what is the phph at the half-equivalence point in the titration of a weak base with a strong acid? the pkbpkb of the weak base is 8.60.

Answer:

if you plant them all at the same time they should all grow evenly..or somehow evenly

Explanation:

I'm thinking but if they are all different I think it doesnt matter bc they are all the same plant..ya know?

The final temperature of the water is 308 K.

To find the final temperature of the water, we need to use the formula Q = mcΔT, where Q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. The heat lost by the iron will be equal to the heat gained by the water, so we can set the equations equal to each other and solve for the final temperature.

  Qiron = Qwater

Heat lost by iron:

  Q = iron mass x specific heat of iron x temperature of iron

      = 25 x 0.449 x (398 - T)

Heat gained by water:

  Q = water mass x specific heat of water x temperature of water

      = 25 x 4.18 x (T - 298)

Since heat lost = heat gained, therefore:

  25 x 0.449 x (398 - T) = 25 x 4.18 x (T - 298)

                        115.725T = 35608.55

                                    T = 308 K

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Answer:

I believe the answer is

\(C. \: Beaker \: A\)

Explanation:

I hope my answer is correct!

Hope this helps!

(:

To calculate the total pressure in the flask, we need to convert all the partial pressures to the same unit and then add them together. We can convert the partial pressures of oxygen and ammonia to atm using the following conversions:

1 atm = 760 torr

1 atm = 101.325 kPa

Partial pressure of oxygen in atm = 643 torr / 760 torr/atm = 0.846 atm

Partial pressure of ammonia in atm = 2865 kPa / 101.325 kPa/atm = 28.27 atm

Now we can add up all the partial pressures in atm:

Total pressure in atm = Nitrogen partial pressure in atm + Oxygen partial pressure in atm + Ammonia partial pressure in atm

Total pressure in atm = 9.84 atm + 0.846 atm + 28.27 atm

Total pressure in atm = 38.956 atm

Therefore, the total pressure in the flask is 38.956 atm (rounded to three decimal places).

The percent composition by mass of the sugar solution is 22.97%.

To find the percent composition by mass of the sugar solution, we need to first calculate the mass of the sugar cube and the mass of the water in the teacup.

The mass of the sugar cube can be calculated using its density, which is 1.59 g/cm³ (this information is not given in the question, but it is a common value for sucrose). Therefore, the mass of the sugar cube is:

A4 = 4 cm x 4 cm x 4 cm = 64 cm³
Mass of sugar cube = density x volume = 1.59 g/cm³ x 64 cm³ = 101.76 g

The mass of the water can be calculated using its density at 80°C, which is 0.975 g/mL. Therefore, the mass of the water in the teacup is:

Mass of water = density x volume = 0.975 g/mL x 350 mL = 341.25 g

The total mass of the sugar solution is therefore:

Total mass = mass of sugar + mass of water = 101.76 g + 341.25 g = 443.01 g

The percent composition by mass of the sugar solution is then:

% composition = (mass of sugar / total mass) x 100%
% composition = (101.76 g / 443.01 g) x 100% = 22.97%

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Answer:

B holding together molecules in a material

Explanation:

Intermolecular forces are primarily responsible for holding together molecules in a material due to the fact that they are interactive forces between molecules

Explanation:

When 6.38 moles of O2 and 9.15 moles of Al react, the ratio of aluminum to oxygen is 9.15/6.38 = 1.434. This shows that all of the oxygen is consumed before the aluminum and when the reaction ends the reactant aluminum is left. The number of moles of Al2O3 formed is approximately 4.25 moles.

d) stronger bases favor the E1 reaction statement about and E1 mechanism is not true

Ionization and deprotonation are typically the two stages involved in the E1 mechanism, also known as unimolecular elimination. The production of a carbocation occurs as an intermediate during ionisation. A proton is lost by the carbocation in deprotonation. SN1 and E1 Reactions have remarkably similar processes; the outcome just depends on whether the nucleophile or the base hits first. The pace of the reaction is solely dependent on the substrate in SN1/E1 reactions as opposed to second order SN2 and E2 reactions (see "SN2 Reactions" and "E2 Reactions").

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Answer:

The first person to use the term "atom" was Democritus.

Answer:

Democritus

Explanation:

Answer:

J.J. Thomson’s experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson proposed the plum pudding model of the atom, which had negatively-charged electrons embedded within a positively-charged “soup.”

Answer:

The fly cells must be compared with human cells

Explanation:

Dr. Gracia's aim is the development of a potential cancer treatment. Remember that the treatment is meant for human beings.

Usually, the pre-clinical trials of the treatment is carried out on other organisms and the success rate is evaluated before trial on humans.

If protein W has been effective on flies, its effect on human cells should also be diligently compared before conclusions are drawn regarding the therapeutic effects of protein W.

The molarity of sodium carbonate is 3.73 M

The molarity of sodium carbonate can be calculated as shown below.

M = moles of solute/liters of solution

Convert the volume from milliliters (mL) to liters (L):

1500 mL = 1500/1000 L = 1.5 L

Substitute the respective values in the above equation.

M = 5.60 mol / 1.5 L

M ≈ 3.73 M

Therefore, the molarity of the solution is approximately 3.73 M.

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The following species can be listed in order of decreasing boiling point:

CO2>O3>N2>O2>H2

The boiling point of gases depends upon the strength of the intermolecular forces of attraction acting between them and the molecular weight of the gaseous species.

The reasons for the order of decreasing boiling point can be stated as:

For CO2- CO2 has the highest boiling point due to the3 polar covalent bond between the carbon and oxygen atoms. It also exhibits dipole-dipole interactions.

For Ozone(O3)- It also has polar covalent bonds but also exhibits London dispersion forces which are a type of weak intermolecular forces.

For Nitrogen(N2)- The intermolecular forces(London dispersion force) are weak and N2 is a nonpolar molecule.

For Oxygen(O2)- O2 is also nonpolar and exhibits London dispersion force.

Hydrogen(H2)- It is also a non-polar molecule exhibiting London dispersions forces due to its low molecular weight and small size.

Hence due to the above-mentioned reasons, the decreasing order of boiling point is:

CO2>O3>N2>O2>H2

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Answer:

welp it would be this option : Move the decimal in 85 TWO places to the right to decrease the value.

Explanation:

Answer:

Option A

Explanation:

Moving the decimal point 2 places to the right will give you 8500 cm=85m

The pH of a solution made by dissolving 0.00135 moles of KOH in water to make 2.7l of solution is 10.70.

To find the pH of a solution made by dissolving 0.00135 moles of KOH in 2.7 liters of water, follow these steps:

1. Calculate the concentration of OH- ions:
Concentration of OH- ions = moles of KOH / volume of solution
= 0.00135 moles / 2.7 L
= 0.0005 mol/L (rounded to 3 decimal places)

2. Calculate the pOH of the solution:
pOH = -log10(concentration of OH- ions)
= -log10(0.0005)
= 3.30 (rounded to 2 decimal places)

3. Calculate the pH of the solution:
pH = 14 - pOH
= 14 - 3.30
= 10.70 (rounded to 2 decimal places)

The pH of the solution is 10.70.

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It takes 1773.0 mL of ethyl alcohol solution to generate a 100 ml of 5.64% (v/v) aqueous solution.

Beer, wine, and spirits all contain methanol when they are diluted. It is a topical ingredient used in pharmaceutical formulations (such as rubbing compounds, creams, tonics, and colognes), perfumes, and scents to combat skin infections.

Volume-by-volume % concentration of a solution,

How many milliliters of solute are present in 100 mL of solution is expressed as 5.64% v/v.

In this instance.

The 5.64% v/v solution will include:

For every 100 mL of solution, there is 5.64 mL of solute.

Therefore, you must have the ethyl alcohol needed to create a 5.64% (v/v) aqueous solution in 100 ml of solute.

100 mL of solution * 100 mL of solute/ 5.64mL of solute

=1773.04 mL of liquid.

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Answer:

150

Explanation:

300 divided by 2

Answer:

c

Explanation:

Answer:

it is number 2

Explanation:

hope this helps it is number 11

Answer:

1.Frequency

2.Amplitude

3.Wavelength

4.Medium

5.Back and Forth

6.Up and Down

Explanation:

CORRECT ME IF I'm wrong

Answer:

A) It increases when the concentration of reactants increases.

Explanation:

When you increase the concentration, there is more of a substance, and therefore more opportunities for the reactants to collide together with enough energy to create a product.

Answer:

A) It increases when the concentration of reactants increases.

Explanation:

It's just right!!!

Fractional distillation is used for the refining of crude petroleum.

Fractional distillation is the procedure used to separate crude oil's numerous constituents.

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The final temperature of the gas is approximately 40.96 Kelvin.

To determine the final temperature of the gas, we can use the ideal gas law, which states:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature in Kelvin.

First, let's convert the given temperatures to Kelvin. We have:

Initial temperature: -125 degrees Celsius = 148 K (approximate)

Final temperature: Unknown

The initial conditions of the gas are as follows:

Initial pressure (P1) = 1.25 atm

Initial volume (V1) = 1250 mL = 1.25 L (since 1 L = 1000 mL)

Initial temperature (T1) = 148 K

The final conditions of the gas are as follows:

Final pressure (P2) = 50.0 atm

Final volume (V2) = 325 mL = 0.325 L

Final temperature (T2) = Unknown

Using the ideal gas law, we can set up the following equation:

(P1 * V1) / T1 = (P2 * V2) / T2

Substituting the known values:

(1.25 atm * 1.25 L) / 148 K = (50.0 atm * 0.325 L) / T2

Simplifying the equation:

T2 = (50.0 atm * 0.325 L * 148 K) / (1.25 atm * 1.25 L)

T2 = 40.96 K

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When the negatively charged metal ball comes in contact with the iron bar, the positive charges of the bar aligns near to the negative charges and they electrostatically attracts results in a static electricity.

When a negatively charged body is comes in contact with an conductor or an insulator, the random charges gets polarized, where the positive charges of the second object align with the negative charges and there occurs a flow of electron from the negatively charged object. This is called static electricity.

A metal in its neutral state contains a sea of positive ions and free electrons. Here, the when the negatively charged metal ball comes near the iron bar, the iron bar gets polarized.

The positive charges of the iron bar gets polarized near the negative charge of the ball and there occurs an electrostatic force of attraction. Electrons from the negative charged ball tends to flow to the conductive iron bar and leads to a static electricity.

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Two substances that have the same pH value are ammonia and sodium bicarbonate. The reason for this is because both of these substances act as weak bases.

The pH value is a measure of acidity or alkalinity in a solution. The pH scale ranges from 0 to 14. A pH value of 7 is neutral, a pH value less than 7 is acidic, and a pH value greater than 7 is basic or alkaline. The pH value of ammonia is 11.0, and the pH value of sodium bicarbonate is 8.3.The pH value of ammonia is high because it is a basic substance. It reacts with water to form ammonium ions and hydroxide ions.

The concentration of hydroxide ions in a solution is what determines the pH value. In other words, a solution with more hydroxide ions has a higher pH value. Since ammonia has a high concentration of hydroxide ions, its pH value is high.Sodium bicarbonate is also a weak base. It reacts with water to form bicarbonate ions and hydroxide ions. The concentration of hydroxide ions in a solution is what determines the pH value. Since sodium bicarbonate has a low concentration of hydroxide ions, its pH value is low compared to ammonia.

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The voltage across the 200 ohm circuit element, that draws a current of 4 A, is equal to 800 volts.

To find the voltage across a circuit element, take Ohm's Law, according to which the resistance (R) of a resistor is equal to the product of the current (I) that flows through it and the voltage (V) across it.

Use the values:

Current (I) = 4 A

Resistance (R) = 200 Ω

Using the formula of Ohm's Law:

V = I × R

V = 4 A × 200 Ω

V = 800 V

Voltage is  800 V.

Thus, the voltage across the 200 ohm circuit element, that draws a current of 4 A, is 800 volts.

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Glycogen, a polymer of glucose, is held together by glycosidic bonds, including the bonds at its branch points.

Glycogen is a complex carbohydrate that serves as a storage form of glucose in animals, including humans. It is made up of glucose units linked together through glycosidic bonds. These bonds form between the hydroxyl (OH) group of one glucose molecule and the anomeric carbon (C1) of another glucose molecule, resulting in a linear chain of glucose units.

Additionally, glycogen has branch points where the chain is extended by the formation of α-1,6-glycosidic bonds. These branch points contribute to the highly branched structure of glycogen, allowing for more efficient storage and rapid release of glucose when needed.

Therefore, the bonds that hold glycogen together, both in the linear chain and at the branch points, are glycosidic bonds. These bonds play a crucial role in maintaining the integrity and functionality of glycogen as a storage form of glucose in the body.

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Answ

Explanation:

true

Answer:

Chemical

Explanation:

Because it's being done by chemical means