What diseases are spread in warm temperatures?

Answer:

1

Explanation:

Answer:

answer is b

Explanation:

Answer: on

Explanation:5

The price of sodium chloride per 5 kg is 179 dollars. The experiment requires 65 g of NaCl. The price of65 g or 0.065 kg is 2.3 dollars.

Sodium chloride is an ionic compound formed by the combination of sodium metal and chlorine atom. Sodium metal has extra one electron in its valance shell and chlorine needs one more electron into its valence shell. Hence sodium donates its valence electron to chlorine forming NaCl.

NaCl is used as the table salt in food. It is a very important compound in our daily diet. Similarly NaCl is industrially important for many reaction especially in electrochemical processes.

It is given that, the price of 5 kg of NaCl = $179

required mass of NaCl = 65 g = 0.065 Kg

then , price of 0.065 kg = (0.065 × 179 /5) =  $2.31

Therefore, the cost of NaCl in the experiment is 2.31 dollars.

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KCl → k+ + Cl. The ensuing aggregate of ions is identical in each pre-and publish-blend unit of compounds. both comprise Na+, Cl-, okay+, and Br- ions, and no insoluble compounds can result from any mixture of those ions.

The three rules for writing net ionic equations are simply pretty trustworthy. only do not forget to break apart the (aq) substances. best split strong electrolytes.

Delete any ions that seem on both sides of the equation. when an aqueous solution of potassium chloride KCl, while combined with silver nitrate AgNO3 answers insoluble AgCl forms as a white substance. this is an example of a double displacement reaction. due to the fact potassium ion and silver ions displace collectively in the product formation.

The net ionic equation is a chemical equation for a response that lists best those species collaborating inside the reaction. The internet ionic equation is generally utilized in acid-base neutralization reactions, double displacement reactions, and redox reactions.

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Answer:

C

Explanation:

The ΔS° value for the reaction KCl(s) → K+(aq) + Cl−(aq) is ΔS° > 0, as the products have a higher degree of disorder than the reactant due to an increase in the number of particles in solution. Hence the correct option is (C) ΔS° > 0.

The ΔS° value for a reaction represents the change in the entropy of the system, which is a measure of the disorder or randomness of the system. The reaction KCl(s) → K+(aq) + Cl−(aq) involves a solid compound breaking down into two separate aqueous ions, which means that the products have a higher degree of disorder than the reactant. This increase in the number of particles in solution results in an increase in entropy, which means that ΔS° > 0. Option (A) is incorrect because the reaction involves a change in state, which results in an increase in entropy. Option (B) is incorrect because it represents the relationship between enthalpy and entropy, not the ΔS° value for this particular reaction. Option (D) is incorrect because the reaction results in an increase in entropy, not a decrease. Option (E) is incorrect because the given information is sufficient to predict the sign of ΔS°.

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The ∆H of solution of NaOH is 46.8 kJ/mol.

First, we need to calculate the amount of heat absorbed by the solution:

q = m × c × ∆T

where q is the heat absorbed (in Joules), m is the mass of the solution (in grams), c is the specific heat capacity of the solution (in J/(g °C)), and ∆T is the change in temperature (in °C).

In this case, the mass of the solution is the sum of the mass of NaOH and the mass of water:

m = 7.59 g + 80.0 g = 87.59 g

The change in temperature is:

∆T = 48.0 °C - 25.0 °C = 23.0 °C

Substituting the values, we get:

q = 87.59 g × 4.184 J/(g °C) × 23.0 °C = 8,878 J

Next, we need to convert the heat absorbed into the enthalpy change of solution (∆H). The enthalpy change of solution is the heat absorbed per mole of solute. The number of moles of NaOH is:

n = m/M

where M is the molar mass of NaOH, which is 40.00 g/mol.

n = 7.59 g / 40.00 g/mol = 0.1898 mol

Therefore, the enthalpy change of solution is:

∆H = q/n = 8,878 J / 0.1898 mol = 46,780 J/mol = 46.78 kJ/mol

The H of a NaOH solution, rounded to three significant numbers, is 46.8 kJ/mol.

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Answer:

Explanation:

H+ = 1 X 10^-7.41 = 3.89 X 10^ -8

POH = 14-7.41 = 6.59

OH- = 1 x 10 ^-6.59 = 2.57 X 10^ -7

The [H+] and [OH−] concentrations of the solution are approximately 2.38 × 10^(-7) M, and the pOH is 6.59.

The pH of a solution is a measure of the concentration of hydrogen ions ([H+]) in the solution. The pH scale ranges from 0 to 14, with a pH of 7 considered neutral. A pH of 7.41 indicates that the solution is slightly basic. To calculate the [H+], [OH−], and pOH of the solution, we can use the relationship:

pH + pOH = 14

Given that the pH is 7.41, we can subtract it from 14 to find the pOH:

pOH = 14 - 7.41 = 6.59

Since pH + pOH = 14, we can also determine the [OH−] by taking the antilogarithm of the pOH value:

[OH−] = 10^(-pOH)

[OH−] = 10^(-6.59)

[OH−] ≈ 2.38 × 10^(-7) M

Since the solution is neutral, the concentration of [H+] will be equal to the concentration of [OH−]:

[H+] = [OH−] ≈ 2.38 × 10^(-7) M

Therefore, the [H+] and [OH−] concentrations of the solution are approximately 2.38 × 10^(-7) M, and the pOH is 6.59.

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Answer:

-1

Explanation:

Proton +1

Neutron 0

Electron −1

Answer:

Largest is Mg as across the period atomic radius decreases

"45.5% by mass NaF solution" means that 45.5% of the mass of the solution is NaF.

The solution has 34.2g of mass, so 45.5% of this is the mass of NaF:

To transform this into moles, we need the molar mass of NaF, which we can calculate using the atomic masses of Na and F:

So, the number of moles is:

So, there are approximately 0.371 mol of NaF.

The number of moles of the gas is 0.016 moles

The airbag reaction is the nitrogen gas obtained by the decomposition of sodium azide and the reaction is

2NaN₃ → 2Na + 3N₂

Then it is under ideal condition

P = 1atm

V = 1L

T =  495°C or 768 K

n = ?

We have to calculate moles of nitrogen = ?

R = 0.082 atm LK⁻¹mol⁻¹

So the formula is

PV =nRT

n = PV/RT

n = 1 atm×1L/0.082 atm LK⁻¹mol⁻¹×768 K

n = 0.016 moles

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Answer:

H2SO4(aq)

Explanation:

The balanced equation for the reaction is given below:

H2SO4(aq) + Mg(s) —> MgSO4(aq) + H2 (g)

An acid is a substance which dissolves in water to produce hydrogen ion, H+ as the only positive ion.

To know which of the substance is acid, let us dissolve them in water to see which will produce hydrogen ion, H+ as the only positive ion.

This is illustrated below:

H2SO4(aq) —> 2H+(aq) + SO4^2-(aq)

Mg(s) + 2H2O(l) —> Mg(OH)2(aq) + H2(g)

MgSO4(aq) —> Mg^2+(aq) + SO4^2-(aq)

H2 is insoluble in water.

From the above, only H2SO4 produces hydrogen ion H+ on dissolution in water. Therefore, H2SO4 is an acid

Answer:

D on edg 2021

Explanation:

To solve this problem we have to use ideal gas law.

First convert mL to L, torr to atm and °C to K:

Use the ideal gas law and solve for n:

Use Avogadro's number to find the number of molecules in the amount of moles obtained:

It means that there are 1.318155x10^22 molecules contained in 815mL.

Answer:

b) PH3

Explanation:

Answer:

answer is Option A

H202.

The new volume assuming that the pressure and temperature remain constant is 0.46 L and the correct option is option 1.

The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as-

                        PV = nRT

where,

P = Pressure

V = Volume

T = Temperature

n = number of moles

Given,

Initial volume = 1.5 L

Initial moles = 7.5 moles.

Moles remaining = 2.3 moles

\(\frac{n_{1} }{V_{1} } = \frac{n_{2} }{V_{2} }\)

\(\frac{7.5}{1.5 } = \frac{2.3}{V_{2} } }\)

V₂ = 0.46 L

Thus, the ideal selection is option 1.

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The layers of the earth include the following;troposphere, stratosphere, mesosphere, thermosphere, and exosphere. It's explanation will be discussed below.

The layers of the earth are grouped into five major layers that includes the following:

Troposphere: This is the layer of the earth that is closest to the earth's surface. It is characterized by having 78% nitrogen, 21% oxygen and remainder of trace gases (carbon dioxide, ozone, hydrocarbons, argon).

Stratosphere: This layers is located immediately above the troposphere. This layer is where ozone formation occurs and it's suitable for flying jets. It can be said that the stratosphere helps to protect us against ultraviolet rays of the sunlight.

Mesosphere: This is the layer found immediately above the stratosphere. This layer is characterized by having internal atmospheric gravity waves.

Thermosphere: This is the layer that is found immediately above the Mesosphere. It has the ability to absorb the sun's radiation.

Exosphere: This is the layer that is found immediately above the thermosphere. There is accumulation of the lightest gases such as hydrogen and helium in this layer.

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Answer:

3

Explanation:

at first try balancing the carbon first. At first multiply 2 with CO2, that produces 2 carbon and 8 oxygen. On reactant side we have 3 Oxygen. Now look at Hydrogen. There are 6 hydrogen atoms on the reactant side. So you need to multiply 3 with H20 to be 6 hydrogen atoms as 3*2 = 6.

Final reaction: C2H5OH + 3O2 ------> 2CO2 + 3H2O

The new volume of the helium sample at 50°C and 203 kPa would be 6.16 mL.

First we need to use the ideal gas law equation:

PV = nRT

Where

To solve for the new volume, we can use the following steps:

Convert the initial temperature to Kelvin:

T = 20°C + 273.15 = 293.15 K

Use the initial conditions to calculate the number of moles of helium:

n = PV/RT = (203 kPa x 4.5 mL) / (8.314 J/(mol·K) x 293.15 K) = 0.00073 mol

Use the new conditions to solve for the new volume:

V = nRT/P = (0.00073 mol x 8.314 J/(mol·K) x (273.15°C + 50°C)) / 203 kPa = 6.16 mL

Therefore, the new volume of the helium sample at 50°C and 203 kPa would be 6.16 mL.

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Answer:

The major ionic constituents whose concentrations can be determined from the salinity are known as conservative substances. Their constant relative concentrations are due to the large amounts of these species in the oceans in comparison t

The average atomic mass of titanium on the given planet is approximately 46.68164 atomic mass units (u). The average atomic mass may vary depending on the specific isotopic composition of titanium found on different celestial bodies or regions.

To calculate the average atomic mass of titanium on the given planet, we need to consider the natural abundances and masses of each isotope of titanium.

The average atomic mass is calculated by multiplying the natural abundance of each isotope by its respective mass and summing them up.

Let's perform the calculation step by step:

Step 1: Multiply the abundance of each isotope by its mass:

(73.700% * 45.95263 u) + (15.000% * 47.94795 u) + (11.300% * 49.94479 u)

Step 2: Calculate the individual contributions from each isotope:

= (0.737 * 45.95263) + (0.150 * 47.94795) + (0.113 * 49.94479)

Step 3: Add up the individual contributions:

= 33.84765431 + 7.1921925 + 5.64179347

Step 4: Sum up the contributions:

= 46.68164 u

Therefore, the average atomic mass of titanium on the given planet is approximately 46.68164 atomic mass units (u).

It's important to note that the calculation assumes the provided natural abundances are accurate and representative of the titanium isotopes on that planet.

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Answer:

\([A]=0.0026M\)

Explanation:

Hello.

In this case, since the second-order rate law is:

\(\frac{dC_A}{dt}=-kC_A^2\)

Whereas the subscript A accounts for C2F4 and its integration turns out into:

\(\frac{1}{[A]}= \frac{1}{[A_0]} +kt\)

Thus, for the initial concentration of C2F4 computed via the 0.1 mol in the 2.31-L container:

\([A]_0=\frac{0.1mol}{2.31L} =0.043M\)

The final concentration after 2.1 h is:

\(\frac{1}{[A]}= \frac{1}{0.043M} +\frac{0.048}{M*s} *\frac{3600s}{1h}*2.1h\\\\\frac{1}{[A]}=\frac{386.1}{M}\)

Solving for the final concentration of C2F4, we obtain:

\([A]=\frac{M}{386.1} =0.0026M\)

Best regards.

Answer:

when an electric current is passed through sodium chloride solution, hydrogen gas forms at the negative electrode, chlorine gas forms at the positive electrode and a solution of sodium hydroxide also forms

To answer this question, we need to convert grams to moles and then use the Avogadro's number to convert moles to molecules.

The molar mass of Mg(OH)2 is 58.32 g/mol.

First, we need to find the number of moles of Mg(OH)2 in 75.0 g.

75.0 g / 58.32 g/mol = 1.287 mol

Next, we need to convert moles to molecules.

1.287 mol x 6.022 x 10^23 molecules/mol = 7.75 x 10^23 molecules

Finally, we can use the molecular formula of Mg(OH)2 to calculate the number of miles of Mg(OH)2.

1 molecule of Mg(OH)2 contains 3 atoms of oxygen (O) and 2 atoms of hydrogen (H).

So, the total number of miles of Mg(OH)2 is:

7.75 x 10^23 molecules x 2 miles/molecule = 1.55 x 10^24 miles

Therefore, there are 1.55 x 10^24 miles of magnesium hydroxide in 75.0 g of magnesium hydroxide.

1) Diesel has a higher viscosity than petrol.

2) Petrol is more flammable than diesel.

3) The formula will be C₁₀H₂₂.

4) The equation is; 2C8H18+25O2→16CO2+18H2O.

Depending on the precise composition and temperature, the viscosity of gasoline and diesel can change. In general, diesel is more viscous than gasoline. Higher viscosity fluids are thicker and flow more slowly than lower viscosity fluids because viscosity relates to the resistance of a fluid to flow.

Diesel is less flammable than gasoline. The lowest temperature at which gasoline can evaporate and turn into an ignitable combination in air is known as its flash point, and it is lower for gasoline. Compared to diesel fuel, petrol vapors are much more flammable and can ignite at lower temperatures.

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