Answers
Answer:
Metals react with water to form oxides or hydroxides and release Hydrogen gas
Explanation:
Related Questions
Calculate the amount of copper in moles in a 27.5g pure copper sheet
Answers
The amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.
To calculate the amount of copper in moles in a pure copper sheet, we need to use the molar mass of copper and the given mass of the sheet.
The molar mass of copper (Cu) is approximately 63.55 g/mol. This value represents the mass of one mole of copper atoms.
Given that the mass of the pure copper sheet is 27.5 g, we can calculate the number of moles using the following formula:
moles = mass / molar mass
Substituting the values:
moles = 27.5 g / 63.55 g/mol
moles ≈ 0.433 mol
Therefore, the amount of copper in moles in the 27.5 g pure copper sheet is approximately 0.433 moles.
To arrive at this result, we divided the given mass of the sheet (27.5 g) by the molar mass of copper (63.55 g/mol). This calculation allows us to convert the mass of the sheet into the corresponding number of moles of copper.
The result tells us that the 27.5 g pure copper sheet contains approximately 0.433 moles of copper atoms. This conversion to moles is useful in various chemical calculations and allows for easier comparison and analysis of quantities on a molecular scale.
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what are the two sources of energy for earths geological systems?
Answers
Answer:
radioactive decay or solar radiation
Explanation:
A flexible container is filled with He(g) to a volume of V1 at a temperature of 150K. The container is then heated at constant pressure to a temperature of 300K. What is the final volume of the container?
a. V1/3b. V1/2c. V1d. 2V1
Answers
Answer:
a but it might also be c
Explanation:
i d k what this is
Answer:
2V1
Explanation:
A beaker of 450g of water is heated from 4.0°C to 25.0°C on a hot plate. If the
specific heat of H2O is 4.18J/9°C how much energy has the water absorbed?
A 39,501 J
B 4.42 x 104
C 5.13 J
D 54,549 J
Answers
Answer: 5.13
Explanation: juss do it
Taking into account the definition of calorimetry, the water has absorbed 39,501 J.
CalorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
Energy that the water absorbedIn this case, you know:
Q= ?c= 4.18 \(\frac{J}{gC}\)m= 450 g ΔT= Tfinal - Tinitial= 25 C - 4 C= 21 CReplacing in the definition of calorimetry:
Q = 4.18 \(\frac{J}{gC}\)× 450 g× 21 C
Solving:
Q= 39,501 J
Finally, the water has absorbed 39,501 J.
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Chemistry Lab Determination of the Universal Gas Constant (R)
SHOW ALL WORK
Given:
Initial mass of butane lighter: 54.24g
Final Mass of Butane Lighter: 54.01g
Temperature of water: 23.0°C
Volume of gas collected: 100.0mL
FIND:
Barometric pressure of room: 766.86 mmHg CONVERTED TO atm
Vapor pressure of water at room temperature(PH2O) (IN atm)
FIND:
Mass difference if butane lighter in grams
Moles of Butane gas collected in moles of C4H10
Partial pressure if butane gas in atm
Converted temperature of water in Kelvin
Converted volume of gas collected in Liters
Experimental value of R in Latm/molk
Accepted value of R in Latm/molk
Percent error in experimental value of R in %
CONCLUSION QUESTIONS:
1. List at least 3 factors that either did it could contribute to the percent error
2. Should the value of R go up or down if the gas had not been corrected for the partial pressure of water. Why?
3. How could this experiment be repeated to increase the accuracy, or in other words, decrease the percent error?
NOTE: LET ME KNOW IF YOU WANT A PICTURE OF THE LAB INSTRUCTIONS TO HELP SOLVE
ALSO SHOW ALL WORK PLS
Answers
To solve this problem, I'll need some additional information related to the molar mass of butane (C4H10). Please provide the molar mass of butane so that I can proceed with the calculations.
For the reaction below, if the rate of appearance of Br2 is 0.180 M/s, what is the rate of disappearance of
NOBr?
2 NOBr(g) → 2 NO(g) + Br2(g)
a. –0.360 M/s
b. –0.090 M/s
c. 0.090 M/s
d. 0.180 M/s
e. 0.720 M/s
Answers
Answer:
–0.360 M/s
Explanation:
Strontium hydroxide reacts with hydrobromic acid to produce Strontium bromide and
water.
Write and balance the chemical reaction above, use it for problems 1-4 below:
1. If 5.50 moles of strontium hydroxide were consumed, how much moles of water are
produced?
2. Find the mass of hydrobromic acid used to produce 7.50 moles water.
3. If 10.8 g of strontium hydroxide were used, how much moles of strontium bromide are
produced?
4. If 13.3 g of hydrobromic acid were consumed, find the mass of the water produced.
Answers
Sr(OH)2 + 2 HCl --> SrCl2 + 2 H2O
To find the moles of water produced when 5.50 moles of strontium hydroxide are consumed, we need to apply the law of conservation of mass. The mass of water produced is equal to the mass of strontium hydroxide consumed. Since strontium hydroxide has a molar mass of 142 g/mol and water has a molar mass of 18 g/mol, 1 mol of strontium hydroxide can produce 9 mol of water. Therefore, 5.50 moles of strontium hydroxide can produce 49.5 mol of water.
Similarly, 7.50 moles of water can be produced by reacting 18 moles of hydrobromic acid with strontium hydroxide. Hydrobromic acid has a molar mass of 79.9 g/mol, so 18 moles of hydrobromic acid would have a mass of 79.9 * 18 = 1435.2 g.
To find the moles of strontium bromide produced when 10.8 g of strontium hydroxide is used, we need to apply the law of conservation of mass again. The mass of the strontium bromide produced is equal to the mass of strontium hydroxide consumed. Since strontium bromide has a molar mass of 410 g/mol and strontium hydroxide has a molar mass of 142 g/mol, 1 mol of strontium bromide can consume 3.23 moles of strontium hydroxide. Therefore, 10.8 g of strontium hydroxide can produce 10.8 / 3.23 = 3.34 moles of strontium bromide.
Finally, to find the mass of water produced when 13.3 g of hydrobromic acid is consumed, we need to apply the law of conservation of mass yet again. The mass of the water produced is equal to the mass of hydrobromic acid consumed. Since hydrobromic acid has a molar mass of 79.9 g/mol, 13.3 g of hydrobromic acid would produce 13.3 / 79.9 = 0.166 moles of water.
what part of the food chain is a lemming
a:producer
b:secondary consumer
c:primary consumer
d: predator
Answers
hmm...for your answer I think it would be D
Answer:
primary consumer
Explanation:
Lemmings are primary consumers.
In TLC chromatography of plant pigments, why do different pigments travel up the plate at different rates
Answers
Which temperature scale was used if water froze at 273 degrees?
O A. Newton
O B. Kelvin
O C. Celsius
O D. Fahrenheit
Answers
i hope this helps:)
Construct the resonance structure for CSO, which has a formal charge of +2 on the central atom and +1 on the oxygen atom.
Answers
Answer:
The given condition is proved.
Explanation:
Given that,
Construct the resonance structure for CSO, which has a formal charge of +2 on the central atom and +1 on the oxygen atom.
We need to construct the resonance structure for CSO
The structure shown in figure
According to question,
A formal charge of +2 on the central atom and +1 on the oxygen atom.
Then tha structure shown in figure
The central atom in the structure is sulphur.
We need to calculate the formal charge on sulphur
Using figure,
\(charge\ on\ S=+3-1\)
\(charge\ on\ S=+2\)
A formal charge of +2 on the central atom.
This is proved.
Hence, The given condition is proved.
Resonance structure is attached below in the image.
Given: We need to construct the resonance structure for CSO
Structure of CSO:A formal charge of +2 on the central atom and +1 on the oxygen atom. The central atom in the structure is sulphur. The formal charge on sulphur is +2 i.e. +3-1 = 2. Thus, a formal charge of +2 on the central atom.
The resonance structure is attached below:
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If 62.1 grams of magnesium react with 100.0 grams of magnesium, how many grams of product are produced?
Which is the Limiting reactant?
Which is the Excess reactant?
How many grams of excess reactant remain?
pls help me with homework
Answers
The limiting and excess reactant can be obtained as follow:
2Mg + O₂ -> 2MgO
Molar mass of Mg = 24 g/molMass of Mg from the balanced equation = 2 × 24 = 48 g Molar mass of O₂ = 32 g/molMass of O₂ from the balanced equation = 1 × 32 = 32 gFrom the balanced equation above,
48 g of Mg reacted with 32 g of O₂
Therefore,
62.1 g of Mg will react with = (62.1 × 32) / 48 = 41.4 g of O₂
We can see from the above that only 41.4 g of O₂ is required to react completely with 62.1 g of Mg.
Thus, the limiting reactant is magnesium, Mg and the excess reactant is oxygen, O₂
How do i determine the mass of the excess reactant remaining?The mass of the excess reactant remaining can be obtained as shown below:
Mass of excess reactant, O₂ given = 100 gMass of excess reactant, O₂ that reacted = 41.4 gMass of excess reactant, O₂ remaining =?Mass of excess reactant remaining = Mass given - mass reacted
Mass of excess reactant remaining = 100 - 41.4
Mass of excess reactant remaining = 58.6 g
How do i determine the mass of product produced?The mass of H₂SO₄ produced can be obtained as illustrated below:
Mg + O₂ -> 2MgO
Molar mass of Mg = 24 g/molMass of Mg from the balanced equation = 2 × 24 = 48 g Molar mass of MgO = 40 g/molMass of MgO from the balanced equation = 2 × 40 = 80 gFrom the balanced equation above,
48 g of Mg reacted to produce 80 g of MgO
Therefore,
62.1 g of Mg will react to produce = (62.1 × 80) / 48 = 103.5 g of MgO
Thus, the mass of product, MgO produced is 103.5 g
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Complete question:
If 62.1 grams of magnesium react with 100.0 grams of oxygen, how many grams of product are produced?
Which is the Limiting reactant?
Which is the Excess reactant?
How many grams of excess reactant remain?
What is the component concentration ratio, [CH3COO−]/[CH3COOH], of a buffer that has a pH of 4.650? (Ka of CH3COOH = 1.8 × 10−5)
Answers
Answer:
Refer to the attached page,
I've done the calculation over there
![What is the component concentration ratio, [CH3COO]/[CH3COOH], of a buffer that has a pH of 4.650? (Ka](https://i5t5.c14.e2-1.dev/h-images-qa/answers/attachments/KmS9mjOLqSW9knGY3oOzLXYrtAYB0Dze.jpeg)
Which of the following electron models is the one currently accepted by modern science?
A.) Dalton's Billiard Ball.
B.) Thomson's Plum Pudding Model.
C.) Schrodinger's Quantum Mechanical Model.
D.) Rutherford-Bohr Planetary Model.
Answers
Schrodinger's Quantum Mechanical Model, which is currently recognised by modern science, is the electron model. The electron cloud model is another name for this one.
What electron model is in use right now?The term "electron cloud" refers to the current atomic structure model. A physicist from Austria named Edwin Schrodinger argued that electrons do not follow static or permanent trajectories.
What atom model is considered to be the most recent?The contemporary atomic model, often known as the cloud model, depicts atoms as having a nucleus made up of protons and neutrons and a diffuse gradient or cloud surrounding it that is made up of electrons. Because electron activity is probabilistic, electrons are often depicted as clouds.
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Draw to scale the lines where the equipotential surfaces due to these plates intersect the paper. Limit your drawing to the region between the plates, avoiding their edges, and draw the lines for surfaces that are 10.0 V apart, starting at the low-potential plate.
how would my graph look?
Answers
The field strength is measured in Volts / meter (V/m). The voltage is 50V. The distance is 'halfway between' 25cm ( = .25m), or .125m. The field strength is thus = 50V / .125m = 400 V/m
Equipotential surfaces are surfaces where the potential difference is constant. In the given scenario, the two parallel metal plates are connected across a 50.0V battery, and the equipotential surfaces due to these plates will intersect the paper in the region between the plates.
The lines representing the equipotential surfaces will be perpendicular to the electric field lines and will be parallel to each other. The equipotential surfaces will start at the low-potential plate and be 10.0V apart, with the potential increasing as you move away from the low-potential plate. The equipotential surfaces will be closer together near the high-potential plate and further apart near the low-potential plate.
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Two very large metal parallel plates that are 25cm apart, oriented perpendicular to a sheet of paper, are connected across the terminals of a 50.0V battery. Draw to scale the lines where the equipotential surfaces due to these plates intersect the paper. Limit your drawing to the region between the plates, avoiding their edges, and draw the lines for surfaces that are 10.0 V apart, starting at the low-potential plate.
Arrange to of electrons in atoms
Answers
2. (a) an s orbital
3. (a) 32
4. (c) 8
5. (c) energy
6. (c) point c
7. (c) a position where an electron probably exists
C6H12O6 + 602 → 6CO2 + 6H₂O
The most efficient ratio is
1 C6H12O6 6 02.
Which set of reactants will be the most
efficient (least wasteful of materials) for
the reaction?
A. 1.0 mol C6H12O6 and 3.0 mol O₂
B. 1.5 mol C6H₁2O6 and 3.0 mol O₂
C. 3.0 mol C6H₁2O6 and 6.0 mol O₂
D. 0.5 mol C6H₁2O6 and 3.0 mol O₂
Answers
Answer:
D
Explanation:
The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.
What is technology?
the process of designing and making tools
any device that contains electronic parts
the use of knowledge to solve practical problems
the study of the natural world
90 points
Answers
Answer:
Any device that contains electronic parts
Which sense organ detects vibrations in the air. A. Ear B. Eye C. Tongue D. Nose
Answers
Compute for the pH of 0.415 HCl acid
Answers
the human population grew form 1 billion in the year 1800to blank billion in the year 200
Answers
The human population grew from 1 billion in the year 1800 to approximately 7.8 billion in the year 2021.
In the year 1800, the estimated global human population was around 1 billion. Over the next two centuries, significant advancements in technology, medicine, agriculture, and improved living conditions contributed to a rapid increase in population.
The growth rate of the human population began to accelerate in the 20th century. By the year 1927, the global population reached 2 billion. It took just 33 years for the population to double, reaching 4 billion in 1960. The population continued to grow at an unprecedented rate, with 6 billion people on Earth by the year 1999. As of 2021, the estimated global population stands at approximately 7.8 billion.
This remarkable growth in population can be attributed to several factors, including advancements in healthcare leading to reduced infant mortality rates, improved access to education and contraception, increased agricultural productivity, and overall socio-economic development.
It's important to note that population growth has not been uniform across all regions. Different countries and regions have experienced varying rates of population growth due to factors such as fertility rates, mortality rates, migration patterns, and government policies.
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Given the reaction: Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
The reaction occurs more rapidly when a 10-gram sample of Mg is powdered rather than in one piece, because powdered
Mg has
1. less surface area
2. more surface area
3. a lower potential energy
4. a higher potential energy
Answers
how scientists used the scientific method to learn more about how dinosaurs became extinct
Answers
Answer:
they tested the bone age
Explanation:
What is the concentration, in m/m%, of a solution prepared from 30.0 g NaCl and 140.0 g of water?
Answers
The concentration in m/m% of the given solution is 17.65%.
What is mass by m/m % concentration?
m/m % concentration is the total amount of the solute present for every 100g of the solution it is dissolved in.
The given solution contains 30.0g NaCl which is a solute dissolved in 140.0g of water which is the solvent. The m/m % has to be calculated. The total mass of the given solution can be calculated as,
Mass of solution = 140.0g + 30.0g = 170.0g
So, 30.0 g of solute is present in 170.0g of the solution. The amount of solute present in 100.0 g of the solution is,
100 x 30 / 170 = 17.65% of NaCl.
Therefore, the m/m % concentration of the given solution is 17.65%.
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Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050 L flask at 668 K, how many moles of CI2(g) will be present at equilibrium?
CO(g) + Cl2(g)》COCl2(g)
Kc= 1.2 x 10^3 at 668 K
Answers
At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
1: Write the balanced chemical equation:
\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)
2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.
Initial:
\(C_O\)(g) = 0.3500 mol
\(Cl_2\)(g) = 0.05500 mol
\(C_OCl_2\)(g) = 0 mol
Change:
\(C_O\)(g) = -x
\(Cl_2\)(g) = -x
\(C_OCl_2\)(g) = +x
Equilibrium:
\(C_O\)(g) = 0.3500 - x mol
\(Cl_2\)(g) = 0.05500 - x mol
\(C_OCl_2\)(g) = x mol
3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:
Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]
4: Substitute the given equilibrium constant (Kc) value into the expression:
1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)
5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:
1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x
6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.
7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.
8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):
\(Cl_2\)(g) = 0.05500 - x
9: Calculate the value of \(Cl_2\)(g) at equilibrium:
\(Cl_2\)(g) = 0.05500 - x
\(Cl_2\)(g) = 0.05500 - (positive value of x)
10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.
Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
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What is a factor that determines whether this energy is a renewable or nonrenewable resource
Answers
Answer:
Nonrenewable energy resources, like coal, nuclear, oil, and natural gas, are available in limited supplies. This is usually due to the long time it takes for them to be replenished. Renewable resources are replenished naturally and over relatively short periods of time
78.0 g of H2O will react with Fe to produce _______ formula units of FeO2
Please help
Answers
Answer:
1.306 × 10^24 formula units.
Explanation:
The chemical equation of this qkrstios as follows:
Fe + 2H2O → FeO2 + 2H2
Based on the reaction, 2 mole of H2O produces 1 mole of FeO2
Using the formula as follows;
Mole = mass/molar mass
Molar mass of H2O = 1(2) + 16 = 18g/mol
mole = 78/18
mole = 4.33moles
If 2 mole of H2O reacts to produce 1 mole of FeO2
4.33 moles of H2O will produce 4.33/2 = 2.17moles of FeO2.
To convert moles to formula units, we multiply number of moles by Avagadro number (6.02 × 10^23 units)
= 2.17 moles × 6.02 × 10^23 units
= 13.06 × 10^23
= 1.306 × 10^24 formula units.
The Lewis structure of N2H2 shows ________. Group of answer choices a nitrogen-nitrogen single bond each hydrogen has one nonbonding electron pair each nitrogen has one nonbonding electron pair each nitrogen has two nonbonding electron pairs a nitrogen-nitrogen triple bond
Answers
Answer:
one bond between nitrogen and hydrogen and a double bond between the nitrogen atoms.
Explanation:
H-N=N-H
A substance's density is known to be
5.6 g/mL. You have a 25.0mL sample of the
substance. What is the mass of the sample?
Answers
Answer:
140
Explanation:
do cross multiple the two mL cancel out each other and you are left with 140
which property is least helpful in identifying a sample of matter? A. melting point B. Volume. C. Reactivity. D. Boiling point
Answers
Answer:
which property is least helpful in identifying a sample of matter is (B) VOLUME
Explanation:
volume depend on the amount of substance present and are not useful in the identification of a sample of matter. volume is an extensive property so it is not useful identifying the sample of matter.