Using the data in Table 1, determine which atom in a bond between carbon and nitrogen would be negatively polarized (C or N). explain

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 0.251 × 1000

We have the final answer as

Hope this helps you

Answer:

v = 34.62 L

Explanation:

Given data:

Moles of H₂ = 2.50 mol

Temperature of gas = -20.0°C

Pressure of gas = 1.5 atm

Volume of gas = ?

Solution:

Formula:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

-20 + 273 = 253 K

Now we will put the values in formula.

1.5 atm × v = 2.50 mol ×0.0821 atm.L/ mol.K  ×  253 K

1.5 atm × v = 51.93 atm.L

v = 51.93 atm.L/1.5 atm

v = 34.62 L

The volume of hydrogen is 34.62 L.

The ion channel that opens in response to acetylcholine is an example of a ligand-gated ion channel, which is a type of direct or membrane signal transduction system.

In this system, the neurotransmitter acetylcholine acts as the ligand that binds to the receptor site on the ion channel, causing it to open and allow the flow of ions across the cell membrane.

This rapid change in ion concentration can trigger a range of cellular responses, such as muscle contraction or nerve impulse transmission.

Ligand-gated ion channels are distinct from other types of signal transduction systems, such as G protein-coupled receptors and enzyme-linked receptors, which rely on intracellular signaling pathways to mediate the response to ligand binding.

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The Miller-Urey experiment, conducted in 1952-1953 by Stanley Miller and Harold Urey, is a famous experiment that aimed to simulate the conditions of the early Earth's atmosphere. This experiment produced organic molecules by subjecting a mixture of gases believed to resemble the early Earth's atmosphere to various energy sources.

The Miller-Urey experiment was a groundbreaking study in the field of abiogenesis, exploring the possibility of how life's building blocks could have originated from non-living matter. By introducing a mixture of gases, including methane, ammonia, water vapor, and hydrogen, into a closed system, Miller and Urey aimed to simulate the conditions of the early Earth.

To mimic the energy sources on the early Earth, they introduced sparks to simulate lightning and heat to simulate volcanic activity. After running the experiment for several days, they analyzed the contents and found the presence of various organic molecules, including amino acids, which are the building blocks of proteins.

The results of the Miller-Urey experiment provided evidence that the Earth's early atmosphere could have facilitated the formation of organic molecules, suggesting a possible pathway for the origin of life. Although the composition of the early Earth's atmosphere is still a subject of scientific debate, the Miller-Urey experiment remains a significant milestone in understanding the prebiotic chemistry that could have led to the emergence of life on Earth.

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The properties of substances can be used to put the into groups.

In chemistry, it is often necessary to put substances into groups based  on similarity in their properties. This is what led to the idea of a periodic table of elements.

Similarly, when we have unknown substances, we can group them according to the similarities in their properties.

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The phase diagram of water depicts the behavior of water with respect to temperature and pressure, showing the physical states of water: solid, liquid, and gas, at different points on the diagram. It is also known as the pressure-temperature phase diagram

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Answer:

Soluble

Explanation:

hope this helps

The heat of reaction (ΔH) for the given reaction is 180.4 kJ/mol. To calculate the heat of reaction (ΔH) for the given reaction:

CCl₄(g) + H₂O(g) -> CHCl₃(g) + HCl(g)

You would need the standard enthalpies of formation for each compound involved in the reaction. The standard enthalpy of formation (ΔHf) is the enthalpy change when one mole of a compound is formed from its elements in their standard states.

Here are the standard enthalpies of formation for the compounds involved:

ΔHf[CCl₄(g)] = -135.5 kJ/mol

ΔHf[H₂O(g)] = -241.8 kJ/mol

ΔHf[CHCl₃(g)] = -104.7 kJ/mol

ΔHf[HCl(g)] = -92.3 kJ/mol

To calculate ΔH for the reaction, you need to sum up the enthalpies of formation of the products and subtract the sum of the enthalpies of formation of the reactants:

ΔH = ΣΔHf(products) - ΣΔHf(reactants)

ΔH = [ΔHf[CHCl₃(g)] + ΔHf[HCl(g)]] - [ΔHf[CCl₄(g)] + ΔHf[H₂O(g)]]

ΔH = [(-104.7 kJ/mol) + (-92.3 kJ/mol)] - [(-135.5 kJ/mol) + (-241.8 kJ/mol)]

ΔH = -196.9 kJ/mol - (-377.3 kJ/mol)

ΔH = 180.4 kJ/mol

Therefore, the heat of reaction (ΔH) for the given reaction is 180.4 kJ/mol.

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Explanation:

Because carbon-14 decays at this constant rate, an estimate of the date at which an organism died can be made by measuring the amount of its residual radiocarbon. ... The carbon-14 method was developed by the American physicist Willard F.

The pH of a .25 M acetic acid solution would be higher than the pH of a .25 M hydrochloric acid solution. This is because acetic acid is a weak acid, meaning it only partially dissociates in water, while hydrochloric acid is a strong acid, meaning it completely dissociates in water. The pH of a weak acid solution is higher than the pH of a strong acid solution of the same concentration.
Based on the terms you provided, I'll compare the pH of 0.25 M acetic acid and 0.25 M hydrochloric acid solutions.
Acetic acid is a weak acid, which means it doesn't completely dissociate in water, whereas hydrochloric acid is a strong acid, meaning it fully dissociates in water. When an acid dissociates, it releases hydrogen ions (H+) into the solution, which determines the pH.
Here's a step-by-step comparison:
1. A 0.25 M acetic acid solution will only partially dissociate, releasing fewer H+ ions into the solution.
2. A 0.25 M hydrochloric acid solution will completely dissociate, releasing more H+ ions into the solution.
Since the pH scale is logarithmic and inversely related to the concentration of H+ ions, a solution with fewer H+ ions will have a higher pH (less acidic) than a solution with more H+ ions.
Therefore, you would expect the pH of a 0.25 M acetic acid solution to be higher (less acidic) than the pH of a 0.25 M hydrochloric acid solution.

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Answer:

1.5 moles

Explanation:

O   mole weight = 15.999

O2 mole weight = 2 * 15.999 = 31.998 gm

48 / 31. 998  = ~ 1.5 moles

Answer:

first is c and second is a

Maltose, which has the chemical formula C12H22O11, is created when three glucose molecules are joined together by dehydration processes.

Maltose, with the chemical formula C12H22O11, is created when dehydration events join three glucose molecules together.

Each glucose molecule that is bonded together during the dehydration event results in the removal of one water molecule. This joins the molecules together in a glycosidic bond, resulting in the disaccharide maltose.

By deducting the total number of water molecules lost from the combined molecular formula of the three glucose molecules, one may get the molecular formula of maltose. Three dehydration processes remove three molecules of water, each of which removes one. Maltose has the chemical formula (C6H12O6)3 - 3H2O, which is translated to C12H22O11 as a result.

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The molecular formula for glucose is C6H12O6. What would be the molecular formula for a molecule made by linking three glucose molecules together by dehydration reactions?

Answer:The natural world contains about 8.7 million species, according to a new estimate described by scientists as the most accurate ever. But the vast majority have not been identified - and cataloguing them all could take more than 1,000 years.

Explanation:

The correct answer is B. 0.35 g.

To calculate the mass of the sample that remains unchanged after 25.53 minutes, we need to use the half-life of iron-53, which is 8.51 minutes.

First, we need to determine how many half-lives have elapsed during the 25.53 minutes.

25.53 min / 8.51 min per half-life = 3 half-lives

This means that the original sample has gone through three half-lives, leaving us with one-eighth of the original amount of iron-53.

1/2 * 1/2 * 1/2 = 1/8

To find the mass of the remaining iron-53, we can multiply the original mass by 1/8:

5.60 g * 1/8 = 0.70 g

However, the question asks for the mass to be expressed to two significant figures, which means that we need to round the answer to 0.35 g. Therefore, the correct answer is B. 0.35 g.

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Answer:

1. 0.3457g

2. 7650mL

3. 216000 seconds

4. 10080minutes

5. 2400 seconds

6. 173.99cm

7. 70283.2g

8. 137.16metres

9. 4.968miles

10. 3.105miles

Explanation:

1. 1000mg = 1g

345.7 mg = 345.7/1000

= 0.3457g

2. 1kL = 1000000mL

0.00765 kL = 0.00765 × 1000000

= 7650mL

3. 1 day = 86400s

2.5 days = 2.5 × 86400

= 216000 seconds

4. 1 week = 10080minutes

1.000weeks is equivalent to 1 week, hence there are 10080minutes in 1.000week.

5. 1minute = 60seconds

40.0minutes = 40 × 60

= 2400seconds.

6. 1 inch = 2.54cm

68.5inches = 68.5 × 2.54

= 173.99cm

7. 1Ib = 16oz

155Ibs = 155 × 16

= 2480 oz

1 oz = 28.34 g

2480oz = 2480 × 28.34

= 70283.2g

8. 1 foot = 12 inches

450 feet = 450 × 12

= 5400inches

1 inch = 0.0254metres

5400 inches = 5400 × 0.0254

137.16metres

9. 1 metre = 0.000621 mile

8000 metres = 8000 × 0.000621

= 4.968miles

10. 1 kilometers = 1000 metres

5km = 5 × 1000

= 5000metres

1 metre = 0.000621 mile

5000metres = 5000 × 0.000621

= 3.105miles

Answer:

The frequency of photon is 0.75×10¹⁵ s⁻¹.

Explanation:

Given data:

Energy of photon = 5×10⁻¹⁹ J

Frequency of photon = ?

Solution:

Formula;

E = hf

h = planck's constant = 6.63×10⁻³⁴ Js

5×10⁻¹⁹ J =  6.63×10⁻³⁴ Js ×f

f =  5×10⁻¹⁹ J / 6.63×10⁻³⁴ Js

f = 0.75×10¹⁵ s⁻¹

The frequency of photon is 0.75×10¹⁵ s⁻¹.

Answer:

Scientific learning is the study methodology used through testing and experimentation.

Answer:

The Science of Learning is an approach that recognizes the value and importance of cross-fertilization across traditional fields of study, drawing on many different methods and techniques to understand how learning occurs— with the ultimate goal of optimizing learning for all.

Answer:

Explanation:

the nymph looks like a smaller version of the adult insect, & it also has no wings & molts.

6:c

7: might be ice but im not really sure, hope you do well.

Explanation:

An ionic salt, is more soluble in water

Polar substances  are generally more soluble in water compared to nonpolar substances. This is because water is a polar solvent, meaning that it has a partial positive charge on one end and a partial negative charge on the other end due to the asymmetric arrangement of its atoms.

Polar substances also have a partial positive and partial negative charge on different parts of their molecules, which allows them to interact with water molecules through electrostatic interactions,

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1. calcium chloride suitable method is Chemical drying method.

2. Hydrogen chloride, suitable method is Absorption method.

3. Methane, suitable method is Adsorption method.

4. Naphtha, suitable method is condensation method.

5. Calcium chloride, suitable method is Chemical method.

6.  Hydrogen fluoride, suitable method is Absorption method.

What are gases?

Gases are samples of matter that has no fixed shape and takes the shape of the container it is filled into.

Gases such as calcium chloride can be dried through chemical drying method.

In conclusion, gases has no fixed shape and takes the shape of the container it occupies.

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Answer:

I think it is 60 :)

Explanation:

The correct reactant ratio for the reaction 2Fe + 3Cl2 → 2FeCl3 is 2 moles of iron (Fe) for every 3 moles of chlorine (Cl2).

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The pH of 1. 0 L of the solution on addition of 30. 0 mL of 1. 0 M HCl to the original buffer solution will be 12.50.

The reaction that occurs when HCl is added to the buffer solution is:

HCl + NH₃ → NH₄⁺ + Cl⁻

The HCl reacts with NH₃ to form NH₄⁺ and Cl⁻. This will cause the concentration of NH₄⁺ in the buffer to increase and the concentration of NH₃ to decrease. However, since we started with a buffer solution, it will still be able to resist changes in pH.

To solve this problem, we will use the Henderson-Hasselbalch equation:

pH = pKb + log([NH₄⁺]/[NH₃])

where [NH₄⁺] is the concentration of the ammonium ion and [NH3] is the concentration of ammonia.

Calculate the moles of HCl added

The volume of HCl added is 30.0 mL = 0.0300 L. The concentration of HCl is 1.0 M, so the moles of HCl added are:

moles of HCl = concentration x volume = 1.0 M x 0.0300 L = 0.0300 moles

Calculate the new concentrations of NH₄⁺ and NH₃

The moles of NH₄⁺ and NH₃ in the original buffer solution can be calculated as:

moles of NH₄⁺ = 0.20 M x 1.0 L = 0.20 moles

moles of NH₃ = 0.50 M x 1.0 L = 0.50 moles

When HCl is added, it reacts with NH₃ to form NH₄⁺ and Cl⁻. The amount of NH₄⁺ produced is equal to the amount of HCl added, since the reaction is 1:1. Therefore, the new concentration of NH₄⁺ is:

[NH₄⁺] = moles of NH₄⁺ / (volume of buffer + volume of HCl added)

[NH₄⁺] = 0.20 moles / (1.0 L + 0.0300 L)

[NH₄⁺] = 0.196 M

The new concentration of NH₃ can be calculated using the buffer equation:

[NH₃] = Ka x [NH₄⁺] / [H⁺]

where Ka is the equilibrium constant for the reaction NH₄⁺ + H₂O → NH₃ + H₃O⁺, which is equal to the acid dissociation constant of NH₃, Kb. Since pKb is given as 4.75, we can calculate Kb:

Kb = 10^(-pKb) = \(10^{-4.75}\)  = 1.78 x 10⁻⁵

Substituting the values we have:

[NH3] = Kb x [NH₄⁺] / [H⁺]

[NH3] = 1.78 x 10⁻⁵ x 0.196 M / \(10^{-pH}\)

[NH3] = 3.49 x 10⁻⁶ / \(10^{-pH}\)

Calculate the new pH of the buffer

Substituting the values we have into the Henderson-Hasselbalch equation:

pH = pKb + log([NH₄⁺]/[NH₃])

pH = 4.75 + log(0.196 M / (3.49 x 10⁻⁶ / \(10^{-pH}\))))

Simplifying and solving for pH:

pH = 4.75 + log(5.61 x 10⁷) + log(\(10^{pH}\))

pH = 4.75 + 7.75 + pH

pH = 12.50

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Answer:

4C4HO + 4Cl2 + 13O2 → 14CO2 + 2CCl4 + 2H2O

Explanation:

Balance The Equation: C4HO + Cl2 + O2 = CO2 + CCl4 + H2O

1. Label Each Compound With a Variable

  aC4HO + bCl2 + cO2 = dCO2 + fCCl4 + gH2O

2. Create a System of Equations, One Per Element

  C: 4a + 0b + 0c = 1d + 1f + 0g

  H: 1a + 0b + 0c = 0d + 0f + 2g

  O: 1a + 0b + 2c = 2d + 0f + 1g

  Cl: 0a + 2b + 0c = 0d + 4f + 0g

3. Solve For All Variables

  a = 4

  b = 4

  c = 13

  d = 14

  f = 2

  g = 2

4. Substitute and Verify Result

  4C4HO + 4Cl2 + 13O2 = 14CO2 + 2CCl4 + 2H2O

      L R

  C: 16 16 ✔️

  H: 4 4 ✔️

  O: 30 30 ✔️

  Cl: 8 8 ✔️

hope this helps! :D

A matter can change from one state to another by absorbing or losing energy. Some of the example of such changes are melting, boiling, freezing, etc. Here 'Ga' changes into liquid state at high temperature.

The three states of matter represents the three distinct physical forms in which matter can take in most environments. The common states of matter are solid, liquid and gas. A change of state is a physical change in the matter.

When the temperature or pressure of a system changes, then there occurs a change of state. The intermolecular interaction between the molecules increases with the increase in temperature and pressure. Similarly when the temperature decreases, molecules form a rigid structure.

Thus a change of state occurs on changing some parameters.

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