The volume of a can of green beans is 791.7 cm. The radius is 6 cm .Find the height of this can ?

Answer:

\(10 coins\)

Step-by-step explanation:

\(5\%\) is equal to \(0.05\) which is just \(5 per 100\). In the number \(200\), there are 2 hundreds, so the answer would be 10 (coins that represent \(5\%\) of her collection. You could also do \(0.05×200=10\).

Answer:

I think its 7330

Answer: Z<4

Step-by-step explanation:

Rearrange the equation

-3(z-6) - (2z-2)>0

-3z+18-2z+2>0

-5z +20>0

-5(z-4)>0

divide  both side by -5

z-4<0

z<4

Answer:

Step-by-step explanation:

sin(x) = opposite over hypotenuse

= 3/(3sqrt(2))

= 1/sqrt(2)

= sqrt(2)/2

x = arcsin( sqrt(2)/2 )

= arcsin( sqrt(2)/2 )

= 45°

The area of the triangle is 31.54 square units

From the question, we have the following parameters that can be used in our computation:

We have the following values

a = 7 units

c = 11 units

B = 55 degrees

The area of the triangle is calculated using the following area formula

Area = 1/2absin(C)

Substitute the known values in the above equation, so, we have the following representation

Area = 1/2 * 7 * 11 * sin(55 degrees)

Evaluate

Area = 31.54

Hence, the area is 31.54 square units

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Answer:

414.48 cm²

Step-by-step explanation:

The following data were obtained from the question:

Pi (π) = 3.14

Slant height (l) = 16 cm

Diameter (d) = 12 cm

Surface Area (SA) =....?

Next, we shall determine the radius.

This can be obtained as follow:

Diameter (d) = 12 cm

Radius (r) =..?

Radius (r) = diameter (d) /2

r = d/2

r = 12/2

r = 6 cm

Finally, we shall determine the surface area of the cone as follow:

Pi (π) = 3.14

Slant height (l) = 16 cm

Radius (r) = 6 cm

Surface Area (SA) =....?

SA = πr² + πrl

SA = (3.14 × 6²) + (3.14 × 6 × 16)

SA = (3.14 × 36) + 301.44

SA = 113.04 + 301.44

SA = 414.48 cm²

Therefore, the surface area of the cone is 414.48 cm²

Using unit I, calculate the average waiting time of customers in the wash line (μ for unit I = 12 per unit).

For unit II at 15 per hour

if waiting time is the only criterion, unit II should be purchased. But before we make the final decision, we must look at the profit differential between both units.

With unit I, some customers would balk and renege because of the 5 minute wait. And, although this greatly complicates the mathematical analysis, we can gain some estimate of lost sales with unit I by increasing Wq = 5 minutes and solving for λ. This would be the effective arrival rate of customers.

Therefore, because the original estimate of λ was 10 per hour, an estimated 2 customers per hour will be lost.

Lost profit of 2 costumers per hour × 14 hours × 1/2 ($0.70 fill-up profit + $0.40 wash profit) = $15.40 per day.

Because the additional cost pf unit II over unit I is only $4 per day, the loss of $15.40 profit obviously warrants installing unit II.

The original five-minute maximum wait constraint is satisfied by unit II.

Therefore, unit III is not considered unless the arrival rate is expected to increase.

Given question is incomplete.

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Answer:

\(\implies f(x) = 2x^2-12x + 22 \)

Step-by-step explanation:

Given :-

And we need to find out the function from the given options which is equivalent to the given function . For that firstly simplify the whole square term , that is ,

Using Identity :-

\(\implies (a-b)^2= a^2-2ab + b^2\)

Whole square term :-

\(\implies (x-3)^2= x^2+9-6x \)

Now multiply the constant term outside the bracket to it . As ,

\(\implies f(x) = (2x^2+18-12x )+ 4 \)

Add the constant terms .

\(\implies f(x) = 2x^2-12x + 22 \)

Hence the second option is correct .

The sample variance is 95.875/7.

To calculate the sample variance and sample standard deviation using the definitional formula, you need to follow these steps:

Calculate the squared deviations from the mean.

Sum up the squared deviations.

Divide the sum of squared deviations by (n - 1) for the sample variance, or by n for the population variance.

Take the square root of the variance to find the standard deviation.

Let's go through the calculations for the provided data set step by step:

Data set: 92, 84, 85, 93, 95, 89, 86, 91

Mean: 89.375

Step 1: Calculate the squared deviations from the mean:

Squared deviations: (2.625)^2, (-5.375)^2, (-4.375)^2, (3.625)^2, (5.625)^2, (-0.375)^2, (-3.375)^2, (1.625)^2

= 6.890625, 28.890625, 19.140625, 13.140625, 31.640625, 0.140625, 11.390625, 2.640625

Step 2: Sum up the squared deviations:

Sum of squared deviations = 6.890625 + 28.890625 + 19.140625 + 13.140625 + 31.640625 + 0.140625 + 11.390625 + 2.640625

= 114.7671875

Step 3: Calculate the sample variance:

Sample variance = Sum of squared deviations / (n - 1)

= 114.7671875 / (8 - 1)

= 114.7671875 / 7

= 16.3953125

Step 4: Calculate the sample standard deviation:

Sample standard deviation = √(sample variance)

= √(16.3953125)

= 4.052488554

Therefore, for the given data set, the sample variance is 16.3953125 and the sample standard deviation is approximately 4.0525.

If the largest value of 95 was misrecorded as 93, we need to recalculate the variance and standard deviation.

Data set with corrected value: 92, 84, 85, 93, 93, 89, 86, 91

Mean: 89.125 (recalculated mean without the misrecorded value)

Step 1: Calculate the squared deviations from the mean:

Squared deviations: (2.875)^2, (-5.125)^2, (-4.125)^2, (3.875)^2, (3.875)^2, (-0.125)^2, (-3.125)^2, (1.875)^2

= 8.265625, 26.265625, 17.015625, 15.015625, 15.015625, 0.015625, 9.765625, 3.515625

Step 2: Sum up the squared deviations:

Sum of squared deviations = 8.265625 + 26.265625 + 17.015625 + 15.015625 + 15.015625 + 0.015625 + 9.765625 + 3.515625

= 95.875

Step 3: Calculate the sample variance:

Sample variance = Sum of squared deviations / (n - 1)

= 95.875 / (8 - 1)

= 95.875 / 7

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Joule per meter second is the unit of measurement for momentum flux or power per unit area. It is commonly used in physics and engineering to quantify the rate of energy transfer or momentum flow per unit area.

Joule per meter second (J/m^2s) is not the correct unit for momentum flux or power per unit area. The correct unit for momentum flux is Newton per square meter (N/m^2), also known as Pascal (Pa), while the correct unit for power per unit area is watt per square meter (W/m^2). The joule per meter second (J/m^2s) is actually the unit for volumetric energy dissipation rate, which measures the rate at which energy is being dissipated within a fluid volume per unit volume. It is used in the study of fluid dynamics and turbulence.

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The time required for the deposit to double at 3.1% interest rate is 22.4 years.

The formula for calculating compound interest can expressed as;

A = Pe^( rt )

Where A is the accrued amount, P is principal, r is interest and t is time.

Given the data in the question;

Let the deposit be represented by x

Since the deposit doubled

Plug the values into the above compound interest formula and solve for time t.  

A = Pe^( rt )

t = ( In( A / p ) ) / r

t = ( In( 2x / x ) ) / 3.1%

t = ( In( 2 ) ) / 0.031

t = ( In( 2 ) ) / 0.031

t = 22.3595

t = 22.4 years.

Therefore, the time needed is 22.4 years.

Option C is the correct answer.

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The value of x for the following tangent through which the given relation of the circle is defined is x = 3 and  the value of WY = 37 .

What about tangent of the circle?

The tangent of a circle is a straight line that touches the circle at exactly one point. This point of contact is called the point of tangency. The tangent line is perpendicular to the radius of the circle at the point of tangency.

The tangent of a circle is an important concept in geometry and calculus. In geometry, the tangent line is used to determine the slope of the curve at a particular point. In calculus, the tangent line is used to approximate the behavior of a curve near a particular point, which is important for finding derivatives and solving related problems.

The tangent of a circle can also be used in various applications, such as in physics to determine the angle of incidence and reflection of light rays, or in engineering to calculate the contact area between a wheel and a surface.

According to the given information:

As we know that tangent of the circle are always equal,

Hence, we have that WY = XY

⇒ 43 - 2x = 12x + 1

⇒ 43 - 1 = 12x + 2x

⇒ 42 = 14x

⇒ x = 3

So, the value of WY = 43 -2x = 43 - 2x3

                                                = 43 - 6

                                                = 37.

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Answer:

Im not sure how you are supposed to answer this but they are similar by side angle side

Step-by-step explanation:

We are given that NO/OQ=PO/OM

This tells us that the sides are in a ratio.

We also know that angle NOM is equal to angle POQ

Now we have 2 sides and 1 angle thus they are similar by side angle side

I hope this helps you come up with your statements and reasons

Answer:

I think the answer is scalpel porators

Step-by-step explanation:

answer = 4 does it is correct

Carol had four times as many coins as Eli had, or a 4:1 ratio.

An ordered pair of integers a and b, represented as a / b, is a ratio if b is not equal to 0. A proportion is an equation that sets two ratios at the same value. For instance, if there is 1 male and 3 girls, you may express the ratio as 1: 3 (there are 3 girls for every guy), meaning that there are 1 in 4 boys and 3 in 4 girls. A ratio in mathematics demonstrates how many times one number is present in another. For instance, if a dish of fruit contains eight oranges and six lemons, the ratio of oranges to lemons is eight to six (that is, 8:6, which is equivalent to the ratio 4:3).

Here,

Dan has twice what Eli has ( D= 2 x E )

Carol had twice what Dan had ( C = 2 x D )

for example , let's suppose Eli had 2 coins

this means Dan had 4 coins,

and Carol had 8 coins .

carol 8 : 2 Eli

=4:1

The ratio in which carol had to the number of coin eli had will be 4:1.

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Answer:

Step-by-step explanation:

2x+1=x-4

2x-x= -4-1

1x=-5

Answer: The answer is A.addition property of equality

Hope I helped

Pkease mark me as brainliest!

The number of blue cars is 375.

What is a ratio?

Ratio is a relationship between two values, represented by numbers or percentage Which expresses which of the two value are bigger. And to find that we cancel the common factor between them.

We are given that the ratio of blue cars to red cars is 3:5

Also there are 600 cars in the parking lot

Now, Let the common factor between them be 'x'

Hence the number of red cars is 3x and number of blue cars is 5x

Hence the equation can be given as

3x+5x = 600

8x = 600

Dividing both sides by 8 we get

x= 75

Hence the number of blue cars is 5(75)= 375

The number of blue cars is 375

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The student's GPA is 3.00, and they did make the dean's list. The student earned grades of B, A, A, C, and D. Those courses had these corresponding numbers of credit hours: 5, 4, 3, 3, and 2.

The grading system assigns quality points to letter grades as follows: A = 4, B = 3, C = 2, D = 1, and F = 0. To calculate the GPA, we first need to find the total number of quality points the student earned. The student earned 3 x 4 + 4 x 3 + 2 x 3 + 3 x 2 + 1 x 2 = 30 quality points.

The student earned a total of 5 + 4 + 3 + 3 + 2 = 17 credit hours. The GPA is calculated by dividing the total number of quality points by the total number of credit hours. The GPA is 30 / 17 = 3.00.

The dean's list requires a GPA of 2.90 or greater. Since the student's GPA is 3.00, they did make the dean's list.

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The volume of the right prism is the product of the length, width and height

The height of the prism is 7.40 ft

The given parameters are:

Volume = 214.5 ft cube

Length = 5 ft

Width = 5.8 ft

The volume of the right prism is calculated as:

Volume = Length * Width * Height

So, we have:

214.5 = 5 * 5.8 * Height

Evaluate the product

214.5 = 29 * Height

Divide both sides by 29

7.40 = Height

Rewrite as:

Height = 7.40

Hence, the height of the prism is 7.40 ft

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Answer:

6.6

Step-by-step explanation:

Using the Master theorem, we can see that the running time is \(O(n^log₂2)\) = O(n), which is less than \(O(n^2).\) Therefore, the algorithm achieves a worst-case running time of \(O(n^2) or o(n^2),\) as required.

To compute the product of two polynomials p(x) and q(x) using a divide-and-conquer algorithm with a worst-case running time of O(\(n^2\)), we can follow the following steps:

1. If the degree of the polynomials P and Q is 0, create a result array R with size 1 and set R[0] as P[0] * Q[0]. Return R.

2. Split the polynomials P and Q into two halves, P₁ and P₂, and Q₁ and Q₂, respectively, by dividing them at the midpoint.

3. Recursively compute the products of the polynomial halves:

  - Compute R₁ as the product of P₁ and Q₁.

  - Compute R₂ as the product of P₂ and Q₂.

4. Create a result array R with size 2n+1.

5. For each coefficient R[i] in R:

  - If i <= n, compute R[i] by summing the corresponding coefficients from R₁ and R₂, i.e., R[i] = R₁[i] + R₂[i].

  - If i > n, compute R[i] by subtracting the corresponding coefficients from R₁ and R₂, i.e., R[i] = R₂[i-n-1] - R₁[i-n-1].

6. Return the result array R.

To argue the correctness of the algorithm, we can observe that polynomial multiplication is equivalent to the convolution of the coefficient arrays. The algorithm recursively divides the polynomials into halves, performs multiplications, and combines the results using addition and subtraction. By following this process, we ensure that each coefficient in the resulting array is correctly computed based on the convolution operation.

The worst-case running time of this algorithm can be derived as follows:

- Splitting the polynomials at each recursion step takes O(1) time.

- Performing two recursive calls on halves of size n/2 takes O(log n) time.

- Combining the results by summing and subtracting coefficients takes O(n) time.

- The total worst-case running time can be represented as T(n) = 2T(n/2) + O(n).

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Answer:

The next number is 24. :)

The number of pizzas you must order for the price to be the same is 5

Bob's Pizza charges = $12 for each supreme pizza

This can be represented as

y = 12x

For Mike's Pizzeria, we have

y = 8x + 20

Substitute y = 12x in y = 8x + 20

12x = 8x + 20

Evaluate the like terms

4x = 20

Divide by 4

x = 5

Hence, the number of pizzas you must order for the price to be the same is 5

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The problem of unit root in standard regression and time-series models arises when a variable exhibits a non-stationary behavior, meaning it has a trend or follows a random walk. Unit root tests, such as the Dickey-Fuller and augmented Dickey-Fuller tests, are used to detect the presence of a unit root in a time series. These tests examine whether the coefficient on the lagged value of the variable is significantly different from one, indicating the presence of a unit root.

In standard regression analysis, it is typically assumed that the variables are stationary, meaning they have a constant mean and variance over time. However, many economic and financial variables exhibit non-stationary behavior, where their values are not centered around a fixed mean but instead follow a trend or random walk. This presents a problem because standard regression techniques may produce unreliable results when applied to non-stationary variables.

Time-series models, such as autoregressive integrated moving average (ARIMA) models, are specifically designed to handle non-stationary data. They incorporate differencing techniques to transform the data into a stationary form, allowing for reliable estimation and inference. Differencing involves computing the difference between consecutive observations to remove the trend or random walk component.

The Dickey-Fuller test and augmented Dickey-Fuller test are commonly used to detect the presence of a unit root in a time series. These tests examine the coefficient on the lagged value of the variable in a regression framework. The null hypothesis of the tests is that the variable has a unit root, indicating non-stationarity, while the alternative hypothesis is that the variable is stationary.

The Dickey-Fuller test is a simple version of the test that includes only a single lagged difference of the variable in the regression. The augmented Dickey-Fuller test extends this by including multiple lagged differences to account for potential serial correlation in the data. Both tests provide critical values that can be compared to the test statistic to determine whether the null hypothesis of a unit root can be rejected.

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Answer:

Nathan multiplies −2x+3y=6 by 2 and then adds the equations. He finds the result is an identity, so there are infinitely many solutions.

Step-by-step explanation:

k12

The solution for the system of equations -

- 2x + 3y = 6

3x - 6y = -12

is (0, 2)

The general equation of a straight line is -

[y] = [m]x + [c]

where -

[m] is slope of line which tells the unit rate of change of [y] with respect to [x].

[c] is the y - intercept i.e. the point where the graph cuts the [y] axis.

The equation of a straight line in point slope form can be also written as-

\(y-y_{1}=m\left(x-x_{1}\right)\)

We have the following set of equations -

- 2x + 3y = 6

3x - 6y = -12

These are the equations of a straight line. Plotting the graphs and finding the point of intersection would give us the solution. It can be seen from the graph that the solution is given by coordinate - (0,2)

Solving by elimination method -

- 2x + 3y = 6       ..[1]

3x - 6y = -12            ..[2]

Multiply [1] by 3 and [2] by 2 -

- 6x + 9y = 18

6x - 12y = - 24

Adding both -

- 6x + 9y + 6x - 12y = 18 - 24

-3y = - 6

y = 2

AND

- 2x + 3y = 6

-2x + 6 = 6

x = 0

Therefore, the solution for the system of equations -

- 2x + 3y = 6

3x - 6y = -12

is (0, 2)

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The probability that the hand contains exactly 3 face cards is 0.1503.

Combinations of 7 cards out of a choice of 52.

52!/(45! *7!)= 52*51*50*49*48*47*46/7*6*5*4*3*2 = 133,784,560

Combinations of 3 face cards out of 12

12*11*10/3*2 = 220

Combinations of 4 non-face cards out of 40

40*39*38*37/4*3*2 = 91,390

Combinations of 5 face cards and 2 non-face cards

220 * 91,390 = 20,105,800

So the probability is 20,105,800/133,784,560 or 0.1503

Probability theory is the theory used to model uncertainty. Probability value o events show how likely it is the event will occur with an interval of values between zero up to one. However, probability theory can only used for events that have information that complete.

For events that have no information complete can be represented by imprecise probability. One model of imprecise probability is the set-valued probability. Probability worth the set is the non-empty set with every the elements are the results of the probability selector mapping.

Then a set-valued measure is constructed which is constructed by set-valued probabilities.

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The area of the figure which consists of two congruent triangles and a rectangle is calculated as: 52 cm².

In the diagram given above, we see a composite figure consisting of two triangles that are congruent, and a rectangle, therefore:

Area of the figure = area of the two triangles + area of rectangle.

The Area of the two triangles:

base = 8 cm²

height = 4.5 cm²

Area of the two triangles = 2(1/2 * base * height) = base * height

Area = 8 * 4.5 = 36 cm²

Area of rectangle = length * width = 4 * 4

= 16 cm²

Total area = 36 + 16 = 52 cm²

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Answer:

I am not sure

Step-by-step explanation:

  i don't believe you've given enough context, here- specify, please