Triangle A′B′C′ is a dilation of ​triangle ABC​ about point P with a scale factor of 1/2. Is the dilation a reduction or an enlargement? reduction enlargement

The correct options that could be an example of a function with a domain (-∞0,00) and a range (-∞,4) are given below.Option A. V = -(0.25)x - 4 Option B. V = − (0.25)x+4

A function can be defined as a special relation where each input has exactly one output. The set of values that a function takes as input is known as the domain of the function. The set of all output values that are obtained by evaluating a function is known as the range of the function.

From the given options, only option A and option B are the functions that satisfy the condition.Both of the options are linear equations and graph of linear equation is always a straight line. By solving both of the given options, we will get the range as (-∞, 4) and domain as (-∞, 0).Hence, the correct options that could be an example of a function with a domain (-∞0,00) and a range (-∞,4) are option A and option B.

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To calculate the cash balance at the end of the period, we need to consider the cash inflows and outflows.

Starting cash balance: $4,520

Cash inflows: $1,654 (receivables collected)

Cash outflows: $1,961 (payments to suppliers) + $500 (cash expenses)

Total cash inflows: $1,654

Total cash outflows: $1,961 + $500 = $2,461

To calculate the cash balance at the end of the period, we subtract the total cash outflows from the starting cash balance and add the total cash inflows:

Cash balance at the end of the period = Starting cash balance + Total cash inflows - Total cash outflows

Cash balance at the end of the period = $4,520 + $1,654 - $2,461

Cash balance at the end of the period = $4,520 - $807

Cash balance at the end of the period = $3,713

Therefore, the cash balance at the end of the period is $3,713.

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The subject formula for t in equation form is "t = (h² + 3)/2".

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions.

Given, the subject formula h=square root of 2t-3

Since h = √2t-3

thus solving the equation for t

h² = 2t - 3

2t = h² + 3

t = (h² + 3)/2

Therefore, the Simplified form of the given equation in the terms of t is "t = (h² + 3)/2"

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Answer:

\(5x = - 1 - 1 = 5x \div 5 = - 2 \div 5 = 2 \div 5\)

If the mean is greater than the median, the data is likely Right-skewed.

In mathematics, the mean is the average of a set of data, which is calculated by adding all the numbers together and then dividing the result by the total number of numbers. Right-skewed distributions have long right tails and are characterized by having a mean that is greater than the median. There are two different sorts of means that may be calculated: the arithmetic mean and the geometric mean. The arithmetic mean is calculated by adding all of the numbers in a set and dividing by the total number of integers in the set.

Therefore, the answer is right-skewed. A data set that is skewed to the right is one where the tail to the right of the data clusters is longer than the tail to the left of the data clusters. This means that the data set will have a mean value that is greater than the median.

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Answer:

Proved

Step-by-step explanation:

Given

\(B =(-2,-1)\)

\(U = (0,3)\)

\(G = (3,2)\)

\(S = (4,-3)\)

Required

Prove BUGS is a trapezoid

Given the coordinates, to prove a trapezoid; all we need to do is to check if one pair of sides is parallel.

Taking BU and GS as a pair

First, we calculate the slope using:

\(m = \frac{y_2 - y_1}{x_2 - x_1}\)

For BU

\(B =(-2,-1)\) --- \((x_1,y_1)\)

\(U = (0,3)\) --- \((x_2,y_2)\)

So, we have:

\(m = \frac{3 - -1}{0- -2}\)

\(m = \frac{4}{2}\)

\(m = 2\)

For GS

\(G = (3,2)\) --- \((x_1,y_1)\)

\(S = (4,-3)\) --- \((x_2,y_2)\)

So, we have:

\(m = \frac{-3-2}{4-3}\)

\(m = \frac{-5}{1}\)

\(m = -5\)

The slope of BU and GS are not the same; hence, they are not parallel.

Taking BS and GU as a pair

Calculate the slope

For BS

\(B =(-2,-1)\) --- \((x_1,y_1)\)

\(S = (4,-3)\) --- \((x_2,y_2)\)

So, we have:

\(m = \frac{-3 - -1}{4- -2}\)

\(m = \frac{-2}{6}\)

\(m = -\frac{1}{3}\)

For GU

\(G = (3,2)\) --- \((x_1,y_1)\)

\(U = (0,3)\) --- \((x_2,y_2)\)

So, we have:

\(m = \frac{3-2}{0-3}\)

\(m = \frac{1}{-3}\)

\(m = -\frac{1}{3}\)

The slope of BS and GU are the same; hence, they are parallel.

BUGS is a trapezoid because BS and GU have the same slope

Answer:

on what...like brush how do we help u if u don't have a question

Answer:

c

Step-by-step explanation:

it moves virticly across

The number of students who registered for both robotics and app development is 70.

The percentage is calculated by dividing the required value by the total value and multiplying by 100.

Example:

Required percentage value = a

total value = b

Percentage = a/b x 100

Example:

50% = 50/100 = 1/2

25% = 25/100 = 1/4

20% = 20/100 = 1/5

10% = 10/100 = 1/10

We have,

Total members = 280

The number of members who registered for the robotics class.

= 75% of 280

= 3/4 x 280

= 3 x 70

= 210

The number of members who registered for the app development class

= 50% of 280

= 1/2 x 280

= 140

We see that,

210 + 140 = 350

But we have 280 members.

So,

The number of students who registered for both robotics and app development.

= 350 - 280

= 70

Thus,

The number of students who registered for both robotics and app development is 70.

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The probability of leaving it in any given class is 1/4, the probability of leaving it in the 5th class is 1/4, or\(0.250 (25.0%).\)

The probability that the student left her iClicker device in the 5th class is 0.250 (25.0%). This is because the probability of leaving it in any given class is 1/4, and as she attends 5 different classes,

there is 5/4 or 1.25 chances of her leaving it in the 5th class.

To explain further, the probability of an event can be calculated by dividing the number of ways the event can occur by the total number of possible outcomes. In this case, the event is leaving the iClicker device in the 5th class, and the total number of possible outcomes is 5 (for the 5 classes).

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The solution to the given initial-value problem by using the Laplace transform  is \(y(t) = e^{(-t) }- cos(t) + t sin(t) - t cos(t).\)

To solve the initial-value problem using Laplace transform, we'll first take the Laplace transform of both sides of the differential equation and use the initial condition to find the Laplace transform of the solution.

Taking the Laplace transform of the given differential equation, we have:

\(L{[y']} + L{[y]} = L{[t sin t]}\)

Applying the linearity property of the Laplace transform and using the derivative property \(L{[y']} = sY(s) - y(0)\), where Y(s) represents the Laplace transform of y(t), we get:

\(sY(s) - y(0) + Y(s) = L{[t sin t]}\)

Since y(0) = 0 according to the initial condition, the equation simplifies to:

\(sY(s) + Y(s) = L{[t sin t]}\)

Using the table of Laplace transforms, we find that the Laplace transform of t sin t is:

\(L{(t sin t)} = 2 / (s^2 + 1)^2\)

Substituting this into the equation, we have:

\(sY(s) + Y(s) = 2 / (s^2 + 1)^2\)

Now, we can solve this equation for Y(s):

\(Y(s)(s + 1) = 2 / (s^2 + 1)^2\)

Dividing both sides by (s + 1), we get:

Y(s) = 2 / ((s + 1)(s^2 + 1)^2)

\(Y(s) = 2 / ((s + 1)(s^2 + 1)^2)\)

Now, we need to find the inverse Laplace transform of Y(s) to obtain the solution y(t).

Using partial fraction decomposition, we can express Y(s) as:

\(Y(s) = A / (s + 1) + (Bs + C) / (s^2 + 1) + (Ds + E) / (s^2 + 1)^2\)

Solving for the constants A, B, C, D, and E, we can rewrite Y(s) as:

\(Y(s) = 1 / (s + 1) - (s + 1) / (s^2 + 1) + (2s - 1) / (s^2 + 1)^2\)

Taking the inverse Laplace transform, we find that the solution y(t) is:

\(y(t) = e^{(-t)} - cos(t) + t sin(t) - t cos(t)\)

Therefore, the solution to the given initial-value problem by using the Laplace transform  is \(y(t) = e^{(-t) }- cos(t) + t sin(t) - t cos(t).\)

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Answer: find an alength times a weight

Step-by-step explanation:

What is the Area of a Rectangle?

a Definition: The area of the rectangle is the region occupied by a rectangle within its four sides or boundaries.

The area of a rectangle depends on its sides. The formula for area is equal to the product of the length and breadth of the rectangle. Whereas when we speak about the perimeter of a rectangle, it is equal to the sum of all its four sides. Hence, we can say, the region enclosed by the perimeter of the rectangle is its area. But in the case of a square, since all the sides are equal, therefore, the size of the court will be equal to the court of side length.

the

1. Find the length of the rectangle. In most cases, you will be given the length; if not, you can find it using a ruler.

Note that the double hash marks on the long sides of the rectangle mean that the lengths of the two sides are the same.

2. Find the width of the rectangle. Use the same methods to find it.

Note that the single hash marks on the wide sides of the rectangle mean that the two widths have equal lengths.

3. Write the length and width next to each other. In this example, the length is 5 cm and the width is 4 cm.

4. Multiply the length times the width. Your length is 5 cm and your width is 4 cm, so you should plug them into the equation A = L * W to find the area.

A = 4 cm * 5 cm

A = 20 cm^2

5. State your answer in square units. Your final answer is 20 cm^2, which means "twenty centimeters squared.

You can write your final answer in one of two ways: either 20 cm. sq. or 20 cm^2.

The factoring of the expression x²=-x+6 is (x-2)(x+3)

By ordering the values, we get:

x² + x - 6 = 0

To solve this exercise, we have to follow the rules of factoring:

1. Looking for the a and b number that state the following equations:

Analyzing that (a*b) is a negative number, it means that (a) and (b) have different signs, and due to the results of (a+b) is positive the higher number has to be the positive one.  

The number could be:

a = -2

b = 3

Confirming:

a + b = -2 + 3 = 1

a * b = (-2) * 3 = - 6

2. Rewriting the factored expression (x+a)(x+b) with the obtained values, we get:

(x-2)(x+3)

Is a technique that consist of decomposition of a factor into a product of another factor, which when multiplied together give the original number.

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Answer:

......................

Answer:

Taller because it is bigger and more likely to have greater volume

Step-by-step explanation:

its correct 100%

The correct statement is,

''The taller cylinder have the larger volume than shorter cylinder.''

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

Will the shorter cylinder or taller cylinder have the larger volume.

Since, We know that;

The volume of a cylinder is calculated by multiplying the area of the base by the height.

And, since the height of the taller cylinder is greater than the shorter cylinder, it is likely to have a larger volume.

Thus, The taller cylinder have the larger volume than shorter cylinder.

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Answer:

a=f/3

b=8or it g

gf/3

c=-3gx*2

bonus=f(x)=h(−4x)

Step-by-step explanation:

Answer:

  (x, y) = (4, 0)

Step-by-step explanation:

You want the solution to the system of equations ...

It often works well to start the solution process by putting both equations into standard form. We do that by removing any common factors from the coefficients. Here, we see that the second equation's coefficients each have a factor of 3, so we can remove that and rewrite the system as ...

Changing the coefficient of the y-term has no effect, telling us that y=0, and the equation reduces to ...

  5x = 20

  x = 4

More formally, if we subtract the first equation from the second, we get ...

  (5x +2y) -(5x -3y) = (20) -(20)

  5y = 0 . . . . . . simplify

  y = 0 . . . . . . . divide by 5

The solution is (x, y) = (4, 0).

Answer:

t is 11

Step-by-step explanation:

you divide each side by 4 to get rid of the coefficient on t and since theres

no equation left on either side you're left with t=11

Answer:

t = 11

Step-by-step explanation:

ima help explain it to you

Step one since the prime/first number is 4 put 4 as a denominator under both 4 and 44. That is the first step to these equations

Now, you have 4/4 and 44/4 if you divide 4 and 44 you will get 11. If you divide 4 and 4 you will get 1. equally you have 11/1 aka 11.

A EZ STEP IS TO LITTERALLY DIVDE 44 AND 4 RIGHT WHEN U SEE IT LOL

hope this helps!!

-Bacon

Answer:

dx+9x+16d^2 dont know it it helps any but i tried

Step-by-step explanation:

There were no suspects with less than two prior arrests in this scenario.

Let's solve the problem step by step:

Let's assume the number of suspects with one prior arrest is "x" and the number of suspects with two prior arrests is "y".

According to the given information:

The total number of suspects is 6.

So, x + y = 6 -- (Equation 1)

The total number of arrests, including yesterday's arrests, is 16.

The number of arrests for suspects with one prior arrest is x + 1 (yesterday's arrest plus their one prior arrest).

The number of arrests for suspects with two prior arrests is 2y (yesterday's arrest plus their two prior arrests).

So, (x + 1) + 2y = 16 -- (Equation 2)

Now, we have a system of two equations (Equation 1 and Equation 2) that we can solve to find the values of x and y.

Solving the equations:

From Equation 1, we can rewrite it as x = 6 - y and substitute it into Equation 2:

(6 - y + 1) + 2y = 16

7 - y + 2y = 16

y + 7 = 16

y = 16 - 7

y = 9

Now, substitute the value of y back into Equation 1 to find x:

x = 6 - y

x = 6 - 9

x = -3

Since we cannot have a negative number of suspects, we conclude that there was an error in the given information or calculations.

Therefore, there were no suspects with less than two prior arrests in this scenario.

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Answer:

4/5

Step-by-step explanation:

Since we know that the first ratio that we have is 16:20, all you have to do is simplify by dividing and you get 4/5.

There you go.

Answer:

4%

Step-by-step explanation:

Actual length of wire = 5 cm

The measured length of wire = 5.2 cm

We need to find the percent error in the measurement of the length of wire. It can be calculated as follows :

\(\%=\dfrac{\text{measured length-actiual length}}{\text{actual length}}\times 100\\\\=\dfrac{5.2-5}{5}\times 100\\\\=4\%\)

So, the required percent error is 4%.

A significance level of 0.10, we have enough evidence to conclude that the new copy machines have a significantly faster mean repair time compared to the older model.

To test if the new copy machines are faster to repair, we can set up the following null and alternative hypotheses:

Null Hypothesis (H₀): The mean repair time for the new copy machines is the same as the mean repair time for the older model.

Alternative Hypothesis (H₁): The mean repair time for the new copy machines is less than the mean repair time for the older model.

Let's perform a one-sample t-test to test these hypotheses. The test statistic is calculated as:

t = (sample mean - population mean) / (sample standard deviation / √(sample size))

Given:

Population mean (μ) = 93 minutes

Sample mean (\(\bar x\)) = 86.8 minutes

Sample standard deviation (s) = 14.6 minutes

Sample size (n) = 18

Significance level (α) = 0.10

Calculating the test statistic:

t = (86.8 - 93) / (14.6 / sqrt(18))

t = -6.2 / (14.6 / 4.24264)

t ≈ -2.677

The degrees of freedom for this test is n - 1 = 18 - 1 = 17.

Now, we need to determine the critical value for the t-distribution with 17 degrees of freedom and a one-tailed test at a significance level of 0.10. Consulting a t-table or using statistical software, the critical value is approximately -1.333.

Since the test statistic (t = -2.677) is less than the critical value (-1.333), we reject the null hypothesis.

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Answer:

x=2 or x=5

Step-by-step explanation:

Answer:

This equation is equal to y=3/2x-2

Step-by-step explanation:

To derive the demand function from the given utility function and endowment, we need to determine the optimal allocation of goods that maximizes utility. The utility function is U(x, y) = -e^(-x) - e^(-y), and the initial endowment is (1, 0).

To derive the demand function, we need to find the optimal allocation of goods x and y that maximizes the given utility function while satisfying the endowment constraint. We can start by setting up the consumer's problem as a utility maximization subject to the budget constraint. In this case, since there is no price information provided, we assume the goods are not priced and the consumer can freely allocate them.

The consumer's problem can be stated as follows:

Maximize U(x, y) = -e^(-x) - e^(-y) subject to x + y = 1.

To solve this problem, we can use the Lagrangian method. We construct the Lagrangian function L(x, y, λ) = -e^(-x) - e^(-y) + λ(1 - x - y), where λ is the Lagrange multiplier.

Taking partial derivatives of L with respect to x, y, and λ, and setting them equal to zero, we can find the values of x, y, and λ that satisfy the optimality conditions. Solving the equations, we find that x = 1/2, y = 1/2, and λ = 1. These values represent the optimal allocation of goods that maximizes utility given the endowment.

Therefore, the demand function derived from the utility function and endowment is x = 1/2 and y = 1/2. This indicates that the consumer will allocate half of the endowment to each good, resulting in an equal distribution.

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Answer:18000$

Step-by-step explanation:

Answer:

\(\boxed {\boxed {\sf x\approx 7.3}}\)

Step-by-step explanation:

The triangle has a small square in the corner representing a 90 degree angle. This is a right triangle so we can use the Pythagorean Theorem to solve for the sides.

\(a^2+b^2=c^2\)

In this equation, a and b are the legs and c is the hypotenuse.

x and 8.5 are the legs because they make up the right angle. 11.2 is the hypotenuse because it is opposite the right angle.

Substitute the values into the formula.

\(x^2+(8.5)^2=(11.2)^2\)

Solve the exponents.

\(x^2+72.25 =125.44\)

Solve for x by isolating the variable. 72.25 is being added, so we subtract 72.25 from both sides because subtraction is the inverse operation of addition.

\(x^2+72.25-72.25 = 125.44-72.25\)

\(x^2=125.44-72.25\)

\(x^2=53.19\)

x is being squared, so we take the square root of both sides.

\(\sqrt{x^2}=\sqrt {53.19}\)

\(x=\sqrt{53.19\)

\(x=7.29314746869\)

Round to the nearest tenth. The 9 in the hundredth place tells us to round the 2 up to a 3.

\(x \approx 7.3\)

The unknown side, x, is approximately 7.3

Let's start by calculating the value for f(-1).

For this we go to the graph and count the number of squares to the left of the axis to be at -1. In this case f(-1) would be 5.

Now let's calculate f(4)

For this case the value of f(4) would be 0.

Similarly we calculate f(-3). As you can see in the graph it would be 6.

The last scenario would be for when f(x) = 9, we look for that value on the curve and realize that it corresponds to x = 1.