what is measurement? why is it important to have regular supervision of the weights and measurement in the market?​

The size of the image in the mirror will decrease as the object moves directly away from the perfectly vertical plane mirror.  When an object moves directly away from a perfectly vertical plane mirror, the size of the image remains the same, the image's distance from the mirror increases, and the image stays upright and virtual.

When an object is moved directly away from a perfectly vertical plane mirror, there are three important things to consider. Firstly, the distance between the object and the mirror will increase as it moves away. Secondly, the size of the image in the mirror will decrease as the object moves further away. Finally, the image will appear to move downwards in the mirror as the object moves away. In summary,

When an object is moved directly away from a perfectly vertical plane mirror, the following three statements hold true: 1.The size of the object's image in the mirror remains the same. This is because the angle of incidence and angle of reflection remain constant, causing the size of the image to be unchanged regardless of the object's distance from the mirror. 2. The image's distance from the mirror increases at the same rate as the object's distance. As the object moves away from the mirror, the distance between the object and its image will also increase while maintaining the same rate of change. 3. Lastly, the image remains upright and virtual. A plane mirror always produces a virtual image that is the same orientation as the object, and moving the object away from the mirror does not affect this property.

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Answer:

B

Explanation:

The fugitive takes approximately 11.31 seconds to catch up to the empty box car.

To determine the time it takes for the fugitive to catch up to the empty box car, we need to find the time it takes for the fugitive to reach a speed of 6.2 m/s. The fugitive starts from rest and accelerates at a rate of 1.4 m/s^2 until reaching the maximum speed.

Using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time, we can rearrange the equation to solve for time: t = (v - u) / a.

Given that the fugitive starts from rest (u = 0), reaches a maximum speed of 6.2 m/s (v = 6.2 m/s), and accelerates at 1.4 m/s^2 (a = 1.4 m/s^2), we can substitute these values into the equation and calculate the time: t = (6.2 - 0) / 1.4 = 4.43 seconds.

Therefore, it takes approximately 4.43 seconds for the fugitive to reach his maximum speed. However, we need to determine the time it takes for the fugitive to catch up to the empty box car. Since the box car is already moving at a constant speed of 5.0 m/s, the fugitive needs to cover the initial distance between them before he starts accelerating.

The distance traveled by the fugitive during this initial time can be calculated using the equation d = ut + (1/2)at^2, where d is the distance, u is the initial velocity, a is the acceleration, and t is the time. Given that the fugitive starts from rest (u = 0), the equation simplifies to d = (1/2)at^2.

Substituting the values of acceleration (1.4 m/s^2) and time (4.43 seconds) into the equation, we can find the distance traveled during the initial time: d = (1/2)(1.4)(4.43)^2 = 13.57 meters.

Therefore, the fugitive covers a distance of 13.57 meters during the initial time. To determine the total time it takes for the fugitive to catch up to the empty box car, we divide this distance by the relative velocity between them: t = d / (5.0 - 6.2) = 13.57 / (-1.2) = -11.31 seconds.

However, we need to consider that time cannot be negative in this context. Thus, we take the absolute value of the time to obtain the positive value: t = |-11.31| = 11.31 seconds.

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The mass of the rock is approximately 86.304 tons.

To convert the mass of the rock from grams to tons, we can use the conversion factor that 1 ton is equal to 907.2 kilograms.

Mass of the rock = 7.84 x 10^7 grams

To convert grams to kilograms, we divide by 1000:

Mass in kilograms = (7.84 x 10^7 grams) / 1000 = 7.84 x 10^4 kilograms

Now, to convert kilograms to tons, we divide by 907.2:

Mass in tons = (7.84 x 10^4 kilograms) / 907.2 = 86.304 tons

Therefore, the mass of the rock is approximately 86.304 tons.

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Answer:

The total distance moved by the car is 80 metres

Explanation:

Given

North = 30 meters

South = 50 meters

Required

Determine the distance

Distance is a scalar quantity and hence, the total distance is the summation of distance moved in both directions

i.e.

\(Total\ Distance = North + South\)

\(Total\ Distance = 30\ metres + 50\ metres\)

\(Total\ Distance = 80\ metres\)

Hence;

The total distance moved by the car is 80 metres

The magnitude of the electric field produced in the region between the two electrodes is \(5.15 \times 10^6 \ V/m\).

The electric field strength produced in the region between the two electrodes is calculated as follows;

\(E = \frac{v}{d}\)

where;

The electric field strength is calculated as follows;

\(E = \frac{3500}{0.68 \times 10^{-3}} \\\\E = 5.15 \times 10^6 \ V/m\)

Thus, the magnitude of the electric field produced in the region between the two electrodes is \(5.15 \times 10^6 \ V/m\).

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The velocity of the ball when it strikes the ground, given the data is 21.56 m/s

From the question given above, the following data were obtained:

The velocity of the ball when it strikes the ground can be obtained as illustrated below:

v = u + gt

v = 0 + (9.8 × 2.2)

v = 0 + 21.56

v = 21.56 m/s

Thus, the velocity of the ball when it strikes the ground is 21.56 m/s

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Answer:

yes but no

Explanation:

if there weren't carnivorous animals then there would be overpopulation of animals but since there are maybe no

Answer:

Microscopes are just plainly a form of a high tech magnifying glass and helping us see what we can't see with our naked eye

Explanation:

If you heat a fixed quantity of gas, the following statements are true:1. The gas molecules will gain kinetic energy, causing them to move faster.2. The temperature of the gas will increase.3. If the volume is held constant, the pressure of the gas will increase due to more frequent and forceful collisions with the container walls (Gay-Lussac's Law).


The volume of the gas will increase: This statement is true. When a gas is heated, the average kinetic energy of its molecules increases, causing them to move faster and collide more frequently with the container walls. As a result, the gas molecules push against the container walls with greater force, leading to an increase in volume.

The pressure of the gas will increase: This statement is also true. According to the Ideal Gas Law, PV=nRT, the pressure of a gas is directly proportional to its temperature (assuming a constant volume and number of moles). Therefore, if the temperature of a fixed amount of gas is increased while the volume is held constant, the pressure will also increase.

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The differential equation for q in terms of t is to be derived and the initial conditions for the quantity of salt in the tank are to be specified.

We know that the rate of change of the quantity of salt in the tank is given by

dQ/dt = (rate of flow in) * (concentration in) - (rate of flow out) * (concentration out)

By the law of conservation of mass, rate of flow in = rate of flow out = 10 - 5 = 5 L/min

Also, initial quantity of salt in the tank = 1000 L * 0.01 kg/L = 10 kg

Hence, dQ/dt = 5 * 0.04 - 5 * (Q/1000)

where Q(t) is the quantity of salt in the tank at time t, measured in kg.

So, the differential equation is

dQ/dt = 0.2 - 0.005Q

with initial condition Q(0) = 10 kg.

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Answer:

A. 45 degrees

Explanation:

Answer:

A. 45 degrees

Explanation:

A projectile travels the farthest when it is launched at an angle of 45 degrees.

The maximum range is 45 degrees, ignoring air resistance.

sin(2θ) = 1

∴ 2θ = π/2.

(2θ)/2 = (π/2)/2

θ = π/4

π/4 or 45°

Answer:

The force of the golf ball on Earth!

Explanation:

Action/Reaction Pairs work like this:

Earth on Golfball, Golfball on Earth.

The control in the experiment is option B. The group that is given no shock.

The method utilized by the researcher in scientific study to reduce the impact of unimportant factors is known as experimental control. The power of the independent variable to alter the dependent variable is further strengthened by experimental control. 9 Nov 2021

A controlled experiment is a scientific test carried out under predetermined circumstances in which only one (or a small number of) variables are altered at a time while all other variables are maintained constant.

Researchers use experimental controls to reduce the impact of unrelated experience and environmental factors, as well as to strengthen the conclusion that changes in the dependent variable are caused by the independent variable (the ability to infer causality).

Hence, option B is correct as it is not receiving any special treatment in the experiment.

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The distance the car would travel when it hit the barrier before coming to a stop is 14.6 m.

The distance travelled by the car before stopping is calculated by applying third kinematic equation as shown.

v² = u² - 2as

where;

when the car stops,  the final velocity will zero, v =  0

0 = u² - 2as

2as = u²

s = u²/2a

The given parameter;

initial velocity of the car, u = 110 km/h = 30.56 m/s

a = 32 m/s²

s = (30.56²) / (2 x 32)

s = 14.6 m

Thus, when the car hits the soft barrier, it will slow down and travel a distance of 14.6 m before coming to rest.

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Yes, it is possible for both the pressure and volume of a monatomic ideal gas to change without causing the internal energy of the gas to change. This occurs when the gas undergoes an adiabatic process, meaning there is no heat transfer between the gas and its surroundings.

In an adiabatic process, the change in internal energy (ΔU) is solely dependent on the work done on or by the gas (W). According to the first law of thermodynamics, ΔU = Q + W, where Q is the heat transfer. Since Q = 0 in an adiabatic process, ΔU = W.

For the internal energy of the gas to remain constant (ΔU = 0), the work done on or by the gas must also be zero. This can be achieved through a specific path in the pressure-volume (PV) diagram, where the gas expands and does work on its surroundings, followed by compression, with the surroundings doing an equal amount of work on the gas. The net work done over this process will be zero, ensuring the internal energy remains unchanged.

In summary, it is possible for both the pressure and volume of a monatomic ideal gas to change without affecting its internal energy by undergoing an adiabatic process with zero net work done.

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The two factors that prevent planets from being pulled into the Sun are option  C. Gravity between the planet and the sun, and option E. Planet's inertia.

Gravity between the planet and the Sun plays a crucial role in keeping the planets in their orbits. This gravitational force acts as a centripetal force, which constantly pulls the planets towards the Sun. However, the planets do not fall into the Sun due to their inertia.

Planet's inertia is the resistance of a planet to changes in its state of motion. Each planet has its own velocity and moves in a specific path around the Sun, known as an orbit. Due to inertia, the planet's motion tries to maintain a straight path. This creates a balance with the gravitational force that pulls it towards the Sun, resulting in a stable orbit.

In summary, the combination of the gravitational force between the planet and the Sun, and the planet's inertia, keeps the planets in their orbits and prevents them from falling into the Sun. Therefore the correct option C and E

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Answer:

9 ohms

Explanation:

P = V²/R

R = v²/p = 6²/4 = 36/4 = 9 ohms.

The resistance is 9 Ohm.

To find the resistance, we need to know about the power in term of resistance and voltage.

Thus, we can conclude that the resistance is 9 Ohm.

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Answer:

E = 1/2 K x^2        (1/2 *F * x * x)

E = 2300 / 2 N/m * (.18 m)^2 = 37.3 Joules

The quantity of elastic potential energy that is currently stored in the system is equal to 37.26 Joules (J).

We may use the formula for elastic potential energy to compute the amount of elastic potential energy that is stored in the system, which is as follows:

PE, or Elastic Potential Energy, is 0.5 times k times x squared.

where k represents the constant force that the spring exerts and x represents the amount of compression that the spring experiences.

Given:

The spring has a force constant of 2300 Newton-meters (k).

The spring was compressed (x) by 18.0 centimetres, which is equivalent to 0.18 metres when measured in metres.

To finish, enter the values into the formula as follows:

PE = 0.5 × 2300 N/m × (0.18 m)² PE = 0.5 × 2300 N/m × 0.0324 m² PE = 37.26 J

37.26 Joules (J) is the amount of elastic potential energy that is stored in the system.

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To determine the velocity of the alpha particle, we can use the formula for the kinetic energy of a moving object:

KE = (1/2)mv^2, where KE is the kinetic energy, m is the mass of the alpha particle, and v is its velocity. The mass of the alpha particle is given as 6.642x10^-4g, which is equivalent to 6.642x10^-7 kg. The kinetic energy is given as 8.0109x10^-13 J. Plugging these values into the equation, we can solve for the velocity: 8.0109x10^-13 J = (1/2)(6.642x10^-7 kg)(v^2). Simplifying and solving for v, we get: v = sqrt((2(8.0109x10^-13 J))/(6.642x10^-7 kg)) = 1.283x10^5 m/s. Therefore, the velocity of the alpha particle is 1.283x10^5 m/s. This is a very high velocity, which is typical of alpha particles emitted during radioactive decay processes.

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Answer:

PFA

:-)

Explanation:

Given three identical metallic spherical objects have individual charges of, q1 = -9.612 nC,

q2 = +3.204 nC,

and q3 = +6.408 nC.

If the three objects are brought into contact with each other at the same time and then separated, the final net charge on q1, q2, and q3 will be calculated as follows;

Initial total charge, Q = q1 + q2 + q3

Q= -9.612 nC + 3.204 nC + 6.408 nC

Q= -0.002 nC

The final net charge on q1, q2, and q3 is same as they are identical:

q1 + q2 + q3 = -0.002 nC

q1 = q2 = q3 = -0.002 nC/3

q1 = -0.0006667 nC

Therefore, the final net charge on q1, q2, and q3 is -0.0006667 nC.The charge on q1 before and after is -9.612 nC and -0.0006667 nC respectively. The difference is the number of electrons that were removed from/added to q1. The number of electrons can be calculated as follows;

Charge on an electron,

e = 1.6 ×\(10^{-19\) C

Total number of electrons removed from

q1 = [(final charge on q1) - (initial charge on q1)] / e

q1 = [-0.0006667 - (-9.612)] / 1.6 × \(10^{-19\)

q1 = 6.0075 × 1013

The number of electrons removed from q1 is 6.0075 × 1013, and electrons were removed from q1. Thus, option d is,

"The number of electrons that were removed from q1 = 6.0075 × 1013 electrons were removed from q1."

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Answer:

1 -a push or a pull acting on a object.

Explanation:

force is a push or pull acting upon an object as a result of its interaction with another object.

Answer:

Pros: It is abundant, and can be used without interruption, cleaner than fossil fuel. Cons: Can result in air pollution, takes a lot of energy to produce, can be seasonable and competes with food production. Landfill gas, solid waste energy comes from harnessing the decomposition of organic material.

Explanation:

q(1) = q

\( \frac{k.q.5q}{ ({3 \times {10}^{ - 2} })^{2} } = 2 \times {10}^{ - 2} \\ \)

\( \frac{9 \times {10}^{9} \times 5 {q}^{2} }{9 \times {10}^{ - 4} } = 2 \times {10}^{ - 2} \\ \)

9s simplify

\( \frac{ {10}^{9} \times 5 {q}^{2} }{ {10}^{ - 4} } = 2 \times {10}^{ - 2} \\ \)

Multiply sides by 10^-4

\(5 {q}^{2} \times {10}^{9} = 2 \times {10}^{ - 2} \times {10}^{ - 4} \)

\(5 {q}^{2} \times {10}^{9} = 2 \times {10}^{ - 6} \)

Divided sides by 10⁹

\(5 {q}^{2} = \frac{2 \times {10}^{ - 6} }{ {10}^{9} } \\ \)

\(5 {q}^{2} = 2 \times {10}^{ - 6} \times {10}^{ - 9} \)

\(5 {q}^{2} = 2 \times {10}^{ - 15} \)

Divided sides 5

\( {q}^{2} = \frac{2}{5} \times {10}^{ - 15} \\ \)

\( {q}^{2} = \frac{4}{10} \times {10}^{ - 15} \\ \)

\( {q}^{2} = 4 \times {10}^{ - 1} \times {10}^{ - 15} \)

\( {q}^{2} = 4 \times {10}^{ - 16} \)

\(q = \sqrt{4 \times {10}^{ - 16} } \)

\(q = 2 \times {10}^{ - 8} \)

\(q = 2 \times {10}^{ - 2} \times {10}^{ - 6} \)

\(q = 2 \times {10}^{ - 2} \: \: \: μc\)

Answer:

9.2

Explanation:

just multiply 4 miles times 2.3 then you get your answer

(a)The energy of each X-ray photon is 62 electron volts.

(b)About 3.32 x 10^8 X-ray photons are absorbed during the dental X-ray.

(a)To find the energy of a photon with a given wavelength, we can use the equation:

Ephoton = hc/λ

where h is Planck's constant (6.626 x 10^-34 J s), c is the speed of light (2.998 x 10^8 m/s), and λ is the wavelength in meters. We can convert the given wavelength of 0.020 nm to meters by multiplying by 10^-9:

λ = 0.020 nm x 10^-9 = 2.0 x 10^-11 m

Plugging in the values, we get:

Ephoton = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / (2.0 x 10^-11 m)

Ephoton = 9.94 x 10^-18 J

To convert this to electron volts (eV), we can use the conversion factor 1 eV = 1.602 x 10^-19 J:

Ephoton = (9.94 x 10^-18 J) / (1.602 x 10^-19 J/eV)

Ephoton = 62 eV

The energy of each X-ray photon is 62 electron volts.

(b). To find the number of photons absorbed, we can use the equation:

N = Etotal / Ephoton

where N is the number of photons absorbed, Etotal is the total energy delivered by the X-rays, and Ephoton is the energy of each photon. We can convert the given energy of 3.3 μJ to joules by multiplying by 10^-6:

Etotal = 3.3 μJ x 10^-6 J/μJ = 3.3 x 10^-9 J

Plugging in the values, we get:

N = (3.3 x 10^-9 J) / (9.94 x 10^-18 J/photon)

N = 3.32 x 10^8 photons

About 3.32 x 10^8 X-ray photons are absorbed during the dental X-ray.

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Answer:

Below

Explanation:

The balloon is moving horizontally the entire time it is in the air....after the sandbag is released , it to is moving horizontally until it hits the ground...

Balloon moves   ( 205 m / 2.5 m/s + 10s ) * 1.1 m/s = 101.2 m

The sandbag takes falls 205 m

205 =    1/2  a t^2      showing it takes  t= 6.46 seconds to hit the ground    it travels   6.46 s * 1.1 ms  = 7.1 m horizontally

101.2 + 7.1 = 108.3 m from launch site