what determines the amplitude of a wave of the type shown

Hi there!

a)
We can use the equation for the magnetic dipole moment to solve for the number of turns:
\(\mu_m = NIA\vec{n}\)

\(\mu_m\) = Magnetic dipole moment (0.194 Am²)

N = Number of loops (?)

A = Area of loop (4.0 cm²)

\(\vec{n}\) denotes the area vector, or the normal line perpendicular to the area.

We first need to convert cm² to m² using dimensional analysis.

\(4.0 cm^2 * \frac{0.01m}{1 cm} * \frac{0.01 m}{1cm} = 0.0004 m^2\)

Rearranging the equation to solve for 'N':

\(N = \frac{\mu_m}{IA}\\\\N = \frac{0.194}{(8.8)(0.0004)} = \boxed{55.11 \text{ turns}}\)

**Since we cannot have part of a turn, the coil has about 55 turns.

b)

For this, we can use the Right-Hand-Rule for current. Looking at the coil from the left with your curled fingers going around the coil with the fingertips pointing through and to the left in the direction of the magnetic moment, your thumb points in the COUNTERCLOCKWISE direction.

c)
Now, let's use the equation for the torque produced by a magnetic field:
\(\tau = \mu_m \times B\)

This is a cross-product, but since our magnetic field is perpendicular to the magnetic moment, we can disregard it.

Plugging in the values for the magnetic moment and the magnetic field:

\(\tau = 0.194 * 45 = \boxed{8.73 Nm}\)

d)

Using the other RHR (current, field, force), the coil will spin about its vertical axis in the field. In more detail, if you look at the coil from the left-hand side with its opening towards you, from this perspective, the left of the coil will come towards you, and the right side of the coil will move away.

Answer:

Anti-Particle

Answer:

1.25 sec, 2 m/s

Explanation:

Period = 2 * 0.625 sec = 1.25 sec

speed = 2.5/1.25 = 2 m/s

Answer:

answer is edh

Explanation:

dened eh

As a result, the picture behind the mirror is virtual, upright, and enlarged.

You will find that the properties of an image (SALT) created in a concave mirror depend on the object's position. A) if the item is larger than C. Size, attitude, and location are all important considerations.

The image will be true, but reversed and much reduced. To obtain a crisp flame image, move the burning candle towards the mirror while moving the screen away from it. The size of the inverted picture grows.

Concave mirrors may create both physical and virtual images. A virtual and enlarged picture is produced when the item gets closer to the mirror. When the item is placed further away from the mirror,.

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Answer:

The velocity is 2661.5 m/s.

Explanation:

Radius, horizontal distance, d = 309 km

height, h = 25 km

acceleration due to gravity on moon, g =3.71 m/s^2

Let the time taken is t and the horizontal velocity is u.

horizontal distance = horizontal velocity x time

309 x 1000 = u t .... (1)

Use second equation of motion in vertical direction.

\(h = u_yt +0.5 gt^2\\\\25000 = 0 + 0.5\times 3.71\times t^2\\\\t =116.1 s\)  

So, put in (1)

309 x 1000 = u x 116.1

u = 2661.5 m/s

Answer:

sperms or semen

Explanation:

sorry if i got it wrong

Answer:

It is called sperm

Explanation:

Explanation:

The formula to calculate wavelength is: wavelength = speed / frequency.

Using the values you provided, we can calculate the wavelength as follows:

wavelength = 343 m/s / 466 Hz = 0.737 meters (rounded to three decimal places).

Therefore, the wavelength of the wave is approximately 0.737 meters.

The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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total goldfish = 36

orange goldfish= x = 7 more than twice the number of black goldfish

x = 2y + 7

Black goldfish = y

x + y = 36

x = 2y + 7

x-2y = 7

A.

x + y = 36

x - 2y = 7

Answer:

Not sure but I think its (A)

Explanation:

I think its (A)

Answer:

C

Explanation:

They divided some numbers and got 5

It said something about it accelerates at 10 seconds so all I did was multiply by 2 and I got C

Answer:

by potential difference and electron gun

Explanation:

a magnetic field is produced whenever an electrical charge is in motion. The spinning and orbiting of the nucleus of an atom produces a magnetic field as does electrical current flowing through a wire. The direction of the spin and orbit determine the direction of the magnetic field.

Answer:

Electromagnetic field can be produced by the superposition of electric field and magnetic field.

Explanation:

When two or waves propagate in a medium without affecting each other , then at any instant the displacement of a particle will be equal to the vectorial sum of the displacements due to the waves.

Hence Electromagnetic field can be produced by L-C CIRCUITS.

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The angle that the net force makes with respect to the x- axis, is determined as 55.3⁰.

The angle that the net force makes with respect to the +x axis, is determined as follows;

F = qvBsinθ

Fy =  qv(By)sinθ

Fx =  qv(Bx)sinθ

The angle that the net force makes with respect to the +x axis;

tanθ = Fy/Fx

tanθ = qv(By)sinθ / qv(Bx)sinθ

tanθ = By/Bx

tanθ = 0.065/0.045

tanθ = 1.444

θ = tan⁻¹(1.444)

θ = 55.3⁰

Thus, the angle that the net force makes with respect to the x- axis, is determined as 55.3⁰.

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The density of the oil when the water and oil are mixed is 661kg/m³.

From the information illustrated, water and then oil are poured into a U-shaped tube, open at both ends and they then come to equilibrium.

It was stated that suppose that H = 25.7 cm and h = 8.72 cm. It should be noted that the pressure ends at the one of the opening is the atmospheric pressure, therefore the gauge pressure will be:

∆P = pgh

This will be illustrated as:

(0.257)P = (1000) × (0.257 - 0.0872)

0.257P = 169.8

Divide

P = 169.8 / 0.257

P = 661kg/m³

The density is 661kg/m³.

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Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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The angle below the horizontal of the velocity of the puck just before it hits the ground is 12.6°.

Given:

v₀x=28m/s

v₀y=0m/s

y₀=2.00m

x₀=0m

we know that velocity of an object is defined as the speed of that thing in a direction. rate of change in  the velocity is acceleration . so here  first we are calculating the time and then we are finding the speed of the object

yf=y₀+v₀yt+1/2at²

yf=0

0=2.00m+0m/s+1/2(−9.8m/s²)t²

4.9 m/s² t²=2.00m

t=1.025s

Then using time to calculate the final x-position...

x=x₀+v₀xt+1/2at²

x=0m+(28ms)(0.64s)+0

x=28.7m/s

After we got the speed then finally we are putting that in a triangle and we are finding the angle.

tan(θ)=2.00/28.7

θ=12.6°

So from the above we got that the angle is 12.6°

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Answer:

C) The book's inertia carried it forward.

When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.

Explanation:

The most denser among the given materials is gold and the least dense one is helium. The order of density from least to most dense is helium, carbon dioxide, water, lead and gold.

Density of a substance is the measure of its mass per unit volume. It describes how  closely packed its particles. density depends on the bond type, temperature and pressure.

The density of helium is very low and it is the lightest element after hydrogen. It density is about 0.00017 g/ml. Density of carbon dioxide is 0.0019 g/ml and the density of water is 1 g/ml.

Gold is a denser metal and its density is about 19.3 g/ml and that of lead is 11.3 g/ml. Hence, the order of density from least to most dense is He < carbon dioxide< water< lead < gold.

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Answer:

35 meters

20+15=35

Considering the definition of speed, you will travel 90 km.

Speed ​​is a quantity that expresses the relationship between the space traveled by an object. That is, the speed is associated with the change of position of an object in space within a certain amount of time.

The speed can be calculated using the expression:

\(speed=\frac{displacement}{time}\)

In this case, you know that:

Replacing in the definition of speed:

\(120\frac{km}{hr} =\frac{displacement}{0.75 hr}\)

Solving:

120\(\frac{km}{hr}\)× 0.75 hr= displacement

90 km= displacement

In summary, you will travel 90 km.

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The mass of the traveling truck is approximately 3000 kilograms.

Momentum is simply the product of the mass of an object and its velocity.

Its is expressed mathematically as;

P = m × v

Where m is the mass of the object and v is its velocity.

Given that:

Momentum of truck P = 6.36 × 10⁴ kgm/s

Velocity of the truck v = 21.2 m/s

Mass of the truck m = ?

Substitute the given values into the equation above and solve for mass.

P = m × v

m = p / v

m = ( 6.36 × 10⁴ ) / 21.2

m = 3 × 10³ kg

m = 3000 kg

Therefore, the truck has a mass of 3000 kg.

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The boat's final velocity can be determined using the work-energy principle. Since the boat starts at rest, the work done on it will be equal to its change in kinetic energy.

Using the equation:

Work = Change in Kinetic Energy

300 J = (1/2) * m * v^2

where m is the mass of the boat and v is the final velocity, we can solve for v.

Plugging in the values:

300 J = (1/2) * 4.5 kg * v^2

Simplifying the equation:

v^2 = (2 * 300 J) / 4.5 kg

v^2 = 200 J / 4.5 kg

v^2 = 44.44 m^2/s^2

Taking the square root of both sides:

v = √(44.44 m^2/s^2)

v ≈ 6.66 m/s

Therefore, the boat's final velocity is approximately 6.66 m/s.

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

F = 695.25 N

Explanation:

The force between Mars and Rover can be given by Newton's Law of Gravitation can be written as follows:

F = Gm₁m₂/r²

where,

F = Force of Gravity = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = mass of rover = 74 kg

m₂ = mass of mars = 6.39 x 10²³ kg

r = distance between the centers of mars and rover = 2.1299 x 10⁶ m

Therefore,

F = (6.67 x 10⁻¹¹ N.m²/kg²)(74 kg)(6.39 x 10²³ kg)/(2.1299 x 10⁶ m)²

F = 695.25 N

Answer:

a    \(D = 3.9 *10^{-12} \ m\)

b    \(\tau_{max} = 1.24 *10^{-25} \ N\cdot m\)

c   \(W = 2.48 *10^{-25} J\)

Explanation:

From the question we are told that

   The magnitude of electric dipole moment is  \(\sigma = 6.2 *10^{-30} \ C \cdot m\)

     The electric field is \(E = 2*10^{4} \ N/C\)

The distance between the positive and negative charge center is mathematically evaluated as

     \(D = \frac{\sigma }{10 e}\)

Where  e is the charge on one electron which has a constant value of  \(e = 1.60 *10^{-19} \ C\)

  Substituting values

     \(D = \frac{6.20 *10^{-30}}{10 * (1.60 *10^{-19})}\)

      \(D = 3.9 *10^{-12} \ m\)

The maximum torque is mathematically represented as

       \(\tau_{max} = \sigma * E * sin (\theta)\)

Here  \(\theta = 90^o\)

This because at maximum the molecule is perpendicular to the field

    substituting values

       \(\tau_{max} = 6.2 *10^{-30} * 2*10^{4} sin ( 90)\)

       \(\tau_{max} = 1.24 *10^{-25} \ N\cdot m\)

The workdone is mathematically represented as

      \(W = V_{(180)} - V_{0}\)

where   \(V_{(180)}\) is the potential energy at 180° which is mathematically evaluated as

     \(V_{(180) } = - \sigma * E cos (180)\)

Where the negative signifies that it is acting against the  field

   substituting values

     \(V_{(180) } = - 6.20 *10^{-30} * 2.0 *10^{4} cos (180)\)

      \(V_{(180) } = 1.24*10^{-25} J\)

and

     \(V_{(0)}\) is the potential energy at 0° which is mathematically evaluated as

            \(V_{(0) } = - \sigma * E cos (0)\)

   substituting values

     \(V_{(0) } = - 6.20 *10^{-30} * 2.0 *10^{4} cos (0)\)

      \(V_{(0) } =- 1.24*10^{-25} J\)

So \(W = 1.24 *10^{-25} - [-1.24 *10^{-25}]\)

    \(W = 2.48 *10^{-25} J\)

Answer:

At zero kelvin (minus 273 degrees Celsius) the particles stop moving and all disorder disappears. Thus, nothing can be colder than absolute zero on the Kelvin scale. Physicists have now created an atomic gas in the laboratory that nonetheless has negative Kelvin values.

Explanation: