using wind turbines to produce electricity avoids the production of nitrogen oxides and sulfur dioxide, which are the major pollutants

Answer:

see below (I hope this helps!)

Explanation:

You are a student, therefore, the people who are the same "rank" as you are your fellow students, this makes them your peers.

Answer:

Recessive

Explanation:

Hope this help I think this is the right answer.

The structure of aldohexose is drawn.

D-glucose is an aldohexose, which means it is a 6-carbon sugar with an aldehyde group (-CHO) at one end. It is a crucial molecule in the metabolism of living organisms and is the primary source of energy for most cells. D-glucose exists in two forms, alpha and beta, which differ in the orientation of the hydroxyl (-OH) group at C1.

D-glucose can also form ring structures, with the aldehyde group reacting with a hydroxyl group on another carbon atom. These ring structures can also exist in alpha and beta forms, depending on the orientation of the -OH group attached to the ring oxygen. Overall, D-glucose plays a critical role in the biochemistry of life, serving as a building block for complex carbohydrates and other biomolecules.

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Explanation:

There are several pieces of evidence that can be used to identify chemical changes, other than a change in color. Some of these include the production of a gas, the formation of a precipitate, a change in temperature, and a change in the state of matter (e.g. from a solid to a liquid or vice versa). For example, if a solid substance is added to a liquid and bubbles of gas are produced, this is evidence of a chemical change. Similarly, if two clear solutions are mixed together and a solid precipitate forms, this is also evidence of a chemical change. Additionally, if a substance is heated and it changes from a solid to a liquid or from a liquid to a gas, this is also evidence of a chemical change.

The acid which contains sulfate ions can be tested by the reagent which is barium chloride.

Acids are defined as substances which on dissociation yield H+ ions , and these substances are sour in taste.

According to the number of H+ ions which are generated on dissociation acids are classified as mono-protic , di-protic ,tri-protic and polyprotic  acids  depending on the number of protons which are liberated on dissociation.

Acids are widely used in industries  for  production of fertilizers, detergents batteries and dyes.They are used in chemical industries for production of chemical compounds like salts which are produced by neutralization reactions.

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10.8 moles are present in 6.5 × 10²⁴ atoms of Barium (Ba). Details on how to calculate number of moles can be found below.

The number of moles of a substance can be calculated by dividing the number of atoms in the substance by Avogadro's number.

According to this question, 6.5 × 10²⁴ atoms of Ba are present, the number of moles is calculated thus:

no of moles = 6.5 × 10²⁴ ÷ 6.02 × 10²³

no of moles = 1.08 × 10¹

no of moles = 10.8moles

Therefore, 10.8 moles are present in 6.5 × 10²⁴ atoms of Barium (Ba).

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Answer:4.5 ×10^22)

Explanation:

no. of particles =no. of mole×avogadro's number of particles no. of particles =0.75×6.02×10^23 no. of particles =4.5 ×10^22

Answer:

0.2 moles de SO₂

Explanation:

La reaccción es:

2H₂S (g) +  3O₂ (g)  →  2SO₂ (g)  +  2H₂O(g)

Asumimos que tenemos 0.250 moles de sulfuro y 0.3 moles de oxígeno.

En primer lugar tenemos que averiguar el reactivo limitante.

Si 2 moles de sulfuro de hidrógeno reaccionan con 3 moles de oxígeno, según la reacción.

Entonces 0.250 moles, reaccionarían con (0.250 . 3) /2 = 0.375moles

Tenemos entonces 0.3 moles de oxígeno y necesitamos 0.375 (no nos alcanza). Por lo tanto el O₂ es el limitante y ahora podemos calcular el producto formado. La ecuación nos dice:

3 moles de oxígeno pueden producir dos moles de SO₂

Entonces 0.3 moles (que son los que tenemos) de O₂ producirían:

(0.3 . 2) /3 = 0.2 moles de SO₂

During electrolysis a metal chemically decompose and deposits on the cathode where as the metal from the other electrode forms its ions in the electrolyte solution.

Electrolysis is the process of chemical decomposition brought out by the passage of electricity through an electrolyte in which the decomposed metal deposits on one electrode.

Electrolysis involves oxidation of one metal and reduction of the other. The prediction of the products of electrolysis requires a consideration of several factors including the potential at which the competing species are discharged at the electrode , if the electrode used are reacted or inert etc.

The oxidation reaction involves the formation of cations in the solution and the reduction involves the deposition of metallic substance at the cathode.

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Answer:

2KOH + 3co2 ------->2ксоз + 2Н20

Answer:  The bonds that are made and broken in a reaction release energy when forming products that contain less total energy than the reactants.

Explanation:  Elements form bonds with each other when the total energy of the resulting products is less than the starting energy.  The term "energy" refers to the energy of the electrons that are being held in an atom by the nucleus.  Keeping the positively charged nucleus happy means that the electrons are trying to get closer, but they repel each other as they get closer to the nucleus.  This results in orbits, preferred areas around the nucleus where the electrons spend their day in a delicate balance with the nucleus and other electrons.  These orbits offer housing for the electrons that involve discreet energies for the electrons.  When elements react, the resulting bonding pattern often results in an overall reduction in total energy.  The energy reduction results in heat, light, and/or sound.  The release is termed "exothermic."

Cyclohexane have the smallest strain energy

(kj/mol)

This chair conformation is the lowest energy conformation for cyclohexane with an overall ring strain of 0 kJ/mol.

When a molecule's chemical structure is stressed, it experiences strain, which increases the internal energy of the molecule relative to a strain-free reference substance. All the energy that a molecule has inside of it makes up its internal energy.

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Answer:

Divide by the molar mass to get moles

Explanation:

The graph shows that as mass increases, kinetic energy increases exponentially. This means that as the mass of an object increases, the kinetic energy increases by a larger and larger amount.

This can be seen by the upward sloping line on the graph. This can be seen in the graph by the steepness of the line, which shows that the increase in kinetic energy is growing faster and faster as the mass increases. Additionally, the graph shows that the rate of increase in kinetic energy is greater for lower masses than for higher masses, which indicates an exponential increase. This can be seen by the upward sloping line on the graph.

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Answer:

Glucose will enter the cell through osmosis.

Explanation:

Diffusion causes molecules to move from high concentration to low concentration, so the glucose molecules outside the cell will move through the membrane to inside of the cell.

The fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

Fugacity is a measure of the escaping tendency of a component in a mixture, which is defined as the pressure that the component would have if it obeyed ideal gas laws. It is used as a correction factor in the calculation of equilibrium constants and thermodynamic properties such as chemical potential. Here we need to determine the fugacity in atm for pure ethane at 310 K and 20.4 atm and the change in the chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm. So, using the formula of fugacity: f = P.exp(Δu/RT) Where P is the pressure of the system, R is the gas constant, T is the temperature of the system, Δu is the change in chemical potential of the system.  Δu = RT ln (f / P)The chemical potential at the initial state can be calculated using the ideal gas equation as: PV = nRT    

=>  P

= nRT/V

=> 20.4 atm

= nRT/V

=> n/V

= 20.4/RT The chemical potential of the system at the initial state is:

Δu1 = RT ln (f/P)

= RT ln (f/20.4) Also, we know that for a pure substance,

Δu = Δg. So,

Δg1 = Δu1 The change in pressure is 24 atm – 20.4 atm

= 3.6 atm At the second state, the pressure is 24 atm.

Using the ideal gas equation, n/V = 24/RT The chemical potential of the system at the second state is: Δu2 = RT ln (f/24) = RT ln (f/24) The change in chemical potential is Δu2 – Δu1 The change in chemical potential is

Δu2 – Δu1 = RT ln (f/24) – RT ln (f/20.4)

= RT ln [(f/24)/(f/20.4)]

= RT ln (20.4/24)

= - 0.0911 RT Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is:

f = P.exp(Δu/RT)

=> f

= 20.4 exp (-Δu1/RT)

=> f

= 20.4 exp (-Δg1/RT) And, the change in the chemical potential between this state and a second state of ethane where the temperature is constant but pressure is 24 atm is -0.0911RT. Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

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Answer:

3.1 moles of Iron(III) Oxide

Explanation:

The equation of the reduction of iron III oxide using carbon is shown;

Fe2O3 + 3CO → 2Fe + 3CO2

From the reaction equation;

1 mole of  Iron(III) Oxide yielded 3 moles of carbon dioxide

x moles of Iron(III) Oxide will yield  9.20 moles of carbon dioxide

x = 9.2 moles * 1 mole/3 moles

x = 3.1 moles of Iron(III) Oxide

The freezing point, in °C, of a 0.407 m solution in benzene is 3.42°C

Freezing point refers to the temperature at which a liquid freezes, and the solid and liquid phases are in equilibrium.

According to this question, a 0.407 m solution is in benzene solution. The freezing point of the solution can be calculated as follows:

∆T = K × m

Where;

∆T = 5.12 × 0.407

∆T = 2.084°C

Freezing point in benzene = 5.5°C - 2.084°C = 3.42°C

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Answer:

b, d,  -13.4

Explanation:

Answer:203.9

Explanation:

Both of these structures satisfy the octet rule for Se.

To draw the Lewis structures for SeF4 and SeF6, we need to determine the number of valence electrons for selenium (Se) and fluorine (F).

- Selenium has six valence electrons (group 16 element) and needs two more electrons to complete its octet.

- Fluorine has seven valence electrons (group 17 element) and needs one more electron to complete its octet.

1. Lewis structure for SeF4:

- Place the Se atom in the center and arrange the F atoms around it.

- Connect the Se atom to each F atom with a single bond.

- Place two lone pairs on the Se atom to satisfy its octet.

F F

| |

F--Se--F

| |

F F

2. Lewis structure for SeF6:

- Place the Se atom in the center and arrange the F atoms around it.

- Connect the Se atom to each F atom with a single bond.

- Add six lone pairs around the F atoms to satisfy their octets.

F

|

F--Se--F

|

F

The octet rule is satisfied for Se in SeF4 and SeF6. In SeF4, Se has a total of eight valence electrons (six from the lone pairs and two from the bonds) and in SeF6, Se has twelve valence electrons (six from the lone pairs and six from the bonds). Both of these structures satisfy the octet rule for Se.

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no. of mole = 88 ÷ ( 12 + 2(16) )

= 2 mol

mass of C = 2 × 12

= 24g ( A )

Answer:

651/22 and 14322

Explanation:

The rank of the indicated ionic compounds according to the increasing order of their lattice energy is MgO, NaBr, NaCl and CaCl2, considering for this the amount of this energy in each compound.

For the rank of these ionic compounds, it has been taken into account that the negative value is because it is energy released when a mole of the solid compound is formed from its elements in a natural state; consequently, NaBr gives off more energy (-728.8 kJ/mol) than MgO (-602.0 kJ/mol), that is, there is an increase in energy.

It is also called reticular energy and is the energy needed to form one mole of a solid ionic compound from its gaseous ions.

Its magnitude is an indicator of the stability of the crystal lattice.

Lattice energy is not measured directly, but rather through the structure and composition of an ionic compound.

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Answer:

D a substance that increases the rate of a reaction without being used up itself in a reaction.

Explanation:

Examples are

ammonia synthesis ==> iron

sulfuric acid manufacture ==> nitrogen(II) oxide, platinum

cracking of petroleum==> zeolites

hydrogenation of unsaturated hydrocarbons ==> nickel, platinum, or palladium

I hope it helps

Answer:

Hey there!

The correct answer would be D. "a substance that increases the rate of a reaction without being used up itself in a reaction."

Hope this helps :)

Rutherford's model of atom could not explain chemical properties as it did not make any mention as to how chemical changes take place.

These properties are defined as those properties which become evident during or after a chemical reaction after the identity of the substance is changed during chemical reaction.

These properties cannot be determined externally just by viewing the substance ,these change immensely after a substance undergoes a chemical change.These are used for identification of unknown substances and for building up chemical classifications.

The major chemical properties are flammability,toxicity,reactivity,acidity and heat of combustion.For a chemical property to be apparent , it is necessary that the structure of the substance is altered.

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The shopper does approximately 1580.5 Joules of work on the cart as they move along the 50.0 m length of the aisle.

To find the work done by the shopper on the cart, we can use the formula: work = force * distance * cos(angle).

Given:

Force (F) = 35 N

Angle (θ) = 25° downward from the horizontal

Distance (d) = 50.0 m

First, we need to determine the horizontal component of the force, which is F_horizontal = F * cos(θ).

F_horizontal = 35 N * cos(25°) ≈ 31.61 N

The work done by the shopper on the cart is then:

Work = F_horizontal * distance

Work = 31.61 N * 50.0 m = 1580.5 Joules

Therefore, the shopper does approximately 1580.5 Joules of work on the cart as they move along the 50.0 m length of the aisle.

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Answer:

0.666 lit

Explanation:

weight of the goid idol = 2 Kg =2000 g which has tobe replaced by the same weight of sand.

2000 g sand = Density of sand x volume of sand

volume of sand = 2000/3 cm 3

= 666.6 cm3

= 0.666 lit