what is 14/20 as a percentage ?

hear here is your answer in attachment attach

Answer:

Step-by-step explanation:

40 = 2*2*2*5  

60 = 2 * 2 * 3 * 5

80= 2 * 2 * 2 * 2 * 5

LCM = 2 * 2 * 2 * 2 * 5 * 3 = 240

HCF = 2*2*5= 20

Answer:

-4/11 or -0.36363

Step-by-step explanation:

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Answer:

-4/11

Step-by-step explanation:

-3/5 = -33/55

-33/55 + 13/55 = -20/55

Simplified: -4/11

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Step-by-step explanation:

similR triangles

so

x/(x+16) = 20/32= 5/8

8x = 5x+80

3x = 80

x = 80/3

The slope of a beer's law plot represents that one can quantitatively determine the molar absorptivity of a substance, which is essential for accurately determining concentrations of unknown samples using spectrophotometric methods.

In Beer's law, the relationship between the concentration of a substance and its absorbance is described by the equation A = εbc, where A is the absorbance, ε is the molar absorptivity (also known as the molar absorptivity coefficient), b is the path length of the sample, and c is the concentration of the substance.

When plotting a graph of absorbance versus concentration, the slope of the line represents the molar absorptivity (ε). The molar absorptivity is a constant that reflects the substance's ability to absorb light at a specific wavelength. A higher molar absorptivity indicates that the substance has a greater tendency to absorb light and is more sensitive to changes in concentration.

Conversely, a lower molar absorptivity indicates weaker absorption characteristics.

In summary, by measuring the slope of the Beer's law plot, one can quantitatively determine the molar absorptivity of a substance.

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Answer:

27

Step-by-step explanation:

30% of 90 can be written as 30% × 90

= 30/100 × 90

= 27

Answer:

the answer is 10.2

Step-by-step explanation:

121-16=105

√105 =10.2

Answer:

6 is the ten thousand number

3 is the thousand number

6 is 20 times larger than 3

Step-by-step explanation:

5 = units

4 = tens

0 = hundred

3 = thousand

6  = ten thousand

7 = 100 thousand

comparison of the value of 6 to 3

 60,000 / 3000 = 20 times

Answer:

The answer would be 32

Step-by-step explanation:

equation would be: 6+2(12+1)

which then turns into 6+24+2

which equals 32

Answer:

32

Step-by-step explanation:

Since a = 3, b = 4, and c = -1

The Equation is:

= 2 × (3) + 2 × [(3) × (4) - (-1)]

= 6 + 2 × [12 - (-1)]

= 6 + 2 × (12 + 1)

= 6 + 2 × 13

= 6 + 26

= 32

Answer:

y = 1/4x + 4

Step-by-step explanation:

y = mx + b

Since the lines are parallel, the slope is the same. m = 1/4

y = 1/4x + b

Substitute (4,5)

5 = 1/4(4) + b

5 = 1 + b

4 = b

The y-intercept is (0, 4).

y = 1/4x + 4

Answer:

First account (4%):  P₁ = $25,500

Second account (3¹/₈%):  P₂ = $44,000

Third account (2¹/₂%):  P₃ = $11,000

Step-by-step explanation:

Simple Interest Formula

\(\large\boxed{\sf I = Prt}\)

Where:

Given information:

Convert the given percentages into decimal form:

\(\implies \sf 4\%=\dfrac{4}{100}=0.04\)

\(\implies \sf 3 \frac{1}{8}\%=3.125\%=\dfrac{3.125}{100}=0.03125\)

\(\implies \sf 2 \frac{1}{2}\%=2.5\%=\dfrac{2.5}{100}=0.025\)

Let P₁, P₂ and P₃ be the principal amounts invested into each of the three accounts, and I₁, I₂ and I₃ be the corresponding interest accrued.

Use the simple interest formula to find expressions for the interest of each account:

\(\implies \sf I_1=P_1 \cdot 0.04 \cdot 1=0.04P_1\)

\(\implies \sf I_2=P_2 \cdot 0.03125 \cdot 1=0.03125P_2\)

\(\implies \sf I_3=P_3 \cdot 0.025 \cdot 1=0.025P_3\)

Let x be the amount invested in third account.

Therefore, the amount invested in the second account = 4x.

The total interest earned is $2,670:

\(\begin{aligned}\textsf{Total interest}&=\sf 2670\\\implies \sf I_1+I_2+I_3&=\sf 2670\\ \sf 0.04P_1+0.03125P_2+0.025P_3&= \sf2670\\\sf 0.04P_1+0.03125(4x)+0.025(x)&= \sf2670\\\sf 0.04P_1+0.125x+0.025x&= \sf2670\\\sf 0.04P_1+0.15x&= \sf2670\\\end{aligned}\)

The total amount invested it $80,500:

\(\begin{aligned} \textsf{Total principal} & = \sf 80500\\\implies\sf P_1+P_2+P_3 &=\sf80500\\\sf P_1+4x+x&=\sf 80500\\\sf P_1+5x&=\sf 80500\\\sf P_1&=\sf 80500-5x\end{aligned}\)

Substitute the expression for P₁ into the total interest equation and solve for x:

\(\begin{aligned}\sf 0.04P_1+0.15x & = \sf 2670\\\implies \sf 0.04(80500-5x)+0.15x & = \sf 2670\\\sf 3220-0.2x+0.15x & = \sf 2670\\\sf 3220-0.05x & = \sf 2670\\\sf 550&=\sf0.05x\\\sf x&=\sf 11000\end{aligned}\)

Therefore:

\(\implies \sf P_2=4x=4(11000)=\$44,000\)

\(\implies \sf P_3=x=\$11,000\)

\(\implies \sf P_1=80500-P_2-P_3=80500-44000-11000=\$25,500\)

Answer:

(5, -7)

Step-by-step explanation:

A reflection across the y axis changes the sign of the x coordinate but nothing else.

Answer:

(5,-7)

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer: The 4th option

Step-by-step explanation:

4 cm x 3cm is 12 cm. 2 cm x 5 cm is 10 cm.

15

5x-2y=9......(1)

6x+ky=4......(2)

slope of eqn i= -5/-2

=5/2

slope of eqn ii = -6/k

since the line are perpendicular

5/2 * -6/k = -1

-30= -2k

k=15

every foot is a second hope that helps

The first five terms of the given sequence are:

a1 = -2

a2 = -5/11

a3 = 0

a4 = 7/67

a5 = 1/8

Also, given sequence should converge to a limit of 0, since the denominator is growing faster than the numerator.

For given question,

We have been given a sequence \(a_n=\frac{n^2-9}{n^3+3}\)

We need to find the first five terms, a1, a2, a3, a4, a5, of the sequence.

For n = 1,

\(a_1=\frac{1^2-9}{1^3+3} \\\\a_1=\frac{-8}{4} \\\\a_1=-2\)

For n = 2,

\(a_2=\frac{2^2-9}{2^3+3}\\\\ a_2=\frac{-5}{11}\)

For n = 3,

\(a_3=\frac{3^2-9}{3^3+3} \\\\a_3=\frac{0}{30}\\\\ a_3=0\)

For n = 4,

\(a_4=\frac{4^2-9}{4^3+3} \\\\a_4=\frac{7}{67}\)

For n = 5,

\(a_5=\frac{5^2-9}{5^3+3} \\\\a_5=\frac{16}{128}\\\\ a_5=\frac{1}{8}\)

Given sequence should converge to a limit of 0, since the denominator is growing faster than the numerator.

Therefore, the first five terms of the given sequence are:

a1 = -2

a2 = -5/11

a3 = 0

a4 = 7/67

a5 = 1/8

Also, given sequence should converge to a limit of 0, since the denominator is growing faster than the numerator.

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The lab should budget for the next year's rat orders be $63,700.00.

The lab orders 100 rats a week for each of the 52 weeks in the year for experiments that the lab conducts.

The prices for 100 rats follow the given distribution:

Price ($): 10.00, 12.50 , 15.00

Probability: 0.35 0.40 0.25

Mean price per 100 rats can be calculated using the expected value formula,

μx = ∑ [ xi × P(xi) ]

where

μx = mean value,

xi = price,

P(xi) = probability of xi

Mean price per 100 rats:

μx = (10.00 × 0.35) + (12.50 × 0.40) + (15.00 × 0.25)

μx = 3.50 + 5.00 + 3.75

μx = $12.25

The mean price per 100 rats is $12.25.

Hence, the cost of 100 rats is $12.25.

Therefore, the lab should budget for the next year's rat orders:

$12.25 × 100 × 52

= $63,700.00

The lab should budget for the next year's rat orders be $63,700.00.

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160/7 is the longest

67/3 is shortest

The calculated value of the length of EA in the diagram is 16.7 cm

The diagram is an illustration of similar triangles, and the length of EA can be calculated using the following proportional equation

EA/EC = BD/DC

Where

EC = 9 + 6 = 15 cm

BD = 10 cm

DC = 9 cm

Substitute the known values in the above equation, so, we have the following representation

EA/15 = 10/9

Multiply both sides of the equation by 15

This gives

EA = 15 * 10/9

Evaluate the equation

EA = 16.7

Hence, the length of EA in the diagram is 16.7 cm

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Therefore, the compound interest of the annuity due of BD 400 paid each 4 months for 6.2 years at a nominal rate of 3% per annum is BD 40,652.17.

Compound interest of an annuity due can be calculated using the formula:A = R * [(1 + i)ⁿ - 1] / i * (1 + i)

whereA = future value of the annuity dueR = regular paymenti = interest raten = number of payments First, we need to calculate the effective rate of interest per period since the nominal rate is given per annum. The effective rate of interest per period is calculated as

:(1 + i/n)^n - 1 = 3/1003/100 = (1 + i/4)^4 - 1

(1 + i/4)^4 = 1.0075i/4 = (1.0075)^(1/4) - 1i = 0.0303So,

the effective rate of interest per 4 months is 3.03%.Next, we can substitute the given values in the formula:

A = BD 400 * [(1 + 0.0303)^(6.2 * 3) - 1] / 0.0303 * (1 + 0.0303)A = BD 400 * [4.227 - 1] / 0.0303 * 1.0303A = BD 400 * 101.63A = BD 40,652.17

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Answer:

B

Step-by-step explanation:

Values of y are decreasing where x is in the range (-4;02)

There are 6 different ways to set up the tournament.

We can make two pairs of teams (a,b and c,d) and then arrange each pair in two different ways (ab, cd and cd, ab). Thus, there are a total of 6 combinations.

(b) There are 8 different outcomes for this tournament. Each pair of teams (a,b and c,d) can play in either the first or second round, and each team can either win or lose. We can calculate the number of outcomes by multiplying the different combinations of the first round (6) with the number of outcomes in the second round (2x2). Therefore, total number of outcomes = 6x2x2 = 8.

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The  solution of the given system of equations is (8, -1). of the given system of equations is (8, -1).

One method to solve the given system of equations is substitution:

- Solve one of the equations for one of the variables (e.g., x = 9 + y from the second equation).

- Substitute the expression for the variable into the other equation.

- Solve the resulting equation for the remaining variable.

- Substitute the value for the remaining variable back into one of the original equations to find the value of the other variable

Using this method with the given equations

- x - y = 9 -> x = 9 + y

- 3x + 2y = 22 -> 3(9 + y) + 2y = 22

- Simplifying and solving for y: 27 + 5y = 22 -> 5y = -5 -> y = -1

- Substituting y = -1 into x = 9 + y: x = 8

To check this solution, we can substitute these values back into both original equations and confirm that they are true statements.

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Answer:

4613203

Step-by-step explanation:

To round as a whole number, take the decimals and see what the first number of the decimal is. if the number is 5 or more, its 1 more number. if its lower than 5, its not a whole number.

(a) The coefficients for testing this contrast are -1, 2, and -1. (b) \(n_{1}\)= \(n_{2}\) = \(n_{3}\) = 16, Degrees of freedom = 45, If the P-value is smaller than the significance level (e.g., α = 0.05), we reject the null hypothesis and conclude that there is evidence to support the hypothesis that the average growth at 50% vegetation control is less than the average growth at 0% and 100% control levels.

(a) To test the contrast hypothesis that the average growth at 50% vegetation control is less than the average growth at 0% and 100% control levels,

we can set up the following contrast coefficients:

Contrast coefficients: c = [-1, 2, -1]

which indicate the weight or contribution of each group mean to the contrast. The first coefficient (-1) represents the weight for the 0% control group, the second coefficient (2) represents the weight for the 50% control group, and the third coefficient (-1) represents the weight for the 100% control group.

(b) To perform the test,

we can use the contrast coefficients to calculate the test statistic and P-value.

Test statistic (t-value):

t = (\(c_{1}\) × \(X_{1}\) + \(c_{2}\) × \(X_{2}\) + \(c_{3}\) × \(X_{3}\)) /  √ (\(sp^2\) × (\(c_{1}^{2} /n_{1}\) + \(c_{2} ^{2} /n_{2}\) + \(c_{3} ^{2} /n_{3}\)))  

where:

\(c_{1}\), \(c_{2}\), \(c_{3}\) are the contrast coefficients

\(X_{1}\), \(X_{2}\), \(X_{3}\) are the sample means for each control level

sp is the pooled standard deviation

\(n_{1}\), \(n_{2}\), \(n_{3}\) are the sample sizes for each control level

Using the given values:

\(c_{1}\) = -1,

\(c_{2}\) = 2,

\(c_{3}\) = -1

\(X_{1}\) = 58,

\(X_{2}\)= 73,

\(X_{3}\) = 105

sp = 17

\(n_{1}\) = \(n_{2}\) = \(n_{3}\) = 16

Calculating the t-value:

t = (-1 × 58 + 2 × 73 - 1 × 105) /  √ (\(17^2\) × (\(-1^2/16\) +\(2^2/16\) + \(-1^2/16\)))

Degrees of freedom:

df = \(n_{1}\) +\(n_{2}\) +\(n_{3}\) - 3

= 16 + 16 + 16 - 3

= 45

Using the calculated t-value and degrees of freedom,

we can determine the P-value from a t-distribution table or statistical software.

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Answer:

x=5

Step-by-step explanation:

i took 12 and subtracted 7 to see what i got and to check my answer i added 5 to 7 to see if i got 12

If the allowable increase for a constraint is 100 units and we add 110 units of the resource, the impact on the objective function value depends on the specific problem and its constraints.

In general, adding more units of a resource beyond the allowable increase can lead to different outcomes:

Feasible Solution: If adding the additional 110 units of the resource still allows the problem to satisfy all constraints and remain feasible, the objective function value may improve or remain the same. This is because the extra resources can be utilized to optimize the objective function further.

Infeasible Solution: If adding the extra 110 units violates any of the problem's constraints, the solution becomes infeasible. In this case, the objective function value may become undefined or have no meaning since the problem cannot be solved within the given constraints.

It's important to note that the specific impact on the objective function value will depend on the nature of the problem, the objective function itself, and the constraints involved. Each problem may have its own unique behavior when additional resources are added beyond the allowable increase.

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The weight of pumpkin that is needed to make 1000 pumpkin pies is 1300 Kg .

In the question ,

it is given that  ,

the weight of the pumpkin required to make 1 pumpkin pie = 1.3 Kg

we have to find the weight of the pumpkin that is needed to make 1000 pumpkin pie .

weight of pumpkin in 1000 pumpkin pie = 1000*(weight of 1 pumpkin pie)

Substituting the weight of 1 pumpkin ,

we get ,

weight of pumpkin in 1000 pumpkin pie = 1000 * 1.3

= 1300 Kg .

Therefore , The weight of pumpkin that is needed to make 1000 pumpkin pies is 1300 Kg .

The given question is incomplete , the complete question is

One pumpkin pie require 1.3 Kg of pumpkin , Find the Weight of the pumpkin that you need to use to make 1000 pumpkin pies ?

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