Use the picture to answer the question.
A red striped bowling ball with 3 finger holes.


Name at least three physical properties of the bowling ball.

Use The Picture To Answer The Question.A Red Striped Bowling Ball With 3 Finger Holes.Name At Least Three

Answers

Answer 1

Answer:

The physical properties is hardness shape and color, I choose hardness because I have grabbed bowling balls before and they are very hard well there could be different types of bowling balls made of different things but I have never seen one or toughed a bowling ball that is not hard. Another physical property  I chose for the bowling ball was shape, The reason I chose shape was because the bowling ball is circle, the actual name for a 3-D circle is sphere. The last physical property for a bowling ball is color because mostly all bowling balls have color for example the one in the picture it is red with a little bit of pink, there is many different bowling balls that have different color different hardness but NOT different  shape. That is the physical properties of a bowling ball.

Explanation:

Answer 2

Answer: The bowling ball is round in shape and red in color. The bowling ball is smooth and hard.

Explanation:

did it on edge


Related Questions

In this diagram, heat energy is being added over time. The vertical axis shows an increase in temperature, and the horizontal axis shows the passage of time. What is happening to the temperature at Point B?
1. The temperature is rising as the molecules break apart from each other.
2. The temperature is not rising because the heat is being used to break the connections between the molecules.
3. The temperature is dropping as the molecules break apart from each other.
4. The temperature is not rising because the molecules are slowing down.

In this diagram, heat energy is being added over time. The vertical axis shows an increase in temperature,

Answers

Answer:

2. The temperature is not rising because the heat is being used to break the connections between the molecules.

Explanation:

I remember doing this question and this is the correct answer i just know it by heart.

just trust me by the heart

Females are theoretically more prone to anxiety disorders due to __________. A. their habit of overreacting to physiological changes B. the high levels of serotonin causing hormone imbalance C. increased levels of norepinephrine causing anxiety sensitivity D. stress levels, life experiences, and friends’ stresses Please select the best answer from the choices provided A B C D

Answers

Answer:

fluctuations in the levels of female reproductive hormones

Explanation:

Women are more prone to anxiety due to a variety of biological, psychological, and cultural factors. Although the exact cause is unknown, recent research suggests that fluctuations in the levels of female reproductive hormones and cycles play an important role in women's enhanced vulnerability to anxiety.

Answer: D. stress levels, life experiences, and friends’ stresses

Explanation:

Females are theoretically more prone to anxiety disorders due to __________. A. their habit of overreacting

This is one popular brand of exercise machine for a crossword puzzle

Answers

Answer:

Aerobics I think.

Explanation:

A vehicle, starting from rest, accelerates on a circular track with a 335m diameter.

Answers

The distance travelled by the vehicle around the circular track is 1,052.4 m.

What is the distance travelled by the vehicle in one complete cycle?

The distance travelled by the vehicle in one complete cycle is calculated by using the following equation as show below.

d = 2πr

d = πd

Where;

r is the radius of the circular trackd is the diameter of the circular track

In one complete cycle, the  vehicle will travel the circular track only once.

d = π(335 m)

d = 1,052.4 m

Thus, the distance travelled by the vehicle around the circular track is a function of the diameter of the circular track.

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The complete question is below:

A vehicle, starting from rest, accelerates on a circular track with a 335m diameter. What is the distance travelled by the vehicle when it makes one complete cycle?

A diver jumps from a 3.0 m board with an initial upward velocity of 5.5 m/s. What is the time the diver was in the air?

Answers

The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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The diagram shows a charge moving into an electric field. Two horizontal parallel plates have equally spaced vectors going from the bottom plate to the top plate. A negatively charged sphere labeled Z in traveling horizontally in between the plates. A vector is pointing right. The top plate is labeled W. There is an X at the far end of the top plate and a Y at the far end of the bottom plate. The charge will most likely leave the electric field near which letter? W X Y Z

Answers

The negatively charged sphere Z is most likely to leave the electric field near the center of plates, which is closest to letter Y.

What is an electric field?

Physical field that surrounds electrically charged particles and exerts force on all the other charged particles in the field is called an electric field.

Negatively charged sphere labeled Z will experience a force due to  electric field created by parallel plates. Since the vector is pointing right, we can assume that electric field is also pointing right.

Electric field lines are perpendicular to plates and are equally spaced. Therefore, electric field is uniform in magnitude and direction between the plates.

As the negatively charged sphere Z travels horizontally between plates, it will experience force in the direction opposite to electric field due to its negative charge. This force will cause sphere to slow down and  stop.

Since the electric field lines are equally spaced between the plates, electric field will be strongest at the edges of plates and weakest in the center. Therefore, negatively charged sphere Z is most likely to leave the electric field near the center of plates, which is closest to letter Y.

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Is this answer correct?

Is this answer correct?

Answers

Yes the answer is correct

Recording a change in which of the following would be an
example of a qualitative observation?
a velocity
b color
c force
d power
Chec

Answers

The color change would be an example of qualitative observation.

What is qualitative observation?

The approach of conducting research known as qualitative observation uses subjective methodologies to collect information or data. Although qualitative observation takes a lot longer than quantitative observation because the goal is to compare quality differences, the research is vast and much more individualized.

The five main senses—sight, smell, touch, taste, and hearing—and how they function are the topics of qualitative observation. This involves attributes rather than measures or numbers.

Hence, recording a color change would be an example of a qualitative observation.

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Convert 56,340,040 meters into scientific notation?

Answers

Answer:

5.634004 × 10^7

Explanation:

the number 7 is for the numbers before the number 5

5.6340040 x 10^7 Because the 10^7 represents the ten millions place.

Which of the following is most likely to be a secondary source

Answers

Answer:

analyze, assess or interpret an historical event, era, or phenomenon,.

Explanation:

Secondary sources are works that analyze, assess or interpret an historical event, era, or phenomenon, generally utilizing primary sources to do so. Secondary sources often offer a review or a critique. Secondary sources can include books, journal articles, speeches, reviews, research reports, and more.

If Earth were a perfect sphere, would you weigh more or less at the equator than at the poles? Explain​

Answers

Answer:

You would weigh the same.

Explanation:

At the moment, since Earth is not a perfect sphere, the Earth "bulges out" at the equator, so you're further from the centre of the Earth. Since gravity acts through a body's center of mass, the further you are from the centre the weaker the gravitational acceleration you will feel, because gravity weakens over distance.

So, you're actually lighter at the equator than you'd be at the poles.

However, if the Earth was a perfect sphere, this "bulge" at the equator would not happen, and so you would weigh the same at the poles and at the equator.

Hope this makes sense.

1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.

2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.

1. A ball is at rest on the top of a hill (see the figure).At the top of the hill, the ball will have

Answers

1. At the top of the hill, the ball will have the maximum value of its gravitational potential energy and the minimum value of its kinetic energy. As the ball rolls down the hill, its gravitational potential energy is converted to kinetic energy when it gets to the ground.

2. When dropping the object, you should drop it so its top part is initially at the height h. The initial speed of the ball will be zero since it starts from rest. To measure the time it takes for the ball to hit the ground, you should start the stopwatch when the ball leaves your hand and stop it when the ball hits the ground for the first time. It is recommended to perform multiple trials and calculate the average time to minimize errors.

Susan needs to select a material to use for creating an insulated container for
transporting chilled liquids. Based on the data in Activity B, which of the following
materials should she use to create an insulated container
glass
aluminum
Copper
steel

Answers

Answer:

Glass

Explanation:

The material that Susan needs to get an insulating container is glass. The correct option is A.

What is insulating material?

Insulation is defined as a material used to trap air and sound. Fiberglass is used in the walls and attic of a house to keep warm air in and cold air out during the winter.

Electrical insulators are used to keep conductors in place while keeping them separate from one another and from surrounding structures.

They act as a barrier between energized parts of an electric circuit, limiting current flow to wires or other conducting paths as desired.

Glass has many useful properties aside from being a good electrical insulator.

It is an excellent thermal insulator and is resistant to a wide range of corrosive chemicals. It is clear, hard, and easily colored; it can also be formed into complex shapes.

Thus, the correct option is A.

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3. A 142 g baseball is thrown at a speed of 42.9 m/s. What is the kinetic energy of the baseball at this moment?
261 )
131 )
O 6090 )
505 )
Kinetic energy (KE) is defined by the equation KE = { mu?.
Point
0
11
4. Harriet is practicing archery. As she draws back an arrow, the arrow has 34.3 of elastic notretia
have when it is about to hit the ground?

Answers

kinetic energy=1/2mv^2
=1/2(142*10^-3)(42.9)^2=130.6=131J

Answer: For question 1

131 is the correct answer

KE = 1/2 mv^2

Explanation:

What is the wavelength of a wave?

Answers

The wavelength is the spatial period of a periodic wave—the distance over which the wave's shape repeats.

Heat can be transferred by conduction when one object is in direct contact with another object. Conduction can occur in solids, liquids, or gases, but it is more effective in A. gases because their particles are moving faster. B. liquids and gases because they occur at higher temperatures. C. liquids because they have a definite volume but not a definite shape. D. solids and liquids because their particles are arranged more closely together.

Answers

Answer:

The correct answer is D. solids and liquids because their particles are arranged more closely together.

Help yea I need help

Help yea I need help

Answers

Answer is D I think....

What is one benefit to measuring your body’s flexibility?

A.
meeting the national requirement for flexibility
B.
determining your muscular strength
C.
tracking your flexibility improvements over time
D.
increasing the length of your life

Answers

Answer:

C

Explanation:

if you measure your body's flexibility then you can keep track of how flexible you have gotten over time

A wire with resistance of 8.0 Ω is drawn out through a die such that its new length is twice its original length. Find the resistance of the longer wire assuming that the resistivity and the density of the material of the wire are unchanged during the drawing process.

Answers

\(\begin{equation*} 16\text{ }\Omega \end{equation*}\)

Explanation

the electrical resistivity is define as

\(\begin{gathered} \sigma=R\frac{A}{l} \\ where \\ R\text{ is the electrical resitance} \\ \text{A is the cross seccional area} \\ l\text{ is the length} \end{gathered}\)

so,if we isolate R

\(\begin{gathered} \sigma= R\frac{A}{l} \\ R=\sigma\frac{l}{A} \end{gathered}\)

hence, the ratio of the resitances is

\(\frac{R_1}{R_2}=\frac{\sigma\frac{l}{A}}{\sigma\frac{l_2}{A}}\)

the volume of the wire is constant , therefore

\(A_1l_1=A_2l_2\)

if the new length is twice the original

The resistance of the longer wire assuming that the resistivity and the density of the material of the wire are unchanged during the drawing process is twice the resistance of the wire before, i.e. 16 Ω.

What is Resistance?

The impediment to current flow in an electrical circuit is measured by resistance. The ohm, a unit of measurement for resistance, is represented by the Greek letter omega. The name of the unit of resistance is derived from Georg Simon Ohm (1784-1854), a German physicist who studied the relationship between voltage, current, and resistance.

Given:

The resistance of the wire, R = 8 Ω.

Calculate the electrical resistivity by the formula given below,

σ = \(R\frac{A}{l}\),

Here σ is the electrical resistivity, A is the area, and l is the length of the wire.

According to Que's statement,

R₁ / R₂ = {σ₁ l₁ / A₁ } / {σ₂l₂ / A₂}

R₂ = 2 *R₁

R₂ = 2*8

R₂ = 16 Ω

Therefore, the resistance of the longer wire assuming that the resistivity and the density of the material of the wire are unchanged during the drawing process is twice the resistance of the wire before, i.e. 16 Ω.

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Arrange the steps in order to describe what happens to a gas when it cools.

Answers

Answer:

A fan pushes hot air out of a vent and into a room. The hot air displaces cold air in the room, causing the cold air to move closer to the floor.

The hot air displacing the cold air is an example of  transfer by

Explanation:

An object of mass 2kg moves in circles at radius 8m at uniform speed of 30m/s calculate. A_angular velocity B_ceritripetal force

Answers

The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.

The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.

Calculation:-

A. angular velocity ω = v/r

                                     = 30 /8

                                      = 3.75 m/s

                                     

B. Centripetal force = mv²/r

                             = 2×30²/8

                              = 225 N

There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.

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Calculate de speed of the wave

wavelength = 2.3 cm and frequency = 3.7 Hz

Answers

Given:λ= 2.3 cmf= 3.7 Hzv= ?Note that:λ: wavelength f: frequency v: velocity To find:The speed of the given wave.Solution:Wave velocity is the distance the wave travels per second or in the given amount time, which is also known as wave speed.

First we'll have to convert centimeter into meter.

\(\large\boxed{\bold{1 \: cm= 100 \: m}}\)

So we'll have to divide 2.3 cm by 100.

\(\frac{2.3}{100}\)

\(\bold{= 0.023 \: m}\)

Now, we can find the speed of the wave.\(\large \boxed{\bold{v= {f}{λ}}}\)

In this question all the values are given so we'll simply have to substitute and solve.

Let's solve!

To find the speed, we'll have to multiply the wavelength and frequency.

Substitute the values according to the formula.

\(v= 0.023\times 3.7\)

\(\large\boxed{\bold{v= 0.0851 \: m/s}}\)

Therefore, the speed of the given wave is 0.0851 m/s

A girl and her sledge have a combined mass of 40kg. She starts from rest and descends a slope which is inclined at 25 degrees to the horizontal. At the bottom of the slope the ground becomes horizontal for 15m before rising at 6 degrees to the horizontal. The girl travels 25m up the slope before coming to rest once more. There is a constant resistance to motion of magnitude 18N. Calculate the distance the girl travels down the slope.​

Answers

To solve this problem, we can use the principle of conservation of energy. According to this principle, the total mechanical energy of an object remains constant as long as there are no external forces doing work on the object.

The initial mechanical energy of the girl and sledge is the potential energy they have due to their height above the ground. This potential energy is given by the formula:

PE = m * g * h

where PE is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height above some reference point.

The final mechanical energy of the girl and sledge is the sum of their kinetic energy and potential energy at the end of their motion.

We can set up the following equation to represent the conservation of energy:

Initial PE + Initial KE = Final KE + Final PE

Since the girl and sledge start from rest, their initial kinetic energy is zero. Therefore, the equation simplifies to:

Initial PE = Final KE + Final PE

We can determine the distance the girl and sledge travel down the slope by calculating the final kinetic energy and potential energy and solving for the distance.

The final kinetic energy is given by the formula:

KE = 1/2 * m * v^2

where KE is the kinetic energy, m is the mass, and v is the velocity.

The final potential energy is given by the formula:

PE = m * g * h

where PE is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height above some reference point.

To calculate the final kinetic energy, we need to determine the velocity of the girl and sledge at the end of their motion. We can use the principle of conservation of energy to solve for the velocity.

Substituting the given values into the equation for conservation of energy, we get:

Initial PE = Final KE + Final PE

= 1/2 * 40 kg * v^2 + 40 kg * 9.8 m/s^2 * h

We can solve for the velocity by rearranging the terms and substituting the values for the mass, initial potential energy, and final potential energy:

v = sqrt((2 * (Final PE - Initial PE)) / m)

= sqrt((2 * (40 kg * 9.8 m/s^2 * h - 40 kg * 9.8 m/s^2 * h)) / 40 kg)

= 0

Since the velocity is zero, the final kinetic energy is also zero. This means that the final mechanical energy is equal to the final potential energy, which is equal to the initial potential energy.

We can therefore set up the following equation to solve for the distance the girl and sledge travel down the slope:

Initial PE = Final KE + Final PE

= 0 + Final PE

= Initial PE

This equation tells us that the initial potential energy is equal to the final potential energy. Since the girl and sledge start from rest at the top of the slope and end at rest at the bottom of the slope, the final potential energy is equal to the initial potential energy.

Therefore, the distance the girl and sledge travel down the slope is equal to the distance they travel up the slope, which is 25m.

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Answers

Answer:

A. 1.

B. 5.

C. 3.

D. 4.

E. 6.

F. 4.

Explanation:

Suppose the water at the top of Niagara Falls has a horizontal speed of 2.73 m/s just before it cascades over the edge of the falls. At what vertical distance below the edge does the velocity vector of the water point downward at a 52.9 ° angle below the horizontal?

Answers

Answer:

required vertical distance below the edge is 0.6648 m

Explanation:

Given the data in the question;

Horizontal speed of water falls v = 2.73 m/s

direction of water falls 52.9° below the horizontal

The vertical velocity must be such that;

tanθ = v\(_y\) / v\(_x\)

Now, vertical speed of water falls;

v\(_y\) = v\(_x\) × tanθ

we substitute

v\(_y\) = 2.73 × tan(52.9°)

v\(_y\) = 2.73 × 1.322237

v\(_y\) = 3.6097

Now, at the top of falls, initial speed u = 0

v² - u² = 2as

s = ( v² - u² ) / 2as

we substitute

s = ( 0² - (3.6097)² ) / (2 × 9.8)

s = 13.029934 / 19.6

s = 0.6648 m

Therefore, required vertical distance below the edge is 0.6648 m

A certain rigid aluminum container contains a liquid at a gauge pressure of P0 = 2.02 × 105 Pa at sea level where the atmospheric pressure is Pa = 1.01 × 105 Pa. The volume of the container is V0 = 2.45 × 10-4 m3. The maximum difference between the pressure inside and outside that this particular container can withstand before bursting or imploding is ΔPmax = 2.35 × 105 Pa.

For this problem, assume that the density of air maintains a constant value of ρa = 1.20 kg / m3 and that the density of seawater maintains a constant value of ρs = 1025 kg / m3.


A) The container is taken from sea level, where the pressure of air is Pa = 1.01 × 105 Pa, to a higher altitude. What is the maximum height h in meters above the ground that the container can be lifted before bursting? Neglect the changes in temperature and acceleration due to gravity with altitude.

B)What is the maximum depth dmax in meters below the surface of the ocean that the container can be taken before imploding?

Answers

The maximum height the container can be lifted before bursting is  970 meters above sea level, and the maximum depth the container can be taken before imploding is 35 meters below the surface of the ocean.

Gauge pressure is the pressure measured relative to the atmospheric pressure at a particular location. It does not take into account the atmospheric pressure and only represents the pressure above or below the atmospheric pressure.

A) To find the maximum height h in meters above the ground that the container can be lifted before bursting, we need to find the new gauge pressure at this higher altitude. We can use the relationship between pressure and altitude:

P = P0 + ρgh

where P is the gauge pressure at the new altitude, ρ is the density of air, g is the acceleration due to gravity (assumed constant), and h is the height above sea level. Solving for h, we get:

h = (P - P0) / (ρg)

We know that the maximum pressure difference the container can withstand is ΔPmax = 2.35 × 105 Pa, so the new gauge pressure at the higher altitude can be found by adding this to the sea level pressure:

P = Pa + ΔPmax = 1.01 × 105 Pa + 2.35 × 105 Pa = 3.36 × 105 Pa

Substituting this into the equation above, along with the given values for ρ and g, we get:

h = (3.36 × 105 Pa - 2.02 × 105 Pa) / (1.20 kg/m3 × 9.81 m/s2) ≈ 970 meters

So, the maximum height the container can be lifted before bursting is approximately 970 meters above sea level.

B) To find the maximum depth dmax in meters below the surface of the ocean that the container can be taken before imploding, we need to find the new gauge pressure at this depth. We can use a similar equation to the one used above, but with the density of seawater instead of the density of air:

P = P0 + ρsgd

where g is the acceleration due to gravity (assumed constant), d is the depth below the surface of the ocean, and ρs is the density of seawater. Solving for d, we get:

d = (P - P0) / (ρsg)

We know that the maximum pressure difference the container can withstand is ΔPmax = 2.35 × 105 Pa, so the new gauge pressure at the maximum depth can be found by subtracting this from the sea level pressure:

P = P0 - ΔPmax = 2.02 × 105 Pa - 2.35 × 105 Pa = -0.33 × 105 Pa

(Note that this gives a negative value for pressure, which means the container will implode rather than burst.)

Substituting this into the equation above, along with the given values for ρs and g, we get:

d = (-0.33 × 105 Pa - 1.01 × 105 Pa) / (1025 kg/m3 × 9.81 m/s2) ≈ -35 meters

So, the maximum depth the container can be taken before imploding is approximately 35 meters below the surface of the ocean.

Therefore, The container can be lifted to a maximum height of 970 meters above sea level without bursting, and it can be submerged to a maximum depth of 35 meters without imploding.

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please help (science)

Plate Boundaries on Earth
Plate boundaries represent parts of the Earth where plates come in contact with one another. There are different ways in which these plates can move and interact. In this assignment, you will identify each type of plate movement and create an illustration to represent this.

Open the worksheet to get started. Use the criteria below to see what you should include in this assignment.

Row 1: Plate Boundary (Movement)

Write the type of plate boundary: convergent, divergent, transform.

Write the correct description for each in parentheses below the name: sliding, separating, or colliding.

Row 2: Diagram

Draw a diagram or illustration of the plate movement at the plate boundary. Include arrows to show whether the plates are colliding, separating, or dividing.

Row 3: Lithosphere (Created or Destroyed)

Identify whether the Earth's crust is created or destroyed at this type of plate boundary.

Row 4: Geologic Process

Give at least one example of the type of process or geological event that occurs on the Earth when the plates move in this manner.

Row 5: Real World Example

Give at least one example of a place on the planet where this type of plate movement is demonstrated along the plate boundary. Include both the location and name of the example.

Row 6: References

This assignment requires you to conduct formal research. When researching, make sure to use only valid and reliable resources; Wikipedia, blogs, and answer sites are not valid or reliable. References must be cited in APA format. Please provide your references in APA format in this column.

please help (science)Plate Boundaries on EarthPlate boundaries represent parts of the Earth where plates

Answers

Plate Boundaries on Earth assignment involves identifying and illustrating different types of plate movements at the Earth's contact points.

Here are the steps to be followed:

Step 1: Understanding the Assignment Requirements

Read through the assignment instructions carefully to ensure a clear understanding of the tasks and expectations.

Step 2: Research

Start by conducting research on plate boundaries, their types, movements, and associated geological processes. Use reliable and valid resources such as scientific journals, textbooks, and reputable websites. Take notes on the different plate movements, their characteristics, and examples of each.

Step 3: Worksheet Setup

Create a table or chart with six rows corresponding to the six categories specified in the assignment instructions: Plate Boundary (Movement), Diagram, Lithosphere (Created or Destroyed), Geologic Process, Real World Example, and References.

Step 4: Fill in Row 1 - Plate Boundary (Movement)

In the first row, list the three types of plate boundaries: convergent, divergent, and transform. Next to each type, write the correct description in parentheses: sliding, separating, or colliding.

Step 5: Fill in Row 2 - Diagram

In the second row, draw a diagram or illustration for each type of plate movement. Use arrows to indicate the direction of movement and whether the plates are colliding, separating, or sliding past each other.

Step 6: Fill in Row 3 - Lithosphere (Created or Destroyed)

In the third row, identify whether the Earth's crust is created or destroyed at each type of plate boundary. Note the corresponding effects of plate movement on the lithosphere.

Step 7: Fill in Row 4 - Geologic Process

In the fourth row, provide at least one example of a geologic process or event that occurs as a result of plate movement at each type of boundary. This could include processes like subduction, seafloor spreading, or earthquakes.

Step 8: Fill in Row 5 - Real World Example

In the fifth row, give at least one real-world example of a location where each type of plate movement is demonstrated along a plate boundary. Include the name of the location and its corresponding plate boundary type.

Step 9: Fill in Row 6 - References

In the final row, provide the references for your research in APA format. Include the sources you used to gather information on plate boundaries, plate movements, and related geological processes.

Step 10: Review and Proofread

Review the completed assignment, ensuring that all information is accurate and properly cited. Proofread for any grammatical or spelling errors.

Note: The specific format and layout of the worksheet may vary based on your preference or instructor's instructions. Make sure to follow any specific formatting guidelines provided by your instructor.

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A large pot is placed on a stove and 1.2 kg of water at 14°C is added to the pot. The temperature of the water is raised evenly to 100°C just before it starts to boil. (a) What amount of heat is absorbed by the water in reaching 100°C? (b) The water then boils until all of it has evaporated, turning to water vapor at 100°C. How much heat does the water absorb in this process?

Answers

Answer:

a) the amount of heat absorbed by the water is 431995.2 J

b) the amount of heat absorbed during evaporation is 2712000 J

Explanation:

Given that;

mass of water Mw = 1.2 kg

Specific heat capacity of water Cw = 4186 J/kg.C

Change in temperature ΔT = final T - Initial T = 100 - 14 = 86°C

Now

A)

Heat required to raise the temperature of water is expressed as:

Q = Mw × Cw × ΔT

Q = 1.2 × 4186  × 86

Q = 431995.2 J

Therefore the amount of heat absorbed by the water is 431995.2 J

B)

Then heat absorbed during evaporation will be:

Q1 = Heat absorbed during phase change from water to steam = Mw × Lv

Lv = latent heat of vaporization of water = 2.26 × 10⁶ J/kg

so

Q1 = 1.2 × 2.26 × 10⁶ = 2712000 J

Therefore the amount of heat absorbed during evaporation is 2712000 J

what causes the coriolis effect

A. Earths orbit around the sun.
B. Wind currents.
C. Earths rotation around its axis
D. Uneven solar heating of earth

Answers

C is the correct answer


A ball is thrown upward in the air with an initial velocity of 40 m/s. How long does it take to
reach back to the point it was thrown from?

Answers

Answer:

You need the definition of acceleration (a=Vf-Vi/t) and 1 equation of linear motion (deltaX = Vi×t + 1/2×a×t^2). Since you know a is constant (gravity) and you know your initial Vi to be 40 m/s and your final velocity Vf to be zero (maximum height), then you can use thhe definition of acceleration to find time.

-9.81m/s^2 = (0-40m/s)/t

t = (-40)/(-9.81) s

t = 4.077s

Now that you have time, you should know all but deltaX in the equation of linear motion.

dX = (40m/s)(4.077s) + (1/2)(-9.81m/s^2)(4.077s)^2

dX = (163.099m) — (81.549m)

dX = 81.55m

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