1. Write a mechanism for the E1 elimination reaction of 2-methylcyclohexanol with phosphoric acid. Be as complete as possible and show electron flow for all steps. You should clearly indicate the mechanistic pathways that lead to each of the products formed in the reaction (there is no need to duplicate common steps, but at some point the pathways diverge)

Answer:

Explanation:

Those are the answers in order, BUT the Goldstein and Rutherford ones are confusing me because Rutherford discovered protons and the nuclear atom. Through my research I also noticed that Goldstein contributed to the discovery of the protons made Rutherford, so I listed him as the one who discovered the proton.

I hope this helps! Have a wonderful night! :D

Answer:

Explanation:

Indira point is the southern most point of India and is situated on great nicobar island in the nicobar island.

Answer:

Your Ans Is

(A) Indra point.

Answer: 0.72

Explanation:

550 mmHg x 1 atm/ 760 mmHg = 0.72 atm

Answer:

Volume of one mole of any gas at NTP is

(b) 22.4 litre

Answer:

22.4L

Explanation:

One mole of any gas at STP weighs 22.4L.

STP stands for Standard Temperature and pressure

Answer: B

Explanation: molarity = concentration c= n/V = 0.5 mol/ 0.05 l = 10 mol/l

The molarity of  a solution is the number of moles of its solute divided by volume in liters. The molarity of the 50 ml solution containing 0.5 moles of potassium fluoride is 10 M or 10 molar.

Molarity is a common term used to express the concentration of a solution. It is the ratio of number of moles of solute particles to the volume of solution in liters. Hence, its unit is mol/L or molar.

The molarity of a solution is a colligative quantity as well as temperature dependent.

Given,

no.of moles of potassium fluoride salt in water = 0.5 moles.

volume of solution = 50 ml

1 L = 1000 ml

then 50 ml = 0.05 L.

Molarity = no.of moles of solute/ volume of solution in L

M = 0.5 moles/ 0.05 L

   = 10 M.

Therefore, the molarity of the given solution is 10 molar.

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Answer:

Yellow Peas

Explanation:

Answer:

yellow

Explanation:

Answer:

26

Explanation:

Answer:

Reactants: NaBr and CA(OH)2

Products: CaBr and NaOH

Explanation:

Reactants are always on th left side of the equation and products on the right side

Answer:

Explanation:

Volume of one mole of a gas = 22.4 litre.

No of molecules in one mole of gas = 6.02 x 10²³ .

Volume of one molecule = 4/3 π R³

= 4/3 x 3.14 x ( 167 x 10⁻¹² m )³

= 19.5 x 10⁶ x 10⁻³⁶ m³

=19.5 x 10⁻³⁰ m³

= 19.5 x 10⁻³⁰ x 10³ litre .

=  19.5 x 10⁻²⁷ litre .

So volume occupied by molecules in one mole of gas

= 19.5 x 10⁻²⁷ x 6.02 x 10²³  litre

117.4 x 10⁻⁴ litre

= .01174 litre.

Excluded volume

= ( 22.4 -  .01174  ) litre .

= 22.388 litre.

Answer:

SO4²

Explanation:

Formula and structure: The sulfate ion formula is SO42- and the molar mass is 96.06 g mol-1. This salt is formed by one sulfate center to which 4 atoms of oxygen are attached, 2 of these atoms are forming S=O.

Answer:

\(so _{4} ^{2 - } \)

Explanation:

sulfate is consisting of sulfur element with 4 oxygen as the structure in the pic given and this group is 2- charged

In order to secure reliable sources of rubber, tin, rice, scrap iron and liquid fuel, japan decided it must both seize much of southeast asia and attack united states pacific bases in hawaii and elsewhere

When first created, natural rubber, also known as caoutchouc or India rubber, is made of polymers of the organic compound isoprene, along with water and trace amounts of other organic compounds. The top two producers of rubber are Thailand and Indonesia. Elastomers are a category for different types of polyisoprene that are used as natural rubbers. At the moment, rubber is mostly obtained from rubber trees or other sources as latex. Making incisions in the bark and collecting the fluid in vessels is a process known as "tapping," which removes the latex, a sticky, milky colloid. The rubber created from the refined latex is then ready for industrial processing. Latex is allowed to coagulate in the collection cup in major areas.

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The volume concentration of clay exchange cations (Qv) in the sand is estimated to be 0.54 meq/cm³.

This value is calculated by multiplying the weight percent of montmorillonite clay (10 wt%) by the QCEC value (1.0 meq/g) and dividing it by the grain density (2.70 g/cc) and porosity (20%).

To calculate the volume concentration of clay exchange cations (Qv), we start by converting the weight percent of clay to meq/cm³. First, we convert the QCEC value from meq/g to meq/cc by dividing it by the grain density: 1.0 meq/g / 2.70 g/cc = 0.37 meq/cc.

Next, we multiply the weight percent of clay (10 wt%) by the QCEC value in meq/cc: 10 wt% * 0.37 meq/cc = 0.037 meq/cc.

Since the porosity is given as a percentage, we convert it to a decimal by dividing by 100: 20% / 100 = 0.20.

Finally, we divide the volume concentration of clay exchange cations by the porosity: 0.037 meq/cc / 0.20 = 0.185 meq/cc.

Therefore, the volume concentration of clay exchange cations (Qv) in the sand is estimated to be 0.185 meq/cc or 0.54 meq/cm³.

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The ratio of the resistance of wires Y and X is 2:1

Resistance in an electrical circuit is used to calculate the current flow. The symbol for the ohm, a unit of measurement for resistance, is omega. The unit of resistance is named after German physicist Georg Simon Ohm, who looked into the relationship between voltage, current, and resistance. He is credited for creating Ohm's Law.

To ascertain the state of a component or circuit, resistance measurements are frequently made.

Since resistance is independent of length, it stays constant. The term resistivity itself refers to the material's resistance per unit length and unit area.

While the resistance depends on the length

R₁=ρL/A

R₂=ρ2L/A

R₂=2ρL/A

R₂=2R₁

Thus, the resistance of a second wire is twice that of a first wire.

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Answer:

Element 5 - Boron

Element 14 - Silicon

Element 32 - Germanium

Element 33 - Arsenic

Element 51 - Antimony

Element 52 - Tellurium

General Formulas and Concepts:

Chemistry

Explanation:

Your Metalloids on the Periodic Table define what we know as "The Staircase." It separates the Transition Metals from the Non-metals. Metalloids are found in Groups 13 - 16.

Attached below is the Metalloids in order from the Periodic Table (in Cyan).

Answer:

A. 6 moles

Explanation:

This question contains a chemical reaction between aluminum (Al) and Copper(II)Chloride to give copper and aluminum chloride. The unbalanced chemical equation is as follows:

Al (s) + 3CuCl2 (aq) → Cu (s) + 2AlCl3

To balance the equation, we use coefficients in front of Al and Cu to ensure the amount of both are uniform on both sides of the equation. The balanced equation is as follows;

2Al (s) + 3CuCl2 (aq) → 3Cu (s) + 2AlCl3

From the balanced equation, 2 moles of Al reacts with 3 moles of CuCl2

Hence, 4 moles of Al will react with (4 × 3) ÷ 2

= 12 ÷ 2

= 6 moles of CuCl2

The balanced equation for the combustion of methane with oxygen gas is: CH4 + 2O2 → CO2 + 2H2O. From this equation, we can see that for every molecule of methane that is burned, two molecules of oxygen gas are required, and one molecule of carbon dioxide is produced, along with two molecules of water vapor.

To determine the amount of carbon dioxide produced when 63452 liters of oxygen gas reacts with an excess of methane at STP, we need to first calculate the amount of methane consumed in the reaction. Since the oxygen is in excess, we can use the amount of methane to determine the amount of carbon dioxide produced. To do this, we use dimensional analysis: 63452 L O2 × (1 mol O2 / 22.4 L O2) × (1 mol CH4 / 2 mol O2) × (1 mol CO2 / 1 mol CH4) × (22.4 L CO2 / 1 mol CO2) = 63452 L CO2 So, the answer is 63452 liters of carbon dioxide is produced when 63452 liters of oxygen gas combusts with an excess of methane at STP.

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The limiting reactant for the combustion reaction of acetylene is oxygen (O2).

In order to determine the limiting reactant, we compare the stoichiometric ratio of the reactants to the amount of each reactant available. From the balanced equation, we can see that the ratio of C2H2 to O2 is 2:5. Therefore, for complete combustion to occur, 2 moles of C2H2 require 5 moles of O2.

Given that the acetylene tank contains 37.0 mol of C2H2 and the oxygen tank contains 81.0 mol of O2, we can calculate the amount of O2 required to react with 37.0 mol of C2H2 by using the stoichiometric ratio:

(37.0 mol C2H2) × (5 mol O2 / 2 mol C2H2) = 92.5 mol O2

Since the available amount of O2 (81.0 mol) is less than the required amount (92.5 mol), oxygen is the limiting reactant. Therefore, the acetylene (C2H2) is in excess, meaning there will be some unreacted acetylene left after the reaction is complete.

The stoichiometric ratio of the reactants tells us the exact ratio in which they should react to form the products. In this case, the ratio of C2H2 to O2 is 2:5. By comparing the available amounts of each reactant to this ratio, we can determine which reactant will be completely consumed, thus limiting the reaction. In this scenario, we find that the available amount of O2 is insufficient to react with all of the C2H2. This means that after all the O2 is consumed, there will still be unreacted C2H2 left.

To confirm this, we calculate the amount of O2 required to react with the available C2H2 using the stoichiometric ratio. The calculated amount (92.5 mol) exceeds the amount of O2 available (81.0 mol), indicating that the reaction will not proceed to completion due to the limited amount of O2. Therefore, O2 is the limiting reactant, and the excess C2H2 will remain unreacted.

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The pressure of this sample at 27° c and at the same volume is  calculated to be 0.6 atm.

Law of Gay-Lussac states that pressure of a given mass of gas varies directly with Kelvin temperature when the volume is constant.

Given that the volumes of the two states are equal. At constant volume, we use the Gay-Lussac equation:

As, P₁/T₁ = P₂/T₂

Given P1= 0.8 , T1= 127°

and T2= 27°

Now, (0.8)/(127+273) = (P₂)/(27+273)

We get, P₂ = 0.6 atm

The pressure of this sample at 27° c and  at same volume is 0.6 atm.

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Answer:

Soda all start with watered down corn syrup. To get the carbonation companies have different ways of doing this all of which are very different. The last step is to add artificial and natural flavors like lemon and lime, this is also the step in which sugar and preservatives are added.

Explanation:

I hope this answer your question, srry I couldn't go into detail.

Exothermic changes give out energy to their surroundings, causing an increase in heat endothermic changes, take in energy, so the opposite takes place.

Answer:

microwaves should be made

Answer:

answer choices plzzzzz

ima edit my answer wht are the choices

Explanation:

mrk mE BRAINLIEST PLZZZZZZZZZZZz

The new pressure inside the syringe will be 1.25 atm

At constant temperatures, the volume of a gas is inversely proportional to its pressure.

Thus:   P1V1 = P2V2

In this case, P1 = 3.0 atm, V1 = 89.6 mL, V2 = 215 mL

P2 = P1V1/V2

                         = 3 x 89.6/215

                              = 1.25 atm

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The third quantum number (m_l) of a 3s² electron in phosphorus is 0.

The third quantum number, denoted as m_l, represents the magnetic quantum number and describes the orientation of an orbital within a subshell. It can have integer values ranging from -l to +l, where l is the azimuthal quantum number.

In the electron configuration of phosphorus, we see that the 3s subshell is being filled. The azimuthal quantum number (l) for the 3s subshell is 0. Since the electron is in the 3s² subshell, there are two electrons present in the 3s orbital.

For the two electrons in the 3s orbital, they will have opposite spins due to the Pauli exclusion principle. However, the magnetic quantum number (m_l) for both electrons in the 3s orbital will be the same, which is 0.

Therefore, the third quantum number (m_l) of a 3s² electron in phosphorus is 0. This means that both electrons in the 3s orbital have the same orientation within the subshell.

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In the presence of water, ionic and hydrogen bonds can be disrupted.

Water is a polar molecule, meaning it has a partial positive charge on one end and a partial negative charge on the other end.

This polarity allows water to interact with other polar molecules, including ionic compounds and molecules containing hydrogen bonds.

Ionic compounds are held together by strong electrostatic forces between positively and negatively charged ions.

In the presence of water, the partial charges on the water molecule can attract and surround the ions, weakening the electrostatic forces and causing the ionic compound to dissociate into its component ions.This is why ionic compounds dissolve readily in water.

Hydrogen bonds are a type of intermolecular force that forms between a hydrogen atom bonded to an electronegative atom and another electronegative atom in a different molecule.

Water molecules can form hydrogen bonds with other polar molecules, and in the presence of water, these hydrogen bonds can be disrupted as water molecules compete for hydrogen bonding partners. This can affect the solubility and reactivity of molecules containing hydrogen bonds.

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Galaxies are the lump of matter. The shape of major galaxies is spiral shape. Thus, the given statement is false.

The galaxies are the lump of dust and mass, held together by the gravitational force. The galaxies are continuously moving in the universe.

The formation of galaxies is believed to be due to the force of attraction between the components.

The shape of major galaxies is assumed to be spiral-shaped, however, the irregular shape galaxies are also present.

Thus, the given statement about the shape of galaxies is false.

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Answer:

The mass of oxygen that reacted is approximately 1.6 grams of oxygen

Explanation:

The given information are;

The mass of magnesium in the reaction = 2.43 grams

The final mass of the magnesium oxide = 4.12 grams

The chemical equation for the reaction is given as follows;

2Mg + O₂  →  2MgO

From which we see that two moles of magnesium, Mg, reacts with one mole of oxygen gas molecule, O₂, to produce two moles of magnesium oxide, MgO

The number of moles of magnesium present, \(n_{Mg}\), is given as follows;

\(n_{Mg} = \dfrac{Mass \ of \, magnesium}{Molar \ mass \ of \, magnesium} = \dfrac{2.43}{24.305} \approx 0.1 \ moles\)

By the given chemical equation, 2 moles of magnesium reacts with one mole of O₂, therefore;

1 mole of magnesium will react with 1/2  moles of oxygen which is 0.5 moles of oxygen also;

0.1 mole of magnesium will react with 0.05 moles of oxygen

The mass of one mole of oxygen = The molar mass of oxygen = 32 g/mol

The mass of oxygen in the reaction = The number of moles of oxygen × The molar mass of oxygen

The mass of oxygen in the reaction = 0.05 × 32 = 1.6 grams

Also from the molar mass  of MgO which is 40.3044 g/mol, we have;

The mass fraction of oxygen = 16/40.3044 = 0.39698 ≈ 0.4

The mass of oxygen = 0.39698 × 4.12 = 1.636 g

Therefore, the mass of oxygen in the reaction is approximately 1.6 grams.

The given problem involves calculating the standard entropy change (ΔS°) for the reactant A in the chemical reaction 4A → 3B, given the value of ΔS° for the reaction and the standard entropy value (S°) for product B.

The standard entropy change is a measure of the disorder or randomness of a system at standard conditions.To calculate the standard entropy change for reactant A, we can use the formula ΔS°(reaction) = ΣS°(products) - ΣS°(reactants), where ΣS° refers to the sum of the standard entropy values for the products or reactants, respectively. Since we are given the value of ΔS°(reaction) and S°(B), we can rearrange the formula to solve for S°(A).Once we have the value of S°(A), we can determine the standard entropy change for A in the reaction.

The standard entropy change for A is equal to the standard entropy change for the reaction multiplied by the stoichiometric coefficient of A in the reaction, which is 4.The final answer will be the value of S°(A) and the standard entropy change for A in the reaction.Overall, the problem involves applying the principles of thermodynamics and entropy to calculate the standard entropy change for a reactant in a chemical reaction. It requires an understanding of the formula for calculating the standard entropy change and the properties of the reactants and products involved.

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A typical atom's diameter is 10,000 times greater than its nucleus' diameter, and the nucleus is where the majority of the mass and density of the atom are concentrated.

At the center of each atom, there is a tiny, dense area known as the nucleus. It has a net positive charge because it is made up of positive protons and neutral neutrons. Although the nucleus only makes up a very small portion of the atom, it is where almost all of its mass is found.

A positively charged nucleus and one or more negatively charged particles known as electrons make up an atom. The atom has no excess of electrons because the positive charges cancel out the negative charges, making it electrically neutral.

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For a tube closed on one end, you typically need to repeat measurements at each resonance position three times to ensure accuracy and account for any experimental errors or inconsistencies.

This repetition helps to minimize the impact of outliers and provides a more reliable average value for the resonance position.

By repeating the measurements multiple times, you can identify and eliminate any anomalous results that may have been caused by factors such as random fluctuations or instrumental errors. Taking an average of the repeated measurements also helps to reduce the overall uncertainty in the resonance position determination.

Therefore, it is recommended to perform at least three measurements at each resonance position for a tube closed on one end to obtain more robust and accurate results.

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