The table shows the commonly eaten foods of some groups of organisms.

Commonly Eaten Foods List
Group Commonly Eaten Foods
A squids, crabs, lobsters
B branches, barks, twigs, roots
C insects, leaves, nuts, bird eggs
D vegetables, fish, grains, fruits


Which groups contain both primary and secondary consumers
HELP ASAP

The statements that accurately describe sound waves are:

2,3,4,6

1. Sound waves require a medium to transfer energy. Unlike electromagnetic waves, such as light, sound waves cannot propagate through a vacuum. They need a material medium, such as air, water, or solids, to transfer their energy.

2. Sound is heard when a vibration strikes the ear. Sound is a mechanical wave that is produced by vibrations or oscillations of objects. When these vibrations reach our ears, they are detected by the auditory system, which allows us to perceive sound.

3. When particles of a medium interact, part of the wave's energy is lost. Sound waves experience energy losses due to factors like friction, absorption, and scattering. As the wave propagates through a medium, some of its energy is converted into other forms, such as heat, resulting in a decrease in the wave's intensity.

4. A wave's energy can be distinguished from other movements of the medium. Sound waves carry energy in the form of vibrations or oscillations of particles within a medium. These movements are distinct from other random or uncorrelated motions of the medium's particles that do not contribute to the propagation of the sound wave.

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Answer:

Speed, \(v=1.6\times 10^8\ m/s\)

Explanation:

Given that,

Distance covered by the electron, d = 32 cm = 0.32 m

Time, t = 2 ns

We need to find the speed of an electron. Speed is equal to distance covered divided by time. So,

\(v=\dfrac{0.32}{2\times 10^{-9}}\\\\v=1.6\times 10^8\ m/s\)

So, the speed of the electron is \(1.6\times 10^8\ m/s\).

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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The length of the stack shortens by 4.88 x 10-6 m.

Brass and steel have Young's modules of 1.0 and 2 respectively, 1010N/m2. Under the same force, a brass wire of the same length and a steel wire with radii of RB and RS, respectively, are both expanded by 1 mm.

The change in length of each cylinder due to the compressive force can be found using the formula:

ΔL = (F * L) / (A * E)

First, let's find the cross-sectional area of each cylinder:

A = π * r² = π * (0.32 cm)² = 0.3217 cm²

L = Lcopper + Lbrass

L = 2 * Lcopper

Ftotal = Fbrass + (-Fcopper) = Fbrass - Fbrass = 0

Since the total force on the stack is zero, the amount by which the length of the stack decreases is the same as the amount by which the length of the brass cylinder decreases:

ΔL = (Fbrass * Lbrass) / (Abrass * Ebrass)

ΔL = (5000 N * Lbrass) / (0.3217 cm²* 9.0 x 10¹⁰ N/m²)

ΔL = (1.554 x 10⁻⁴ m/N) * Lbrass

V = π * r² * Lbrass

Lbrass = V / (π * r²)

Lbrass = 1 cm / (π * (0.32 cm)^2)

Lbrass = 3.14 cm

Finally, we can substitute this value into the equation for ΔL:

ΔL = (1.554 x 10⁻⁴ m/N) * 3.14 cm

ΔL = 4.88 x 10⁻⁶ m

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The fulcrum should be placed 0.120 m from the left end of the bar to balance the system horizontally.

What is balance?

To balance the system horizontally, the center of gravity (CG) of the bar and the attached masses should be placed directly above the fulcrum. We can find the location of the CG using the following formula:

CG = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3)

where m1, m2, and m3 are the masses of the bar, the 0.055 kg mass, and the 0.110 kg mass, respectively, and x1, x2, and x3 are their respective distances from the left end of the bar.

We know that the total mass of the system is:

m = m1 + m2 + m3 = 0.120 kg + 0.055 kg + 0.110 kg = 0.285 kg

Let x be the distance from the left end of the bar to the fulcrum. Then, the distance from the fulcrum to the center of gravity is (L/2 - x), where L is the total length of the bar (90.0 cm). Therefore, we want to find x such that:

CG = (L/2 - x)

Substituting the expressions for the CG and the masses, we get:

(m1x1 + m2x2 + m3x3) / (m1 + m2 + m3) = (L/2 - x)

Simplifying and rearranging, we get:

x = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3) - L/2

We can choose any two points on the bar as reference points, and take their distances as x1 and x3. Let's choose the left end of the bar as x1 = 0, and the right end of the bar as x3 = L = 90.0 cm = 0.900 m. Then, we can find x2, the distance from the left end to the 0.110 kg mass, as:

x2 = L - x1 - x3 = 0.900 m - 0 m - 0.090 m = 0.810 m

Substituting the masses and distances, we get:

x = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3) - L/2

x = (0 kg × 0 m + 0.055 kg × 0.810 m + 0.110 kg × 0.900 m) / (0.120 kg + 0.055 kg + 0.110 kg) - 0.450 m

x = 0.570 m - 0.450 m

x = 0.120 m

Therefore, the fulcrum should be placed 0.120 m from the left end of the bar to balance the system horizontally.

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Answer:

When the tides are especially weak, it is called a NEAP tide.

Explanation:

Hope this helps :)

Answer:

Neap

Explanation:

Answered!

Answer:

Explanation:

The mass of the object can be found by using the formula

\(m = \frac{f}{a} \\ \)

f is the force

a is the acceleration

From the question we have

\(m = \frac{1200}{8} \\ \)

We have the final answer as

Hope this helps you

Answer:

12\(s^{-1}\)

Explanation:

Period= how long for each revolution

Since we have 10 revolutions in 120 seconds.

120/10=12s

The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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Answer:

210000.................

The specific heat capacity of glycerine is 2333.3 J/(kg·K).

We can use the formula for heat (Q) absorbed by a substance:

Q = mcΔT

Where Q is the heat absorbed, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

We know the mass of glycerine (m = 2 kg), the time for which heat is supplied (t = 35 minutes = 2100 seconds), the rate of heat supply (P = 100 W), the initial temperature (T1 = 30°C = 303 K), and the final temperature (T2 = 75°C = 348 K).

First, we need to calculate the total heat absorbed by the glycerine:

Q = Pt

Q = 100 W × 2100 s

Q = 210000 J

Next, we can calculate the change in temperature:

ΔT = T2 - T1

ΔT = 348 K - 303 K

ΔT = 45 K

Finally, we can calculate the specific heat capacity of glycerine:

c = Q/(mΔT)

c = 210000 J/(2 kg × 45 K)

c = 2333.3 J/(kg·K)

Therefore, the specific heat capacity (c) = 2333.3 J/(kg·K).

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Answer:

the answer is 2

Explanation:

when you solve for this equation it wont make sense but I'm making you read this because I ain't ever seen 2 best friends.

ANSWER:

False​

STEP-BY-STEP EXPLANATION:

The maximum height is determined by the speed but also by the acceleration of gravity.

The acceleration of gravity is not the same on the Moon as it is on the earth, therefore, the maximum height will not be the same.

By applying the equation 1, 2, and 3, the induced emf (E) in a solenoid is 12.32 J/C.

Given that:

Applying the equation for the length of the solenoid as equation (1);

The magnetic B from the center can be estimated by applying the equation (2);

Using the equation or magnetic field B;

\(\mathbf{B = \dfrac{\mu_o \times N \times I}{l}}\)

where;

∴

\(\mathbf{B = \dfrac{4 \pi \times 10^{-7}\times 519 \times 50 \times 10^{-3}}{20.76}}\)

B = 1.57 × 10⁻ T

B = 1.57 μT

Finally, applying equation (3) for the induced emf, the induced emf can be calculated by using the formula:

\(\mathbf{\varepsilon = \dfrac{n \times B\times A}{\Delta t}}\)

where;

\(\mathbf{\varepsilon = \dfrac{100 \times 1.57 \times 10^{-6}\times 7.85 \times 10^{-5}}{1}}\)

\(\mathbf{\varepsilon =1.232 \times 10^{-8} \ v/s}\)

∴

The induced emf \(\mathbf{\varepsilon =12.32 \times 10^{-9} \ J/C}\)

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Answer:0.65606 -> 0.66

Explanation:

Press 2nd on your calculator then hit sin, this will give you the inverse of sin. enter 0.61 in the ( ) and then enter.

Answer:

Hi there!

Your answer is:

A. Linear

Explanation:

Linear measurement is when you measure things in a straight line using tools such as a ruler, yardstick or tape measure. To measure height, they are using a ruler, which is a form of linear measurement!

I hope this helps!

Answer:

a. True

Explanation:

Illumination distance is the distance, up to which the light of the vehicle can reach. Hence, it is a maximum distance from the, that driver can see.

Stopping distance is the minimum distance required by the car to stop after brakes are applied.

So, in order to avoid any accident the illumination distance must be greater than the stopping distance. So, the driver can stop the vehicle in time, when he sees something in front of it.

Since, the stopping distance in this case is two or three times longer than illumination distance. Therefore, low beam light does not provide enough visibility in high speed driving situations.

Hence, the correct option is:

a. True

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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The answer is option C) The car experienced negative acceleration with velocity in the positive direction.

Given that,

Number of turns, N = 25

Magnetic field, B = 1.5 T

The coil has a crosssectional area of 0.80 m2

The coil exits the field in 1.0 s.

To find,

Induced emf in the coil.

Solution,

The induced emf in the coil is given by :

\(\epsilon=\dfrac{-d\phi}{dt}\\\\=\dfrac{dB}{dt}\\\\=\dfrac{NBA}{t}\\\\=\dfrac{25\times 1.5\times 0.8}{1}\\\\=30\ V\)

So, the induced emf in the coil is 30 V.

Explanation:

ur answer is in attachment.

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Explanation:

Force applied on the box = 20 N

Displacement, s = 10 m

Time taken = 5 sec

According to first condition of the question, we could find the value of work done

i.e

Work done = force × displacement

= 20 × 10

= 200 Joule

According to second condition of the question, we could find the value of power

i.e

Power = work done/Time taken

= 200/5

= 40 watt.

Hope it helpful!!!!!!!!!!!!

Answer:

The modal verb must is used to express obligation and necessity. The phrase have to doesn't look like a modal verb, but it performs the same function.

Before the collision, the total momentum of the two train cars is

(13.0 kg) (3.40 m/s) + 0 = 44.2 kg•m/s

After the collision, the two cars have velocity v₁ and v₂ so that their total momentum is

(13.0 kg) v₁ + (38.0 kg) v₂

Momentum is conserved, so

(13.0 kg) v₁ + (38.0 kg) v₂ = 44.2 kg•m/s

Before collision, the total kinetic energy of the two cars is

1/2 (13.0 kg) (3.40 m/s)² + 0 = 75.14 J

and after collision,

1/2 (13.0 kg) v₁² + 1/2 (38.0 kg) v₂²

Energy is also conserved, so

1/2 (13.0 kg) v₁² + 1/2 (38.0 kg) v₂² = 75.14 J

or

(13.0 kg) v₁² + (38.0 kg) v₂² = 150.28 J

Solve the momentum equation for either v₁ or v₂ :

(13.0 kg) v₁ + (38.0 kg) v₂ = 44.2 kg•m/s

⇒   v₂ = (44.2 kg•m/s - (13.0 kg) v₁) / (38.0 kg)

Substitute this into the energy equation and solve for the other variable :

(13.0 kg) v₁² + (38.0 kg) [(44.2 kg•m/s - (13.0 kg) v₁) / (38.0 kg)]² = 150.28 J

⇒   (17.4 kg) v₁² - (30.2 kg•m/s) v₁ + 51.4 J ≈ 150.28 J

⇒   (17.4 kg) v₁² - (30.2 kg•m/s) v₁ - 98.9 J ≈ 0

Using the quadratic formula,

⇒   v₁ = 3.40 m/s   or   v₁ ≈ -1.67 m/s

(We ignore the second solution because that's the initial condition.)

Solve for the remaining velocity:

v₂ = (44.2 kg•m/s - (13.0 kg) (-1.67 m/s)) / (38.0 kg)

⇒   v₂ ≈ 1.73 m/s

A program that could do an instantaneous analysis of video motion will be useful it in a sportscast to analyze events as they occur.

A motion video is defined as the display of video images at a rate (such as thirty frames per second) that causes objects to appear to move smoothly and continuously.

Sports inherently involve fast and accurate motion, which can be difficult for competitors to master but also for coaches and trainers to analyze and audiences to follow. Because of the nature of most sports, monitoring with sensors or other devices attached to players or equipment is generally not possible. This opens up a plethora of opportunities for the use of computer vision techniques to assist competitors, coaches, and the audience

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Answer:

920000

Explanation:

Each kg contains 1,000 grams

Answer:

F = G M m / R^2         a = G M / R^2

aS / aE = (MS / RS^2) / (ME / RE^2)

aS / aE = 329390 * RE^2 / RS^2) = 1    If acceleration due gravity equal

RE^2 = 1 / 329290 * (6.96E8)^2

RE^2 = 1.471 E12

RE = 1.213E6 m

actual RE = 6.38E6 m      (average density of sun < that of earth)

Whenever an object is moving at a constant rate . . .

a).  its speed is that constant rate.

b).  Its acceleration MAY BE zero, if it's also moving in a straight line.

c).  Its velocity is that constant rate if it's moving in a straight line.  Otherwise, its velocity could have many different values, depending on the path it's following.  

The two spheres have opposite charges.

When a positive charge points downwards ↓ and the negative charge points upwards ↑, this causes attraction and shows that the two charges are different.

Thus, we can conclude that the two spheres have opposite charges.

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The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Given:

Initial distance between the planets = 1 million miles

Initial gravitational force = 1,000,000 N

Final distance between the planets = 2 million miles

To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.

Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.

According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:

(F2/F1) = (d1/d2)²

Substituting the given values:

(F2/1,000,000 N) = (1 million miles / 2 million miles)²

Simplifying:

(F2/1,000,000 N) = (1/2)²

(F2/1,000,000 N) = 1/4

F2 = (1/4) * 1,000,000 N

F2 = 250,000 N

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The centripetal acceleration (a) of an object moving in a circular path is given by the formula:

a = v^2 / r

where v is the speed of the object and r is the radius of the circular path.

If the object moves at a uniform speed of 4v instead, we can plug this value into the formula to find the new centripetal acceleration (a'):

a' = (4v)^2 / r

Simplifying the expression, we get:

a' = 16v^2 / r

Now, we can compare the new centripetal acceleration (a') to the original centripetal acceleration (a):

a' = 16(a)

So, if the object moves in the same circular path at a uniform speed of 4v, the centripetal acceleration will be 16 times greater than the original centripetal acceleration.

Answer: V 2 /r

Explanation: "If a particles move with a uniform speed of V on any given circular path having the radius (r), the particle will have a centripetal acceleration of magnitude (v 2 /r). However, the direction continuously changes and always maintains its position towards the circle."