What invisible force will cause you to fall to the earth if you fall off your bed?

So, the force that must be applied to the spring is 75.0 N.

Hi ! Here I will help you to solve the problem of the force required while stretching the spring. The force or load applied to the spring can cause the spring to stretch or compress. By stretching, there should be a change in the length of the spring (\(\sf{\Delta x}\)). The concept that you should know in this question :

The formula that show the relationship between the force, the coefficient of the spring, and the change in the length of the spring is expressed in the equation:

\(\boxed{\sf{\bold{F = k \cdot \Delta x}}}\)

With the following condition :

We know that :

What was asked ?

Step by step :

\(\sf{F = k \cdot \Delta x}\)

\(\sf{F = 100 \cdot 0.75}\)

\(\boxed{\sf{F = 75.0 \: N}}\)

So, the force that must be applied to the spring is 75.0 N.

The force that is exerted on the spring is 75 N.

Let us recall that Hooke's law states that the extension of an elastic material is directly proportional to the force that is applied as long as the elastic limit of the material has not been exceeded.

Given now the fact that we have;

F = Ke

F = force applied

K = force constant

e = extention

e = 750 millimeters or 0.75 m

K = 100 N/m

F =  0.75 m *  100 N/m

F = 75 N

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Answer:

strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.

Explanation:

The lines of magnetic force are drawn so that the density of lines is proportional to the intensity of the magnetic field.

Therefore, the sections where the magnetic field is strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.

The potential V(x, y, z) everywhere inside the box. Formulas give V=0 at the center of this cube. Is E=0 there\((A_{n,m}e^{a/2\sqrt{(n^{2}+m^{2})\pi^{2}/a^{2}}}+B_{n,m}e^{-a/2\sqrt{(n^{2}+m^{2})\pi^{2}/a^{2}}})=\frac{16V_{0}}{nm\pi^{2}}\: \: \: n,m =odd\)

Laplace equation in cartesian co-ordinates is

\(\frac{\partial^2 V}{\partial x^2}+\frac{\partial^2 V}{\partial y^2}+\frac{\partial^2 V}{\partial z^2}=0\)

Multiply both side by \(sin\left ( \frac{n'\pi x}{a} \right )sin\left ( \frac{m'\pi z}{a} \right )\)   and integrate over x and z from 0 to a

\(\int_{0}^{a}\int_{0}^{a}V_{0}sin\left ( \frac{n\pi x}{a} \right )sin\left ( \frac{m\pi z}{a} \right )dxdz=\frac{a^{2}}{4}(A_{n,m}e^{-a/2\sqrt{(n^{2}+m^{2})\pi^{2}/a^{2}}}+B_{n,m}e^{a/2\sqrt{(n^{2}+m^{2})\pi^{2}/a^{2}}})\)

\((A_{n,m}e^{-a/2\sqrt{(n^{2}+m^{2})\pi^{2}/a^{2}}}+B_{n,m}e^{a/2\sqrt{(n^{2}+m^{2})\pi^{2}/a^{2}}})=\frac{4V_{0}}{a^{2}}\int_{0}^{a}sin\left ( \frac{n\pi x}{a} \right )dx \int_{0}^{a}sin\left ( \frac{m\pi z}{a} \right )dz\)

\((A_{n,m}e^{-a/2\sqrt{(n^{2}+m^{2})\pi^{2}/a^{2}}}+B_{n,m}e^{a/2\sqrt{(n^{2}+m^{2})\pi^{2}/a^{2}}})=\frac{16V_{0}}{nm\pi^{2}}\: \: \: n,m =odd\)

Now apply the final boundary condition V(x, y=a/2, z) = V0

Solving we get

\((A_{n,m}e^{a/2\sqrt{(n^{2}+m^{2})\pi^{2}/a^{2}}}+B_{n,m}e^{-a/2\sqrt{(n^{2}+m^{2})\pi^{2}/a^{2}}})=\frac{16V_{0}}{nm\pi^{2}}\: \: \: n,m =odd\)

The Laplace equation is a partial differential equation that describes the behavior of a scalar field in space. In its simplest form, it states that the sum of the second partial derivatives of the scalar field with respect to each of the spatial dimensions is equal to zero. This means that the scalar field has no sources or sinks, and its value is determined only by the boundary conditions.

The Laplace equation has many applications in physics, engineering, and mathematics. For example, it can be used to model the behavior of electric and gravitational fields, fluid flow, and heat transfer. It is also used in solving problems involving potential functions, which arise in many areas of physics and engineering.

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Complete Question: -

You have a cubical box (sides all of length a) made of 6 metal plates which are insulated from each other. The left wall is located at y=-a/2, the right wall is at y=+a/2. Both left and right walls are held at constant potential V=V0. All four other walls are grounded. Find the potential V(x, y, z) everywhere inside the box. Do your formulas give V=0 at the center of this cube? Is E=0 there? (Should they be??)

Hi there!

Recall the equation for an LR circuit time-constant:
\(\tau = \frac{L}{R}\)

L = Inductance (H)

R = Resistance (Ω)

Plug in the given values.

\(\tau = \frac{0.005}{1000} = 0.000005 s = \boxed{\text{5 } \mu s}\)

Answer:

  v = \(n \frac{\hbar }{m r}\)

the sppedof the electron is also quantized

Explanation:

The angular momentum of a rotating body is

         L = m v r

in Bohr's atomic model the quantization postulate is that the angular momentum is equal to

         L = n \(\hbar\)

we substitute

        n \(\hbar\) = m v r

        v = \(n \frac{\hbar }{m r}\)

where n is an integer.

Therefore, the sppedof the electron is also quantized, that is, sol has some discrete values.

Answer:

proton and neutrons

Explanation:

electron has negligible mass

The acceleration of a 50 g object pushed with a force of 0.5 N is 10 m/s².

To find the acceleration of the object, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration:

F = m * a

Given:

Force (F) = 0.5 N

Mass (m) = 50 g = 0.05 kg

Substituting the given values into the equation, we have:

0.5 N = 0.05 kg * a

To find the acceleration (a), we rearrange the equation:

a = F / m

a = 0.5 N / 0.05 kg

a = 10 N/kg

Since acceleration is measured in meters per second squared (m/s²), we convert the unit of N/kg to m/s²:

1 N/kg = 1 m/s²

Therefore, the acceleration of the 50 g object pushed with a force of 0.5 N is 10 m/s².

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The time taken for the ball to reach its maximum height is 1 second.

To calculate the time taken for the ball to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the ball is thrown vertically upwards, so the initial velocity (u) is 10 m/s (considering upwards as positive) and the acceleration (a) is -10 m/s² (negative because it opposes the motion).

The final velocity (v) at the maximum height will be zero because the ball momentarily comes to a stop before reversing its direction. Therefore, we can rewrite the equation as:

0 = 10 - 10t

Simplifying the equation, we get:

10t = 10

Dividing both sides by 10, we find:

t = 1 second

Therefore, the time taken for the ball to reach its maximum height is 1 second.

During this time, the ball covers the distance required to reach the maximum height, overcoming the gravitational acceleration. After reaching the maximum height, it will start to descend towards the ground due to the gravitational pull.

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A 20-minute cycle ergometer exercise at 60% VO2max has been demonstrated to dramatically improve impact for the majority of persons.

the property of being strongly felt or having a powerful impact: The explosion was so loud that it could be heard from five kilometres distant. Measures of luminosity. [C or U] the strength of being something that may be measured, such as sunlight, sound, etc.

A measure that is produced from a randomised measure is known as an intensity measure in probability theory. Since the randomised measure of a set's expected value is the intensity measure, which is a non-random measure, it equates to the average volume that the random measure assigns.

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Answer:

Explanation:

a False

b True

c True

d False

e False

f False

g True

h False

i False

The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.

Since the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.

The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.

According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.

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The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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This statement is False, Article 130, Work Involving Electrical Hazards, by definition, covers work involving four hazards caused by either proximity or equipment failure.

Electrical hazards refer to the potential risks associated with the use of electricity, which can cause injury or even death. These hazards can arise from a variety of sources, including electrical systems, appliances, tools, and wiring.

Electrical hazards can include electrical shock, burns, and electrocution. Electrical shock occurs when a person comes into contact with an electrical current and can cause muscle contractions, respiratory failure, and cardiac arrest. Burns can result from direct contact with an electrical current or from an arc flash, which is a sudden release of electrical energy. Electrocution is a severe form of electrical shock that can result in death. It is essential to receive proper training and education on electrical safety and to always be aware of potential electrical hazards in the environment.

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Work of art from the Amarna Period that is abstract or descriptive in nature.

That momentarily altered during the Amarna Period. The neck, arms, and hands were among the longer characteristics on the body. The traditional Egyptian painting form was briefly replaced by this strange new art form, which resulted in portraits of people that were virtually caricatures.

Religious iconoclasts are associated with the Amarna Period. Because he only worshiped the Aten, the pharaoh Amenhotep IV changed his name to Akhenaten. At Tell el-Amarna in Middle Egypt, he constructed a brand-new capital and cemetery.

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Answer:

the equations of motion can be separated into an equation that depends on a single variable.

Explanation:

he one-dimensional kinematics equations can be applied to two-dimensional systems because we can write the equations in such a way that each one of them depends on variables in a single dimension plus time, which, because it is a scalar, can be used in all dimensions.

A mathematical way of saying this is that the equations of motion can be separated into an equation that depends on a single variable.

The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people

We'll begin by converting 175 cm to m. This can be obtained as illustrated below:

100 cm = 1 m

Therefore,

175 cm = (175 cm × 1 m) / 100 cm

175 cm = 1.75 m

Thus, 175 cm is equivalent to 1.75 m

The number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:

Number of people needed = Height of tower / height of a person

Number of people needed = 553 / 1.75

Number of people needed = 316 people

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When the thistle funnel is moved upwards towards the surface of the liquids, the height (h) decrease.

What happens when the thistle funnel is moved upward?

An important principle outlined by Pascal's law states that any fluid (in this instance, liquids) experiences equal transmission of force in every direction within it. Hence, there is an intimate relationship between the height of a liquid column and its pressure.

Raising a thistle funnel reduces this height causing loss of weight from above this point thus decreasing its pressure.

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See complete question in the attached image.

The unit vector normal to the plane is determined as (i  - 4j  -  13k) / √186.  

Option  B.

The magnitude of the cross product of a→ and b→, is determined as follows;

|a→ × b→| = (3i +4j -k) × (i- 3j + k )

= [i       j       k]

  [3     4      -1]

  [1     -3       1]

The cross product of the vectors is calculated as follows;

= i (4 - 3) - j(3 - - 1)  + k (-9 - 4)

= i  - 4j  -  13k

The magnitude of the vector is calculated as follows;

|n| = √ (1² + 4² + 13²)

|n| = √186

The unit vector normal to the plane is calculated as follows;

n = (i  - 4j  -  13k) / √186

Thus, the unit vector normal to the plane is determined as (i  - 4j  -  13k) / √186.   The answer is B.

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Answer:

i don'tkniw

Explanation: ido not know

A wool sweater worn under a cotton jacket produces more static charges.

Static charge is an imbalance of electric charges within or on the surface of a material or between materials.

Static charges can be produced by two materials together (friction method).

A wool sweater worn under a cotton jacket (in the absence of lubricant like water) creates friction which enables more static charge to be produced.

Thus, a wool sweater worn under a cotton jacket produces more static charges.

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The force on the test charge is 14 N.

When a test charge is placed in an electric field, it experiences a force. The strength of the electric field is measured in newtons per coulomb, and the magnitude of the force exerted on the test charge is proportional to the amount of charge on it. The formula to calculate the force is given by:

F = q*E

where F is the force, q is the amount of charge on the test charge, and E is the strength of the electric field. Given:

Test charge = 2 C CoulombsElectric field = 7 N/C

Using the formula above,

F = q*E = 2C * 7N/C = 14 N

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Answer:

slightly different frequencies

Explanation:

The alternate increase or decrease of sound produced by the interference of two sound waves of slightly  different frequencies is called ‘Beat’. The maximum beat frequency that a human ear can detect is 7 beats/sec.

This definition of the beats is clearly pointing out that the two waves whose frequencies are slightly different will add together to produce the beats.

Therefore, the correct answer will be:

slightly different frequencies

Answer:

equator

Explanation:

in south & north pole you could have 20+ hours daylight or night, everyday!

Machine 1 has the greatest mechanical advantage among the given machines. To determine the machine with the greatest mechanical advantage, we need to calculate the mechanical advantage for each machine.

Machine 1: Mechanical Advantage = Output Force / Input Force = 50 N / 5 N = 10

Machine 2: Mechanical Advantage = Output Force / Input Force = 50 N / 10 N = 5

Machine 3: Mechanical Advantage = Output Force / Input Force = 50 N / 25 N = 2

Machine 4: Mechanical Advantage = Output Force / Input Force = 50 N / 50 N = 1

Comparing the mechanical advantages, we can see that Machine 1 has the highest mechanical advantage of 10. This means that Machine 1 can multiply the input force by 10 to produce the output force. It provides the greatest amplification of force among the four machines.

Machine 2 has a mechanical advantage of 5, Machine 3 has a mechanical advantage of 2, and Machine 4 has a mechanical advantage of 1. Therefore, Machine 1 has the greatest mechanical advantage among the given machines.

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Answer:

5.277 kg

Explanation:

Since the formula for work is W = F * d and we are given distance and work, the force on the grocery bag is 88 = F * 1.7 F = 88 / 1.7 = 51.765 N.

We also know that force follows the equation F = m * a. Since the constant gravitational acceleration on earth is 9.81 m / s^2, we can find the mass through 51.765 = m * 9.81 m = 51.765/9.81 = 5.277 kg

The answer is 1) The pressure at point D is 80 kPa. 2) The temperature at point D is 800 K. 3) The net work done on the gas over four cycles is zero. 4) The internal energy of the gas at point A is 100 J. 5) The total change in internal energy during four complete cycles is zero.

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We are given:

Frequency of the wave = 100 Hz

Velocity of the wave = 5 m/s

Finding the Wavelength:

We know the relation between the wavelength and frequency is:

u = νλ    [where ν is the frequency, u is the speed and λ is the wavelength]

5 = 100*(λ)

λ = 5/100         [dividing both sides by 100]

λ = 1/20

λ = 0.05 m

Hence, the wavelength is 0.05 m