what is the fluid speed (in m/s) in a fire hose with a 7.50 cm diameter carrying 81.0 l of water per second? m/s

Answers

Answer 1

The fluid speed (in m/s) in a fire hose with a 7.50 cm diameter carrying 81.0 l of water per second is 3.42 m/s.

We need to use the equation for the volume flow rate of a fluid through a pipe:

Q = A * v

where:

Q is the volume flow rate,

A is the cross-sectional area of the pipe, and

v is the fluid speed.

First, let's convert the diameter of the fire hose from centimeters to meters:

Diameter = 7.50 cm = 0.075 m

Next, we can calculate the cross-sectional area of the hose:

A = π * (Diameter/2)^2

Now we can plug in the values into the equation:

81.0 L/s = A * v

We need to convert liters to cubic meters:

81.0 L/s = 0.081 m^3/s

Solving for the fluid speed (v):

v = (0.081 m^3/s) / A

v = (0.081 m^3/s) / (π * (0.075/2)^2)

v ≈ 3.42 m/s

Therefore, the fluid speed in the fire hose is approximately 3.42 m/s.

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Related Questions

Which of the following do NOT make up our personality? behaviors skills and abilities feelings thoughts

Answers

Skills and abilities do not make up our personality.

What is  our personality?

Personality encompasses an intricate amalgamation of traits that define our individuality, comprising our cognitions, emotions, and actions. It is shaped by a combination of genetic predispositions and environmental factors.

Individuals with diverse personality profiles exhibit distinct patterns of thinking, emoting, and engaging in conduct. By comprehending our individual personality traits, we empower ourselves to make wiser decisions and cultivate lives imbued with greater happiness and well-being.

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get distance calculated with varying fa 5.0 kg dog sits on the floor of an elevator that is moving downward with a constant speed of 9.8 m/s. what is the magnitude of the normal force of the elevator floor on the dog?orce

Answers

The magnitude of the normal force of the elevator floor on the 5.0 kg dog when it sits on the floor of an elevator that is moving downward with a constant speed of 9.8 m/s is 49N.

To find the magnitude of the normal force of the elevator floor on the dog.

The normal force (N) is the perpendicular force that a surface exerts on an object in contact with it, preventing the object from falling through the surface.

Hence the Distance is  calculated with varying force.

Now the force acting on the dog is its weight, which is equal to (mass x acceleration due to gravity).

W = m × g

where mass of dog (m) = 5.0 kg

acceleration due to gravity (g) = 9.8 m/s²

Substituting the values we get,

W = 5.0 kg × 9.8 m/s²

W = 49 N

This is the gravitational force acting on the dog downwards.

The normal force (N) acting on the dog is equal in magnitude and opposite in direction to this force (due to the third law of motion).

Hence, the magnitude of the normal force of the elevator floor on the dog is 49 N.

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need help asap, thank you !
In the absence of air resistance, a projectile launched at an angle of 33 above the horizontal will have the same range as a projectile launched at which of the following angles? O 38 O 57⁰ 0:45. 07

Answers

A projectile is launched at an angle of 33⁰ above the horizontal, then the projectile launched at an angle of 90 - 33 = 57⁰ will have the same range as the projectile launched at 33⁰. The correct option is (B) 57⁰.

In the absence of air resistance, a projectile launched at an angle of 33 above the horizontal will have the same range as a projectile launched at an angle of 57⁰.

The range of a projectile can be determined by using the range formula.

R = ((v^2 * sin(2θ))/g) Where

R is the range of the projectile,

v is the velocity of the projectile,

θ is the angle at which the projectile is launched, and

g is the acceleration due to gravity.

In the absence of air resistance,

the horizontal component of velocity of a projectile remains constant throughout the flight.

So, the range of a projectile depends only on its initial velocity and the angle at which it is launched.

If a projectile is launched at an angle θ,

the time of flight of the projectile can be calculated by using the following formula:

T = (2v * sin(θ))/g

The maximum height reached by the projectile is given by the formula:

H = (v^2 * sin^2(θ))/2gIf a projectile is launched at an angle θ, then the range of the projectile will be the same as the range of the projectile launched at an angle of (90 - θ).

So, if a projectile is launched at an angle of 33⁰ above the horizontal, then the projectile launched at an angle of 90 - 33 = 57⁰ will have the same range as the projectile launched at 33⁰.

Therefore, the correct option is (B) 57⁰.

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if light photons are massless then why are they attracted by black holes?​

Answers

Answer:

Photons have no mass, they do have energy, and the gravity of a black hole (or any other gravitating body) will attract them.

Explanation:

is that what you wanted?

fill in the blanks
8) Kinetic energy is the energy of ________.



9)The potential energy of an object depends on its ________ and its height.



10) The law of ________ of energy states that energy can be neither created nor destroyed, but it can change its form.

Answers

Answer: Kinetic energy is the energy an object has because of its motion

(if it needs to be a one worded answer than just type motion)

The potential energy of an object depends on its mass and its height.

The law of conservation of energy states that energy can be neither created nor destroyed, but it can change its form.

Answer:Kinetic energy is the energy an object has because of its motion. If we want to accelerate an object, then we must apply a force. Applying a force requires us to do work.

As expressed by the equation, potential energy depends upon the mass and the height of the object. Any increase in these two quantities will lead to an increase in the amount of potential energy possessed by the object.

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside.

Two friends are playing with a toy telephone. Which of the points P,Q and R will vibrate if one of the friends speak into the cup? Justify your answer

Answers

The point that will vibrate the most when one of the friends speaks into the cup is point Q as vibration dampens and energy is lost due to friction.

In a toy telephone, sound is transmitted through a string that connects two plastic cups. When one person speaks into one cup, the sound waves vibrate the cup, which in turn vibrates the string and causes the other cup to vibrate as well.

Assuming that the string is held taut, the vibration of the cups will depend on the placement of the points P, Q, and R, as shown in the figure. If the string is not taut, the cups may not vibrate at all, or the vibrations may be too weak to transmit the sound effectively.

Point P is located at the midpoint of the string, and it will not vibrate much because the two cups are attached to it and there is no space for it to move.

Point Q is located at one end of the string, and it will vibrate the most when one of the friends speaks into the cup. This is because the cup will vibrate the string, and the vibration will be transmitted all the way to the other end of the string, where point Q is located.

Point R is located between P and Q, and it will vibrate to some extent, but not as much as point Q. This is because the vibration will be damped as it travels along the string, and some of the energy will be lost due to friction.


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Two coherent sources of light are three
wavelengths out of phase. does light from these
sources experience constructive interference,
destructive interference, or no interference at all?
explain how you know.

Answers

Answer:

The difference phase = 3 λ

In terms of wavelength the difference of phase is zero so the sources would experience "constructive" interphase at that point.

If the light from the sources differed by 1/2, 3/2, 5/2 wavelengths  etc, then the sources would be out of phase at that point.

a 300 g air-track glider is attached to a spring. the glider is pushed in 12 cm and released. a student with a stopwatch finds that 20 oscillations take 24.0 s. what is the spring constant?

Answers

The spring constant is approximately 0.8 N/m

To find the spring constant, we can use Hooke's law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position.

The formula for the period of oscillation of a mass-spring system is:

T = 2π * sqrt(m/k)

Where:

T is the period of oscillation,

m is the mass of the glider, and

k is the spring constant.

In this case, the glider is pushed 12 cm, so the amplitude of the oscillations is A = 0.12 m.

The period T is given as 24.0 s for 20 oscillations, which means the period for one oscillation is T/20 = 1.2 s.

Substituting the known values into the equation, we have:

1.2 = 2π * √(0.3/k)

Solving for k:

sqrt(0.3/k) = 1.2 / (2π)

\(0.3/k = (1.2 / (2π))^2\)

\(k = 0.3 / [(1.2 / (2π))^2]\)

Using a calculator, we can calculate the value of k:

k ≈ 0.8 N/m

Therefore, the spring constant is approximately 0.8 N/m

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An object has a mass of 10 kg and it is accelerating at a rate of 12 m/s2. What is the net force causing this acceleration?
100 N
O 120 N
0 140 N
O 160 N

Answers

Answer:

net force causing acceleration is 120N

Explanation:

Given parameters:

Mass of the object  = 10kg

Acceleration  = 12m/s²

Unknown:

Net force of this acceleration  = ?

Solution:

According to newtons second law of motion;

     Force  = mass x acceleration

Sine the unknown is the net force, input the parameters and solve for it;

   Force  = 10 x 12  = 120N

The net force causing acceleration is 120N

A Projectile is launched horizontally from a height of 120m. If it lands 300 ft away from where it was launched, how fast was it launched?

Answers

The initial speed of the projectile is 18.5m/s

What is a projectile ?

Projectile motion is the motion of an object thrown into the air under gravity. Examples of projectiles include a fired bullet, a thrown javelin e t.c

When a projectile is launched horizontal, it's horizontal range is given as R = u(√2h/g)

R = 300ft = 91.44meters

h= 120m

therefore 91.44= u( √ 2×120/9.8)

91.44 = u ( √24.49)

91.44 = 4.95 u

divide both sides by 4.95

u = 91.44/4.95

u = 18.5m/s

therefore the speed of the projectile is 18.5m/s

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A 0.400 kg object undergoing SHM has Part A a x

=−1.80 m/s 2
when x=0.200 m. What is the time for one oscillation? Express your answer with the appropriate units.

Answers

The time for one oscillation of the object is approximately 2.09 seconds. To find the time for one oscillation of the object undergoing Simple Harmonic Motion (SHM), we can use the equation:

a = -ω²x

Where:

a is the acceleration,

ω is the angular frequency, and

x is the displacement from the equilibrium position.

In SHM, the acceleration is proportional to the displacement and is given by the negative product of the square of the angular frequency (ω²) and the displacement (x).

From the given information, we have:

a = -1.80 m/s²

x = 0.200 m

Substituting these values into the equation, we get:

-1.80 m/s² = -ω² * 0.200 m

Simplifying the equation, we have:

ω² = 1.80 m/s² / 0.200 m

= 9 m/s²

To find the angular frequency (ω), we take the square root of both sides:

ω = √(9 m/s²)

= 3 m/s

The time for one oscillation (T) can be calculated using the formula:

T = 2π / ω

Substituting the value of ω, we have:

T = 2π / 3 m/s

Calculating this value, we find:

T ≈ 2.09 s

Therefore, the time for one oscillation of the object is approximately 2.09 seconds.

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Scientists and engineers are testing three different satellites orbiting Earth. The scientists are able to use sensors to determine the gravitational force experienced by each satellite. Some of the data from each of the orbiting satellites is shown in the table below. Distance Satellite from Earth (km) 36,000 36,000 36.000 X Y Z Mass (kg) 400 1.200 900 Gravitational Force (N) 120 360 270 Which statement best summarizes the information given? OA. The gravitational force exerted by Earth on the satellite depends on the satellite's mass. OB. The satellite with the least amount of mass is able to exert greater gravitational force on Earth than the others. OC. The gravitational force exerted by Earth changes the mass of each of the satellites. OD. The gravitational force on the satellite depends only on the distance from Earth at which it is travelling.​

Answers

The statement that best summarizes the information given is: The gravitational force exerted by Earth on the satellite depends on the satellite's mass.

The correct option is A.

What is the relationship between gravitational force and mass?

Gravitational force is the force of attraction that exists between two objects.

Gravitational force is directly proportional to the product of the masses of the objects and inversely proportional to the square of the distance of separation.

Greater gravitational forces will be used to attract heavier things since the gravitational force is directly proportional to the mass of both interacting objects. Therefore, the gravitational attraction between two objects grows as their respective masses do as well.

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which would best be explained using newton's third law?question 15 options:a larger engine allows a car to accelerate faster.a bicyclist coasts down from the top of a hill.a car stops short and the passenger moves forward.a gun moves backward while firing a bullet.

Answers

the best explanation using Newton's third law is the gun moving backward while firing a bullet.

Newton's third law of motion states that for every action, there is an equal and opposite reaction. In the case of the gun firing a bullet, when the bullet is expelled from the barrel, it exerts a forward force on the bullet. Simultaneously, according to Newton's third law, the gun experiences an equal and opposite backward force (recoil). This backward motion of the gun is a result of the action-reaction pair.

In the other options:

- A larger engine allowing a car to accelerate faster can be explained by Newton's second law, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

- A bicyclist coasting down from the top of a hill can be explained by the conservation of energy and the force of gravity acting on the cyclist.

- When a car stops short and the passenger moves forward, it can be explained by Newton's first law, also known as the law of inertia. The passenger tends to continue moving forward due to inertia until an external force (such as a seatbelt or airbag) acts on them to stop their motion.

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The solid shaft AE rotates at 500 rpm and transmits 45 kW from the motor M to the
machine tools connected to gears G and H. Knowing that = 50 Mpa and that 30
kW is taken off at gear G and 15 kW is taken off at gear H, determine the smallest
permissible diameter of shaft AE

Answers

The smallest possible shaft AE is having the diameter equal to 22nm or 22 nanometer, which can be calculated by using the formula for the torque transmitted by the shaft.

The smallest permissible diameter of shaft AE can be determined using the formula for torque transmitted by a solid shaft:

T = (π/16) × τ × d³

where T is the torque transmitted by the shaft, τ is the maximum shear stress, and d is the diameter of the shaft.

Given that:

T = 45 kW / (2π × 500 rpm) = 0.143 Nm,

τ = 50 MPa, and

that 30 kW is taken off at gear G and 15 kW is taken off at gear H, we can calculate the torque transmitted by gears G and H as follows:

\(T_G\) = 30 kW / (2π × 500 rpm)

= 0.095 Nm

\(T_H\) = 15 kW / (2π × 500 rpm) = 0.048 Nm

The torque transmitted by shaft AE can be calculated as follows:

\(T_{AE}\) = T + \(T_{G}\) + \(T_{H}\) = 0.143 + 0.095 + 0.048 = 0.286 Nm

Substituting these values into the formula for torque transmitted by a solid shaft and solving for d, we get:

d = [(16 × T_AE) / (π × τ)]¹/³

= [(16 × 0.286) / (π × 50)]¹⁾³ ≈ 22 mm

Therefore, the smallest permissible diameter of shaft AE is approximately 22 mm.

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If the child is gaining weight at an expected rate, a child who weighs 36 lb (16.3 kg) at 3 years of age would weigh what amount at age 5?

Answers

The child at 5 years old would weight: 60 lb (27.16 kg) If he continues gaining weight a that rate

To solve this problem we will use a rule of three with the problem information:

3 years-------- 36 lb child's weight

5 years -------- x

Applying the rule of three we get:

x = ( 5 years * 36 lb child's weigh) / 3 years

x = 60 lb

By converting the weight units from lb to kg we have:

x = 60 lb * 16.3 kg/36 lb

x = 27.16 kg

What is rule of three?

It describes the proportionality of 3 known data and an unknown data. When you have more than 3 known facts that are involved in the proportionality, it is known as a compound rule. The rule of three is also known as a direct proportions.

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If the child is gaining weight at an expected rate, a child who weighs 36 lb (16.3 kg) at 3 years of

An electron moves in a circular path of radius 20 cm in a uniform magnetic field of 2 x 10³ T Find the speed of the electron and period of revolution. Mass of electron = 9.1 x 10-31 kg. [Ans: 7.02 x 10 m/sec and 5.6 x 10 rev/sec] ​

Answers

The linear speed of the electron is 7.03 x 10¹³ m/s and the angular speed of the electron is 5.6 x 10¹³ rev/s.

Speed of the electron

The speed of the electron is calculated as follows;

F = ma = mv²/r  ---(1)

F = qvB  ----- (2)

mv²/r = qvB

mv/r = qB

mv = qBr

v = qBr/m

where;

m is mass of the electronB is magnetic fieldr is radius of the circleq is charge of the electron

v = (1.6 x 10⁻¹⁹ x 2 x 10³ x 0.2) / (9.1 x 10⁻³¹)

v = 7.03 x 10¹³ m/s

Angular speed of the electron

ω = v/r

ω = (7.03 x 10¹³ m/s) / (0.2 m) = 3.51 x 10¹⁴ rad/s

ω = 3.51 x 10¹⁴ rad/s  x 1 rev/2π rad

ω = 5.6 x 10¹³ rev/s

Thus, the linear speed of the electron is 7.03 x 10¹³ m/s and the angular speed of the electron is 5.6 x 10¹³ rev/s.

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What is the height of the cannon before it is launched, at t=0? Remember to include units.

Answers

The height of the cannon before it is launched, at t=0, is 58 m.

Model for the motion of the cannon ball

The equation of motion of the cannon ball is given as;

h(t) = -4.9t² + 19.8t + 58

Height of the cannon at time, t = 0

The initial height of the cannon before it was launched is calculated as follows;

h(0) = -4.9(0) + 19.8(0) + 58

h(0) = 58 m

Thus, the height of the cannon before it is launched, at t=0, is 58 m.

Complete question is below:

The equation that models the path of a cannon ball is  h(t) = -4.9t² + 19.8t + 58. What is the height of the cannon before it is launched, at t=0? Remember to include units.

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I need help in this question

I need help in this question

Answers

The only true statement about the toy car is " the toy does not approach the spring".

option A is the correct answer.

What is the acceleration of the toy car?

The acceleration of the car is calculated by applying Newton's second law of motion, which states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F - Ff = 0

F = Ff

ma = μmg

a = μg

where;

a is the acceleration of the carμ is the coefficient of frictiong is acceleration due to gravity

a = 0.14 x 9.8 m/s².

a = 1.37 m/s²

The distance traveled by the car before stopping is calculated as follows;

v² = u² - 2as

where;

v is the final velocity of the caru is the initial velocitys is the distance travelled

when the car stop's the final velocity, v = 0

0 = u² - 2as

2as = u²

s = u²/2a

s = ( 2² ) / ( 2 x 1.37 )

s = 1.5 m

Thus, the final distance travelled by the car is less than 3 m, hence the car did not come in contact with spring.

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If the bolt is subjected to a compressive force of P = 21.1 kN, determine the average normal stress in the steel The 10-mm-diameter steel bolt in (Fiqure 1) is surrounded by a bronze sleeve . The outer diameter of this sleeve is 20 mm, and its inner diameter is 10 mm. Est 200 GPa, Br = 100 GPa. Express your answer to three significant figures and include appropriate units Figure 1 #1 of 1 MPa Submit My Answers Give Up Incorrect; One attempt remaining; Try Again Not quite. Check through your calculations; wrong number of significant figures ,you may have made a rounding error or used the 10 mm Part B 20 mm If the bolt is subjected to a compressive force of P = 21.1 kN, determine the average normal stress in the bronze Express your answer to three significant figures and include appropriate units u-Value Units

Answers

The average normal stress in the bronze sleeve is approximately 89,564.1 Pa (or 89.6 kPa) to three significant figures.

To determine the average normal stress in the steel and bronze components, we can use the formula for stress:

Stress = Force / Area

a) Average normal stress in the steel bolt:

Given:

Diameter of the steel bolt = 10 mm

First, we need to calculate the area of the steel bolt:

Area = π * (diameter/2)^2

Area = π * (10 mm / 2)^2

Area = π * (5 mm)^2

Area = 78.54 mm^2

Now, let's calculate the average normal stress in the steel bolt using the compressive force:

Stress = Force / Area

Stress = 21.1 kN / 78.54 mm^2

To convert the stress to the appropriate units, we need to convert kilonewtons (kN) to newtons (N) and millimeters (mm^2) to square meters (m^2):

Stress = (21.1 kN * 1000 N/kN) / (78.54 mm^2 * (10^-6 m^2/mm^2))

Stress = 268,216.4 N/m^2

The average normal stress in the steel bolt is approximately 268,216.4 Pa (or 268.2 MPa) to three significant figures.

b) Average normal stress in the bronze sleeve:

Given:

Outer diameter of the bronze sleeve = 20 mm

Inner diameter of the bronze sleeve = 10 mm

First, we need to calculate the area of the bronze sleeve:

Area = π * (outer diameter/2)^2 - π * (inner diameter/2)^2

Area = π * (20 mm / 2)^2 - π * (10 mm / 2)^2

Area = π * (10 mm)^2 - π * (5 mm)^2

Area = 235.62 mm^2

Now, let's calculate the average normal stress in the bronze sleeve using the compressive force:

Stress = Force / Area

Stress = 21.1 kN / 235.62 mm^2

To convert the stress to the appropriate units, we need to convert kilonewtons (kN) to newtons (N) and millimeters (mm^2) to square meters (m^2):

Stress = (21.1 kN * 1000 N/kN) / (235.62 mm^2 * (10^-6 m^2/mm^2))

Stress = 89,564.1 N/m^2

The average normal stress in the bronze sleeve is approximately 89,564.1 Pa (or 89.6 kPa) to three significant figures.

Note: The units used are in Pascal (Pa), which is equivalent to N/m^2.

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a. In which cluster(s) would you not expect to find a white dwarf? List all that apply.
b. You observe a supernova go off in each of the six clusters. In which cluster(s) would the events be consistent with a core collapse supernova? List all that apply.

Answers

a. Youngest and oldest clusters would not have white dwarfs.

b. Clusters with high stellar masses may produce core-collapse supernovae.

a. A white smaller person is the final result of the development of a low-mass star. Subsequently, bunches that are excessively youthful to have stars that have developed to this stage wouldn't have white smaller people.

Groups that are too old, then again, might not have any white smaller people left, as they would have chilled off to become undetectable to telescopes. Thusly, we wouldn't anticipate tracking down white diminutive people in the most youthful or the most seasoned groups.

b. Center breakdown supernovae are brought about by the horrendous breakdown of the center of a monstrous star. Subsequently, we would hope to witness these occasions just in groups that contain monstrous stars. The groups with the most gigantic stars would be the probably going to deliver center breakdown supernovae.

Hence, we would hope to witness these occasions in the groups with the most elevated heavenly masses, for example, those with high metallicity, high star-development rates, or those that are going through a starburst stage.

To figure out which explicit bunches would be predictable with a center breakdown cosmic explosion, we would have to assemble more observational information, like the phantom mark of the cosmic explosion and its light bend.

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The complete question is:

a. Based on the characteristics of white dwarfs, which clusters would not be expected to contain these stellar remnants? Please provide a list of all applicable clusters.

b. If a supernova occurs in each of the six clusters, which clusters would be consistent with a core-collapse supernova? Please list all applicable clusters and provide a brief explanation to support your answer.

Which will have the greater acceleration rolling down an incline— a bowling ball or a volleyball?

Answers

Answer:

Bowling ball

Explanation:

The bowling ball's mass will make it roll down the incline faster than the lighter volleyball.

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1. If you use an applied force of 45N to slide a 12Kg wooden crate across a floor at a constant velocity, what is the coefficient of kinetic friction between the crate and the floor?

Answers

Answer:

Coefficient of kinetic friction = 0.38 (Approx.)

Explanation:

Given:

Applied force = 45 N

Mass of wooden crate = 12 kg

Find:

Coefficient of kinetic friction

Computation:

Coefficient of kinetic friction = Applied force / (Mass)(Acceleration due to gravity)

Coefficient of kinetic friction = 45 / (12)(9.8)

Coefficient of kinetic friction = 45 / 117.6

Coefficient of kinetic friction = 0.3826

Coefficient of kinetic friction = 0.38 (Approx.)

You are designing a spaceship, and you want it to have an artificial gravity of 9.8 m/s2 at the center of mass of an average human. The average human has a center of gravity that is about 90 cm above their feet. Through other engineering constraints, you have determined the rotational speed of the ship to be 0.2 rad/s. What should the radius of the ship be (in m)? (Round your answer to the nearest whole number!)

Answers

Answer:

The tangential acceleration is 0 m/s².

Explanation:

Answer:

The tangential acceleration is 0 m/s².

Explanation:

What is Newton's third law of motion? Give an example.

Answers

Answer: Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation: hope this helps :)

Determine the maximum theoretical speed that may be achieved over a distance of 60 m by a car starting from rest, knowing that the coef- ficient of static friction is 0.80 between the tires and the pavement and that 60 percent of the weight of the car is distributed over its front wheels and 40 percent over its rear wheels. Assume (a) four-wheel drive, (b) front-wheel drive, (c) rear-wheel drive

Answers

The maximum theoretical speed that can be achieved over a distance of 60 m by a car starting from rest depends on the coefficient of static friction and the weight distribution.

For a car with four-wheel drive, front-wheel drive, and rear-wheel drive, the maximum theoretical speeds can be determined using the principles of friction and weight distribution.

The maximum theoretical speed is limited by the maximum static friction force that the tires can provide. The maximum static friction force is determined by multiplying the coefficient of static friction by the normal force. In this case, the weight of the car is distributed differently depending on the drive type.

For four-wheel drive, the weight is evenly distributed between the front and rear wheels. For front-wheel drive, 60% of the weight is distributed to the front wheels, and for rear-wheel drive, 60% is distributed to the rear wheels.

Using the maximum static friction force, the maximum acceleration can be determined using Newton's second law, and then using the distance and acceleration, the maximum theoretical speed can be calculated using the equation v = √(2ad).

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PLEASE HELP 25 POINTS !!!!!!!!!!!!!!!! Add the following numbers and round your answer to the correct number of significant figures:

90.0 + 80 =

Show both the unrounded and rounded answer.

Answers

Answer:

90.0 + 80 = 170

2 signifigant figures

1.70 x 10^2

A magnetic object is shown here, recently broken into two pieces. The region at the point labeled "a" is the positive end of the
original magnet. Which questions are relevant to ask with regard to the magnetic object shown here? Select ALL that apply (Choose
2)
A)
8)
C
6
Dj
G
Do "a" and "d" repel each other?
Do "b" and "c" attract to each other?
Are "b' and 'e' both negative ends of the new objects?
Are "a" and "e" both positive ends of the new objects?
Do "b" and "d" create an electric current when in proximity to each other?

Answers

The relevant questions to ask with regard to the magnetic object are options B and D:

Are "b" and "c" attract to each other?

Are "a" and "e" both positive ends of the new objects?

What makes an object magnetic?

When electrons in an item spin in the same direction, they form a net magnetic field. When you magnetize something, the spinning electrons align and generate a powerful magnetic field. The magnetic properties of a material are governed by its atomic and molecular structure, as well as external effects such as temperature and magnetic fields.

Some materials, such as iron, nickel, and cobalt, are magnetic by nature, whereas others may be magnetized by a number of means, such as exposure to high magnetic fields or electric currents.

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Which is the following best describes the bottleneck resource for a process? Its the resource that takes the longest time Its the resource that is fewest in number Its the resource with smallest capac

Answers

The best description of the bottleneck resource for a process is: It is the resource that takes the longest time.

In process management, a bottleneck refers to a point in the process where the flow of work is limited or constrained, causing a delay in the overall process. The bottleneck resource is the specific resource (such as a machine, equipment, or person) that has the longest processing time compared to other resources in the process.

The presence of a bottleneck resource can significantly impact the efficiency and throughput of the entire process. Since the bottleneck resource takes the longest time to complete its tasks, it creates a bottleneck effect by limiting the overall capacity of the process. The output of the process cannot exceed the capacity of the bottleneck resource, which can lead to waiting times, delays, and inefficiencies in the process.

Identifying and managing the bottleneck resource is crucial for optimizing process performance. Strategies such as increasing the capacity of the bottleneck resource, balancing workloads, improving efficiency, or redesigning the process flow can help alleviate the bottleneck and improve the overall productivity of the process.

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Which describes the sum of potential energy and kinetic energy of objects or systems? *

a. nuclear energy and electric energy
b. nuclear and mechanical energy
c. thermal energy and electric energy
d. thermal energy and mechanical energy

Answers

Answer:

The Total Mechanical Energy

The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy. This sum is simply referred to as the total mechanical energy (abbreviated TME).

Thermal energy and mechanical energy describes the sum of potential energy and kinetic energy of objects or systems. Correct option is D.

Potential Energy: This is the energy that an object possesses due to its position or condition. For example, a book placed on a shelf has potential energy because it can potentially fall down. The higher the object is positioned, the more potential energy it has.

Kinetic Energy: This is the energy of motion. An object that is moving has kinetic energy. The kinetic energy of an object depends on its mass and its velocity (speed).

Thermal Energy: This is the energy associated with the random motion of particles within a substance. It's related to temperature and is a form of kinetic energy at the microscopic level.

Mechanical Energy: This is the sum of potential energy and kinetic energy in a mechanical system. In other words, it accounts for both the energy an object has due to its position and the energy it has due to its motion.

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Why do many people want to use renewable energy like solar energy or hydroelectric energy instead of energy from coal?

pls help asap will mark as brainliest if correct!

Answers

Answer:

Explanation:

Solar energy is efficently present naturally , whereas coal and natural gas are more efficient by reliable applications, things like coal and natural gases are also non renewable they also cause pollution .so using solar enery are better than coal and natural gases.

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