what current is transfered if 0.24 coublombs is to be transfered in 15ms​

Answer:

true, there are certain forms of bacteria in water that can cause permanent brain damage (although its rare) so further contamination of water can lead to higher chances of contracting serious illnesses caused by such bacteria.

Explanation:

It exists in the tube as single molecules in liquid form. But when they come into contact with water, the molecules react with hydroxide ions to form long polymer chains that set into a hard solid. As there is a thin layer of moisture covering most surfaces, cyanoacrylate can bond them together very effectively.

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

2km

Explanation:

Given data

We are told that the direction traveled are

North>>>East>>>South

Hence the displacement is defined as the distance away from the initial position is

Initial position =18km

FInal position = 16km

The displacement = 18-16= 2km

Hence the displacement is 2km

The mass of the helium sample is approximately 0.187 g.

To solve this problem, we can use following formula:

w = nR(T2 - T1)

We can rearrange this formula to solve for n:

n = w / (R * (T2 - T1))

To find the mass of the helium sample, we can use following formula:

m = n * M

where m is the mass of the sample, n is  number of moles of gas, and M is the molar mass of helium.

Substituting the given values into the first equation, we get:

70 J = n * 8.31451 J/mol*K * (358 K - 283 K)

Simplifying this equation, we get:

n = 0.0467 mol

Substituting this value into the second equation, we get:

m = 0.0467 mol * 4 g/mol = 0.187 g

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Answer:

No a shape is a 2d figure and cannot have a smell or anything else

Explanation:

Move numbers to the boxes to show the factor pairs of 14:

Blank space 1: 1

Blank space 2: 1

Blank space 3: 2

Blank space 4: 7

A factor pair of a number is a pair of whole numbers that can be multiplied together to give the original number. For the number 14, the factor pairs are (1,14) and (2,7). So, we can put 1 in the first blank, 14 in the second blank, 2 in the third blank, and 7 in the fourth blank to show the factor pairs of 14.

To show the factor pairs of 14 in the given response area with 4 blank spaces, we need to find the two numbers that can be multiplied together to give 14. These two numbers are called factor pairs of 14.

To begin, we can start listing the factors of 14. The factors of 14 are 1, 2, 7, and 14. We can then use these factors to form factor pairs by multiplying them together. The factor pairs of 14 are (1, 14) and (2, 7).

To show these factor pairs in the given response area, we can put the first factor of each pair in the first and third blank spaces, and the second factor of each pair in the second and fourth blank spaces. Therefore, we can put 1 in the first blank, 14 in the second blank, 2 in the third blank, and 7 in the fourth blank to show the factor pairs of 14.

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The initial speed of the second ball is c. 26.8 m/s

Speed is the distance per unit time moved by an object/

Since the ball is a projectile, to find the initial speed of the second ball, we need to find the maximum height of the first ball using

h = u²sin²Ф/2g where

Substituting the values of the variables into the equation, we have

h = u²sin²Ф/2g

h = (32 m/s)²× (sin57°)²/(2 × 9.8 m/s²)

h = 1024 m²/s²× (0.8387)²/(19.6 m/s²)

h = 1024 m²/s²× (0.7034)/(19.6 m/s²)

h = 720.249 m²/s²/(19.6 m/s²)

h = 36.75 m

Now, since a second projectile is thrown vertically to the same maximum height, we need to find its initial speed.

Using the equation of motion v² = u² - 2gh where

Making u subject of the formula, we have

u = √(v² + 2gh)

Substituting the values of the variables into the equation, we have

u = √(v² + 2gh)

u = √[(0 m/s)² + 2 × 9.8 m/s² × 36.75 m]

u = √[0 m²/s² + 19.6 m/s² × 36.75 m]

u = √[720.3 m²/s²]

u = 26.84 m/s

u ≅ 26.8 m/s

So, the initial speed of the second ball is c. 26.8 m/s

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Jacob's weight when sitting in a chair with a mass of 74.8 kg is 733.0 N

Weight can be defined as the gravitational pull of a body.

To calculate Jacob's weight, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the weight of Jacob is 733.0 N.

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Answer:

Volumetric cylinders and volumetric flasks are used to measure volume of liquids contained in them. They are calibrated for volume included in them - this is indicated by the marking "IN". The liquid has accurate volume when it reaches the corresponding marking on the scale. Volume is usually indicated in mL. Mark me brainliest please

Answer:

C) proton acceptor

Explanation:

A proton acceptor is another name for a base,

Part: a

First let's represent each vector on a grid.

When we combine vectors visually, we connect the tip (arrow side) of one vector to the tail (non-arrow side) of the other. The vector is then drawn from the beginning point to the final position.The graphical representation of the sum of vectors \($\vec{A}$\)and \($\vec{B}$\) is:[See attachment]

Part: b

The graphical representation \($\vec{A}-\vec{B}$\) is:  [See attachment]

What is Vectors?

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Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.

Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.

Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.

Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.

To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.

For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.

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Known :

z1 = 380 ft

z2 = 210 ft

D1 = 8 in

D2 = 4 in

hL = 36 ft

Solution :

Continuity Equation

Q1 = Q2

A1 • V1 = A2 • V2

(πD1²/4) • V1 = (πD2²/4) • V2

D1² • V1 = D2² • V2

8² • V1 = 4² • V2

V2 = 4V1 ... (i)

Energy Equation :

P1/γ + V1²/2g + z1 = P2/γ + V2²/2g + z2 + hL

Since P1 = P2, then

V1²/2g + z1 = V2²/2g + z2 + hL

V1²/2(32.2) + 380 = V2²/2(32.2) + 210 + 36

V2² - V1² = 8.63 × 10³ ... (ii)

Subtitute (i) into (ii)

(4V1)² - V1² = 8.63 × 10³

15V1² = 8.63 × 10³

V1 = 24 ft/s

Q = A1 • V1

Q = [π(8/12)² / 4] • 24

Q = 8.377 cfs

The value of the horizontal position of the pumpkin is 62.5.

Its height is a maximum, we need to seek values of xm for which: > View Available Hint(s) y(x) = axm^2 +b = 0

dy/dx = 2axm+b 272+b=0 200+

The pumpkin's highest height is reached 62.5 horizontal meters from the point of launch.

The computation looks like this:

The equation, which corresponds to a parabola-shaped curve, is y = - 0.008x 2 + x.

Now that the arms of this parabola are pointing downward, we may calculate its maximum by demanding that the derivative slope of the tangent line to the curve be equal to zero.

The result is that u prime = -0.016x + 1 0 = -0.016x + 1 x = 1 / d * iv * 0.016 = 62.5m.

The value of the horizontal position of the pumpkin is 62.5.

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Answer: It is brighter

Explanation: We are getting closer to the light because the earth is expanding.

the answer is it is brighter cause the light from the object is known as blueshift

Flying into a microburst is more dangerous than flying into a hurricane because it usually happens during takeoff and landing.  

A microburst is a strong movement of air downwards. It happens inside a thunderstorm. In a microburst a plan is pushed towards the ground with a high force.

A hurricane is a typical cyclone with winds rotating rapidly with a spiral arrangement of thunderstorm. A hurricane is accompanied by rain, thunder and lightning. If an aircraft enters a hurricane the air craft loses control yet stays up in the air, so the pilot can control if the aircraft enters an area where the effect of hurricane is low.

Therefore, flying into a microburst is more dangerous than flying into a hurricane because it usually happens during takeoff and landing.  

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The density of the liquid in the drum is 459.184 kg/m³.

To find the density of a liquid, we must know its pressure, the depth to which it is filled, and the gravitational acceleration acting on it. Using the equation for pressure at a depth h below the surface of a liquid in a container of height H, P = ρgh, where P is the pressure, ρ is the density, g is the gravitational acceleration, h is the height of the liquid, and H is the height of the container.Let's substitute the given values in the above formula:P = 9000800 Pa; h = 2m; g = 9.8m/s²Therefore, ρ = P/gh = 9000800/(9.8 × 2) ≈ 459184.

This means that the density of the liquid in the drum is 459.184 kg/m³ (kilograms per cubic meter).

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Answer:

Given: V=12 V

            I=2.5 mA

Let the resistance be R

By Ohm's Law, 

V=IR

12=2.5×10−3R

R=4.8×103 Ω

In physics, a lower fixed point refers to the minimum temperature at which a particular substance or system can reach and below which it cannot be cooled further.

It is a fundamental concept in the study of thermodynamics, specifically in relation to phase transitions and the behavior of substances at low temperatures.

The lower fixed point is often associated with the concept of absolute zero, which is the lowest possible temperature in the Kelvin scale (-273.15 degrees Celsius or -459.67 degrees Fahrenheit).

At absolute zero, particles in a substance possess the minimum amount of energy and their motion ceases, resulting in the absence of thermal energy.

The lower fixed point serves as a reference point for temperature scales, such as the International Temperature Scale of 1990 (ITS-90), which defines temperature measurements based on fixed points like the melting point of certain substances and the triple point of water.

These fixed points provide reproducible and well-defined temperature values for calibration and measurement purposes.

Understanding the lower fixed point is crucial for various scientific and technological applications, such as cryogenics, superconductivity, and the study of quantum phenomena at extremely low temperatures.

By pushing the boundaries of cooling techniques, researchers aim to approach the lower fixed point and explore the fascinating properties and behaviors of matter at such extreme conditions.

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The mass rate of change of the space probe is approximately 28.49 kg/s .

To solve this problem, we can use the generalized form of Newton's Second Law, which states that the force acting on an object is equal to its mass times its acceleration:

F = ma

In this case, the force acting on the space probe is the thrust force generated by the rocket motor, which is equal to the rate of change of momentum of the ejected fuel:

F = (Δ m /Δt) * v

where;

Since the space probe is landing on the planet, the net force acting on it should be equal to the force of gravity pulling it down minus the upward thrust force generated by the rocket motor. So we can write:

F_net = m * g - (Δ m /Δt) * v

Plugging in the values and solving for delta m / delta t, we get:

2.00 m/s² = (175,000 kg * 8.25 m/s²) - (Δ m / Δt) * 35,000 m/s

Δ m / Δt = (175,000 kg * 8.25 m/s² - 2.00 m/s² * 35,000 m/s) / 35,000 m/s

Δm / Δt ≈ 28.49 kg/s

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If the speed of the magnet is doubled, the induced voltage is twice as great

Faraday's law of induction states that whenever relative motion exists between a coil and magnetic field, a voltage will induce in the circuit and this voltage is proportional to the rate of change of the flux. The expression for the motional emf is as follows:

ε=Blv

Here, ε is the motional emf, B is the magnetic field, l is the length of the conductor, and v is the velocity at which the magnetic field changes.

The induced voltage by the moving magnet is directly proportional to the speed of the magnet. Therefore, an increase in the speed of the magnet will increase the induced voltage.

If the speed of the magnet is doubled, the induced voltage is twice as great

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Answer:

a. TRUTH

b. FALSE

c. TRUTH

d. FALSE

Explanation:

The emf (electromagnetic force) is generated in a loop or solenoid by the change in the magnetic flux in a closed conductor path (for example, a wire).

This can be noted in the following formula, which is known as the Lenz's law:

\(emf=-N\frac{d\Phi_B}{dt}=-N\frac{d(AB)}{dt}\)   (1)

Then, the change, in time, of the area of the conductor, or the change in the magnitude of the magnetic field, the induced emf acquires different values. Furthermore, the loops have a resistance, then, a current can be measured when an emf is induced.

Based on this information you have:

a. an induced emf is caused by a changing magnetic flux. TRUTH

b. an emf can only be induced in a conducting loop by moving the loop through an area that has a constant magnetic field. FALSE

c. an induced emf can be observed by measuring the current that is created. TRUTH

d. an induced emf and conventional induced current are in opposite directions. TRUTH (the minus sing in the equation (1) )

The magnitude of the centripetal acceleration of the piece of clay on the wheel will be  4.51 \(m/s^{2}\)

When an object  is moving in a circle , it experiences an acceleration towards the center of the circle is known as Centripetal acceleration

centripetal acceleration = radius * (\(omega^{2}\))

                                        = 0.22 * 20.5

                                        = 4.51 \(m/s^{2}\)

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Answer:

Potential Energy

Explanation:

Answer:

25.13274 W (WATT) (Sound Power of the Sound Source)

134.002 dB (Sound Power Level)

The vector field that expresses the density of induced or permanent electric dipole moments in a dielectric medium is known as polarization density (also known as electric polarization or just polarization).

Thus, A dielectric is considered to be polarized when its molecules acquire an electric dipole moment when exposed to an external electric field.

Electric polarization of the dielectric is the term used to describe the electric dipole moment induced per unit volume of the dielectric material.

The forces that emerge from these interactions can be calculated using the polarization density, which also defines how a material reacts to an applied electric field and how it modifies the electric field. It is comparable to magnetization, which measures a material's equivalent response.

Thus, The vector field that expresses the density of induced or permanent electric dipole moments in a dielectric medium is known as polarization density (also known as electric polarization or just polarization).

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The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Answer:

bouncing  a baskletball

Explanation:

Answer:someone kicking a soccer ball.

Explanation:

Because the ball isn’t in motion until acted on by another object (the foot)

The resistance of the electric device using a power of 650 watts is approximately 27.7 ohms.

Ohm’s law states that the potential difference between two points is directly proportional to the current flowing through the resistance.

Hence

V = IR

R = V/I

Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.

We need to first find the electric current I.

Note:

Power = Voltage × Current.

Hence:

Current I = Power/Votage

Plug in the values

I = 650 / 120

I = 13/3 A

Substituting the values of voltage and current intio the above formula, we can calculate the resistance:

R = V/I

R = 120 / (13/3)

R = 27.7 ohms

Therefore, the resistance is approximately 27.7 ohms.

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