What is this -5/7 divide by -1/3

Answer:

below

Step-by-step explanation:

1. 1 over 8

2. 4 over 1

Answer:

360° = 131° + 110° + 107° + 108°

360° = 456° + x

.: x = -96°

The light source of the compound light microscope is F.

The light source for a microscope is called an illuminater, and it is typically found in the base of the microscope. The majority of light microscopes employ low-voltage halogen bulbs with a base-mounted continuous variable lighting control.

The light from the illuminator is collected and focused using a condenser onto the specimen. The light source for a compound light microscope is typically an electric lamp, such as a halogen lamp or a LED. In the microscope, the light is passed through a series of lenses and is directed through a condenser lens and onto the specimen being viewed. The letter that represents the light source on a diagram of a microscope is typically "F."

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The inequality expressions for the number of male and female sea turtles are given as 0 < x ≤ 8 and 0 < 2x ≤ 16 respectively.The correct option is (b).

A linear inequality is the equivalent expression for the range of the values of a variable. On the graph it represents the area either above or below a straight line.  

Suppose the number of male turtles be x and females be y.

Then, as per the question the inequality expression for the male population can be written as follows,

0 < x ≤ 8

But the equation for the female population is given as y = 2x.

Now, the inequality expression can be written as,

0 < x ≤ 8

Multiply 2 on all sides to get,

2 × 0 < 2x ≤ 8 × 2

⇒ 0 < 2x ≤ 16

The required expressions of inequality are 0 < x ≤ 8 and 0 < 2x ≤ 16 respectively.

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The value of x in the given diagram is 10

From the question, we are to determine the value of the side labeled x

First, we will find the value of side |BC|

By the Pythagorean theorem, we can write that

|BC|² = 12² + 16²

|BC|² = 144 + 256

|BC|² = 400

|BC| = √400

|BC| = 20

Now,

Since ΔABC and ΔDEF are similar, we can write that

|BC| / |EF| = P ΔABC / P ΔDEF

But,

P ΔABC = 12 + 16 + 20 = 48

Thus,

|BC| / |EF| = P ΔABC / P ΔDEF becomes

20/ |EF| = 48/24

20/x = 2

x = 20/2

x = 10

Hence, the value of x in the given diagram is 10

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The end behavior of a polynomial function can be determined by examining the leading coefficient and degree of the polynomial. If the leading coefficient is positive, the graph will increase without bound as the x-values increase. If the leading coefficient is negative, the graph will decrease without bound as the x-values increase.

The end behavior of a polynomial function depends on the equation of the function. The degree of a polynomial is the highest power of the variable, and the leading coefficient is the coefficient of the term with the highest degree. If the leading coefficient is positive, the graph will increase without bound as the x-values increase. This is because the terms in the equation with positive coefficients will become increasingly larger than the terms with negative coefficients as the x-values increase. On the other hand, if the leading coefficient is negative, the graph will decrease without bound as the x-values increase. This is because the terms in the equation with negative coefficients will become increasingly larger than the terms with positive coefficients as the x-values increase. In addition, the degree of the polynomial can also affect the end behavior of the graph. If the degree is even, the graph will not have an extreme point. However, if the degree is odd, the graph will have an extreme point. The extreme point will be a maximum or a minimum depending on the sign of the leading coefficient.

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Question 1a

To calculate the book value at the end of the first year using straight-line depreciation, we need to determine the annual depreciation expense first. The straight-line method assumes that the asset depreciates by an equal amount each year over its useful life. Therefore, we can use the following formula to calculate the annual depreciation:

Annual Depreciation = (Cost - Salvage Value) / Useful Life

Substituting the given values, we get:

Annual Depreciation = ($200,000 - $20,000) / 10 years = $18,000 per year

This means that the tractor will depreciate by $18,000 each year for the next 10 years.

To determine the book value at the end of the first year, we need to subtract the depreciation expense for the year from the original cost of the tractor. Since one year has passed, the depreciation expense for the first year will be:

Depreciation Expense for Year 1 = $18,000

Therefore, the book value of the tractor at the end of the first year will be:

Book Value = Cost - Depreciation Expense for Year 1

= $200,000 - $18,000

= $182,000

So the book value of the tractor at the end of the first year, December 31, 2022, using straight-line depreciation is $182,000. so the answer is D

Question 1(b)

To determine the farmer's noncurrent liabilities, we need to use the information provided to calculate the total liabilities and then subtract the current liabilities from it. Here's the step-by-step solution:

Calculate the total current liabilities using the current ratio:

Current Ratio = Current Assets / Current Liabilities

2 = $80,000 / Current Liabilities

Current Liabilities = $80,000 / 2

Current Liabilities = $40,000

Calculate the total liabilities using the debt/equity ratio:

Debt/Equity Ratio = Total Liabilities / Owner Equity

1.0 = Total Liabilities / $100,000

Total Liabilities = $100,000 * 1.0

Total Liabilities = $100,000

Subtract the current liabilities from the total liabilities to get the noncurrent liabilities:

Noncurrent Liabilities = Total Liabilities - Current Liabilities

Noncurrent Liabilities = $100,000 - $40,000

Noncurrent Liabilities = $60,000

Therefore, the farmer's noncurrent liabilities are $60,000. so the answer is B.

The Term to term rule for 28 25 22 19 16 is 25 + 3n.

An arithmetic sequence simply means an ordered set of numbers which have a common difference between the consecutive term.

Based on the information, it should be noted that the formula for an arithmetic sequence will be:

= a + (n - 1)d

a = first term = 28

d = common difference = 25 - 28 = 3

Therefore, the sequence will be illustrated as:

a + (n - 1)d

28 + (n - 1)3

= 28 + 3n - 3

= 25 + 3n

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Answer:

=47/36

(Decimal: 1.305556)

Step-by-step explanation:

Answer:

3 1/4

Step-by-step explanation:

3/4 + ( 1/3 / 1/6 ) - (- 1/2)

First, divide within the parenthesis

3/4 + 2 - (- 1/2)

Next, change the double subtraction to an addition

3/4 + 2 + 1/2

Convert to forths

3/4 + 2 + 2/4

Add 3/4 and 2

2 3/4 + 2/4

Add 2 3/4 and 2/4

3 1/4

I hope that this helps :)

(a) An example of an infinite field such that 4-a -o for all e F is F_2.

Here, the only elements of the field are 0 and 1, and we have 1 + 1 = 0,

which is equivalent to 4 - 1 - 1 = 2 - 1 - 1 = 0. Therefore, for all a e F_2, 4 - a - a = 0, so F_2 satisfies the given condition.

(b) An example of an infinite, non-commutative ring R such that for all a we have that 2a = 0 is the ring of 2x2 matrices over the field F_2 (as defined in part (a)). If we identify the matrix \begin{pmatrix}a&b\\c&d\end{pmatrix} with the element ad + bc of F_2, then R becomes a ring.

Note that R is not commutative since the product of two matrices is not necessarily equal to the product of their entries, and that 2a = 0 for all matrices \begin{pmatrix}a&b\\c&d\end{pmatrix} in R since \begin{pmatrix}a&b\\c&d\end{pmatrix}\begin{pmatrix}0&1\\0&0\end{pmatrix} = \begin{pmatrix}0&a\\0&c\end{pmatrix} and \begin{pmatrix}a&b\\c&d\end{pmatrix}\begin{pmatrix}0&0\\1&0\end{pmatrix} = \begin{pmatrix}b&0\\d&0\end{pmatrix} have entries that are equal to 0 in F_2. Therefore, R satisfies the given condition.

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Answer:

\( - 11 \frac{1}{2} \)

Step-by-step explanation:

8x + 5y = 7

4x - 5y = 11

If you all it all up we have

8x + 4x +5y - 5y = 18

12x=18

x=18/12=1.5=3/2 = 1 whole number 1 over 2(1 1/2)

subtituting the value of x into equation 1(8x + 5y = 7)

8(1.5) + 5y = 7

5y=7-12

5y = -5

y=-5/5

y= -1

Answer:

a

Step-by-step explanation:

The value of x from the given trapezium is 5.

From the given figure, AD=38 units, EB=7x-4 units and FC=6x-6 units.

The geometrical constraint is that the average of the top and bottom line segments will be the middle line segment in the trapezium.

Here, \(\frac{1}{2} (AD+FC)=EB\)

\(\frac{1}{2} (38+6x-6)=7x-4\)

\(\frac{1}{2} (32+6x)=7x-4\)

\(16+3x=7x-4\)

Transpose 3x to the RHS of the equation and -4 to the LHS of the equation, we get

\(16+4=7x-3x\)

\(4x=20\)

\(x=5\)

Therefore, the value of x from the given trapezium is 5.

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The sum of Peter, Richard, and John's ages is 191.

We know that the ratio of Peter's age to Richard's age is = 5/8 --(i)

The ratio of John's age to Peter's age is = 7/12 --(ii)

Similarly, the ratio of John's age to Richard's age is = (5*7)/(8*12)= 35/96 -(iii)

Using the value of (i),(ii),(iii), we get -

Age of Peter = (5*12)/(8*12) = 60/96

= 60 years of age

Age of John = (7*5)/(12*5) = 35/60

=35 years of age

From the value of (iii), since no one is over 100 years of age, the age of Richard= 96 years of age

Hence the sum of their ages is = 96+35+60

= 191

Therefore, we know that the sum of their ages is 191.

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Differential equations and boundary value problems are mathematical equations that contain derivatives of unknown functions and their variables.

These equations are used to model a wide range of physical, biological, and chemical processes. The seventh edition of Fundamentals of Differential Equations and Boundary Value Problems by R. Kent Nagle, Edward B. Saff, and Arthur David Snider is a comprehensive textbook that covers the fundamentals of these equations.Differential equations and boundary value problems are mathematical equations that contain derivatives of unknown functions and their variables.  It includes topics such as first order equations, higher order linear equations, systems of equations, Laplace transforms, Fourier series, and numerical methods. It also contains a variety of worked examples, exercises, and applications to help students understand the material. Examples include solving initial value problems, boundary value problems, and inverse problems. The book also provides a step-by-step approach to solving problems, including the use of formulas such as the Euler-Cauchy formula, the Picard-Lindelof formula, the Runge-Kutta formula, the Laplace transform, and the Fourier series.

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Complete question:

Find the solution to the differential equation dy/dx + 4y = 0, given the boundary values y(0) = 2 and y(2) = 0.

The height of the pendulum can be modeled by the function h(t) = cos(2πt / 3), where t is the time in seconds.

Let's model the height of the pendulum using a cosine function. The angle between the pendulum's widest swing and the vertical hanging position is π/3 (60 degrees). The length of the rope is 4 m, and the height of the ceiling is 5 m.

Calculate the horizontal displacement (x) of the pendulum at its widest swing:

Using trigonometry, we can calculate the horizontal displacement as follows:

x = L × sin(angle)

x = 4 × sin(π/3)

x = 4 × √3/2

x = 2√3 m

Calculate the vertical displacement (h) of the pendulum at its widest swing:

The vertical displacement is the difference between the height of the ceiling and the height of the pendulum at its widest swing. Since the pendulum is initially at rest in the vertical hanging position, the height of the pendulum at its widest swing is equal to the length of the rope (L).

h = ceiling height - L

h = 5 - 4

h = 1 m

Determine the period (T) of the pendulum:

The period (T) is the time taken for one complete swing. In this case, it is given as 3 seconds.

Use the cosine function to model the height of the pendulum as a function of time:

The height (h) of the pendulum can be modeled using the cosine function:

h(t) = A × cos(2πt / T) + C

Where:

A is the amplitude of the pendulum's swing, which is equal to the vertical displacement at its widest swing (h = 1 m).

t is the time.

T is the period of the pendulum (T = 3 seconds).

C is the vertical displacement from the vertical hanging position (C = 0 since we consider vertical to be t = 0).

Substituting the values into the cosine function, we can model the height of the pendulum as a function of time:

h(t) = 1 × cos(2πt / 3) + 0

h(t) = cos(2πt / 3)

This equation represents the height of the pendulum at any given time (t) in seconds, considering the vertical position as t = 0.

So, the height of the pendulum can be modeled by the function h(t) = cos(2πt / 3), where t is the time in seconds.

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Question

A pendulum is connected to a rope 4 m long, which is connected to a ceiling 5 m high. The angle between its widest swing and vertical hanging position is π/3. If the pendulum swings out to its widest position in 3 seconds, model the height of the pendulum using a cosine function, considering vertical to be t = 0.

Answer:

pi/2 units to the left

Step-by-step explanation:

the formula is y = cos(x-b) so when b is negative, the formula will show a plus sign because minus negative is adding. this means the graph is shifted -pi/2 to the right which is really pi/2 to the left

Answer:

The value of x = -2

Step-by-step explanation:

Given equation:

2x + 4 = 0

Find:

The value of x

Computation:

We know that given equation 2x + 4 = 0 is a liner equation with only one variable.

So, we can solve this by elimination method

2x + 4 = 0

Step 1 :

Subtract 4 from both side

2x + 4 - 4 = 0 - 4

2x = -4

Divide 2 from both side

2x / 2 = -4 / 2

x = -2

The value of x = -2

Answer: 13?i really dont know

Step-by-step explanation:

We can think of the limit of f(x) as x approaches c as the value that f(x) approaches as we get arbitrarily close to c, but not necessarily equal to c. On the other hand, f(c) is the actual value of the function at the point x=c, which may or may not be equal to the limit as x approaches c.

If the limit on the left and the limit on the right of a function f(x) as x approaches some value c are both equal to L, then we say that the limit of f(x) as x approaches c exists and is equal to L. In this case, the limit on the left and the limit on the right both equal 5, so we can say that:

lim x->c- f(x) = 5

lim x->c+ f(x) = 5

Since the limits from both sides agree, this means that the limit of f(x) as x approaches c exists and is equal to 5. However, this does not necessarily mean that f(c) is equal to 5 as well. In fact, we're given that f(c) = 20, which is different than the limit.

Geometrically, we can think of the limit of f(x) as x approaches c as the value that f(x) approaches as we get arbitrarily close to c, but not necessarily equal to c. On the other hand, f(c) is the actual value of the function at the point x=c, which may or may not be equal to the limit as x approaches c.

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Answer:

false

Step-by-step explanation:

because there is no solution or answer

The vectors T(e₁) and T(e₂) are linearly independent and form a basis for the image of T. Therefore, option (B) is correct, which gives {(2,0,14), (1,-1,0)} as a basis for the image of T.

To find the kernel of T, we need to solve for the values of (x1, x2, x3) that satisfy T(x1, x2, x3) = (0, 0, 0). Thus, we have:

-7- x₁-7-x2 + x3 = 0

7 x₁ +7x2-x3 = 0

56 x₁ +56 x2 = 0

Simplifying the third equation, we get:

x₁ + x₂ = 0

Using this equation to eliminate x₂ from the first two equations, we get:

-8x₁ + x₃ = 0

Thus, the solutions to the system are given by:

x₁ = t, x₂ = -t, x₃ = 8t

where t is an arbitrary constant. Therefore, the kernel of T is spanned by the vector (-1, 1, -8), which is option (C).

To find the image of T, we need to determine the span of the set of vectors {T(e₁), T(e₂), T(e₃)}, where e₁, e₂, and e₃ are the standard basis vectors in R³. Thus, we have:

T(e₁) = (-7, 7, 56)

T(e₂) = (-8, 0, 56)

T(e₃) = (-9, 14, 0)

To determine which of these vectors are linearly independent, we can form a matrix with the vectors as columns and row-reduce it:

|-7 -8 -9|

| 7  0 14|

|56 56  0|

Row-reducing this matrix, we get:

| 1  0  0|

| 0  1  0|

| 0  0 -1|

Thus, the vectors T(e₁) and T(e₂) are linearly independent and form a basis for the image of T. Therefore, option (B) is correct, which gives {(2,0,14), (1,-1,0)} as a basis for the image of T.

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Rotate the shape about its central axis by making it stationary.

Answer:

11/10°C

Step-by-step explanation:

7 x 3/10 = 21/10

Temperature at Midnight = -1°C

Temperature at 7.00am = 21/10 + (-1°C)

= 11/10°C

Therefore, the surveyor is approximately 61 meters away from the base of the cliff. Rounded to the nearest meter, the answer is 61 meters.

Distance is a numerical measurement of the physical space between two points or objects. It is often expressed in units such as meters, feet, miles, or kilometers, depending on the system of measurement being used. Distance is a scalar quantity, meaning that it has only magnitude and no direction. It is different from displacement, which is the vector quantity that describes the overall change in position of an object, taking into account both magnitude and direction. Distance can be calculated using various methods depending on the context, such as using a ruler or tape measure for small distances or using GPS or other advanced technologies for larger distances.

by the question.

We can use trigonometry to solve this problem. Let's call the distance from the surveyor to the base of the cliff "x". Then, we can use the tangent function to find x:

\(tan(71°) = opposite/adjacent\)

In this case, the opposite side is the height of the cliff (160 meters) and the adjacent side is x, so we have:

\(tan(71°) = 160/x\)

To solve for x, we can multiply both sides by x and divide both sides by tan (71°):

\(x = 160 / tan(71°)\)

Using a calculator, we find that tan (71°) is approximately 2.62, so:

\(x = 160 / 2.62\)

x ≈ 61.07 meters

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The general equation of a circle is written like \((x-h)^2+(y-k)^2=r^2\), where (h,k) is the centre and r is the radius.

Firstly, we're given that the centre is (8,6).

Plug this into the general equation:

\((x-h)^2+(y-k)^2=r^2\\(x-8)^2+(y-6)^2=r^2\)

We're given this other point on the circumference of the circle, (8,0), which is 6 units away from the center.

Therefore, the radius is 6 units. Plug this into the general equation too:

\((x-8)^2+(y-6)^2=r^2\\(x-8)^2+(y-6)^2=6^2\\(x-8)^2+(y-6)^2=36\)

\((x-8)^2+(y-6)^2=36\)

The general solution of the differential equation is given by: \(y(x) = c1*sin(2x) + c2*cos(2x) + c3*x + c4*cos(x) + c5*sin(x) + c6*x^2\)

1. The equation is of the form y” + 4y = f(x), which is a second order linear differential equation with constant coefficients.

2. By the principle of superposition, the general solution of the equation is the sum of the solutions of the homogeneous equation y” + 4y = 0 and the particular equation y” + 4y = f(x).

3. The homogeneous equation has two linearly independent solutions, \(y1 = sin(2x) and y2 = cos(2x)\)

4. The particular equation has three linearly independent solutions, \(y3 = x, y4 = cos(x) and y5 = sin(x).\)

5. Hence, the general solution of the equation is\(y(x) = c1*sin(2x) + c2*cos(2x) + c3*x + c4*cos(x) + c5*sin(x) + c6*x^2\), where c1, c2, c3, c4, c5 and c6 are arbitrary constants.

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Phil's monthly cost function: C(x) = 912, revenue function: R(x) = 464x, and profit function: P(x) = 464x - 912.

The fixed cost for owning the stand is given as $912 per month, which remains constant regardless of the number of rugs made and sold. Therefore, Phil's monthly cost function C(x) is simply the fixed cost: C(x) = 912.

The revenue generated from selling the rugs is dependent on the number of rugs made and sold each month. Since Phil earns $464 for each rug sold, his revenue function R(x) can be expressed as R(x) = 464x, where x represents the number of rugs made and sold.

To calculate Phil's profit, we subtract his total costs from his revenue. The profit function P(x) is given by P(x) = R(x) - C(x). Substituting the expressions for R(x) and C(x), we have P(x) = 464x - 912.

Therefore, Phil's monthly cost function is C(x) = 912, his revenue function is R(x) = 464x, and his profit function is P(x) = 464x - 912. These functions allow us to determine the cost, revenue, and profit associated with different quantities of rugs made and sold each month.

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