Two students measured the length of the same stick, each using a different 30 cm ruler. One student reported a length of 22 cm, and the other reported a length of 8 cm. The most likely explanation for the difference in the reported values is that one —

A. *student improperly read the ruler

B. ruler was metal and the other ruler was plastic

C. student viewed the ruler from a different angle

D. ruler was constructed with nonstandard cm marks

The two molecules that best complete the reactants' side of the equation\(CO_2\) + 2\(H_2O\) are \(O_2\) and CO.

The correct answer would be \(O_2\) and CO.

Based on the partial chemical equation provided, \(CO_2\) + 2\(H_2O\), we need to select two molecules that complete the reactants' side of the equation while also considering the conservation of mass. Let's evaluate the given options:

1. \(NaCl_3\): This compound, sodium trichloride, does not contain carbon (C) or oxygen (O) atoms, which are required to balance the equation. Therefore, \(NaCl_3\) is not a suitable choice.

2. \(HS_4\): This compound, hydrogen tetrasulfide, also does not contain carbon (C) or oxygen (O) atoms necessary to balance the equation. Hence, \(HS_4\) is not the correct choice.

3. \(CH_4\): This molecule, methane, consists of one carbon atom (C) and four hydrogen atoms (H). It contains carbon but lacks oxygen atoms required for balancing the equation. Thus, \(CH_4\) does not complete the reactants' side.

4. \(O_2\): Oxygen gas (diatomic oxygen) is represented by\(O_2\). It contains two oxygen atoms, which helps balance the equation since there are two oxygen atoms on the product side (2\(H_2O\)). \(O_2\) is a valid choice for completing the reactants' side.

Considering the conservation of mass, we still need a molecule that contains carbon. Among the given options, CO is the only molecule that consists of one carbon atom (C) and one oxygen atom (O). By adding CO to the reactants' side, we balance both carbon and oxygen atoms in the equation.

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The increase in temperature of the bullet in degrees C is 87.17

Define Specific Heat Capacity?

When a material's temperature rises by 1 K (or 1 °C), or when its mass increases by 1 kg, the specific heat capacity is defined as the amount of heat (J) absorbed per unit mass (kg).

This measurement is expressed as J/(kg K) or J/(kg °C).

The heat that is transferred to the bullet as a result of the conversion of kinetic energy to heat is what causes the bullet's temperature to rise.

                                          Q = cm T,

where Q is the energy transferred, c is the substance's specific heat, m is its mass, and T is the temperature change, describes this relationship.

Given,

mass = 2.7 x 10^-3 kg

speed = 202 m/s

C = 234 J/kg/C.

The kinetic energy of the travelling bullet is,

1/2 m(v^2) = 1/2 x 2.7 x 10^-3 x 202 x 202

                 = 55.08 J

Energy that raises the temperature = 55.08 J

This is equal to mCΔT

Equalising the 2 energies,

55.08 = mCΔT

ΔT = 55.08 / mC

      = 55.08 / 2.7 x 10^-3 x 234

      = 87.17

Hence, the increase in temperature of the bullet in degrees C is 87.17

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Answer:

jack has done more work pulling more weight and Jill has more power.

Explanation:

The length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.

Given data: r = 0.2 mm = 0.2 x 10^-3m Resistivity = 3 x 10^-6 ohm R = 15.552 ohm

Formula Used: Resistivity (ρ) = (RA)/L

Where, R is resistance, A is the area of cross-section, L is the length of the wire.

Resistance (R) = ρ (L/A)

Multiplying A on both sides, we get

Resistance (R) x A = ρ L ... equation (1)

Area of the cross-section of a wire of radius (r) is given by, A = πr^2

where, π is a constant whose value is 3.14

Substituting the given values, we get

A = πr^2= π (0.2 x 10^-3m)^2= 1.2566 x 10^-7 m^2

Substituting the values of R, A and ρ in equation (1), we get

Length of wire (L) = (Resistance x Area) / Resistivity= (15.552 ohm x 1.2566 x 10^-7 m^2) / (3 x 10^-6 ohm)= 6.5268 m

Therefore, the length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.

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Answer:

i think this may help you

Explanation:

In an inelastic collision the total kinetic energy after the collision is not equal to the total ... If there are no net forces at work (collision takes place on a frictionless surface ... Momentum is equal to the product of mass and velocity. ... bodies before the collision is equal to the total kinetic energy of the bodies after the collision.

Answer:

C 1 degree

Explanation:

Divorce is viewed negatively by functionalists from a macro perspective. A functionalist would blame divorce on the breakdown of social structures rather than looking at the persons involved. Some of the structures that  have evolved over the years leading to the rise in divorce rates according to Functionalists is the increasing erosion of the traditional role of men and women in the society.

According to conflict theorists, divorce is the consequence of a disagreement over resources in a marriage.

Conflict theory holds that the disintegration of marriage occurs from rivalry for resources and authority within the marriage, just as it does in a society when groups compete for limited resources.

Choices, according to symbolic interactionists, are based on learnt behavior.

Symbolic interactionists believe divorce is the consequence of two persons affected by their friends and family members.

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The two equally charged particles are about 651 m apart from each other.

The Coulomb's inverse-square law, sometimes known as Coulomb's law, is an experimental physical principle that measures the force exerted between two electrically charged particles that are stationary. Common names for the electric force between two charged objects at rest include electrostatic force and Coulomb force.

The inverse square dependency of electric force is represented by Coulomb's law. Additionally, the law is accurately used in the proofs of Magnus' law for general instances. Coulomb's law's vector form is crucial since it describes the direction of the electric fields created by charges.

Briefing:

Coulomb's law, force of attraction/repulsion

F = kQ₁Q₂/r²

Q₁ and Q₂ are the charges in coulombs

r is separation in meters

k = 8.99e9 Nm²/C²

Here, Q1 = Q2 = Q

So,

F = kQ² / r²

r = Q/√(F/k)

⇒ r = 5/√(4.3/8.99e9)

⇒ r = 650.79 m

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The height of the hill is approximately 0.128 meters.

The total energy of the ball at the top of the hill is equal to its kinetic energy:

E_top = K = 15 J

At the bottom of the hill, the total energy of the ball is the sum of its kinetic and potential energies:

E_bottom = K + U = 70 J + 5 J = 75 J

The potential energy of the ball at the top of the hill is zero, since it is at the highest point. Therefore, the potential energy at the bottom of the hill is:

U = E_bottom - K = 75 J - 70 J = 5 J

The potential energy of an object at a height h is given by:

U = mgh

where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2), and h is the height. Rearranging this equation gives:

h = U/(mg)

Substituting the values given in the problem, we get:

h = 5 J / (4 kg * 9.8 m/s^2) ≈ 0.128 m

Therefore, the height of the hill is approximately 0.128 meters.

What is kinetic energy?

Kinetic energy is the energy possessed by a moving object due to its motion. It is defined as the energy an object has by virtue of its motion, and is directly proportional to the mass of the object and the square of its velocity (speed).

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A transverse wave moves perpendicular to the particle vibration, while a compressional wave moves parallel to the particle vibration. Light waves are an example of a transverse wave, and sound waves are an example of a compressional wave.

A transverse wave is a type of wave in which the particles of the medium vibrate perpendicular to the direction of the wave's propagation. This means that as the wave moves forward, the particles move up and down or side to side. An example of a transverse wave is a light wave. When light travels through space, the electric and magnetic fields oscillate perpendicular to the direction of the wave.
A compressional wave is a type of wave in which the particles of the medium vibrate parallel to the direction of the wave's propagation. This means that as the wave moves forward, the particles move back and forth, creating compressions and rarefactions in the medium. An example of a compressional wave is a sound wave. When sound travels through air, the molecules of air vibrate back and forth, creating areas of high pressure (compressions) and low pressure (rarefactions).
In summary, a transverse wave moves perpendicular to the particle vibration, while a compressional wave moves parallel to the particle vibration. Light waves are an example of a transverse wave, and sound waves are an example of a compressional wave.

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Explanation:

To determine the velocity and pressure head at position B in a horizontally converging pipe, we can use the principle of conservation of mass and Bernoulli's equation.

According to the principle of conservation of mass, the mass flow rate remains constant throughout the pipe. Therefore, we can write:

A₁V₁ = A₂V₂

where A₁ and A₂ are the cross-sectional areas at positions A and B, respectively, and V₁ and V₂ are the velocities at positions A and B, respectively.

Given:

A₁ = (π/4)(d₁)² = (π/4)(200 cm)² = 31416 cm²

A₂ = (π/4)(d₂)² = (π/4)(150 cm)² = 17671 cm²

V₁ = 2 m/s

We can calculate V₂ using the equation:

V₂ = (A₁V₁) / A₂

Substituting the values:

V₂ = (31416 cm² * 2 m/s) / 17671 cm² ≈ 3.54 m/s

Therefore, the velocity at position B is approximately 3.54 m/s.

Next, to determine the pressure head at position B, we can use Bernoulli's equation:

P₁ + (1/2)ρV₁² + ρgh₁ = P₂ + (1/2)ρV₂² + ρgh₂

Assuming the datum is at position B, where the pressure head (h₂) is zero, the equation simplifies to:

P₁ + (1/2)ρV₁² + ρgh₁ = P₂ + (1/2)ρV₂²

Given:

g = 10 m/s² (acceleration due to gravity)

Z = 0 m (datum)

ρ = density of the liquid (not given)

Since the density (ρ) of the liquid is not provided, we cannot determine the absolute pressure at position B or calculate the pressure head. The information given is insufficient to determine the pressure head at position B.

In summary:

- The velocity at position B is approximately 3.54 m/s.

- The pressure head at position B cannot be determined with the given information.

The correct answer is :

Here 100 N force is applied to make the box move with constant velocity from rest. That means 100 N force is applied to overcome the limiting  static friction and as soon as 100 N force is applied it starts moving.

Now,

Constant velocity means acceleration = 0

Net force acting on the box =mass × accelaration = mass × 0 = 0

Conceptually it is zero as it is balanced by kinetic friction which has equal value that of applied force. Because net force =Applied force - friction force and hence here friction force =applied force.

If there was any accelaration then there would exist a net force and then frictional force and applied force will be the same.  

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Answer:

    v₂ = 63.62 m / s

Explanation:

For this exercise in fluid mechanics we will use Bernoulli's equation

         P₁ + ρ g v₁² +  ρ g y₁ = P₂ +  ρ g v₂² +  ρ g y₂

where the subscript 1 refers to the inside of the wing and the subscript 2 to the top of the wing.

We will assume that the distance between the two parts is small, so y₁ = y₂

        P₁-P₂ =  ρ g (v₂² - v₁²)

pressure is defined by

        P = F / A

we substitute

        ΔF / A =  ρ g (v₂² - v₁²)

         v₂² = \(\frac{\Delta F}{A \ \rho \ g} + v_1^2\)

suppose that the area of ​​the wing is A = 1 m²

we substitute

         v₂² = \(\frac{1000}{1 \ 1.29 \ 9.8} + 63^2\)

         v₂² = 79.10 + 3969

         v₂ = √4048.1

         v₂ = 63.62 m / s

Tension in the left cable is 4395.9 N.

Tension is defined as a pulling force that acts along the length of a flexible medium like rope or cables.

Here,

The total mass of the riders is given, m = 330 kg

Let the tension in the left cable be T₁ and that in the right cable be T₂.

From the figure,

T₁ cos 15 = T₂ cos 26

T₁ = T₂ cos 26/cos 15

Also,

T₁ sin15 + T₂ sin 26 = mg

Substituting values,

(T₂ cos 26/cos 15) sin 15 + T₂ sin 26 = 330x 9.8

0.241 T₂ + 0.438 T₂ = 3234

0.679 T₂ = 3234

T₂ = 4762.8 N

Therefore, Tension in the left cable, T₁ = 0.930x 4762.8

         T₁ = 4395.9 N

Hence, The tension in the left cable is 4395.9 N

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Your question was incomplete. Attaching the image here.

Answer:

a. 0.849 micro farad

b. 2.89 s

Explanation:

a) V=V0 e^-t/RC

3=12*e^-4/3.4*10^6*C

3/12=e^-4/3.4*10^6*C

-1.3863 =-4/3.4*10^6*C

C=8.49*10^-7 F

=0.849 micro farad

B) time constant= R*C

=3.4*10^6*8.49*10^-7

=2.89 S

a. The capacitance is 0.849 micro farad

b. The  time constant of the circuit is 2.89 s

a)

We know that

V=V0 e^-t/RC

3=12*e^-4/3.4*10^6*C

3/12=e^-4/3.4*10^6*C

-1.3863 =-4/3.4*10^6*C

C=8.49*10^-7 F

=0.849 micro farad

B)

Now

time constant= R*C

=3.4*10^6*8.49*10^-7

=2.89 S

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Answer:

Ribosomes

Explanation:

thy are the sites in a cell in which protein synthesis takes place. cells have many ribosomes, and the exact number depends on how active a particular cell in synthesizing proteins.

The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.

The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula

W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.

Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.

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Answer:

d. 268 s

Explanation:

Constant Speed Motion

An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

\(\displaystyle v=\frac{d}{t}\)

Where  

v = Speed of the object

d = Distance traveled

t  = Time taken to travel d.

From the equation above, we can solve for d:

d = v . t

And we can also solve it for t:

\(\displaystyle t=\frac{d}{v}\)

Two cars are initially separated by 5 km are approaching each other at relative speeds of 55 km/h and 12 km/h respectively. The total speed at which they are approaching is 55+12 = 67 km/h.

The time it will take for them to meet is:

\(\displaystyle t=\frac{5}{67}\)

t = 0.0746 hours

Converting to seconds: 0.0746*3600 = 268.56

The closest answer is d. 268 s

Answer:

1. High Illiteracy Rate in a Nation has a Negative Impact on the Conducting of Census

2.Corruption Interferes with Census

3.Traditional and Religious Beliefs can Interfere with the Census Exercise

4.insufficient and Ineffective Census Educational Campaign

5.Insufficient Census Experts

Explanation:

Answer:

Explanation:

F = kx = 65 N/m(0.94 m) = 61.1 = 61 N

This question involves the concept of the centripetal force.

The largest value that r can have is "2.16 m".

In order for the car to remain in contact with the track all the time, the weight of the car must be equal to the centripetal force acting on the car.

\(Weight = Centripetal\ Force\\\\mg = \frac{mv^2}{r}\\\\g = \frac{v^2}{r}\\\\r = \frac{v^2}{g}\)

where,

r = radius = ?

v = speed = 4.6 m/s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

\(r = \frac{(4.6\ m/s)^2}{9.81\ m/s^2}\)

r = 2.16 m

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The attached picture illustrates the centripetal force.

Answer: The depth of the ocean is 650 feets at the bottom of the sunlight zone.

The distance travelled by echo sound is given by the formula -

Speed = 2×distance/time

So, calculating the speed of sound from the formula using distance and time

Speed = 2×25/(1/100)

Speed = 50×1000

Speed of sound = 5000 feet/second

Now, calculating the distance or depth of ocean at the bottom of the sunlight zone -

Distance = (speed×time)/2

Distance = (5000×26/100)/2

Distance = 1300/2

Distance = 650 feets

Hence, the depth of ocean is 650 feets.

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Answer:

We can start by using the formula:

distance = speed x time

where distance is twice the depth of the ocean at the bottom of the Sunlight Zone (since the pulse travels down to the seafloor and then back up), speed is the speed of sound in water, and time is the round-trip time of the pulse.

The speed of sound in water is approximately 1,500 meters per second (or 4,921 feet per second).

Converting the round-trip time to seconds, we have:

26 seconds - 1 second = 25 seconds

Substituting the values into the formula:

2 x depth = 4,921 feet/second x 25 seconds

2 x depth = 123,025 feet

depth = 61,512.5 feet

Therefore, the ocean at the bottom of the Sunlight Zone is about 61,512.5 feet deep.

Answer:

Established in 1972 by the McMahon Government, the institute's primary function is research for sustainable use and protection of the marine environment. The Institute investigates topics from broad-scale ecology to microbiology.

Answer:

c is the answer,................

The required length of the base of larger flag when other sides are specified is calculated to be 6.25 ft.

The given two triangles are the flags of two different sizes. The lengths of various sides are specified.

The length of the base of the larger flag is to be found out.

The given two angles in small flag are equal to the corresponding angles in the large flag.

Two flags are the similar triangles as they look proportionate.

Both triangles' edges are proportional to one another.

So, from the figure, 4/5 = 5/x

x = 25/4 = 6.25 ft

Thus, the required x on the base of bigger flag is 6.25 ft

The given question is incomplete. The figure is missing. It is attached in the figure below.

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Answer:

5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.

Explanation:

We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.

Plugging in the values:

(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)

Simplifying:

24 kg m/s = 2 kg v1f + 6 kg v2f

Conservation of kinetic energy:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

Plugging in the values:

(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2

Simplifying:

144 J = 1 kg v1f^2 + 3 kg v2f^2

Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:

v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f

Plugging this into the second equation:

144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2

Simplifying and solving for v2f:

144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2

144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2

6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0

Dividing by 6 kg:

v2f^2 - 12 kg m/s v2f + 24 J/kg = 0

Using the quadratic formula:

v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)

v2f = [12 kg m/s ± sqrt(96) m/s]/2

v2f = 6 kg m/s ± 2sqrt(6) m/s

v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s

Plugging these values into the equation we found for v1f:

v1f = 12 m/s - 3v2f

v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s

Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:

v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s

Answer:

Electromagnetic Induction by a Moving Magnet

Then the action of moving a coil or loop of wire through a magnetic field induces a voltage in the coil with the magnitude of this induced voltage being proportional to the speed or velocity of the movement.

Explanation:

Answer:

The acceleration of an item is proportional to the net force exerted on it and inversely proportional to its mass. When the force pushing on an item rises, so does the object's acceleration. The acceleration of an item decreases as the mass of the thing increases.

If the force on an object remains constant, increasing mass will decrease acceleration. In other words, force and acceleration are directly proportional, while mass and acceleration are inversely proportional. ( How Newton's Laws of Motion Work" 29 July 2008.)

If the mass of an object is held constant, increasing force will increase acceleration. If the force on an object remains constant, increasing mass will decrease acceleration.

This net force is the resultant force of all forces acting on the body at any given instant. The larger the magnitude of this net force, the larger the acceleration of the body. One of the definitions of mass is the resistance of a body to motion in general and acceleration in particular due to the application of force.

Explanation:

The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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