Answers
Some good experiment ideas for quantum physics is magic wavelength magnetometry of ultra-cold atoms.
What is an Experiment?This is referred to as a procedure which is carried out to support or refute a hypothesis. It is usually performed in the laboratory under controlled conditions and to achieve a purpose.
Quantum physics on the other hand is the study of matter and energy at the most fundamental level and also explains the properties and behaviors of very small objects, such as electrons, photons etc.
Magic wavelength magnetometry of ultra-cold atoms is characterized by the use of perturbations in the ambient magnetic field on particles such as electrons which are caused by contrasts in magnetic susceptibility and it helps in the study of quantum physics.
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Related Questions
As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.15 mm apart and position your screen 3.93 m from the slits. Although Young had to struggle to achieve a monochromatic light beam of sufficient intensity, you simply turn on a laser with a wavelength of 647 nm . How far on the screen are the first bright fringe and the second dark fringe from the central bright fringe
Answers
Answer:
a) y = 2.21 10⁻³ m, b) y = 5.528 10⁻³ m
Explanation:
In the double-slit experiment the interferences occur at the positions
d sin θ = m λ constructive interference
d sin θ = (m + ½) λ destructive interference
let's use trigonometry for the angle
tan θ = y / L
as in this experiment the angles are very small
tan θ = sin θ/cos θ = sin θ
sin θ = y / L
we substitute
d y / L = m λ constructive interference
d y / L = (m + ½) λ destructive interference
Let's answer the questions
a) first line of constructive interference me = 1
y = m λ L / d
y = 1 647 10⁻⁹ 3.93 /1.15 10⁻³
y = 2.21 10⁻³ m
b) second dark band m = 2
y = (m + ½) λ L / d
y = (2 + ½) 647 10⁻⁹ 3.93 /1.15 10⁻³
y = 5.528 10⁻³ m
The Sun converts 6 × 1011kg of hydrogen into helium every second. Only 99.3% (= 0.993) of that goes into helium; the rest, 00.7%, goes into the energy that causes the Sun to shine. So, over the next 5 billion years (= 1.6 × 1017seconds). Calculate the amount of hydrogen that will be converted into helium.
Answers
Where the rate of conversion is the amount of hydrogen converted into helium per second, and the time is the duration over which the conversion takes place.
The rate of conversion is given as 6 × 10^11 kg per second, but only 99.3% of that goes into helium. So the actual rate of conversion into helium is:
6 × 10^11 kg/s x 0.993 = 5.958 × 10^11 kg/s
Now, we can calculate the amount of hydrogen that will be converted into helium over the next 5 billion years:
Amount of hydrogen converted into helium = 5.958 × 10^11 kg/s x 1.6 × 10^17 s
Amount of hydrogen converted into helium = 9.5328 × 10^28 kg
Therefore, over the next 5 billion years, about 9.5328 × 10^28 kg of hydrogen will be converted into helium.
Having aced your introductory physics course, you are hired as a summer intern at NASA. You are sent as part of a team to explore the possibility of mining iron from a small, airless spherical asteroid with a radius of 499 km and a surface acceleration of 2.6 m/sec2.
1) What is the mass of the asteroid?
2) What is the minimum vertical velocity you could give a 4 kg rock from the surface of this asteroid so that it continues to move upwards forever (i.e. it would never return to the surface)?
3) What is the minimum vertical velocity you could give an 8 kg rock from the surface of this asteroid so that it continues to move upwards forever (i.e. it would never return to the surface)?
4) How far will the 4 kg rock go if it leaves the asteroid's surface with a vertical velocity of 1000 m/s?
5) What will the speed of the 8 kg rock be at the surface of the asteroid if it is dropped from a point 1000 km above the surface of the asteroid?
Answers
Answer:
1) M = 9.7*10^21 kg
2, 3) 1610.81 m/s
4) 312.911 km
5) 1315.65 m/s
Explanation:
Given:-
- The radius of the asteroid, R = 499 km
- The surface acceleration, g = 2.6 m/s^2
Solution:-
- To determine the mass of the asteroid ( M ) we will use the relation for the gravitational acceleration produced by a spherical object of mass ( M ) as follows:
\(g = G\frac{M}{R^2}\)
Where,
G: the universal gravitational constant = 6.674*10^−11
- Use the radius of asteroid ( R ) and the given surface acceleration ( g ) and solve for the mass ( M ) of the asteroid using the relation given above:
\(M = \frac{gR^2}{G} \\\\M = \frac{2.6*(499,000)^2}{6.674*10^-^1^1} \\\\M = 9.7*10^2^1 kg\)
- To determine the escape velocity of the mass of rock ( m = 4kg ) from the gravitational pull of the asteroid. We will use the conservation of energy principle.
- The conservation of energy principle states:
\(K.E_i + P.E_i = K.E_f + P.E_f\)
Where,
K.Ei: The initial kinetic energy of the rock of mass ( m )
P.Ei: The potential energy of the system at the surface
K.Ef: The final kinetic energy of the rock of mass ( m )
P.Ef: The final potential energy of the system at infinite
- The gravitational potential energy of the system of an object of mass (m ) at any distance ( r ) from the center of the more massive body ( M ) is given as:
\(P.E = - G\frac{M*m}{r}\)
- The escape velocity is just enough initial velocity ( ve ) that allows an object to cross the gravitational effect of the massive body. Once the effect of the gravity is insignificantly small ( infinite ). Almost all of the kinetic energy has been lost by doing work against the gravitational pull.
- Therefore, K.Ef = P.Ef = 0 ( at infinity ).
\(0.5mv_e^2 - G\frac{Mm}{r} = 0\\\\v_e = \sqrt{2G\frac{M}{r} } = \sqrt{2G\frac{M}{R} } \\\\v_e = \sqrt{2(6.674*10^-^1^1)\frac{9.7*10^2^1}{499,000} }\\\\v_e = 1610.81 \frac{m}{s}\)
- From the above relationship derived for an object at the surface of an asteroid body to escape the grasp of the gravitational pull is independent of the mass of the object ( m ). Hence, whatever the mass of the object is it does not affect the required escape velocity.
Answer: The rock of mass m = 8 kg and m = 4 kg require minimum vertical velocity of 1610.81 m/s to escape the asteroid gravitational pull.
- For the final part we will again apply the principle of conservation of energy for the system of asteroid of mass ( M ) and an object of mass ( m ). We have:
\(K.E_i + P.E_i = K.E_f + P.E_f\)
Where,
K.Ei: The initial kinetic energy of the rock of mass ( m ) = 0 ( dropped)
P.Ei: The potential energy of the system at altitude ( h )
K.Ef: The final kinetic energy of the rock of mass ( m ) at surface
P.Ef: The final potential energy of the system at surface
\(0 - G\frac{Mm}{( R + h )} = 0.5mv^2 - G\frac{Mm}{ R } \\\\v^2 = 2GM* [ \frac{1}{R} - \frac{1}{R+h} ] \\\\v = \sqrt{2(6.674*10^-^1^1)*(9.70*10^2^1)* [ \frac{1}{499,000} - \frac{1}{1499000}]}\\\\v = 1315.65 \frac{m}{s}\)
Answer: The speed of the 8kg rock upon hitting the surface of asteroid would be 1315.65 m/s
- Similarly, how far away a rock of mass ( m ) can go to from the surface of asteroid if it leaves the surface with initial velocity vi = 1000 m/s. We will use the energy conservation expression derived in the previous part. We have:
\(0.5mv^2 - G\frac{Mm}{R} = G\frac{Mm}{R + h} \\\\\frac{0.5v^2}{GM} - \frac{1}{R} = -\frac{1}{R + h}\\\\R + h = \frac{1}{-\frac{0.5v^2}{GM} + \frac{1}{R}} \\\\h = \frac{1}{-\frac{0.5v^2}{GM} + \frac{1}{R}} - R\\\\h = \frac{1}{-\frac{0.5(1000)^2}{(6.674*10^-^1^1)*(9.7*10^2^1)} + \frac{1}{(499000)}} - 499000\\\\h = 312.911 km\)
Answer: The 4 kg rock would be able to travel 312.911 km above the asteroid surface if it had an initial velocity of 1000 m/s.
What happens if you are riding your bike and hit something (like a curb) with the front wheel
Answers
which quanities are scalars
Answers
Answer:
they are quantities with magnitude without direction e.g weight,
the choice of materials for an exciting playground slide should ___.
A. have a large coefficient of kinetic friction between cloth and the slide material.
B. have a small coefficient of kinetic friction between cloth and the slide material.
C. have a large coefficient of static friction between cloth and the slide material
D. have a small coefficient of static friction between cloth and the slide material.
Answers
The choice of materials for an exciting playground slide should have a small coefficient of kinetic friction between cloth and the slide material.
A playground slide is always present in schools, parks and other recreational areas. Children slide down the set up to catch fun.
One thing that must be kept in mind is that the kinetic friction between a cloth and the playground slide material must be kept low so that children can be able to slide down the st up.
Therefore, the choice of materials for an exciting playground slide should have a small coefficient of kinetic friction between cloth and the slide material.
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Which image illustrates reflection?
A
B
с
D
Answers
Answer: I beleive A
Explanation:
Answer:
A
Explanation:
We can see the light being reflected off the mirror.
The springs of a 1700-kg car compress 5.0 mm when its 66-kg driver gets into the driver seat. If the car goes over a bump, what will be the frequency of oscillations?
Answers
Answer:
The frequency of oscillations is 7 Hz
Explanation:
Given;
mass of car, = 1700 kg
mass of driver, = 66 kg
compression of the spring, x = 5mm = 0.005 m
The frequency of the oscillation is given as;
\(F = \frac{1}{2 \pi } \sqrt{\frac{k}{m} }\)
where;
k is force constant
m is the total mass of the car and the driver
m = 1700 kg + 66 kg = 1766 kg
Weight of the car and the driver;
W = mg
W = 1766 x 9.8
W = 17306.8 N
Apply hook's law, to determine the force constant;
F = kx
W = F
Thus, k = W/x
k = 17306.8 / 0.005
k = 3461360 N/m
Now, calculate the frequency
\(F = \frac{1}{2\pi}\sqrt{\frac{k}{m} } \\\\F = \frac{1}{2\pi}\sqrt{\frac{3461360}{1766} }\\\\F = 7 \ Hz\)
Therefore, the frequency of oscillations is 7 Hz
Tension force ........... throughout a string that changes direction over a pulley.
(Fill in the blank)
Answers
Answer:
"is constant"
find the pressure exerted by a force of 8000 newtons on an area of 25m square..give your answer in Newtown/m2
Answers
Answer:
Pressure = 320 N/m²
Explanation:
Given the following data;
Force = 8000 Newton
Area = 25 m²
To find the pressure, we would use the following formula;
Pressure = force/area
Substituting into the formula, we have;
Pressure = 8000/25
Pressure = 320 N/m²
HELP PLEASE TY!
Two objects on Earth with the same weight must have the same:
A. Density
B. Acceleration
C. Mass
Answers
Answer:
C. Mass
Explanation:
If something has the same weight than it has the same mass
Answer: C
Explanation: the mass is the same as weight so if they have weight they also must have mass.
The time required for one complete cycle of a mass oscillating at the end of a spring is 0.40 s. What is the frequency of oscillation?
Answers
Answer:
the frequency of the oscillation is 2.5 Hz.
Explanation:
Given;
time to complete the oscillation, t = 0.4 s
number of oscillations, n = 1
The frequency of the oscillation is calculated as;
\(F = \frac{n}{t} \\\\F = \frac{1}{0.4} \\\\F = 2.5 \ Hz\)
Therefore, the frequency of the oscillation is 2.5 Hz.
Nuclear plants use radioactive fuel to produce steam which turns a turbine to generate electricity. This is an example of a(n) _____. A) heat pump B) heat mover C) internal combustion engine D) external combustion engine
Answers
Answer:
C) internal combustion engineExplanation:
M
An 80% furnace's discharge air temperature is 125 degrees F and is adding heat to a space at the rate of 80,000 BTU's an hour. What is the input rating of the furnace?
a. 60,000 Btu's
b. 120,000 Btu's
c. 75,000 Btu's
d. 100,000 Btu’s
Answers
D. The input rating of the furnace is determined as 100,000 BTU.
What is input rating?
Input power rating means the power, expressed in Watts or one of its multiples, for which the energy storage unit has been designed to operate at nominal conditions.
eff = (output rating / input rating) x 100%
80/100 = 80,000 BTU / input rating
0.8 = 80,000 BTU / input rating
input rating = 80,000 BTU/0.8
input rating = 100,000 BTU
Thus, the input rating of the furnace is determined as 100,000 BTU.
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a roller coaster weighs 2000 kg This ride includes an initial vertical drop of 59.3 m.
Assume that the roller coaster has a speed of nearly zero as it crests the top of the hill.
If the track was frictionless, find the speed of the roller coaster at the bottom of
the hill.
Answers
The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.
Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.
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A large water tank is completely filled with water. The tank is 3.0 m high and its surface is open. If a small hole is made on one side of the tank at a height of 0.8 m, calculate the speed with which the water comes out of the pipe.
Answers
The speed of the water through the pipe is 4.96 m/s
How to calculate the speed at which the water comes out of the pipe?Since a large water tank is completely filled with water. The tank is 3.0 m high and its surface is open. If a small hole is made on one side of the tank at a height of 0.8 m, to find the speed with which the water comes out of the pipe, we use Bernoulli's equation
What is Bernoulli's equation?Bernoulli's equation governs flows through pipes. It is given by
P₁ + ρgh₁ + 1/2ρv₁² = P₂ + ρgh₂ + 1/2ρv₂² where
P₁ = pressure at point 1,h₁ = height at point 1,v₁ = speed at point 1,P₂ = pressure at point 2,h₂ = height at point 2, andv₂ = speed at point 2Given that
P₁ = atmospheric pressure = 1.013 × 10⁵ Pa,h₁ = height of tank = 3 m,v₁ = speed at top ot tank = 0 m/s (since it is stationary there),P₂ = pressure at bottom of tank = 0 Pa,h₂ = height at hole = 0.8 m, andv₂ = speed at hole = speed of water through pipe and ρ = density of water = 1000 kg/m³So, susbstituting the values of the variables into the equation, we have
P₁ + ρgh₁ + 1/2ρv₁² = P₂ + ρgh₂ + 1/2ρv₂²
1.013 × 10⁵ Pa + 1000 kg/m³ × 9.8 m/s² × 3 m + 1/2 × 1000 kg/m³ × (0 m/s)² = 0 + 1000 kg/m³ × 9.8 m/s² × 0.8 m + 1/2 × 1000 kg/m³ × v₂²
1.013 × 10⁵ Pa + 29400kg/ms² + 0 = 0 Pa + 7840kg/ms² + 5000v²
130700 Pa = 7840kg/ms² + (5000 kg/m³)v²
130700 Pa - 7840 Pa = (5000 kg/m³)v²
122860 Pa = (5000 kg/m³)v²
Making v subject of the formula, we have
v = √(122860 Pa/5000 kg/m³)
= √(130.7/5 Pam³/kg)
= √(24.572 Pam³/kg)
= 4.96 m/s
So, the speed of the water through the pipe is 4.96 m/s
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Answer the question below:
Answers
Answer:
D) the decay rates of radioactive uranium and lead
Explanation:
As we know that when she found the substance it must have some fixed ratio of radioactive uranium and Lead in that substance.
Here since Uranium is radioactive substance so it will continuously convert into Lead and this ratio will change with time
So here we can say that the ratio of radioactive uranium and lead will depend on its decay rate
now to find the age of the substance we can find the present ratio of lead and uranium in that substance and then compare it with freshly prepared substance.
so by the formula
we can find the age of the sample
Answer:
Its D
Explanation:
Two bodies separated from
each other at a certain distance
started moving simultaneously
to meet each other - one with ar
acceleration of 2.4 m/s, and the
other with an acceleration of 4.8
m/s2. Determine the ratio of the
displacement module of the first
body to the displacement
module of the second body at
the moment of their meeting.
Answers
The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.
How to find displacement ratio?To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:
d = vt + 1/2at²
where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.
Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.
Assume that the time at which they meet is t, then:
d₁ = 1/2 * 2.4t²
And the equation for the displacement of the second body:
d₂ = 1/2 * 4.8t²
If d₁ = d₂
then, 1/2 * 2.4t² = 1/2 * 4.8t²
Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2
So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.
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You have to lift a 15 kg object. What is your output force?
Using a lever, you push down 20 N to lift a 10 kg object.
A) Find the output force.
B) What is the input force?
C) How much does the ramp multiply your force?
You push with 10 N up a ramp to move a 40 N object to the top
of a table. By how much does the ramp multiply your force?
Answers
Answer:
Explanation:
A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:
Output force = Weight of object = m * g
where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:
Output force = 15 kg * 9.81 m/s^2 = 147.15 N
Therefore, the output force required to lift a 15 kg object would be 147.15 N.
B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.
C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:
Mechanical advantage = Output force / Input force = 40 N / 10 N = 4
So, the ramp multiplies your force by a factor of 4.
Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.
What is the equivalent temperature in kelvin if you have a metal at 50°F?
Answers
Answer:
The required temperature is 283 K.
Explanation:
\(T\:=\:\left(50-32\right)\times \frac{5}{9}+273\\\\T=283\:K\)
Best Regards!
Batman and Robin are attempting to escape that dastardly villain, the Joker, by hiding in a large pool of water (refractive index nwater = 1.333). The Joker stands gloating at the edge of the pool. (His makeup is watersoluble.) He holds a powerful laser weapon y1 = 1.49 m above the surface of the water and fires at an angle of θ1 = 27◦ to the horizontal. He hits the Boy Wonder squarely on the letter "R", which is located y2 = 3.77 m below the surface of the water. θ x y y 1 1 2 R J Batplastic surface Mirrored Surface water B How far (horizontal distance) is Robin from the edge of the pool? (Fear not, Batfans. The "R" is made of laser-reflective material.) Answer in units of m.
Answers
Answer:
x_total = 4.29m
Explanation:
To solve this exercise we must work in parts. Let's use the law of refraction to find the angle of the refracted ray and trigonometry to find the distances.
Let's start by looking for the angles that the laser refracts
n₁ sin θ₁ = n₂ sin θ₂
where n₁ is the air refraction compensation n₁ = 1, n₂ the water refractive index n₂ = 1,333
θ₂ = sin⁻¹ (n₁ sin θ₁/n₂)
θ₂ = sin⁻¹ (1 sin 27 / 1,333)
θ₂ = sin⁻¹ 0.34057
θ₂ = 19.9º
now let's find the distance from the edge of the pool to the point where the ₂lightning strikes the water
tan θ₁ = y₁ / x₁
x₁ = y₁ / tan θ₁
x₁ = 1.49 / tan 27
x₁ = 2,924 m
Now let's look for the waterfall in the water as far as Robin
tan θ₂₂ = y₂ / x₂
x₂ = y₂ / tan θ₂
x₂ = 3.77 / tan 19.9
x₂ = 1,364
the distance from the edge of the pool to Robin is
x_total = x₁ + x₂
x_total = 2,924 + 1,364
x_total = 4.29m
Comparing Conduction and Induction; Are electrons transferred?
Answers
Answer: Correct option is d
Explanation:
Conduction involves contact therefore electrons are transferred.
Induction does not involve contact therefore, electrons are not transferred.
26) After a skiing accident, your leg is in a cast and sup-ported in a traction device, as shown in FIGURE 6-43. Find the magnitude of the force F> exerted by the leg on the small pulley. (By Newton's third law, the small pulley exerts an equal and opposite force on the leg.) Let the mass m be 2.27 kg.
Answers
Explanation
Step 1
free body diagram
Step 2
now, let's analyze the forces
a) in y
Newton's first law says that if the net force on an object is zero ( Σ F = 0 \Sigma F=0 ΣF=0\Sigma, F, equals, 0)
so, as the leg is in rest
\(\begin{gathered} \sum ^{\square}_{\text{ y}}=_{}0 \\ T_1\sin 30-T_2sen\text{ 30=0} \end{gathered}\)let
m= 2.27 Kg , so
\(\begin{gathered} \text{weigth}=m\cdot g \\ \text{weigth}=2.27\operatorname{kg}\cdot9.81m/s^2 \\ \text{weigth}=22.2687\text{ N} \end{gathered}\)hence
\(\begin{gathered} T_2=weigth \\ T_2=22.2687 \end{gathered}\)\(\begin{gathered} T_1\sin 30-T_2sen\text{ 30=0} \\ T_1\sin 30-(22.2687)sen\text{ 30=0} \\ T_1\sin 30-(22.2687)sen\text{ 30=0} \\ T_1\sin 30-11.13435=0 \\ \text{add}11.13435\text{ in both sides} \\ T_1\sin 30-11.13435+11.13435=0+11.13435 \\ T_1\sin 30=11.13435 \\ \text{divide both sides by sin 30} \\ \frac{T_1\sin30}{\sin\text{ 30}}=\frac{11.13435}{\sin \text{ 30}} \\ T_1=22.2687\text{ Newtons} \end{gathered}\)b) now in x ( horizontally)
\(\begin{gathered} \sum ^{\square}_{\text{ x}}=_{}0 \\ -F+T_1cos30+T_2cos\text{ 30=0} \\ \text{add F in both sides} \\ -F+T_1cos30+T_2cos\text{ 30+F=0}+F \\ F=T_1cos30+T_2cos\text{ 30} \\ \text{replace} \\ F=(22.2687)cos30+(22.2687)_{}cos\text{ 30} \\ F=38.57\text{ Newtons} \end{gathered}\)therefore, the answer is
\(F=38.57\text{ Newtons to the left}\)I hope this helps you
Mrs Turner has a scale drawing of her apartment.IN the scale drawing the lenght of her apartment is 6.25 inches and the width is 2.75 onches. If Mrs. Turner used the scale factor 1 inc/18ft, what would the area of the apartment be?
Answers
The area of Mrs. Turner's apartment is approximately 0.05304 square feet.
To find the area of Mrs. Turner's apartment, we need to convert the measurements from the scale drawing to the actual measurements in feet, using the given scale factor of 1 inch/18 feet.
Length of apartment in feet = 6.25 inches × (1 foot/18 inches) = 0.34722 feet
Width of apartment in feet = 2.75 inches × (1 foot/18 inches) = 0.15278 feet
Now, we can calculate the area of the apartment in square feet by multiplying the length and width:
Area of apartment in square feet = Length × Width = 0.34722 feet × 0.15278 feet = 0.05304 square feet
Therefore, the area of Mrs. Turner's apartment is approximately 0.05304 square feet.
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Which is a component of skill-related fitness?
Flexibility
Reaction time
Muscular strength
Body Composition
Answers
Answer:
B. Reaction Time
Explanation:
Reaction Time is the amount of time it takes to respond to anything.
A wave travels at 48 m/s and has a frequency of 12 Hz. What is the wavelength of the wave?
0.25 m
4.0 m
36 m
60 m
Answers
Answer:
Wavelength = 4 m
Explanation:
We know that Velocity = Wavelength × Frequency
So, Wavelength = Velocity / Frequency
Here in the question , Velocity = 48 m/s & Frequency = 12 Hz.
So wavelength = 48/12 = 4 m
In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 73.5 m/s. The driver of the Thunderbird realizes that she must make a pit stop, and she smoothly slows to a stop over a distance of 250 m. She spends 5.00 s in the pit and then accelerates out, reaching her previous speed of 73.5 m/s after a distance of 400 m. At this point how far has the Thunderbird fallen behind the Mercedes Benz, which has continued at a constant speed
Answers
Answer:
Thunderbird has fallen behind the Mercedes Benz by 1017.49 m
Explanation:
Given the data in question;
initial speed of the ford u1 = 73.5 m/s
distance d1 = 250 m
t1 = 5.00 s
d2 = 400 m
Now, let the time taken to stop be t2 and deceleration is a1
so,
a1 = u1² / (2 × d1)
a1 = (73.5)² / (2 × 250)
a1 = 10.8045 m/s²
Now , for acceleration is a2
a2 = v² / (2 × d2)
a2 = (73.5)² / (2 × 400)
a2 = 6.7528 m/s²
total time spend = 5 + u/a1 + u/a2
total time spend = 5 + (73.5/10.8045) + (73.5/6.7528)
total time spend = 22.687 sec
Now, distance Mercedes is ahead = 22.687 × 73.5 - 400 - 250
= 1667.4945 - 400 - 250
= 1017.49 m
Therefore, Thunderbird has fallen behind the Mercedes Benz by 1017.49 m
Four cuboids are shown in the diagram below. The position of their center of mass is also shown. Which of the cuboids is the most stable.
Answers
The position of their center of mass is also shown. the square cuboids is the most stable. Hence option B is correct.
A cuboid is a six-sided solid known as a hexahedron in geometry. Quadrilaterals make up its faces. Cuboid is short for "like a cube". A cuboid is similar to a cube in that a cuboid may become a cube by varying the lengths of the edges or the angles between the faces.
The square cuboid has its center of mass on the center of square, the masses are uniformly distributed about it.
Hence option B is correct.
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In a DC generator, the generated emf is directly proportional to the
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In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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why fan videos be streamed from the cloud to a computer with no lost quality
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Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.
How do digital signals work?
An established or one that represents data as a step made up of discrete values is known as a digital signal. There is no noise produced by digital signals. Electronic signals sent as pulses are used to transmit digital signals to computers. These signals can be found in things like digital phones and computers.
Because digital signals are used to transport data to and from the cloud, it should be noted that videos are said to stream from the cloud to a computer without quality degradation.
Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.
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