Answer:
The number is 7
Step-by-step explanation:
To find the missing number, subtract 5 from 12.
12 - 5 = 7
Which of the following equations demonstrate the multiplication property of equality for the equation x = 2? Check all
that apply.
✔x(3) = 2(4)
x(5) = 10
x(1.5) = 2(2)
x(0.5) = 2(0.5)
x(12) = 12
Intro
Done
3 of 12
Answer: x(5) = 10 has the multiplication property.
Step-by-step explanation:
To verify the multiplication property of equality , We need to put the value of x= 2
1. x(5) = 10
Solution = 2(5) = 10 ✔
2. x(1.5) = 2(2)
Solution = 2 (1.5) = 3 X
3. x(0.5) = 2(0.5)
Solution = 2 (0.5) = 1 X
4. x(12) = 12
Solution = 2 (12) = 24 X
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Answer:
Step-by-step explanation:
answer B and D
I got it right and didnt spell the entire constitution
.......................................
Answer: the answer is /
Step-by-step explanation: due to the placement of the dots and how many there are there is 40 dots in total. which is the equivalent pixels to a backspace, therefore the answer is /
A political pollster is conducting an analysis of sample results in order to make predictions on election night. Assuming a two-candidate election, if a specific candidate receives at least 55% of the vote in the sample, that candidate will be forecast as the winner of the election. If you select a random sample of 100 voters, what is the probability that a candidate will be forecast as the winner when:___.
a. The population percentage of her vote is 50. 1%?
b. The true percentage of her vote is 60%?
c. The true percentage of her vote is 49% (and she will actually lose the election)?
d. Find a 95% confidence interval of the true percentage of her vote, if 55 voters in the sample of 100 indicated that they voted for her.
e. If 55% of a sample of 300 indicated that they have voted for her, is there sufficient evidence at 90% level of confidence that she has won the election? (Hint: If 0. 5 or less is within the C. I. , then no)
a. Probability of candidate being forecast as the winner ≈ 17.78%
b. Probability of candidate being forecast as the winner ≈ 99.65%
c. Probability of candidate being incorrectly forecast as the winner ≈ 1.58%
d. 95% confidence interval for the true percentage of the candidate's vote ≈ (0.449, 0.651)
e. No, there is not sufficient evidence at 90% level of confidence that she has won the election.
a. If the population percentage of the candidate's vote is 50%, then the probability of her receiving at least 55% of the vote in a sample of 100 voters can be calculated using the binomial distribution with n=100 and p=0.50:
P(X ≥ 55) = 1 - P(X < 55) = 1 - binomial distribution (54, 100, 0.50, true)
≈ 0.1778
b. If the true percentage of the candidate's vote is 60%, then the probability of her receiving at least 55% of the vote in a sample of 100 voters can be calculated using the binomial distribution with n=100 and p=0.60:
P(X ≥ 55) = 1 - P(X < 55) = 1 - binomial distribution (54, 100, 0.60, true)
≈ 0.9965
c. If the true percentage of the candidate's vote is 49%, then the probability of her receiving at least 55% of the vote in a sample of 100 voters can be calculated using the binomial distribution with n=100 and p=0.49:
P(X ≥ 55) = 1 - P(X < 55) = 1 - binomdist(54, 100, 0.49, true) ≈ 0.0158
d. The 95% confidence interval for the true percentage of the candidate's vote can be calculated using the following formula:
CI = p ± zα/2 × √(p×(1-p)/n)
where p is the sample proportion (55/100=0.55), zα/2 is the critical value for a 95% confidence interval (1.96), and n is the sample size (100).
Substituting the values, we get:
CI = 0.55 ± 1.96 × √(0.55×(1-0.55)/100) ≈ (0.449, 0.651)
e. If 55% of a sample of 300 indicated that they have voted for her, the sample proportion is p=0.55 and the sample size is n=300. We can calculate the standard error of the sample proportion using the following formula:
SE = √(p×(1-p)/n) ≈ √(0.55×(1-0.55)/300) ≈ 0.0316
The margin of error for a 90% confidence interval can be calculated by multiplying the standard error by the critical value for a 90% confidence interval, which is approximately 1.645:
ME = 1.645 × SE ≈ 0.052
The 90% confidence interval for the true proportion can be calculated as:
CI = p ± ME ≈ 0.55 ± 0.052 ≈ (0.498, 0.602)
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I only need help with 5 and 6 Please help me! I’ll give a lot of points! And I need an explanation!♥️
Answer:
Look at explantation.
Step-by-step explanation:
5. It's the first and last one.
6. It's the third one.
Step-by-step explanation:
5: y=[x+3] FALSE
y=-[x-3] FALSE
y=-[x]-2 FALSE
y= [x+8]+5 FALSE
conclusion: none in 5 are right.
explanation: unable to identify a local extrema l
6: y=1/4[x]+5 FALSE
y=-[x]-2 TRUE
y= -7[x+5] TRUE
y= 3[x-2] FALSE
conclusion 2/4 are correct.
explanation: using desmos i could see that 2 had a. shift to the left and 2 were to the right
Provide the missing statement and reasons for the following proof:
Theorem: Opposite Sides of Parallelograms are Congruent
The missing statements and reason for the given parallelogram are R3: Alternate Interior angles, S5: ΔACD ≅ ΔABC, and R6: Corresponding sides are equal respectively.
What is parallelogram?
A quadrilateral with two sets of parallel sides is referred to as a parallelogram. In a parallelogram, the opposing sides are of equal length, and the opposing angles are of equal size. Additionally, the interior angles that are additional to the transversal on the same side. 360 degrees is the sum of all interior angles.
From the definition of a parallelogram and the given figure
R3: Alternate Interior angles
S5: ΔACD ≅ ΔABC
R6: Corresponding sides are equal
Hence, these are the required missing statement and reasons for the following proof.
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hi im really need help because m on my quiz pllllzzzz help
The expression is equal to in the given sentence 1/3x + 3/4 + 2/3x - 1/4 - 2/3x is 1/3x + 1/2
How can you determine an expression's value?You must change a number by each variable and carry out the arithmetic operations in order to evaluate an algebraic statement. Since 6 + 6 equals 12, the variable x in the situation above is equal to 6. If we are aware of the values of our elements, we may substitute those values for the original variables before evaluating the expression.
An term that is equal to: must be found.
1/3x + 3/4 + 2/3x - 1/4 - 2/3x
Let's continue to solve it as follows:
If we separate similar phrases, we obtain,
1/3x + 2/3x - 2/3x + 3/4 - 1/4
Further calculation yields, thus,
1/3x + 1/2
Consequently, the phrase has the same meaning as
1/3x + 3/4 + 2/3x - 1/4 - 2/3x is 1/3x + 1/2
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Answer:
7/4a + 1/3
1 3/4a + 1/3
Hope this helped
factoris fully 2ab² + 8a²b
Answer:
2ab(b + 4a)
Step-by-step explanation:
2ab² + 8a²b
Factor Out the 2:
2(ab² + 4a²b)
Factor Out the a:
2a(b² + 4ab)
Factor Out the b:
2ab(b + 4a)
A charge ol −3.40nC is placed at the crigin of an x-cocrdinsle syztem, and a charge of 260nC is placed on the y axis al y−425rm. Ne thire charge, of 5.00LC, is now placed at the point is =2.95 cm,y=4.25 cm lind the x and z corrponents of the total force exarted on this charge by the offer two ctarges. Express answers numerically separated by a comma.- Part B Find the rragnoude of this force.
The x-component of the force acting on the third charge is -0.041 N and the y-component of the force acting on the third charge is -0.058 N. The magnitude of the force acting on the third charge is 0.071 N.
Given Data :Charge of the first charge, q₁ = -3.4nC
Charge of the second charge, q₂ = 260nC
Charge of the third charge, q₃ = 5.00L
Cordinates of the third charge, x₃ = 2.95 cm and y₃ = 4.25 cm
Now, we need to find the magnitude of the force acting on the third charge due to the first and second charges and also find the x and y components of the total force acting on it.
Electric force is a vector quantity that is a combination of the magnitude of the charge and the direction in which it is acting.
Electric force is expressed in terms of Coulombs, which is a measure of the electric charge. The Coulombs are defined as the number of electrons that are present in one unit of charge.
Coulombs are expressed in terms of their magnitudes, with positive charges indicating that the charge is repelling, and negative charges indicating that the charge is attracting.
The electric force is a vector quantity, which means that it has both a magnitude and a direction. In order to find the magnitude of the force, we need to calculate the sum of the electric forces acting on the third charge due to the first and second charges.
Now, we need to find the magnitude of the force acting on the third charge due to the first and second charges and also find the x and y components of the total force acting on it.
From the diagram above, we can see that the distance between the first charge and the third charge is r₁ = x and the distance between the second charge and the third charge is r₂ = y - 4.25 cm.
Therefore, the magnitude of the electric force acting on the third charge due to the first charge is given by
F₁₃ = k * q₁ * q₃ / r₁² where k is Coulomb's constant which is equal to 9.0 × 10⁹ N · m²/C² and q₁, q₃ are the charges of the first and third charges respectively.
Thus, the magnitude of the force acting on the third charge due to the first charge is given by:
F₁₃ = (9.0 × 10⁹ N · m²/C²) * (-3.4 × 10⁻⁹ C) * (5.00 C) / (2.95 × 10⁻² m)²
F₁₃ = -0.071 N
Now, we can find the x and y components of the total force acting on the third charge as:
Fx = F₁₃ * cosθ where θ is the angle between the force F and the x-axis.
Thus,θ = tan⁻¹(y / x)
θ = tan⁻¹(4.25 cm / 2.95 cm)
θ = 53.5°
Therefore, the x-component of the force acting on the third charge is given by:
Fx = (-0.071 N) * cos(53.5°)
Fx = -0.041 N
Similarly, we can find the y-component of the force acting on the third charge as:
Fy = F₁₃ * sinθ where θ is the angle between the force F and the x-axis.
Therefore, the y-component of the force acting on the third charge is given by:
Fy = (-0.071 N) * sin(53.5°)
Fy = -0.058 N
Thus, the x and y components of the total force acting on the third charge are -0.041 N and -0.058 N respectively. Therefore, the magnitude of the force is given by:
F = sqrt(Fx² + Fy²)F = sqrt((-0.041 N)² + (-0.058 N)²)
F = 0.071 N
The x-component of the force acting on the third charge is -0.041 N and the y-component of the force acting on the third charge is -0.058 N. The magnitude of the force acting on the third charge is 0.071 N.
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In an arithmetic series, s40 = 1900 and u40 = 106. find the value of the first term and the common difference.
The first term and common difference of the arithmetic series are -11 and 3.
How to solve an arithmetic series?In the arithmetic series, S₄₀ = 1900 and U₄₀ = 106
Hence,
Sₙ = n / 2 (2a + (n - 1)d)
S₄₀ = 20(2a + 39d)
S₄₀ = 40a + 780d
1900 = 40a + 780d
Uₙ = a + (n - 1)d
U₄₀ = a + 39d
106 = a + 39d
Combine the equation
a + 39d = 106
40a + 780d = 1900
20a + 780d = 2120
40a + 780d = 1900
20a = - 220
a = -220 / 20
a = -11
Hence,
106 = a + 39d
106 = -11 + 39d
106 + 11 = 39d
117 = 39d
divide both sides by 39d
d = 117 / 39
d = 3
Therefore, the first term and common difference of the arithmetic series are -11 and 3.
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Evaluate 7y - 5x^2 when x =2 and y=3
Answer:
1
Step-by-step explanation:
7x3=21
2x2=4
4x5=20
21-20=1
Find the product: (5x + 5y) (x + 4y)
A. 4x2 +22ry - 12y2
B.5x2+ 20y2
c.5x2 + 25xy + 20y2
D. 35x2 - 54ry + 16y2
Answer:
c
Step-by-step explanation:
Assume that the demand curve D(p) given below is the market demand for widgets:
Q=D(p)=2272−19pQ=D(p)=2272-19p, p > 0
Let the market supply of widgets be given by:
Q=S(p)=−3+6pQ=S(p)=-3+6p, p > 0
where p is the price and Q is the quantity. The functions D(p) and S(p) give the number of widgets demanded and supplied at a given price.
What is the equilibrium price?
Please round your answer to the nearest hundredth.
What is the equilibrium quantity?
Please round your answer to the nearest integer.
What is the price elasticity of demand (include negative sign if negative)?
Please round your answer to the nearest hundredth.
What is the price elasticity of supply?
Please round your answer to the nearest hundredth.
The price elasticity of demand at the equilibrium point is approximately -0.99.
To find the equilibrium price, we need to set the demand equal to the supply:
2272 - 19p = -3 + 6p
Solving for p, we get:
25p = 2275
p = 91
Therefore, the equilibrium price is $91.
To find the equilibrium quantity, we can substitute the equilibrium price into either the demand or supply function:
Q = 2272 - 19(91) = 1743
Therefore, the equilibrium quantity is 1743 widgets.
To find the price elasticity of demand at the equilibrium point, we can use the formula:
E_d = (p/Q)(dQ/dp)
At the equilibrium point, p = 91 and Q = 1743. Taking the derivative of the demand function with respect to p, we get:
dQ/dp = -19
Substituting in p and Q, we get:
E_d = (91/1743)(-19) = -0.99
Therefore, the price elasticity of demand at the equilibrium point is approximately -0.99.
To find the price elasticity of supply at the equilibrium point, we can use a similar formula:
E_s = (p/Q)(dQ/dp)
Taking the derivative of the supply function with respect to p, we get:
dQ/dp = 6
Substituting in p and Q, we get:
E_s = (91/1743)(6) = 0.30
Therefore, the price elasticity of supply at the equilibrium point is approximately 0.30.
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Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it.
lim cos(x)/(1 − sin(x))
x → (π/2)+
To find the limit of cos(x)/(1-sin(x)) as x approaches (π/2)+, we can use l'Hospital's Rule.
First, we can take the derivative of both the numerator and denominator with respect to x: lim cos(x)/(1 − sin(x)) x → (π/2)+ = lim [-sin(x)/(cos(x))] / [-cos(x)] x → (π/2)+ = lim sin(x) / [cos(x) * cos(x)] x → (π/2)+
Now, plugging in (π/2)+ for x, we get: lim sin(π/2) / [cos(π/2) * cos(π/2)] x → (π/2)+ = 1 / (0 * 0) = undefined
Since the denominator approaches 0 as x approaches (π/2)+, and the numerator is bounded between -1 and 1, the limit does not exist.
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Can someone help explain how to solve
Can someone help explain how to solve
In the picture there are 4 question that are
1) \(A(-6,-2)\rightarrow A^{'}(-6,2)\\B(-3,-6)\rightarrow B^{'}(-3,6)\\C(-2,-2)\rightarrow C^{'}(-2,2)\\\)
2)\(D(15,10)\rightarrow D^{'}(6,4)\\E(5,10)\rightarrow E^{'}(2,4)\\F(10,-5)\rightarrow F^{'}(4,-2)\\\)
3)\(G(-2,7)\rightarrow G^{'}(-7,-2)\\H(-4,8)\rightarrow H^{'}(-8,-4)\\I(-3,5)\rightarrow I^{'}(-5,-3)\\\)
4) \(J(11,-8)\rightarrow J^{'}(1,-5)\\K(6,-1)\rightarrow K^{'}(-4,2)\\L(3,-7)\rightarrow L^{'}(-7,4)\\\)
The transformation has the following form:
1)\((x,y)\rightarrow(x,-y)\)
2)\((x,y)\rightarrow\frac{2}{5}(x,y)\)
3)\((x,y)\rightarrow(-y,x)\\\)
4) It does not have transformation.
Geometric Transformation:
Images of triangles, quadrilaterals, pentagons, and other geometric shapes can undergo geometric transformations through the vertices in a Cartesian plane. Reflection, rotation, and translation are the three transformations; they only affect the geometric figure's location and not its size. Expansion and contraction are the two transformations that alter the geometric figure's size.
It is necessary to know the sort of transformation that took place given the points and their transformations.
1) We observe that point transformation A,B and C are transformed.
The transformation has the following form:
\((x,y)\rightarrow(x,-y)\)
Every x-value remains constant, while every y-value flips from what it was.\((x,y)\rightarrow(x,-y)\)
2)We observe that point transformations D, E, and F are contractions. Let's now identify the scalar that was applied to the transformation. We compute the product of the original point's coordinate and one of the transformation point's coordinates.
\(\frac{D^{'} _{y} }{D_{ y}} =\frac{4}{10} =\frac{2}{5}\)
We multiply the coordinates of points E and F and check the results to make sure this is true.
For E:
\(\frac{2}{5} (5,10)=(2,4)\\Therefore,E^{'} =(2,4)\)
For F:
\(\frac{2}{5} (10,-6)=(4,-2)\\Therefore,F^{'} =(4,-2)\)
Therefore, The transformation has the following form:
\((x,y)\rightarrow\frac{2}{5}(x,y)\)
3)We observe that point transformation G,H and I are transformed.
The transformation has the following form:
\((x,y)\rightarrow(-y,x)\)
Every y-value flips from what it was to the opposite. The x and y values are reversed.\((x,y)\rightarrow(-y,x)\)
4)We observe that point transformation J,K and L are not transformed.
It does not satisfy the condition of the transformation.
Therefore, this is how we solve the transformation.
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How many solutions does the system have?
y= -2x - 4
y= 3х + 3
Answer:
One solution
Step-by-step explanation:
The system has one solution and that is (-1.4, -1.2)
Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B, are selected on an experimental basis. Location A was observed for 13 days and location B was observed for 18 days. The number of the particular items sold per day was recorded for each location. On average, location A sold 39 of these items with a sample standard deviation of 8 and location B sold 55 of these items with a sample standard deviation of 2. Select a 90% confidence interval for the difference in the true means of items sold at location A and B
We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:
\(\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }\)In order to use t*, we need to check conditions for using a t-distribution first.
Random for both samples -- NOT STATED in the problem ∴ proceed with caution!Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is trueNormality: CLT is not met; n < 30 for both locations A and B ∴ proceed with caution!Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.
Solve for t*:
We need the tail area first.
\(\displaystyle \frac{1-.9}{2}= .05\)Next we need the degree of freedom.
The degree of freedom can be found by subtracting the degree of freedom for A and B.
The general formula is df = n - 1.
df for A: 13 - 1 = 12df for B: 18 - 1 = 17 df for A - B: |12 - 17| = 5Use a calculator or a t-table to find the corresponding t-score for df = 5 and tail area = .05.
t* = -2.015Now we can use the formula at the very top to construct a confidence interval for two sample means.
\(\overline {x}_A=39\) \(s_A=8\) \(n_A=13\) \(\overline {x}_B = 55\) \(s_B=2\) \(n_B=18\) \(t^{*}=-2.015\)Substitute the variables into the formula: \(\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }\).
\(39-55 \ \pm \ -2.015 \big{(}\sqrt{\frac{(8)^2}{13} +\frac{(2)^2}{18} } } \ \big{)}\)Simplify this expression.
\(-16 \ \pm \ -2.015 (\sqrt{5.1453} \ )\) \(-16 \ \pm \ 3.73139\)Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:
\((-20.5707,-11.4293)\)If we want to interpret the confidence interval of (-20.5707, -11.4293), we can say...
We are 90% confident that the interval from -20.5707 to -11.4293 holds the true mean of items sold at locations A and B.
A bird bath that is 4 ft. tall casts a shadow that is 6ft. long. find the length of the shadow that 6 ft. tent casts.
a) 9ft.
b) 3ft.
c) 10ft.
d) 4ft.
Answer:
a) 9 ft.
Step-by-step explanation:
The bath and the tent along with their shadows and the ground make 2 similar triangles. So:
4/6 = 6/x
4x = 36
x = 9 ft.
Help? Is this true or false? Ill give brainliest
Answer:
False I believe the answer is false
Step-by-step explanation:
The slope is 6 but the y - intercept is 2
although women are catching up to men in many fields, there is an increasing gender gap in computer science and engineering. the latest statistics from the national science foundation show that the percentage of engineering degrees awarded to women fell from 20 percent in 2005 to 18 percent in 2008, and that the percentage of computer science degrees awarded to women fell from 22 percent to 17 percent during the same period.
The latest statistics from the National Science Foundation indicate a concerning Gender gap persists in computer science and engineering fields with declining women's degrees from 2005 to 2008.
The data shows that the percentage of engineering degrees awarded to women decreased from 20% in 2005 to 18% in 2008, while the percentage of computer science degrees awarded to women dropped from 22% to 17% during the same period.
These findings highlight the persistent gender disparity in these fields, despite progress in other areas. To address this issue, efforts should focus on promoting and encouraging women to pursue careers in computer science and engineering, providing equal opportunities and supportive environments to bridge the gender gap and foster diversity and inclusion in these crucial fields.
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Pleaseeeeeeee!!!!!!!
Answer:
The answer is C
Step-by-step explanation:
2x10=20
2+10=12
20-12=8
10 is 8 more than 2
2x(7a+8a)-5 +56*2÷3
Answer:
Below
Step-by-step explanation:
● 2x(7a+8a) -5+56×2÷3
● 14ax + 8a -5 +56×2÷3
When you have multiplication and division go from left to right
● 14ax + 8a -5 +112÷3
● 14ax + 8a -5 +112/3
● 14ax + 8a - 15/3 + 112/3
● 14ax + 8a + 97/3
Tins of milk each of volume 77cm^3 and weight 170g
were packed into an empty carton of volume 1540cm^3
and weight 5ooo g.
How many tins of milk can be packed to fill the carton ?
What is the weight of the carton when packed with the tins of milk?
Answer:
1. 20 tins of milk
2. Weight of the Carton = 8,4kg ot 8400g
Step-by-step explanation:
Given
Volume of a Tin = 77cm³
Weight of a tin = 5000g
Volume of Empty Carton = 1540cm³
Weight of Empty Carton = 5000g
Calculating the number of tins of milk
To do this, we have to make use of the given volumes;
And this is done as follows;
\(Number = \frac{Volume\ of\ Empty\ Carton}{Volume\ of\ a\ Tin}\)
Substitute 77cm³ for Volume of a Tin and 1540cm³ for Volume of an Empty Carton
\(Number = \frac{1540cm^3}{77cm^3}\)
\(Number = 20\)
Hence, 20 tins of milk will filled the empty carton
Calculating the weight of the Carton after filled with tins of milk
This is calculated as thus;
Total Weight = Weight of Empty Carton + Weight of Tins of Milk
Substitute 5000g for Weight of Empty Carton
Total Weight = 5000g + Weight of Tins of Milk
_________________________________________
Calculating Weight of Tins of Milk
Since 20 tins of milk will fill the empty carton, the
Weight of Tins of Milk = 20 * Weight of 1 Tin of Milk
Weight of Tins of Milk = 20 * 170g
Weight of Tins of Milk = 3400g
_________________________________________
Substitute 3400g for Weight of Tins of Milk
\(Total\ Weight = 5000g + 3400g\)
\(Total\ Weight = 8400g\)
In Kilograms:
\(Total\ Weight = 8.4kg\)
Consider the following time series y(t): 10, 20, 30, 40, 50 for time periods 1 through 5. Using a moving average of order p = 3, a forecast for time period 6 is
Using a moving average of order p = 3, a forecast for time period 6 is 46.
The moving average is a mathematical method for calculating a series of averages using various subsets of the full dataset. It is also known as a rolling average or a running average. The moving average smoothes the underlying data and lowers the noise level, allowing us to visualize the underlying patterns and patterns more readily. In other words, a moving average is a mathematical calculation that employs the average of a subset of data at various time intervals to determine trends, eliminate noise, and better forecast future outcomes. Answer: 46.
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(8,3) and (-4,-3).
Slope
Answer:
The slope is 1/2
Step-by-step explanation:
The rate of y over the rate of x so it would be y/x. You put the equation y2-y1/x2-x1
Which would look like -3-3/-4-8= -6/-12=6/12 and then you simplify it to 1/2
What is the value of y?
isosceles triangle so angle Q = angle R
and sum of the angles of a triangle = 180
so
y + y + 84 = 180
2y = 96
y = 48
somebody please help im giving 20 points and a brainliest !
Answer:
Price today= 3078
Price 10 years from today= 3877.88
Step-by-step explanation:
Price today= 3000 (1.026)= 3078
Price 10 years from today= 3000 (1.026)^10= 3877.88
Can someone help me with this aleks
Part 2−20 Points - See Below Given this list of departments. 1. Receiving 2. Fabrication 3. Painting 4. Assembly \& Shipping 5. Offices 6. Restrooms \& lockers 7. Stores 1. Calculate how many relationship codes there will be in this chart. 2. Create an activity relationship diagram 3. Populate the diagram with codes for all the relationships 4. What is the percentage of codes in each category? Does it follow the standard percentages? 5. Provide at least 3 reason codes for the chart 6. Create a work sheet to assist in the creation of the dimensionless block diagram. 7. Create a dimensionless block diagram for your data B. Show the flow through the dimensionless block diagram
The task requires analyzing a list of departments and performing several tasks related to relationship codes, activity relationship diagrams, reason codes, a worksheet, and a dimensionless block diagram.
We need to consider the number of departments. Since we have 7 departments listed, the number of relationship codes can be calculated using the formula: (n * (n-1)) / 2, where n is the number of departments.
Substituting the value of n = 7, we get:
Relationship Codes = (7 * (7-1)) / 2
= (7 * 6) / 2
= 42 / 2
= 21
Therefore, there will be 21 relationship codes in the chart.
Create an activity relationship diagram:
An activity relationship diagram visually represents the relationships between departments. Here is a basic diagram representing the given departments:
Receiving --+
+-- Assembly & Shipping -- Offices
Fabrication--+
+-- Painting -- Stores
Restrooms & Lockers
Populate the diagram with codes for all the relationships:
To populate the diagram with codes, we can assign a unique code to each relationship. Here's an example of assigning codes to the relationships in the diagram:
Receiving (R) --+
+-- Assembly & Shipping (AS) -- Offices (O)
Fabrication (F)--+
+-- Painting (P) -- Stores (S)
Restrooms & Lockers (RL)
What is the percentage of codes in each category? Does it follow the standard percentages?
To determine the percentage of codes in each category, we need to count the number of codes in each category and calculate the percentage relative to the total number of codes (21).
In this case, we have the following categories and their respective codes:
Production: R, F, AS, P (4 codes)
Administration: O, S (2 codes)
Support: RL (1 code)
Percentage of Production codes = (4 / 21) * 100 ≈ 19.05%
Percentage of Administration codes = (2 / 21) * 100 ≈ 9.52%
Percentage of Support codes = (1 / 21) * 100 ≈ 4.76%
These percentages do not necessarily follow any standard percentages. The distribution of codes among categories can vary depending on the specific organization or context.
Provide at least 3 reason codes for the chart:
Reason codes are used to provide explanations or justifications for the relationships depicted in the chart. Here are three example reason codes for the given chart:
R01: Receiving department receives raw materials and supplies from external sources.
AS01: Assembly & Shipping department assembles products and prepares them for shipment.
O01: Offices department provides administrative support and management functions for the organization.
Create a worksheet to assist in the creation of the dimensionless block diagram:
Here's an example of a worksheet that can assist in creating the dimensionless block diagram:
Relationship Code From Department To Department
R Receiving Fabrication
F Fabrication Painting
AS Assembly & Shipping Offices
P Painting Stores
RL Restrooms & Lockers -
O Offices -
S Stores -
This worksheet lists the relationship codes along with the corresponding "From" and "To" departments.
Create a dimensionless block diagram for your data B. Show the flow through the dimensionless block diagram:
A dimensionless block diagram represents the flow of activities or information between different departments. Here's an example of a dimensionless block diagram based on the given data:
Receiving --> Fabrication --> Painting --> Stores
|
v
Assembly & Shipping --> Offices
|
v
Restrooms & Lockers
The arrows indicate the flow of activities or information from one department to another.
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HELP PLS!!!!!!!!!!!!!!!!!
Answer:
Step-by-step explanation:
the solutions are options: 2, 3, 4
Riverside and Fresno are 36 cm apart on a map. The map has a scale of 2 cm = 15 miles. How many miles apart are Riverside and Fresno?
Answer:
270 miles
Step-by-step explanation:
36/2=18. So 18 times of 15 miles = 270