What is heat?What are it's units?​

Answer:

Yes

Explanation:

I think our memories can be altered by emotions. If someone tells you something over and over and over again with strong emotion you will start to remember that more than the memory.

Emotions are very powerful and if you feel a certain emotion connected with a different memory I think that is stronger and can trick your brain into thinking that is the memory because of the strong emotion, even though the true memory was right, since it might not have as strong of mental emotion your brain will think that is the false memory because whatever is more memorable your brain will remember.

If that makes any sense,

If the value of h₀ (Hubble constant) is 60 km/s/Mpc (kilometers per second per megaparsec), the order of decreasing energy for the types of electromagnetic radiation remains the same: gamma rays > microwaves > radio waves.

The Hubble constant represents the rate at which the universe is expanding. It relates the recessional velocity of distant galaxies to their distances from us.

The value of the Hubble constant has been a subject of ongoing research and refinement, and different measurements have yielded varying results over time.

However, the value of the Hubble constant does not affect the order of electromagnetic radiation in terms of energy. The energy of electromagnetic radiation is determined by its wavelength or frequency, and the order remains consistent regardless of the specific value of the Hubble constant.

Therefore, even with a different value for h₀, the correct order of decreasing energy for gamma rays, microwaves, and radio waves remains unchanged: gamma rays > microwaves > radio waves. The energy of gamma rays is still higher than that of microwaves and radio waves, regardless of the Hubble constant value.

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The length of the straight line drawn from one side of the hoop to the other, passing through the center, is approximately 25.3 inches.

To find the length of the line, we need to find the diameter of the circle, which is the straight line drawn from one side of the hoop to the other, passing through the center.

The circumference of the circle is equal to the length of the strip of metal, which is 79.5 inches. The formula for the circumference of a circle is C = πd, where C is the circumference and d is the diameter. We can rearrange this formula to solve for the diameter:

d = C/π

Substituting the given values, we get:

d = 79.5/π

d ≈ 25.3 inches

Therefore, the length of the line, which is the diameter of the circle, is approximately 25.3 inches.

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Answer:

a = 5 m/s^2

Explanation:

The force is constant. The distance does not matter if there is no friction. This is an example of Newton's second law.

F = m * a

F = 10 N

m = 2 kg

a = ?

10 = 2 * a    Divide by 2

10/2 = a

a = 5 m/s^2 second from the bottom.

→ The charge in electron charge Q(e) is equal to the charge in coulombs Q(C) times 6.24150975⋅1018:

1C = 6.24150975⋅10¹⁸e

Q(e) = Q(C) × 6.24150975 × 10¹⁸

Q(e) = 96,500 × 6.24150975 × 10¹⁸

Q(e) = 6.02305690875 × 10²³

which is round off to

→ 6.03 × 10²³ electrons

(a) The magnitude of the force propelling the bobsled forward is 648 N. (b) The magnitude of the net force acting on the bobsled is 198 N.

Use Newton's second law of motion, which states that force equals mass times acceleration (F = ma). Rearranging the formula, we get F = ma, where F is the force, m is the mass, and a is the acceleration.

So, the force propelling the bobsled forward is,

F = ma = (270 kg)(2.4 m/s^2) = 648 N

The net force acting on the bobsled can be calculated by subtracting the forces resisting the motion from the force propelling the bobsled forward. So, the net force acting is,

Net force = Force propelling forward - Forces resisting motion

Net force = 648 N - 450 N

Net force = 198 N

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Answer:heart

The hardest working muscle is the heart. It pumps out 2 ounces (71 grams) of blood at every heartbeat. Daily the heart pumps at least 2,500 gallons (9,450 liters) of blood. The heart has the ability to beat over 3 billion times in a person's life.

Explanation:hope this helps

the charge of each cylinder given the following additional information about each one is 10434.445 coulomb, 14906.35 Coulomb, 178876.2 coulomb, 223,595.25 coulomb.

To solve this question we are to use the equation 1 below :

Charge Q = uniform charge density p × Total area of the cylinder A

From the question, we are given radius, R to be 2.33 cm and length, L to be 5.82 cm.

Calculate for the total area of the cylinder, A. equation 2

Total area of the cylinder, A = area of the top surface + area of the bottom + area of the curved surface of the cylinder.

Hence, total area of the cylinder A is;

πR^2 + πR^2 + 2πRL.

Then, total area of the cylinder A is;

(L + R)2πR.

find the charge of each cylinder equation 3

For the first cylinder; we have the uniform charge density to be 35 nC/m^2.

Therefore, the combination of equation (1) and (3) gives equation 4

Charge Q= p × (L + R)2πR

Hence,

Charge Q = 35 × [(5.82 + 2.33) 2× 3.143 × 5.82]

Charge Q = 10434.445 coulomb.

For the cylinder B, we have a uniform charge density of 50 nC/m^2.

Using equation (4),

charge Q =  p × (L + R)2πR

= 50 × [(5.82 + 2.33) 2× 3.143 × 5.82]

= 14906.35 Coulomb

For The cylinder C, the uniform charge density is 600, we use of equation (4);

Charge Q = 600 × 298.127

Charge Q = 178876.2 coulomb.

For cylinder D, the uniform charge density is 750 nC/m^2. use of equation (4)

Charge Q = 298.127 x 750

charge Q = 223,595.25 coulomb.

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Answer:

\(1000\; {\rm N}\).

Explanation:

By Pascal's Law, the pressure on the two pistons should be the same.

Let \(F_{\text{in}}\) and \(F_{\text{out}}\) denote the forces on the two pistons. Let \(A_{\text{in}}\) and \(A_{\text{out}}\) denote the area of the two pistons.

Divide force by area to find the pressure.

By Pascal's Law, \(P_{\text{in}} = P_{\text{out}}\). Therefore:

\(\displaystyle \frac{F_{\text{in}}}{A_{\text{in}}} = \frac{F_{\text{out}}}{A_{\text{out}}}\).

It is given that \(F_{\text{in}} = 40\; {\rm N}\) and that \(A_{\text{out}} = 25\, A_{\text{in}}\). Therefore, the equation becomes:

\(\displaystyle \frac{40\; {\rm N}}{A_{\text{in}}} = \frac{F_{\text{out}}}{25\, A_{\text{in}}}\).

Rearrange to find \(F_{\text{out}}\):

\(\begin{aligned}F_{\text{out}} &= \frac{(40\; {\rm N})\, (25\, A_{\text{in}})}{A_{\text{in}}} = 1000\; {\rm N}\end{aligned}\).

The speedometer of a car measures instantaneous speed. It tells you the speed of the car at any given moment in time.

The speedometer of a car measures instantaneous speed. This means it gives the reading of the speed at any given moment in time.

Main part: The speedometer of a car measures instantaneous speed. It tells you how fast you are driving at that particular moment. The speedometer gives you a direct reading of how fast your vehicle is traveling. It measures the vehicle's speed at any given moment in time, rather than calculating the average speed of the entire journey.

A speedometer is attached to a vehicle's wheels to measure its speed. As the wheels turn, the speedometer calculates the speed at which they are turning. Inside the speedometer, there is a component called a speedometer cable. This component is connected to the back of the speedometer's drive mechanism. The other end of the cable is connected to a gear that is inside the transmission or the transfer case. When the vehicle is moving, the driveshaft turns the gears in the transmission or transfer case. The gear connected to the speedometer cable also turns, causing the cable to rotate. The rotation of the cable creates a magnetic field that drives the speedometer's magnetometer, which is connected to the speedometer pointer. This causes the pointer to move along the dial and show the speed of the vehicle on the speedometer.

Conclusion: In conclusion, the speedometer of a car measures instantaneous speed. It tells you the speed of the car at any given moment in time.

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Answer:

1) F = 24 N

2) Distance = 1 m

Explanation:

We are given;

Mass; m = 120 g = 0.12 kg

Initial velocity; u = 20 m/s

Final velocity; v = 0 m/s since it came to rest.

Time; t = 0.1 s

We can calculate acceleration from Newton's first equation of motion;

a = (v - u)/t

a = (0 - 20)/0.1

a = -200 m/s²

1) magnitude of the resistance will be;

F = ma

F = 0.12 × (-200)

F = -24 N

Since, we are dealing with the magnitude, we will take the absolute value. Thus, F = 24 N

2) To find the distance moved by the bullet, we know that;

Distance = Average speed × time

Thus;

Distance = ((v + u)/2) × t

Distance = ((0 + 20)/2) × 0.1

Distance = 1 m

Explanation:

Distance is the length of the path.

d = 3 km + 4 km

d = 7 km

Displacement is the difference between the final position and initial position.

x = 3 km + (-4 km)

x = -1 km

x = 1 km south

The distance will be "7 km" and displacement be "1 km (south)".

Distance would be a scalar number that describes "that however much ground an item had also adequately covered" while moving.

Displacement would be a vector variable which thus describes "just how out of placement of an item represents"; everything just reflects the amount change throughout the position of the object.

According to the question,

David walk,

Now,

The distance (d) be:

= \(3+4\)

= \(7\) km

and,

The displacement (x) be:

= \(3+(-4)\)

= \(3-4\)

= \(-1\) km i.e.., \(1\) km (south)

Thus the response above are correct.

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Power can be defined as the rate at which work is accomplished.

Option D is the correct answer.

The work done by an object in a given time interval is called the power of that object.

Suppose an external force F is applied to any object for the time interval T seconds. Due to this external force, the object will perform some amount of work for the time T seconds. This work W done by the object for the time interval T seconds is called the power of that object.

Power can be defined in mathematical term which is given below.

\(P = \dfrac {W}{T} \;\rm Watts\)

Thus the power can also be defined as the work done by the object per unit time interval.

Hence we can conclude that option D is the correct answer.

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The radioactivity of the element after 5 minutes is 75 Bq.

Radioactivity is a phenomenon exhibited by radioactive elements or isotopes by emitting energy and subatomic particles spontaneously.

The radioactivity of a radioactive element or isotope in  becquerels is denoted by decay per second.

The radioactivity of the isotope in  becquerels is calculated as follows;

Bq = decay / time

Half life = 10 min

This implies that after 10 minutes, the activity of the element will be;         ¹/₂(100 Bq) = 50 Bq

The given time, 5 minutes is not up to 10 minutes, so the element will not be reduced to 50 Bq.

5 minutes = half of 10 minutes

half of 50 Bq = 25 Bq

So after 5 minutes, the element will decay 25 Bq, and the activity will be 75 Bq.

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Answer: f= 100n

Explanation: So you will have to multiply 20kg to 5m/s2 and that how you will get F= 100N

The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is A m/C (ampere meter per coulomb). This unit represents the ratio between the electric field and the magnetic field, indicating the strength and direction of the electromagnetic field.

The SI unit of electric field (E) is NC^(-1) (newton per coulomb) and the SI unit of magnetic field (B) is NA^(-1) m^(-1) (tesla). To determine the unit of E/B, we need to divide the unit of E by the unit of B.

Dividing the unit of E (NC^(-1)) by the unit of B (NA^(-1) m^(-1)), we can simplify the expression:

E/B = (NC^(-1))/(NA^(-1) m^(-1))

To simplify this expression, we can cancel out the common units in the numerator and denominator:

E/B = (N/C)/(N/(A m))

Now, let's simplify further by dividing the numerator and denominator:

E/B = (N/C) * (A m/N)

Canceling out the common units:

E/B = (A m)/(C)

Therefore, the unit of E/B is A m/C (ampere meter per coulomb).

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False, because in a rear tire skid when the rear wheel is in line with the front wheel, you want to release the rear brake to quickly straighten the motorcycle.

Understanding the rationale behind each correct response on the motorcycle written test is crucial for passing your motorbike permit examinations and developing into a safe rider.

When riding a motorcycle, a rear wheel skid can be a risky circumstance to encounter.

When the rear wheel locks up as a result of excessive braking, rear wheel skids happen.

You won't be able to turn around if the rear wheel locks up and starts to slide.

You must relieve the pressure on the rear brakes to stop the skidding of the rear wheels. However, the bike might quickly straighten out and knock you off in a high-side crash if the front and rear wheels are not in line when you remove the rear brake.

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The material the parachute is made out of" will not be a suitable control variable as it is needed in the research.

It should be noted that a control variable simply means any variable that is held constant in a research.

In this case, the material the parachute is made out of" will not be a suitable control variable as it is needed in the research.

Therefore, it's false.

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The distance between two lines in the diffraction  is 3.84 x 10^-4 cm.

Diffraction refers to the bending or spreading of waves around an obstacle or through an opening, resulting in an interference pattern. It is a phenomenon that occurs when waves encounter an object or an opening that is comparable in size to their wavelength.

Diffraction is observed with different types of waves, such as light waves, sound waves, and water waves. The distance between two lines in a diffraction grating can be calculated as follows:

d = 1 / (number of lines per unit length)

For a diffraction grating with 2590 lines per cm, the distance between two lines can be calculated as follows:

d = 1 / (2590 lines/cm)

=> 1 / 2590 cm/line

=> 3.84 x 10^-4 cm/line

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Answer:

Geothermal energy can be trapped using geothermal plants that utilizes steam escaping from the earth surface to make electricity.

The limitations include :

Explanation:

Geothermal energy originates in form of heat/steam escaping from the inner parts of the earth surface. The steam trapped is converted to electricity through turbines. The hot water pumped by heat pumps can be used to heat homes or for heating purposes in industries.

The limitations of geothermal energy are high initial capital costs for installing the systems, depletion of geothermal sites after sometime, environmental concerns due to greenhouse gases emissions and land requirements for geothermal projects.

No atomic  model is a picture of an atom but only helps explain the behavior of one

We know that the atom is the smallest particle of a substance that is able to take part in a chemical reaction. We know that in the atom there are certain smaller particles that we can be able to refer to as the subatomic particles.

In this case, we are talking about the different models that we can be able to use to show the atom. None of these models can be said to show the atom exactly but can approximate how the atom behaves.

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Formula of

Line segment

is AB =

\(\sqrt{(x_{2} -x_{1} )^{2} } +\sqrt{(y_{2} -y_{1} )^{2} }\)

Line segment

is a part of line with definite length. It has two ending points whereas a line has no end points and extended infinitely in both the direction. Line which joins both ending points with possible shortest way is known as

Line segment

.

            A ______________________ B    

        (x₁,y₁)                                             (x₂,y₂)      

This line segment can be represented as \(\frac{}{AB} /\frac{}{BA}\). In other word we can say line segment is

subset

of line, so it contains all the points of line lying between both end point of segment. For shorter length it can simply measure by

ruler

. A bar (-) is always on top of its notation {\(\frac{}{AB}\)}.

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Formula of Line segment is AB =  \(\sqrt{(x_{2}-x_{1})^{2} } +\sqrt{(y_{2}-y_{1})^{2} }\)

Line segment

is a part of line with a definite length. It has two ending points whereas a line has no end points and extended infinitely in both the direction. Line which joins both ending points with possible shortest way is known as

Line segment

        A ______________________ B    

       (x₁,y₁)                                             (x₂,y₂)      

This line segment can be represented as\(\overline{AB}/\overline{BA}\) . In other word we can say line segment is subset of line, so it contains all the points of line lying between both end point of segment. For shorter length it can simply measure by ruler A bar (-) is always on top of its notation {\(\overline{AB}/\overline{BA}\)}.

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Answer:

Where is the question?

Explanation:

Answer:

6 Newtons to the left.

Explanation:

We can convert  this into a generic algebra equation by giving directions positive and negative values.

The 6 will be positive, and the 10 and 2 will be negative.

Add 10 and 2 to have 12.

6-12 = -6.

Therefore you have 6 newtons to the left (negative).

Note that the correct times are t = 0, t = 1/4, t = 1/2. You can tell from the spaces between the two digits. i.e 1&4 and 1&2

Answer:

y(0) = 2.00 cm

y(1/4) = 1.56 cm

y(1/2) = 1.21 cm

Explanation:

This is a very simple exercise, the displacement of the oscillating weight from equilibrium has already been modeled by the equation:

\(y(t) = 2e^{-t} cos 4t\)

Where y = displacement ( in cm)

and t = time (in seconds)

The task is to find the displacement when t = 0, 1/4 and 1/2

When t = 0 s

\(y(0) = 2e^{0} cos 4(0)\\y(0) = 2* 1*1\\y(0) = 2.00 cm\)

When t = 1/4 s

\(y(1/4) = 2e^{-1/4} cos 4(1/4)\\y(14) = 2e^{-1/4} cos (1)\\y(1/4) = 1.56 cm\)

When t = 1/2

\(y(1/2) = 2e^{-1/2} cos 4(1/2)\\y(14) = 2e^{-1/2} cos (2)\\y(1/2) = 1.21 cm\)

The work done by gravity on the block depends on the system under consideration. If the system consists of the block only, the work done by gravity is zero. If the system includes both the block and the Earth, the work done by gravity is negative.

Work is defined as the product of the force applied on an object and the displacement of the object in the direction of the force. In the case of gravity, the force acts vertically downward and the displacement is in the opposite direction when the block is lifted upward.

When considering the system as only the block, the gravitational force and the displacement are in opposite directions. Therefore, the work done by gravity on the block is zero because the cosine of the angle between the force and displacement is 180 degrees, resulting in a negative value.

However, if we consider the system as both the block and the Earth, the displacement of the block is in the same direction as the gravitational force between the block and the Earth. In this case, the work done by gravity on the block is negative because the cosine of the angle between the force and displacement is 0 degrees.

Hence, the work done by gravity on the block is zero if the system consists of the block only, and it is negative if the system consists of both the block and the Earth.

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The average reaction distance is around 1 second at 20 mph. Let's say that the distance covered by the vehicle in 1 second is 8 meters. Therefore, the reaction distance is 8 meters.

Braking distance is the distance the vehicle travels from the time the driver applies the brakes until the time the vehicle comes to a complete stop. This distance is affected by many factors such as road conditions, tire conditions, and the condition of the brakes. On dry roads, the average braking distance is around 4 times the speed of the vehicle in meters.

Let's say the vehicle weighs 1,000 kg and has good brakes and tires. In this case, the braking distance would be around 24 meters (4 x 20 x 0.25).

Therefore,Stopping Distance = Perception Distance + Reaction Distance + Braking Distance= 7.5 + 8 + 24= 39.5 meters.

Now, let's calculate the distance required to stop a vehicle traveling at a speed of 40 mph.

Stopping Distance = Perception Distance + Reaction Distance + Braking Distance.

As the length of the vehicle and the reaction time of the driver do not change, the only variable that changes in this equation is the braking distance.

Therefore, Stopping Distance = Perception Distance + Reaction Distance + Braking Distance= 7.5 + 8 + (4 x 40 x 0.25)= 79 meters.

Therefore, if the speed of a vehicle doubles from 20 mph to 40 mph, the distance required to stop the vehicle increases by 4 times.

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Answer:

0.76 lbs (if shoes 2lbs)

Explanation:

Gravity on Mars is only ~38% as strong as it is on Earth, so objects would only weigh ~38% of their Earth weight.