what is inside an atom​

Conjugate acid-base pair is the combination of two compounds which can accept and donate hydrogen ions.

The compounds are HCI, H₂SO₄, HPO, Acetic acid, Formic Acid, HF, carbonic acid, ammonium ion, water, nitric acid.

a.

Conjugate bases of HCl is Cl⁻.

Conjugate bases of H₂SO₄ is HSO₄⁻.

Conjugate bases of HPO₄²⁻ is PO₄³⁻.

Conjugate bases of CH₃COOH is CH₃COO⁻.

Conjugate bases of formic acid is formate ion.

Conjugate bases of HF is F⁻.

Conjugate bases of carbonic acid is the bicarbonate.

Conjugate bases of ammonium ion ammonia.

Conjugate bases of water is H₃O⁺.

Conjugate bases of HNO₃ is NO₃⁻.

b.

HCl ⇄ H⁺ + Cl⁻

H₂SO₄ ⇄ 2H⁺ + SO₄²⁻

H₃PO₄ ⇄ H⁺ + PO₄³

CH₃COOH ⇄ H⁺ + CH₃COO⁻

HCOOH ⇄ H⁺ + HCOO⁻

HF ⇄ H⁺ + F⁻

H₂CO₃ + H₂O ⇄ HCO₃⁻ + H₃O⁺

Ammonia does not ionizes in water.

H₂O ⇄ H₃O⁺ + OH⁻

HNO₃ ⇄ H⁺ + NO₃⁻

c.

Strong acids: HCl, H₂SO₄, HNO₃,

Weak acids: H₃PO₄, CH₃COOH, HCOOH, HF, H₂CO₃, ammonium ion

Water is both weak and strong acid.

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The given question is incomplete.

The complete question is:

When methane is burned with oxygen, the products are carbon dioxide and water. If you produce 9 grams of water and 11 grams of carbon dioxide from 16 grams of oxygen, how many grams of methane were needed for the reaction?

Answer: 4 grams of methane were needed for the reaction

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

{tex]CH_4+2O_2\rightarrow CO_2+H_2O\)

Given:  mass of oxygen = 16 g

Mass of carbon dioxide = 11 g

Mass of water = 9 g

Mass of products = Mass of carbon dioxide + mass of water = 11 g  +9 g = 20 g

Mass or reactant = mass of methane + mass of oxygen = mass of methane + 16 g

As mass of reactants = mass of products

mass of methane + 16 g= 20 g

mass of methane  = 4 g

Thus 4 grams of methane were needed for the reaction

Avogadro's number states that:

1 mol of Cu = 63.54 g of Cu = 6.02x10^23 atoms of Cu

Now, we proceed like this:

1 kg = 1000 g ===> 187 kg = 187,000 g

63.54 g Cu -------- 6.02x10^23 atoms of Cu

187,000 g Cu -------- X

X = 1.77x10^27 atoms Cu

Answer: 1.77x10^27 atoms Cu

By the concept of calculating moles ,it can br concluded that the no. of atoms of phosphorus in 8.80mol of copper(II) phosphate is=1.06\(x10^{25}\)

A mole is defined as amount of substance containing as many as elementary entities that are there in atoms of exactly 12 g of carbon-12.Therefore we can say,1 mole of copper(II) phosphate, Cu3(PO4)2, contains three moles of copper(II) cations and two moles of phosphate anions.

Again 1mole of phosphate anions contains one mole of phosphorus and four moles of oxygen.Considering all these informations we can conclude that:1 mole of copper(II) phosphate contains 2 moles of Phosphorus

Accordingle the sample contains=(8.80\(x\)2) moles of Phosphorus

                                    =(17.6\(x\)Avogadro's constant) atoms of  Phosphorus

                                    =(17.6\(x\)6.022\(x\)\(10^{23}\)) atoms of  Phosphorus

                                    =1.06\(x10^{25}\) [approx] no. of Phosphorus atoms

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In 8.80 moles of copper(II) phosphate, there are approximately 1.06 x 10²⁵ atoms of phosphorus.

The number of atoms of phosphorus in a given amount of a compound can be calculated using the concept of mole in chemistry. Copper(II) phosphate is Cu3(PO4)2, containing 2 moles of phosphorus (P) for every 1 mole of the compound. Avogadro's number (6.022 x 10²³) gives the number of atoms in one mole.

So, if there are 8.80 moles of copper(II) phosphate, there would be 2 × 8.80 moles of phosphorus. Multiplying this by Avogadro's number gives the total number of phosphorus atoms.

Therefore, the number of phosphorus atoms is 2 × 8.80 × 6.022 x 10²³ = 1.06 x 10²⁵ atoms of phosphorus.

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Explanation:

Structural Formulas v. Empirical Formulas

An empirical formula (like a molecular formula) lacks any structural information about the positioning or bonding of atoms in a molecule. It can therefore describe a number of different structures, or isomers, with varying physical properties. For butane and isobutane, the empirical formula for both molecules is C2H5, and they share the same molecular formula, C4H10. However, one structural representation for butane is CH3CH2CH2CH3, while isobutane can be described using the structural formula (CH3)3CH.

Answer:

Moles of magnesium chloride can be produced are 0.2 moles

Explanation:

The reaction of Mg with Cl2 is:

Mg + Cl₂ → MgCl₂

Where 1 mole of Mg reacts per mole of Cl₂ to produce MgCl₂.

As the reaction is 1:1, we need to convert the mass of both Mg and Cl₂ to moles. The lower number of moles will determine the moles of MgCl₂ that will be produced:

Moles Mg -Molar mass: 24.3g/mol-:

4.86g * (1mol / 24.3g) = 0.2 moles Mg

Moles Cl₂ -Molar mass: 24.3g/mol-:

21.27g * (1mol / 70.9g) = 0.3 moles Cl₂

As moles of Mg < moles of Cl₂, Mg is limiting reactant and moles of magnesium chloride can be produced are 0.2 moles

If you accidentally add salt instead of sugar to a recipe, you can use vinegar to counteract the salty taste.

If you have added salt instead of sugar to a recipe, then you can try to remove the salt by adding a substance that will counteract its flavor. One such substance is vinegar, which is an acid and can help to neutralize the salty taste. Here are the steps to remove salt from a dish:

1. Remove as much of the salty liquid or sauce as possible.

2. Dilute the remaining sauce or liquid by adding more of the ingredients in the recipe, except for the salt

3. Taste the dish and add more sugar if needed.

4. If the dish is still too salty, add a little bit of vinegar.

5. Keep tasting the dish and adjusting the sugar and vinegar until it is no longer too salty.6. If the dish becomes too sweet, add more of the other ingredients to balance it out.

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The particle decay process described as 226 88 Ra → 222 Rn + He 86 involves the emission of a helium nucleus (He), which consists of two protons and two neutrons. This type of emission is known as alpha decay. Option A.

Alpha decay occurs when a radioactive nucleus releases an alpha particle, resulting in the emission of high-energy helium nuclei. In this case, the radium-226 (Ra) nucleus decays into radon-222 (Rn) by emitting an alpha particle. The resulting helium nucleus (He) is the emitted alpha particle.

Alpha particles have a positive charge and are relatively large and heavy. They are composed of two protons and two neutrons, which gives them a helium-like structure. Due to their size and charge, alpha particles have limited penetrating power and are typically stopped by a few centimeters of air or a sheet of paper.

Therefore, the correct answer A.  alpha radiation.

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Answer:Osmotic pressure is the minimum amount of pressure a solution must exert in order to prevent from crossing a barrier by osmosis. Solute molecules have difficulty crossing semipermeable membranes, so the more solutes that are in a solution, the higher the osmotic pressure will be. Between 30% sucrose and 60% sucrose, 60% sucrose will have a greater osmotic pressure than 30% because it has a higher percentage of solutes. However, since sucrose has a higher potential to cross semipermeable membranes and is more absorbable than magnesium sulfate, magnesium sulfate would have a higher osmotic pressure than 60% sucrose even though 60% sucrose has higher molecules.

Explanation:

The ideal gas law and stoichiometry must be used to calculate the volume of carbon dioxide gas produced by the breakdown of 4.09 g of calcium carbonate at STP (Standard Temperature and Pressure).

Use the molar mass of calcium carbonate (CaCO3) to determine how many moles it contains. CaCO3 has a molar mass of 100.09 g/mol.

CaCO3 mass divided by its molar mass equals the number of moles of CaCO3: 4.09 g/100.09 g/mol.

The number of moles of carbon dioxide (CO2) generated may be calculated using the stoichiometric ratio from the balancing equation. By using the equation:

A unit of CaCO3 and CO2 is produced.

CO2 moles equal the same number of moles of CaCO3.

Use the ideal gas law to translate the volume of carbon dioxide into moles.

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Answer:

1) Oxidation-Reduction (Redox) Reaction

2) Combustion Reaction

3) Decomposition Reaction

4) Synthesis Reaction

5) Single Displacement (Substitution) Reaction

6) Double Displacement (Metathesis) Reaction

7) Acid-Base Neutralization Reaction

8) Precipitation Reaction

Here are the Answer:

1. Oxidation-Reduction (Redox) Reaction

2. Combustion Reaction

3. Decomposition Reaction

4. Synthesis Reaction

5. Single Displacement (Substitution) Reaction

6. Double Displacement (Metathesis) Reaction

7. Acid-Base Neutralization Reaction

8. Precipitation Reaction

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These substances have dispersed particles that are large enough to scatter light, making the beam visible. Therefore, out of the options provided, a mixture that scatters light is an example of a colloid. Option B)

A colloid is a type of mixture in which particles are dispersed throughout a medium, creating a homogeneous appearance. Unlike solutions, where the particles are completely dissolved, and suspensions, where the particles settle out, colloids have particles that are larger than those in solutions but smaller than those in suspensions. One characteristic of colloids is that they can scatter light due to the size of the particles. This scattering of light is known as the Tyndall effect. Examples of colloids include milk, fog, and aerosol sprays. These substances have dispersed particles that are large enough to scatter light, making the beam visible. Therefore, out of the options provided, a mixture that scatters light is an example of a colloid. Therefore option B) is correct

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Note Complete Question

which is an example of a colloid?

a mixture that settles out,

b mixture that scatters light,

c mixture that is separated by filtration,  

d salt and water mixture?

Answer:

Ba + Cr + O₄

Answer:

Explanation:

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is:

HCl(aq) + NaOH(s) → NaCl(aq) + H2O(l)

From the balanced equation, we can see that one mole of hydrochloric acid reacts with one mole of sodium hydroxide to produce one mole of sodium chloride and one mole of water.

First, we need to determine which reactant is limiting, i.e., which reactant is completely consumed in the reaction. To do this, we need to compare the number of moles of each reactant, using their respective molar masses:

Molar mass of HCl = 1.008 g/mol (atomic weight of hydrogen) + 35.45 g/mol (atomic weight of chlorine) = 36.46 g/mol

Molar mass of NaOH = 22.99 g/mol (atomic weight of sodium) + 16.00 g/mol (atomic weight of oxygen) + 1.008 g/mol (atomic weight of hydrogen) = 39.99 g/mol

Number of moles of HCl = mass / molar mass = 30.0 g / 36.46 g/mol ≈ 0.823 mol

Number of moles of NaOH = mass / molar mass = 14.3 g / 39.99 g/mol ≈ 0.358 mol

Since the stoichiometric ratio between HCl and NaOH is 1:1, NaOH is the limiting reactant because it has fewer moles than HCl.

Therefore, we can calculate the maximum mass of NaCl that can be produced by the reaction using the number of moles of NaOH:

Number of moles of NaCl produced = number of moles of NaOH used in the reaction = 0.358 mol

Mass of NaCl produced = number of moles of NaCl produced x molar mass of NaCl

Molar mass of NaCl = 22.99 g/mol (atomic weight of sodium) + 35.45 g/mol (atomic weight of chlorine) = 58.44 g/mol

Mass of NaCl produced = 0.358 mol x 58.44 g/mol = 20.9 g

Therefore, the maximum mass of NaCl that can be produced by the reaction is approximately 20.9 g

The dissociation of cadmium chloride is as follows: CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)

Dissociation is the process by which a compound body breaks up into simpler constituents; said particularly of the action of heat on gaseous or volatile substances.

It is a chemical reaction in which a compound breaks apart into two or more components. The general formula for a dissociation reaction follows the form:

AB → A + B

According to this question, cadmium chloride undergoes dissociation into cadmium and chlorine ions as follows:

CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)

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a. Atomic number 16 is Sulfur its electronic configuration is:  

 1s2 2s2 2p6 3s2 3p4

b. Atomic number 11 is Sodium its electronic configuration is:

 1s2 2s2 2p6 3s1

c. Atomic number 32 is Germanium its electronic configuration is :

 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p2

d. Atomic number 47 is Silver its electronic configuration is :

  1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s1

e. Atomic number is 12 Magnesium its electronic configuration is :

  1s2 2s2 2p6 3s2

f. Atomic number 28 is Nickel its electronic configuration is :

 1s2 2s2 2p6 3s2 3p6 4s2 3d8

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Answer:

Explanation: Nitrogen triple bonding with nitrogen is a covalent bond. Each nitrogen needs three electron to fill its octet so both nitrogen atoms will share the electrons. Chlorine- Chlorine has a covalent bond. Each chlorine atom needs one electron to fill its octet and so both chlorine atoms share. Bromine-Flouride is polar because of the difference in electronegative, flourine being the more electronegative of the two.

The type of compound represented by the graph at right is a strong acid (option B).

An acid is generally any compound capable of dissociating into its respective constituent ions when in an aqueous solution.

An acid is categorised as strong or weak depending on whether it can dissociate completely or partially. A strong acid dissociates completely in water.

According to this question, HA, when added to water, dissociates into H+ and A- ions, hence, is a strong acid.

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ANSWER

Fe³⁺ is being reduced

Fe³⁺ + 3e⁻ → Fe

EXPLANATION

Fe³⁺ is reduced as in the reaction, Fe goes from +3 to 0 which indicates the gain of electrons.

Answer:

2

Explanation:

final velocity: 20

initial velocity: 0

time taken: 10

acceleration: ?

a=( v-u)÷2

a=(20-0)÷2

a=20÷2

therefore acceleration =2

The moles of \(N_2\) and \(H_2\) that were present originally in the reaction will be 1.5 moles and 2.5 moles respectively.

The two reactants,  \(N_2\) and \(H_2\), react in a closed container to form \(NH_3\). The normal stoichiometric ratio of the reaction is according to the following equation:

\(N_2 (g) + 3H_2 (g) --- > 2NH_3 (g)\)

The stoichiometric ratio of  \(N_2\), \(H_2\), and \(NH_3\) is 1:3:2.

This means for every 1 mole of ammonia formed, 0.5 moles of \(N_2\) and 1.5 moles of \(H_2\) is required.

However, 1 mole of \(N_2\) and 1 moles of \(H_2\) remained after the reaction has ceased.

Thus, total amount of  \(N_2\) present originally = 1 + 0.5

                                                                           = 1.5 moles

Total amount of  \(H_2\) present originally = 1 + 1.5

                                                               = 2.5 moles

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Answer:

methane

Explanation: methane is obtained from the decaying of flora and fauna mostlyunder damp

Answer:

The final temperature of the copper would be 311.3°C.

I hope this helps you

Answer:

12

Explanation:

Let's consider the basic reaction of methylamine.

CH₃NH₂ + H₂O ⇄ CH₃NH₃⁺ + OH⁻

The concentration of the weak base is Cb = 0.195 M and the basic dissociation constant is Kb = 4.4 × 10⁻⁴. We can calculate the concentration of OH⁻ using the following expression.

[OH⁻] = √(Kb × Cb)

[OH⁻] = √(4.4 × 10⁻⁴ × 0.195) = 9.3 × 10⁻³ M

The pOH is:

pOH = -log [OH⁻] = -log 9.3 × 10⁻³ = 2.0

The pH is:

pH + pOH = 14

pH = 14 - pOH = 14 - 2.0 = 12

The pH of the 0.195 M methylamine solution has been 12.0.

The pH of the solution has been defined as the hydrogen ion concentration in the sample. The pOH has been the hydroxide ion concentration in the sample.

From the Kb of the methylamine, the hydroxide ion concentration of the solution can be determined as:

[\(\rm OH^-\)] = \(\rm \sqrt{Kb\;\times\;concentration}\)

[\(\rm OH^-\)] = \(\rm \sqrt{4.4\;\times\;10^-^4\;\times\;0.195}\)

[\(\rm OH^-\)] = 9.3 \(\rm \times\;10^-^3\) M

The pOH of the solution can be calculated as:

pOH = -log [\(\rm OH^-\)]

pOH = -log 9.3 \(\rm \times\;10^-^3\)

pOH = 2.0

The sum of pH and pOH has been a constant quantity.

pH + pOH = 14

pH + 2 = 14

pH = 14 - 2

pH = 12.0

The pH of the 0.195 M methylamine solution has been 12.0.

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The name of the salt tells us that:

a) there is just one other element combined with the metal by looking at the suffix of the salt's name.

b) the presence of oxygen in a salt can be indicated by the name of the salt.

a) The name of a salt can tell us that there is just one other element combined with the metal by looking at the suffix of the salt's name. If the salt name ends in "-ide," it indicates that the salt is composed of a metal and a single non-metal element.
For example, sodium chloride (NaCl) and potassium bromide (KBr) are salts where the metal (sodium and potassium) is combined with a single non-metal element (chlorine and bromine, respectively). The "-ide" suffix suggests the presence of only one other element in the salt.

b) The presence of oxygen in a salt can be indicated by the name of the salt. If the salt name includes the element oxygen, it suggests that oxygen is present in the salt compound.
For example, sodium carbonate (Na₂CO₃) and calcium sulfate (CaSO₄) contain the element oxygen in their chemical formulas. The presence of oxygen in the salt is implied by the name and the combination of elements in the compound.

Therefore, the name of salt tells us that there is just one other element combined with the metal and there is oxygen present in the salt

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Answer:

Explanation:

Hey there!

From question;

The molecular mass of NH₄OH is 35.

Avogadro number = 6.023*10²³ molecules.

Then,

From mole concept,

Molecular mass =  Avogadro number

So, 35 grams contains  6.023*10²³ molecules.

1 gram contains \(\frac{ 6.023*10^{23} }{35}\) molecules.

52.1 grams contains \(\frac{6.023*10^{23} }{35} *52.1\) molecules.

Therefore, 52.1 grams contains 8.96*10²³ molecules.

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The answer is A: Oil.

Answer:

Explanation:

A. Oil

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