A wave has a frequency of 2.79 x103 Hz and an angular wave number of 37.6 rad/m. How far will the wave travel in 28.7 s?
Answer:13394.15 m
Explanation:
We can use the wave speed formula to solve this problem. The wave speed (v) of a wave is given by the product of its frequency (f) and wavelength (λ):
v = fλ
The angular wave number (k) is related to the wavelength by the formula:
k = 2π/λ
So we can rearrange the formulas to get:
λ = 2π/k
and
v = fλ = f(2π/k)
Substituting the given values, we get:
λ = 2π/37.6 rad/m = 0.167 m
v = (2.79 x 10^3 Hz)(0.167 m) = 466.93 m/s
Finally, we can use the formula for distance (d) traveled by a wave in time (t) to get:
d = vt = (466.93 m/s)(28.7 s) = 13394.15 m
Therefore, the wave will travel approximately 13394.15 meters in 28.7 seconds.
if star a is closer to us than star b, then star a's parallax angle is _________. larger than that of star b smaller than that of star b fewer parsecs than that of star b hotter than that of star b
The correct answer is Smaller than that of star B.
The parallax angle of a star is inversely proportional to its distance from Earth. Therefore, if star A is closer to us than star B, star A's parallax angle will be smaller than that of star B. The parallax angle is a measure of the apparent shift of a star's position when viewed from different vantage points on Earth's orbit.
Parallax is used to determine the distance to nearby stars. By measuring the parallax angle of a star, astronomers can calculate its distance using trigonometric principles. The smaller the parallax angle, the greater the distance to the star.
In the context of the question, since star A is closer to us than star B, it means that star A is at a shorter distance from Earth. Consequently, its parallax angle will be smaller compared to the parallax angle of star B, which indicates that star A is farther away from us than star B.
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Help!!
Remember W = mg, 1 kg = 2.2 lbs. S
1) If you have a 12 lbs. bag of potatoes what is its mass? What is its weight?
Answer:
5.5 KG is the mass
53.9 is the Weight
Nico vibrates an object at different frequencies. At a certain frequency, the sound gets louder and then returns to the same volume when he moves to the next frequency.
What is occurring when the sound gets louder?
The natural frequency of the object is changing.
The amplitude of the wave is doubling.
A standing wave is being generated.
Pitch is producing the louder sound.
Answer: c
Explanation: I passed the test and got this answer right
When the sound gets louder so here the standing wave should be produced.
What is a standing wave?The standing wave refers to the stationary wave that combined the two waves that should be moved in the inverse directions and contain the similar kind of the amplitude and the frequency.
Also, it leads to the interference where the waves should be superimposed and the energies should be added or canceled out.
Therefore, the third option is correct.
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A window in a skyscraper has a surface area of 3.50 m^2. Wind rushes by the outside of the window at 17.4 m/s, while inside the air is stationary. What is the DIFFERENCE IN PRESSURE between the inside and outside?
[?] Pa
The difference in the pressure between the inside and outside will be 369.36 N/m²
What is pressure?
The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.
It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.
The given data in the problem is;
dP is the change in the presure=?
Using Bernoulli's Theorem;
\(\rm \rho\frac{V^2_{12}}{2} +P_1= \rho \frac{V^2_{22}}{2} +P_2 \\\\\ P_2-P_1=\rho \frac{v_2^2-v_1^2}{2} \\\\ P_2-P_1= 1.21 \times \frac{17.4^2-0}{2} \\\\ \triangle p=369.36 \ N/m^2\)
Hence, the difference in the pressure between the inside and outside will be 369.36 N/m²
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Answer: 195.2802 → 195 for Acellus
Explanation: 0.5*1.29*17.4^2
Two identical thin rectangular sheets have dimensions 0.30 m × 0.50 m. They are both set to rotation by the same torque, but the first one rotates about an axis which lies on its 0.30 m side, while the second one rotates about an axis which lies on its 0.50 m side (Fig. 1). The first sheet reaches its final angular velocity in 8.0 s, starting from rest. How long will it take the second sheet to reach the same angular velocity, also starting from rest.
Therefore, it will take the second sheet approximately 4.63 s to reach the same angular velocity.
What is the starting velocity and final velocity formula?With a few calculations and some fundamental conceptual understanding, one can easily determine the ultimate velocity. By dividing the amount of time it took the object to move a certain distance by the overall distance, one can calculate the object's initial velocity.
For a thin rectangular sheet rotating about a plane perpendicular to one of its edges, the moment of inertia is given by:
\(I = (1/12)M(L^2 + W^2)\)
Since both sheets have the same torque causing them to rotate, the torque is the same for both sheets. The first sheet's moment of inertia is:
\(I1 = (1/12)M(0.3^2 + 0.5^2) = 0.0125M\)
The angular acceleration for the first sheet is:
α1 = τ/I1
ω1 = α1t1
Solving for α1, we get:
α1 = ω1/t1
Substituting this into the equation for angular acceleration and solving for ω1, we get:
ω1 = (τ/I1)t1
Similarly, for the second sheet, the moment of inertia is:
\(I2 = (1/12)M(0.5^2 + 0.3^2) = 0.0125M\)
The angular acceleration for the second sheet is:
α2 = τ/I2
ω2 = α2t2
Substituting in the equation for angular acceleration and solving for t2, we get:
t2 = ω2/α2
To find ω2, we can use the fact that the torque is the same for both sheets:
τ = I1α1 = I2α2
Substituting in the expressions for I1, I2, α1, and α2, we get:
\(τ = (1/12)M(0.3^2 + 0.5^2)(ω1/t1) = (1/12)M(0.5^2 + 0.3^2)(ω2/t2)\)
Canceling out the mass and torque, and solving for ω2, we get:
\(ω2 = (0.3^2 + 0.5^2)/(0.5^2 + 0.3^2)(ω1)t1\)
Substituting this into the equation for t2, we get:
\(t2 = (0.5^2 + 0.3^2)/(0.3^2 + 0.5^2)(t1)\)
Plugging in the values for t1 (8.0 s), we get:
\(t2 = (0.5^2 + 0.3^2)/(0.3^2 + 0.5^2)(8.0 s)\)
≈ 4.63 s
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Which types of changes must follow the law of conservation of mass?
Both physical and chemical changes
Neither physical nor chemical changes
Only physical changes
Only chemical changes
Answer:
Both physical and chemical changes
Answer:
Both physical and chemical changes follow the law since when the system is closed to all transfers of matter and energy, the mass of the system must remain constant over time, irrespective of the state.
Explanation:
pls mark brainliest
Si una persona conduce a 100km/h durante 6 horas, ¿que distancia recorrerá?
Answer:
600 kilometers.
Explanation:
Hope this helps!
Direction: Write TRUE if the statement is correct, and FALSE if it is not
correct
3. When light strikes a black surface, it is reflected by the surface and
nothing is absorbed.
4. Mirrors are used in telescopes because they have the ability to reflect
5. Transmission in the passing of light through some materials
-----------------------------------------------------------------------------------------------------------------
When light strikes a black surface, it is reflected by the surface and
nothing is absorbed This would be False because black absorbs the light not reflect
Mirrors are used in telescopes because they have the ability to reflect
True? Telescopes designed with mirrors avoid the problems of refracting telescopes. Because the light is reflected from the front surface only, flaws and bubbles within the glass do not affect the path of the light
Transmission in the passing of light through some materials
False? Some materials allow much of the light that falls on them to be transmitted through the material without being reflected. Materials that allow the transmission of light waves through them are called optically transparent. ... Materials which do not allow the transmission of any light wave frequencies are called opaque.
How many different license plates with 4 letters (26) followed by 2 digits (0-9) are possible if letters and digits cannot be repeated?
Answer:
26
Explanation:
edg
Two satelites, both with mass 10,000 kg, are in space about 30 m
apart. What is the force of gravity between them? Universal
Gravitational Constant: G = 6.674 x 10-11 m2/kg/s2
The force of gravity between the two satellites is approximately 2.22266667 x 10^-6 Newtons.
To calculate the force of gravity between two satellites, we can use Newton's law of universal gravitation. The formula is given as:
F = (G * m1 * m2) / r^2
where:
F is the force of gravity,
G is the gravitational constant (G = 6.674 x 10^-11 m^3/(kg s^2)),
m1 and m2 are the masses of the satellites, and
r is the distance between the centers of the satellites.
In this case, both satellites have a mass of 10,000 kg, and they are 30 m apart.
Plugging the values into the formula, we have:
F = (6.674 x 10^-11 * 10,000 * 10,000) / (30^2)
Calculating this expression, we find:
F = 2.22266667 x 10^-6 N
Therefore, the force of gravity between the two satellites is approximately 2.22266667 x 10^-6 Newtons.
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In which instrument of the following the water works as a bulb
Answer:
hydrometer
Explanation:
A hydrometer is an instrument used to determine specific gravity. It operates based on the Archimedes principle that a solid body displaces its own weight within a liquid in which it floats. Hydrometers can be divided into two general classes: liquids heavier than water and liquids lighter than water.
HELP ME PLEASE I NEED IT NOW
a) What is the value of the angle of incidence of Ray PQ on the mirror AB?
Answer:
the angle of incident is 40°
Explanation:
NQ is the normal to the mirror, therefore
angle NQA =90°
PQA = 50°
incident angle = NQA - PQA
90°- 50° = 40°
note that the angle of reflection is equal to the angle of incident
A car, initially traveling at 5 meters per second north, accelerates to 25 meters per second north in 4.0 seconds. Determine the magnitude and direction of the car's acceleration.
Answer:
a = 5 [m/s²].
Explanation:
To solve this equation we must use the following equation of kinematics.
\(v_{f} =v_{o} +a*t\)
where:
Vf = final velocity = 25 [m/s]
Vo = initial velocity = 5 [m/s]
a = acceleration [m/s²]
t = time = 4 [s]
Note: The positive sign for the acceleration in the above equation means that the car is increasing its velocity.
25 = 5 +a*(4)
25 - 5 = 4*a
20 = 4*a
a = 5 [m/s²]
How do you convert Fahrenheit to Kelvin formula?
Fahrenheit to Kelvin conversion formula: (°F - 32) * 5/9 + 273.15.
To convert from Fahrenheit to Kelvin, remove 32 from the Fahrenheit temperature, multiply the result by 5/9, and then add 273.15. This yields the temperature in Kelvin, which is the scientific community's absolute temperature scale.
It is vital to emphasise that 0 Kelvin is absolute zero, or the temperature at which all matter has no thermal energy. Thus, in scientific studies, Kelvin is employed to measure temperature, but Fahrenheit is frequently utilised in the United States. It is critical to be precise when converting temperatures from Fahrenheit to Kelvin in order to precisely measure temperature.
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I don’t know where each one goes
A force of 115.0 N is applied horizontally to a 25.0 kg box to move it across a
horizontal floor. If the box has an acceleration of 3.00 m/s2, find the coefficient of
friction.
So, the coefficient of kinetic friction approximately 0.16.
IntroductionHi ! Here I will help you to solve the problem of the coefficient of kinetic friction. When an object moving on a rough surface, there will be a frictional force called kinetic friction. Remember that friction is also a force, but reduces the value of the force acting. Kinetic friction force is affected by the normal force (N) and the coefficient of kinetic friction. The greater the value of the normal force (N) and/or the coefficient of friction, the greater the value of the kinetic friction force. The normal force is also affected by the mass and the gravity acceleration [See the attached image to see the direction of the friction force].
Formula UsedFor kinetic friction, there are the following equations that you will use in various problem conditions. However, the equation in the box is the formula you use for solve this problem.
\(\sf{\sum F = m \cdot a}\)
\(\sf{F - f_k = m \cdot a}\)
\(\boxed{\sf{\bold{F - \mu_k \cdot m \cdot g = m \cdot a}}}\)
With the following condition:
\(\sf{\sum F}\) = resultant of the force (N)F = acting force (N)m = mass of the object (kg)a = acceleration (m/s²)\(\sf{f_k}\) = kinetic friction (N)g = coefficient of the earth gravity ≈ 9.8 m/s²\(\sf{\mu_k}\) = coefficient of the kinetic frictionSolutionWe know that:
F = acting force = 115.0 Nm = mass of the object = 25.0 kga = acceleration = 3 m/s² g = coefficient of the earth gravity ≈ 9.8 m/s²What was asked ?
\(\sf{\mu_k}\) = coefficient of the kinetic friction = ... ?Step by step:
\(\sf{F - \mu_k \cdot m \cdot g = m \cdot a}\)
\(\sf{115.0 - \mu_k \cdot 25.0 \cdot 9.8 = 25 \cdot 3}\)
\(\sf{115.0 - \mu_k \cdot 245 = 75.0}\)
\(\sf{-\mu_k \cdot 245 = 75-115}\)
\(\sf{-\mu_k \cdot 245 = -40}\)
\(\sf{\mu_k = \frac{-40}{-245}}\)
\(\boxed{\sf{\mu_k \approx 0.16}}\)
ConclusionSo, the coefficient of kinetic friction approximately 0.16.
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Which of these is most directly related to the mass of an object? A. inertia B. acceleration C. velocity D. volume
Answer:
A. Inertia
Explanation:
Answer:
A inertia is directly related to mass
Explanation:
inertia
batteries need group of answer choices material to conduct charges between the electrodes. two electrodes made of different materials. activation energy to work. material to resist charges between the electrodes. two electrodes made of the same material. an electrical outlet to work.
The batteries need a material to conduct charges between the electrodes and two electrodes made of different materials.
How does a batteries work?Batteries work by converting chemical energy into electrical energy through a chemical reaction that takes place between two electrodes, which are made of different materials. The electrodes are separated by an electrolyte, a material that conducts charges between the electrodes. When the battery is connected to a circuit, electrons flow from one electrode to the other, creating an electric current.
The activation energy required for the reaction to take place depends on the type of battery and the materials used in the electrodes. The electrolyte also plays a role in the battery's performance by resisting the flow of charges between the electrodes.
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True or False. Can Metalloids conduct electricity under certain conditions?
Answer:
Conduction: Some metalloids, such as silicon and germanium, can act as electrical conductors under the right conditions, thus they are called semi-conductors. Luster: Silicon for example appears lustrous, but is not malleable or ductile (it is brittle - a characteristic of some nonmetals).
Explanation:
I am having a bit of difficulty with this lab question:
_________________________________________
The passage of an occluded front may be accompanied by widespread precipitation and little temperature change at ground level. This is because occluded fronts are a combination of (1). [one / two / three] cold/cool air mass(es), which shifts a (2). [cold / warm / hot] air mass (3). [aloft / sideways / downwards].
_________________________________________
Currently, I have my answers as follows:
1. two cool/cold air masses
2. warm
3. downwards
Could someone help me out and let me know if I am correct? Thanks!
This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.
When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.
In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.
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How much time will it take an armadillo traveling 0.1 m/s to go 2010 meters?
Answer:
20100s
Explanation:
Hello, please help:
1. A copper wire that is 1 mm thick and 30 cm long is connected to a 1 V battery. (The resistivity of copper is 1.69 x 10-8 Ω⋅m.)Find the current in the wire in [A] assuming it's at room temperature.
2. Consider a resistor (R=1000 kΩ) and a capacitor (C=1μF) connected in series. This configuration is connected in series to a battery with an emf
In constructing an open rectangular box from of material, what dimensions will result in a box of maximum volume?
To construct an open rectangular box with maximum volume, the dimensions should be such that the length, width, and height are equal.
To find the dimensions that result in a box of maximum volume, we need to consider the relationship between the dimensions and the volume of the box. Let's assume the length of the box is L, the width is W, and the height is H. Since the box is open, it does not have a top surface.
The volume of a rectangular box is given by the formula V = L * W * H. However, in this case, we have a constraint that the material used to construct the box has a fixed amount, so the total surface area of the box must be constant. The surface area of an open rectangular box is given by A = 2LW + LH + WH.
To find the dimensions that maximize the volume, we need to find the critical points of the volume function. By applying the constraint of constant surface area, we can express one of the dimensions in terms of the other two using the surface area formula. Substituting this expression into the volume formula, we obtain a function that depends on two variables. Taking the derivative of this function and setting it to zero, we can solve for the critical points.
By solving the equations, we find that the dimensions resulting in a box of maximum volume are when the length, width, and height are all equal. In other words, the box is a cube. This is because a cube maximizes the volume within the given constraints, as any deviation from equal dimensions would result in a smaller volume.
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3. What is a consideration when forcing interior walls?
A.
C.
D.
The wall coverings often hide interior metal framing.
The walls may be load-bearing and affect structural integrity.
Power tools must be used since all interior walls are reinforced.
Forcing the wall will require firefighters to work in a team of two.
Power tools must be used since all interior walls are reinforced is a consideration when forcing interior walls.
The correct option is C.
What does a load-bearing?The load of the floor or roof construction above them is supported by load-bearing walls, also referred to as "bearing walls." They are made to transfer weight from the roof to the foundation by passing through the flooring. A bearing wall, also known as a load-bearing barrier or a structural wall, supports the entire weight of the home. This wall assists in distributing the weight of the building from the roof to the base, and its loss could lead to the building collapsing.
How is a load-bearing determined?Tom proposes going up to the attic or basement to check which direction the joists run to see if a wall is load-bearing. The wall is still most likely not load-bearing if it runs parallel to the joists.
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The complete question is -
What is a consideration when forcing interior walls?
A-The wall coverings often hide interior metal framing.
B-The walls may be load-bearing and affect structural integrity.
C-Power tools must be used since all interior walls are reinforced.
D-Forcing the wall will require firefighters to work in a team of two.
What are waveform conversion circuits? 2. Where are waveform conversion circuits typically used
Waveform conversion circuits, also known as signal conversion circuits, are electronic circuits designed to convert one form of an electrical waveform into another form. Waveform conversion circuits find application in a wide range of fields where the modification, conditioning, or transformation of electrical waveforms is necessary to achieve specific objectives.
These circuits modify the characteristics of an input signal to achieve a desired output waveform. The conversion can involve changing the amplitude, frequency, phase, or shape of the waveform.
Waveform conversion circuits are used in various applications where it is necessary to transform signals to match specific requirements. Here are some common areas where waveform conversion circuits are typically used:
Audio Processing: In audio applications, waveform conversion circuits are used to modify audio signals for various purposes. This includes amplifying, filtering, equalizing, or modulating audio waveforms to enhance sound quality, remove noise, or achieve specific audio effects.
Power Electronics: Waveform conversion circuits are extensively employed in power electronics systems for converting and conditioning electrical power. These circuits are used in devices such as inverters, converters, rectifiers, and voltage regulators to transform power waveforms, adjust voltage or current levels, and ensure efficient power transfer.
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An electrical motor is used to raise an object. The object transfers 150J of useful energy when the motor is supplied with 250J of electrical energy.
A) what is total energy supplied to the motor?
B)what is the useful energy transfer?
C) what is the efficiency?
Answer:
A) 250 J
B) 150 J
C) The efficiency = 0.6 and the percentage efficiency = 60%
Explanation:
The question relates to definition of terms in energy transfer and the calculation of efficiency
The parameters of the given are;
The energy the object transfers = 150 J
The amount of electrical energy supplied to the motor = 250 J
Therefore, we have;
A) The total energy supplied to the motor = The amount of electrical energy supplied to the motor = 250 J
B) The useful energy transferred = The energy used to do work = 150 J
C) The efficiency = (Useful energy transferred (out))/(Total energy supplied (in)
\(The \ efficiency = \dfrac{Useful \ energy \ transferred \ (out)}{Total \ energy supplied \ (in)} = \dfrac{150 \, J}{250 \, J} = 0.6\)
The percentage efficiency is given as follows;
\(The \ percentage \ efficiency = \dfrac{Useful \ energy \ transferred \ (out)}{Total \ energy supplied \ (in)} \times 100\)
\(\therefore The \ percentage \ efficiency = \dfrac{150 \, J}{250 \, J} \times 100 = 0.6 \times 100 = 60\%\)
Answer:
A) 250 J
B) 150 J
C) efficiency = 0.6, percentage efficiency = 60%
Explanation:
: In the spring of 2021, the New Horizons spacecraft reached a distance of 50 astronomical units ("AU") from Earth. At that time, how many km was New Horizons from Earth? Note: One astronomical unit is the distance from the Earth to the Sun or about 150 million km. Question 3 (6 points): The planet Mars completes one orbit of the Sun in 687 days. Use scientific notation to express this time in units of seconds. You may use the character ∧
for the power of 10 , like 4.5×10 ∧
4 (4.5 times 10 to the 4 th power).
The time taken by the planet Mars to complete one orbit of the Sun is 5.94 x 10⁷ seconds.
Given information: In the spring of 2021, the New Horizons spacecraft reached a distance of 50 astronomical units ("AU") from Earth. One astronomical unit is the distance from the Earth to the Sun or about 150 million km.
Calculation: To find how many km was New Horizons from Earth, we need to multiply the distance in AU by the conversion factor. 1 AU = 150 million km 50 AU = 50 x 150 million km = 7.5 billion km Thus, the New Horizons spacecraft was 7.5 billion km from Earth in the spring of 2021. Now, let's move on to the second question. The planet Mars completes one orbit of the Sun in 687 days. We need to express this time in seconds using scientific notation.
To convert days to seconds, we need to multiply the number of days by the conversion factor. 1 day = 86400 seconds 687 days = 687 x 86400 seconds= 5.94 x 10⁷ seconds (using scientific notation) Therefore, the time taken by the planet Mars to complete one orbit of the Sun is 5.94 x 10⁷ seconds.
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Evaporation requires the particles to _____ energy.
Answer:
create
release
absorb
destroy
Answer:
Release
Explanation:
The water is heated until
Which of the following would be an example of a field force?
An example of a field force is an object that is falling freely.
What is a field force?
In the most elementary sense of the word, we define force in physics as a push or a pull. There are basically two kinds of force that acts on an object and these two kinds of force are the field force and the contact force.
When we talk about the field force, we are talking about the kind of force that does not need to make any contact with the object upon which it does act. The contact force is the force that must have to make some kind of contact with the object upon which it must act.
Thus, an object that if falling is acted upon by the earth's gravitational force so it is a field force.
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