the top of the saturated zone, as marked by the dashed line in the illustration, is called the water .

Answer: Try and subtract

Explanation:

The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.

Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.

Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.

So the filled cubic box has a side length of approximately 0.141 m.

Answer:

It contains approximately 14,568.7 square meters

Explanation:

Area Units Conversion

There are several units to express the area of a shape:

\(cm^2,\ m^2,\ km^2,\ ft^2,\ in^2,\ acres, \ hectares\)

The process of expressing the area from one unit to the other is called a conversion.

Specifically, we are interested in converting from acres to square meters. The rule to make the conversion is:

\(1 acre = 4,046.86\ m^2\)

The plot of land has 3.6 acres, thus its area is:

\(3.6 * 4046.86 =14,568.696\ m^2\)

It contains approximately 14,568.7 square meters

Answer:

Answer:30 cm

Answer:30 cmExplanation:

Answer:30 cmExplanation:Given=ROC= 60cm

Answer:30 cmExplanation:Given=ROC= 60cmObject be placed so that the rays that came from the object to them mirror are reflected from the mirror, and, then travel parallel to each other= 30cm at focus.

Adding globes in parallel makes no difference to their brightness because all the bulbs glowed with the same brightness indicating that the current flowing through the bulbs had the same value.

The current in each light bulb was the same.

An electric current is a flow of electrons as a result of a potential difference between two points in conductor.

Electrons are negatively-charged particles that are one of the fundamental particles of an atom. The flow of electrons through a conductor is able to do work.

Two or more globes in a simple parallel circuit do not experience any drop in the voltage, thus allowing the maximum flow of electric current. Also, connecting devices in a parallel circuit ensures that if one of the component lops is disconnected, the flow of current through the other loops remains intact.

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The amount of damping force that allow shortest possible time is called​ critical damping of the system.

Critical damping is the threshold between overdamping and underdamping  at which the oscillator returns to the position of equilibrium quickly as possible.

Critical damping is frequently desired because such a system returns to and maintains equilibrium quickly. Furthermore, a constant force applied to a critically damped system moves the system to a new equilibrium position as quickly as possible without overshooting or oscillating around the new position.

Critical damping thus provides the rapid approach to zero amplitude for a damped oscillator.

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In fluid dynamics, the terms "lines of flow" and "streamlines" are used to describe the path followed by individual fluid particles as they move within a flow. While both terms are closely related, they have slightly different meanings.

Lines of flow refer to the imaginary lines that are drawn in a fluid flow field to represent the direction in which the fluid particles move. These lines can be fluid dynamics,as the path that a fluid particle would trace out over time. Lines of flow can provide information about the overall flow pattern and direction in a fluid system.

On the other hand, streamlines are the actual curves or lines that are tangent to the velocity vector at every point in the flow field.

These streamlines are defined as the locus of points through which a fluid particle passes at a given instant. Streamlines are a mathematical representation of the flow pattern and can be determined through computational fluid dynamics (CFD) or experimental methods.

In laminar flow, where the fluid flows smoothly in layers with minimal turbulence, the lines of flow and streamlines coincide with each other. This means that the lines of flow and streamlines are identical, and fluid particles move along these lines without crossing each other.

The streamlines do not intersect or cross paths in laminar flow, indicating that the flow is well-ordered and predictable.

In summary, lines of flow and streamlines both describe the path followed by fluid particles in a flow field, with the key difference being that lines of flow are conceptually drawn paths, while streamlines are the actual curves tangent to the velocity vector at each point. In laminar flow, the lines of flow and streamlines coincide, reflecting the organized and smooth nature of the flow.

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Answer:

arrow c tell me if im incorect

Explanation:

Answer:

15 km

Explanation:

1 sec = 25 m travelled

10mins = 600 sec ?

600×25 = 15000m

The vector whose magnitude is 36 and inclination is 60° is v = <18, 18√(3)>.

The inclination of a vector is the angle between the vector and a reference line. In this case, the reference line is the horizontal axis. Let the components be x and y. We know that the magnitude of the vector is 36, so,

magnitude = √(x² + y²) = 36

Squaring both sides of this equation, we get,

x² + y² = 1296

We also know that the inclination is 60°. The tangent of 60° is √(3), which is equal to the ratio of the vertical component to the horizontal component of the vector,

tan(60°) = y/x

y/x= √(3)

Multiplying both sides by x, we get,

y = √(3)x

Now we can substitute y in terms of x in the equation x² + y² = 1296,

x² + (√(3)x)² = 1296

Simplifying this equation, we get,

4x² = 1296

x² = 324

Taking the square root of both sides, we get,

x = +/- 18

Since the vector is making an angle of 60° with the horizontal, it must be in the first or fourth quadrant, where x is positive. Therefore, we take x = 18. Using y = √(3)x, we get,

y = sqrt(3)18

y = 18√(3)

So the vector is,

v = <18, 18√(3)>

Therefore, the vector whose magnitude is 36 and inclination is 60° is v = <18, 18√(3)>.

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Answer:

Step 1: List the mass and velocity of the object. Step 2: Convert any values into SI units (kg, m, s). Step 3: Multiply the mass and velocity of the object together to get the momentum of the object.

Answer:

Explanation:

Out of the given options, A would not describe a physical property of a substance. How a substance reacts with another substance is a chemical property, whereas physical properties are intrinsic characteristics that can be observed or measured without changing the substance's identity. B, C, and D are examples of physical properties - shininess, color, and mass respectively.

The statement that can be made about the three objects when air resistance is assumed to be negligible is; The ratio of net force to mass is constant across all objects.

For the objects falling from a height, a net force (F) acts on them causing them to move.

Now, we have assumed the air resistance to to be constant so from Newtons's law; F = ma;

Where;

The acceleration of the object is given by;

a = F/m

This acceleration is constant for all the three objects and is called the acceleration due to gravity.

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Differentiate the components of position to get the corresponding components of velocity :

\(v_x = \dfrac{\mathrm dx}{\mathrm dt} = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) t^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)t\)

\(v_y = \dfrac{\mathrm dy}{\mathrm dt} = \left(1\dfrac{\rm m}{\mathrm s^2}\right)t-2\dfrac{\rm m}{\rm s}\)

At t = 5.0 s, the particle has velocity

\(v_x = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) (5.0\,\mathrm s)^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s) = 17.5\dfrac{\rm m}{\rm s}\)

\(v_y = \left(1\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)-2\dfrac{\rm m}{\rm s} = 3.0\dfrac{\rm m}{\rm s}\)

The speed at this time is the magnitude of the velocity :

\(\sqrt{{v_x}^2 + {v_y}^2} \approx \boxed{17.8\dfrac{\rm m}{\rm s}}\)

The direction of motion at this time is the angle \(\theta\) that the velocity vector makes with the positive x-axis, such that

\(\tan(\theta) = \dfrac{3.0\frac{\rm m}{\rm s}}{17.5\frac{\rm m}{\rm s}} \implies \theta = \tan^{-1}\left(\dfrac{3.0}{17.5}\right) \approx \boxed{9.73^\circ}\)

The magnitude of the resultant vector is obtained by finding the sum of two horizontal vectors and the sum of two vertical vectors. Thus, option C is correct.

The resultant vector is the single vector that has the same effect in the number of vectors collectively produced. The resultant vector in the horizontal and vertical direction is obtained by drawing a diagonal and hence by using the Pythagoras theorem.

To find resultant vector is obtained by finding the sum of two horizontal vectors and vertical vectors and then using the Pythagoras theorem.

Thus, the ideal solution is option C.

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

80 N

Explanation:

For A + B: the net force is 100 N = (mA + mB)*a

a = 100/(20 + 5) = 100/25 = 4 m/s²

For A, the net force = mA * a = 20 * 4 = 80 N

The forces responsible for the states of aggregation of matter are the intermolecular forces.

Intermolecular forces are the interactions that occur between molecules given their nature, this depends on the characteristics of the molecules that are going to join. The types of unions are classified according to the polarity of the molecules and the types of bonds that occur can be covalent or ionic.

Some bonds are stronger than others, this also determines the characteristics and temperatures to which they have to be exposed to change their states of aggregation.

Therefore, we can confirm that the forces responsible for the states of aggregation of matter are the intermolecular forces.

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Answer:

Draw a table showing the different forms of the first law for the four processes described.

Answer: \(7.96\ \mu C\)

Explanation:

Given

The dimension of the plate is \(1\ cm\times 6\ cm\)

The gap between the plate is \(0.001\ cm\)

Voltage applied \(V=15,000\ V\)

The capacitance of the capacitor is

\(C=\dfrac{\epsilon_o A}{d}\\\\C=\dfrac{8.85\times 10^{-12}\times 1\times 6\times 10^{-4}}{10^{-5}}\\\\C=53.1\times 10^{-11}\ F\)

Charge acquired by the capacitor

\(\Rightarrow Q=CV\\\Rightarrow Q=53.1\times 10^{-11}\times 15,000\\\Rightarrow Q=796.5\times 10^{-8}\\\Rightarrow Q=7.96\times 10^{-6}\ C\)

Answer:

32.67km

Explanation:

~= round off

11.2km/h~3.11m/s

175minutes=10500s

10500*3.11~32, 666.67m

=32.66667km

~ 32.67km

First of all, weight is a force typically measured in Newtons. So right away, you can eliminate 35 kg and 343 kg from the given choices.

The object's weight F on Venus as given by the universal law of gravitation is

F = G (35 kg) (4.87 x 10²⁴ kg) / (6.05 x 10⁶ m)²

where G = 6.67 x 10⁻¹¹ N•m²/kg² is the gravitational constant. You would find the weight of the object to be

F ≈ 310.8 N

so the closest answer is 311 N.

Answer:

5760000... 5760000... 5760000

Answer:

3 significant figures

Explanation:

as there is no decimal, count from the right starting with the first nonzero number

Direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.

Given:

Apparent power (S) = 10 KVA = 10,000 VA

Line voltage (V) = 380 V

Frequency (f) = 50 Hz

Xd = 12 ohms

Xq = 8 ohms

Ra = 1 ohm

Power factor (pf) = 0.8 lagging

Load angle (δ) = 16.15 degrees

(i) Armature current's direct axis and quadrature axis components

We know that the apparent power is given by S = 3VLILcos(φ), where VL is the line voltage, IL is the line current, and φ is the angle between them. For a star-connected alternator, line voltage is equal to phase voltage, so we can write:

S = 3Vphase Iphase cos(φ)

Iphase = S / (3Vphase cos(φ))

For a lagging power factor, cos(φ) = 0.8, so

Iphase = 10,000 / (3 x 380 x 0.8) = 10.46 A

The direct axis component (Id) and the quadrature axis component (Iq) make up the armature current.  Using the given values of Xd, Xq, and Ra, we can calculate these components as follows:

Id = (VL - IaRa) / Xd

Iq = (VL - IaRa) / Xq

where Ia is the magnitude of the armature current, which is equal to the magnitude of the line current divided by √3. Thus,

Ia = Iphase / √3 = 10.46 / √3 = 6.03 A

Substituting the given values:

Id = (380 - 6.03 x 1) / 12 = 30.28 A

Iq = (380 - 6.03 x 1) / 8 = 46.92 A

(ii) Excitation voltage of the generator:

The excitation voltage (E) of the generator is given by:

E = Vphase + IqXq

Substituting the given values:

E = 380 + 46.92 x 8 = 765.36 V

Therefore, the direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.

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It will take the Hubble Telescope 94,247 seconds or 26.18 hours to complete one full rotation around the Earth.

The Hubble Telescope is in a circular orbit around the Earth at a constant speed of 20 m/s. The distance between the telescope and the center of the Earth is:

300 km + 100 m = 300,100 m.

Orbital period T of the Hubble Telescope = T = 2πr / v

where

In this case, r = 300,100 m and v = 20 m/s, so:

T = 2π(300,100 m) / (20 m/s) = 94247 seconds

Thus, it will take the Hubble Telescope approximately 94,247 seconds, or about 26.18 hours, to complete one full rotation around the Earth.

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Answer:

resultant force = 14 N  ( East direction)

Explanation:

A =   √( (4*7)² + (4*7)² )

A = 39.6 N

B = 4 * 7

B = 28 N

C = 2 * 7

C = 14 N

∑ y forces = Ay - B = (4*7) - 28 = 0

∑ x forces = Ax - C = (4*7) - 14 = 14 N

so the resultant force = 14 N  ( East direction)

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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