Answer:
51.2Joules
Explanation:
Work done = Force × distance
Force = mg = 64.5×9.81
Force = 632.745N
Next is to get the distance using the equation of motion
v² = u²+2gS
1.26² = 0+2(9.81)S
1.5876 = 19.62S
S = 1.5876/19.62
S = 0.0809m
Get the work done:
Work done = F×S
Work done = 632.745×0.0809
Work done = 51.2Joules
Hence the net work done in Joules is 51.2Joules
The net work done required to stop a crate will be "51.2 Joules".
Force and MassAccording to the question,
Mass, m = 64.5 kg
Speed, v = 1.26 m/s
Acceleration due to gravity, g = 9.8
We know,
The force, F = mg
By substituting the values,
= 64.5 × 9.8
= 632.745 N
By using Equation of motion,
→ v² = u² + 2gS
(1.26)² = 0 + 2(9.81) S
1.5876 = 19.62 S
S = \(\frac{1.5876}{19.62}\)
= 0.0809 m
hence,
The work done (W) will be:
= F × S
= 632.745 × 0.0809
= 51.2 Joules
Thus the above response above is correct.
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A very dense 1500-kg point mass (A) and a dense 1200-kg point mass (B) are held in place 1.00 m apart on a frictionless table. A third point mass is placed between the other two at a point that is 20.0 cm from B along the line connecting A and B. When the third mass is suddenly released, find the magnitude and direction (toward A or toward B) of its initial acceleration.
Answer:
Explanation:
Let m be the third point mass
Force pulling toward A
Fa = Gm(1500)/0.800² = 2343.75Gm
Force pulling toward B
Fb = Gm(1200)/0.200² = 30000Gm
Net force acting on m
30000Gm - 2343.75Gm = 27656.25Gm
a = F/m = 27656.25Gm/m = 27656.25G
a = 27656.25(6.674 x 10⁻¹¹) = 1.8457... x 10⁻⁶ m/s² towards mass B
HELPPP WILL MARK BRAINLIST What type of image is formed by a lens if m= 2.7?
A. The image is smaller than the object and is virtual.
B. The image is smaller than the object and is real.
C. The image is larger than the object and is real.
D. The image is larger than the object and is virtual.
Answer:
I GOTCHU FAM
The image is larger than the object and is virtual.
Explanation:
JUST DID DA QUIZ BOI
Magnification is the measure of the nature of images and their size. The image formed by a lens if the magnification is 2.7 is larger and virtual.
What is magnification?Magnification is the ratio of image height to object height. The positive magnification means the image is virtual, formed by the convex mirror and vice-versa.
Thus, the image formed by a lens if the m = 2.7 is larger than the object and virtual. The correct option is D.
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A force of 250 N is exerted on a cable wrapped around a drum with a diameter of 20 cm. What is the torque produced about the centre of the drum?
The torque that is produced at the center of the drum is 50 Nm.
What is a torque?The term torque has to do with a force that leads to a turning effect. I can use the example of a tap to show you what is meant by a torque. The force that is exerted on a tap causes the tap to turn and this is what we mean by saying that a torque would produce a turning effect.
We have the following;
Force = 250 N
Distance = 20 cm or 0.2 m
Torque = 250 N * 0.2 m
= 50 Nm
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Why is seismology (the study of earthquakes) important?
Answer:
It is importants because it facilitates the monitoring and analysis of global earthquakes and other sources of seismic activity.
Explanation:
On a hot summer night (32°C), you are listening to a rock group in a stadium 350 m away. A friend of yours is sitting in an air-conditioned house across the country, listening to the broadcast on the radio. If the signal travels 30,000 km up to a satellite that retransmits it, who hears the concert first (speed of signal = 3.00 x 108 m/s)?
In ou case we have
\(\text{Temp}=331.4+(0.606\cdot32)=350.8\text{ m/s}\)Then for the case of the friend
\(\text{Friend}=300,000,000\text{ m/s}\)Therefore the person who hears the concert first is your friend
ANSWER
Your friend
What must the charge (sign and magnitude) of a particle of mass 1.48 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 640 N/C
Answer:
\(q=-2.26\times 10^{-5}\ C\)
Explanation:
Given that,
The mass of a particle, m = 1.48 g = 0.00148 kg
The electric field, E = 640 N/C
We need to find the charge of the particle when placed in a downward-directed electric field.
The force of gravity is balanced by the electric force such that,
mg = qE
Where
q is the charge of the particle
\(q=\dfrac{mg}{E}\\\\q=\dfrac{0.00148\times 9.8}{640}\\\\q=2.26\times 10^{-5}\ C\)
q must be negative, the force must be upward (opposite direction of the electric field).
A dielectric block such as shown in Fig. P5.1 is uniformly polarized. The polarization is P. Find the polarization charge density , on the faces 1, 2, and 3. (Find both magnitude and sign of the charge.) P Fig. P5.1
The vector field that expresses the density of induced or permanent electric dipole moments in a dielectric medium is known as polarization density (also known as electric polarization or just polarization).
Thus, A dielectric is considered to be polarized when its molecules acquire an electric dipole moment when exposed to an external electric field.
Electric polarization of the dielectric is the term used to describe the electric dipole moment induced per unit volume of the dielectric material.
The forces that emerge from these interactions can be calculated using the polarization density, which also defines how a material reacts to an applied electric field and how it modifies the electric field. It is comparable to magnetization, which measures a material's equivalent response.
Thus, The vector field that expresses the density of induced or permanent electric dipole moments in a dielectric medium is known as polarization density (also known as electric polarization or just polarization).
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In machines with low efficiency, most of the lost energy is turned into?
a. Light
b. Sound
c. Power
d. Heat
Answer:
Option (C)
Explanation:
All electric machines are not ideal, therefore they have some losses due to which efficiency being less than 100%.
the video states that the planetary orbits are shown to scale. which statement correctly describes the way the planet sizes are shown compared to their orbits?
In relation to their orbits, all of the planets are substantially too big. According to Kepler's first law, the Sun is at one focus of each planet's elliptical orbit.
What one of the following traits does each planet inside the solar system share?It specifies three requirements for a planet: It must revolve around the Sun, a planet in our solar system. It must be large enough for gravity to pull it in a spherical direction. It must have been large enough that any nearby objects of a similarly sized were removed by its gravitational pull.
Which of following traits applies to all four inner solar system planets?The interior planets are all solid rocky, dense planets The moons of the inner planets are either absent or limited to one Earth or three Mars. The inner planets don't have any rings. The planets orbits have smaller orbits all around Sun than the outer planets, but they all rotate more slowly.
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A race car makes one lap around a track of radius 50 m in 9.0 s. What was the car's centripetal acceleration?
The velocity of the car is 5.5 m/s. Then the centripetal acceleration of the car will be 0.6 m/s².
What is centripetal acceleration?Acceleration is a physical quantity measuring the rate of change in velocity. It has both magnitude and direction.
Centripetal acceleration is the acceleration of an object moving through a circular path. Thus its measures the rate of change in velocity of the body moving in the curvature path.
The centripetal acceleration = V²/R.
Where R is the radius of the curvature path.
The car moves 50 m in 9 seconds. Its velocity is 50/9 = 5.5 m/s.
Thus, centripetal acceleration = (5.5 × 5.5) m/s/ 50 m = 0.6 m/s².
Therefore, the centripetal acceleration of the car moving at a speed of 9 m/s through curvature path is 0.6 m/s².
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When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 53.5 N and it is acting with an effective lever arm of 2.25 cm , what is the torque that the muscle produces on the wrist
Answer:
1.20Nm
Explanation:
Given data
Force= 53.5N
Perpendicular distance= 2.25cm= 2.25/100= 0.0225m
The expression for the torque is given as
Torque= Force* Perpendicular distance
Torque= 53.5*0.0225
Torque= 1.20Nm
Hence the toque produced is 1.20Nm
If a third resistor is added in a parallel to the other 2 resistors, How will that affect the brightness of the original 2 light bulbs?
The original two light bulbs will appear brighter when the third resistor is added in parallel.
When a third resistor is added in parallel to the other two resistors in a circuit, it will have an impact on the overall brightness of the original two light bulbs.
In a parallel circuit, each resistor has its own branch connected to the power source. The current flowing through each branch is inversely proportional to the resistance of that branch. Adding a third resistor in parallel means an additional path for current to flow.
The introduction of the third resistor reduces the total resistance of the circuit. As a result, the total current drawn from the power source increases, as per Ohm's Law (I = V/R). The increased current is distributed among the parallel branches, including the original two light bulbs.
Since the current through the bulbs is now greater, their brightness will also increase. This is because the brightness of an incandescent light bulb is directly proportional to the current passing through it.
It's worth noting that the specific effect on brightness depends on the resistance values of the resistors and the characteristics of the light bulbs. However, in general, adding a resistor in parallel reduces the overall resistance, increases the current, and subsequently enhances the brightness of the light bulbs in the circuit.
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The uniform beam has a weight W and length L and is supported by a pin at A and cable BC ( figure 1)
Part A
Determine the horizontal and vertical components of reaction at A
Express your answers in terms of some or all of the variables W, R. Φ and θ). Enter your answers separated by a comma.
View Available Hint's)
Aa + Ay = ____
Parts B
Determine the one cable car necessary to hold the beans position shown
Express your answers in terms of some or all of the variables W, R. Φ and θ).
The reaction is in A in vertical direction is W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ).
What is Normal Stress and Strain?In terms of psychology, "stress" and "strain" are sometimes used interchangeably in popular culture, as in the expressions "I'm feeling stressed" or "I'm under a lot of pressure."
In engineering, these phrases have specific, technical meanings. If a hook in the steel wire is attached,
If you hang the wire from the ceiling while placing a weight on the lower end, it will sag. By dividing the length change by the starting length, the strain in the wire may be computed.
Thus, as per the given scenario, W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ) will be the equation.
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A constant torque of 3 Nm is applied to an unloaded motor at rest at time t = 0. The motor reaches a speed of 1,393 rpm in 4 s. Assuming the damping to be negligible, calculate the motor inertia in Nm·s2.
Answer:
The moment of inertia of the motor is 0.0823 Newton-meter-square seconds.
Explanation:
From Newton's Laws of Motion and Principle of Motion of D'Alembert, the net torque of a system (\(\tau\)), measured in Newton-meters, is:
\(\tau = I\cdot \alpha\) (1)
Where:
\(I\) - Moment of inertia, measured in Newton-meter-square seconds.
\(\alpha\) - Angular acceleration, measured in radians per square second.
If motor have an uniform acceleration, then we can calculate acceleration by this formula:
\(\alpha = \frac{\omega - \omega_{o}}{t}\) (2)
Where:
\(\omega_{o}\) - Initial angular speed, measured in radians per second.
\(\omega\) - Final angular speed, measured in radians per second.
\(t\) - Time, measured in seconds.
If we know that \(\tau = 3\,N\cdot m\), \(\omega_{o} = 0\,\frac{rad}{s }\), \(\omega = 145.875\,\frac{rad}{s}\) and \(t = 4\,s\), then the moment of inertia of the motor is:
\(\alpha = \frac{145.875\,\frac{rad}{s}-0\,\frac{rad}{s}}{4\,s}\)
\(\alpha = 36.469\,\frac{rad}{s^{2}}\)
\(I = \frac{\tau}{\alpha}\)
\(I = \frac{3\,N\cdot m}{36.469\,\frac{rad}{s^{2}} }\)
\(I = 0.0823\,N\cdot m\cdot s^{2}\)
The moment of inertia of the motor is 0.0823 Newton-meter-square seconds.
A horizontal force is applied to push a 105 N trunk across the floor to the left with an acceleration of 25.1 m/s2. The coefficient of sliding friction between the trunk and the desk is 0.63.
With a 25.1 m/s2 acceleration, 2,946.19 N of horizontal force is required to push the trunk across the floor to the left.
What is the friction coefficient formula?Usually, the Greek letter mu is used to indicate it (). is mathematically equivalent to F/N, where F denotes frictional force and N is normal force. Due to the fact that F and N are both measured in units of force, the coefficient of friction has no dimensions (such as newtons or pounds).
An object's mass times its acceleration equals the object's net force:
F_net = m * a
The applied force less the frictional force equals the net force acting on the trunk:
F_net = F_applied - F_friction
The force of friction is given by:
F_friction = μ * N
As there is no vertical acceleration of the trunk, its weight is equal to the normal force:
N = m * g
where g is the gravitational acceleration.
When you combine everything, you get:
F_net = F_applied - μ * m * g = m * a
With the applied force factored in, we obtain:
F_applied = m * (a + μ * g)
Plugging in the given values, we get:
F_applied = 105 N * (25.1 m/s^2 + 0.63 * 9.81 m/s^2) = 2,946.19 N
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Two blocks are attached by a string as shown. The blocks are released from rest and
allowed to move freely. The sloped ramp angle is θ = 30⁰. Find the coefficient of friction
on the blocks (assume they have the same coefficient), assuming the blocks have the
same mass, and given that the blocks travel a distance of 0.50 m in a time of 0.935 s.
The coefficient of friction between the two blocks is 0.194.
The problem involves finding the coefficient of friction between two blocks of equal mass attached by a string that moves over a sloped ramp with an angle of 30 degrees. The blocks start from rest and are allowed to move freely. The distance traveled by the blocks is 0.50 m, and the time taken to travel this distance is 0.935 s. To solve the problem, we need to consider the forces acting on the system of blocks. The forces acting on the blocks are the gravitational force, the tension in the string, and the frictional force. As the blocks are moving up the ramp, the force of gravity is pulling them down. The tension in the string is pulling the blocks up the ramp. The frictional force is opposing the motion of the blocks and is acting in the opposite direction to the tension in the string.
To determine the coefficient of friction, we can use the equations of motion to find the acceleration of the blocks. Once we have the acceleration, we can use Newton's Second Law to find the net force acting on the blocks. We can then use the force of friction to find the coefficient of friction. Using the equations of motion, we can find the acceleration of the blocks:
a = 2d/t^2
where d is the distance traveled by the blocks and t is the time taken to travel the distance. Plugging in the given values, we get:
a = 2(0.50 m)/(0.935 s)^2 = 1.15 m/s^2
Next, we can use Newton's Second Law to find the net force acting on the blocks:
ΣF = ma
where ΣF is the sum of the forces acting on the blocks. Plugging in the known forces, we get:
T - mg sin θ - μmg cos θ = ma
where T is the tension in the string, m is the mass of the blocks, g is the acceleration due to gravity, θ is the angle of the ramp, and μ is the coefficient of friction.
We can simplify this equation by substituting mg sin θ for the component of the weight of the blocks that is acting down the ramp and mg cos θ for the component of the weight that is acting perpendicular to the ramp:
T - mg sin θ - μmg cos θ = ma
T - mg(1/2) - μmg(√3/2) = ma
We can also use the equation for the tension in the string:
T = 2mg sin θ
Substituting this into the equation for net force, we get:
2mg sin θ - mg(1/2) - μmg(√3/2) = ma
Simplifying and solving for μ, we get:
μ = (2gsinθ - a)/(2gcosθ)
Substituting the given values, we get:
μ = (2(9.81 m/s^2)sin 30° - 1.15 m/s^2)/(2(9.81 m/s^2)cos 30°) = 0.194
Therefore, the coefficient of friction between the two blocks is 0.194.
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3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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which statement describes the molecules and a reaction once it reaches equilibrium
A. They maintain stable concentrations
B. They stop moving
C. They consist mainly of reactant molecules
D. They react only if they are disturbed
Answer:
They maintain stable concentrations
Explanation:
Just took the test.
The statement describes the molecules and a reaction once it reaches equilibrium: they maintain stable concentrations, which is option A as the When a chemical reaction reaches equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction.
What is equilibrium?Equilibrium is a dynamic state, meaning that the reaction is still ongoing but the rates of the forward and reverse reactions are equal. This means that molecules are still reacting with each other, but at a constant rate, so that the concentrations of the reactants and products remain stable. When a reaction is not at equilibrium, the concentrations of the reactants and products change as the reaction progresses. However, once equilibrium is reached, the concentrations of the reactants and products no longer change, but the individual molecules are still moving and reacting with each other.
Hence, The statement describes the molecules and a reaction once it reaches equilibrium: they maintain stable concentrations, which is an option. A
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How to find the angle in a projectile motion when displacement and heigh are the same
projectile's vertical speed v yv y v, start , y, drops prior to reaching its maximum height since its acceleration is in the opposite direction. Since the object's height is rising, the initial direction of the velocity is upward
.
At the projectile's highest point, vertical velocity zeroes out. After reaching the highest point, the vertical speed increases due of the same-direction acceleration. As the object's height lowers, the vertical velocity has a downward direction.
In projectile The beginning vertical velocity determines the maximum height. Increasing the launch angle raises the maximum height because steeper launch angles have a larger vertical velocity component.
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You and your friends are at the lake on a particularly sunny day. Use specific heat capacity to explain why the sand on the shores of the lake feels so much hotter than the water in the lake even though the same solar energy is being absorbed by both materials.
Answer:
well the water is way bigger and cant hold much heat while the sand
is smaller than the ocean and is able to hold heat
Explanation:
i dont have one ;-;
Answer:
hi
Explanation:
[SHOW YOUR WORK] A 2000 kg car at rest at the top of a 1000 meter
high hill rolls down to the bottom. a) Assuming no friction is acting to slow
down the car as it rolls down the hill, how fast is it going when it reaches
the bottom of the hill? b) Assuming that there is friction stopping the car
when it reaches the bottom of the hill - how much work is done to stop
the car? c) How much friction force is required to stop the car in 100
meters?
Answer:
Explanation:
Potential energy is converted to kinetic energy
½mv² = mgh
a) v = √2gh = √2(9.8)(1000) = 140 m/s
Assuming the car is now on horizontal ground, The work will convert the kinetic energy to friction heat
b) W = ½mv² = ½(2000)140² = 19,600,000 J = 19.6 MJ
c) W = Fd
F = 19600000/100 = 196000 N = 196 KN
Sounds like a job for a parachute!!!
Answer:
a) 140 m/s
b) 19.6 MJ
c) 196 KN
Explanation:
will give brainliest pls help
Answer:
a and c
Explanation:
A car is traveling at a constant velocity of 20 m/s for 45 seconds. How far does the car go?
Answer: My bad bro. Just tryna get me some points g
Explanation: tuff
Answer:
Explanation:
D=s*t
D=(20)(45)
D=900m.
hope it helps
In the image below, a worker is pushing a crate with a mass of 10 kg up a
ramp at a constant rate. Ignoring friction, how much force must the worker
apply so that the crate continues to move at the same speed? (Recall that g =
9.8 m/s²)
A. 25.6 N
B. 67.5 N
C. 16.2 N
D. 49.0 N
Answer:
D. 49N
Explanation:
Because there is no acceleration the sum of the forces in the x-direction is zero. Your weight force is mass x gravity which is 98N. The x-component of which is sin(30). 98sin30 = 49N in the negative x-direction. -49N + The force applied by the worker must equal zero. So, the force applied by the worker must be 49N.
the efficiency of combine double pulley is 60 how much load is lifted using 50n effort
The amount of load lifted by the pulley when the efficiency is 60% and effort is 50 N is determined as 30 N.
What is the amount of load lifted?The amount of load lifted by the pulley is calculated by applying the formula for efficiency of a machine as follows;
E = L / E x 100%
where;
L is the load overcome or output workE is the effort applied or the input workThe amount of load lifted by the pulley is calculated as;
60 = L / 50 x 100%
60 = 100L / 50
100L = 50 x 60
100 L = 3000
L = 3000 / 100
L = 30 N
Thus, the amount of load lifted by the pulley is 30 N.
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A 4-stroke heat engine in an automobile is
used to
A convert mechanical energy into heat
energy.
B convert heat energy into mechanical
energy.
с convert steam into solar energy.
D convert chemical energy into electrical
energy.
Answer:
b
Explanation:
convert heat energy into mechanical
A chemical system is considered to have reached dynamic equilibrium when:__________.
a. the frequency of collisions between the reactant molecules is equal to the frequency of collisions between the product molecules.
b. the rate of production of each of the product species is equal to the rate of consumption of each of the reactant species. c. the rate of production of each of the products is equal to the rate of their consumption by the reverse reaction.
d. the sum of the concentrations of each of the reactant species is equal to the sum of the concentrations of each of the product species.
e. the activation energy of the forward reaction is equal to the activation energy of the reverse reaction.
Answer:
D
Explanation:
Sum of the concentrations of each of reactant species is equal to the sum of the concentrations of each of the product species
explain why the ray does not bend when it enters the semi circular glass block
The ray does not bend when it enters the semi circular glass block - Light ray incident on semicircular block at 90 degrees, therefore there is no change in the direction of ray at P.
Electromagnetic radiation that falls within the region of the electromagnetic spectrum that the human eye can see is known as light or visible light.
Light is electromagnetic radiation that the human eye can perceive. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than around 1 1011 meters, electromagnetic radiation occurs throughout an incredibly broad range of wavelengths.
Light governs our sleep-wake cycle and is crucial to our health and wellbeing. In actuality, "light" that is visible is a type of radiation, which is just energy that moves in the form of electromagnetic waves. It can alternatively be explained as a flow of "wave-packets," or particles, known as photons.
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How much work is done by a babysitter who uses 8000 W of power to lift a baby in 2s?
Answer:
16000 Joules
Explanation:
8000W x 2
During a group project, two students constructed a simple machine to add to their Rube Goldberg project. They were told to create one that demonstrates the concept of force-distance tradeoff. One student created model A and the other students created model B.
image
Using the CER method, which model best demonstrates the force-distance tradeoff and why?
Answer:
Image B
Explanation:
although I'm not exactly sure, i've recently gotten this question as well. but model B demonstrates the force- distance trade off because you can see how in that image them distance is increased in the force is decreased with the object being shorter. hopefully this helps in some way