Answers
Answer:
Balanced forces are responsible for unchanging motion. Balanced forces are forces where the effect of one force is cancelled out by another. A tug of war, where each team is pulling equally on the rope, is an example of balanced forces. The forces exerted on the rope are equal in size and opposite in direction.
Explanation:
Related Questions
Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)
Answers
The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.
First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.
Next, we calculate the effective thermal conductivity of the air layer as:
k_eff = (k_air * L_air) / (L_air + k_glass)
Substituting the given values, we have:
k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air
Now, we can calculate the heat flow per second through the air layer using the formula:
Q = (k_eff * A * ΔT) / L_air
Substituting the given values, we get:
Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s
Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
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A red horse and a black horse raced on a 1-mile long circular racetrack. The red horse
completed the race in 120 seconds, and the black horse completed the race in 150
seconds. Which choice correctly describes the speed of the horses?
A- Only the red horse ran at a constant speed
B- The red horse's average speed was greater than the black horse's average speed.
C- The black horse's average speed was greater than the red horse's average speed.
D- Only the black horse ran at a constant speed.
Answers
Answer
your format is incorrect!!
Explanation:
there is no such thing as a red horse. there are chestnuts, bays and red roans, just no reds. usually though, blacks are faster scientifically than red roans.
Planets A and B have the same size, but planet A is half the mass of planet B.
Which statement correctly explains the weight you would experience on each
planet?
A. You would weigh the same on both planets because the planets
are the same size.
B. You would weigh less on planet A because it has less mass than
planet B.
C. You would weigh the same on both planets because your mass
would be the same on both.
D. You would weigh more on planet A because it has less mass than
planet B.
Answers
Answer:
B
Explanation:
The more mass an object has, the more gravity it has.
The statement which correctly explains the weight you would experience on each planet is: B. You would weigh less on planet A because it has less mass than planet B.
Weight can be defined as the force acting on a body or an object as a result of gravity.
Mathematically, the weight of an object is given by the formula;
\(Weight = mg\)
Where;
m is the mass of the object.g is the acceleration due to gravity.Hence, we can deduce that the weight and gravity acting on an object is highly dependent on the mass of an object.
Therefore, the higher the mass in a planet, the higher the gravity existing there.
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Solar System - Scaling. When you look at Neptune in a telescope, you are actually looking into the past as the light has to travel from Neptune to your eyes. If the speed of light is ~300,000 km/s, how far back into the past are you looking (or put another way, how long does it take light to travel from Neptune to your eyes on Earth)
Answers
Answer:
Distance from sun to Neptune = 4.495E9 km
Time for light to travel = 4.495E9 / 3E5 sec = 14,980 sec
That is from sun to Neptune time fof light = 250 min
Time for light to travel from sun to earth is about 8 min
So the time from Neptune would be 242 to 258 min depending on position of Neptune - Note that Neptune is about 30X as far from the sun as earth and
250 min / 8 min is roughly 30
The uniform motion of kinematics allows us to find the time it takes for light to arrive from Neptune to Earth, which varies between:
t₁ = 1.45 10⁴ s and t₂₂= 1.55 10⁴ s
depending on the relative distance of the two planets
given parameters
The speed of light c = 300,000 km / s = 3 10⁸ m / s The distance from Neptune to Sum
to find
The time when light arrives from Neptune to Earth
They velocit of an electromagnetic wave is constant, so we can use the uniform motion relationships
v = d / t
t = d / v
where v is the speed of light, d the distance and y time, in this case the speed of the wave is the speed of light (v = c)
We look in the tables for the distances and the rotation periods around the sun
distance ( m) period (s)
Sun Neptunium 4.50 10¹² 5.2 10⁹
Sun - Earth 1.5 10¹¹ 3.2 10⁷
With the data of the period it is observed that the rotation of Neptune is much greater than that of Eart rotation around the sun, for which we will assume that Neptunium is fixed in space and the Earth may be in its aphelion or perihelion, maximum approach o away distance from the sun, consequently we calculate the time for the two cases:
Maximum approach
positions relative distance from the dos Plantetas is
Δd = \(x_{Neptuno - Sum} - x_{Earth - Sum}\)d
Δd = 4.50 10¹² - 1.5 10¹¹
Δd = 43.5 10¹¹ m
the time it takes for Neptune's light to reach Earth is
Δt = \(\frac{ 43.5 \ 10^{11} }{3 \ 10^8}\)
Δt = 14.5 10³ s
Δt = 1.45 10⁴ s
We reduce to hours
Δt = 1.45 10⁴ s (1 h / 3600 s) = 4.03 h
Maximum away
Δd = \(x_{Neptune - Sum} + x_{Neptune-Sum}\)
Δd = 4.50 10¹² + 1.5 10¹¹
Δd = 46.5 10¹¹
The time is
Δt = \(\frac{46.5 \ 10^{11}}{ 3 \ 10^8}\)
Δt = 15.5 10³
Δt = 1.55 10⁴ s
We reduce to hours
Δt = 1.55 10⁴ s (1 h / 3600 s) = 4.31 h
In conclusion, the time it takes for light to arrive from Neptune to Earth varies between:
t₁ = 1.45 10⁴ s and t₂ = 1.55 10⁴ s
depending on the relative distance of the two plants
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A car has a mass of 1,200 kg. What is its acceleration when the engine exerts a force of 600 N? (Formula: F=ma)
O 0.5 m/s2
2 m/s2
O 600 m/s2
1,800 m/s2
Answers
Answer:
Option (a)
Explanation:
Given that,
Mass of a car, m = 1200 kg
Force exerted by the engine, F = 600 N
Noe force,F = ma
a is the acceleration of the engine
\(a=\dfrac{F}{m}\\\\a=\dfrac{600\ N}{1200\ kg}\\\\a=0.5\ m/s^2\)
So, the acceleration of the car is 0.5 m/s².
Answer:
0.5 m/s^2
Hope it works!
Explanation:
What is Concave lenses ?
Answers
Explanation:
A concave lens is also known as a diverging lens because it is shaped round inwards at the centre and bulges outwards through the edges, making the light diverge. They are used to treat myopia as they make faraway objects look smaller than they are.
You are walking on a moving walkway in the airport. The length of the walkway is 59.1 m. If your velocity relative to the walkway is 2.35 m/s, and the walkway moves with a velocity of 1.85 m/s, how long will it take you to reach the other end of the walkway
Answers
Answer:
14.1seconds approx
Explanation:
Given data
Distance= 59.1m
Your velocity= 2.35m/s
Walkway velocity= 1.85m/s
Total velocity= 2.35+1.85= 4.2m/s
We know that
Velocity= distance/time
time= distance/velocity
substitute
time= 59.1/4.2
time= 14.07
time=14.1seconds approx
Hence the time is 14.1seconds approx
The mass of an empty cylindrical tin is
proportional to its surface area.
Two empty cylindrical tins, G and H, are
shown below.
The mass of tin G is 72 g, and the surface
area of tin H is 792π cm².
2
a) Work out the total surface area of tin G in
terms of π.
b) Work out the mass of tin H.
Tin G
12 cm
5 cm
Tin H
Not drawn accurately
Answers
a) The total surface area of tin G in terms of π is 170π cm².
b) The mass of tin H is 336 g.
To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.
a) Total surface area of tin G in terms of π:
The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:
Lateral surface area = 2πrh
where r is the radius of the base and h is the height of the cylinder.
In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:
Lateral surface area = 2π(5 cm)(12 cm)
Lateral surface area = 120π cm²
Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:
Area of a circle = πr²
The radius of the circular base of tin G is 5 cm, so the area of each circular base is:
Area of each circular base = π(5 cm)²
Area of each circular base = 25π cm²
To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:
Total surface area of tin G = Lateral surface area + 2 × Area of each circular base
Total surface area of tin G = 120π cm² + 2 × 25π cm²
Total surface area of tin G = 120π cm² + 50π cm²
Total surface area of tin G = 170π cm²
Therefore, the total surface area of tin G in terms of π is 170π cm².
b) Mass of tin H:
We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:
(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)
Using the given values, we have:
(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)
Cross-multiplying and solving for the mass of tin H, we get:
(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)
mass of tin H = (72 g) × (792π cm²) / (170π cm²)
mass of tin H = 336 g
Therefore, the mass of tin H is 336 g.
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Calculate the de Broglie wavelength of a proton whose kinetic energy is equal to the rest mass energy of an electron. What should be the accelerating potential that need to be applied on an electron so that it has a de Broglie wavelength equal to that of the proton calculated above?
Answers
mvh=1. 654106. 6210=41014m is the de Broglie wavelength of a proton whose kinetic energy is equal to that of the proton.
What is the energy of an electron that has undergone a 100 kV potential difference?An electron has an energy of 100,000 eV (100 keV) at a potential difference of 100,000 V (100 kV), and so on. The energy gained by an ion with a double positive charge when it is accelerated through 100 V is 200 eV.
What is the relationship between kinetic energy and the de Broglie wavelength?De Broglie wavelength is the length of a particle with kinetic energy E. The wavelength changes to /2 when energy E is added to it.
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Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1100-kg car was moving at 10.9 m/s and stopped in 0.159 seconds.
Answers
The change in momentum of Kara's car is -1.43 × 10⁴ kg.m/s, the magnitude of force is -1.021 × 10⁵ N.
What is Force?Force is the external agent which causes the motion of an object or it is the resistant which makes the object come at rest from motion. It is a vector quantity, because it has both the magnitude and direction.
Mass of Kara's car = 1300 Kg
moving with speed = 11 m/s
time taken to stop = 0.14 s
final velocity = 0 m/s
distance between Lisa ford and Kara's car = 30 m
a) change in momentum of Kara's car
Δ P = m Δ v
Δ P = m(vf - vi)
Δ P = 1300 (0 - 11)
Δ P = -1.43 × 10⁴ kg.m/s
The impulse is equal to the change in momentum of the car
I = -1.43 × 10⁴ kg.m/s
Magnitude of the force experienced by Kara
I = F × t
where, I is impulse acting on the car
t is time
- 1.43 × 10⁴ = F × 0.14
F = -1.021 × 10⁵ N
Negative sign represents the direction of the force.
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Your question is incomplete, most probably the complete question is:
Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1300-kg car was moving at 11 m/s and stopped in 0.14 seconds.
a. Determine the momentum change of Kara's car.
b. Determine the impulse experienced by Kara's car.
c. Determine the magnitude of the force experienced by Kara's car.
In a certain two-slit interference pattern, eight bright fringes lie
within the second side peak of the diffraction envelope and diffraction minima coincide with two-slit interference maxima.
(a) What is the ratio of the slit separation to the slit width?
(b) How many bright fringes lie within the first side peak?
Answers
a) The ratio of the slit separation to the slit width is 2.
b) There are four bright fringes within the first side peak.
How to determine ratio and brightness?a) The ratio of the slit separation to the slit width is 2. This is because the second side peak of the diffraction envelope is located at an angle of
2λ/d, where λ = wavelength of light and d = slit width.
The diffraction minima coincide with the two-slit interference maxima, which are located at angles of λ/d.
Therefore, the ratio of the slit separation to the slit width is 2.
(b) There are four bright fringes within the first side peak. This is because the first side peak of the diffraction envelope is located at an angle of
λ/d, where λ = wavelength of light and d = slit width.
The diffraction minima coincide with the two-slit interference maxima, which are located at angles of λ/d.
Therefore, there are 4 bright fringes within the first side peak.
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I need help with these questions please
Answers
24.A
25.B
26.True
27. False
28.True
Answer:
24.A
25.B
26.True
27.False
28.True
(Figure 1) shows a thin liquid film bounded on the right side by a sliding wire that is attached to a spring with spring constant 0.50 N/m. The spring is stretched by 1.3 cm. What is the liquid's surface tension in mN/m?
Answers
The liquid's surface tension in N/m is determined as 0.25 N/m.
What is surface tension?
Surface tension is defined as the property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.
Mathematically, the formula for surface tension of a liquid is given as;
γ = F/L
γ = F/2x
where;
F is the applied forcex is the extension of the springγ is the surface tensionFrom Hooke's law, the force applied on an elastic material is directly proportional to the extension of the material.
F = kx
where;
k is the spring constantx is the extension of the springThe final equation for the surface tension of the liquid film becomes;
γ = F/2x
γ = kx/2x
γ = k/2
γ = (0.5 N/m) / 2
γ = 0.25 N/m
Thus, the surface tension of a liquid depends on the applied force and length of the liquid surface.
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A certain type of lens changes the direction of light rays from A to B. What property does
this illustrate?
Answers
The figure shows the polarization of light in the image.
What is light?We have to note that light is the form of energy that we can be able to see by the use of the optical eyes that we have. There are several propoerties of light that are also the properties of waves.
We should know that light is an electromagnetic wave and the polarization of waves can only occur in an electromagnetic wave. From A to B in the figure that have been shown, we can see the polarization of waves.
Thus the light waves are polarized.
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how large amount of energy is produced during the fission of uranium
Answers
Answer:
answer is a very large amount of energy is produced from a very small mass
Explanation:
nuclear energy is produced either by fusion or fission the former is fusion of lighter atoms into heavier elements while the letter is the splitting of a heavier atom into lighter atoms. both produce tremendous amount of energy fusion causes compassion of mass wild fission reduces it. and produce it. fusion does not produce radioactive particles while fission does (alpha and beta particles and neutrons)
An engine does 18500 J of work and rejects 7810 J of heat into a cold reservoir whose temperature is 285 K. What would be the smallest possible temperature of the hot reservoir
Answers
This question involves the concepts of thermal efficiency and hot reservoir.
The smallest possible temperature of the hot reservoir would be "960 k".
The thermal efficiency of an engine is given by the following formula:
\(Efficiency=\frac{Work}{Heat\ In}=\frac{Work}{Work+Heat\ Rejected}\\\\Efficiency = \frac{18500\ J}{18500\ J+7810\ J}\\\\Efficiency = 0.703\)
Another formula for thermal efficiency of an engine is:
\(Efficiency = 1-\frac{T_2}{T_1}\)
where,
T₁ = Temperature of the hot reservoir = ?
T₂ = Temperature of the cold reservoir = 285 k
Therefore,
\(0.703=1-\frac{285\ k}{T_1}\\\\\frac{285\ k}{T_1}=1-0.703\\\\T_1=\frac{285\ k}{0.297}\)
T₁ = 960 k
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the flux through the coils of a solenoid changes from 6.78*10^-4 wb to 1.33*10^-4 wb in 0.0333 s if the solenoid has 605 loops how much emf is generated
Answers
The electric and magnetic field ( emf ) generated given the number of loops in the solenoid is 9.90 V.
Given the data in the question;
\(\delta \theta_1 = 6.78*10^{-4}Wb\)\(\delta \theta_2 = 1.33*10^{-4}Wb\)\(\delta t = 0.0333s\)\(N = 605\)Electric and magnetic fields (EMF)
Emf are invisible energy regions also called radiation, associated with the use of electrical power and various forms of lighting.
From Faraday's law; emf E is expressed as;
\(emf = -N\frac{\delta \theta }{\delta t}\)
Where N is number of loops, \(\delta \theta\) is change in magnetic flux ( \(\delta \theta_2 - \delta \theta_1\) ) and \(\delta t\) is change in time.
First we determine the change in flux through each loop;
\(\delta \theta\) = ( \(\delta \theta_2 - \delta \theta_1\) )
\(\delta \theta = (1.33 * 10^{-4} Wb) - (6.78 * 10^{-4} Wb)\\\\\delta \theta = -0.000545\)
Now, we substitute our values into the expression above
\(emf = -N\frac{\delta\theta}{\delta t} \\\\emf = (-605) * (\frac{-0.000545}{0.0333}) \\\\emf = (-605) * (-0.016366)\\\\emf = 9.90V\)
Therefore, the electric and magnetic field ( emf ) generated given the number of loops in the solenoid is 9.90 V.
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what is the total distance traveled by a bike rider who rides for three hours at 40 km/hr and then two more hours at 50 km/hr?
Answers
Answer:
220 km
Explanation:
3 hours at 40 km/hr
40 km = 1 hour
40 km times 3 = 120 km
2 hours at 50 km/hr
50 km = 1 hour
50 times 2 = 100 km
Total distance
120 km + 100 km = 220 km
7. A 50 kg athlete runs and grabs a 10.0 m rope and swings to a maximum height of 1.8 m above
the ground. A second athlete, who has a mass of 100. kg runs at the same speed, v, and grabs a
5.0 m rope. What maximum height will the 100. kg athlete swing to? Assume the mass of the
ropes and air resistance are negligible. Support your answer with calculations and/or a proof.
(3 marks)
50 kg
10 m
100 kg
T
5m
Answers
Answer:
1.8 m
Explanation:
All the KE of the 50 kg runner converts to PE at the top of his swing.
1/2mv² = mgh
1/2(50 kg)(v²) = (50 kg)(9.8 m/s²)(1.8 m)
25v² = 882
v² = 882/25 = 35.3
v = √35.3 = 5.94 m/s
The 100 kg runner also runs at the same speed, 5.94 m/s.
You can solve for the max. height (h) of the 100 kg runner:
1/2 (100 kg)(5.95 m/s)² = (100 kg)(9.8 m/s²)(h)
h = 1764.2/980 = 1.8 m SAME AS THE OTHER RUNNER!
During a home run, the batter only needs to run around all 4 bases if he wants to, since the ball cleared the outfield fence.
True
False
Answers
Answer: False
Explanation:
what is kinematics ;-;
explain.
Answers
Answer:
the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.
Explanation:
If Th-234 emits a beta particle, what nucleus is formed?
Answers
Given:
The parent nucleus is,
\(Th^{234}\)To find:
The product when Th-234 emits a beta particle
Explanation:
When a particle emits a beta particle, the atomic number increases by 1, but the mass number remains the same.
So,
\(Th_{90}^{234}-\beta=Pa_{91}^{234}\)Hence, the product is Pa-234 with atomic number 91.
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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.What is the relationship between the solar radius and the brightness of stars?
Answers
Answer:
Its radius is thought to be around 1400 times than of our sun, and its luminosity 270,000 greater than our sun. Also, if a star has the same radius as the sun but a higher surface temperature, the hotter star exceeds the sun in luminosity
Explanation:
As the solar radius of the star increases, the brightness of the star also increases.
What is meant by luminosity ?Luminosity is defined as the measure of brightness of a celestial object or the relative quantity of light.
Here,
Solar radius is a unit of distance, which is used to determine the size of the stars relative to the sun.
The size of the star and the luminous intensity are directly proportional. As the size of the star increases, the luminosity of the star also increases. Therefore, larger stars shine more brighter than the smaller ones.
The brightness of a star is directly proportional to the square of its solar radius. Therefore, the luminosity increases with increase in solar radius.
Hence,
As the solar radius of the star increases, the brightness of the star also increases.
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The speed of light is 3×10^8 meters per second, which means that light can travel 300 million meters in just one second. How far can light travel in one minute?
Answers
Answer:
(1.8 × 10^9) meters in one minute
Explanation:
To determine how far light can travel in one minute, we need to multiply its speed by the number of seconds in a minute.
The speed of light is 3 × 10^8 meters per second.
There are 60 seconds in a minute.
Therefore, the distance light can travel in one minute is:
Distance = Speed × Time
Distance = (3 × 10^8 meters per second) × (60 seconds)
Calculating this, we get:
Distance = 3 × 10^8 meters/second × 60 seconds
Distance = 18 × 10^8 meters
Distance = 1.8 × 10^9 meters
So, light can travel approximately 1.8 billion (1.8 × 10^9) meters in one minute.
Forests have been completely wiped out in some parts the world. In areas that are economically depressed, people use the cut wood to fuel fires for cooking and for making shelters or homes. How would deforestation most likely impact Earth's biogeochemical cycles?
Group of answer choices
Less carbon dioxide will be present in the atmosphere because the people living in the area still breath in oxygen.
An increase in carbon dioxide will occur in the atmosphere because there are less trees to use the gas in the process of photosynthesis.
Carbon dioxide levels will not change, since plants do not have a role in the carbon cycle.
More water will be released into the atmosphere because transpiration and condensation will produce more precipitation.
Answers
Answer: An increase in carbon dioxide will occur in the atmosphere because there are less trees to use the gas in the process of photosynthesis.
Explanation: Photosynthesis can be simply defined as a process where green plants uses minerals from the soil, water and carbon dioxide to produce their own food (energy-rich organic compound/starch) while oxygen is released into the environment.
On the other hand, Human beings and other animals inhales the oxygen released into the environment by green plants and breath out carbon dioxide.
Deforestation is the permanent removal trees either for commercial or household use or in some cases, to make room or space for other activities or development.
Now when these trees (green plants) are permanently cut down without replacement, humans and other animals continuously exhale carbon dioxide and there will be little or no green plants (trees) available to convert this carbon dioxide into oxygen.
Hence, there will be an increased amount of carbon dioxide in the atmosphere as their are little or no tress to use the gas (carbon dioxide) in the process of photosynthesis.
Please help (science)
Plate Boundaries on Earth
Plate boundaries represent parts of the Earth where plates come in contact with one another. There are different ways in which these plates can move and interact. In this assignment, you will identify each type of plate movement and create an illustration to represent this.
Open the worksheet to get started. Use the criteria below to see what you should include in this assignment.
Row 1: Plate Boundary (Movement)
Write the type of plate boundary: convergent, divergent, transform.
Write the correct description for each in parentheses below the name: sliding, separating, or colliding.
Row 2: Diagram
Draw a diagram or illustration of the plate movement at the plate boundary. Include arrows to show whether the plates are colliding, separating, or dividing.
Row 3: Lithosphere (Created or Destroyed)
Identify whether the Earth's crust is created or destroyed at this type of plate boundary.
Row 4: Geologic Process
Give at least one example of the type of process or geological event that occurs on the Earth when the plates move in this manner.
Row 5: Real World Example
Give at least one example of a place on the planet where this type of plate movement is demonstrated along the plate boundary. Include both the location and name of the example.
Row 6: References
This assignment requires you to conduct formal research. When researching, make sure to use only valid and reliable resources; Wikipedia, blogs, and answer sites are not valid or reliable. References must be cited in APA format. Please provide your references in APA format in this column.
Answers
Here is a draft of the worksheet for the three main plate boundary types:
Plate Boundary (Movement) Convergent (Colliding)
Diagram
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Lithosphere (Created or Destroyed)
Created
Geologic Process Mountain building
Real World Example
Himalayas (Along India-Eurasia plate boundary in Asia)
References
APA reference for research
Plate Boundary (Movement) Divergent (Separating)
Diagram
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Lithosphere (Created or Destroyed)
Destroyed
Geologic Process
Volcanic eruptions and rift valleys
Real World Example
Mid-Atlantic Ridge (Between North America and Europe plates)
References
APA reference
Plate Boundary (Movement) Transform (Sliding)
Diagram
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Lithosphere (Created or Destroyed)
Neither
Geologic Process
Earthquakes
Real World Example
San Andreas Fault (California, USA along Pacific-North America plates)
References
APA reference
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Answers
Answer:
D gravity
Explanation:
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Answer:
D. The force that the branch applies to the kitten
Explanation:
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1. Consider a circular track with a radius of 200 meters. A runner starts on the east side and runs around the track to a point diametrically opposite her starting point. What is the magnitude of her displacement? She then runs the rest of the way around the track to complete a full lap. What is the magnitude of her total displacement after she has returned to her starting point?
Answers
Answer:
The magnitude of her displacement when at a point diametrically opposite her starting point is 400 meters
After she has returned to her starting point, the magnitude of her displacement is zero
Explanation:
Displacement is a vector quantity defined as the length of the shortest path between the final and the initial points. In other words, displacement can be defined as the distance traveled in a straight line.
From the question,
The circular track has a radius of 200 meters.
The runner starts on the east side to a point diametrically opposite her starting point. The diametrically opposite point is the point at the opposite end of the diameter of the circle.
Hence, her displacement ( that is, the length of the shortest path between her final and her initial points) is the length of the diameter of the circle.
Diameter d, of a circle is given as twice the radius r, of the circle.
That is, d = 2r
Radius r, of the circular track is 200 meters
∴ d = 2r = 2 (200 meters)
d = 400 meters
Hence, her displacement when at a point diametrically opposite her starting point is 400 meters
Now, after she has returned to her starting point, the magnitude of her displacement is zero.
This is because, the length between her final point ( which is the same as her initial point) and her initial point in zero.
A 0.60- m -tall barrel is filled with water (with a weight density of 9800 N/m3 ). Find the water pressure on the bottom of the barrel. Express your answer to two significant figures and include the appropriate units.
Answers
Answer:
P = ρ g H explains the pressure of a uniform column of density ρ
P = ρ H where ρ is given as a weight density
P = 9800 N/m^3 * .60 m = 5880 (5900) N / m^2
Note N/m^2 = Force / Area the definition of pressure