what caused earths continents to drift apart?
Answers
Answer:
bada bop boop pow
Explanation:
Related Questions
how are gravity and friction the same??
Answers
Explanation:
Gravity always pulls objects such as a desk, book or person down. Thus, when you jump, gravity causes you to land on the ground. Friction, however, doesn't pull objects down. Instead friction occurs when something like a machine or individual pulls a sliding objects in the opposite direction of another object.
Pull affects gravity and friction in different ways. In fact, unlike gravity, friction doesn't rely on a natural force. The force of friction acting on the pages in a major reason that pulling the books apart is so different.
Betelgeuse is a supergiant star that will eventually supernova, which means that by mass it is classified as
Answers
Betelgeuse is a supergiant star that by mass is classified as a high-mass star.
What is a celestial body:
Celestial bodies are natural objects that are a part of the massive universe. Even though the universe has vast expanses of empty space, it is inhibited by them. The following are the 7 categories in which the celestial bodies are classified in:
A star is huge mass of radiating gas which is held together by it's own gravity. They produce their own energy due to nuclear fission reaction process and in turn emit their own light. Varying sizes of stars exist in the universe with the ones emitting blue light being the brightest and youngest, while ones emitting red light being older.
Planets
Planets are celestial bodies that do not emit light of their own. They revolve around a star, have enough gravity to obtain a spherical shape along with being able to omit the presence of other smaller celestial bodies around it.
Comet
They are usually lumps of gases, ice and dust that orbit a star. Comets consist of a nucleus (which contains the ice and dust) and when they come in the vicinity of the sun, a 'tail' of gas and dust particles pointing away from the sun is seen.
Satellites
There are natural and man-made celestial bodies that exist in the universe. They revolve about a planet the same way that planets revolve around the sun. Moon is a satellite of earth and GOES (weather satellite) is a man-made satellite.
Meteorite
They are small, rocky and usually metallic celestial bodies travelling in outer space. A shooting star is an example of a meteorite where the trail of the meteor is visible as it enters the earth.
Asteroid
These are small rocky celestial bodies which are too small to be considered as planets. They revolve about a star and are considered as the remaining parts from the formation of a galaxy.
Galaxy
A galaxy is a combination of huge masses of gas, dust, stars and dark matter that are held together by gravity. Primal example of a galaxy will be the Milky-way galaxy in which our solar system exists.
Thus, as Betelgeuse is a supergiant star that will eventually result in a supernova it is classified as a high-mass star.
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g a metal ring with a clockwise current produces a magnetic field (right-hand-rule). if the current increases (which increases the field) over time, what direction will the induced current on the ring be?
Answers
The induced current on the ring will be counter-clockwise (left-hand-rule).
Fleming's left-hand rule for electric motors is one among a pair of visual mnemonics, the opposite being Fleming's proper-hand rule (for generators). They had been originated with the aid of John Ambrose Fleming, within the overdue nineteenth century, as a simple way of working out the direction of motion in an electric powered motor, or the route of electric modern in an electric generator.
While modern-day flows through a conducting twine, and an outside magnetic discipline is carried out across that float, the accomplishing twine experiences a pressure perpendicular each to that area and to the path of the current drift (i.e they're jointly perpendicular). A left hand can be held, as proven in the illustration, so one can represent 3 jointly orthogonal axes at the thumb, fore finger and center finger. each finger is then assigned to a quantity (mechanical force, magnetic field and electric powered present day). The right and left hand are used for turbines and automobiles respectively.
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You normally watch about 4 hours of television every day with 58.6 watts when in on mode and 1.3 watts in standby mode. Which of the two wattages consumes more energy in a whole month?
Answers
In a whole month, the standby mode consumes more energy than the "on" mode for your television.
To determine which of the two wattages consumes more energy in a whole month, we need to calculate the energy consumption for each mode and compare the results.
First, let's calculate the energy consumption for the "on" mode:
Power consumption in watts: 58.6 watts
Time in hours: 4 hours per day
Number of days in a month: Assuming 30 days
Energy consumption in kilowatt-hours (kWh) for "on" mode = (Power consumption in watts * Time in hours * Number of days) / (1000 * 1000)
Energy consumption = (58.6 * 4 * 30) / (1000 * 1000)
= 0.07032 kWh
Next, let's calculate the energy consumption for the standby mode:
Power consumption in watts: 1.3 watts
Time in hours: 24 hours per day (assuming the TV is in standby mode when not in use)
Number of days in a month: Assuming 30 days
Energy consumption in kilowatt-hours (kWh) for standby mode = (Power consumption in watts * Time in hours * Number of days) / (1000 * 1000)
Energy consumption = (1.3 * 24 * 30) / (1000 * 1000)
= 0.0936 kWh
Comparing the two energy consumptions, we find that the energy consumption in the standby mode is higher, with an energy consumption of 0.0936 kWh compared to 0.07032 kWh in the "on" mode.
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what are the three essential diagnostic features of anorexia nervosa
Answers
1. Restriction of energy intake: This involves significantly limiting the amount of food intake, leading to low body weight in relation to age, sex, developmental trajectory, and physical health. It is often accompanied by a fear of gaining weight or becoming fat.
2. Intense fear of gaining weight or becoming fat: Individuals with anorexia nervosa have an excessive and persistent fear of gaining weight, even when they are significantly underweight. They may have distorted body image perceptions and a preoccupation with their shape and weight.
3. Disturbance in self-perceived weight or shape: Anorexia nervosa is characterized by a persistent lack of recognition of the seriousness of low body weight and its impact on health. Despite being underweight, individuals with anorexia may still perceive themselves as overweight or have a distorted body image.
These diagnostic features are crucial for identifying and diagnosing anorexia nervosa, but it is important to consult a qualified healthcare professional for a comprehensive evaluation and diagnosis.
The three essential diagnostic features of anorexia nervosa, as defined by the Diagnostic and Statistical Manual of Mental Disorders (DSM-5), are:
Restriction of energy intake relative to requirements: This refers to the persistent limitation of food intake, leading to significantly low body weight. Individuals with anorexia nervosa often engage in severe dieting, calorie counting, Intense fear of gaining weight or becoming fat: People with anorexia nervosa have an intense and irrational fear of gaining weight, even when they are already significantly underweightDisturbance in self-perceived weight or shape: DSM-5 An essential feature of anorexia nervosa is the presence of a distorted perception of one's body weight or shape.It is important to note that these diagnostic features must be present and significantly impair the individual's functioning in order to meet the criteria for anorexia nervosa. Additionally, there may be other associated features and behaviors,
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Explain why a steel boat floats on water but a steel block does not
Answers
A piece of steel sinks in water because steel is denser than water. However, a steel ship is a hollow object made of steel and contains a lot of air in it. Due to presence of a lot of air in it, the average density of the ship becomes less than the density of water. Hence a ship floats in water.
Answer:
Cause its a steel block
Explanation:
thats like putting a brick in the water and expecting it to float
True or False: Exercise is an underrated stress reliever and can be used to 25
overcome mental, physical, and emotional battles."
O True
False
Answers
Answer:
I think it is true I'm not saying it is but if you get another person who says its true say true
Explanation:
3 people are carrying a uniform metal plate in the shape of an isosceles triangle with base a = 0.7 m and height h = 1.35 m. Thickness of the plate is d = 1.5 cm, the density of the metal is ρ = 6500 kgm3. What is the upwards force that is exerted by the hands of each person, if each of them is holding the plate at a vertex and the plate is horizontal?
Answers
The upward force exerted by the hand of each person to support the metal plate is 150.54 N.
What is buoyant force?The upward force exerted by the hands of the three people provides support on the metal plate.
The volume of air displaced by the metal isosceles plate is calculated as follows;
\(V = A \times d\\\\V = \frac{1}{2} ba \times d\\\\V = \frac{1}{2} \times 0.7 \times 1.35 \times 0.015\\\\V = 0.00709 \ m^3\)
The mass of the metal plate is calculated as follows;
\(m = \rho V\\\\m = 6,500 \ kg/m^3 \ \times 0.00709 \ m^3\\\\m = 46.085 \ kg\)
The upward force that must be provided by the 3 people to support the metal plate is calculated as follows;
\(F_n = mg\\\\F_n = 46.085 \times 9.8\\\\F_n = 451.633 \ N\)
The upward force exerted by the hand of each person to support the metal plate is calculated as follows;
\(F_1 = F_2 = F_3 = \frac{F_n}{3} = \frac{451.633}{3} = 150.54 \ N\).
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A gas at 300 kPa, is in a sealed container of volume 100 cm3 at 30°C. If the container is heated to 100°C, what is pressure of the gas inside the container?
Answers
Given:
Pressure, P = 300 kPa
Volume, V = 100 cm³
Temperature, T = 30°C
Let's fin the pressure of the gas inside the container if it is heated to 100°C.
Apply the Gay-Lussac's law:
\(\frac{P_1}{T_1}=\frac{P_2}{T_2}\)Where:
P1 = 300 kPa
T1 = 30 + 273 = 303 K
T2 = 100 + 273 = 373 K
V1 = V2 (since the container is sealed).
Let's solve for P2.
Rewrite the formula for P2:
\(\begin{gathered} P_2=\frac{P_1T_2}{T_1} \\ \\ P_2=\frac{300*373}{303} \\ \\ P_2=\frac{111900}{303} \\ \\ P_2=369.31\text{ kPa} \end{gathered}\)Therefore, the pressure if the container is heated to 100°C is 369.31 kPa.
ANSWER:
369.31 kPa
Phys-1A Horizontal Practice 2
Ground-to-Ground Equations
Horizontal Equations
Vicos
Vertical Equations
sin
ay earth).-9.8 m/s
Horizontal Launch Equations
Horizontal Equations
Vertical Equational
Velocity-as-Hits:
wv * , te
Use. Pythagorean Range
and tan (9)
Show work/use units !!
1. For each problem, solve for "?" and "?", and Velocity-as-it-Mits. Circle your final answers with units.
2.26, 226, 24.3 65.7
Vf, V+ay.t
wh25
V4.0
(Pythag. +
7+17,
tan
Velocity-as-Hits -
2. For each problem, solve for "7" and "?", and Velocity-as-it-Hits Circle your final answers with units.
2.02,742, 21.1 69.5
W.77
VF, VI+ ayt
VF,
Mercede
(Pythag.+ v
tan
Velocity-as-Hits -
Answers
Sphere B of charge +8q is at a distance a to the left of sphere A, and sphere C of charge +2q is to the right of sphere A.
What must be the distance from sphere A to sphere C on the right such that the original small sphere remains at rest?
Answers
Answer:
The distance from sphere A to sphere C on the right such that the original small sphere remains at rest is a/2
Explanation:
The force of a charge at a point is given as follows;
From an online source, we have;
E₁ + E₂ = 0
The electric field due to the sphere B of charge +8q = E₁
\(E_1 = \dfrac{k \cdot (8 \cdot Q)}{a^2}\)
The position of the sphere B = A distance 'a' to the left of 'A'
The electric field due to the sphere C of charge +2q = E₂
The position of the sphere C = A distance to the right of 'A'
Therefore, for the electric field strength of sphere 'B' at 'A', we have;
\(E_1 = \dfrac{k \cdot (8 \cdot Q)}{a^2} = 4 \times \dfrac{k \cdot (2 \cdot Q)}{a^2}\)
Let 'x' be the distance of the +2q charge to the right of 'A', we have;
\(E_2 = \dfrac{k \cdot (2 \cdot Q)}{x^2}\)
Therefore, for the force of the +2q charge to balance the +8q charge at C, we have;
\(\dfrac{k \cdot (2 \cdot Q)}{x^2} = \dfrac{k \cdot (8 \cdot Q)}{a^2} = 4 \times \dfrac{k \cdot (2 \cdot Q)}{a^2}\)
\(\therefore \ \dfrac{1}{x^2} = \dfrac{4}{a^2}\)
\(\therefore \ \sqrt{ \dfrac{1}{x^2} }= \sqrt{\dfrac{4}{a^2}}\)
\(\dfrac{1}{x} = \dfrac{2}{a}\)
\(x= \dfrac{a}{2}\)
Therefore, the distance, 'x', from sphere A to sphere C on the right such that the original small sphere remains at rest is x = a/2.
What forces act to pull the poles of a magnet together, or to push them apart?
Answers
Answer:
Gravity,
I hope this correct
a car travels at 90 km per hour how much distance in metre does the car travel in 25 seconds
Answers
Answer:
90000m÷3600s=25m25m×25s=625msa system gains heat from the surroundings and has work done on it by the surroundings. what are the signs of qsystem and wsystem?
Answers
Since heat is gained here, Q is positive. Since work is done on system, W is positive.
Weathered rocks and soil are moved by _____?
A. Weathering
B. erosion
C. cycles
D. deposition
Answers
Answer:
The correct answer is B
draw a figure of a simple pendulum explain its amplitude and effective length ?
Answers
Answer:
Explanation:
A simple pendulum consists of a mass (usually represented as a small object or bob) attached to a string or rod of negligible mass. The mass is free to swing back and forth under the influence of gravity.
In the figure, the point of suspension is denoted by "O," and the mass (bob) is represented by the small circle. The string or rod is represented by the vertical line connecting the point of suspension to the bob.
Amplitude:
The amplitude of a pendulum refers to the maximum displacement or swing of the bob from its equilibrium position. In the figure, the amplitude can be represented by the angle formed between the vertical position and the position of the bob when it swings to its maximum distance on one side. It is usually denoted by the symbol "A."
Effective Length:
The effective length of a pendulum refers to the distance from the point of suspension to the center of mass of the bob. It represents the distance over which the mass swings back and forth. In the figure, the effective length can be measured as the length of the string or rod from the point of suspension to the center of the bob. It is usually denoted by the symbol "L."
It is important to note that the amplitude and effective length of a simple pendulum affect its period of oscillation (the time taken for one complete swing). The relationship between these parameters and the period can be described by mathematical formulas.
Overall, the simple pendulum is a fundamental concept in physics and provides a simplified model for understanding oscillatory motion and the principles of periodic motion.
An ant clings to the outside edge of the tire of an exercise bicycle. When you start pedaling, the ant's speed increases from zero to 12 m/s in3. 3 s. The wheel's rotational acceleration is11 rad/s2.
1: Determine the average tangential acceleration of the tire.
2: Determine the radius of the tire.
3: Determine the angle the ant has turned during this time interval.
4: Determine the distance the ant has traveled along the arc during this time interval
Answers
1: Average tangential acceleration = (12 m/s - 0 m/s) / 3.3 s ≈ 3.64 m/s²
2: radius = 3.64 m/s² / 11 rad/s² ≈ 0.331 m
3: θ = 0.5 * 11 rad/s² * (3.3 s)² ≈ 59.67 radians
4: The ant has traveled approximately 19.78 meters along the arc of the tire during the given time interval.
1: The average tangential acceleration of the tire can be determined using the formula:
Average tangential acceleration = (final tangential velocity - initial tangential velocity) / time
Given that the ant's speed increases from zero to 12 m/s in 3.3 seconds, the initial tangential velocity is 0 m/s and the final tangential velocity is 12 m/s. Plugging these values into the formula, we get:
Average tangential acceleration = (12 m/s - 0 m/s) / 3.3 s ≈ 3.64 m/s²
2: The radius of the tire can be determined using the formula:
Average tangential acceleration = rotational acceleration * radius
Given that the rotational acceleration of the wheel is 11 rad/s² and the average tangential acceleration is 3.64 m/s², we can rearrange the formula to solve for the radius:
radius = average tangential acceleration / rotational acceleration
Plugging in the values, we get:
radius = 3.64 m/s² / 11 rad/s² ≈ 0.331 m
3: The angle the ant has turned during this time interval can be calculated using the formula:
θ = 0.5 * rotational acceleration * (time)²
Plugging in the given values, we get:
θ = 0.5 * 11 rad/s² * (3.3 s)² ≈ 59.67 radians
4: The distance the ant has traveled along the arc during this time interval can be calculated using the formula:
Distance = radius * θ
Plugging in the values, we get:
Distance = 0.331 m * 59.67 radians ≈ 19.78 meters
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Una bola de 1 kg gira alrededor de un circulovrtical en el extremo de un cuerda. El otro extremo de la cuerda esta fijo en el centro del circulo. Calcular la diferencia entre las tensiones (de la cuerda) maxima y minima
Answers
Answer:
La diferencia entre las tensiones máxima y mínima es de 19.614 newtons.
Explanation:
Puesto que la bola gira en un círculo vertical, existe claramente una diferencia entre las tensiones debido a la influencia de la gravedad y la tensión que resulta de la aceleración centrípeta experimentada por la masa. La máxima tensión ocurre cuando la bola se encuentra en el nadir (o la sima) del trayecto circular, la cual se describe por la Segunda Ley de Newton:
\(T_{max} - m\cdot g = m\cdot \frac{v^{2}}{L}\)
En cambio, la mínima tensión aparece cuando la bola se encuentra en el cénit (o la cima) del trayecto circular, descrita por la misma ley de Newton:
\(T_{min} + m\cdot g = m\cdot \frac{v^{2}}{L}\)
Donde:
\(T_{min}\), \(T_{max}\) - Tensiones mínima y máxima, medidas en newtons.
\(m\) - Masa de la bola, medida en kilogramos.
\(g\) - Constante gravitacional, medida en metros por segundo al cuadrado.
\(L\) - Distancia con respecto al eje de rotación, medida en metros.
\(v\) - Rapidez tangencial, medido en metros por segundo.
Se elimina la aceleración centrípeta de ambas expresiones por igualación:
\(T_{min} + m\cdot g = T_{max} - m\cdot g\)
Ahora, la diferencia entre las tensiones máxima y mínima es:
\(T_{max} - T_{min} = 2\cdot m \cdot g\)
Si \(m = 1\,kg\) y \(g = 9.807\,\frac{m}{s^{2}}\), entonces:
\(T_{max} - T_{min} = 2\cdot (1\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\)
\(T_{max}-T_{min} = 19.614\,N\)
La diferencia entre las tensiones máxima y mínima es de 19.614 newtons.
A poker is a long thin tool used to move pieces of coal or logs burning in a fire. To be as safe as possible, the poker should be made from a material that
Answers
Answer:
See the answer below
Explanation:
A poker that will effectively and safely function to move pieces of coal or logs in a burning fire must be fireproof itself. Hence, to be as safe as possible, such poker should be made from a material that is fireproof and that does not conduct a lot of heat. Otherwise, the poker will catch fire/becomes too hot during the course of usage.
1) A tourist accidentally drops a camera from a 50.0 m high bridge. What is the speed of the camera as it hits the water? *
2) Determine the total displacement of a car that is initially at 10 m/s but then accelerates at 2 m/s^2 for five seconds. *
3) A car travels down a long straight road at 20 km/h for 0.60 h. How far does the car travel during this interval? *
4) A skateboarder slides down a ramp starting from rest and moving to 10 m/s in 12 seconds. How far will the skater travel during this time interval?
5) A runner travels south along a straight path for 5.5 h with an average velocity of 1.75 km/h, then travels south for 7.5 h with an average velocity of 0.90 km/h. What is the hiker’s displacement for the total trip? *
6) A runner accelerates from rest for 3.2 seconds. If the runner travels 24.6m, what is the runner's acceleration? *
7) A car moving at 5 m/s accelerates at 0.2 m/s^2 for one minute. How fast is the car moving? *
Can someone please answer these questions for me :))
Answers
Question:
1) A tourist accidentally drops a camera from a 50.0 m high bridge. What is the speed of the camera as it hits the water? *
Answer:
28.0 m/s
Rhodes research indicates that people are generally accurate in guessing the ages of unfamiliar persons based on their faces. This research has important implications for
Answers
The available options are:
A. bartenders serving alcohol
B. students identifying their professors.
C. Doctors diagnosing cases of schizophrenia.
D. eyewitnesses identifying suspects from a lineup.
Answer:
A. bartenders serving alcohol
Explanation:
This is because of the underage rule concerning sale of alcohol. Thus, there are occasional period in which underage person or a minor will want to buy alcohol, and without necessarily asking for the birth certificate or ID card that contains Age information, it is therefore, necessary for bartenders to be able to tell the age of their unfamiliar customers, by mere looking at them, so as not to sell to a minor.
Hemce, Rhodes research in guessing the age of unfamiliar person has important implications for BARTENDERS SERVING ALCOHOL, because it will guide them to determine Underage or Minor, that want to buy alcohol from them.
How do you find the image size in a concave mirror?
Answers
The concave mirror is represented by a vertical line MMl. The principal axis is represented by a horizontal line drawn on the PC. 1 mm. 12 mm (focal length: 12 cm); I Image position.
Here, u = 25 cm for the object distance (To the left of the mirror)
Also, the focal length is f = 20 cm (It is a concave mirror)
What is the size of the image in a concave mirror?
The size of image formed by a concave mirror is same as the size of object.
Use the magnification of a mirror formula to obtain the size of the object. Accordingly depict its nature using the sign of the image height. Where v is the image distance u is the object distance and f is the focal length.
However, if we increase the distance between the object and the mirror then the size of the image reduces and a real and inverted image is formed. The image formed by the concave mirror can be small or large and can be real or virtual.
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The concave mirror is represented by a vertical line MMl. The principal axis is represented by a horizontal line drawn on the PC. 1 mm. 12 mm (focal length: 12 cm); I Image position.
Here, u = 25 cm for the object distance (To the left of the mirror)
Also, the focal length is f = 20 cm (It is a concave mirror)
What is the size of the image in a concave mirror?
The size of image formed by a concave mirror is same as the size of object.
Use the magnification of a mirror formula to obtain the size of the object. Accordingly depict its nature using the sign of the image height. Where v is the image distance u is the object distance and f is the focal length.
However, if we increase the distance between the object and the mirror then the size of the image reduces and a real and inverted image is formed. The image formed by the concave mirror can be small or large and can be real or virtual.
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Simple BJT OP Amp 1. DC Analysis 1. Find current values of \( I_{A 1}, I_{A C 2}, I_{A C 2}, I_{A 2}, I_{A 3}, I_{R 4}, I_{A S}, I_{R G} \) and \( I_{R 7} \). 2. Find voltage values at \( v_{\text {ou
Answers
BJT stands for Bipolar Junction Transistor, and the OP-Amp is the abbreviation of the Operational Amplifier. An OP-Amp circuit consists of various resistors, capacitors, transistors, and voltage sources. The OP-Amp symbol indicates that the input and output signals are AC-coupled.
DC Analysis
The DC analysis of the circuit is very simple and straightforward. We will consider that the capacitors are short circuits because they do not allow DC signals to pass through them. As a result, the voltage values at the terminals of the capacitors are 0V in a DC analysis. Moreover, the current value is the same throughout the series of resistors.
Current Values:
The current flowing through the resistors in the circuit can be calculated using Ohm's law, which is V = IR, where V is the voltage, I is the current, and R is the resistance. In the given circuit, the currents can be calculated as follows:
The current through resistor R1 = (9-0.7) / 2200 = 3.53 mA
The current through resistor R2 = (9-0.7) / 2200 = 3.53 mA
The current through resistor R3 = (9-0.7) / 2200 = 3.53 mA
The current through resistor R4 = (9-0.7) / 2200 = 3.53 mA
The current through resistor R5 = (9-0.7) / 2200 = 3.53 mA
The current through resistor R6 = (9-0.7) / 2200 = 3.53 mA
The current through resistor R7 = (9-0.7) / 1000 = 8.3 mA
The current through resistor RE = (0.7-0.7) / 220 = 0 mA
The current through resistor RG = (5-0) / 1000000 = 5 uA
The current through transistor Q1 = (3.53 - 0) = 3.53 mA
The current through transistor Q2 = (3.53 - 0) = 3.53 mA
Voltage Values:
The voltage values of the circuit can be determined by using Kirchhoff's Voltage Law (KVL), which states that the sum of the voltages around any closed loop is zero. Therefore, we can calculate the voltage values as follows:
The voltage across resistor R4 is V(R4) = 3.53 * 2.2k = 7.766V
The voltage across resistor R5 is V(R5) = 3.53 * 2.2k = 7.766V
The voltage across resistor R6 is V(R6) = 3.53 * 2.2k = 7.766V
The voltage across transistor Q1 is V(Q1) = 0.7V
The voltage across transistor Q2 is V(Q2) = 0.7V
The voltage at the output terminal is V(OUT) = V(R5) - V(R6) = 0V
Therefore, the current values are:
\(I_{A 1}, I_{A C 2}, I_{A C 2}, I_{A 2}, I_{A 3}, I_{R 4}, I_{A S}, I_{R G}\) and \(I_{R 7}\) 3.53mA, 3.53mA, 3.53mA, 3.53mA, 3.53mA, 8.3mA, 0mA, 5μA, 8.3mA respectively.
The voltage values are:
V(R4) = 7.766V, V(R5) = 7.766V, V(R6) = 7.766V, V(Q1) = 0.7V, V(Q2) = 0.7V, V(OUT) = 0V.
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What information is given on the X-axis of the graph below?
answers:
there is no x axis
years from 1920-2005
co2 concentration
the name of the observatory
Answers
The information given on the X-axis of the graph attached is the years from 1920-2005 (option B).
What is a graph?A graph in mathematics or statistics is a data chart (graphical representation of data) intended to illustrate the relationship between a set (or sets) of numbers (quantities, measurements or indicative numbers) and a reference set.
A graph consists of two axes namely; X-axis and Y-axis. The x-axis on a graph is usually drawn left to right and usually shows the range of values of an independent variable.
On the other hand, the Y-axis is the axis on a graph that is usually drawn from bottom to top and usually shows the range of values of variable dependent on one other variable.
Therefore, according to the graph illustrated above, the x-axis shows the years from 1920-2005.
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Amir bought a lamp with a design attached to it that casts a shadow when the lamp is lit, as shown below. He wants to carryout an experiment using this lamp to find out the factors that effect the size of the shadow.
The effect of which factors can he actually find out using only this lamp?
Answers
The effect of the factors which he can he actually find out using only this lamp to determine the size of shadow is the light intensity and type of object.
What is Experiment?
This forms part of the scientific methods and is referred to as a procedure which is used to support or refute an hypothesis.
The size of the shadow is dependent on factors such as the light intensity and the type of object. Since the lamp produces the light in which the intensity can be gotten and the type of material it is in contact with then it therefore the correct choices.
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A train decelerates uniformly at a rate of 2 m/s2 and comes to a stop in 10 seconds. Find the initial velocity of the train.
Answers
The initial velocity of the train is 20m/s when the train decelerates uniformly at a rate of 2m/s2. It means that initially, at time = 0 seconds, the train was moving with a velocity of 20m/s.
We know that,
v = u +at
where, v = final velocity
u = initial velocity
a = acceleration
t = time taken
In this case, as the train is decelerating we will use a negative sign with acceleration.
Substituting the values we get,
v = u + (-2)(10)
v will be equal to zero, as the train comes to a stop.
0 = u - 20
u = 20 m/s
Hence, the initial velocity of the train is 20m/s when the train decelerates uniformly at a rate of 2m/s2 and comes to a stop in 10 seconds.
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mass = 28g
volume=?
density= 13 g/ml
Answers
Answer:
2.15ml
Explanation:
The formula for density is D = m/v
Since we already have density and mass, we need to rearrange the equation to find the volume.
The rearranged formula is V = m/D
V = 28g/13g/ml
The volume is 2.15ml
you have to go to a planet which is 16.4 au away, traveling at 231000 km/h. how many days does i take you?
Answers
It would take you approximately 442.50 days to travel to a planet that is 16.4 AU away at a speed of 231,000 km/h.
To calculate the time it takes to travel to a planet 16.4 astronomical units (AU) away at a speed of 231,000 km/h, follow these steps:
1. Convert the distance from astronomical units to kilometers:
1 AU is equal to approximately 149,597,870.7 km. So, 16.4 AU would be:
16.4 AU * 149,597,870.7 km/AU ≈ 2,453,405,078 km.
2. Calculate the time taken to travel this distance at a speed of 231,000 km/h:
Time = Distance / Speed
Time = 2,453,405,078 km / 231,000 km/h ≈ 10,619.93 hours.
3. Convert the time from hours to days:
There are 24 hours in a day.
So, to convert the time to days, divide the number of hours by 24:
10,619.93 hours / 24 hours/day ≈ 442.50 days.
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Can you determine the general relationship between the work done by the spring on the cart to the velocity of the cart?
Answers
The work done by the spring on the cart is directly related to the velocity of the cart, with an increase in work resulting in an increase in velocity, assuming constant mass and displacement.
Yes, there is a general relationship between the work done by the spring on the cart and the velocity of the cart. The work done by the spring on the cart can be related to the change in kinetic energy of the cart.
The work-energy principle states that the work done on an object is equal to the change in its kinetic energy. In the case of a spring, if it is compressed or stretched and then released, it can exert a force on the cart, doing work on it.
The work done by the spring on the cart is given by:
Work = (1/2) k x²
- k is the spring constant, which measures the stiffness of the spring.
- x is the displacement of the spring from its equilibrium position.
According to the work-energy principle, this work done by the spring is equal to the change in kinetic energy of the cart:
Work = (1/2) m v²
Where:
- m is the mass of the cart.
- v is the velocity of the cart.
Equating these two expressions, we have:
(1/2) k x² = (1/2) m v²
This equation shows the relationship between the work done by the spring and the velocity of the cart. It indicates that as the work done by the spring increases, the velocity of the cart also increases, provided that the mass and displacement remain constant.
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A car starts at rest and accelerates at a rate of 4 m/s^2. How far does the car travel in 5
seconds? Why?
A) 10 m
B) 20 m
C) 50 m
D) 100m
Answers
Answer:
C. 50m
Explanation:
Given parameters:
Initial velocity = 0m/s
Acceleration = 4m/s²
Time of travel = 5s
Unknown:
distance covered = ?
Solution:
To solve this problem, we use the expression below;
S = ut + \(\frac{1}{2}\) at²
S is the distance
u is the initial speed
t is the time
a is the acceleration
S = (0x 5) + \(\frac{1}{2}\) x 4 x 5² = 50m