solve an exercise set of variation problems varies directly as the number of problems and inversely as the number of people working on the solutions. it takes 4 people 36 minutes to solve 18 problems. how many minutes will it take 6 people to solve 42 problems.
The number of minutes needed to solve an exercise set of variation problems varies directly with the number of problems and inversely with the number of people working on the solutions. it will take 6 people approximately 24 minutes to solve 42 problems based on the given variation relationship.
Let's denote the number of minutes needed to solve the exercise set as "m," the number of problems as "p," and the number of people as "n." According to the given information, we have the following relationships: m ∝ p (direct variation) and m ∝ 1/n (inverse variation).
We can express these relationships using proportionality constants. Let's denote the constant of direct variation as k₁ and the constant of inverse variation as k₂. Then we have the equations m = k₁p and m = k₂/n.
In the initial scenario, with 4 people solving 18 problems in 36 minutes, we can substitute the values into the equations to find the values of k₁ and k₂. From m = k₁p, we have 36 = k₁ * 18, which gives us k₁ = 2. From m = k₂/n, we have 36 = k₂/4, which gives us k₂ = 144.
Now, we can use these values to determine how many minutes it will take 6 people to solve 42 problems. Substituting n = 6 and p = 42 into the equation m = k₂/n, we get m = 144/6 = 24. Therefore, it will take 6 people approximately 24 minutes to solve 42 problems based on the given variation relationship.
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Salma runs 6 miles in 55 minutes. At the same rate, how many miles would she run in 44 minutes?
Answer:
The number of miles she would run in 44 minutes is;
\(4.8\text{ miles}\)Explanation:
Given that;
Salma runs 6 miles in 55 minutes;
The rate at which she run is;
\(\text{rate =}\frac{\text{ distance}}{\text{time}}=\frac{6}{55}miles\text{ per minute}\)At the same rate, the distance it will cover in 44 minutes is;
\(\begin{gathered} \text{time}=\frac{\text{distance}}{\text{rate}} \\ \text{distance}=\text{time}\times rate \\ \text{distance}=44\times\frac{6}{55} \\ \text{distance = 4.8 miles} \end{gathered}\)The number of miles she would run in 44 minutes is;
\(4.8\text{ miles}\)Find the distance between 2 and -2
A) -6
B) -4
C) 0
D) 4
Answer:
d
Step-by-step explanation:
A line has a slope of - Which ordered pairs could be points on a parallel line? Select two options.
(-8, 8) and (2, 2)
(-5, -1) and (0, 2)
(-3, 6) and (6,-9)
(-2, 1) and (3,-2)
(0, 2) and (5, 5)
The ordered pairs that could be points on a parallel line are:
(-8, 8) and (2, 2)
(-2, 1) and (3, -2)
Which ordered pairs could be points on a parallel line?Parallel lines have the same slope. Thus, we have to find ordered pairs with a slope of -3/5.
We have:
slope of the line is -3/5.
Thus, m = -3/5
Formula for slope between two coordinates is;
m = (y₂ - y₁)/(x₂ - x₁)
A) At (–8, 8) and (2, 2);
m = (2 - 8)/(2 - (-8))
m = -6/10
m = -3/5
B) At (–5, –1) and (0, 2);
m = (2 - (-1))/(0 - (-5))
m = 3/5
C) At (–3, 6) and (6, –9);
m = (-9 - 6)/(6 - (-3))
m = -15/9
m = -5/3
D) At (–2, 1) and (3, –2);
m = (-2 - 1)/(3 - (-2))
m = -3/5
E) At (0, 2) and (5, 5);
m = (5 - 2)/(5 - 0)
m = 3/5
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Let Pij = the production of product i in period j. To specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units, we need to add which pair of constraints?
P52-P42 <= 80; P42-P52 <= 80
None of the other above.
P24 - P25 <= 80; P25-P24 >= 80
O P24 - P25 >= 80; P25-P24 >= 80
P24 - P25 <= 80; P25-P24 <= 80
The correct pair of constraints that needs to be added to specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units is: P24 - P25 <= 80; P25-P24 <= 80. Therefore, the correct option is 5.
Here, the given information is Pij = the production of product i in period j. We need to find the pair of constraints that will specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units. Thus, let the production of product 2 in period 4 and in period 5 be represented as P24 and P25 respectively.
Therefore, we can write the following inequalities:
P24 - P25 <= 80
This is because the production of product 2 in period 5 can be at most 80 units less than that of period 4. This inequality represents the difference being less than or equal to 80 units.
P25-P24 <= 80
This is because the production of product 2 in period 5 can be at most 80 units more than that of period 4. This inequality represents the difference being less than or equal to 80 units.
Therefore, we need to add the pair of constraints P24 - P25 <= 80 and P25-P24 <= 80 to specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units. Hence, option 5 is the correct answer.
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everyone in this neighborhood owns a car. George lives in this neighborhood. Therefore, George owns a car. This is an example of
a. universal instantiation
b. existential generalization
c. existential instantiation d.universal generalization
The given statement "Everyone in this neighborhood owns a car. George lives in this neighborhood. Therefore, George owns a car." is an example of universal instantiation.
Universal instantiation is a valid logical inference rule that allows us to infer a specific instance from a universal statement. It is based on the idea that if a statement applies to every member of a group or category, then it must also apply to a specific individual within that group.
In the given statement, the universal statement is "Everyone in this neighborhood owns a car." This statement asserts that every member of the neighborhood owns a car. By applying universal instantiation, we can infer that George, who is a member of this neighborhood, also owns a car. This inference is valid because George is part of the group described by the universal statement, and thus the statement applies to him as well.
To further understand this concept, let's break down the options provided:
a. Universal instantiation: This is the correct answer. It refers to the process of deriving a specific instance from a universally quantified statement.
b. Existential generalization: This rule allows us to infer the existence of at least one instance based on specific instances. It is not applicable to the given statement.
c. Existential instantiation: This rule allows us to introduce a new instance based on the existence of a specific instance. It is not applicable to the given statement.
d. Universal generalization: This rule allows us to infer a universally quantified statement from specific instances. It is not applicable to the given statement.
In conclusion, the example provided is an instance of universal instantiation because it derives a specific instance (George owning a car) from a universally quantified statement (everyone in the neighborhood owning a car).
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Pliss help me
Classify these numbers as Irrational and Irrational and place them in their correct area.
vo 1 35.421109, V17.39, II, 200 18,0,-9
Answer:A
Step-by-step explanation:
Ayden filled up hi car with ga before embarking on a road trip acro the country. The car ue 2 gallon of ga for every hour driven, and after driving for 4 hour, there were 4 gallon of ga left in the tank. Write an equation for G,G in term of T,T, repreenting the number of gallon of ga remaining in Ayden ga tank after TT hour of driving
Equation for G, representing the number of gallons of gas left after ‘T’ hours will be: G = 12 - 2T
Let G be the total number of gallons of gas left
And t be the time in hours
Since, car uses 2 gallons of gas in 1 hours
Therefore, total gallons of gas used in 4 hours will be 2 x 4 = 8 gallons
Total gallons of gas left after 4 hours = 4 gallons
Therefore, total gallons of gas before embarking on a road trip = 8 + 4 = 12 gallons
In general from the unitary method, number of gallons of gas used in time ‘T’ will be 2T
Therefore, Total gallons of gas left = (Total gallons of gas embarked on a road trip) - ( Total gallons of gas used in the trip at time ‘T’ )
From the above conclusions, we can write
G = 12 - 2T
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Which statement describes the function shown on the graph
A. The function has a slope of -10 and a y-intercept of 9.
B. The function has a slope of 9 and a y-intercept of -10.
C. The function has a slope of -10 and a y-intercept of 1/9.
D. The function has a slope of 1/9 and y-Intercept of -10
I think the answer is c :)
Answer:
the answer is C. the function had a slope of 9 and a y-intercept of 1/9
The function plotted on graph has a slope of 9 and its
y-intercept is -10.
What is the general equation of a straight line?
The general equation of a straight line is -
y = mx + c
where -
m is the slope of line
c is the y - intercept
Given is a graph of a Straight line.
For a straight line, as discussed above -
c represents the y - intercept and m represents the slope.
Now, from the graph it can be seen that the graph cuts the y - axis at
y = - 10. Therefore, the y - intercept will be -10.
Now, at x = 2, y = 8 and at x = 0, y = -10 . Putting values, we get -
m = (y[2] - y[1]) / x[2] - x[1])
m = (- 10 - 8)/(0 - 2)
m = 9
Therefore, the function plotted on graph has a slope of 9 and its
y-intercept is -10.
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what is the hypothesis of the conditional statement? if i can save the money, then i will visit my aunt in spain.
Answer:
Step-by-step explanation:
The answer would be A because the hypothesis of a conditional statement is the statement after the "if", but before the "then".
1. Calculate the value of a 10 year bond with a face value of AUD 100, annual coupons of AUD 10, when the market yield (yield to maturity) is 11%.
a.
AUD 100
b.
AUD 94.11
c.
AUD 138.61
d.
AUD 88.70
e.
AUD 83.72
f.
AUD 106.42
The present value of a 10 year bond with a face value of AUD 100 and annual coupons of AUD 10, when the market yield (yield to maturity) is 11% is AUD 94.11.
Calculate the present value of the annual coupon payments. The present value of a perpetuity is equal to the periodic payment (in this case, AUD 10) divided by the discount rate (in this case, 0.11)P = C / r
P = AUD 10 / 0.11
P = AUD 90.91
Calculate the present value of the face value. The present value of the face value is equal to the face value (in this case, AUD 100) divided by (1 + the discount rate raised to the number of periods remaining (in this case, 10)). P = F / (1 + r)n
P = AUD 100 / (1 + 0.11)10
P = AUD 38.65
Add the present value of the annual coupon payments and the present value of the face value to get the present value of the bond. Present Value of Bond = Present Value of Coupons + Present Value of Face Value Present Value of Bond = AUD 90.91 + AUD 38.65Present Value of Bond = AUD 129.56
Present Value of Bond = Present Value of Coupons + Present Value of Face Value Present Value of Bond = AUD 90.91 + AUD 38.65 Present Value of Bond = AUD 129.56
Therefore, the present value of the bond is AUD 129.56 or AUD 94.11 after rounding to two decimal places.
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Compute each of the following Galois groups. Which of these field extensions are normal field extensions? If the extension is not normal, find a normal extension of Q in which the extension field is contained
To compute the Galois groups and determine if the field extensions are normal, we need to know the specific field extensions in question. However, I will provide a general method for computing Galois groups and determining normal field extensions.
Step 1: Identify the field extension
Let's say our field extension is given by K/Q, where K is the extension field and Q is the base field (the field of rational numbers).
Step 2: Determine the minimal polynomial
Find the minimal polynomial f(x) of the field extension K/Q. This is the smallest degree polynomial with rational coefficients for which the elements of K are roots.
Step 3: Compute the Galois group
The Galois group, G(K/Q), is the group of automorphisms of the field K that fix the base field Q. To compute G(K/Q), determine the set of automorphisms of K that keep the elements of Q fixed.
Step 4: Check for normality
A field extension K/Q is normal if and only if the minimal polynomial f(x) splits into distinct linear factors over K. If this is true, then K/Q is a normal field extension.
Step 5: Find a normal extension if necessary
If K/Q is not normal, we can find a normal extension L/Q containing K by considering the splitting field of the minimal polynomial f(x) over Q. The splitting field L is the smallest field containing Q and all the roots of f(x), and the extension L/Q will be normal.
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224 in 8 minutes. Use the unit rate to complete the table of values for the proportional relationship.
X. Y
2. ?
4. ?
6. ?
9514 1404 393
Answer:
see attached
Step-by-step explanation:
It can be convenient to use mental arithmetic methods* to fill in this table.
Since the relationship is proportional the y-value for x=4 will be half that for x=8, so will be 224/2 = 112. Similarly, the y-value for x=2 will be half that for x=4, so will be 112/2 = 56.
Then the y-value for x=6 will be the sum of the y-values for x=2 and x=4, so will be 112 +56 = 168.
If you actually care to find the "unit rate," you can divide the y-value for x=2 by 2 to get the corresponding y-value for x=1: 56/2 = 28. The unit rate is 28.
_____
* Multiplication or division by 2 is simply a matter of doubling or halving. In most cases, it is easy to double a number, or to compute half of it. (If it isn't, you need to review your arithmetic facts.)
3. Marie planted a tree a few years ago and wanted to see how much it had grown. Marie
measures the angle from a point A to the top of the tree to be 34 degrees. She measures her
distance to be 8 meters from the base of the tree. How high is the tree to the nearest tenth of a
meter?
Answer:
5.4 mStep-by-step explanation:
Given
The top of the tree, the point A and the base form a right triangleHorizontal leg = 8 mVertical leg = the height of the tree = xAngle A = 34° is opposite to the threeUse the ratio to find the value of x:
opposite / adjacent = tan Ax/8 = tan 34°x = 8 tan 34 degreex = 5.4 m (rounded)What is the area of the figure?
(NEED THE ANSWER ASAP. PLEASE DONT PUT ANYTHING NONSENSE OR I'LL REPORT U. THANK U FOR UR HELP)
The area of the given figure is 12 square meters
The given figure is a parallelogram
Parallelogram is a geometric figure that has both pair of opposites parallel sides and opposite sides are equal . Number of vertices and edges are four
The height of the parallelogram = 2 meters
The base length of the parallelogram = 6 meters
The area of the parallelogram = The height of the parallelogram × The base length of the parallelogram
Substitute the values in the equation
The area of the parallelogram = 2 × 6
Multiply the numbers
= 12 square meters
Therefore, the area is 12 square meters
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I have solved the question in general , as the given question is incomplete
The complete question is :
What is the area of the figure ?
CAN SOMEONE HELPPP MEEE MY HOMEWORK IS SOO HARDDD PLEASE!!!!
Answer:
#5 the sum would be on the right side because it is positive
6th grade math help me pleasee
--------------------
1. Kris
2. Katie
---------------------
Chloe is packing up her room to move to a new city. Together, all the books on her bookshelf weigh 85 pounds. She wants to divide the books among 4 boxes, so that each box will weigh the same amount.
if the man swims at 2 mi/hr, what is the minimum walking speed for which it is quickest to walk the entire distance?
The man should swim the entire distance at 2 miles per hour because the minimum walking speed that would make it quicker to walk the entire distance is infinity, which is not practical.
Let's assume the distance the man needs to travel is d miles. If the man swims at 2 miles per hour, he can swim the distance in d/2 hours. If he walks at a speed of x miles per hour, he can walk the distance in d/x hours. Therefore, the total time T it takes to travel the distance using swimming and walking is:
T = d/2 + d/x = d(1/2 + 1/x)
We want to find the walking speed x that minimizes the total time T. To do this, we can take the derivative of T with respect to x and set it equal to zero:
d(T)/dx = -d/2x^2 + d/x^2 = d/x^2(1/2 - 1) = -d/2x^2
Setting d(T)/dx = 0, we get:
d/2x^2 = 0
Solving for x, we get:
x = infinity
This means that the minimum walking speed for which it is quickest to walk the entire distance is infinity, which is not a practical solution. Therefore, the man should swim the entire distance at 2 miles per hour.
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PLEASE HELP ASAP FOR ALGEBRA 1 Mr Reder has just robbed a bank and is trying to escape on foot. He is currently 3 miles from the bank and running at 5 miles per hour. Write an equation to model how far from the bank Mr Reder is after a certain amount of time has passed. How far has he gone after 3 hours? Draw an appropriate graph for this equation.
Answer:
He has ran 15 miles and passed the bank 12 miles from his location where he is at.
Step-by-step explanation:
WHY WAS HE ROBBING A BANK?????????
Answer:
Step-by-step explanation:
His distance from the bank can be modeled using an equation in the form y=mx+b. Since he has already ran 3 miles, the "b" is equal to 3, and can be added to how many miles he runs on from now on. If he can run 5 miles per hour, then that means every hour, he will run 5 miles. We can represent how many hours have passed as x. This would make our equation y=5x+3.
After 3 hours he has gone 5(3)+3 miles, or 18 miles
A ∧ B , A → C , B → D ⊢ C ∧ D
construct a proof using basic TFL
The given statement to prove is: A ∧ B, A → C, B → D ⊢ C ∧ D.TFL stands for Truth-Functional Logic, which is a formal system that allows us to make deductions and prove the validity of logical arguments.
The steps to prove the given statement using basic TFL are as follows:1. Assume the premises to be true. This is called the assumption step. A ∧ B, A → C, B → D.2. Apply Modus Ponens to the first two premises. That is, infer C from A → C and A and infer D from B → D and B.3. Conjoin the two inferences to get C ∧ D.
4. The statement C ∧ D is the conclusion of the proof, which follows from the premises A ∧ B, A → C, and B → D. Therefore, the statement A ∧ B, A → C, B → D ⊢ C ∧ D is true, which means that the proof is valid in basic TFL. Symbolically, the proof can be represented as follows:
Premises: A ∧ B, A → C, B → DConclusion: C ∧ DProof:1. A ∧ B, A → C, B → D (assumption)2. A → C (premise)3. A ∧ B (premise)4. A (simplification of 3)5. C (modus ponens on 2 and 4)6. B → D (premise)7. A ∧ B (premise)8. B (simplification of 7)9. D (modus ponens on 6 and 8)10. C ∧ D (conjunction of 5 and 9).
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There are 16 ounces in 1 lb juwan is mailing a package that weighs 10 lb he wants to know the weights of the package and the ounces
Juwan is mailing a package that weighs 10lb
for every 1 lb you have 16 ounces inside the package
if 1 lb ------- 16 ounces
10lb ------- x ounces
reason why we have x ounces is because we dont know how many ounces 10 lb we give us
cross multiplication
1 * x = 10 x 16
x = 10 x 16
x = 160 ounces
10lb we give us a total of 160 ounces
therefore, there are 160 ounces in the 10 lb package juwan is mailing
The answer is 160 ounces
Hello I’m in algebra and I need help on questions I’ll give brainlist ASAP!
Answer:
9/12 = 4/x
Step-by-step explanation:
The height of the larger triangle is 9. The base of the larger triangle is 12. So let's make the ratio 9/12.
The height of the smaller triangle is 4. The base of the smaller triangle is x. So let's make the ratio 4/x.
Since both triangles are congruent, let's make these both equal each other to solve for x (if you need to).
Thus, it's 9/12 = 4/x.
Which of the following is an irrational number?
A) - ✓16
B) ✓0.4
C) ✓4
D) ✓16
Answer:
B
Step-by-step explanation:
3. A survey of 400 recent high school graduates found that 340
had drivers licenses and 216 had jobs. 42 of the graduates
said that they had neither a drivers license nor a job.
Job
No Job
Total
340
License
No License
Total
42
216
184
a) Complete the above two way frequency table to represent
the above situation,
b) If one of these 400 graduates is randomly selected, what
is the probability that he or she had a job but no license?
Answer:
Look below
Step-by-step explanation:
Chart
Job No job Total
Lisence 198 142 340
No lisence 18 42 60
Total 216 184 400
60/400
simplified = 15/100
i have R150 in my bank account and I withdraw R100 how much would I have in my bank account
A student went on a two-day hike. • On day one, the student hiked 11 kilometers. On day two, the student hiked at a rate of 2 kilometers per hour for x hours. Which of the following graphs represents y, the total distance, in kilometers, the student hiked over both days after hiking for x hours on day two?
The slope is 2, which equals the distance travelled each hour. The total distance hiked at the start of the second day is represented by the y-intercept, which is 4, which is also the y-value. intercept's
Explain about the Slope?We locate the rise/run before calculating the slope. Since the line increases by 2 between each point, the rise is 2. It travels over 1 between the points, hence the run is 1. The slope is now 2/1, or 2.
Given that it is rise/run, this gives us miles/hours, which indicates the number of miles she treks per hour.
The line's crossing of the y-axis is known as the y-intercept. At four, this is.
The fact that the y-value at this time is 4 and the x-value at this point is 0 tells us that she has trekked 4 miles in the 0 hours since the start of the second day, which is the distance she has covered so far.
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A researcher is investigating the effect of sleep deprivation on learning. She recruits 30 participants and randomly assigns half to a "no sleep" group and half to a "regular sleep" group. The "no sleep" group are required to stay up all night and report to a testing room at 2PM the following day. The "regular sleep" group are instructed to have a normal night's sleep and report to the testing room at 9AM the following day. Unfortunately, a water pipe broke outside the testing room window and there was noisy construction crew working the whole day of testing. Which of the following statements is true?
a. The study may be affected by a situational variable.
b. The construction noise may contribute to variability in test scores.
C. The study has a confounding variable. The groups differ in the time they are to report to the testing room.
d. All of these are true.
The study has a confounding variable since the two groups differ in the time they were supposed to report to the testing room. Since the groups differed in terms of sleep deprivation and the time they were supposed to report to the testing room, the effect of sleep deprivation on learning could not be isolated.
The statement that is true is: d. All of these are true.Explanation:A study may have various sources of variability, including participant selection, the setting in which the study is conducted, and the measure used. The following options are as follows:a. The study may be affected by a situational variable.b. The construction noise may contribute to variability in test scores.c. The study has a confounding variable. The groups differ in the time they are to report to the testing room.d. All of these are true.Therefore, all of these options are true. For example, the study may be affected by a situational variable if a natural disaster or other unforeseen event happens that causes the study to be disrupted. In this case, the study was disrupted by a noisy construction crew, which may have contributed to variability in test scores. The study has a confounding variable since the two groups differ in the time they were supposed to report to the testing room. Since the groups differed in terms of sleep deprivation and the time they were supposed to report to the testing room, the effect of sleep deprivation on learning could not be isolated.
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Linda buys a bag of cookies that contains 8 chocolate chip cookies, 5 peanut butter cookies, 9 sugar cookies and 8 oatmeal cookies. What is the probability that Linda reaches in the bag and randomly selects a peanut butter cookie from the bag, eats it, then reaches back in the bag and randomly selects an oatmeal cookie
The probability that Linda randomly selects a peanut butter cookie, eats it, and then randomly selects an oatmeal cookie is 2/43.
1. First, we need to find the total number of cookies in the bag. The bag contains:
- 8 chocolate chip cookies
- 5 peanut butter cookies
- 9 sugar cookies
- 8 oatmeal cookies
Total cookies = 8 + 5 + 9 + 8 = 30 cookies
2. Next, we find the probability of Linda randomly selecting a peanut butter cookie:
Probability of peanut butter = (Number of peanut butter cookies) / (Total number of cookies)
Probability of peanut butter = 5/30
3. After eating the peanut butter cookie, there are now 29 cookies left in the bag (and 4 peanut butter cookies remaining).
4. Now, we find the probability of Linda randomly selecting an oatmeal cookie:
Probability of oatmeal = (Number of oatmeal cookies) / (Total number of remaining cookies)
Probability of oatmeal = 8/29
5. To find the overall probability of both events occurring, we multiply the individual probabilities:
Probability of both events = (Probability of peanut butter) * (Probability of oatmeal)
Probability of both events = (5/30) * (8/29)
6. Simplify the fraction:
Probability of both events = 40/870
7. Reduce the fraction to its lowest terms:
Probability of both events = 2/43
So the probability that Linda randomly selects a peanut butter cookie, eats it, and then randomly selects an oatmeal cookie is 2/43.
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