Answer:
4.25248 x \(10^{6}\) μg per vial
Explanation:
Conversion Factors
28.3495231 g = 1 dry oz
\(10^{6}\) μg (micrograms) = 1 g
[(1.5 dry oz) x (28.3495231 g / 1 dry oz) x (\(10^{6}\) μg / 1 g)] / 10 vials = 4,252,428.465 μg / vial
you consider starting material a. you know that a can undergo two irreversible reactions as shown in the below reaction coordinate diagram with one reaction pathway labeled in red and one reaction pathway labeled in blue. the red path leads to product b, while the blue path leads to product c. assuming both reaction pathways occur simultaneously in competition with each other, what is the major product, and why?
Product B because it has a lower energy level than Product C's transition state, which leads to Product C.
What are reaction pathways?The series of reactions required to create a desired product are described by a reaction pathway. The distribution strategy for a product is determined by things like percentage yield. Atomic economics. reaction time. is a connected graph with chemical species as its nodes. If a reaction transfers material from one species to the other, an edge unites the two. An vector from reactant toward the product is depicted as the edge.
What role do reactions pathway ?Energy, or ATP, is created by chemical reactions within our cells. All living things require energy to survive, and Adp would be a reactant that fuels a number of other chemical reactions inside cells. Cells generate energy through a process called cellular respiration.
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The specific heat of water is 4.18 J/g•°C. How much heat does 225.0 g of water release when it cools from 85.5°C to 50.0°C?
225.0 g of water releases -33,646.125 J of heat energy when it cools from 85.5°C to 50.0°C.
To calculate the amount of heat released when water cools, we can use the formula:
Q = m * c * ΔT
Where:
Q is the heat energy in joules,
m is the mass of the water in grams,
c is the specific heat of water in J/g•°C,
ΔT is the change in temperature in °C.
Given:
m = 225.0 g
c = 4.18 J/g•°C
ΔT = (50.0°C - 85.5°C) = -35.5°C (negative because the water is cooling)
Substituting these values into the formula, we have:
Q = 225.0 g * 4.18 J/g•°C * (-35.5°C)Q = -33,646.125 J
The negative sign indicates that heat is being released by the water as it cools. Therefore, 225.0 g of water releases -33,646.125 J of heat energy when it cools from 85.5°C to 50.0°C.
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Can somebody give me 2 answers and make sure there correct thx!!!
(WILL MARK BRAINLIEST)
:D
/google or whatever u can use to answer)
Answer:
The theory of Biological Evolution makes two very bold claims about living creatures: First: All living things on earth are related. They evolved from a common ancestor. Second: The evolution of living things is powered by natural processes. Things which can be studied and understood
Explanation:
draw the products formed when the following alkene is treated with o3 followed by zn, h2o. be sure to answer all parts.
The given alkene can undergo ozonolysis in the presence of ozone (O3) followed by reduction with zinc (Zn) and water (H2O) to yield two products.
The ozonolysis reaction cleaves the double bond in the alkene and generates two carbonyl compounds, which can then be reduced by zinc to form aldehydes or primary alcohols depending on the reaction conditions.
The ozonolysis of the given alkene, 2-methyl-2-pentene, results in the formation of two carbonyl compounds: propanal and 2-methylpropanal. These carbonyl compounds can then undergo reduction with zinc and water to form the corresponding aldehydes or primary alcohols.
The reduction of propanal with zinc and water results in the formation of propan-1-ol, which is a primary alcohol. The reaction involves the addition of hydrogen atoms to the carbonyl group of propanal, followed by the removal of the resulting oxygen atom as water. The reduction of 2-methylpropanal with zinc and water results in the formation of 2-methylpropan-1-ol, which is also a primary alcohol. The reduction mechanism is similar to that of propanal, but with the addition of hydrogen atoms to the carbonyl group of 2-methylpropanal instead.
In summary, the products formed when 2-methyl-2-pentene is treated with ozone followed by zinc and water are propan-1-ol and 2-methylpropan-1-ol. These products are formed by ozonolysis of the alkene to generate carbonyl compounds, followed by reduction of the carbonyl compounds to primary alcohols with zinc and water. This reaction demonstrates the versatility of ozonolysis and reduction reactions in synthesizing aldehydes and primary alcohols from alkenes, which are important building blocks in organic chemistry.
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What does (w/w)% mean?
Answer: 2% w / w solution means grams of solute is dissolved in 100 grams of solution. ... 5% v / v solution means 5 ml of solute is dissolved 100 ml of solution.
Explanation:
so (w/w)% u would need a number to use it.
Eva buys a package of food, and the nutrition label says that
one serving is equal to 36 grams and has 110 Calories. However, the
box is printed with a label that says 0.150 pounds. If Eva eats the
whole package, how many Calories will she have consumed?
The nutrition label is the representation of the calories provided by the molecules. If Eva eats the whole package weighing 0.150 pounds then she consumed 207.9 calories.
What is a nutrition label?The nutrition label has been seen on packaged food items and is a representation of the nutrient values given by the ingredients like the fat, carbohydrates, proteins, fats, fiber, minerals, vitamins, etc. in per serving amount.
Given,
One serving weighs = 36 grams
Calories per serving = 110 calories
Total box weighs = 0.150 pounds
It is known that 1 pound = 453.592 grams
Then, 0.150 pounds = 68.03886 grams
If 36 grams = 110 calories
Then, 68.04 grams = X calories
Solving for X as:
X = (110 calories × 68.04 grams) ÷ 36 grams
X = 207.9 calories
Therefore, Eva consumes 207.9 calories.
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How do I balance this?
C12H22O11 (s) + 12O2 (g) ⇒ 12CO2 (g) + 11H2O (g)
What is the weighted average of a
bean in the sample data given?
Sample Number
of Beans
Black
Eyed Peas
Cannellini
Beans
410
90
Abundance Mass
(%)
(g)
1.32
82
18
2.94
Weighted
Average (g)
[?]
Answer: 1.6116
Explanation:
\((1.32)(0.82)+(2.94)(0.18)=\boxed{1.6116}\)
The weighted average of a bean in the given sample data is equal to 1.6116 g.
What is the Weighted Average?The weighted average can be described as a calculation that takes into account the varying degrees of importance of the numbers in a data set. Each number is multiplied by a predetermined weight in the given data set before the final calculation is made in calculating a weighted average.
A weighted average assigns weights that calculate in advance the relative abundance of each data point. A weighted average is commonly determined to equalize the frequency of the values in a data set.
Given the abundance of Black eyes peas, m₁ = 82% = 0.82
The mass of the Black eyes peas, W₁ = 1.32 g
the abundance of cannellini beans, m₂ = 18% 0.18
The mass of cannellini beans, W₂ = 2.94 g
The weighted average = m₁W₁ + m₂W₂ = 1.32× 0.82 + 2.94 ×0.18
The weighted average of a bean = 1.6116 g
Therefore, the weighted average of a bean in the sample is 1.6116 g.
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what information can you figure out about an atom using only the atomic number?
When iron (iii) oxide, Fe2O3, and aluminum are heated together at a high temperature, iron (Fe) and aluminum oxide (Al2O3) is formed
1.What is the meaning of the symbol (iii) in iron (iii) oxide?
2.Write a balanced equation for this reaction
Correct question to answer : Wine goes bad soon after opening because the ethanol CH3CH2OH dissolved in it reacts with oxygen O2 gas to form water and aqueous acetic acid CH3COOH, the main ingredient in vinegar. Calculate the moles of ethanol needed to produce 0.900mol of acetic acid. Be sure your answer has a unit symbol, if necessary, and round it to 3 significant digits.Do not answer : Ammonium phosphate ((NH4)3(PO4) is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid with liquid ammonia. Calculate the moles of ammonia needed to produce of ammonium phosphate. Be sure your answer has a unit symbol, if necessary, and round it to significant digits.
• The balanced equation for the reaction is given by:
CH3CH2OH + O2 → CH3COOH+ H2O• From the above reaction we can see that:
1 mole of ethanol (CH3Ch2OH) produces 1 mol of acetic acid(CH3COOH)
so . x mole of ethanol will produce 0.9mol of acetic acid ....(cross multiply)
xmol ethanol * 1mol acetic = 1mol ethamol* 0.9molacetic
∴ xmol ethanol = 1*0.9 /1
= 0.90 mol
• This means that, 0.90 mol of ethanol, is needed to produce 0.9mol acetic acid,.
Arrange these gases in order of solubility, NH3, N2 CO2
The correct increasing order of solubility for the given gases is: NH₃ < N₂ < CO₂
What does solubility mean?A chemical's solubility is the maximum amount of that substance that will dissolve in a specific amount of solvent at a specific temperature. Solubility has several practical applications, including water filtering, beverage manufacturing, and vitamin storage.
Why is solubility important?The ability of a medicine to dissolve is essential to its effectiveness. A drug substance could be absorbed without it, which results in limited bioavailability. Drugs with poor solubility can potentially cause problems with metabolism or permeability, interaction with other medications, or the requirement for prolonged drug release.
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A 50. 0 ml. Soap bubble is blown at standard pressure. When a thunderstorm passes later in the day, the pressure becomes 700. 0 mmHg. Will the bubble get bigger or smaller? What is its new volume?
The new volume of the soap bubble is approximately 54.29 mL. Since the volume has increased, the bubble will get bigger when the pressure drops to 700.0 mmHg during the thunderstorm.
A 50.0 mL soap bubble is blown at standard pressure. When a thunderstorm passes later in the day, the pressure becomes 700.0 mmHg. To determine if the bubble will get bigger or smaller and to find its new volume, we will use Boyle's Law, which states that P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Step 1: Convert the initial and final pressures to the same unit. The standard pressure is 1 atmosphere (atm), which is equivalent to 760 mmHg. The final pressure is given as 700.0 mmHg.
Step 2: Apply Boyle's Law. Let P1 = 760 mmHg, V1 = 50.0 mL, and P2 = 700.0 mmHg. We will solve for V2, the new volume.
760 mmHg * 50.0 mL = 700.0 mmHg * V2
Step 3: Solve for V2.
V2 = (760 mmHg * 50.0 mL) / 700.0 mmHg
V2 ≈ 54.29 mL
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1) How much heat is needed to
melt 5.40 grams of ice at its
melting point?
answer: heat needed=18,300
expanation
Convert 15.2 moles of K to atoms of K.
Answer:
\(\boxed {\boxed {\sf 9.15*10^{24} \ atoms \ K}}\)
Explanation:
To convert atoms to moles, Avogadro's Number must be used: 6.022*10²³.
This tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case it is the atoms of potassium. We can create a ratio.
\(\frac {6.022*10^{23} \ atoms \ K }{ 1 \ mol \ K }\)
Multiply by the given number of moles: 15.2
\(15.2 \ mol \ K *\frac {6.022*10^{23} \ atoms \ K }{ 1 \ mol \ K }\)
The moles of potassium cancel.
\(15.2 *\frac {6.022*10^{23} \ atoms \ K }{ 1 }\)
The denominator of 1 can be ignored.
\(15.2 * {6.022*10^{23} \ atoms \ K }{\)
Multiply.
\(9.15344*10^{24} \ atoms \ K\)
The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated that is the hundredth place. The 3 in the thousandth place tells us to leave 5.
\(9.15*10^{24} \ atoms \ K\)
In 15.2 moles of potassium, there are 9.15*10²⁴ atoms of potassium.
Hello everyone, please help me with this question.
A sample of 0.83g of an oxide of cobalt was reduced to metallic cobalt by heating in a stream of hydrogen. The mass of cobalt produced was 0.59g.
1. Find the formula of this oxide.
2. Write an equation for the reduction of this oxide.
The formula of this cobalt oxide is CoO₂, and the reduction equation is CoO₂ => Co + 4e⁻.
Reduction is the chemical manner wherein a species profits electrons or loses oxygen. this is in particular used for extracting irons from ores. Ans: discount is located in our activity, and respiration is one instance. Reduction is a day-to-day discount as it refers to the day-to-day addition of electrons, which results in a reduction in the oxidation number daily.
calculation:-
mass of cobalt oxide CoO = 0.83
after reducing to cobalt metal, mass = 0.59g.
mass of oxygen = 0.24
The formula of this oxide = CoO₂
An equation for the reduction of this oxide.
CoO₂ => Co + 4e⁻
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Glass has a hardness that is in the middle of the hardness scale What is the hardness of Glass
Hardness 9
Hardness 8
Hardress 5
tardress 10
The correct answer is option c. Glass has a hardness that is in the middle of the hardness scale. So, the hardness of Glass is 5.
Glass possess high hardness levels compared to many other materials. The majority of glass varieties are brittle in nature, which makes them susceptible to breaking. The high hardness level of glass is due to silicon dioxide's robust Si-O chemical bonds. Glass imperfections, like bubbles and such as surface flaws, like scratches, mostly affects glass strength that reduce it more as they do for other fragile materials.
The hardness of glass can be measured by "Mohs Test," that compares the "scratch hardness" of 10 reference minerals. A mineral's hardness is defined as a measure of its relative resistance to scratching. It is measured by scratching the mineral against another substance of known hardness on the Mohs Hardness Scale.
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Consider the following reaction… 5C + 2SO2 CS2 + 4CO a) How many moles of CS2 would be produced by reacting 9.50 moles of SO2 with an excess of C? _________________ b) How many grams of C would be needed to fully react 5.5 L of SO2 at STP? _________________ c) How many liters of CO can be produced from 20.0 moles of C at STP?
We first verify that the equation is balanced. We have 5 carbons (C), 2 sulfurs (S), and 4 oxygens (O) on each side of the reaction. So the reaction is balanced.
a) Now if we look at the reaction we can see that when 2 moles of SO2 react, 1 mole of CS2 is produced. That is, the ratio is 2 to 1. For each mole of SO2 half as many moles of CS2 will be produced.
So if we have 9.5 moles of SO2 we will have 9.5/2 moles, that is 4.75 moles of CS2.
Answer a) By reacting 9.50 moles of SO2 with an excess of it would be produced 4.75 moles of CS2.
Now, for the following parts of the question, we can apply the ideal gas law. This is because the reaction is in the gas phase and the law applies only to gases.
\(PV=nR_{}T\)Where,
P= Pressure at STP = 1 atm
T= Temperature at STP = 273.15K
R= Ideal law constant = 0.08206 (atm L)/(mol K)
V= Volume of the gas
n= Numer of moles
b)We clear n and we replace the known values of SO2 to find the number of moles of SO2 that react.
\(\begin{gathered} n=\frac{PV}{RT}=\frac{1at_{}m\times5.5L}{0.08206\frac{atm.L}{\text{mol}\mathrm{}K}\times273.15K} \\ n=0.24mol\text{ SO}_2 \end{gathered}\)Now, for each mole of SO2 that reacts we need 5/2 moles of C, that is 0.24x5/2=0.61 moles of C.
We use mass molar of C to calculate the grams.
Mass molar of C=12.01g/mol
Mass of C= Moles of C x Mass Molar
Mass of C= 0.61 mol x 12.01 g/mol = 7.37 g
So, To fully react 5.5 L of SO2 at STP we will need 7.37 g of C.
c)We apply the gas law again but this time we clear the volume.
We also take into account that for each mole of C, 4 moles of CO are produced, so if we have 20 moles of C we will produce 20x4=80 moles of CO.
\(\begin{gathered} V=\frac{nRT}{P} \\ V=\frac{80mol\times0.08206\frac{atm.L}{mol.K}\times273.15K}{1atm} \\ V=\text{ 1793.18 L} \end{gathered}\)So, from 20.0 moles of C at STP can be produced 1793.18 liters of CO
molatilty is measured by using what units? A) g B) L C) Kg D) m
Molality is a measure of concentration and is defined as the number of moles of solute per kilogram of solvent. Molality is typically represented by the symbol "m" and is expressed in the unit of moles per kilogram (mol/kg). Therefore, the correct answer is D) m.
Molality (not molatilty) is indeed a measure of concentration, specifically the amount of solute per kilogram of solvent. It is denoted by the symbol "m" and is expressed in units of moles of solute per kilogram of solvent (mol/kg).
Molality is different from molarity, which is another concentration unit that expresses the amount of solute per liter of solution (mol/L or M).
To clarify, molality is measured in moles of solute (not solvent) per kilogram of solvent (not solute). Therefore, the correct answer is D) m (moles per kilogram).
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Identify the precipitate(s) of the reaction that occurs when asilver nitrate solution is mixed with a sodium chloridesolution.
sodium nitrate
silver chloride
sodium chloride
silver nitrate
When a silver nitrate solution is mixed with a sodium chloride solution, a chemical reaction takes place that results in the formation of a white precipitate of silver chloride.
This precipitate forms because silver ions from the silver nitrate solution combine with chloride ions from the sodium chloride solution to form insoluble silver chloride. This reaction is known as a double displacement reaction, and the balanced chemical equation for it is:
\(AgNO_3 + NaCl --> AgCl + NaNO_3\)
The remaining products of the reaction, sodium nitrate and soluble silver nitrate, stay in solution and do not form a precipitate. The formation of silver chloride precipitate is a common reaction used in laboratory experiments to identify the presence of chloride ions in a sample. Overall, the reaction between silver nitrate and sodium chloride results in the formation of silver chloride precipitate, which is insoluble and readily visible.
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EXERCISE 3: WHAT DOES pCO2 CHANGE? - When pCO
2
increases, the concentration of total CO
2
dissolved in water - When pCO
2
increases, the concentration of only CO
2
dissolved in water - When pCO
2
increases, the pH - Which form of dissolved CO
2
is most common in water? Ocean acidification is the decrease in pH due to increasing atmospheric CO
2
concentration.
2
. Choose the correct word option in the statements below: - An organism that needs CO
2
is likely to fare better / worse under ocean acidification. - An organism that needs HCO
3
- is likely to fare better/worse under ocean acidification. - An organism that needs CO
3
2−
is likely to fare better/worse under ocean acidification.
pCO2 is an important factor that affects various aspects of water chemistry and the impacts of ocean acidification. When pCO2 increases, the concentration of total CO2 dissolved in water also increases. This leads to changes in pH, which decreases due to increasing atmospheric CO2 concentration.
When pCO2 rises, the concentration of only CO2 dissolved in water increases. The dissolved CO2 forms carbonic acid, which contributes to the acidification of the ocean. This increase in CO2 affects the equilibrium between CO2, HCO3-, and CO3^2-, shifting it towards higher levels of dissolved CO2 and H+ ions, resulting in a lower pH.
In terms of the impacts of ocean acidification on different organisms, the effects can vary depending on their specific needs. An organism that requires CO2 is likely to fare better under ocean acidification since the increase in dissolved CO2 can provide them with a favorable environment. However, organisms that rely on HCO3- or CO3^2- may fare worse under ocean acidification, as the lower pH interferes with the availability of these carbonate ions, which are essential for shell formation and calcification in some marine organisms.
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Explain how to arrange the following in increasing order of atomic size/radius: Al, C, Si
Answer:
C, Si, Al
Explanation:
We use periodic trends to help us find the atomic radii. The trend for atomic radii on the Periodic Table of Elements is down and to the left. So whichever elements are furthest to the left and farthest down have the largest atomic radii.
what protic solvent for sn1 master organic chemistry?
Some common protic solvents used in SN1 reactions include water, alcohols, and carboxylic acids.
In organic chemistry, SN1 reactions are a type of substitution reaction that occurs in a protic solvent.
A protic solvent is a solvent that has a hydrogen atom bonded to an electronegative atom, such as oxygen or nitrogen. This allows the solvent to form hydrogen bonds with the reactants and stabilize the transition state of the reaction.
These solvents are able to stabilize the carbocation intermediate that is formed during the reaction, which helps to increase the reaction rate.
It is important to note that the choice of solvent can have a significant impact on the rate and outcome of the reaction. For example, a polar protic solvent like water will favor the SN1 reaction, while a polar aprotic solvent like acetone will favor the SN2 reaction.
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what is the name of the covalent compound N5Cl8
Answer:
Did you put that in right because i've never heard of a compound called that nor is there a compound called that on the internet
Explanation:
You must of put that in wrong
for a c-br bond that is oriented with the bromide to the right of the carbon, where does the nucleophile have to attack from?
Electrophiles (electron-deficient species capable of removing electrons from electron-rich centers), such as HBr, attack carbon-carbon double bonds, such as butene.
Who or what is a nucleophile?
By sacrificing two electrons, a chemical species in chemistry known as a nucleophile forms bonds. Any molecule or ion with a free pair of electrons or at least one pi bond is referred to as a "nucleophile." Lewis bases are nucleophiles because they provide
What are an example of a nucleophile?
A reactant known as a nucleophile provides an electron pair in order to create a covalent bond. Typically, a nucleophile has a negative charge or is neutral with one or two donateable electrons. Some examples include H2O, -OMe, or -OtBu. The species with a lot of electrons is a nucleophile overall.
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the decolorizer in the acid-fast stain is ___ and the counterstain is _____. acid alcohol; carbolfuchsin methylene blue; acid alcohol acid-alcohol; methylene blue acetone/alcohol; methylene blue
The decolorizer in the acid-fast stain is acid-alcohol, and the counterstain is methylene blue.
In the acid-fast stain, acid-alcohol is used as the decolorizer. It plays a crucial role in removing the primary stain (carbolfuchsin) from non-acid-fast cells while leaving the acid-fast cells stained. This helps differentiate acid-fast bacteria from non-acid-fast bacteria or other cellular components.
After decolorization, methylene blue is used as the counterstain in the acid-fast stain. It provides contrast to the acid-fast cells that retained the primary stain and were not decolorized, allowing them to be easily visualized and distinguished.
In the acid-fast stain, the decolorizer used is acid-alcohol, which selectively removes the primary stain from non-acid-fast cells. The counterstain employed is methylene blue, which helps visualize the acid-fast cells that retained the primary stain. This staining technique is commonly used to detect acid-fast bacteria, such as Mycobacterium tuberculosis, in clinical and microbiological settings.
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Which commercial technology commonly uses plasmas?
a radio
a race car
a television
a microwave oven
The correct answer is C. A television
Explanation:
Plasma is a particular state of matter that differs from liquid, solid, and gas because plasma is a gas but contains mainly particles that have lost their electrons or ions. This makes plasma have properties other states do not have. Additionally, plasma is now widely used in technologies, including televisions, this is because plasma is used in thousands of small containers to create the images in a Tv. This leads to high quality and precise images. Therefore, the commercial technology that commonly uses plasmas is a television.
Answer:
c
Explanation:
edge
What did you notice about the structures of the different hormones responsible for different emotions?
Different hormones responsible for different emotions have different structures. Hormones are responsible for regulating different emotional states in humans, including love, fear, stress, and anxiety. Hormones have different structures that determine their function in the body. For example, cortisol has a more complex structure than adrenaline and noradrenaline, and it is responsible for controlling the body's stress response system.
Hormones are the chemicals produced by different glands in the body, including the pituitary gland, adrenal gland, and hypothalamus, among others. Hormones are responsible for various emotions, including love, stress, fear, and anxiety, among others. In this sense, hormones are critical in regulating the emotional state of individuals. Hormones, however, have different structures, depending on the type of hormone. The structures are essential in the determination of the hormone's function in the body, including the emotions they elicit.
The different hormones responsible for different emotions have different structures. For example, adrenaline and noradrenaline have similar structures and are responsible for eliciting the fight or flight response in humans. Adrenaline and noradrenaline are both produced by the adrenal gland. Another hormone that is responsible for stress is cortisol, produced by the adrenal gland. Cortisol has a more complex structure than adrenaline and noradrenaline and is responsible for controlling the body's stress response system.
The hormone oxytocin is responsible for love and social bonding. Oxytocin is produced in the hypothalamus and released into the bloodstream. It has a peptide structure and is responsible for eliciting the feeling of love and social bonding. The hormone dopamine, on the other hand, is responsible for the feeling of pleasure and reward. Dopamine is produced in the brain, and it has a similar structure to adrenaline and noradrenaline.
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a furnace dedicated to paper (assume pure cellulose, c 6 h 10 o 5 ) operates with air. how much (g) air is required to burn 1 g of paper?
The amount of air required to burn 1 gram of paper is 17.22 grams. This is because paper is made up of pure cellulose which is a compound of 6 carbon atoms, 10 hydrogen atoms, and 5 oxygen atoms (C6H10O5).
To burn this compound, the oxygen from the air must combine with the carbon and hydrogen atoms from the paper. For every 1 mole of C6H10O5, 12 moles of oxygen are required.
Since 1 mole of oxygen has a mass of 32 grams, 12 moles of oxygen would have a mass of 384 grams.
Since 1 gram of paper has 1 mole of C6H10O5, 384 grams of oxygen is required to burn 1 gram of paper.
Since air is composed of approximately 21% oxygen, the amount of air required to burn 1 gram of paper is 17.22 grams (384/21 = 17.22).
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When an aqueous NaCl solution is electrolyzed, how many faradays need to be transferred at the anode to release 0.150 mol of Cl, gas? 201 (aq) → C12(8)+2e 8. How long must a current of 0.25 A pass through a sulfuric acid solution to liberate 0.400 L of H2 gas at STP? D o ndoo Do
The current of 0.25 A must pass through the sulfuric acid solution for approximately 13,748 seconds (or approximately 3.82 hours) to liberate 0.400 L of H₂ gas at STP.
To determine the number of faradays required to release 0.150 mol of Cl₂ gas at the anode during the electrolysis of an aqueous NaCl solution, we can use Faraday's law of electrolysis.
The balanced half-reaction at the anode during the electrolysis of an aqueous NaCl solution is:
2Cl⁻(aq) -> Cl₂(g) + 2e⁻
From the balanced equation, we can see that 2 moles of electrons are required to produce 1 mole of Cl₂ gas. Therefore, to produce 0.150 mol of Cl₂ gas, we would need to transfer 0.150 x 2 = 0.300 moles of electrons.
1 mole of electrons represents 1 faraday of charge (1 mole of electrons = 96,485 C or 1 F). Therefore, to release 0.300 moles of electrons, we would need 0.300 faradays of charge.
So, 0.300 faradays need to be transferred at the anode to release 0.150 mol of Cl₂ gas.
Regarding the second question, to calculate the time required for a current of 0.25 A to liberate 0.400 L of H₂ gas at STP (Standard Temperature and Pressure), we need to use the concept of Faraday's law and the molar volume of a gas at STP.
The balanced half-reaction for the liberation of H₂ gas during electrolysis is:
2H⁺ + 2e⁻ -> H₂
From the balanced equation, we can see that 2 moles of electrons are required to produce 1 mole of H₂ gas. Therefore, to produce 0.400 L of H₂ gas at STP (which is equivalent to 0.400/22.4 = 0.0179 moles), we would need to transfer 0.0179 x 2 = 0.0358 moles of electrons.
Using Faraday's law, 1 mole of electrons represents 1 faraday of charge (1 mole of electrons = 96,485 C or 1 F). Therefore, to transfer 0.0358 moles of electrons, we would need 0.0358 faradays of charge.
To calculate the time (t) required for this charge to pass through the solution, we can use the equation:
Q = I * t
Where Q is the charge (in coulombs), I is the current (in amperes), and t is the time (in seconds).
Converting the current to coulombs:
0.25 A * t = 0.0358 F * 96,485 C/F
Solving for t:
t = (0.0358 F * 96,485 C/F) / 0.25 A
t ≈ 13,748 seconds (or approximately 3.82 hours)
Therefore, a current of 0.25 A must pass through the sulfuric acid solution for approximately 13,748 seconds (or approximately 3.82 hours) to liberate 0.400 L of H₂ gas at STP.
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0.300 faradays need to be transferred at the anode to release 0.150 mol of Cl gas.
To determine the number of faradays needed to release 0.150 mol of Cl gas at the anode, we can use Faraday's laws of electrolysis.
First, we need to determine the number of moles of electrons required to release 0.150 mol of Cl gas. From the balanced equation:
2 Cl-(aq) → Cl2(g) + 2e-
We can see that 2 moles of electrons are required to release 1 mole of Cl2 gas. Therefore, the number of moles of electrons required to release 0.150 mol of Cl gas is:
0.150 mol Cl * (2 mol e-/1 mol Cl) = 0.300 mol e-
Next, we can use Faraday's first law to determine the number of faradays required. Faraday's first law states that the amount of substance produced or consumed is directly proportional to the quantity of electricity passed. One faraday is equal to the charge of one mole of electrons, which is approximately 96,485 coulombs.
Therefore, the number of faradays required is:
0.300 mol e- * (1 faraday/1 mol e-) = 0.300 faradays
So, 0.300 faradays need to be transferred at the anode to release 0.150 mol of Cl gas.
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