What are the colors that have lower energy than the color blue

Answer:

Force and Motion - Word ACROBAT w otion" Applied Force O Newtons DD -500 500 Net Force Motion Friction Acceleration I

2. Select the checkboxes: Forces, Values, Masses and Speed Force Values Masses Speed 3. Push the skateboard and the box with a force of 500N. Observe and describ behavior of the velocity once the skateboard is released Explain the reason of such behavior Part III. Friction 1. Click on "Friction" 2. Select the checkboxes: Forces, Sum of Forces, Values, Masses and Speed. Kee the knob that regulates the friction at the center of the scale. Forces Sum of Forces Values Masses

3. Start to push the box, increasing the force applied on the box slowly. There is a force that is opposite to the force you are applying. What is the name of the force opposing to the motion? 4. Once the box start moving, the magnitude of the resultant force increase instantaneously. How do you explain that? 5. Push the box and find the force needed to make the box to start moving. Add more mass (box, kid, man,refrigerator, basket as needed) and repeat the procedure such that you complete the table below. Hint: Weight = mass x gravity Magnitude of Normal Force = Magnitude of the Weight Mass (kg) Weight (N) Normal Force (N) Force of Static Friction (N) 50 90 130 150 180 x 0 N

Explanation:

The forces act on skateboard when we push it are , external force of 500N and friction force because of the surface.

The stationary object will remain stationary or the subject in the motion will keep its motion until or unless the external force is not applied .

So, by the Newton's first law of motion we can understand this concept.

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Answer:

90m

Explanation:

Given that an arrow is shot horizontally from a height of 4.9 m above the ground. The initial speed of the arrow is 45 m/s.

Since the arrow is shot horizontally, the initial vertical velocity will be equal to zero.

Using the second equation of motion,

h = Ut + 1/2gt^2

substitute h = 4.9m and g into the formula

4.9 = 1/2 × 9.8 × t^2

4.9 = 4.9t^2

t^2 = 4.9/ 4.9

t = 1

For horizontal motion g = 0 and the total time T = 2t

T = 2 × 1

T = 2

Substitute T and U into the equation

R = UT

R = 45 × 2

R = 90m

Therefore, the arrow will hit the ground 90m away from the archer.

Answer: 45 meters.

Explanation:

First, let's calculate the time that the arrow needs to hit the ground.

Let's analyze the vertical axis.

The only force acting on the arrow is the gravitational force, then the only acceleration will be the gravitational acceleration.

We can write this as:

a(t) = -g

where  = 9.8m/s^2

For the vertical velocity, we can integrate the above equation over the time:

v(t) = -g*t + v0

where t is our variable, the time in seconds, and v0 is the initial vertical velocity.

But we know that the arrow is shot horizontally, then we don't have initial vertical velocity: v0 = 0m/s.

v(t) = -g*t

and the vertical position can be obtained integrating again.

p(t) = -0.5*g*t^2 + p0

Where p0 is the initial position, we know that this is 4.9 meters, then the position equation is:

p(t) = -0.5*9.8m/s^2*t^2 + 4.9m

Now we want to find the value of t where the position is equal to zero, this will be the time that the arrow needs to hit the ground.

0 = -0.5*9.8m/s^2*t^2 + 4.9m

t^2 = 4.9/(0.5*9.8) s^2

t = √( 4.9/(0.5*9.8) s^2 ) = 1s

Now let's analyze the horizontal case.

As we can neglect the air resistance, the horizontal velocity is constant:

v(t) = 45m/s

And the position will be:

V(t) = 45m/s*t + p0

Where in this case p0 is the position of the archer, that we can define as our zero in this axis, then p0 = 0m

Now we know that the vertical displacement of the arrow when it hits the ground will be:

p(1s) = 45m/s*1s = 45m

The time it takes for the car to fall from a certain height would not be affected by the time it takes for the ball to fall, even if the car's velocity were doubled.

If the car's velocity were doubled, the time it takes for the car to fall would not be affected by the time it takes for the ball to fall. This is because the time taken for an object to fall from a certain height is determined by the acceleration due to gravity and the distance from the ground, but not by the object's initial velocity.

The acceleration due to gravity is constant, which means that the time taken for an object to fall a certain distance is also constant. This means that the time taken for the ball to fall and the car to fall from the same height would be the same, regardless of the car's velocity.

This can be explained by the equation of motion for a falling object:

d = 1/2gt²,

where d is the distance from the ground, g is the acceleration due to gravity, and t is the time taken to fall.

Since the acceleration due to gravity is constant, the time taken for the car and the ball to fall the same distance would be the same, regardless of their initial velocity.

Therefore, if the car's velocity were doubled, the time it takes for the car to fall would be the same as before, but it would be moving faster when it hits the ground.

In conclusion, the time it takes for the car to fall from a certain height would not be affected by the time it takes for the ball to fall, even if the car's velocity were doubled.

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If the work required to speed a car up from 10km/h to 20km/h is 5.0 x 10^3 J, the work required to increase the cars speed from 20km/h to 30km/h is: 8.33 × 10³J.

Using this formula to determine the   work required to increase the cars speed from 20km/h to 30km/h

\(Wii = Wi (V^2_2- V^2_1) /v^2_2 - v^2_1\)

Let plug in the formula

Work required = (5 × 10³) (30² -20²) / (20² -10²)

Work required = (5 × 10³)  ( 900 - 400) /(400  - 100)

Work required = (5 × 10³) ( 500) / 300

Work required = 8.33 × 10³J

Therefore the Work required is 8.33 × 10³J.

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Answer:

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

GPE = 60 × 10 × 75

We have the final answer as

Hope this helps you

Answer:

3.125×10²¹ N/C

Explanation:

Electric Field: This can be defined as the force experienced per unit charge. The S.I unit of electric Field is N/C

Applying,

E = F/q.................. Equation 1

Where E = Electric Field, F = Force experienced, q = Charge of an electron.

From the question,

Given: F = 500 N, q = 1.6×10⁻¹⁹ C

Substitute these values into equation 1

E = 500/(1.6×10⁻¹⁹)

E = 312.5×10¹⁹

E = 3.125×10²¹ N/C

The force acts for approximately 1.14 seconds.

A. The ball's change in momentum can be calculated using the formula:

Δp = m * Δv

where Δp is the change in momentum, m is the mass of the ball, and Δv is the change in velocity. Here, the ball starts from rest, so its initial velocity is 0 m/s, and it reaches a final velocity of 10 m/s. Therefore, the change in velocity is:

Δv = 10 m/s - 0 m/s = 10 m/s

Substituting the values, we get:

Δp = 4 kg * 10 m/s = 40 kg·m/s

So, the ball's change in momentum is 40 kg·m/s.

B. The impulse can be calculated using the formula:

J = Δp

where J is the impulse and Δp is the change in momentum. Substituting the value of Δp from part (A), we get:

J = 40 kg·m/s

So, the impulse is 40 kg·m/s.

C. The time for which the force acts can be calculated using the formula:

J = F * t

where J is the impulse, F is the force applied, and t is the time for which the force acts. Substituting the values of J and F, we get:

40 kg·m/s = 35 N * t

Solving for t, we get:

t = 40 kg·m/s / 35 N ≈ 1.14 s

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There are 4 data streams are used in 802.11ac wave 2 devices.

The 802.11ac standard specifies a theoretical maximum connection speed of up to 7 Gbit/s. By increasing the channel width to 80 MHz, increasing the spatial streams, and supporting the new 256-QAM modulation, we were able to significantly increase the data transmission rate. However, the Wave 2 standard could open the door to Gigabit WiFi.

The physical PHY rate impacts the data transfer throughput rate, which is much higher in wave 2. Wave 1 PHY rate max reaches 1.3Gbps, and Wave 2 reaches 2.34Gbps. 802.11n and 802.11ac technologies support multiple antennas. 2x2 or 4x2 in the specification means 2 transmit antennas and 2 receive antennas or 4 transmit antennas and 2 receive antennas. See Wi-Fi, 802.11, wireless routers, and dual-band routers for more information.

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\(\bold{Heya~!}\)

Space X is that designs, and also. that manufactures and launches the world's most advanced rocket ships, and spacecraft. And the company was that founded in 2002,  by "Elon Musk."

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When the gold cube is immersed in mercury, the tension in the string in Newtons is 3.142N.

Tension is the force acting on the linear object like string, chain or rope due to pulling.

Volume of gold V = mass / density

V = 1.18 /19.3x 10³ =61.1 x 10⁻⁶ m³

Tension in the string after immersing will be

T = [ρ(Gold)  -ρ(Hg)] g. V

T =[ 19.3x 10³ - 13.6 x 10³] x 9.81 x 61.1 x 10⁻⁶

T =3.416 N
Thus, the tension in the string is 3.42 N.

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According to the given statement the number x is 2. The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

The equation given is:

Volume per second = k * (p * a) / n

Where:
- k is a constant
- p is the excess pressure (force per unit area)
- a is the radius of the pipe
- n is the frictional quantity of dimension MLT⁻¹


To find the number x, we need to determine the dimensions of each term in the equation.

1. Dimension of Volume per second:

  - Volume has the dimension L³ (length cubed)
  - Time has the dimension T (time)
  - Therefore, Volume per second has the dimension L³  / T

2. Dimension of k:

  - The equation states that k is a constant. Constants are dimensionless.

3. Dimension of p * a:

  - Pressure has the dimension M / (L * T² ) (mass divided by length and time squared)
  - Radius has the dimension L (length)
  - Multiplying pressure by radius results in the dimension M / (L * T² ) * L = M / (L²  * T² )

4. Dimension of n:

  - Given in the question, n has the dimension MLT⁻¹
(mass times length times time to the power of -1)

Now, we can equate the dimensions:

L³  / T = k * (M / (L²  * T² )) * MLT⁻¹


Simplifying the dimensions:

L³  / T = k * M / (L²  * T² ) * MLT⁻¹


L³  / T = k * M / L²  * M / T²  * L^-1 * T⁻¹


L³  / T = k * M²  / L²  * T⁻¹


To equate the dimensions, both sides of the equation must have the same dimensions. Therefore:

L³ / T = k * M² / L² * T⁻¹


Comparing the dimensions on both sides, we can conclude:

L³ / T = k * M² / L²* T⁻¹

The dimensions on the left side are L^3 / T, and the dimensions on the right side are (k * M²) / (L² * T).

Therefore, the number x is 2.

The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

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Answer:

f = 23.64 Hz

Explanation:

From the wave equation, the relationship between frequency and wavelength is given by;

f = cλ

Where;

λ is wavelength

c is speed of light with a constant value of 3 × 10^(8) m/s

f is frequency

We are given wavelength of 7.88 x 10^(-8) m

Thus;

f = 7.88 x 10^(-8) × 3 × 10^(8)

f = 23.64 Hz

Answer: it is located over Ellesmere Island, Canada

Explanation

it is now drifting away from North America and toward Siberia.

Answer:ellesmere island, Canada

To learn the equilibrium and temperature.

What is equilibrium?

When Newton's first law is true, the equilibrium state of an object is present. When all external forces (including moments) operating on an object in a reference coordinate system are equal, the object is said to be in equilibrium. The net effect of all external forces and moments acting on this object is zero as a result.

What is temperatue?

Temperature is a unit of measurement that can be expressed on a variety of scales, including Fahrenheit and Celsius. Temperature shows the direction of the spontaneous movement of heat energy, i.e., from a hotter body (one with a higher temperature) to a colder body (one with a lower temperature).

Their temperatures must be equal if two bodies are in thermal equilibrium.

As for coldness or warmth, we generally observe that metals feel colder while non metallic objects don't (i.e. comparatively they feel warmer than metals). This is due to the fact that metals are good conductor of heat. So when we touch a metallic body, heat flows from our body and is transferred to other points of the metal object. Since our body loses heat, we feel cold. In non metals, this conduction of heat from point of contact to other locations does not happen.

Therefore, the amount of heat loss from our body is much smaller. So we don't feel that cold.

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Some underwater earthquakes shake the ocean floor and cause large sea waves that destroy property and threaten lives. Such a sea wave is called a "tsunami."

Tsunamis are incredibly powerful and can travel great distances at high speeds. They are caused by the displacement of a large amount of water, usually due to an earthquake, but can also be caused by volcanic eruptions or landslides. Tsunamis can travel across entire ocean basins and can reach speeds of up to 800 kilometers per hour, but they are usually imperceptible in deep water. As the waves approach the shore, their height increases and they can cause devastating damage to coastal communities and infrastructure. Tsunamis can cause widespread destruction and loss of life and are major natural disasters that can affect coastal communities around the world.

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Answer:

Net force = 509.90 N

Explanation:

Given that,

Force exerted by wind is 500 N South on a sailboat.

The force exerted by water is 100 N on the sailboat.

Two forces are acting at an angle of 90 degrees. We can find the net force acting on the sailboat. Let it is F.

\(F=\sqrt{500^2+100^2} \\\\=509.90\ N\)

So, the net force on the sailboat is 509.90 N.

Answer:

Astronauts who are orbiting the Earth often experience sensations of weightlessness. These sensations experienced by orbiting astronauts are the same sensations experienced by anyone who has been temporarily suspended above the seat on an amusement park ride. Not only are the sensations the same (for astronauts and roller coaster riders), but the causes of those sensations of weightlessness are also the same. Unfortunately however, many people have difficulty understanding the causes of weightlessness.

Answer:

The answer is below

Explanation:

Charlee's law states that the volume of a gas is directly proportion to the temperature of the gas at constant pressure. That is:

V = kT, where V = volume and T = temperature, k = constant. Therefore:

V / T = k

\(\frac{V_1}{T_1}=\frac{V_2}{T_2}\)

Given that: \(V_1=3\ m^3, T_1=20^oC=(20 + 273)K=293\ k,T_2=60^oC=(60 + 273)K=333\ k.\\\\\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\\\frac{3}{293}=\frac{V_2}{333} \\\\V_2=\frac{3}{293}*333\\\\V_2=3.41\ m^3\\\)

The new volume is 3.41 m³. That is it expands by 0.41 m³

Answer:

0.02484

Explanation:

Trust me bro

Answer:

television

Explanation:

a television refracts light (the light bounces off of the screen

Answer:

Suppose you have a glass slab as a paper weight, if you keep it on the paper, dont you see something strange? The paper becomes elevated in the glase slab. Everyone sees a waterbottle or glass everyday, while seeing through it, does everything seem normal? Nope. That's refraction.

Explanation:

You must have seen a prism, right? It makes light split into the visible electromagnetic spectrum.

1. Ta is the air temperature measured using the dry bulb thermometer. 2. Tw is the wet bulb temperature measured using the wet bulb thermometer. 3. Ta - Tw is the wet-bulb depression. 4. RH is the relative humidity percentage obtained from Table i. Toow is the dew point temperature obtained from Table 2.

To determine the air temperature (Ta), wet bulb temperature (Tw), relative humidity (RH), and dew point temperature (Toow), you will need to refer to the Sling Psychrometer Experiment document and the psychometric tables.

1. Start by using the Sling Psychrometer Experiment document to measure the air temperature (Ta) and the wet bulb temperature (Tw). These measurements can be obtained using a sling psychrometer, which consists of two thermometers - a dry bulb and a wet bulb. The dry bulb thermometer measures the air temperature (Ta), while the wet bulb thermometer measures the wet bulb temperature (Tw).

2. Once you have obtained the values for Ta and Tw, calculate the wet-bulb depression by subtracting Tw from Ta. This will give you the difference between the two temperatures, which is an important factor in determining relative humidity.

3. To determine the relative humidity (RH), refer to the psychometric tables found in the Lab Document. Table i is used to find the relative humidity (RH) corresponding to the wet-bulb depression. Locate the wet-bulb depression value on Table i and read the corresponding relative humidity percentage (RH).

4. Finally, to determine the dew point temperature (Toow), refer to Table 2 in the psychometric tables. Locate the relative humidity (RH) percentage from step 3 on Table 2 and read the corresponding dew point temperature (Toow) in degrees Celsius or Fahrenheit.

To summarize:
- Ta is the air temperature measured using the dry bulb thermometer.
- Tw is the wet bulb temperature measured using the wet bulb thermometer.
- Ta - Tw is the wet-bulb depression.
- RH is the relative humidity percentage obtained from Table i.
- Toow is the dew point temperature obtained from Table 2.

By following these steps and referring to the appropriate documents and tables, you can accurately determine the air temperature, wet bulb temperature, relative humidity, and dew point temperature. Remember to use the correct values and units from the experiment to ensure accurate calculations.

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Expressing the answer in three significant figures separated by a comma, we get: F⃗ _3 = (-7.99, -6.00) N = (-10.00 N, -38.88°) using newton second law.

To find the third force, we can use Newton's second law, which states that the net force on an object is equal to its mass times its acceleration:

F⃗ _net = m⃗ a⃗

where F⃗ _net is the vector sum of all the forces acting on the object.

We can start by finding the vector sum of F⃗ _1 and F⃗ _2:

F⃗ _1 + F⃗ _2 = (3.06 N)x^ + (-1.62 N)x^ + (1.73 N)y^

= (1.44 N)x^ + (1.73 N)y^

Now, we can find the net force by subtracting the vector sum of F⃗ _1 and F⃗ _2 from the mass times acceleration:

F⃗ _3 = m⃗ a⃗ - (F⃗ _1 + F⃗ _2 )

= (6.10 kg)(1.31 m/s^2 x^ - 0.673 m/s^2 y^) - (1.44 N)x^ - (1.73 N)y^

= (7.99 N)x^ - (6.00 N)y^

Therefore, the third force F⃗ _3 has a magnitude of 10.00 N and is directed at an angle of 38.88 degrees below the positive x-axis:

|F⃗ _3| = √[(7.99 N)^2 + (-6.00 N)^2] = 10.00 N

θ = tan⁻¹(-6.00 N / 7.99 N) = -38.88° (measured below the positive x-axis)

Expressing the answer in three significant figures separated by a comma, we get:

F⃗ _3 = (-7.99, -6.00) N = (-10.00 N, -38.88°)

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The girl is at a distance of 2 m from the fulcrum, the father must sit at a distance of 378 cm from the fulcrum. The correct answer is option a. 67 cm from the girl.

To balance the seesaw, the torques on both sides of the fulcrum must be equal:

m₁ * g * d₁ = m₂ * g * d₂

Substituting the given values:

30 kg * 9.8 m/s² * 2 m = 90 kg * 9.8 m/s² * d₂

Simplifying the equation:

588 Nm = 882 Nm * d₂

Dividing both sides by 882 Nm:

d₂ = 588 Nm / 882 Nm = 2/3

Therefore, the father must sit at a distance of 2/3 of the total length of the seesaw. The total length is the sum of the distances of the girl and the father from the fulcrum.

Total length = d₁ + d₂ = 2 m + (2/3) m = 8/3 m = 2.67 m

So, the father must sit at a distance of 2/3 * 2.67 m = 1.78 m = 178 cm from the girl.

Since the girl is at a distance of 2 m from the fulcrum, the father must sit at a distance of 2 m + 1.78 m = 3.78 m = 378 cm from the fulcrum.

Therefore, the correct answer is option a. 67 cm from the girl.

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The separation length of induced dipole is \(E_{net}\) =\(\frac{kq}{d^{2} }\) ( 1 + \(\frac{s}{8d}\) ) leftward.

What is dipole moment?

A charge separation results in dipole moments. Dipole moments are caused by changes in electronegativity and can appear in ionic bonds between two ions or covalent bonds between atoms. The dipole moment increases with increasing electronegativity disparity. Another element affecting the size of the dipole moment is the distance between the charge separations. A molecule's polarity can be determined by its dipole moment.

We have,

Electric field due to dipole = E₂

As negative charge is nearer then the electric field will be toward the dipole.

E₁ = \(\frac{kqs}{r^{3} }\) = \(\frac{kqs}{(2d)^{3} }\) = \(\frac{kqs}{8d^{3} }\)

Now, electric field due to single charge -q = E₂

E₂ = \(\frac{kq}{r^{2} }\) = \(\frac{kq}{d^{2} }\)

\(E_{net}\) = E₁ + E₂ = \(\frac{kq}{d^{2} }\) ( 1 + \(\frac{s}{8d}\))

So, \(E_{net}\) = \(\frac{kq}{d^{2} }\) (1 + \(\frac{s}{8d}\) ) leftward.

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Answer:

While self-gravity pulls the star inward and tries to make it collapse, thermal pressure (heat created by fusion) pushes outward. These two forces cancel each other out in a main sequence star, thus making it stable.

Explanation:

The external force present causes her to slow down and results in a lower velocity of 6.0 m/s after passing the rough ice compared to her initial velocity of 8.0 m/s.

To analyze the situation, we can consider the conservation of momentum. Since there is no external force acting on the system, the momentum before and after the skater hits the rough ice should be the same.

The momentum of the skater can be calculated by multiplying the mass of the skater by the velocity. Let's denote the mass of the skater as m.

Before hitting the rough ice:

Momentum before = mass * velocity = m * 8.0 m/s

After hitting the rough ice:

Momentum after = mass * velocity = m * 6.0 m/s

Since the momentum is conserved, we have:

Momentum before = Momentum after

m * 8.0 m/s = m * 6.0 m/s

We can cancel out the mass (m) on both sides of the equation:

8.0 m/s = 6.0 m/s

Therefore, the equation is not balanced, indicating that the assumption of conservation of momentum does not hold in this scenario.

The discrepancy in momentum conservation suggests that there is an external force acting on the skater when she hits the rough ice. This force causes her to slow down and reduces her momentum, resulting in a lower velocity after passing the rough ice.

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Answer:

Scalar quantities are defined by a magnitude with no applicable direction. In contrast, vector quantities must have both magnitude and direction of action. Some common scalar quantities are distance, speed, mass, and time. Some common vector quantities are force, velocity, displacement, and acceleration.

Explanation:

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Answer:

v = 20.31 m/s

Explanation:

p = mv -> v = p/m = 32,500 kg*m/s / 1,600 kg = 20.31 m/s

To estimate Mercury's daytime temperature, we can use the Stefan-Boltzmann law, which relates the radiated power of a blackbody to its temperature.

According to the problem, Mercury receives a total power of 1.77 x 10^17 W from the Sun, and it absorbs 88% of this power. This means that the absorbed power by Mercury is:

Absorbed power = 0.88 * (1.77 x 10^17 W) = 1.5576 x 10^17 W

Given that Mercury radiates all of the absorbed light energy as a blackbody, we can equate the absorbed power to the radiated power using the Stefan-Boltzmann law:

Radiated power = σ * A * T^4

Where:

σ is the Stefan-Boltzmann constant (approximately 5.67 x 10^-8 W/m^2·K^4)

A is the total surface area of Mercury (7.78 x 10^13 m^2)

T is the temperature of Mercury in Kelvin (which we want to find)

Since half of Mercury's surface is at the night side temperature and half at the day side temperature, we can assume that the radiated power is evenly distributed over the entire surface. Therefore, we can divide the total surface area by 2:

Radiated power = (1/2) * σ * A * T^4

Equating the absorbed and radiated powers:

1.5576 x 10^17 W = (1/2) * σ * A * T^4

Simplifying the equation:

T^4 = (2 * 1.5576 x 10^17 W) / (σ * A)

T^4 = (2 * 1.5576 x 10^17 W) / (5.67 x 10^-8 W/m^2·K^4 * 7.78 x 10^13 m^2)

T^4 ≈ 4.02 x 10^11 K^4

Taking the fourth root of both sides:

T ≈ (4.02 x 10^11 K^4)^(1/4)

T ≈ 467 K

Therefore, the estimated daytime temperature of Mercury is approximately 467 Kelvin.

Based on the rough estimate using the Stefan-Boltzmann law, Mercury's daytime temperature is estimated to be approximately 467 Kelvin. This high temperature indicates that Mercury's day side is extremely hostile to water-based life, and even the night side with a temperature of 100 Kelvin is inhospitable.

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When a neuron is at resting potential, the state of the electrical charge is negative inside the neuron compared to the outside

Because of an unequal distribution of ions like potassium (K+) and chloride (Cl-) inside and outside the neuron, the interior of the neuron is negatively charged at resting potential. The membrane of the neuron is selectively permeable, permitting certain ions to pass while preventing others from doing so. A gradient in electrochemistry results from this.

Ion channels, notably the sodium-potassium pump, which actively transfers sodium ions (Na+) out of the neuron and potassium ions (K+) into the neuron, are responsible for maintaining the resting potential. As a result, the neuron produces an excess of negative charge within and an excess of positive charge outside.

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Assumed that resistors are connected in series .

Current=I