What do all elements in a column in the periodic table have in common? (2 points)
Oa
Their atoms have the same number of valence electrons.
Ob
Their atoms have the same atomic mass.
Their atoms have the same number of protons and electrons.
Od
Their atoms have the same number of neutrons.

Science builds on itself because the process of science is iterative and not predetermined.

Science is said to build on itself because the process of science is iterative. This means that science does not have a linear path but circles back on itself so that useful ideas are built upon and used to learn even more about the natural world.

For instance, the discovery of inheritance that could be passed from parent to their offspring by Gregor Mendel.

Many more scientist has worked subsequently on chromosome, gene and DNA.

They have continued to deepen and extend our understanding of genes, how they are controlled, how patterns of control themselves are inherited, and how they produce the physical traits that pass from generation to generation.

Science is said to build on itself because the process of science is not predetermined. This means that carrying out an experiment on an idea would lead to the discovery of a new idea altogether.

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Answer: a . it decreases

Explanation:

Determine the planet's radius and mass. Use the formula g=GMR2 to get the acceleration 93.63×10¹⁶m/s brought on by gravity on that planet's surface.

The most practical formula for estimating the acceleration caused by gravity is given by these two laws: g = G*M/R2, where g is the acceleration caused by gravity, G is M represents mass, R is distance, and G is the gravitational constant of the universe.

g = G*M/R2,

g = 5.972×10²⁴/ 6.378×10⁶

g = 5.972×10¹⁸/6.378

g = 93.63×10¹⁶m/s

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We have that the total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is

\(X=58.96gal/day\)

From the Question we are told that

Pipe Drip\(=155 mL/min.\)

Generally

We have that for mL to gallons conversion

\(1mL=0.000264172\)

And

A minute to day con version is

\(1min=0.000694444\)

Therefore

\(X=155 mL/min.\)

\(X=155(\frac{0.000264172}{0.000694444})\)

\(X=58.96gal/day\)

In conclusion

The total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is \(X=58.96gal/day\)

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Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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Answer:

\(v=1.24\times 10^8\ m/s\)

Explanation:

Given that,

The refractive index of benzene is 2.419

We need to find the speed of light in benzene. The ratio of speed of light in vacuum to the speed of light in the medium equals the refractive index. So,

\(n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{2.419}\\\\v=1.24\times 10^8\ m/s\)

So, the speed of light in bezene is \(1.24\times 10^8\ m/s\).

The resultant displacement of the car can be determined using Pythagorean theorem. The magnitude of car's displacement here is 47.3 Km.

Displacement is a vector quantity measuring the change in position of an object. It can be used in short  term distances. Displacement have both magnitude and direction.

Given , distance to travelled to east = 15 km

to the north = 45 km

then,  the two points if connected will form a triangle where we can use the Pythagorean theorem to find the resultant vector.

The resultant displacement = √(45² + 15 ²) = 47.3 km

Therefore, the displacement of the car is 47.3 km.

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The tension in the cables as the elevator travel upwards is 1,960 N.

The given parameters:

Newton's second law of motion states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.

The tension in the cables as the elevator travel upwards is calculated by applying Newton's second law of motion as shown below;

T = ma + mg

where;

At constant velocity, acceleration is zero (a = 0)

T = m(0) + mg

T = mg

T = 200 x 9.8

T= 1,960 N

Thus, the tension in the cables as the elevator travel upwards is 1,960 N.

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The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

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Answer:

join my z o o m

Explanation:

The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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Answer:

3 m/s²

Explanation:

acceleration = Force / mass;  4.5/1.5 = 3

When a student applies a net force of 4.5 Newtons to the 1.5-kilogram textbook, then the magnitude of the acceleration would be 3 meters/second².

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².

As given in the problem, when a student applies a net force of 4.5 Newtons to the 1.5-kilogram textbook, then we have to find the magnitude of the acceleration,

the applied force on the textbook = 4.5 Newtons

the mass of the textbook is 1.5 kilograms

acceleration of the textbook = force / mass

                                             =4.5 Newtons /1.5 kilograms

                                             =3 meters/second²

Thus, the magnitude of the acceleration would be 3 meters/second².

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Using the conversion factor that we have seen in the solution, the value obtained is 40.25 kilometers per hours

To convert miles per hour (mph) to kilometers per hour (kph), you need to multiply the speed value in mph by a conversion factor of 1.61, which is the number of kilometers in one mile.

Given that;

1 miles/hour = 1.61 kilometer per hour

25 miles per hour = 25 * 1.61/1

= 40.25 kilometers per hours

Hence the value that we get is 40.25 kilometers per hours

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The convert unit of  25 miles per hour is equivalent to 40.2335 kilometers per hour

Unit conversion is the process of converting a value expressed in one unit of measurement to another unit of measurement that is equivalent in terms of its value or quantity. This is done by using a conversion factor, which is a numerical factor that relates the two units of measurement.

To convert miles per hour (mph) to kilometers per hour (km/h), we need to multiply the speed in mph by 1.60934, which is the conversion factor from miles to kilometers.

So, to convert 25 mph to km/h:

25 mph × 1.60934 = 40.2335 km/h

Therefore, 25 miles per hour is equivalent to 40.2335 kilometers per hour.

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Answer:

protons: 6

electrons: 6

neutrons: 8

Explanation:

atomic number -> number of protons -> 6

mass number -> number of protons + number of neutrons

    so 14-6 = 8. 8 neutrons

this atom is neutral (net charge is 0), so the number of electrons is the same as the number of protons, which is 6

Answer:

303.264

Explanation:

Work=Power x time

Work=194.4 x 1.56

Work=303.264

Explanation:

Power= Work/ time

Work = Power×time

but SI unit for time is seconds

Changing 1.56 minutes to seconds,

1.56×60= 93.6 s

this implies that, Work = 194.4 × 93.6

= 18195.84J

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass

v is the velocity

From the question we have

\(k = \frac{1}{2} \times 8 \times {4}^{2} \\ = 4 \times 16\)

We have the final answer as

Hope this helps you

the answer to your question is 200 J

Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.

Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:

1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.

2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.

3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.

4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.

These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.

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Answer:

See below

Explanation:

Assuming starting from zero velocity

vfinal = at

24   = a (5.5)

a = 4.36  m/s^2        I think part of your question is missing....what was the initial velocity?

part a) If Q increases by 5 times its original value, the electrostatic force (F) will increase5 times as well.

part b) If r is halved (reduced by 2), the force will become four times stronger (since 2² = 4).

part c) If Q1 is positive and Q2 is negative, the charges will attract each other.

part d) If the force that Q1 exerts on Q2 is 5 times larger than the force that Q2 exerts on Q1 is same.

The electrostatic force is described as the force of attraction or repulsion between two charged particles.

With regards to Coulomb's Law, we have that the electrostatic force between two charges separated by a distance is :

Force = k * (Q1 * Q2) / r²

Where:

F_ =  electrostatic force

k = electrostatic constant

Q1 and Q2 =  magnitudes of the charges

r = distance

for case a:

If one of the charges, Q1 or Q2, increases by 5 times then the electrostatic force  will also increase by 5 times.

case b)

If the distance between the charges, r, is halved, the electrostatic force   will become four times stronger because (1/r²).

for case c.

if Q1 is positive and Q2 is negative, the charges will attract each other because of magnetic laws.

for case d.)

If the force that Q1 exerts on Q2 is 5 times larger than the force that Q2 exerts on Q1 is same as there is a resulting stronger gravitational or electromagnetic force.

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The number of distinct ways of placing four indistinguishable balls into five distinguishable boxes is 20.

To solve this problem, we can use the stars and bars method, which is a combinatorial technique used to count the number of ways to distribute indistinguishable objects into distinguishable containers. In this case, we have four indistinguishable balls and five distinguishable boxes.

The stars and bars method works by representing each ball as a star and using bars to separate the balls into different boxes. For example, if we wanted to distribute two balls into three boxes, we could use the following diagram:

* | * * | *

In this diagram, the first and last bars represent the boundaries of the containers, while the stars represent the balls.

The second bar separates the first two balls from the last ball, indicating that the first two balls are in the first container and the last ball is in the third container.

To distribute four balls into five boxes, we need to use three bars to separate the balls into four groups. We have a total of six spaces to place the bars (including the boundaries), and we need to choose three of them to place the bars.

Therefore, the number of distinct ways to place four indistinguishable balls into five distinguishable boxes is the same as the number of ways to choose three spaces out of six, which is:

6 choose 3 = (6!)/(3!3!) = 20

Therefore, there are 20 distinct ways to place four indistinguishable balls into five distinguishable boxes using the stars and bars method.

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The dependent variable in this experiment is: D. the time for the blocks to hit the ground.

An experiment can be defined as a scientific investigation which typically involves the process of manipulating an independent variable (the cause), so as to determine or measure the dependent variable (the effect).

In every experiment, there are two (2) main types of variables and these include the following:

In this scenario, we can infer and logically deduce that the dependent variable in this experiment is the time for the blocks to hit the ground because it signifies the effect of the independent variable (three blocks).

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Complete Question:

A student drops three blocks from the same height and measures the time it takes for the blocks to hit the ground. Each block has a different mass.

What is the dependent variable in the experiment?

A. the volume of the blocks

B. the drop height

C. the mass of the blocks

D. the time for the blocks to hit the ground

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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The wave speed of the wave was calculated from the frequency and the wave length is 1600 m/s. Hence, option D is correct.

The speed of the wave is obtained by the product of frequency and the wavelength of the wave. It is measured in m/s.

From the given,

frequency of the wave (f) = 270 Hz

Wavelength (λ)  = 6m

Wave speed = f×λ

                    = 270×6

                     = 1620 m/s

Thus, the wave speed of the wave is 1620 m/s. Hence, the ideal solution is option D.

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Answer:

identify who they are as a person

Explanation:

Answer:

44.294 m/s

you might want to double check the answer depending on what you use for g. some people use 9.81, some 9.8, and some 10. that can effect the final answer

Explanation:

use the formula \(v^{2}-v_{0}^{2} = 2ax\), which can be moved around to get \(v = \sqrt{2ax}\)

note that mass does not effect the velocity

since the blocks were dropped from rest, v_0 = 0m/s. a = g = 9.81 m/s^2, and x = h = 100m.

plug in the values for the variables to get v = sqrt(2(9.81)(100)) = 44.294 m/s for both blocks

Answer:

  (b)  0.29 m/s

Explanation:

The average speed is found by dividing the net displacement by the amount of time it took to achieve that displacement.

__

The net displacement is ...

  6 m -8 m = -2 m . . . . . where north is positive

The total time is ...

  2 s + 5 s = 7 s

Then the distance per unit time (speed) is ...

  (2 m)/(7 s) = 2/7 m/s ≈ 0.29 m/s

Answer:

We are given:

m1 = 500 kg             m2 = 1500 kg

v1(initial) = x m/s       v2(initial) = 0 m/s

v1(final) = 20 m/s      v2(final) = 20m/s

According the the law of conservation of momentum:

m1v1(initial) + m2v2(initial) = m1v1(final) + m2v2(final)

Plugging the values in this formula:

(500*x) + (1500 * 0) = (500 * 20) + (1500 * 20)

500x = 20(1500 + 500)

500x = 20(2000)

x = 20 * 4

x = 80 m/s

Therefore, the car was initially moving at a velocity of 80 m/s

Answer:

Let's define t = 0s (the initial time) as the moment when Car A starts moving.

Let's find the movement equations of each car.

A:

We know that Car A accelerations with a constant acceleration of 5m/s^2

Then the acceleration equation is:

\(A_a(t) = 5m/s^2\)

To get the velocity, we integrate over time:

\(V_a(t) = (5m/s^2)*t + V_0\)

Where V₀ is the initial velocity of Car A, we know that it starts at rest, so V₀ = 0m/s, the velocity equation is then:

\(V_a(t) = (5m/s^2)*t\)

To get the position equation we integrate again over time:

\(P_a(t) = 0.5*(5m/s^2)*t^2 + P_0\)

Where P₀ is the initial position of the Car A, we can define P₀ = 0m, then the position equation is:

\(P_a(t) = 0.5*(5m/s^2)*t^2\)

Now let's find the equations for car B.

We know that Car B does not accelerate, then it has a constant velocity given by:

\(V_b(t) =20m/s\)

To get the position equation, we can integrate:

\(P_b(t) = (20m/s)*t + P_0\)

This time P₀ is the initial position of Car B, we know that it starts 100m ahead from car A, then P₀ = 100m, the position equation is:

\(P_b(t) = (20m/s)*t + 100m\)

Now we can answer this:

1) The two cars will meet when their position equations are equal, so we must have:

\(P_a(t) = P_b(t)\)

We can solve this for t.

\(0.5*(5m/s^2)*t^2 = (20m/s)*t + 100m\\(2.5 m/s^2)*t^2 - (20m/s)*t - 100m = 0\)

This is a quadratic equation, the solutions are given by the Bhaskara's formula:

\(t = \frac{-(-20m/s) \pm \sqrt{(-20m/s)^2 - 4*(2.5m/s^2)*(-100m)} }{2*2.5m/s^2} = \frac{20m/s \pm 37.42 m/s}{5m/s^2}\)

We only care for the positive solution, which is:

\(t = \frac{20m/s + 37.42 m/s}{5m/s^2} = 11.48 s\)

Car A reaches Car B after 11.48 seconds.

2) How far does car A travel before the two cars meet?

Here we only need to evaluate the position equation for Car A in t = 11.48s:

\(P_a(11.48s) = 0.5*(5m/s^2)*(11.48s)^2 = 329.48 m\)

3) What is the velocity of car B when the two cars meet?

Car B is not accelerating, so its velocity does not change, then the velocity of Car B when the two cars meet is 20m/s

4)  What is the velocity of car A when the two cars meet?

Here we need to evaluate the velocity equation for Car A at t = 11.48s

\(V_a(t) = (5m/s^2)*11.48s = 57.4 m/s\)