Water boils at 100 degrees Celsius. What is the boiling point for water on the Kelvin scale? K = °C + 273 and °C = K - 273​

Answers

Answer 1

Answer:

the answer is 373

Explanation:

K=°C + 273

K=100+273=373


Related Questions

The average speed of a diatomic fluorine molecule at 25 ∘C is 442.4 m⋅s−1 . What is the average wavelength of a fluorine molecule at this temperature? Assume that the molecule acts as a single particle

Answers

The average wavelength of the fluorine molecule will be 2.36 × 10⁻¹¹ metres.

Fluorine Molecule's Speed = 442.4 m/s

The Molar Mass of the F₂ = 38 g/mol

Now as we know that any molecule's

1 mole contain  = 6.022 × 10²³ Molecule

So, 1 Fluorine molecule mass =

Fluorine's Molar mass / Number of Fluorine molecule in 1 mole

So, 1 Fluorine molecule mass = 38 / ( 6.022 × 10²³ )

1 Fluorine molecule mass = 6.31 × 10⁻²³ g

1 Fluorine molecule mass = 6.31 × 10⁻²⁶  Kg

So molecule's momentum = Molecule's mass × Molecule's Velocity

So molecule's momentum = ( 6.31 × 10⁻²⁶ ) × 442.4

So molecule's momentum = 2.8 × 10⁻²³  Kg.m/s

Now wavelength of Fluorine molecule = λ = planks constant / momentum

wavelength of Fluorine molecule = λ = ( 6.626 × 10⁻³⁴ ) / ( 2.8 × 10⁻²³ )

wavelength of Fluorine molecule = λ = 2.36 × 10⁻¹¹ metre

So the wavelength of the diatomic fluorine molecule came out to be 2.36 × 10⁻¹¹ metres after applying all the concepts and formulas.

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Determine the number of moles in the following samples:

1. 5.19 x 1029 FeCl3 formula units
2. 6.02 x1025 Mg atoms
3. 5.3 x 1012 N2 molecules
4. 40,000 MgO Formula Units

I need help ASAP

Answers

Answer:

1. Molar mass of FeCl3 is 162.204 g/mol

2. 6.02 x 10^23

3. 8.817663948945736e-24

4. 992.4474747174

The SN1 reaction yields Entry field with incorrect answer two (number) products. This is because ______________________. Entry field with incorrect answer The carbocation that forms can react with CH3OH from the top side of the molecule. The carbocation that forms can react with H2O from either the top or bottom side of the molecule. The carbocation that forms can react with either nucleophile (H2O or CH3OH) from the top side of the molecule. The carbocation that forms can react with H2O from the bottom side of the molecule. The carbocation that forms can react with CH3OH from either the top or bottom side of the molecule. The carbocation that forms can react with either nucleophile (H2O or CH3OH) from the bottom side of the molecule. The carbocation that forms can react with H2O from the top side of the molecule. The carbocation that forms can react with CH3OH from the bottom side of the molecule. The carbocation that forms can react with either nucleophile (H2O or CH3OH) from either the top or bottom side of the molecule.

Answers

Answer:

Four substitution products are obtained. The carbocation that forms can react with either nucleophile (H2O or CH3OH) from either the top or bottom side of the molecule

Explanation:

An SN1 reaction usually involves the formation of a carbocation in the slow rate determining step. This carbocation is now attacked by a nucleophile in a subsequent fast step to give the desired product.

However, the product is obtained as a racemic mixture because the nucleophile may attack from the top or bottom of the carbocation hence both attacks are equally probable.

The attacking nucleophile in this case may be water or CH3OH

Which of these is measured during a scientific investigation

Answers

Answer:

What ae the options?  

Explanation:

A 3.3 g sample of sodium hydrogen carbonate is added to a solution of acetic acid weighing 10.3 g. The two substances react, releasing carbon dioxide gas to the atmosphere. After the reaction, the contents of the reaction vessel weigh 12.1 g. What is the mass of carbon dioxide released during the reaction

Answers

Answer:

1.73g of CO2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

NaHCO3 + CH3COOH → CH3COONa + H2O + CO2

Next we shall determine the masses of NaHCO3 and CH3COOH that reacted and the mass of CO2 produced from the balanced equation. This is illustrated below:

Molar mass of NaHCO3 = 23 + 1 + 12 + (16x3) = 84g/mol

Mass of NaHCO3 from the balanced equation = 1 x 84 = 84g

Molar mass of CH3COOH = 12 + (3x1) + 12 + 16 + 16 + 1 = 60g/mol

Mass of CH3COOH from the balanced equation = 1 x 60 = 60g

Molar mass of CO3 = 12 + (2x16) = 44g/mol

Mass of CO2 from the balanced equation = 1 x 44 = 44g

From the balanced equation above,

84g of NaHCO3 reacted with 60g of CH3COOH to produce 44g of CO2.

Next, we shall determine the limiting reactant of the reaction. This is illustrated below:

From the balanced equation above,

84g of NaHCO3 reacted with 60g of CH3COOH.

Therefore, 3.3g of NaHCO3 will react with = (3.3 x 60)/84 = 2.36g of CH3COOH.

From the above illustration, we can see that only 2.36g of CH3COOH out of 10.3g given reacted completely with 3.3g of NaHCO3. Therefore, NaHCO3 is the limiting reactant while CH3COOH is the excess reactant.

Finally, can determine the mass of CO2 produced during the reaction.

In this case the limiting reactant will be used because it will produce the mass yield of CO2 as all of it were used up in the reaction. The limiting reactant is NaHCO3 and the mass of CO2 produced is obtained as shown below:

From the balanced equation above,

84g of NaHCO3 reacted to produce 44g of CO2.

Therefore, 3.3g of NaHCO3 will react to produce = (3.3 x 44)/84 = 1.73g of CO2.

Therefore, 1.73g of CO2 is released during the reaction.

Heredity Lab Report Instructions:
In the Heredity lab, you investigated how hamsters inherit traits from their parents. Record your observations in the lab report below. You will submit your completed report.
Name and Title: Include your name, instructor's name, date, and name of lab.

Objective(s): In your own words, what was the purpose of this lab?

Hypothesis: In this section, please include the if/then statements you developed during your lab activity.

These statements reflect your predicted outcomes for the experiment.

Test One: If I breed a short fur, FF female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Two: If I breed a short fur, Ff female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Test Three: If I breed a long fur, ff female with a long fur, ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.
Procedure: The procedures are listed in your virtual lab. You do not need to repeat them here.
Please be sure to identify the test variable (independent variable) and the outcome variable (dependent variable) for this investigation. Remember, the test variable is what is changing in this investigation.
The outcome variable is what you are measuring in this investigation.
Test variable (independent variable): Outcome variable (dependent variable): Data: Record the data from each trial in the data chart below. Be sure to fill in the chart completely. Test One Parent 1: FF Parent 2: Ff Phenotype ratio: ________ : ________ short fur : long fur Test Two Parent 1: Ff Parent 2: Ff Phenotype ratio: ________ : ________ short fur : long fur Test Three Parent 1: ff Parent 2: ff Phenotype ratio: ________ : ________ short fur : long fur Conclusion: Your conclusion will include a summary of the lab results and an interpretation of

Answers

For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2

What are the phenotype ratios from the test crosses?

For Test One:

Parent 1: FF (homozygous dominant for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff = 1 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 2 : 0 or 100% short fur

For Test Two:

Parent 1: Ff (heterozygous for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff : ff = 1 : 2 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur

For Test Three:

Parent 1: ff (homozygous recessive for long fur)

Parent 2: ff (homozygous recessive for long fur)

The Punnett square for this cross will give the following genotype ratios:

ff : ff = 1 : 0

And the corresponding phenotype ratios will be:

Short fur : Long fur = 0 : 2 or 100% long fur

For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.

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C3H8O dissolved in water

Answers

If C3H8O is dissolved in water, it would be expected to be a strong electrolyte.

What is a strong electrolyte?

A strong electrolyte is a solute or solution (already an electrolyte) that can completely dissociates in solution.

C3H8O is one of those compounds expected to be a strong electrolyte.

Thus, if C3H8O is dissolved in water, it would be expected to be a strong electrolyte.

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For each of these molecules, identify the proper MO diagram and the number of valence electrons. The 1
orbital is not shown.

Identify the MO diagram for B2.


diagram A

diagram B
B2
valence e−:

6
Identify the MO diagram for C2.


diagram A

diagram B
C2
valence e−:

6
Identify the MO diagram for N2.


diagram A

diagram B
N2
valence e−:

10
TOOLS
x10y
Identify the MO diagram for O2.


diagram B

diagram A
O2
valence e−:

16
Identify the MO diagram for F2
.

diagram B

diagram A
F2
valence e−

Answers

The molecular orbitals for each of the required molecules has been shown in the images attached.

What is an MO diagram?

An illustration of a molecule's molecular orbitals and the corresponding energy levels is called a molecular orbital (MO) diagram. MO diagrams are used to illustrate how the atomic orbitals in a molecule combine to generate the molecular orbitals.

The diagram shows the internuclear distance between the two atoms on the horizontal axis and the relative energy of the atomic orbitals on the vertical axis.

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For each of these molecules, identify the proper MO diagram and the number of valence electrons. The
For each of these molecules, identify the proper MO diagram and the number of valence electrons. The
For each of these molecules, identify the proper MO diagram and the number of valence electrons. The
For each of these molecules, identify the proper MO diagram and the number of valence electrons. The
For each of these molecules, identify the proper MO diagram and the number of valence electrons. The

Anyone want have a baby?


This would be an experiment (;


If u know what I mean

Answers

Answer:

An experiment that could go extremely wrong or just well.

Answer:

Explanation:

Bro huh??? you can't be asking that on brainly bro ;-;

Select the statements that correctly describe an meteoroid. Check all that apply

largest of the space rocks.

smallest of the space rocks

when in the atmosphere, they are called a meteor

they never come near Earth

Answers

Answer:

they are the smallest of space rocks, when in the atmosphere they are called meteors.

Explanation:

i think this is right.

Research some ways in which scientists and engineers have harnessed and currently use the energy in fossil fuels to benefit society. Think about how these methods involve a chemical reaction, and explain how energy is conserved. Describe one method of using fossil fuels for energy, and state one advantage and disadvantage about this method. In your replies to others' comments, state whether you agree or disagree with the advantages and disadvantages they list and explain your reasoning.

Hint: Consider what happens to fossil fuels (such as coal, natural gas, and petroleum) when they are burned.

Answers

Answer:

Explanation:

Fossil fuels are fuels that are formed by naturally processes leading to the formation of crude oil, coal and natural gas.

Scientists and engineers have used the energy from these fossil fuels to benefit the society by converting these fuels into consumable products for engines which are used for various daily life routine, such as transport (as in the case of the combustible engines in cars, trains, airplanes and ships), power generation (as in the case of gas turbines for power generation, petroleum or diesel for the engines of power generators) and even for home use in food processing (as in the case of cooking gas).

The chemical reaction mostly involved in this process especially in the case of engines is combustion reaction. Combustion reaction is an exothermic reaction in which an organic substance is burnt in excess oxygen to produce carbon dioxide.  The energy conserved in this reaction (combustion reaction) is from stored potential energy (in the form of chemical energy) to thermal energy (which is the heat released when the hydrocarbon is burnt).

As mentioned earlier, one of the methods of using fossil fuels for energy is it's use in power generation by power generating sets (generators) and gas turbines. One advantage of using fossil fuel products for power generation is that it is cheaper than it's alternatives (such as solar power generation). However, one disadvantage of using fossil fuel products for power generation is that they release toxic gases/chemicals (such as carbon monoxide, CO, nitrogen oxides, NO and NO₂) into the atmosphere.

Which of the following rate constants is negligible for the initial velocity (V 0) of an enzyme-catalyzed reaction?
k1.
k-1.
k2.
k-2.

Answers

In an enzyme-catalyzed reaction, the rate-limiting step is typically the binding of substrate to the active site of the enzyme. K2 and k-2 represent the rate constants for the formation and breakdown of the enzyme-substrate complex, respectively. These rate constants are important in determining the overall rate of the reaction, but they do not determine the initial velocity, which is largely determined by k1.

About Enzyme Catalyzed

Enzyme Catalyzed is the increase in the rate of a process by a biomolecule. Such biomolecules are called enzymes, and most enzymes are proteins, while the processes they accelerate are mostly chemical reactions in the body.

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5. The accepted values for density are: aluminum = 2.71 g/cm³; PE = about 0.925 g/cm³; and iron = 7.87 g/cm³. Compare your values from Question 4 with these. How do they compare? Why are they different? Note: the density of different kinds of PE and PVC vary because of the difference in the arrangements of their molecules.​

5. The accepted values for density are: aluminum = 2.71 g/cm; PE = about 0.925 g/cm; and iron = 7.87

Answers

Answer:Percent error=5.6%

Explanation:

Application 2:

1. Another component of acid rain is nitric acid, which forms when NO, also a pollutant, reacts with oxygen and water according to the simplified equation:

4 NO2(g) + 02(g) + 2 H0(1) -> 4 HNO, (ag)

The generation of the electricity used by a medium-sized home produces about 16 kg of NO2 per year. Assuming that there is adequate Oz and H2O, what mass of HNO;, in kg, can form from this amount of NO2 pollutant?

Application 2:1. Another component of acid rain is nitric acid, which forms when NO, also a pollutant,

Answers

Chemical reaction in balance: 4HNO3 is the result of 4NO2 + O2 + 2H2O. N has a mass of 14 u, while O has a mass of 16 u.

Which of the following describes a mole in the most comprehensive and accurate manner?

The quantity of a substance that contains as many particles as there are atoms in precisely 12 g of carbon 12 isotope is referred to as a mole. Regardless of their nature, 6.0221023 particles are represented by a mole. As a result, when propane is burned, it produces 4 moles of water and 3 moles of carbon dioxide.

When propane C3H8 burns, what kinds of products are produced?

Answer: The hydrocarbon propane (C3H8) is a member of the homologous series of alkanes. As a result, propane will be combusted to produce four molecules of water and three molecules of carbon dioxide.

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How much ice in grams would have to melt to lower the temperature of 352 mL
of water from 15 ∘C
to 0 ∘C
? (Assume that the density of water is 1.0 g/mL

Answers

Answer:

66 grams of ice would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C.

Explanation:

To calculate the amount of ice that would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C, we need to use the formula:

Q = m_water * c_water * ΔT_water + m_ice * Lf

where,
Q = the amount of heat transferred,
m_water = the mass of water, c_water is the specific heat capacity of water,
ΔT_water = the change in temperature of water, m_ice = the mass of ice,
Lf = the specific latent heat of fusion of ice.

First, let's calculate the amount of heat transferred to the water:

Q = m_water * c_water * ΔT_water
Q = 352 g * 1.0 cal/(g*°C) * (15-0) °C
Q = 5,280 cal

Next, we can use the specific latent heat of fusion of ice, which is 80 cal/g, to calculate the amount of heat required to melt the ice:

Q = m_ice * Lf
Q = m_ice * 80 cal/g
m_ice = Q / Lf
m_ice = 5,280 cal / 80 cal/g
m_ice = 66 g

A sample of wastewater has 0.00048 g of lead in 100. g of solution. What is the ppm of lead in the solution?

Answers

The concentration of lead in the solution is 4.8 ppm.

The parts per million

The ppm (parts per million) is a unit used to express the concentration of a solution. It is defined as the number of parts (by mass) of a solute per million parts (by mass) of the solution. To convert from grams per 100 grams to ppm, we can use the following formula:

ppm = (mass of solute/mass of solution) x 10^6

In this case, the mass of solute (lead) is 0.00048 g, and the mass of solution is 100. g. Plugging these values into the formula, we get:

ppm = (0.00048/100) x 10^6

ppm = 4.8

Therefore, the concentration of lead in the solution is 4.8 ppm.

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which of the following has mass​

Answers

Answer:

Everything in the universe has mass.

Explanation:

This equation is not balanced. Click on the coefficient we should change first.
help ASAP

This equation is not balanced. Click on the coefficient we should change first.help ASAP

Answers

Answer:  The coefficient we should change first is for \(NO_{3}\).

Explanation:

The given reaction equation is as follows.

\(Al + Ni(NO_{3})_{2} \rightarrow Al(NO_{3})_{3} + Ni\)

Here, number of atoms present on reactant side are as follows.

Al = 1Ni = 1\(NO_{3}\) = 2

Number of atoms present on the product side are as follows.

Al = 1Ni = 1\(NO_{3}\) = 3

To balance this equation, multiply Al by 2 and \(NO_{3}\) by 3 on reactant side. Also, multiply \(Al(NO_{3})_{3}\) by 2 and Ni by 3 on the product side.

Hence, the equation can be rewritten as follows.

\(2Al + 3Ni(NO_{3})_{2} \rightarrow 2Al(NO_{3})_{3} + 3Ni\)

Now, number of atoms present on reactant side are as follows.

Al = 2Ni = 3\(NO_{3}\) = 6

Number of atoms present on product side are as follows.

Al = 2Ni = 3\(NO_{3}\) = 6

Since, the atoms on both reactant and product side are same. Hence, it is now a balanced chemical equation.

Thus, we can conclude that the coefficient we should change first is for \(NO_{3}\).

What mass of NaCl is needed to produce a 26.4 mol/L with a 1.7 L volume?

Answers

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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The equilibrium constant for A + 2B → 3C is 2.1 * 10^-6
Determine the equilibrium constant for 2A + 4B → 6C.
a- 4.2 * 10^-6
b- 4.4 * 10^-12
c- 2.3 *10^11
d- 1.8 *10^-11
e- None of these

Answers

Answer:

b- 4.4 * 10^-12.

Explanation:

Hello.

In this case, as the reaction:

A + 2B → 3C

Has an equilibrium expression of:

\(K_1=\frac{[C]^3}{[A][B]^2}=2.1x10^{-6}\)

If we analyze the reaction:

2A + 4B → 6C

Which is twice the initial one, the equilibrium expression is:

\(K_2=\frac{[C]^6}{[A]^2[B]^4}\)

It means that the equilibrium constant of the second reaction is equal to the equilibrium constant of the first reaction powered to second power:

\(K_2=K_1^2\)

Thus, the equilibrium constant of the second reaction turns out:

\(K_2=(2.1 * 10^{-6})^2\\\\K_2=4.4x10^{-12}\)

Therefore, the answer is b- 4.4 * 10^-12.

Best regards.

How many grams of potassium chloride will be needed to produce
829 grams of zinc chloride?

Answers

Answer:

\(2KCl + Zn {}^{2 + } → 2K {}^{ + } + ZnCl _{2} \\ molecular \: mass \: of \: zinc \: chloride = 65 + (35.5 \times 2) = 136 \: g \\ molecular \: mass \: of \: potassium \: chloride = 39 + 35.5 = 74.5 \: g

In this reaction, 28.7 g of lithium nitrate reacts 14.5 g of barium
sulfate. What will be the mass of the products?
LINO3+ BaSO4 → Products

Answers

Answer:ABOMC5LDECEVCEC

Question 1 (2 points)
What is the mass in mg of 9.3 x 1016 lead atoms? Give answer with correct
significant figures and units.

Answers

Answer:

the answer would be 9,448.8

The mass of 9.3 × 10¹⁶ lead atoms is equal to 0.032 mg.

What is Avogadro's number?

Avogadro’s number represents the number of entities in one mole of any substance. Generally, these units can be molecules, atoms, ions, electrons, or protons, depending upon the type of chemical reaction or reactant and product.

The value of Avogadro’s constant is approximately equal to 6.022 × 10²³ mol⁻¹.

Given, the number of atoms of the lead =  9.3 × 10¹⁶

The atomic mass of the lead = 207.2 g/mol

So 6.022 × 10²³ atoms of lead have mass = 207.2g

Then 9.3 × 10¹⁶ lead atoms will have mass \(=\frac{207.2\times 9.3\times 10^{23}}{ 6.022\times 10^{23}}\)  = 31.998 ×10⁻⁷g

As we know, 1 gram = 1000 mg

The mass of the  9.3 × 10¹⁶ lead atoms =  31.998 ×10⁻⁴ mg = 0.0032 mg

Therefore, the mass of 9.3 × 10¹⁶ lead atoms is  0.032 mg.

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What are most membranes made up of?

layers of ducts

layers of epithelial tissue

layers of bursae

Answers

Answer:

layers of epithelial tissue

Answer:

It's B

Explanation:

Suppose a species of snake is living in a certain area. Some of the snakes in the population are black and some are orange. Over time, the area changes and the orange snakes have a harder time blending into the environment. This makes it difficult for the orange snakes to catch food.

According to Darwin’s theory of evolution, what will most likely happen to this snake population over time?

Most orange snakes will survive and reproduce, passing on their traits to their offspring. Few black snakes will remain in the population.
Most black snakes will survive and reproduce, passing on their traits to their offspring. The number of orange snakes in the population will not change.
The black snakes will survive and reproduce, passing on their traits to their offspring. Few orange snakes will remain in the population.
Most orange snakes will survive and reproduce, passing on their traits to their offspring. The number of black snakes in the population will not change.

Answers

Answer:

The black snakes will survive and reproduce while the orange snakes die out.

Explanation:

The orange snakes will be easier to see by their prey and predators, and therefore will die out while the black snakes thrive because of their camouflage.

Answer:

the black snakes will survive and reproduce, therefore, passing their traits to their offspring, while few orange snakes will remain in the population.  

Explanation:

how many grams of water are needed to react with 71.0g CaN2?

Answers

Answer:

1

Explanation:

Mass of

C

a

C

N

2

= 75.0 g

From the equation,

C

a

C

N

2

(

s

)

+

3

H

2

O

(

l

)

C

a

C

O

3

(

s

)

+

2

N

H

3

(

g

)

1 mol of

C

a

C

N

2

reacts with 3 moles of water to give calcium carbonate and ammonia.

Number of moles of

C

a

C

N

2

,

n

=

G

i

v

e

n

m

a

s

s

M

o

l

a

r

m

a

s

s

Molar mass of

C

a

C

N

2

= 92.11 g/mol

Therefore,

n

C

a

C

N

2

=

75

g

92

.11

g

/

m

o

l

=

0

.814

m

o

l

Moles of water =Therefore,

n

C

a

C

N

2

=

75

g

92

.11

g

/

m

o

l

=

0

.814

m

o

l

Moles of water =

3

×

0

.814

m

o

l

e

s

=

2

.442

m

o

l

e

s

Mass of water needed;

=

m

o

l

e

s

o

f

w

a

t

e

r

×

m

o

l

a

r

m

a

s

s

o

f

w

a

t

e

r

=

2

.442

m

o

l

×

18

g

/

m

o

l

=

43

.956

g

Thus, 43.96 g of water is needed to react with 75 g of

C

a

C

N

2

.

6b. Identify the quantum numbers for the very last electron in Cadmium (Cd).
n=
1=
mi =
ms=

Answers

The quantum numbers for the very last electron in Cadmium (Cd) atom is  (5, 0, 0, ±¹/₂) for the four quantum numbers.

What are quantum numbers?

Quantum numbers are the set of numbers used to express the location and energy of an electron in an atom.

There are four quantum numbers used to describe the location and energy of an electron in an atom, and they are:

Principal quantum number, nazimuthal quantum number, lmagnetic quantum number, mi andspin quantum numbers, ms

The electronic configuration of cadmium is  [Kr]4d¹⁰5s².

Hence, cadmium belongs to period 5 of the periodic table, and the last electron occupies the 5s orbital.

The l value of the s orbital is 0, and mi is 0 as well.

The value of ms is ±¹/₂.

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Why would you want to slow down a chemical reaction? ​

Answers

Answer:

We often want to decrease the rates of certain reactions rather than speeding them up. For example, to prolong the shelf lives of certain foods, the chemical reactions by which they spoil must be slowed down.

Pls help me I’m having a hard day pls answer these?

Pls help me Im having a hard day pls answer these?

Answers

Answer:the first one is D second one is A and the third one is A   :D

Explanation:

What angle is needed to spread 4 bonds as far apart as possible?

Answers

Answer:

109°

Explanation:

According to Valence Shell Electron Pair Repulsion Theory, electron pairs on the valence shell of the central atom of a molecule must be positioned as far apart in space as possible to minimize repulsion between valence shell electron pairs.

The shape of a molecule depends on the number and type of electron pairs on the valence shell of its central atom. Lone pairs generally cause more repulsion than bond pairs of electrons.

The ideal bond angle for a molecule with four bonds is 109° which corresponds to a tetrahedral geometry. This enables the four bonds to spread as far apart in space as possible.

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