In your own words Describe the Law of Conservation of Mass and what it has to do with balancing chemical equations.
USE YOUR OWN WORDS

The formed amount of KCl from the reaction is 297.12 g which is not enough to kill someone.

A limiting reagent can be defined as a reactant that is exhausted completely from the mixture at the completion of a chemical reaction.

When quantities of reactant are not taken in stoichiometry, the limiting reactants in the chemical reaction will decide the maximum amount of product.

Given, a balanced equation of the decomposition of KClO₃ is:

\(KClO_3\longrightarrow KCl +O_2\)

One mole of KClO₃ will produce one mole of KCl.

122.55 g of the KClO₃ will produce KCl = 74.55 g

Given, the amount of KClO₃ = 488.43 g

Then 488.43 g of KClO₃ will produce KCl  = (74.55/122.55) × 488.43

                                                                      = 297.12 grams

As given 420.45g of potassium chloride would be required to kill someone. Therefore,  there is not enough potassium chloride that Melanie killed the butler.

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Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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Answer:

\(m_{AgBr}=1.48gAgBr\)

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

\(KBr(aq)+AgNO_3(aq)\rightarrow AgBr(s)+KNO_3(aq)\)

Thus, since the potassium bromide and silver nitrate are in a 1:1 mole ratio, the first step is to identify the limiting reactant, by considering the reacting volumes of reactants in order to compute the available moles of potassium bromide and the moles of potassium bromide consumed by the 15.4 mL of 0.512-M solution of silver nitrate:

\(n_{KBr}=0.0599L*0.282\frac{molKBr}{L} =0.0169molKBr\\\\n_{KBr}^{consumed}=0.0154L*0.512\frac{molAgNO_3}{L} *\frac{1molKBr}{1molAgNO_3}=0.00788molKBr\)

In such a way, since less moles are consumed than available, we infer that silver nitrate is the limiting reactant, for which the resulting grams of silver bromide (molar mass 187.8 g/mol) result:

\(m_{AgBr}=0.00788molAgNO_3*\frac{1molAgBr}{1molAgNO_3} *\frac{187.8gAgBr}{1molAgBr} \\\\m_{AgBr}=1.48gAgBr\)

Best regards.

Answer:

Explanation:

Here, we want to get the molar mass of the given molecule

To get this, we have to add up the atomic mass unit of the individual constituent elements, using the multiples where necessary

Thus, we have it that:

ANSWER

The amount of heat released is -54, 957.175J

EXPLANATION

Given that;

To find the amount of energy released, then apply the below formula

Recall, that the specific heat capacity of steam (c) is 2.03 J/g degrees Celcius

Therefore, the amount of heat released is -54, 957.175J

Dissolve 60g of potassium bromide in 340g of water to produce 15% (mass/mass) aqueous solution of potassium bromide.

Here we have to prepare a total of 400 g of solution. Aqueous solution means the solvent we use here is water.

So to prepare 400 g of 15% aqueous solution of potassium bromide, we need to find out how many grams of potassium bromide need to be dissolved in water and how many grams of water must be used.

Here the weight percent is given, that is 15%

       15/100 = weight of potassium bromide/ 400 g

       0 .15      = weight of potassium bromide / 400

      weight of potassium bromide needed = 0.15 × 400

                                                                       =  60 g

So, we calculated the required amount of potassium bromide as 60 grams. The total weight of the solution to be made is 400 grams.

So amount of water required = 400 - 60

                                                =  340 g

So we need to mix 60 grams of potassium bromide in 340 grams of water to get a 15% (mass/mass) aqueous solution.

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The volume needed to dilute a stock solution diluted to make 50cm3 of 0.05M K2Cr2O7 is 1cm³.

The volume needed to dilute a solution can be calculated by using the following formula:

M1V1 = M2V2

Where;

According to this question, a stock solution needs to be diluted to make 50cm3 of 0.05M K2Cr2O7. The volume needed can be calculated as follows:

2.5 × V1 = 50 × 0.05

2.5V1 = 2.5

V1 = 2.5/2.5

V1 = 1cm³

Therefore, the volume needed to dilute a stock solution diluted to make 50cm3 of 0.05M K2Cr2O7 is 1cm³.

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Answer:

a

Explanation:

5'-GTCCTACGGACGCG-3' is the DNA sequence that matches the data given by shortest fragment on the left to longer fragments on the right.

Chromatography is a laboratory method used in chemical analysis to separate a mixture into its constituents. The combination is dissolved in a fluid solvent known as the mobile phase, which transports it through a system containing a substance known as the stationary phase. A chromatogram is the result of a chromatography run. It is a hardcopy or electronic file comprising the information generated during the chromatography run. Chromatography works on the premise of smearing molecules in a mixture onto a solid or surface, and a stable phase (fluid stationary phase) separates the components of a mixture while working with a mobile phase.

Here,

The DNA sequence 5'-GTCCTACGGACGCG-3' corresponds to the data provided by the smallest fragment on the left to the larger segments on the right.

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In 0.8291 moles of hexane (\(C_6H_1_4\)) there are 20.8 liters in 0.8291 moles of hexane at room temperature and atmospheric pressure.

To determine the number of liters in 0.8291 moles of hexane (C6H14), we need to use the ideal gas law equation:

PV = nRT

where:

P = pressure (atm)

V = volume (L)

n = moles of gas

R = gas constant (0.0821 L*atm/mol*K)

T = temperature (K)

We need to rearrange this equation to solve for V:

V = nRT/P

First, we need to calculate the number of moles of hexane:

n = mass/molar mass

The molar mass of hexane (C6H14) is:

6(12.01 g/mol) + 14(1.01 g/mol) = 86.18 g/mol

n = 0.8291 moles

Next, we need to convert the temperature to Kelvin. Assuming room temperature (25°C or 298 K):

T = 298 K

Finally, we need to assume a pressure value. Let's assume atmospheric pressure (1 atm).

P = 1 atm

Now we can plug in the values and solve for V:

V = (0.8291 mol)(0.0821 L*atm/mol*K)(298 K)/(1 atm)

V = 20.8 L

Therefore, there are 20.8 liters in 0.8291 moles of hexane at room temperature and atmospheric pressure.

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Answer:

The oxidation state of the reducing agent has changed from 0 to +2.

Explanation:

reducing agent is anything that loses electron or gains oxygen

in this case, zinc

Answer:

\(mol=0.0709mol\)

Explanation:

Hello,

In this since one mole equals 6.022x10²³ particles of silver by means of the Avogadro's number, we can compute the moles in 4.27x10²² particles as shown below:

\(mol=4.27x10^{22}particles*\frac{1mol}{6.022x10^{23}particles}\\\\mol=0.0709mol\)

Best regards.

The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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Answer:

(a) GaF3, gallium(III) fluoride

(b) LiH, lithium hydride

(c) AlI3, aluminum(III) iodide

(d) K2S, potassium sulfide

As per the given data, 1.6 grams of oxygen reacted in this experiment.

To calculate the amount of oxygen that reacted in the experiment, we need to determine the difference in the mass of X oxide (X,O) formed and the mass of X initially used.

Given:

Mass of X = 4.6 g

Mass of X oxide (X,O) = 6.2 g

To find the amount of oxygen that reacted:

Mass of oxygen = Mass of X oxide - Mass of X

= 6.2 g - 4.6 g

= 1.6 g

Therefore, 1.6 grams of oxygen reacted in this experiment.

Calculate the mass of 1 mole of X:

Given that the mass of X is 4.6 g, we can calculate the molar mass of X by dividing the mass by the number of moles:

Molar mass of X = Mass of X / Number of moles of X

Molar mass of X = 4.6 g / 0.1 mol

Molar mass of X = 46 g/mol

Therefore, the mass of 1 mole of X is 46 grams.

Thus, the answer is 46 grams.

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Answer:

A. True

Explanation:

C. 51.5%  is the percent yield for the reaction below when 364 g SO2 and 42.0 g O2 produce 408 g SO3

The actual yield is determined by calculating the quantity of the product created. We can estimate the percentage yield by dividing the actual yield by the theoretical value. The percentage yield is the difference between the quantity of product that was actually created and the maximum calculated yield.

2SO₂(g) + O₂(g) → 2SO3(g)

SO₂ mass => 364g

O₂ mass => 42g

SO3 mass => 408g

Theoretical yield of SO3:

mole of  O₂ => 42g/32g => 1.31

according to the chemical equation:

1 mole of oxygen => 2 moles of SO3

1.31 mole O2 => x moles of SO3

x=> 2 x 1.31 => 2.62

Hence, the mass of SO3 => 2.62 x 80.06 => 209.75g

The percentage of yield => Actual yield / theoretical yield x 100

                                  => 209.75/408 x 100 => 51.45 => 51.5%

The theoretical yield is the yield that is derived using a balanced chemical reaction. What you actually acquire from a chemical reaction is the actual yield.

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The percent by mass of the fluorine in the compound is 46.472%.

We know that the percent by mass has to do with the ratio of the total mass of the atom that is part of the compound and the total molar mass of the compound multiplied by one hundred.

The question in this case has demanded that we ought to obtain the mass percent of fluorine from the compound that we can be able to identify from the formula of the compound that is shown here as xenon hexa fluoride.

Mass of the compound can be obtained from; 131 + 6(19)

= 245 g/mol

The total mass of the fluorine atom in the compound is 114 g

Thus we have the use of;  114 /245 * 100/1

= 46.472%

The percent  by mass is now gotten for the fluorine atom as 46.472%.

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1. The number of mole of C₃H₈ needed to make 15.5 moles of CO₂ is 5.2 moles

2. The number of moles of O₂ needed is 25.8 moles

The number of mole of C₃H₈ needed can be obtained as illustrasted below:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

From the balanced equation above,

3 moles of CO₂ was obtained from 1 mole of C₃H₈

Therefore,

15.5 moles of CO₂ will be obtain from = (15.5 × 1) / 3 = 5.2 moles of C₃H₈

Thus, number of mole of C₃H₈ needed is 5.2 moles

We can obtain the number of mole of O₂ needed as follow:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

From the balanced equation above,

3 moles of CO₂ was obtained from 5 moles of O₂

Therefore,

15.5 moles of CO₂ will be obtain from = (15.5 × 5) / 3 = 25.8 moles of O₂

Thus, number of mole of O₂ needed is 25.8 moles

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Complete question:

How many moles of C₃H₈ are needed to make

15.5 moles of CO₂? How much O₂ will be needed?

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

Answer:

Volume of the gass will decrease by three times of the original volume

Explanation:

Volume is inversly propotional to the pressure applied on it.

Answer:

it is decreased to one third of its original volume

Explanation:

The viscosity, which affects the amount of friction between water molecules, also plays a role. Despite the low viscosity of water, friction is still a problem. All moving fluids constantly lose energy as a result of rubbing against their surroundings. Water will move from high-energy regions to low-energy ones.

When it comes to confined aquifers, the situation becomes much more complicated, but we still need to understand how they function because they are significant water sources. demonstrates that even if the geological materials at the surface have very low permeability, there is always a water table. This aquifer will have its own "water table," which is actually called a potentiometric surface because it is a measure of the total potential energy of the water, wherever there is a confined aquifer, which is one that is separated from the surface by a confining layer. The potentiometric surface for the confined aquifer  as a red dashed line. It represents the total energy that the water is under. inside the restricted aquifer. The water will rise to the water table if we drill a well into the unconfined aquifer. But if we drill a well into the confined aquifer through both the confining layer and the unconfined aquifer, the water will rise to the level of the potentiometric surface above the top of the confined aquifer. Due to the fact that the water rises above the aquifer's surface, this is referred to as an artesian well.

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Answer:

The correct answer is - option B -  lowest b.p.... isobutane < acetone < isopropanol ...highest b.p.

Explanation:

Isobutane has lowest boiling point due to no hydrogen bonding and no diole to dipole interaction found in them. Isobutane only shows weak dispersion force.

Acetone has dipole dipole interaction but due to lack of Hydrogen bonding they have low boiling point than isopropanol but higher than isobutanol.

Isopropanol is the compound that has ability to form hydrogen bonding with other molecule its boiling point is maximum among all three.

Thus, the correct answer is - option B -  lowest b.p.... isobutane < acetone < isopropanol ...highest b.p.

The element with the smallest atomic number is hydrogen

A chemical element's atomic number is its position in the periodic system, which places the elements in ascending order of the number of protons in their nuclei. As a result, the atomic number is also determined by the number of protons, which is always equal to the number of electrons in a neutral atom.

The charge number of an atomic nucleus is the chemical element's atomic number, also known as nuclear charge number. This is the number of protons present in the nucleus of each atom of that element, or the proton number, for conventional nuclei. The atomic number of common chemical elements can be used to uniquely identify certain elements.

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Sally is wrong because copper is less electropositive than hydrogen, thus, can not displace hydrogen from dilute acids.

The reactions to prepare copper (ii) chloride are:

the chlo­ri­na­tion of cop­per sul­fide at a high tem­per­a­ture

reaction of copper (ii) oxide with dilute hydrochloric acid

The equations of the given reactions are as follows:CuS + Cl₂ ---&gt; CuCl₂ + SCuO + 2HCl ----&gt; CuCl₂ + H₂O

Reactive metals are metals that readily give up their electrons to form positive ions.

Reactive metals displace hydrogen from dilute acids. They are found in group 1A and 2A of the periodic table. Copper is not a reactive metal and will not displace hydrogen from acids.

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Sally is wrong because copper chloride is not made from the reaction of copper and dilute hydrochloric acid.

2. Copper (ii) chloride can be prepared as follows:

3. the equations of the reaction are:

Single replacement reactions are reactions in which a more reactive atom replaces another atom in a compound.

An example of a single replacement reaction is the reaction of chlorine gas with copper sulfide at high temperatures to form copper chloride.

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answer and explanation

the percent mass %m/m of a solution is the mass of the solute divided by the mass of the solution x 100

therefore

%m/m = 3 g/ 78g x 100

= 3.85%

Answer:

antimony

Explanation:

The representation of the electrons in the shell is called electronic configuration.

The correct answer is antimony

The shell is as follows:-

These are the shells in which electrons are filled.

The total number of electrons is 2+2+6+2+6+2+10+6+2+7= 45

After calculating the electrons, the total number of electrons is 45 which is the atomic number of antimony.

Hence, antimony is the correct option.

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29 Cu⁺​. We have to place 29 electrons and then we will substract 1 electron because of the positive charge.

The electron configuration of Cu should be:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁹

2 + 2 + 6 + 2 + 6 + 2 + 9 = 29

Then Copper has one anomalous thing. The energy difference between the 3d and 4s orbitals is very low. It's an exception, but one electron jumps from the subshell 4s to the subshell 3d. In that way it has the subshell 3d that is lower in energy filled, and it is more stable. So the electron configuration of 29 Cu is:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d¹⁰

1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s¹

To write the electron configuration of 29 Cu+ we take off one electron from the 4s orbital. S

1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰

It has 18 valence electrons (3s² 3p⁶ 3d¹⁰).

Answer:

17 reactions

Explanation:

Answer:

(a): Precipitate of calcium carbonate will form.

(b): Precipitate of barium sulfate will form.

(c): Precipitate of silver iodide will form.

(d): Precipitate of sodium chromate will form.

Explanation:

Complete ionic equation is defined as the equation in which all the substances that are strong electrolytes present in an aqueous state and are represented in the form of ions.

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

(a):

The balanced molecular equation is:

\(CaCl_2(aq)+K_2CO_3(aq)\rightarrow 2KCl(aq)+CaCO_3(s)\)

The complete ionic equation follows:

\(Ca^{2+}(aq)+2Cl^-(aq)+2K^+(aq)+CO_3^{2-}(aq)\rightarrow 2K^+(aq)+2Cl^-(aq)+CaCO_3(s)\)

As potassium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

\(Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)\)

Precipitate of calcium carbonate will form.

(b)

The balanced molecular equation is:

\(BaCl_2(aq)+MgSO_4(aq)\rightarrow MgCl_2(aq)+BaSO_4(s)\)

The complete ionic equation follows:

\(Ba^{2+}(aq)+2Cl^-(aq)+Mg^{2+}(aq)+SO_4^{2-}(aq)\rightarrow Mg^{2+}(aq)+2Cl^-(aq)+BaSO_4(s)\)

As magnesium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

\(Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)\)

Precipitate of barium sulfate will form.

(c):

The balanced molecular equation is:

\(AgNO_3(aq)+KI(aq)\rightarrow KNO_3(aq)+AgI(s)\)

The complete ionic equation follows:

\(Ag^{+}(aq)+NO_3^-(aq)+K^+(aq)+I^{-}(aq)\rightarrow K^+(aq)+NO_3^-(aq)+AgI(s)\)

As potassium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

\(Ag^{+}(aq)+I^{-}(aq)\rightarrow AgI(s)\)

Precipitate of silver iodide will form.

(d):

The balanced molecular equation is:

\(2NaCl(aq)+(NH_4)_2CrO_4(aq)\rightarrow 2NH_4Cl(aq)+Na_2CrO_4(s)\)

The complete ionic equation follows:

\(2Na^{+}(aq)+2Cl^-(aq)+2NH_4^+(aq)+CrO_4^{2-}(aq)\rightarrow 2NH_4^+(aq)+2Cl^-(aq)+Na_2CrO_4(s)\)

As ammonium and chloride ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

\(2Na^{+}(aq)+CrO_4^{2-}(aq)\rightarrow Na_2CrO_4(s)\)

Precipitate of sodium chromate will form.